VISVESVARAYA TECHNOLOGICAL UNIVERSITY BELAGAVI MATHEMATICS HANDBOOK I and II Semester BE Program Effective from the academic year 2022-2023 VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Derivatives of some standard functions: d n x n x n 1 dx d c 0 dx d x e ex dx d x a a x log a dx d sin x cos x dx d cos x sin x dx d tan x sec2 x dx d cot x cos ec 2 x dx d sec x sec x tan x dx d cos ecx cos ecx cot x dx d 1 log x dx x log e d log a x a dx x d 1 cos 1 x dx 1 x2 d 1 tan 1 x dx 1 x2 d 1 cot 1 x dx 1 x2 d sinh x cosh x dx d cosh x sinh x dx d tanh x sec h2 x dx d coth x cos ech2 x dx d sec hx sec hx tanh x dx d cos echx cos echx coth x dx d 1 sin 1 x dx 1 x2 Rules of Differentiation: 𝑑 𝑑𝑢 (𝑐𝑢) = 𝑐 𝑑𝑥 𝑑𝑥 d d d uv u v v u dx dx dx 1|Page d u dx v v d d u u v dx dx v2 VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Parametric differentiation: If 𝑥 = 𝑥(𝑡) & 𝑦 = 𝑦(𝑡) 𝑡ℎ𝑒𝑛 𝑑𝑦 𝑑𝑥 = 𝑑𝑦 ) 𝑑𝑡 𝑑𝑥 ( ) 𝑑𝑡 ( Chain Rule: If 𝑦 = 𝑓(𝑢) & 𝑢 = 𝑔(𝑥) then 𝑑𝑦 𝑑𝑥 = 𝑑𝑦 𝑑𝑢 𝑑𝑢 𝑑𝑥 Integrals of some standard functions: (Constant of Integration C to be added in all the integrals) x n 1 1 n x dx n 1 xdx log x log xdx x log x x, x 0 kdx k x ax log a x x e dx e x a dx sin x dx cos x cos x dx sin x tan x dx log sec x cot x dx log sin x sec x dx log sec x tan x cos ecx dx log cos ecx cot x sec cos ec x dx cot x 2 x dx tan x 2 sec x tan x dx sec x cos ecx sinh x dx cosh x cosh x dx sinh x tanh x dx log cosh x coth x dx log sinh x sec h x dx tanh x cos ech x dx coth x 2 a f 2 ' 1 1 dx tan 1 x a 2 x a x f x dx log f x ax e cos bx dx ax e sin bx dx 2|Page eax a cos bx b sin bx a 2 b2 eax a sin bx b cos bx a 2 b2 cot x dx cos ecx 2 1 a x f ' x 2 f x 2 dx sin 1 x a dx 2 f x VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK a b a f x dx f a x dx 0 a a a f x dx f x dx a 0 a 2 f x dx f x dx 0 0 b f x is even function if f x is odd function if 𝑎 2𝑎 2 ∫ 𝑓(𝑥)𝑑𝑥, 𝑖𝑓 𝑓(2𝑎 − 𝑥) = 𝑓(𝑥) ∫ 𝑓(𝑥)𝑑𝑥 = { 0 0 0, 𝑖𝑓 𝑓(2𝑎 − 𝑥) = −𝑓(𝑥) Integration by parts: u x v x dx u x v x dx d u x dx v x dx dx Bernoulli’s rule of integration: If the 1st function is a polynomial and integration of 2nd function is known. Then ∫ 𝑢(𝑥)𝑣(𝑥)𝑑𝑥 = 𝑢 ∫ 𝑣 𝑑𝑥 − 𝑢′ ∬ 𝑣 𝑑𝑥𝑑𝑥 + 𝑢" ∭ 𝑣 𝑑𝑥𝑑𝑥𝑑𝑥 − 𝑢′′′ ∬ ∬ 𝑣 𝑑𝑥𝑑𝑥𝑑𝑥𝑑𝑥 + ⋯⋯⋯⋯ Where dashes denote the differentiation of u . Or ∫ 𝑢(𝑥)𝑣(𝑥)𝑑𝑥 = 𝑢 ∙ 𝑣1 − 𝑢′ ∙ 𝑣2 + 𝑢′′ ∙ 𝑣3 − 𝑢′′′ ∙ 𝑣4 + ⋯ ⋯ ⋯ ⋯ Where dashes denote the differentiation of u , vk denotes the integration of v, k times with respect to x. Vector calculus formulae: Position vector r x iˆ y ˆj z kˆ Magnitude r x2 y 2 z 2 iˆ iˆ ˆj ˆj