Important Equations in A Level Physics CIE
P2: Planning, analysis and evaluation
1
Choice of axes for
straight-line graphs
Relationship
Graph
y = mx+c
y against x
ln y against
ln x
lg y against
lg x
y = axn
3
4
m
c
n
ln a
lg a
Because...
ln y = n ln
x + ln a
lg y = kx +
ln a
Always add uncertainties, never subtract. Where quantities are:
• Added or subtracted, then add absolute uncertainties;
• Multiplied or divided, then add percentage uncertainties.
y = aekx
2
Intercept on yaxis
Gradient
Combining
uncertainties
Uncertainties and
logarithms
Error in gradient
ln y against x
k
ln a
logarithm likely value - logarithm smallest/largest value
error = (gradient of the best fit line) – (gradient of worst acceptable line)
Circular Motion (Unit 7 syllabus)
5
6
7
Angle in radians
π=
πππππ‘β ππ πππ π
=
πππππ’π
π
To convert from degrees to radians, multiply by
To convert from radians to degrees, multiply by
8
Angular velocity
9
Relating velocity and angular
velocity
10
Centripetal acceleration
11
Centripetal force
π=
34
567
567
;<=>?;@ ABCD?;EFGF<H
HBGF H;IF<
34
=
or
or
βK
βH
4
897
897
4
=
34
L
=2ππ
speed = angular velocity × radius βΉ π£ = ππ =
34@
L
3
π£
= π3 π
π
ππ£ 3
πΉ=
= πππ3
π
π=
Gravitational Fields (Unit 8 syllabus)
12
Gravitational constant G
13
Newton’s law of gravitation
14
Gravitational field strength g
15
Gravitational potential
16
Gravitational potential
energy
πΊ = 6.67 × 10Z88 ππ3 πΎπZ3
πΊππ
π3
πΉ πΊπ
π= = 3
π
π
The gravitational potential at a point is the work done per unit
mass in bringing a mass from the infinity to the point
πΊπ
π=−
π
πΊππ
π. π. π. = −
π
πΉ=
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18
π£3 =
Orbital speed v
ab
@
π3 =
Orbital period
or π£ =
34@
L
3
4π
π5
πΊπ
Oscillations (Unit 13 syllabus)
8
19
Period
Time (T) for a complete oscillation π =
20
Frequency
Frequency (f) is the number of oscillations per unit time π =
21
Equations of s.h.m.
π₯ = π₯7 sin ππ‘ or π₯ = π₯7 cos ππ‘
22
Acceleration of an oscillator
π = −π3 π₯
23
Velocity of an oscillator
or π£ = π£7 cos ππ‘ or π£ = ±π π₯73 − π₯ 3
24
Maximum velocity of an
oscillator
π£ = ππ₯7
25
Kinetic energy
26
Potential energy
27
Phase difference
e
1
πΈ = ππ3 (π₯73 − π₯ 3 )
2
1
πΈ = ππ3 π₯ 3
2
π₯
π‘
∅ = 2π ππ ∅ = 2π
π
π
Communication (Unit 16 syllabus)
28
Attenuation
29
Attenuation per unit length
30
Signal to noise ratio
31
ππ’ππππ ππ ππ΅ = 10πππ
wHHF<>;HBx< Ay
zF<=H{ xe |;}?F (~G)
10πππ
tu
tv
8
tu
z
tv
= 10πππ
ππππππ πππ€ππ
ππππ π πππ€ππ
Thermal Physics (Unit 12 syllabus)
The internal energy of a system is the sum of the random
Internal Energy
distribution of kinetic and potential energies of its atoms or
molecules
Δπ = π + π€
32 First law of Thermodynamics
33
Specific Heat Capacity
πΈ = ππβπ
34
Specific Latent Heat
πΈ = ππΏ
Ideal Gases (Unit 10 syllabus)
35
Boyle´s Law
pV=constant or π8 π8 = π3 π3
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L
36
Ideal gas equation
37
Pressure
38
ππ = ππ
π
1 ππ π 3 1
π=
= ππ3
3
π
3
1
3ππ
π
πΈ= ππ3=
(π = )
2
2
πw
Mean translational kinetic energy E
of a particle of an ideal gas
Coulomb’s Law (Unit 17 syllabus)
39
Œu Œv
πΉ=
Coulomb´s Law
40
Work done in moving a charge from the
negative to the positive plate
41
Electric Field Strength
πΈ=
42
Electric Potential
π=
•4Ε½• @ v
π=
Œ
•4Ε½• @ v
π
4ππ7 π
πΈ=
43 Field Strength (uniform field)
π
π
“
A
Capacitance (Unit 18 syllabus)
44
Capacitance
45
Work done in charging a capacitor
46
Capacitors in parallel
(all have same voltage)
47
Capacitors in series
(all have same charge)
48
Capacitance of isolated bodies
πΆ=
π
π
1
1
1 π3
π = ππ = πΆπ 3 =
2
2
2 πΆ
πHxH;? = π8 + π3 + π5 + β―
πΆHxH;? = πΆ8 + πΆ3 + πΆ5 + β―
1
πΆHxH;?
