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State
1. Solid
Methods
Shortcut
and
ImportantFormulae
definite shape.
o
volume and
has definite
it
which
arrangement.
substance in
have orderly
state of the
The
particles
State:
constituent
Solid
substances in which
The
Crystalline Solids:
Crystalline Solids:
Classification of
Network Crystals
ii. Covalent
Crystals
Crystals
i. lonic
iv. Metallic
arrangement,
Molecular Crystals
orderly
have
not
ii.
do
constituent particles
substances in which
The
the relative
Amorphous Solids:
points. This depicts
identical
arrangement of
dimensional orderly
three
A
Lattice:
Space
particles in the crystal.
arrangement of constituent
crystalline solid is called unit cel.
repeating structural unit of
Unit
um
1
2
Unit cell parameters
.Crystal
s
e
s
t
a
Cell: The smallest
systems:
Cubic
0
2
is
b
u
o
D
to goiul sroits
ed
(A)EE
sbibor fgiel
o
Orthorhombic
T
E
C
Crystal systems
T
H
.Types
M
Tetragonal
Monoclinic
3-HOS19-r
Rhombohedral
Triclinic
Hexagonal
sle
of Cubic Unit Cells: Simple, body centred (bcc)
&fi
(S)2
Isbeh:olqeaxo 101
and face centred (fec).
Total No. of Atoms per Unit Cell:
Simple cubic
8x=1
bec
fcc
8x+1-2
8x+6x-4o
nozoto
n
o
10slo
Solld Stato (85)
otween radius (r) of an atom and
elation between
Rela
edge length (a)
of cubic unit cell:
Simple cubic | bee
3
a
Coordination Number and Packing Efficiency
Simple
Type
cubic
s
e
Coordination
s
t
number
tive
Packing
52.4%68%
etticiency
tetrahedral voids = 2x No. of atoms
of octahedral voids = No. of atoms
Number of
Number
1gitgriveo
b
u
9222101slebul
related to edge length and atomic mass (formula mass) by the formula:
nXMM
of the crystal is
.Density
l
p=
n
o
is
bcc
PaxNA
Point defects
Iregularities exist around a point or an atom.
1
2
o
D
a. Stoichiometric defects (intrinsic or thermodynamic defects)
0
Vacancy defect: Non-ionic solids
vacant.
are
sites
lattice
some
of the
Arises when
in density of the substance.
decrease
in
Results
i.
T
E
C
Results
i.
M
T
H
D.
0
2
Interstitial defect : Non-ionic solids
interstitial site.
constituent particles occupy and
some
when
Arises
the substance.
in increase in density of
ii.
Frenkel defect: Ionic solids
cation) from its normal site
smaller ion (usually
of
delocalization
Arises due to site.
to an interstitial
defect.
Also called as dislocation
of the substance.
oidto busta
Does not affect the density
DCnottky defect:
Ilonic solids
u and anions from their lattice
h number oflscations
equal
Characterized by missing of
neutrality.
the substance.
Site to maintain electrical
in density of
decrease
defect and
in vacancy
ESults
(substitutional
hoOSt atoms
of
place
Impurity defects
lattice site in
present at the (interstitial impurity defect).
Arises when
are
a
atoms
foreign
eign
interstitial sites
purity defect) orat the vacant
gaewgoflol ari g
oidos
2S)
LoL3
LoL3
La
TI
x
Questlons
MHT-CET Exam
(86)
o
Non-Stoichiometric defects
c.
i.
MHT-CET 2
Which an
8.
defect
vacancies
Metal excess
maintaining electrical
to anionic
thus
due
arises
electron
defect
an
Metal excess a hole which is occupiedandbyimpart colour to crystals.
Leaving
called F-centres
balance. Sites are
Schottky defects.
interstitial sites.
Similar to
extra cations at
interstitial
of
presence
arises due to
present in another
Metal excess defect
an electron
by
maintained
neutrality is
s
t
site.
defects
Similar to Frenkel
transition
deficiency defect
i. Metal
variable valency 1.e., in
shows
metal
when
defect arises
Metal deficiency
b
u
lattice site and the
metals.
a cation from its
missing
of
to
due
occurs
The defect
the adjacent lattice site.
cation having high charge in
Multiple Choice Questions
MHT-CET 2004
1. Silicon is
(A) semiconductor
1
2
2. A metallic element has a cubic lattice. Each edge
is 2.5 g
The unit cells in 200 gof metal are
cm.
(B)1x 10
0
2
presence
o
D
(D)
1x
105
(A)52.40
11. How ma
(A) 1
12.
If a met
metal at
(A) 1.86
13.
Which a
(A)In th
(B) In th
(C) Forr
14. Which
(A) Vali
(B) The
(C) The
D)The
15. In body
MHT-CET 2013
1s
3. A metal has a fcc lattice. The edge length
unit cell is 404 pm. The density of the metal
2.72 g cm. The molar mass of the metal is (NA, Avogadro's constant 6.02 x 10 mol")
(A)40 g mol
(B)30 g mol
(C)27 g mol
(D)20 g mol
16. If thee c
MHT-CET 2015
*4. Select a ferromagnetic material from the followings.
(A)Dioxygen
(B) Chromium (TV) oxide
(C) Benzene
(D)Dihydrogen monoxide
17. Arrang
(A) bec
T
H
T
E
C
(A)
B)
T
6. Which among the following solids is a nonpolar solid?
(A) Hydrogen chloride
(B) Sulphur
(C) Water
p
g
(A) 38°
FCC ty
(A) 2
(C) fec
18. Which
MHT-CET 2016
*5. In face centred cubic unit cell, what is the volume occupied?
