MAHATHI DUVVURI
101265779
PSYC 2001 C
ASSIGNMENT 2
Answer 1:
a) Green 1991 formula
m= number of predictors
N> 50+8m
N> 50+8(2)
N> 50+16
N> 66
b) Burmeister and Aitken 2012 formula
n= [(p1+p2+....pn) -1] x 100
n= [(1+1) - 1] x 100
n= [2-1] x 100
n= 1 x 100
n= 100
Answer 2:
Two tailed alpha= 0.05
Standard deviation= 0.25
Margin of error= 0.05
Z- score= 1.96
n= ( z-score)2 x StdDev x (1-StdDev)
(margin of error)2
= (1.96)2 x 0.25 x (1-0.25)
(0.05)2
= 3.84 x 0.25 x 0.75
0.0025
n = 288
Answer 3:
Modality: The modality in the given histogram is unimodal, as it has only one peak. In this
distribution mean, median and mode are close to each other.
Symmetrical shape: The histogram is positively skewed, as there is a long positive tail and a
peak on the left side.