A
)
m,
v1
the
=
=
Mz
=
V2
=
at
moving
150kg
mass
cases
a
velocity
calculate
,
30m51
of
the
velocity
:
stationary
is
car
of
car
following
the
in
car
100kg
mass
another
with
i
of
car
100
y,
?
=
112=2
30
.
150
0
momentum
total
Miu
before
=
Mz V2
=
t
,
100130 )
150 ( O )
+
+
(
45000
1011 ,
30
=
③
sub
-
EM
90th
-
24th
-
V2
,
5042
+
75
V22
-
( V2 -24 )
=
0
=
0
=
0
112=0
sub
V2
30
=
=
-
,
=
into
-24
'
-
(
rejected )
③
1.5124 )
6m51
,
V2
"
=
+75 V2
112.542+75 V2
+
6
-
V2
+2.251122 )
112--24
V
kinetic energy
v12 + tzmzv }
②
4500lb
-
V5
°
-①
1-21100711,2+1-2115071122
=
=
45000-4500 V2
=
187.5 V22
• .
15112
-30
1.5112
50 ( 900
=
45000
,
150×2
total
=
50130-1.5 V25 +75
=
45000
11
+
150 V2
15112
+
into
45000
11 ,
+
24ms
after
M2 V2
①
=
Yi
1011 ,
=
¥ Miu ? tzmz V22
¥1100) 30ft 0
+
10011 ,
=
total kinetic energy before
+
IOOV ,
=
300
300
M , V,
=
3000
from
total momentum
②
after
collides
of each
ii )
the
M,
U
,
11
,
=
=
=
car
100
is
moving towards
Mz
=
30
v2
?
V2
total
=
=
first
the
car
at
a
velocity of
150
-20
0
before
momentum
Milli
100 (301
M2 V2
+
1501-20)
+
0
Miv ,
=
100 Vi
75000
tzmiv?
50 vi.
=
sub
150 V2
+
①
-
+
+
¥ M2Vz2
75
V22
5042+75 V22
=
500
150 V2
KE after
=
501305+751205
M 2112
+
1.5 V2
-
momentum
+
1004
=
£ M2 V22
V12
=
①
1500=1
1500
=
=
KE before
+
total
=
V,
↳Miu ?
=
__②
1.5 V22
+
into ②
-
5VzF
1.
1.5 V22
+
2.251122+1.542
=
1500=3.7542
V2
1=20
=
V2
=
20
ms
sub
l
V2 -20
-
V,
V1
into
-1.5120)
=
-30ms
=
i.
-
=
V2 :
"
-30ms-1
"
20ms
①
after
20ms
"
iii
)
the
the
in
M
U
=
,
Mz
=
30
V2
=
v=
?
both
i.
forward
after
boy
the
boy
→
24ms
stone
the
velocity
have
'
in
stone
5kg
a
24m51
=
standing
50kg
mass
Mi + Mz )
250 )
(
v
=
cars
of
(
v
=
3000
t
momentum after
total
=
M2 V2
+
,
y
throws
car
20
3000
of
"
150
Miu
boy
20ms
first
the
as
total momentum before
A
of
velocity
a
direction
same
100
=
,
with
moving
is
car
'
stationary
a
with
velocity
a
thrown
is
boat of
of
mass
"
10ms
.
Find
.
-
,
↳
stone
boat
'
boy
boat
and
initially they
because
other
considered
be
will
remain
Boat
-
stone
,
1
system
→
1
system
there
systems
is
0
0
0
respect
Final
=
Momentum
Boat
Boy
=
(50+100)
-
15011
t
is
-
Boat
zero
Stone
+
v
Boy
by
momentum
=
=
equal
are
t
b- (
lo )
50
15011=-50
✗
-
=
¥
11=-0.333
i.
( singular
1 system,
are
cuz , there
then their velocity
movement
no
initial
,
/
→
momentum
Initial
Since
1
.
>
Boy
system
stationary as
as
velocity
is
-
of
0.333
-1
Ms
the
"
ms
boy
and
the boat
,
0
and
.
Stone
rigid body)
to
each
100kg
velocity
of
the
boat &