M
perc
10. The
D)In t
of the unit cell is 2 A. The density of the metal
C)1x 1022io
Which an
(A) NaN
(C) K2SC
9.
of the
(D)none of these
(C)conductor
(B) insulator
MHT-CET 2006
(A)1x10
is
s
e
Electrical
n
o
(A) NaCl
(A)Sch
)
dioxide
D) Carbon dioxide
3
33
chsegpe
ra89
MHT-CET 2018
7. In which among the following solids, Schottky defect is
NOT observed?
(A)ZnS
(B) NaCl
(C)KCI
(D)CsCl
C) Inte
MHT-CE
19. Calcula
volume
(A)3.2
20. Sodiun
sodium
(A)5.2
aBte
os21
Solld State (87)
MHT-CET 2019
Which among the tollowing solids shows Frenkel defect?
,
(B) CsCI
(A) NaCl
nercentage
(A)52.40%
1 How
ofunoccupied volume in simple cubic
cell is
(C)68.04%
(B) 32.00%
total constituent particles are present
in simple cubic unit cell?
(B)3
(C)4
(D)2
1f a metal crystallizes in bcc structure with edge length of unit cell 4.29x 10 cm, the radius of
metal atom is
(B) 1.07 x 107 cm (C) 3.2x 10
(A) 1.86 x 10 cm
cm
(D) 1.07 x 10 cm
many
s
t
b
u
13. Which among the following statements is true about Schottky defect?
(A)In this regular cation is replaced by different cation.
(B) this cation or anion moves from regular site to place between lattice site.
(C)Formation of metal alloy is example of this defect.
D) this defect cation and anion are lacking in stoichiometric proportion.
In
In
o
D
14. Which among the following statements is NOT true about amorphous solids?
(A) Values of physical properties change with direction of measurement
(B)
1
2
These are pseudo solids
super cooled liquids
behave like fluids
(C)These are
(D) These
0
2
is
15. In body-centred cubic cell the space occupied by constituent particles
(D)
68%
C)74%
(A) 38%
(B) 62%
10, if the constituent particles
FCC type unit is equal to
(A) 2
then
of crystal lattice are of identical size
T
E
C
(B) 3
(C)1
o die
total particles present in
(D) 4
decreasing order of packing efficiency.
trange following type of unit cells according to their
cubic
(B) fcc> bcc > simple
(A) bec> fcc> simple cubic
>
(D) Simple cubic bcc > fcc
(C) fcc > simple cubic> bec
observed in Brass?
the following defects is
impurity
Aamong
(B) Substitution
A)Schottky
g
D) Frenkel
C)Interstitial impurity
17. A
T
H
MHT-CET
0 091
lot
2020
density 19.3 g cm and
of noble metal having
g
38.6
the 1number of unit cells in
volum
(D)6.236 x 100
of one unit cell is 6.18 x
(C)6.180 x 10
(A)3.236
10
x 10
(B) 3.236 x
cm. What is the length of unit cell of
20. Sodium
radius 1.86 X 10
with
crysta
structure
allizes in bcc
sodium?
(D)4.3 x 10 cm
7,44 x 10 cm
A)5.26x
(C)
cm
(B)3.272 x
19. Calculate
the
10cm.
10 cm
10
is
s
e
(D)47.60%
(A)I
M
n
o
(C)AgCl
(D) KCI
mong the following
following nain
among
pairs of compounds
is
NOT
CaCO
isomorphous ?
(A) NaNOs and
(B) NaF and MgO
K;SeO4
and
K
SO,
(C)
(D) NaCl and KCI
Which
MHT-CET Exam Questions
37. An
Cal
(A)
cell?
type of in unit
(88)
(D)68%
space in bcc
percentage of void
(C)26%
the
21. What is
g?
(B) 74%
(A)32%
an element is 6 x 104
atom
of
one
mass
of
unit cell if
(D)2.4 x 10g
mass of an fec
(C)2.4 x
22. What is the
(A)4 x
38. Wh
10g
(B)24 x 10"g
102g
(C)
molecular solid?
NOT a polar
is
following
(D) SO20
the
1
HCI
23. Which among
CHa
(B)
(A)HS
crystal structure?
(D)52.4%
packing efficiency of fec
the
is
What
(C) 74.0%
24.
(B)47.6%
havine
(A) 68.04 %
an element with fec crystal
100
of
g
in
present
unit cells are
25. How many number of
pm?
g/cm and edge length 100
x 1025
OC)
density 10
(B)3x10
(A)4x 105
26.
Nickel crystallizes in a fec
nickel atom.
(A)0.1624 nm
s
e
D)1
(C)2x 105
s
t
radius of
is 0.3524 nm. Calculate the
length
edge
cell,
unit
type of
(B)0.1426 nm
b
u
o
D
28. An element crystallizes in bcc type having atomic radius 1.33
(A)4
B)2.17x 10
cm
x 10
cell is 4 g cm
cm, the edge length of unit
1
2
0
2
T
H
Calculate molar mass of the element
(A)22.0 g mol
(B)27.0 g mol
o
43. A
44. A
d
if edge
(D)23.12 g
forms fcc unit cell having
edge length 4
(C)33.0 g mol
10g
45.
A
*46. S
47. A
x 10
(D)36.0 gmol
34. Molar mass of an element is 60.22 g mol. What is the
mass of fcc type unit cell of an elemeu
(A) 1.0x 10g
(B) 4.0 x 10 g
C)2.0x
M
42.
(
32. An element crystallizes in fcc lattice with cell edge 250
pm. Calculate the density of
element. (At. Mass = 90.3)
(A) 19.20 g cm
(B) 38.40 g cm
C)48.40 g cm
cm
33. An element with density 2.8 g cm
41. W
ca
(D)2
30. Lithium crystallizes into body centered cubic structure. What is the radius of lithium
length of it's unit cell is 351 pm?
