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Anonymous answered this
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My Textbook Solutions
Showthefree-bodydiagramofthegivensystemasinFigure(1)
General Chemistry
Solutions ➔
Physics for Scien…
Calculatetheforceactingonthegate.
Solutions ➔
F=yh,A
=(62.41b/Nr*)(10A)(51tx5Nt)
View all solutions
=15.60016
Calculatethecenterdistance.
¾=
Iss+
Ya
y
(;(SA)(SR))
8
+2.5A(SAxSA)
IA
2.5Nt)
(12.5M)(5AXSA+(1
=12.67ft
CalculatetheforceF.
=710(12At)A.
=(62.41b/A*)(12ft)(3Pt×4ft)
=11.2301b
FromFigure(1),takemomentatthepointO
{.M.=0
(15,6001b)12.67ft-
4
¡#+(50016)(18)-(11,23010)(})(3m)-F.(AR)=0
F=6326.7516
Therefore,thehorizontalreactiondevelopedonthegateCis6326.751b
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