" what r " how q r ✓¥ - UC ; are many electrons = n ✓h"% = ↳ c to . . . 106 = missing " . . " OR . ¥eo = e = of electrostatic force between two identical ions magnitude " "> F i § = " the distance be most charge one of a : ÷ us a = r✓É n=§ electron (( " " If pcirtice ↳ Fz ↳ - 41¥ ( 91€ = 9292 - ✗z particles all ( ) 1-3=0 where ( <→ gz Ms L - ✗ 12 V52 = ✗ 92 = I ¥ at a- Fyi # n°4 just solve for × " Magnitude É y=o K = 9¥¥# ' Fili = ,, of net electrostatic force ' Fy ; = cos - -09 on particle Sino - , ;^ 113 )) due to the other . diagonal one ¥ - /NETT Ñhl particles - 41 is the - Éy + , '' Éyz , + f- 43 4- K be attractive 1931 .%¥ iii. laundry T Éyz razz DIRECTIONAL coordinate a " " " → " , = i 2 qz . he 1941 n - " , ' da cancel , keep * so that change flip ratio the you get they nonzero a force net the direction of the want will be force accelerated in Magnitude F- ✗ the of 41¥ ¥ = electric net . Ey (19,1+1921-1931-1941) . cc particles four 9, qz =3 e. = ÉNET fixed in place are . Orient . y 4T¥ (¥fz = - . . axis to the 41¥ ¥ = ( -19,1+1 qzl ' of net electric field Magnitude . 's @ Swore's by particle produced field particles that didn't 1- center 1931 - @ point •É - to due the a high Em e - Same ✗ Vo :O ; V2 V02 Zax + , What is $ I on 4 → Y) particles different question " guns due to the four other particles =81T%d- (&99%09 = thus v ✓Zai = => m Cm = - ✓ ← mass of proton = zero particle force 93 electric potential Net " in - ← electric field = = produced be can ) - arctanl Ex Image . " speed protons is ••• - other ✓ Beams of - If the net " I - • § 1941 ) P cancel out " -0 { . " cc " 4)1 - MAGNITODF-TVF-nei-ciitfnei-c.sn#-..n.a.a-/IfIs arctanc.FI?-Y.?-, ratio kg * " remain in place when released y coordinates S ✗ is to be located such that ✓ + • - J Nd • PM d d <É• u 0 * t * " × = Ia the time it f- at = shows a L = rQ Eapg 2 takes distance if -0 is rod . F" 41T C- OR2 -0 The rod . . forms radians ; -0 = ③ at - E / ④ = ZEO I ✓Z2+Rz- - / - ✓zz¥rz= = ÷ = + Of circle . . . by what is the factor magnitude multiplied 25in (-0/2) are central axis . . . is the magnitude of the field equal to electric ] > " of the E ② PARTICLE along the Z • = E - ✓ , ( 21T ) cc what distance 10/21 a - expressed in ZQ Sin (-0/2) = attain final speed proton travels a nonconducting proton to a 2- ✓zz+pz- ¥ = ZZ = ¥ 2- 2 + ÷ R2 => 44 " times . . . W z2 Where can room SKIP good while the yourself " dipole an electric moment . . . What is potential energy , magnitude of torque - U (f) (a) U = = - - I É - I . É . = - pE (b) cos I = . , If an external Ñx É (c) W Review Dot and Cross product . = = AU - [ = (Ñ ; ( pi ) - agent how much work is done (G) W * . you do the - É . " what p is multiplied by , in this case harm " Ñf ) É ( pf ) ] doing least by agent ' - still 1.30×10 -3°C " - m most " spherical drop of a 9 *V > = 41TEoR- = (b) R' "3 = = C to q ' ✗ ' drop the radius of . 18 99 potential surface . . . of the drop new " . 109N MYC2) ( q ) - V 10-12 = zq = = 4-4 Charges 2 EV = ; . => 41T€ ou ' Identical U R = 4¥ zy}p?_ " ✓ " 2 = . q R PC water Qa are Kf i ×z+yz- 41T£ ☐ ✓ 2213 V > fixed on Ki Oi = + x-axis an Of - Ki = . . energy of particle Kinetic . ?¥÷o ( ✓×zt+y;z- + . at what value . . ✓×z+lyz - * set y will the origin @ ✗ " negative value y momentarily stop of = these values should be the same (b) Kf = Initial and final coordinates 0 kit Ui Uf = > = Ki ZQ a + 41T£ ☐ ✓ ✗z = + yiz "TEO mw → ✓×Zty solve for cc yf F- ✗ " " rod nonconducting V 2 : . . (8.99×109) (z) take V . 