(A)75.50 pm
(B) 240.80 pm
(C)300.50 pm
(D) 151.98 pm
*31. The edge length of fcc type unit cell of copper having atomic radius 127.6 pm equal to
is
(A)331 pm
(B) 378 pm
C) 295 pmn
(D)361 pmn
T
E
C
Th
(A
C)2.66x 10 cm
(C)8
(B)1
40.
(A
(C
(A
(D)3.07x 10 cm
29. What is the number of atoms present per unit cell of aluminium having edge length 4 A?
cm
39. Dr
(D)0.1246 nm
(C)0.2164 nm
unit
unit cell, the density and edge length of
27. An element crystallizes bcc type of
an element?
and 500 pm respectively. What is the atomic mass of
(D)250.0
(C)125.5
(B) 150.0
olleba
(A) 100.1
cell will be
(A)4.08 x 10
is
n
o
its
(A)
(C)
x
D) 4.0 10
48.
g8
*35. Aluminium crystallizes in a face centred cubic structure,
its atomic radius 125
pm. What 1s
is
the edge length of unit cell?
(A)335.5 pm
B) 288.6 pm
(C) 280 pm
D)353.5 pm
36. Sodium crystallizes in bcc structure with radius 1.86 x
10* cm. Calculate the edge lenguh
unit cell.
(A) 6.20 x 10 cm (B) 4.29 x 10 cm (C) 3.72 x
10 cm (D) 8.05 x 10 cm
*49.
50. F
ent crystallizes in bcC type
eleme
Solld State (89)
crystal structure
Calculate radius of element.
with edge length
of unit cell 300 pm.
(A) 1.299 x 10 cm
oimo
ibor
6.920 x 10 cm
ii6)
(C) 1.440 x 10 cm
(D) 2.299 x 10
cm
That
is the volume of
mole of a crystalline
solid
having
oat edge
unit cell
unit
its unit cell contains 24 molecules?
length 16x 10 cm, it
37. An
I
e
cm mol
102.7 cm mol
(A) 159.3
(C)
39.
Dry ice i18 an example
(A) ionic solid
(C) metallic
ng
D) 142.1 cm mol
of
s
e
(B) covalent solid
(D) molecular solid
solid
s
t
The coordination number of
the sphere in cubic close packed
(ccp) structure is
(B) 4
(A) 8
40
C)6
of
41, What
is
cation is
(A) 4
(D) 12
the coordination number of cation in ionic
compound if the type of hole occupied by
cubic?
(B) 6
b
u
poC)3
(D)8
42. Xenon crystallizes in fec lattice and the edge length of unit cell is 620 pm. What is the radius of
atom?
(A) 536.9 pm
Xe
(B) 438.5 pm
43.A compound has fcc structure.
unit cell? (Molar mass = 98.99))
it
(A)8.780Å
4.
1
2
C)7.783 A
g
cm', what is the edge length of
D) 5.783 A
metallic element crystallizes in simple cubic lattice. If edge length of the unit cell is 3A, with
density 8 g/cc, what is the number of unit cells in 108 g of the metal? (Molar mass of metal =
A
g/mol)
A) 2x 104
(B) 5 x
0
2
1023
(C)2.7 x 102
has a bcc structure with cell edge of 288 pm,
AnWhatelement
an
the
element?
atomic mass of
(B) 25.89
is
(A) 77.68
T
E
C
crystallizes
ver atom?
an
D) 219.2 pm
If density of unit cell is 3.4
(B) 6.083 A
100
ge
o
D
() 265.5 pm
silver
(A) 121.91
pm
in foc structure.
D)
the density of element is 7.2 g
(C) 62.43
If edge length of unit cell
(B) 111.91 pm
1.33 x 100
(C) 137.04 pm
(D) 51.81
is 316.5 pm, what is the radius
D)
158.25
pmn
ement
T
H
ent?
M
th of
of
element is
edge of 500 pm. The density of the
crystallizes in a bcc lattice with cell
5 g cm. How manyatoms are present in 300 g of metal?
atoms
(B) 6.4 x 10
(A)3.2 x 10"
atoms
(D)12.8 x 10 atoms
C)1.6x 103 atoms
type of hole occupied by
What
ionic compound if the
is the
coordination number of cation in
c coord
cation is octahedral?
(D)4
47. A
Cn
cm.
A)6
49.Which
(B)3
asgo
C)8
be
amorphous solid?
among the following 18 an example of
(D) Magnesium
(A)Diamond
(C) Glass
(B) Camphor
S0.
cel1?
Howmuch
corner of bcc unit
(D) 1/2
each
upies
art of an atom
(A)1/8
(C) 1/6
(B) 1/4
n
o
is
(B) 404.0 cm' mol
65.
Exam Questions
fec unit cell?
(D)74% oreloofe
(90)MHT-CET
unoccupied space in
(C)68%
percentage of
edoe1
32%
nm. What is the
S1. What is the
(B)
17.32
radius
(A) 26%
structure with atomic
bec
with
crystallizes
(D) 40 nm
E
52. An element
nm
(C)29
cell?
of unit
nm
(B) 64
cm
is 24.99x 10-24
(A) 33 nm
volume of one unit cell
The
n
cell.
unit
ofpure
crystallizes in fcc type of
number of unit cells in 36 g
the
Calculate
53. An element
cm.
element is 7.2 g
the
and density of
sample of element.
(A)2.0 x 10
54. What is the
3.819 x
55.