kˆ kˆ 1 and Cross product of unit vectors iˆ iˆ ˆj ˆj kˆ kˆ 0 and Dot product of unit vectors Angle between two vectors Unit vector 3|Page cos A Aˆ A A. B A B iˆ ˆj ˆj kˆ kˆ iˆ 0 iˆ ˆj kˆ, ˆj kˆ iˆ, iˆ kˆ ˆj VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK ds dt d 2s a 2 dt V Velocity Acceleration ⃗⃗ = (𝑎2 𝑖 + 𝑏2 𝑗 + 𝑐2 𝑘) & 𝐶⃗ = (𝑎3 𝑖 + 𝑏3 𝑗 + 𝑐3 𝑘) For any vectors 𝐴⃗ = (𝑎1 𝑖 + 𝑏1 𝑗 + 𝑐1 𝑘), 𝐵 Dot product of two vectors A B a1 a2 b1 b2 c1 c2 ˆj kˆ iˆ Cross product of two vectors A B a1 a2 a3 b1 b2 b3 A B C Scalar triple product a1 A B C b1 c1 a2 a3 b2 b3 c2 c3 Trigonometric formulae: Identities sin 2 cos 2 1 1 tan 2 sec2 1 cot 2 cos e c 2 Compound angle formulae sin A B sin A cos B cos A sin B sin A B sin A cos B cos A sin B cos A B cos A cos B sin A sin B cos A B cos A cos B sin A sin B tan A tan B 1 tan A tan B tan A tan B tan A B 1 tan A tan B tan A B Transformation formulae 1 sin A B sin A B , 2 1 cos A cos B cos A B cos A B , 2 CD CD , sin C sin D 2sin cos 2 2 CD CD , cos C cos D 2 cos cos 2 2 sin A cos B 4|Page 1 sin A B sin A B 2 1 sin A sin B cos A B cos A B 2 CD CD sin C sin D 2sin cos 2 2 CD CD cos C cos D 2sin sin 2 2 cos A sin B VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Multiple angle formulae sin 2 A 2 sin A cos A sin A 2sin A 2 cos A 2 cos 2 A cos 2 A sin 2 A cos A cos 2 A 2 sin 2 A 2 sin 2 A 1 cos 2 2 1 sin 3 A 3sin A sin 3 A 4 Hyperbolic and Euler’s formulae e x e x sinh x 2 cos 2 A 1 cos 2 2 1 cos3 A 3cos A cos 3 A 4 cosh x e x e x 2 cos x eix e ix 2 cosh 2 sinh 2 1 ei cos i sin sin x eix e ix 2i Logarithmic formulae: log e A B log e A log e B log e x n n log e x log a a 1 A log e log e A log e B B log e B log a B log e a log a 1 0 log e 0 Solid geometry formulae: Distance between two points (𝑥1 , 𝑦1 , 𝑧1 ) 𝑎𝑛𝑑 (𝑥2 , 𝑦2 , 𝑧2 ) is x2 x1 y2 y1 z2 z1 2 2 l cos , m cos , n cos a b c , m , n . Direction ratios l a 2 b2 c 2 a 2 b2 c 2 a 2 b2 c 2 Direction ratios of a line joining two points (𝑎, 𝑏, 𝑐) = (𝑥2 − 𝑥1 , 𝑦2 − 𝑦1 , 𝑧2 − 𝑧1 ) Direction cosines 5|Page 2 VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK nth Derivatives of standard functions m mn D n ax b m m 1 m 2 ...... m n 1 ax b .a n n D n ax b n !a n Dn xn n! n 1 1 n !a D n 1 ax b ax b n n 1 n 1!a n . D log ax b n ax b n D n a mx a mx m log a n 1 n D n eax a n e ax D n sin ax b a n sin ax b n. / 2 D n cos ax b a n cos ax b n. / 2 D n eax sin bx c a 2 b 2 D n eax cos bx c a 2 b 2 n2 a cos bx c n tan b a eax sin bx c n tan 1 b n2 eax 1 Polar coordinates and polar