ABSTRACTS The vapor pressure of water refers to the pressure exerted by water vapor molecules when they are in equilibrium with liquid water at a specific temperature and the enthalpy of vaporization, also known of vaporization , is the amount of heat energy required to convert one mole of liquid water into vapor at a constant temperature and pressure. The experiment conducted aimed at determining the vapor pressure and estimating the enthalpy of vaporization of water. During the experiment 800mL beaker with filled distilled water to just below the lip. Then 6.5ml of water was put in a measuring cylinder. The mouth of the cylinder was closed and inverted into the beaker of water. The water was heated to 80oC and allowed to cool. The volume of gas in the cylinder was recorded at every 5oC to 30oC then an ice was put in the water to drop the temperature to 5oC and the volume of the gas was recorded. From the recorded temperature and the volumes, the values of πΌππ πππ were obtained and a graph of πΌππ πππ 1 π 1 π was plotted. The value of the enthalpy was calculated using the Clausius Clapeyron Equation. The enthalpy was calculated to be 8.7kJ. 1 INTRODUCTION In thermodynamics and chemical engineering, vapor pressure of water refers to the pressure exerted by water vapor at thermodynamics equilibrium with its liquid phase at a specific temperature. It represent the tendency of molecules to escape from the liquid and enters the gas phase. This process is called phase transition. The phase transition is the spontaneous conversion of one phase into another phase, occurs at a characteristic transition temperature, Ttrs, for a given pressure (Atkins, P. W. (2006). At this point the vapor pressure is called saturated vapor pressure. As the temperature increases, the average kinetic energy of water molecules also increases. When the kinetic energy is increasing, more molecules escapes the water surface and the saturated vapor pressure is correspondingly higher. The enthalpy of vaporization, βπ»π£ππ of water is the energy required to evaporate one molecule of water at constant temperature and pressure. It is a measure of the strength of intermolecular forces in a pure water substance. The relationship between the temperature of a water and its vapor pressure is not a straight line. The Clausius Clapeyron Equation is a mathematical relationship relating the vapor pressure of a liquid to the temperature of the liquid. When vapor pressure is plotted against temperature, a nonlinear trend is observed, πΌππ = − βπ»π£ππ π π +πΆ Where Hvap is the enthalpy of vaporization, R is the universal gas constant (8.314 J mol-1k-1), T is the Kelvin temperature, and C is a constant based on the liquid. Equation 1 is an equation in the straight line form y=mx+b. The slope of this plot is equal to − βπ»π£ππ π . Using this relationship the value of the enthalpy of vaporization can be determined. Thus, this experiment allows to calculate the enthalpy of vaporization of water using the Clausius-Clapeyron equation by obtaining the vapor pressure of water over a range of temperatures. 2 METHODOLODY An 800mL beaker was filled with water just below to the lip. About 6.5ml of water was poured into a 10mL graduated measuring cylinder. The top of the tube was covered by the figure and inverted. While inverted the cylinder was put into the beaker. The beaker was put on a wire gauze on a tripod stand. The cylinder was clamped alongside a thermometer. The water was heated to 80°C by the Bunsen burner. The heat was removed and water was allowed to cool. During cooling the volume of water was recorded at every 5°C till the temperature drops to 30°C from 80°C. During cooling half of the water was removed and replaced by an ice till the temperature drops to 5°C and the volume of trapped air in the tube was recorded. 