C)2.0 x 1023
(B) 7.038 x
C)1.5276 x 10g
10g
108
ferromagnetic in nature?
Which among the following is
s
e
b
u
amorphous solid?
56. Which among the following is NOT an
57. Which of the following is ferromagnetic in nature?
(A) Gadolinium
67.
68
69
70
(C)Butter0 91 (D)Rubber
(B) Camphor
(A)Tar
10g
i
(D)Iron2 toi
(C)Water
(B) Benzene
(A)Oxygen
s
t
(D)7.638 x
n
o
is
sodium
mass of one atom of
sodium
if
cell
of
unit
mass of bcc type
10g?
(A)3.819 x
(D) 1.25 x
(B) 2.0 x 10
08
1021
66
o
D
(C) Water
(B) Oxygen
(D)Benzene
2 (A)
71
58. Which among the following elements when added to silicon forms P- type semiconductor?
(C) As
(B) Bi
(A) Sb
1
2
D) B
59. Which among the following crystal structures the edge length of unit cell is equal to twice the
radius of one atom?
(A) End - centred orthorhombic
(C) Body centred cubic
0
2
yiecsb
(B) Simple cubic
D) Face centred cubic
omg 007
0
60. Which is the number of atoms in 12.08 x
10 unit cells if an element crystallizes in bee
structure?
(A) 4.838 x 104
(B) 2.416x 1024
(C) 2.08x 10
(D) 1.208 x 1023
Sodium crystallizes in bcc type of crystal
lattice. If the edge length
of unit cell is 4.29 A, what s
the radius of sodium atom?
A
(A) 2.15
(B) 2.94 A
C) 4.29 A
3o e61.
T
E
C
aieo 62. How many unit cells are present in 1.00 cm' of aluminum
3.54 x 10 cm?
(A) 4.508 x 102
T
H
(B) 6.022 x 103
C)1.126
63 What is the density of iron crystalwhich crystallizes
=
gd beiq length 287 pm? (At. mass of Fe 56 amu)
(A)7.87 g/cm
M
(B) 6.07 g/cm
D) 1.86 A
A
crystal, if edge length
of unit cell3
x 102
72
73
74
7
(D) 2.254 x 102
in body centred
cubic structure with edge
C)7.07 g/cm
(D)6.87 g/cm
77
ireiA
7
64. Which is the radius of sodium tom if it crystallizes in
bcc structure with
4.29 x 10 cm?
edge length ofunit
un cell
bilo uotigoreto
(A) 1.61 x 10 cm
(B) 1.85x 10 cm
(C) 6.19 x 10 cm
(D) 2.30 x 10 cm
s
age
Date No.
65. What is
mass of unit
t
cell
of
(At mass of gold= 197 g mol) gold if it crystallises
neto
(A) 130.85 x 1023
(C) 32.71 x 103g
edgelength
in fcc structure?
Solid State
(91)
Y (B)
98.14 x
102 g
65.42
n
o
soD)
10
fecc structure
66. Gold crystallizes in fcc
with edge
(A) 198 pm
x 102
(B) 162 pm
length 396
r chloride
)(C)714pmpm, find atomic radius
crystallizes
dius of gold.
in to fec type
the edge ngth of unit
(D)
140 pm
of
c
ell
will be (Given crystal system.
(A) 9.889 Å
If density of
At. Mass
(B) 7.426 A
unit cell is 3.4 g
of Cucm
An element
(C) 5.783 A 63, CI-36)
crystallizes as
simple
cubic having
of an element?
D) 3.642 A
celledge length 5
(A) 261.5 pm
A.
What is the radius
(B) 176.8 pm
cm
g of pure
odium is
S
59.The edge length
of bcc type of
unit
y(C)
s
t
216.5 pm
of atom
2.144 g cm
b
u
C) 7.289 g cm
70. The number
of atoms in 100 g
(D) 5.189 g cm
of an fec crystal with
200 pm is equal
density 10g cm
to
and unit cell edge
length
(A)1x104
(B) 3 x 1034
xe(C)2x 104
71. What is the edge length
D) 5x 104
of
type
fcc
60 g respectively?
of unit cell having density
and atomic mass 6.22
g cm and
(A) 6.83 x 10
cm (B) 4.0x 10 cm
C)3.47 x 10cm
72. metallic element
(D) 8.0x 10 cm
crystallizes to bcc type
Calculate radius
crystal lattice, having
of
edge length of unit
of its atom.oriod
cell 5 AA.
(A)250.0 pm
B) 176.8 pmi
()261.5 pm
8, An
(D)216.5 pm
element (atomic
= 100 g/mol)
mass
having
the density
bcc
structure
has
unit cell edge 400 pm.
of the
or?
ice the
1
2
A
in bcc
(A) 2.144 g/cm
hat i
(A)
B) 10.376 g/cm
1025
o
D
What is
C)1.289 g/cm
aD) 5.188 g'cm
a cubic lattice with edge length ofunit cell 2 A. Calculate
the number of
of the metal, if density of metal is 2.5 g cm
7
(B) 6.25 x 105
(C) 6.40 x 1025
(D) 1.0x 1025
T
E
C
10.0x
0
2
element?goE
metallic element
has
unit cells in
200 g
A
radius of a
ne
sphere in simple cubic lattice is 3 nm. What will be the edge
cell?
length
ell is
(A)
9x 10 m
76. Silver
T
H
edge
M
What
(C)3x 10m
(D) 1.5x 10 m
face centred cubic structure, if radius of silver atom is 144.5 pm.
length of unit cell'?