curves: Angle between radius vector and tangent tan r d 1 dr or cot dr r d Angle of intersection of the curves tan 1 tan 2 1 tan 1 tan 2 1 2 tan 1 Orthogonal condition 1 2 2 or tan 1 tan 2 1, Pedal equation or p-r equation P r sin 1 1 1 1 𝑑𝑟 2 2 (1 = + cot ∅) = (1 + ( ) ) 𝑝2 𝑟 2 𝑟2 𝑟 2 𝑑𝜃 6|Page VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Derivative of arc length: In Polar: 𝑑𝑠 = √1 + ( ) 𝑑𝑥 𝑑𝑥 = √1 + 𝑑𝑟 In Parametric: 𝑠𝑖𝑛∅ = 𝑟 𝑑𝑦 2 𝑑𝑠 In Cartesian: 𝑑𝛳 𝑑𝑠 𝑑𝑠 𝑑𝑡 𝑑𝛳 2 1 𝑑𝑠 & ( ) 𝑟 2 𝑑𝑟 𝑑𝑦 𝑑𝑠 & 2 𝑑𝜃 𝑑𝑥 2 = √1 + ( ) 𝑑𝑦 𝑑𝑟 2 = √𝑟 2 + ( ) 𝑑𝛳 2 𝑑𝑥 𝑑𝑦 = √( ) + ( ) 𝑑𝑡 𝑑𝑡 𝑑𝑟 & 𝑐𝑜𝑠∅ = 𝑟 𝑑𝑠 Radius of curvature 3 (1+𝑦1 2 )2 In Cartesian form: 𝜌 = 𝑦2 3 In parametric form: 𝜌 = (𝑥̇ 2 +𝑦̇ 2 )2 𝑥̇ 𝑦̈−𝑦̇ 𝑥̈ 3 (𝑟 2 +𝑟1 2 )2 In polar from: 𝜌 = 𝑟 2 −𝑟𝑟 1 +2𝑟1 Pedal Equation: 𝜌 = 𝑟 2 𝑑𝑟 𝑑𝑝 Indeterminate Forms - L’Hospital’s rule: 𝑓′ (𝑥) 𝑓(𝑥) If 𝑓(𝑎) = 𝑔(𝑎) = 0 , then lim 𝑔(𝑥) = lim 𝑔′ (𝑥) 𝑥→𝑎 𝑥→𝑎 𝑓′ (𝑥) 𝑓(𝑥) If 𝑓(𝑎) = 𝑔(𝑎) = ∞ , then lim 𝑔(𝑥) = lim 𝑔′ (𝑥) 𝑥→𝑎 1 𝑛 1 lim (1 + 𝑛) = 𝑒 , 𝑠𝑖𝑛𝜃 𝜃→0 𝜃 , 𝑛→∞ lim 𝑥→𝑎 =1 lim (1 + 𝑛)𝑛 = 𝑒 𝑛→0 𝑥 𝑛 −𝑎 𝑛 𝑥→𝑎 𝑥−𝑎 lim = 𝑛𝑎𝑛−1 Series Expansion: Taylor’s series expansion about the point x a. y x y a x a y' 1! a x a 2! 2 y a '' x a 3 3! y ''' a .. Maclaurin’s Series at the point x 0 y x y 0 7|Page x ' x2 x3 x4 y 0 y '' 0 y ''' 0 y '''' 0 .... 1! 2! 3! 4! VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Euler’s theorem on homogeneous function and Corollary: u u x y n u (Theorem) x y x u u f (u ) y n ' x y f (u ) 𝜕2 𝑢 𝜕2 𝑢 (Corollary 1) 𝜕2 𝑢 𝑥 2 𝜕𝑥 2 + 2𝑥𝑦 𝜕𝑥𝜕𝑦 + 𝑦 2 𝜕𝑦 2 = 𝑛(𝑛 − 1)𝑢 (Corollary 2) Composite function: If z f x, y and x t , y t then 𝑑𝑧 𝑑𝑡 = 𝜕𝑧 𝑑𝑥 𝜕𝑥 𝑑𝑡 + 𝜕𝑧 𝑑𝑦 𝜕𝑦 𝑑𝑡 If z f x, y and x u , v , y u , v 𝜕𝑧 𝜕𝑢 = 𝜕𝑧 𝜕𝑥 𝜕𝑥 𝜕𝑢 + 𝜕𝑧 𝜕𝑦 𝜕𝑦 𝜕𝑢 𝜕𝑧 & 𝜕𝑣 = 𝜕𝑧 𝜕𝑥 𝜕𝑥 𝜕𝑣 + 𝜕𝑧 𝜕𝑦 𝜕𝑦 𝜕𝑣 If u f r , s, t and r x, y, z , s x, y, z , t x, y, z u u r u s u t x r x s x t x u u r u s u t y r y s y t y u u r u s u t z r z s z t z Jacobians: u u , v x J x, y v x u y v y and Multiple Integrals: Area A= dx dy - Cartesian form A Area A= rdrd -Polar form A 8|Page u x u , v, w v x, y , z x w x u y v y w y u z v z w z VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Volume V= dx dydz - Cartesian form V Volume V= zdx dy - by double integral A Gamma function: n e x x dx 2 e t t 2 n 1dt n 1 2 0 0 1 Beta function: m, n x n 1 1 x m 1 2 dx 2 sin 2 n 1 cos 2 m 1 d 0 0 Beta and Gamma relation: m, n m n 2 and 1 m n Vector Calculus: dr v (t ) dt Velocity d v d2 r a (t ) . dt dt 2 Acceleration The unit tangent vector dr Tˆ dt dr dt Angle between the tangents cos