Electronics (Unit 21 syllabus)
=
1
1
1
+ + +β―
πΆ8 πΆ3 πΆ5
πΆ = 4ππ7 π
π
e
πx>H
=−
πB<
π
B<
πx>H
π
8
πΊ=
=1+
πB<
π
3
+
If V is slightly greater in magnitude than V-, then Vout
will have a magnitude equal to the positive power
supply voltage.
+
If V is slightly smaller in magnitude than V-, then Vout
will have a magnitude equal to the negative power
supply voltage.
πΊ=
49
Inverting Amplifier
50
Non-inverting Amplifier
51
The op-amp as a comparator
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53
54
55
Magnetic Fields (Unit 22 syllabus)
Magnetic Flux Density for a uniform
magnetic field
Magnetic Force on a current-carrying
conductor
Magnetic flux density for charged particles
Charged particles (Unit 22 syllabus)
Magnetic force on a moving particle at right angles to a
magnetic field
56
Electron traveling in a uniform magnetic field
57
Velocity of an undeflected charged particle in a region
where electric and magnetic fields are at right angles
58
Hall Voltage
59
Charge-to-mass ratio
60
Kinetic energy of electrons leaving the anode in a
deflection tube
π΅=
πΉ
πΌπΏ
πΉ = π΅πΌπΏ sin π
π΅=
ππ£
ππ
πΉ = π΅ππ£
πF π£ 3
= π΅ππ£
π
πΈ
π£=
π΅
π΅πΌ
π— =
ππ‘π
π
2πE;
= 3 3
πF π π΅
1
ππ£ 3 = ππE;
2
Electromagnetic induction (Unit 23 syllabus)
61
Magnetic flux F through area A
62
Faraday’s law
63
Magnetic flux linkage
ππ· = ππ΅π΄ cos π
64
Motional e.m.f
π = π΅ππ£
π· = π΅π΄
πΈ=
β(ππ·)
βπ‘
Electromagnetic induction (Unit 24 syllabus)
65
Sinusoidal alternating current
πΌ = πΌ7 sin ππ‘
66
Sinusoidal alternating e.m.f.
π = π7 sin ππ‘
67
Root-mean-square of an alternating current
πΌ@GC = πΌ7 / 2
68
Transformers
πC π›
=
πD πD
πΌD πD = πΌC πC
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Quantum Physics (Unit 25 syllabus)
πΈ = βπ or πΈ =
{E
69
Energy of a photon
70
Kinetic energy of a particle of charge e accelerated
through a voltage V
1
ππ = ππ£ 3
2
71
Einstein’s photoelectric equation
βπ = π· + π. π.G;•
72
De Broigle wavelength
π=
73
Difference in energy between two levels when a photon is
either emitted or absolved
βπΈ = πΈ8 − πΈ3 = βπ =
œ
β
ππ£
βπ
π
Nuclear Physics (Unit 26 syllabus)
74
Einstein energy-mass equation
75
Activity of a radioactive sample
76
Exponential decrease of a quantity (A/R/N)
77
Half-life
πΈ = ππ 3
βπ
= −ππ
βπ‘
π΄=
π₯ = π₯7 π (ZœH)
π‘8
3
=
ln 2 0.693
=
π
π
Medical Imaging (Unit 22 and 25 syllabus)
ππ
β
78
Maximum X-ray frequency
πG;• =
79
Attenuation of X-rays as they pass a uniform
material
πΌ = πΌ7 π Z
80
Half thickness
81
Acoustic impedance of a material
82
Fraction of the intensity of an ultrasound wave
reflected at a boundary
83
Thickness of bone
πβππππππ π ππ ππππ =
84
Lamour frequency
85
Frequency f0 of the processing nuclei
π₯8
3
=
•
ln 2
π
π = ππ£
πΌH
π3 − π8
=
πΌ7
π3 + π8
3
3
π3 − π8
=
π3 + π8
3
πππ π‘ππππ π‘πππ£πππππ ππ¦ π’ππ‘πππ ππ’ππ
πΔπ‘
=
2
2
π7 = πΎπ΅7
π7 =
ππ΅7
2π
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