7.Mass of unit
(B)
cell offan
an element is 415 x 10
Cmo(B)9.67
78.Metallic
What is
289.0 pm bait o (C)428.6 pmot gavol (D)333.7 pm
(A)7.32the density of element
is
of an unit
10m
(B) 6x
Crystallizes in
the edge
pm
tcell
s
e
(D) 250.0 pm
cell
element = 100 of an element is 400 pm.
Calculate the
g mol
density of unit
(B) 10.378 g cm
cell.(Molar mass of an
(A)
is
g/cm
g.
If edge length of unit cell
ox (C)1.18 gcml
a
is 3.50 x
10 cm.
m,
D)4.67 g/cm
oT 1ts
nent crystallizes FCC type crystal lattice. What is the radius of atomi edge length
unit cell
(A)113.2
ny aul 1o (D) 202.5 pm
pm is 405 pm?
if
(B)143.2 pm
(C)175.3 pm
XloL3
length of unitcel
having edge
crystal lattice
of
type
crystallizes in bcc
element?
cm
79. An element
radius of atom of an
(D) 1.905 x 10
the
is
What
x 10 cm
4.72
(C)
4.4 x 10 cm.
(B) 3.72 x 10 cm
Element A ocCupy
y 23
(A) 2.22 x 10 cm
form a molecule.
to
lattice
hep
in
crystallize
elements A and B
molecule is
80. Atoms of
(D) AB3
the formula of
(C)AB
of tetrahedral voids, (B) AB
ma
197 g mol, the mass
is
(A) AB
gold
mass
of
structure. If atomic
face centred cubic
81. Gold crystallizes in
is
(D) 3.9x 10 kg
of unit cell of gold (B) 3.25 x 10 kg (C) 1.3 x 10 kg
cm and densiity
(A)6.5 x 10kg
cell is 4.07 x 10
unit
the
length
of
fec lattice. If edge
82. An element crystallizes in
element.
the atomic mass of
is 10.5 g cm". Calculate
D) 106.6 gmol
(C)64.33 g mol
mol
10.66
g
(B)
mol
(A)67.41 g
pm, calculate the
radius of copper atom is 127.8
the
cell.
If
unit
fec
83. Copper crystallises with
= 63.55 g mol")
density of copper? (At. mass: Cu
8.9 g
cm
(C)4.4 g cm
(B) 1.89 g
(A)9.5 g cm
(92)MHT-CET Exam
94. How
Questions
s
t
b
u
85. The mass of fec type unit cell
(A) 1.047 x 10 g
(C) 1.048 x 10 g atom
atomb gitvsd flos
86. Which among the following types
and 'b'?
(A) Tetragonal
10
o
D
g. What is the mass
of one atom
s
(B) 2.09 x 10g atombo silf
g atomitooias102
(D) 4.19 x 10
1
2
0
2
2.
D)
Numb
Given
Mass
Volur
Mass
3
(C) Orthothombic
Nu
3. (C)
For f
Edge
D) Monoclinic
87. Copper crystallizes as face centered cubic lattice, with edge length of unit cell 361
Calculate the radius of copper atom.
(A) 108.6 pm
(B) 127.6 pm
condu
of copper?
of unit cells has bond angle equal to 120° between edges 'a'
(B) Hexagonl
(A)
Si and
(D) Metallic solid
(C) lonic Solid
of copper is 419 x
1.
cm
D)
84. Fullerene is an example of
(B) Molecular solid
(A) Covalent solid
0.53 g
(A) one
edg
95. The
density
(A) 246
n
o
is
s
e
pm.
Dens
imote) tesmele nA.a
ive (C)157.600e8
fom
NA
Mol
181.6 pmn
pmoroD)
88. An element crystallizes in bc structure. The number of unit cells of an element
in 4 g of it s
(Given: At mass = 40)
rdus s2stl eotmois 3km A B
fstorm
to
9.1xNA
toit
(A)2x0.1 Na
(B)0.2 xNA
c
1(C)
D)0.1 NA
J
T
E
C
o(e
T
H
(B) 353.5 pm
(C) 465.0 pm
D)253.5 pm
*90. Which among the following is NOT paramagnetic
in nature?
(A) Benzene
(B) Fe
C)Cu
pl
M
B)3
(C)
(D)Oxygen
nue
stoe
10c
B)
Chr
5. (C)
cell?0(A
opl
4r
(D) V8r
3
92. Bcc type of crystal lattice contains 1.208
x 10 unit cells. Howlo
present in these unit cells ?
many atoms of the elemenare
(A) 6.04 x 10
(B) 3.618 x
(C)1.208 x 103e
(D) 2.416 x 10
*93. The edge length of fcc unit cell
of xenon is 620 pm. What
is the radius of Xe atom?
(A) 235.166 pm
(B) 189.37 pm
(C) 209.87 pm
D) 219.23 pm
p
4.
mag
91. Which ofthe following formulae is used
to find edge length bcc
of
unit
(A)
Wel
n
89. Aluminium crystallizes in face centred cubic structure, having
atomic radius 125 pm. The edge
length of the unit cell of aluminium is
(A)250.0 pm
m
M.tt
Vol
6. (D)
Car
7. (A)
Na
8. (C
AGe
No.
(Date
ogl2
th of unit
cell
0
nt
many 1ithium atoms are
present
in a unit
0.53 g cm (At mass of Li = 6.94)
Solid State (93)
cell with
atom
nebr
one
leo
(B)
edge length
four
(A)
3.5 A and density
(C) two
length of bce type
95. Theedge
of unit cell
atomso(D)
of metal is
density is 2 g/cc ?
six
5 A. What
is the radius
(A) 246.5 pm
(B) 232.5 pm
of metal atom if it' s
(C)176.8
pm
94. How
cm
A occupy
atomsu
2/3
mol, the mass
(A)
I.
