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L6 T3 2018-2019 MATHS IA mod 3

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HILLVIEW COLLEGE
TERM III 2018/2019
MATHEMATICS
I.A. – Unit 1 Module 3
๐Ÿ
LOWER SIX
TIME: 1๐Ÿ HOURS
Attempt ALL questions. Give non-exact numerical answers correct to 3 significant figures or 1 decimal place
in the case of angles in degrees unless a different level of accuracy is specified.
1.
(a)
(b)
√๐‘ฅ+3 −2
๐‘ฅ−1
=
(i)
Show that
(ii)
Hence evaluate Lim
1
√๐‘ฅ+3 −2
๐‘ฅ→1 ๐‘ฅ−1
[1]
4 − 9๐‘ฅ ๐‘ฅ < −3
The functions f is defined by ๐‘“(๐‘ฅ) = {
. Find
2๐‘ฅ + 3 ๐‘ฅ ≥ −3
(i)
Lim+ ๐‘“(๐‘ฅ)
๐‘ฅ→−3
(ii)
[2]
√๐‘ฅ+3+2
Lim ๐‘“(๐‘ฅ)
[2]
[2]
๐‘ฅ→−3−
Deduce that ๐‘“(๐‘ฅ) is discontinuous at ๐‘ฅ = −3
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[2]
(c)
Differentiate from first principles y=cos 2x
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[5]
๐‘˜
Find the value of k if ∫2 6(1 − ๐‘ฅ)2 ๐‘‘๐‘ฅ = 52
2.
(a)
(b)
The rate of change of the area, Acm2, of a circle is 6t2 – 2t + 1
[5]
(i)
Write down a differential equation.
[2]
(ii)
Given that the area of the circle is 11cm2 when t = 2, find A in terms of t.
[5]
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(c)
6๐‘ฅ
Using the substitution ๐‘ข = 3๐‘ฅ + 1, find ∫ (3๐‘ฅ+1) ๐‘‘๐‘ฅ
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[5]
3.
8
(a)
Find the equation of the normal to the curve ๐‘ฆ = ๐‘ฅ − 6√๐‘ฅ, ๐‘Ž๐‘ก ๐‘กโ„Ž๐‘’ ๐‘๐‘œ๐‘–๐‘›๐‘ก ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘ฅ = 4 [5]
(b)
The function y = ax3 + bx2 -12x + 13 passes through (1, 0) and has a stationary point where
x = -1. Find
(i)
the value of a and of b
[5]
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(ii)
the type and the position of the stationary points.
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[5]
๐œ‹⁄
(c)
Evaluate∫๐œ‹⁄ 2 3cosx + 2sin2x dx.
4
(a)
[5]
6
(i)
๐‘‘๐‘ฆ
Show that if ๐‘ฆ = ๐‘ ๐‘’๐‘๐œƒ, then ๐‘‘๐œƒ = ๐‘ ๐‘’๐‘๐œƒ ๐‘ก๐‘Ž๐‘›๐œƒ
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[3]
(ii)
1
The parametric equations of a curve are ๐‘ฅ = 1 + ๐‘ก๐‘Ž๐‘›๐œƒ, ๐‘ฆ = ๐‘ ๐‘’๐‘๐œƒ ๐‘“๐‘œ๐‘Ÿ − 2 ๐œ‹ < ๐œƒ <
๐‘‘๐‘ฆ
๐œ‹
2
Find ๐‘‘๐‘ฅ , simplifying your answer.
(iii)
[3]
Find the coordinates of the point in the curve at which the gradient is the curve is ½. [3]
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(b)
(i)
๐‘‘๐‘ฆ
−๐‘˜
The diagram shows a curve for which ๐‘‘๐‘ฅ = ๐‘ฅ 3 , ๐‘˜ is a
constant. The curve passes through the points (1, 18)
and (4, 3).
16
Show that the equation of the curve is ๐‘ฆ = ๐‘ฅ 2 + 2.
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[5]
16
2
(ii)
Find ∫ (๐‘ฅ 2 + 2) ๐‘‘๐‘ฅ
(iii)
Hence or otherwise find the volume, in terms of π, when the shaded region is rotated through
360° about the x – axis.
[5]
[5]
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