Do the following study results test questions honestly and seriously!
1. Alya got the assignment to conduct a hydrostatic pressure experiment to find out
the application of hydrostatic pressure to a submarine. Using a U-shaped pipe
connected by a plastic hose filled with water. Then the funnel is inserted into
the water and pressed at a depth of 12 cm,
13cm and 14cm. Obtained the difference in the height of the liquid in the U pipe
consecutively are 11.50 cm, 12.40 cm and 14.40 cm.
Based on the experiments conducted, it is known that the deeper the depth of
an object, the greater the hydrostatic pressure. From this information, make a
possible problem statement to investigate hydrostatic pressure!
Answer:
-
Will the Hydrostatic Pressure at the same depth and at different positions be
the same?
How does depth affect hydrostatic pressure?
How does the density of the fluid affect the amount of hydrostatic pressure?
What is the working principle of hydrostatic pressure in the U pipe?
What affects the hydrostatic pressure value?
2. Randu wants to prove the principle of Pascal's law on a hydraulic pump using
miniatures made of injections of different diameters, namely small injections of
2 cm in diameter and large injections of 3 cm in diameter. The hose that
connects the small and large injections is filled with water. Then the small
injection is given a compressive force of 8 N, 10 N and 12 N. The proposed
hypothesis is that the compressive force on the sucker with a small crosssectional area is inversely proportional to the thrust on the sucker with a large
cross-sectional area. Help Randu to identify the variables and the operational
definitions of the variables for the experiment he is doing!
Answer:
The variables contained in this study are the cross-sectional area and the
applied compressive force. The cross-sectional area is the diameter of the tool
which in this study was an injection with two sizes, namely a small injection
with a diameter of 2 cm and a large injection of 3 cm. While the compressive
force is the force exerted on the object so that the changes that occur can be
observed. In this study, measurements were made in units of distance (meters,
centimeters, etc.) and force (Newton, Pascal, Joule, etc.). The research was
carried out by connecting large and small injections using a tube, in small
injections a variation of the compressive force was given to see the reaction
that occurred in the large injection.
3. Dinar received an assignment from his teacher to conduct an investigation
on Archimedes' Law. The formulation of the hypothesis proposed is that
the greater the volume of a submerged object, the greater the buoyant force
of the object and vice versa. The data obtained as follows
The mass of the block = 2.00 kg
Weight of block in air = 19.60𝑁
𝜌𝑎𝑖𝑟 = 1.000 𝑘𝑔/m3.
𝑉𝑏 dipped
The weight of the block in
the fluid
(N)
Lifting style:Fa = Wu - Wa
(N)
1
3
16,72
2,88
12,54
7,06
9,80
9,80
2
3
1
Answer:
The volume of the object is the difference between the volume of water before
the block is immersed and the volume of water after the block is immersed. The
results of the data on the volume of water immersed in the water are used to
calculate the amount of upward lift experienced by the beam with the equation
Fa =Wu-Wa. Wu is the weight of the block in air, while Wa is the weight of the
block in water. Wu can be obtained by operating the mass of the block and the
acceleration due to gravity. While Wa is obtained from the equation Wa = Wu
– Fa, where Fa is expressed by multiplying the density of water, the acceleration
due to gravity and Vb dipped.