Ge
nductor
calculate the
are semiconductors
at high
temperature.
(D)
mass of one unit cell
id
of copper?
edges 'a
3. C)
Edge
o
n.Theedge
cell, n = 4
length, a = 404 pm
Density
. (B)
Ch
that density, (P)
T
E
C
M=
9pub
T
H
S. (C)
ldon to g080 iallso
10-1.0x
tu
to
1035
o
10 cm
nxM
CrO exhibit very strong
magnetic property. It can be permanently
It ontains larg number of unpaired electrons.
od
occupied
arbon dioxide
e tisg zinu
to
ogg pod
u ougge bioy
beigucon
jo omlog
by face centred cubic unit cell is
6 (D)
a
is non-polar solid.
aCl,KCI,
CsCl
C
(A).
cm
n
Volume
1.(A)
srt
belob
P-a NA2.72x(4.04x10x6.02>x10-27 gmolrl
magnetised.V)oxide i.e.
M
auh
0
2.NA
cm
Weknow
ma
element are
1
2
inu sno to fov
= 4.04 x
of metal, d = 2.72 g
NA=6.02 x
10 mol
Molar mass
ofthe metal, M =?
ell 361 pm.
g of it is
o
D
of
x density = 8 x
10x 2.5 = 20 x 1024
Number of unit cells in 200
g metal= mass of metal
200
Js9m 1o Jov ass of one unit cell 20x10-2410x
For fcc
4
s
t
b
u
a
edge length of unit cell = 2A =
2x 10 cm
Mass of metal = 200 g, Density
metal = 2.5 g cm
of
Volume of unit cell =
(edge length = (2 x 10 =
8x 10
Mass of one unit cell = volume
Given,
pen
which are bad conductors
of electricity
Hence, Si and Ge
are semiconductors at room temperature but a
mass of metal
Number of unit cells
m
s
e
SOLUTIONS
and density
is
D) 216.5 pm
kg
m
n
o
atomso
show Schottky defect.
glo
yigo bviog
(8).
to oiavge
on
it
oont,Hoal
Lal]
Sol
9.
Exam Questions
formula
aeand
similar chemical
have
They
identical.
comparable.
is almost
(D)
isomorphous substances cation radii are generally
Crystal of
and
anion
(94) MHT-CET
polarizability
10. (D)
i.e.
n
o
ratio of
cubic
cell-52.4%
simple
Volume occupied in
unoccupied47.6%
Volumeremains
12.(A)
ForBCC,
.av34.29*10"*-1.86
is
s
e
11.()
s
t
x 10* cm
4
cations in the crystal
vacancies caused by absence of anions and
The defect produces due to
lattice is called as Schottky defect.
18. (B)
17. (B)
16. (D)
15. (D)
(A)
b
u
13. (D)
19.(B)
19.3g cm
Density
No.
of unit cells in 38.6g
20. (D)
x 10
T1.86
=2
T
E
C
o
D
38.6g - 2 cm
Mass
Vol. of metalensity
1
2
of noble metal
0
2
cm
=.
Total vol. of metal
Vol. of one unit cell
2 cm
3.236 x
6.18x10" cm
1022
For bcc structure, r =
V3a=4r
r4x1.86x10
cm
a
4.3 x 10 cm
21.(A)
M
T
H
Packing efficiency in bcc type
of unit cell
Unoccupied volume or void space in 68%.
bec type of unit cell
is about 32 %.
22. (D)
InFCC, No, of atoms per unit cell -4
Mass ofunit cell
Mass of 4
atoms4 x 6 x
-24x 10"g-2.4x 10
23. (B)
CH4, there is no
In
24. (C)
separation of positive
10
g
g
and negative charges.
25. (D)
mulae
and
=(100 pm)
10 cm
Vol.
of unit cell
Vol.
of 100 g of an element
No.
eoup moxT Solid
State (95)
=
(100 x 100 cm)
Mass
Density
of unit cells in 100 g of an element
=
oniheto
26.(
For a fec type
of unit cell,
0.3524 nm
the crystal
27.(B)
In bec,
Volume of unit cell,
cm
5
pxaxN
cm)
a
4X1.33 x10% cm
0
2
1.732
3.07 x 10 cm.
a
29. (A)
10
a4Å
=
M
n=?
4x
T
E
C
27,
Pxa'XN
n
1
2
r-
=
cm, p
=
s
e
s
t
fog &.09 aesnio
x 104 cm
o
D
(C).2e
os i
od so
A
x6.022X I
2.7x(4x10
=3.85 =4oLxExDE
27
For bcc unit cell,
VS
O)8E
YSXS
-151.98pm
31.(D)
M
is
cels
2.7 g cm,
M
30. (D)
125
For foc type
32.(B)
a
250 pm
M 90.3
dolom 3o
unit cel
a
22
r(2/2)
- 127.6
m
2.5x 10 cm
mol,
n
o
4x125x10 X6.022 X10-150.5 g mol
28. (D)
For bec crystal,.
=
MX
b
u
x 10 cm
a = (5 x 10
10 cm
istoo
n= 2, p = 4 g cm
500 pm = 500 x 107
a
=
Total volume
Volume of one unit cell
10 cm
x10 unit
10 cm
=0.1246 nm
2.828
T
H
100g
10g cm
Mx
(for fec cell)
(2/2)=360.85
-361 pm
armuie
oesailleteCoho olamo prmulo
(C.8
(96)MHT-CET Exam
42. (D)
Questions
nxM
axN,
a
4x90.3
(2.5x10*' x6.022 x 10
Fo
709001 Joya
3840 g cm
p
33. (B)
cm, a-4x
p2.8g
M-2
(for foc),
n-4
nXM
p-
a'xN
M
34. (B)
10 cm,
PXa"XN
M
6.022 x
Molar mass 60.22 g mol contains
element contains 4 particles (FCC)
10
xgof
60.22x4
40 x 1023=4.0
6.022x103
a-r(2/2)
r=
125(2/2) = 353.5 pm
1
2
36. (B)
For bec unit cell,
r
a= -4x1.86x10
:.