3 RESULTS AND DISCUSSIONS The table bellows shows the temperature and the volume reading obtained during the experiment TEMPERATURE OF THE WATER DURING COOLING (oC) VOLUME OF THE AIR IN THE TUBE (mL) 80 6.8 75 6.7 70 6.5 65 6.3 60 6.1 55 5.9 50 5.7 45 5.5 40 5.3 35 5.1 30 4.9 5 4.0 Assuming that the atmospheric pressure is 760mmHg. The low temperature volume can be taken as air in the cylinder at that temperature and pressure since vapor pressure of water is negligible at 5°C. The vapor pressure of water in the cylinder is: ππ»2π = πππ‘π − ππ»2π 4 Temperature(K) Volume (cm3) ππππ (mmHg) ππ»2π (mmHg) πΌππ 353 6.8 583.1 287.0 5.66 1 π 2.832×10-3 348 6.7 583.4 286.6 5.65 2.874×10-3 343 6.5 592.7 277.3 5.62 2.915×10-3 338 6.3 602.6 267.4 5.59 2.959×10-3 333 6.1 613.2 256.8 5.54 3.000×10-3 328 5.9 624.4 245.6 5.50 3.049×10-3 323 5.7 636.5 233.5 5.45 3.096×10-3 318 5.5 649.4 220.6 5.39 3.144×10-3 313 5.3 663.3 206.7 5.33 3.195×10-3 308 5.1 678.3 191.7 5.26 3.247×10-3 303 4.9 694.6 175.4 5.17 3.300×10-3 278 4.0 780.6 89.4 4.49 3.597×10-3 The graph of πΌππ = π΄ π +π΅ 5,8 5,7 5,6 Inp 5,5 5,4 5,3 y = -1054,6x + 8,694 5,2 5,1 0,0028 0,0029 0,003 0,0031 0,0032 0,0033 0,0034 I/T During heating the volume of the vapour of water collected in the empty space of the measuring cylinder started to increase till the thermodynamic equilibrium is achieved. This is because during 5 heating the temperature of the water molecules increases thus increases the kinetic energy of the molecules thereby escaping from the water surface. During cooling the vapor pressure decreases following the phenomena inverse relationship with the temperature. The temperature was cooled to 5°C. At this temperature the vapor pressure of water is negligible and can be neglected. Pair is taken to be equal to the barometer pressure. Given the number of the moles of air trapped in the cylinder, the ππππ is calculated using the ideal gas equation because the volume vapour pressure is assumed to behave ideally (ππππ = ππππ π π π ). At temperature above 5°C, the total pressure in the cylinder (Pcylinder) is the sum of water vapor (Pw) and that of the trapped air (Pair) according to the Dalton’s ππ€ + ππππ = πππ¦ππππππ …………………………………………………………… 1 The total pressure in the cylinder, πππ¦ππππππ was calculated from the measured barometer pressure and the difference in water levels in the beaker and in the cylinder. πππ¦ππππππ = πππ‘πππ πβπππ + β(πππ»2 π) × 1.0πππ»π 13.6πππ»2 π ……………………………………… 2 The partial pressure of water at every temperature is calculated using the equation 1 and 2. The analyzed data of pressure- temperature leads to the plotting of the graph of πΌπππ€ versus 1/T. the enthalpy of vaporization of water, βπ»π£ππ was calculated from the slope of the linear produced graph. The graphical method of calculating the enthalpy of vaporization is more accurate than the method of using two different points because it use multiple of data points. The more points available, a truer correlation is made as there is a possibility of measurements errors that goes by unnoticed. During the experiment an estimation was made that h (gas level) remained constant throughout all the measurement despites the change of the gas volume level in the cylinder. The fact is that the level of the gas (h) was changing due to the change of the volume as the pressure was changing and the expectation is that the value of (h) probably should have been measure for each 6 temperature. They were some error associated with the experiment. For example, human errors caused by human factor which were due to incorrect readings of the temperature, improper and poor set up of the apparatus mostly in inverting the measuring cylinder and calculations mistakes. 7 CONCLUSION The purpose of the experiment was to estimate the enthalpy of vaporization of water vapor pressure which was successful met. The enthalpy of vaporization was calculated using the slope of the linearly graph of πΌππ π£πππ π’π 1 π . The thermodynamic phenomena is that when the water is been heated, the molecules increases in kinetic energy and escape from water surface to gas phase and during cooling the kinetic energy decreases thus increasing the intermolecular force among the particles and condenses back to liquid. Through the process the data of pressure and temperature was obtained and analyzed to obtain the enthalpy of vaporization. Some of the associated errors during the experiment can be reduced by being accurate in taking readings. 8 REFERENCE Atkins, P. W. (2006), Physical Chemistry, 8th Ed. Oxford University Press: Oxford CHE 411 & 421, 2013/2014 Physical Chemistry Practical’s Laboratory Manual. Chemistry Department, Chancellor College, Zomba. J.M. Smith, Hendrick Van Ness, Michael Abbott, Mark Swihart(2018) Introduction to Chemical Engineering Thermodynamics. McGraw-Hill Education (2018) Thomas Engel, phillip Reid, (2006) “physical chemistry” Pearson Education INC,,New York 2006 9 APPENDIX ππ 760×0.004 nwater =π π , = 62.4×278 =1.8×10−4mole 1.8×10−4 ×62.4×278 Pair at 278 k= π₯π 0.004 =780mmHg 5.33−5.62 Slope=π₯π=0.00144−0.00295= - 1,543 βπ» Since, slope= - π , βπ» =1,543K×8.314J/k.mol=12.8KJ/mol 10