T 1 .T 2 T1 T 2 Component of velocity C.V v . nˆ Component of accelerations C. A a . nˆ Tangential component of acceleration T .C. A a . v Normal component of acceleration N .C. A a tangential component v , Where n̂ is the unit vector Gradient of grad = ˆ ˆ ˆ i j k x z z Unit vector normal to the surface n̂ Directional Derivative: D. D . nˆ 9|Page v v VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Angle between the surfaces 1 .2 cos 1 2 Divergence of vector field F f1i f 2 j f 3k . F divF f1 f 2 f3 x z z Curl of vector field F F curl F iˆ ˆj kˆ x f1 y f2 z f3 Solenoidal vector field div F F 0 Irrotational vector field Curl F F 0 . List of vector identities curl ( grad ) 0. div (curl F ) F 0. div ( F ) div F grad F curl ( F ) curl F grad F Reduction formulae /2 cos /2 n xdx 0 /2 0 0 n 1 n 3 n 5 .........1 when n is even n n 2 n 4 ..............2 2 n sin xdx n 1 n 3 n 5 .........3 1 when n is odd n n 2 n 4 ................1 m 1 m 3 ......... n 1 n 3 ......... m n m n 2 m n 4 .............2 m n sin x cos xdx m 1 m 3 ......... n 1 n 3 ......... m n m n 2 m n 4 .............. 10 | P a g e 2 when m and n is even other cases VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Differential Equations: Differential Equations dy Linear in y Py Q dx dx Linear in x Px Q dy dy Bernoulli’s P y Q yn dx Exact differential equation M N Mdx Ndy 0 with . y x Not exact differential equation Case 1 : If Mdx Ndy 0 and Mdx Ndy 0 Case 2 : If the differential equation is of the form yg1 xy dx xg 2 xy dy 0 Case 3: If 1 M N f ( x) or C N y x Solution/ substitution y ( I .F ) Q( I .F )dx C x I .F Q I .F .dy C divide by y n and Put y1 n z terms of N not containing x dy C M dx y constant I .F . 1 , Mx Ny 0 Mx Ny I .F . 1 with Mx Ny I .F . e f x dx or e Cdx I .F . e f y dy or e Cdy 1 N M f ( y ) or C M x y Case 5 : If the differential equation is of the form ' ' x n y n mydx nxdy x p y q m' ydx n' xdy 0 I .F . x h y k With Newton’s law of cooling T To C1e k t Case 4 : If Mx Ny 0 p h 1 q k 1 p' h 1 q' k 1 and m n m' n' Linear Algebra: Inverse of a square matrix A adj A . A1 A Rank of a Matrix A The number of non-zero rows in the echelon form of A is equal to rank of A Normal Form of a Matrix. Ir 0 0 0 11 | P a g e VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Gauss-Elimination Method The system is reduced to upper triangular system from which the unknowns are found by back substitutions. Gauss-Jordan Method The system is reduced to diagonal system from which the unknowns are