1.732
37.(A)
a
T
E
C
300 pm =3x 10
cm
For bcc unit cell, r = YSa
4
1.732x3x10 cm
4
T
H
38. (C)
a
b
u
8
o
D
M
=
2
Mwo
45.
4.29 x 10 cm
46.
(1
1.299 x 10 cm
leg
i03d
4096x104
90t
Volume of I mole of a crystalline
solid
24
170.67x
170.67x
102 cm
1024 x 6.022 x 10
1027.77 x 10
41. (D)
47. 1
a
302
4096x 10 cm
4096 x 10 cm
Volume of 1 molecule
40. (D)
M
09
F
Volume of 24 molecules
39. (D)
44. (E
0
2
cm
16x 10 cm
Volume of one unit cell = a =(16 x 10
.
43. (D
.0-39d
Ox00E q
35.(D)
For fcc unit cell,
s
t
particles
x 10
is
s
e
2.8x(4x10 )x6.022x10-26.97-27g mol
n
o
102.7 cm mol
e
DateNo.
elb
b os
42.(D)
21
pmn
a620
For
620
219.2
2x1.414
43.(D)
g cm
n4,p3.4
a nXM
a
oklicylobedago
r=
fec unit cell,
,
M-98.99,
a=?
4x98.99
3.4x6.022x103
193.4 x 10
cm
5.783
o19durnosboeea
s
t
A
.(B)
a=3A =3x 10 cm
Volume ofthe unit cell
Mass
216x 10
g=l
unit cell
108
108 g
216x10- 5x
1023 unit
a
288 pm
p
2.88 x
=
(2.88 x 10
46. (B)
For fcc unit
T
E
C
cel,
r/
r316.5pm = 111.91
0
2
2x1.414
T
H aN
(6).e
aiiorgemerCitsd
M-25x125x10 x6.022x10-282.3 g mol
9g0n
282.3
o
(E)08
10 cm
(5 x 10 cm)= 125 10 cm
x
7.5g
cm, m 300 g,n=2 (for bcc cell)
P nMM
M - Pxa'xN
a'N
a
of
ousrgorol-o1
pm
S00pm =5x
M
allessioto
2800.
a=316.5 pm
47.(B)
cmn
le 1o loV
cm", n =
U9 7ia 1osqg9dsq amois 1o
PXa' xN 7.2x2.39x10x6.022x103
51.81
n
g
adto 2M
7.2 g
M
1
2
10 cm
cm =
2.39x10
2 (for bcc cell)
o
D
3
to alqmse oug to g ot i
cells.
45.(D)
a
b
u
SE.DE
(a) = (3 x
cm =27
x 104 cm
=27 x 10" cm° x10
8 g cm
=
216x 107g
of unit cell
gofmetal
913910g4010ret
uiloba)
oitongaitiet
ogyAO
jsteW
n
l0eoy
3om
2
10 atoms bgnol ogb 0oal otdiy olgrale a
300 g of
metalcontains 6.022x10x3006.399 x 10 atoms = 6.4 x 10 atoms
ntains 6.022 x
282.3
is
s
e
(Ce
x 10 cm
a5.783
n
o
pmn
pxN
-
Solid State(97)
no
MHT-CET Exam
(98)
60. (B
In
Questions
octahedral void is 6.
48. (A)
number of an
coordination
The
N
n
o
49. (C)
50. (A)
51. (A)
Packing efficiency
For fec unit cell,
Unoccupied space 26%
= 74
s
e
52. (D)
For BCC,
17.32
0.4330 x a
a
17.32
0.433
s01
53. (C)
Vol. of element
No. of unit cells in 36 g
368 5 cm
7.2 g cm
of pure sample of element
54.(D)
Mass of bcc unit cell Mass of two atoms
. Mass of boce unit cell of Na 3.819x
55. (D)
T
E
C
1
2
0
2
No. of atoms per bec type of unit cell,
n= 2
98
1023 x 2
7.638 x 10
g
T
H
56. (B)
57. (A)
Gadolinium- ferromagnetic
Oxygen- Paramagnetic
Water, Benzene Diamagnetic
58.(D)
2
61.
F
62.
(E)
6A8-
o
D
63.
01
Total Vol. of element
Vol. of one unit cell 901
5 cm
x 1023
x10-Cm2.0
24.99
n 0tx 28.)
Mxa
M
(EO3
mg &o1t
O-Paramagnetic
Benzene, water Diamagnetic
Fe- Ferromagnetic
s
t
b
u
40
Mass
Density
is
%
12
3lso
01x
64.
sinu oo1 10
mg
M
(81.4
65.
00s
M
When a trivalent impurity (B, Ga, In, Al) are
mall
added to a pure semiconductor
(Si, Ge) in s
amount results in p-type semiconductor,
a
59. (B)
In a simple cubic lattice, edge length (a)= 2r
ttoooioc
oc
66.
o0.(B)
cach unit
In bee,
cell has 2 atoms.
No. of atoms
per unit cell
No. of atoms
12.08x 1023
x 1023
24.16
Solld State(99)
No. of atoms
No. of unit cells
=
No. of atoms-
structure, 4r
bee
For
3xa-
3
2 x4.291.857
10
--3.54
(3.54 x 10
x
No. of unit
cells=
of Aluminium
Ol.