0 = @ infinity . What is V ln[É] (b) along 1- the rod's bisector Magnitude of electric field @ if - the electric V potential is = 5.50W yz2 " how y = = Uf (g) (¥ 2) 2 - = 41T C- OF =HE×i+cEy5+u IET is required to set up the much work 2 -5.50×2-2 = * W four work is then there is component of charge configuration - negative , meaning that . . . É X an - , , 2✗ = > + V2 y ' ' (2×-29) × w/ => g) Vz - E. F 0 ✗ =L ✗ I = ZV some > = Mug back in , . corresponding nonvanisning a particles " take it would Ey V ZV = E× along in the opposite direction and the - point I direction , = Ey . * If the electric potential increases JI dy - " ✗ dx F- is V @ P superposition V :O due to d (( (b) What . V , (✗ 2 are amount to disrupt it " S@ infinitely apart " positive . rest . CC The plates of C = spherical capacitor a ab 41T C- o . . . (a) ab = b. a the calculate (b) A (8.99×109) ( b- a) capacitance (b) What must be the plate area of a parallel plate capacitor " . . . C(b = €0 [ pF ] [ cmz ] " If Cz measured potential difference across the first the = Vo c * capacitors in parallel have the same potential 1 " ' " " → ') C, " 1- ¥ 1-1 ° C. = ÷ . = Ci = c 9 = , /vs (2) (b) Vf = U; = ÷ Vi % Avi a capacitor ⇐ final ⇐ Initial : Of (a) W = = di " a certain - V Capitance of this second capacitor " . ) - . . and an potential difference air energy 9 , = C , zzv all three capacitors = > V , = 9 , /c = > V , - V , = V2 = > 92 Cz V2 [ uc ] - - ea MM ↳ % cz=y%s ✓ i - = df filled separation / di A df_ U ; ⇐ Up ( par what is the s ↳N = stored " • - - . 10-4 Ui - q U = = (F- max - Id ZKEOA 103 ) KEOA with a dielectric I 2. OV Cece ( ÷ to 3 - = final energy stored parallel plate capacitor is filled Czz by graph ' Zdi (C) . > cz + Cz + given parallel plates in g C. ( Cz + C 3) 123 ¢ (C difference - , cc ÷ capacitor drops to . . . Maximum energy that can be stored " • c÷) - + / = Cztcz A"d a " c E°÷ ( "') = [ hrnnrrrrrrrrrrrrrrrrrrrrrrr " The V figure V = +e Vz 1- , V3 + + arrangements . Which . . " - e 41¥% = ex is arrangement off _•e V4 4T¥ = 4 shows • the electric A is in - - ↳ The moves to a charge region of charge goes If higher a correct is ↳ The electric potential to closer 8 electric field lines electric field about it A @ " central adding fractions 0 O O • common denominator rewire ¥g ye , → " flies 0 point away # Once the the . " rod removed the closer the electric field charged object , a object near " what = , , . zero * y,¥ ÷ 4¥ g- 4¥ g- t.gg#-q . fixed place a potential -•e lose " charge object PRACTICE EXAMS lines are spaced has an excess . wire are the , S bail Charge + 4T " F- o In terms of @ Eo Q F- " 41T¥ zYzz+¥- = Is their a ↳ have same what ↳ " 42 = C is E between direction halved ' on symmetry a line of , @ 1- dist L . " . +•E i ET = is " particles the due U , point p to opposite doubled wi , , where an erection . . charge so Separation . no be in If . IT ,, egg, ,, , gum Same Charge between plates is then doubled yes -•3 Where Zero ↳ . a the °" is axis the E. P " to the left of between the " the charges charges - " WRONG about capacitor S capacitance is for given a 4 orientation ↳ E 2- parallel plate capacitor Isolated ↳ @ point " " z ' ' @ electric field what is the , au 1,2 to A- 03 = , capacitor > , , we and 3 can store as much charge as we wish by increasing the potential difference btwn plates . Et " respectively A- V2 • - . • cc . ' . " . = . U . . . A = 9 • , = 9192 I + - K qz . . E?÷ . electric . + K %÷ potential energy of = > u = the ER EL system 9? - = Eb a A• → < to → % + <→ • • B C es • • to si LET HEB ↳ The change " k = D in electric potential energy of the three - particle system is " positive " Bubble Problem ↳ F- STOPPED @ 33 : = Ey = ✓ ÷ EL EL Et : K 2£ * 1 → KII Ex = ← Er = dz + t Er F- b = = K - - K ¥ 3£ lE×5+lEy¥?¥ ,