found by back substitutions. Eigenvalues Roots of the characteristic equation A I 0 Eigen Vectors Non-zero solution x xi of A I x 0 Diagonal form 1 0 0 D P AP 0 2 0 0 0 3 Computation of power of a square matrix A 1 A n P D n P 1 Canonical Form V 1 y 2 2 y 2 3 y 2 ....... n y 2 1 2 3 n Nature, Rank and Index of Quadratic forms: positive-definite if all the eigenvalues of A are positive. positive-semi definite if all the eigenvalues of A are non-negative and at least one of the eigenvalues is zero. negative-definite if all the eigenvalues of A are negative. negative-semi definite if all the eigenvalues of A are negative and at least one of the eigenvalues is zero. indefinite if the matrix A has both positive and negative eigenvalues. Rank the number of non-zero terms Index the number of positive terms Signature the number of positive terms minus the number of negative terms 12 | P a g e VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Laplace Transforms: Laplace Transform of Standard Functions L tn 1 L 1 s n! , n 1, 2,3....... s n 1 Where n is a positive integer L e at 1 sa L e at 1 sa L sin at a s a2 L cos at L sinh at a s a2 L cosh at L u t 2 2 1 s s s a2 2 s s a2 2 e as L u t a s Properties of the Laplace transform: 𝐿{𝑓(𝑡)} = 𝐹(𝑠) 𝑓(𝑡) Translation L e at f t F s a (first Shifting Theorem) 13 | P a g e dn f t 1 n F s ds Multiplication by t L t Time scale 1 s L f at F a a Integration t 1 L f t d L f t 0 s Division by t f t L F s ds. t s n n VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Transform of a Periodic Function: If f (t) is periodic with a period T , then T 1 L f t e st f t dt . sT 1 e 0 Second Shifting Theorem: If F s L f t and a 0, then L f t a u t a e as L f t . Transforms of the derivatives: 𝐿{𝑓 ′ (𝑡)} = 𝑠𝐿{𝑓(𝑡)} − 𝑓(0) 𝐿{𝑓′′ (𝑡)} = 𝑠 2 𝐿{𝑓(𝑡)} − 𝑠 𝑓(0) − 𝑓′(0) 𝐿{𝑓 𝑛 (𝑡)} = 𝑠 𝑛 𝐿{𝑓(𝑡)} − 𝑠 𝑛−1 𝑓(0) − 𝑠 𝑛−2 𝑓 ′ (0) − 𝑠 𝑛−2 𝑓"(0) − ⋯ ⋯ ⋯ − 𝑓 𝑛−1 (0) Inverse Laplace Transform: Transform F ( s ) L f (t ) L tn n! s n 1 14 | P a g e f (t ) L1 F ( s) t n 1 1 L1 n n 1! s Where n is a positive integer L e at Inverse Transform Where n is a positive integer 1 eat L1 s a 1 sa L sinh at a s a2 a sinh at L1 2 2 s a L cosh at s s a2 s cosh at L1 2 2 s a 2 2 L sin at a s a2 a sin at L1 2 2 s a L cos at s s a2 s cos at L1 2 2 s a 2 2 VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Formulae on Shifting rule: 𝐿[𝑒 𝑎𝑡 𝑐𝑜𝑠𝑏𝑡] = 𝐿[𝑒 𝑎𝑡 𝑠𝑖𝑛𝑏𝑡] = 𝑠−𝑎 (𝑠−𝑎)2 +𝑏2 𝑠+𝑎 +𝑏2 𝑏 𝐿[𝑒 −𝑎𝑡 𝑠𝑖𝑛𝑏𝑡] = (𝑠+𝑎)2 𝐿[𝑒 𝑎𝑡 𝑠𝑖𝑛ℎ𝑏𝑡] = +𝑏2 𝑏 (𝑠−𝑎)2 −𝑏2 𝑠−𝑎 𝐿[𝑒 𝑎𝑡 𝑐𝑜𝑠ℎ𝑏𝑡] = (𝑠−𝑎)2 −𝑏2 𝑠+𝑎 𝐿[𝑒 −𝑎𝑡 𝑐𝑜𝑠ℎ𝑏𝑡] = (𝑠+𝑎)2 −𝑏2 𝐿 [(𝑠+𝑎)2 +𝑏2 𝑏 𝐿−1 [(𝑠+𝑎)2 𝐿−1 [ = 𝑒 𝑎𝑡 𝑠𝑖𝑛𝑏𝑡 ] = 𝑒 −𝑎𝑡 𝑐𝑜𝑠𝑏𝑡 +𝑏2 𝑏 ] = 𝑒 −𝑎𝑡 𝑠𝑖𝑛𝑏 ] = 𝑒 𝑎𝑡 𝑠𝑖𝑛ℎ𝑏𝑡 (𝑠−𝑎)2 −𝑏2 𝑠−𝑎 𝐿−1 [(𝑠−𝑎)2 2 ] −𝑏 𝑠+𝑎 −1 𝐿 𝑏 𝐿[𝑒 −𝑎𝑡 𝑠𝑖𝑛ℎ𝑏𝑡] = (𝑠+𝑎)2 ] = 𝑒 𝑎𝑡 𝑐𝑜𝑠𝑏𝑡 (𝑠−𝑎)2 +𝑏2 𝑏 𝐿−1 [ ] (𝑠−𝑎)2 +𝑏2 𝑠+𝑎 −1 𝑏 𝐿[𝑒 −𝑎𝑡 𝑐𝑜𝑠𝑏𝑡] = (𝑠+𝑎)2 𝑠−𝑎 𝐿−1 [ (𝑠−𝑎)2 +𝑏2 [(𝑠+𝑎)2 −𝑏2 ] = 𝑒 −𝑎𝑡 𝑐𝑜𝑠ℎ𝑏𝑡 𝑏 𝐿−1 [(𝑠+𝑎)2 −𝑏2 = 𝑒 𝑎𝑡 𝑐𝑜𝑠ℎ𝑏𝑡 −𝑏2 ] = 𝑒 −𝑎𝑡 𝑠𝑖𝑛ℎ𝑏𝑡 Convolution Theorem: Let f t and g t be piecewise continuous on 0, and F s L f t & G s L g t . t Then, L1 F s G s f u g t u du. 0 Numerical Methods: 𝑥𝑘+1 −𝑥𝑘 Regula Falsi formula: 𝑥𝑘+2 = 𝑥𝑘 − for k = 0,1,2,……… 𝑓(𝑥𝑘+1 )−𝑓(𝑥𝑘 ) Newton-Raphson formula: 𝑥𝑛+1 = 𝑥𝑛 − 𝑓(𝑥𝑛 ) 𝑓′(𝑥𝑛 ) for n = 1, 2, 3, …….. Newton’s Forward Interpolation formula: 𝑦𝑝 = 𝑦0 + 𝑝∆𝑦0 + Where 𝑝 = 𝑝(𝑝−1) 2! ∆2 𝑦0 + 𝑝(𝑝−1)(𝑝−2) 3! ∆3 𝑦0 + ⋯ ⋯ ⋯ 𝑥−𝑥0 ℎ Newton’s Backward Interpolation formula: 𝑦𝑝 = 𝑦0 + 𝑝∇𝑦0 + Where 𝑝 = 15 | P a g e 𝑥−𝑥𝑛 ℎ 𝑝(𝑝 + 1) 2 𝑝(𝑝 + 1)(𝑝 + 2) 3 ∇ 𝑦0 + ∇ 𝑦0 + ⋯ ⋯ ⋯ 2! 3! VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Newton’s General Interpolation formula (Divided difference formula): 𝑦 = 𝑓(𝑥) = 𝑦0 + (𝑥 − 𝑥0 )[𝑥0 , 𝑥1 ] + (𝑥 − 𝑥0 )(𝑥 − 𝑥1 )[𝑥0 , 𝑥1 , 𝑥2 ] + (𝑥 − 𝑥0 )(𝑥 − 𝑥1 )(𝑥 − 𝑥2 )[𝑥0 , 𝑥1 , 𝑥2 , 𝑥3 ] + ⋯ ⋯ ⋯ + (𝑥 − 𝑥0 )(𝑥 − 𝑥1 ) ⋯ ⋯ (𝑥 − 𝑥𝑛 )[𝑥0 , 𝑥1 , ⋯ ⋯ , 𝑥𝑛 ] Lagrange’s Interpolation formula: (𝑥 − 𝑥1 )(𝑥 − 𝑥2 )(𝑥 − 𝑥3 ) ⋯ ⋯ ⋯ (𝑥 − 𝑥𝑛 ) 𝑓(𝑥) = 𝑦 (𝑥0 − 𝑥1 )(𝑥0 − 𝑥2 )(𝑥0 − 𝑥3 ) ⋯ ⋯ ⋯ (𝑥0 − 𝑥𝑛 ) 0 (𝑥 − 𝑥0 )(𝑥 − 𝑥2 )(𝑥 − 𝑥3 ) ⋯ ⋯ ⋯ (𝑥 − 𝑥𝑛 ) + 𝑦 (𝑥1 − 𝑥0 )(𝑥1 − 𝑥2 )(𝑥1 − 𝑥3 ) ⋯ ⋯ ⋯ (𝑥1 − 𝑥𝑛 ) 1 (𝑥 − 𝑥0 )(𝑥 − 𝑥1 )(𝑥 − 𝑥3 ) ⋯ ⋯ ⋯ (𝑥 − 𝑥𝑛 ) + 𝑦 (𝑥2 − 𝑥0 )(𝑥2 − 𝑥1 )(𝑥2 − 𝑥3 ) ⋯ ⋯ ⋯ (𝑥2 − 𝑥𝑛 ) 2 +⋯⋯⋯⋯ (𝑥 − 𝑥0 )(𝑥 − 𝑥1 )(𝑥 − 𝑥2 ) ⋯ ⋯ ⋯ (𝑥 − 𝑥𝑛 ) + 𝑦 (𝑥𝑛 − 𝑥0 )(𝑥𝑛 − 𝑥1 )(𝑥𝑛 − 𝑥2 ) ⋯ ⋯ ⋯ (𝑥𝑛 − 𝑥𝑛−1 ) 𝑛 Numerical Integration: Trapezoidal Rule: 𝑥0 +𝑛ℎ ∫ 𝑓(𝑥) 𝑑𝑥 = 𝑥0 ℎ [(𝑦 + 𝑦𝑛 ) + 2(𝑦1 + 𝑦2 + ⋯ ⋯ + 𝑦𝑛−1 )] 2 0 Simpson’s (1/3)rd rule: 𝑥0 +𝑛ℎ ∫ 𝑓(𝑥) 𝑑𝑥 = 𝑥0 ℎ [(𝑦 + 𝑦𝑛 ) + 4(𝑦1 + 𝑦3 + ⋯ + 𝑦𝑛−1 ) + 2(𝑦2 + 𝑦4 + ⋯ + 𝑦𝑛−2 )] 3 0 Simpson’s (3/8)th rule: 𝑥0 +𝑛ℎ ∫ 𝑓(𝑥) 𝑑𝑥 𝑥0 3ℎ [(𝑦0 + 𝑦𝑛 ) + 3(𝑦1 + 𝑦2 + 𝑦4 + 𝑦5 + ⋯ + 𝑦𝑛−1 ) 8 + 2(𝑦3 + 𝑦6 + ⋯ + 𝑦𝑛−3 )] = 16 | P a g e VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Numerical methods for ODE’s: Taylor’s series expansion about the point x x0 . y x y x0 x x0 y ' 1! x0 x x0 2! 2 y x0 '' x x0 3! 3 y ''' x0 .. Taylor’s series expansion about the point x 0 y x y 0 x ' x2 x3 x4 y 0 y '' 0 y ''' 0 y '''' 0 .... Euler’s Method: 1! 2! 3! 