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Final-exam-key

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Giảng viên ra đề:
(Ngày ra đề)
(Ngày duyệt đề)
Người phê duyệt:
(Chữ ký, Chức vụ và Họ tên)
(phần phía trên cần che đi khi in sao đề thi)
Semester/year
FINAL EXAM
Course
Ho Chi Minh City University of Technology Course No.
(HCMUT), VNU-HCM
FACULTY OF CHEMICAL ENGINEERING Duration
Date
2
2022-2023
30/05/2023
Organic Chemistry - KEY
CH2021
90 min
Code 01
Note: - Materials, cell phones, or any communication devices are not allowed.
- Only the answers in the boxes are accepted.
Question 1) (L.O.2, 2 points): 0.5 pt for each correct answer. No further solutions are accepted.
2.
1.
3.
4.
Question 2) (L.O.1, 2 points): 0.5 pt for each correct answer. No further solutions are accepted.
(A)
(B)
(C)
(D)
ID number……………………Full name: ........................................................... Page 1/3
Question 3) (L.O.1, 2 points): 0.5 pt for each correct answer. No further solutions are accepted.
(E)
(F)
(G)
(H)
Question 4) (L.O.3, 2 points): 0.5 pt for each correct answer. No further solutions are accepted.
2 synthetic parts should be checked independently, No heating → fine, no ether → fine
No keton protection → ZERO for Part No.2
Bromination before acylation → ZERO for the whole question
No catalyst for acylation/bromination →ZERO for the corresponding part
No catalyst for ketalization → ZERO for Part No.2
Use H2CrO4 to oxidize alcohol to benzaldehyde → ZERO for Part No.2
ID number……………………Full name: ........................................................... Page 2/3
2 synthetic parts should be checked independently, No heating → fine, no ether → fine
No reaction with NaOH for the synthesis of aniline → fine
No “excess” for the Grignard reaction → fine
No acidic treatment → ZERO for Part No.2
Treatment with water only instead of acid → ZERO for Part No.2
No water for bromination → fine
Use metal/lewis acid catalyst for bromination → ZERO for Part No.2
Radical bromination of methyl → ZERO for the whole question
Question 5) (L.O.3, 2 points): 0.5 pt for each correct answer. No further solutions are accepted.
An isomer only → Zero
Either (Z) or (E) alkene is OK.
Configuration of chiral carbon must be (S).
ID number……………………Full name: ........................................................... Page 3/3
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