4! y nE1 y n hf ( x n , y n ), n 0,1,2,3, Modified Euler’s Method: h yn 1 yn f ( xn , yn ) f ( xn 1 , ynE1 ) , 2 n 0,1, 2,3, Runge–Kutta Method k h k 2 hf xn , y n 1 2 2 Step1: Find k1 hf ( x n , y n ) ; k h k 3 hf x n , y n 2 ; k 4 hf x n h, y n k 3 2 2 1 Step2: Find y n 1 y n k1 2k 2 2k 3 k 4 6 Milne’s Method: Step1: Find f1 f ( x1 , y1 ), f 2 f ( x 2 , y 2 ) and Step2: Predictor Formula y 4( P ) y 0 Step3: Compute 4h 2 f1 f 2 2 f 3 3 f 4 f ( x 4 , y 4( P ) ) Step4: Corrector Formula y4c y2 17 | P a g e f 3 f ( x3 , y 3 ) . h f 2 4 f1 f 4P 3 VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Adams – Bashforth Method: Step1: Find f 0 f x0 , y0 , f1 f ( x1 , y1 ), f 2 f ( x 2 , y 2 ) and Step2: Predictor Formula y4P y3 Step3: Compute f 3 f ( x3 , y 3 ) . h 55 f3 59 f 2 37 f1 9 f0 24 f 4 f ( x 4 , y 4( P ) ) Step4: : Corrector Formula y4c y3 h f1 5 f 2 19 f1 9 f 4P 24 Modular Arithmetics: Set of Natural Numbers (N): {1, 2, 3, …..} Set of Integers (I) = set of natural, negative naturals and zero: 𝑵 ∪ −𝑵 ∪ {𝟎} Greatest common divisor: 𝒈 𝒐𝒓 𝒅 = 𝒈𝒄𝒅(𝒂, 𝒃) Relative Primes: 𝒈 𝒐𝒓 𝒅 = 𝒈𝒄𝒅(𝒂, 𝒃) = 𝟏 Division Algorithm: For integers a and b, with a > 0, there exist integers q and r such that 𝒃 = 𝒒 ∙ 𝒂 + 𝒓 and 𝟎 ≤ 𝒓 < 𝒂, where q: quotient, r: remainder 6. Euclidean Algorithm b a a b = q1 a + r1 r 1 = b – a q1 r1 a = q2r1 + r2 r2 = a - q2r1 g = d∙ gcd (a, b) = ax + by with x and y integers 7. Modular and modular class: 𝒎/(𝒂 − 𝒃) then 𝒂 ≡ 𝒃(𝒎𝒐𝒅𝒎), 𝟎 ≤ |𝒃| < 𝒎 𝒃 ≡ 𝒂(𝒎𝒐𝒅𝒎), 𝟎 ≤ |𝒂| < 𝒎 If 𝒂 ≡ 𝒃(𝒎𝒐𝒅𝒎) then 𝒂 − 𝒃 = 𝒌 ∙ 𝒎 8. Properties of modular arithmetic: 𝑎 𝑎 𝑎 𝑎 ≡ 𝑎(𝑚𝑜𝑑𝑚) ≡ 𝑏(𝑚𝑜𝑑𝑚) 𝑎𝑛𝑑 𝑏 ≡ 𝑐(𝑚𝑜𝑑𝑚), then 𝑎 ≡ 𝑐(𝑚𝑜𝑑𝑚) ≡ 𝑐(𝑚𝑜𝑑𝑚) 𝑎𝑛𝑑 𝑏 ≡ 𝑐(𝑚𝑜𝑑𝑚), then 𝑎 ≡ 𝑏(𝑚𝑜𝑑𝑚) ≡ 𝑏(𝑚𝑜𝑑𝑚) then for any 𝑐, 𝑎 + 𝑐 ≡ (𝑏 + 𝑐)(𝑚𝑜𝑑𝑚) 18 | P a g e VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK If 𝑎 ≡ 𝑏(𝑚𝑜𝑑𝑚) then for any 𝑐, 𝑎 + 𝑐 ≡ (𝑏 + 𝑐)(𝑚𝑜𝑑𝑚) If 𝑎 ≡ 𝑏(𝑚𝑜𝑑𝑚) then for any 𝑐, 𝑎 ∙ 𝑐 ≡ (𝑏 ∙ 𝑐)(𝑚𝑜𝑑𝑚) If 𝑎𝑐 ≡ (𝑏𝑐)(𝑚𝑜𝑑𝑚) 𝑎𝑛𝑑 𝑑 = gcd(𝑚, 𝑐), then 𝑎 ≡ 𝑏(𝑚𝑜𝑑 𝑚/𝑑) If 𝒂𝒄 ≡ (𝒃𝒄)(𝒎𝒐𝒅𝒎) and m is a prime number, then 𝒂 ≡ 𝒃(𝒎𝒐𝒅 𝒎) If 𝑎 ≡ 𝑏(𝑚𝑜𝑑𝑚) 𝑎𝑛𝑑 𝑐 ≡ 𝑑(𝑚𝑜𝑑𝑚), then 𝑎 ± 𝑐 ≡ (𝑏 ± 𝑑)(𝑚𝑜𝑑𝑚) If 𝑎 ≡ 𝑏(𝑚𝑜𝑑𝑚) 𝑎𝑛𝑑 𝑐 ≡ 𝑑(𝑚𝑜𝑑𝑚), then 𝑎 ∙ 𝑐 ≡ (𝑏 ∙ 𝑑)(𝑚𝑜𝑑𝑚) If 𝒂𝒄 ≡ 𝒃(𝒎𝒐𝒅𝒎) 𝒂𝒏𝒅 𝒄 ≡ 𝒅(𝒎𝒐𝒅𝒎), 𝐭𝐡𝐞𝐧 𝒂𝒃 ≡ 𝒃(𝒎𝒐𝒅𝒎) If 𝒂 ≡ 𝒃(𝒎𝒐𝒅𝒎), 𝒕𝒉𝒆𝒏 𝒂𝒏 ≡ 𝒃𝒏 (𝒎𝒐𝒅𝒎) If 𝐠𝐜𝐝(𝒎, 𝒏) = 𝟏, 𝒂 ≡ 𝒃(𝒎𝒐𝒅𝒎) 𝒂𝒏𝒅 𝒂 ≡ 𝒃(𝒎𝒐𝒅𝒏), then 𝒂 ≡ 𝒃(𝒎𝒐𝒅 𝒎𝒏) If 𝒂𝒃 ≡ 𝟏(𝒎𝒐𝒅 𝒏), 𝒕𝒉𝒆𝒏 𝒂 𝒊𝒔 𝒊𝒏𝒗𝒆𝒓𝒔𝒆 𝒐𝒇 𝒃 𝒂𝒏𝒅 𝒃 𝒊𝒔 𝒕𝒉𝒆 𝒊𝒏𝒗𝒆𝒓𝒔𝒆 𝒐𝒇 𝒂 Linear Diophantine equation: 𝒂𝒙 + 𝒃𝒚 = 𝒄, 𝒘𝒊𝒕𝒉 𝒅 = 𝒈𝒄𝒅(𝒂, 𝒃) 𝒉𝒂𝒔 𝒔𝒐𝒍𝒖𝒕𝒊𝒐𝒏 𝒊𝒇 𝒅/𝒄 (i) has d congruent solutions and if x0 and y0 are primitive solutions, 𝒃 then 𝒙 = 𝒙𝟎 + (𝒅) 𝒕, 𝒚 = 𝒚𝟎 + (𝒂/𝒅)𝒕, for positive integer t (ii) if d = 1 then it has unique solution Remainder theorem: 𝒙 ≡ 𝒂𝒊 (𝒎𝒐𝒅 𝒎𝒊 ), 𝒊 = 𝟏, 𝟐, 𝟑, 𝒘𝒊𝒕𝒉 (𝒎𝒊 , 𝒎𝒋 ) = 𝟏, 𝒊 ≠ 𝒋 Procedure to apply remainder theorem If 𝒎𝒊 , 𝒊 = 𝟏, 𝟐, 𝟑 are relatively prime Then the solution of 𝒙𝒊 ≡ 𝒃𝒊 (𝒎𝒐𝒅 𝒎𝒊 ), 𝒊 = 𝟏, 𝟐, 3 is 𝒙 = ∑𝟑𝟏 𝒃𝒊 𝑴𝒊 𝒚𝒊 where, Mi = M / mi with 𝑴 = ∏𝟑𝟏 𝒎𝒊 Mi𝒚𝒊 ≡ 𝟏(𝒎𝒐𝒅 𝒎𝒊 ) where 𝒚𝒊 𝒊𝒔 𝒊𝒏𝒗𝒆𝒓𝒔𝒆 𝒐𝒇 Mi under mod mi 11. Fermat’s little theorem: If p is any prime and p ∤a, then 𝒂𝒑−𝟏 ≡ 1 (mod p) or 𝒂𝒑 ≡ a (mod p) 12. Euler’s Φ function: If n is any composite number with prime factorization n = 𝒑𝟏 𝒎𝟏 X 𝒑𝟐 𝒎𝟐 𝑿 … ; then number of primes up to n is 𝟏 𝟏 𝟏 𝟐 𝚽(𝒏) = 𝒏 (𝟏 − 𝒑 ) (𝟏 − 𝒑 ) ⋯ ⋯ 13. Wilson’s theorem: Prime p divides (p − 1)! + 1 19 | P a g e VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK 14. RSA cryptosystem: If p and q are large prime numbers and a is any integer then, plain text M is encrypted to c by, 𝒄 ≡ 𝑴𝒆 (𝒎𝒐𝒅 𝒑𝒒) The public key will be = (pq, e) d the decryption key the inverse of e, then 𝒅 ∙ 𝒆 ≡ 𝟏(𝒎𝒐𝒅(𝒑 − 𝟏)(𝒒 − 𝟏)) then 𝑴 ≡ 𝒄𝒅 (𝒎𝒐𝒅𝒑𝒒). Curvilinear Coordinates: Curvilinear coordinates are often used to define the location or distribution of physical quantities which may be scalars, vectors or tensors. ̂ , then ⃗⃗⃗ = 𝒙(𝒖, 𝒗, 𝒘)𝒊̂ + 𝒚(𝒖, 𝒗, 𝒘)𝒋̂ + 𝒛(𝒖, 𝒗, 𝒘)𝒌 If 𝑹 (i) ⃗⃗⃗ 𝝏𝑹 ⃗⃗⃗ 𝝏𝑹 Tangent vectors to the u-curve, the v-curve and the w-curve are 𝝏𝒖 , 𝝏𝒗 𝒂𝒏𝒅 respectively ⃗⃗⃗ 𝝏𝑹 ⃗⃗⃗ 𝝏𝑹 ⃗⃗⃗ 𝝏𝑹 (ii) Scale factors 𝒉𝟏 = |𝝏𝒖| , 𝒉𝟐 = |𝝏𝒗 | 𝒂𝒏𝒅 𝒉𝟑 = |𝝏𝒘| (iii) Unit Tangent Vectors to the u-curve, the v-curve and the w-curve are 𝑇𝑢 = ⃗⃗⃗ 𝜕𝑅 ) 𝜕𝑢 ( ℎ1 , 𝑇𝑣 = ⃗⃗⃗ 𝜕𝑅 ) 𝜕𝑣 ( ℎ2 𝑎𝑛𝑑 𝑇𝑤 = ⃗⃗⃗ 𝜕𝑅 ) 𝜕𝑤 ( ℎ3 , respectively. Normal to the surfaces 𝒖 = 𝒖𝟎 , 𝒗 = 𝒗𝟎 𝒂𝒏𝒅 𝒘 = 𝒘𝟎 are 𝑇 𝑇 ∇𝑢 = ℎ𝑢 , ∇v = ℎ𝑣 𝑎𝑛𝑑 ∇w = 1 2 𝑇𝑤 ℎ3 respectively Unit normal vectors to the surfaces 𝒖 = 𝒖𝟎 , 𝒗 = 𝒗𝟎 𝒂𝒏𝒅 𝒘 = 𝒘𝟎 are ∇𝑢 ∇v ∇w 𝑁𝑢 = |∇𝑢| , 𝑁𝑣 = |∇v| and 𝑁𝑤 = |∇w| , respectively Polar Coordinates (𝒓, 𝜽) : Coordinate transformations: 𝑥 = 𝑟 𝑐𝑜𝑠 𝜃, 𝑦 = 𝑟 𝑠𝑖𝑛 𝜃 Jacobian: 𝜕(𝑥,𝑦) 𝜕(𝑟,𝜃) =𝑟 (𝐴𝑟𝑐 − 𝑙𝑒𝑛𝑔𝑡ℎ)2 : (𝑑𝑠)2 = (𝑑𝑟)2 + 𝑟 2 (𝑑𝜃)2 20 | P a g e ⃗⃗⃗ 𝝏𝑹 𝝏𝒘 VISVESVARAYA TECHNOLOGICAL UNIVERSITY, BELAGAVI MATHEMATICS HANDBOOK Cylindrical Coordinates (𝝆, 𝝋, 𝒛): Coordinate transformations: 𝑥 = 𝜌 𝑐𝑜𝑠 𝜑, 𝑦 = 𝜌 𝑠𝑖𝑛 𝜑, 𝑧 = 𝑧 Jacobian: 𝜕(𝑥,𝑦,𝑧) 𝜕(𝜌,𝜑,𝑧) =𝜌 (𝐴𝑟𝑐 − 𝑙𝑒𝑛𝑔𝑡ℎ)2 : (𝑑𝑠)2 = (𝑑𝜌)2 + 𝜌2 (𝑑𝜑)2 + (𝑑𝑧)2 Volume element: 𝑑𝑉 = 𝜌𝑑𝜌 𝑑𝜑 𝑑𝑧 Spherical Polar Coordinates (𝒓, 𝜽, 𝝋) : Coordinate transformations: 𝑥 = 𝑟 sin 𝜃 cos 𝜑 , 𝑦 = 𝑟 sin 𝜃 sin 𝜑 , 𝑧 = 𝑟 cos 𝜃 Jacobian: 𝜕(𝑥,𝑦,𝑧) 𝜕(𝑟,𝜃,𝜑) = 𝑟 2 sin 𝜃 (𝐴𝑟𝑐 − 𝑙𝑒𝑛𝑔𝑡ℎ)2 : (𝑑𝑠)2 = (𝑑𝑟)2 + 𝑟 2 (𝑑𝜃)2 + (𝑟 sin 𝜃)2 (𝑑𝜑)2 Volume element: 𝑑𝑉 = 𝑟 2 sin 𝜃 𝑑𝑟 𝑑𝜃𝑑𝜑 21 | P a g e