Vol.of
unit cell
I cm
Cm
4.436x103
63.(4)
nXM
287 x 10
For BCC,
001eS
m 287x 10 cm
n=2
1.423x1014.23
64. (B)
BCC structure,
3
=
a
1
2
112
1.423x10' x10
T
E
C
0
2
1.732x4.29x101.85x10 cm
65.(A)
I
of mole
S
Mass
T
H
M
S
(6.022 x
10 atoms)
197
has 4 atoms.
So mass
of gold
66.
of Gold atoms 197 g/mol
Mx
otxox 01x005)
of 1 atom of gold. 6.022x103
FCC cell
nall
102
o
D
005
112 7.87 g/cm
112
4r
b
u
2.254 x
FO1SS0.0xotxko
2x56
6.022x103 x (287x 10-10
In
s
t
ig 002A2e
4.436 x 10-2 cm
DensityN,xa
s
e
1.86 A
cm
=
in unit cell
197 X4
6.022x10
ORESO
D)
In fcc
structure
4r-2a
414x396
is
a
62.(D)
a
139.98-140 p
n
o
2.416 x 104
61.(D)
1.3085 x 10
g
130.85 x
10g
(100)MHT-CET Exam Questions
12
67. (C)
Density (d)
nxM
N
4x99
3.4
on
[CuCl 63 +36 99)
x6.02x10
to.o
0
396
is
3.4x6.022x10
a193.47 10x 1024
cm
a
-5.78x
Edge length (a)
uto
68. (D)
length (a)
For simple cubic unit cell; edge
pm
500
=
5
A=
Edge length (a)
r-
500pm
=
s
e
s
t
2r
250 pm
b
u
2
69. (D)
Edge length of bcc type cell
M=100 g mol
nxM
Density (P)
pm
400
64x10 x6.022x10
70.(D)
Density= nXM
Density
1
2
0
2
4xM
(200x10)yx6x103
10X8x100 x6x103
M
T
E
C
g will contain
=
(A)
=
0xT8s
- 5.189 g/cm
O101&60A
a xNo
10
o
D
allsa inu to so
2x100
(400x100} x6.022x 103
200
100
opd o4
5.78A
=
O8)O1x
01x661
1ulouzie 908
12 g/mol
6x10 x100
x 103= 5 x 10
12
SSo.
atoms
71. (B)
T
H
Density=
turo0KSS00)
1orae tRi
2mo1a bloD10 slom 1
aXN
6.22
M
nxM
(A) 2
to22d
4x60
ax6.023x10
240
6.22x6.023x10
-64.06 x 104
-4x 10 cm
n
o
o
2400
xCc03 9u
6.22x 6.023 x10
ri blon to ay
g
7
ate
72.(D)
o
or iFor BCC, 3
a
=
3x5x10-10
4
2.165 x
e0.c
r-
4rnolb
TSolld State (101)
lotep
roy bodosor ow
is
100=r
216.5 x 10* m=216.5 pm
73. (D)
Density p
=
axN
2x100
200
64x6.022 x10
200
Number of unit cells in 200 g of the metal
2.5(2x10 cm)
o
D
200
2.5x8x10*
(A).a
75. (B)
I=3
1
2
a-2
nmn
a= 2(3)=6 nm =
76. (A)
For FCC,r
=
.
T
E
C
6x
5.188 g/cm
=
b
u
74.(D)
For simple cubic lattice,
s
t
sAat oluoolontougo
(400x1010y x6.022x10
r
s
e
XM
n=2
For bcc;
-200104 = 1.0x10
20
O30.20xot0
20
Tomg 2.0013
10 m
0
2
-0.3535 a
144.5 0.3535 a
a = 408.7 pm
0
77.(B)
Mass of unit cell
a
Volume of unit cell i.e.
Density
T
H
415x10
415x104
42.875 x104
(3.5x10
SS
- 9.67 g/cm
AA
78.(B)
For FCC,
M
79.(D)
0.3535
DCC Crystal,
xa
=0.3535 x
405-
143.167 pm
ls
moo3oaosM
epg inaogroH
ofg bered asf alfey acs lo
ip
of
0Ci
wsd
10
x
4.4 x 10=1.905 x
433 x a 0.433
g i
n
o
o
e(102)
MHT-CET Exam Questlons
atom. Since
with each
associated
voids
nere are two tetrahedral
the ratio of A and B is,
2A B
88.
tetrahedral.
vo
A OCCupy
80. (C)
2x 1
M
Ratio of A: B = 4:3
A4B3
Formula of molecule is
81. (C)
6.022 x 10 particles
Since, 197g of gold =
gold = 4 particles
xgof FCC crystal of
197x4
x 10" g= 0.1308 x
130.8
X
6.022x10
82.(D)
10.5
a'N
4xM
(4.07x10yx6.022x10
426.29
83. (D)
nM
a'N,
a
T
E
C
T
H
0
2
10
x
10
2820.02
20
cm
cm
4x63.55
47.25x10x6.022x10
25
M
-3oV
-8.934 g cm
28.451
O1&218
84. (A)
85. (C)
Since it is FCC type unit cell, n = 4
Mass
of one atom of Cu
419x104
4
- 1.0475 x 10 g atom
(a).e
86. (B)
Hexagonal types of unit cells has bond angle equal
to 120° between edges 'a' and D
87.(B)
For FCC crystal, r=
90
91
91
2E9
2
3.615 x
kg
89
9
4x1.278x10 cm
47.25
P
1
2
M=106.57 g mol
=
x 10
o
D
nM
P
s
t
b
u
10kg=
1.3
is
s
e
4:3
n
o
EEEOsECO
361-127.6
pm
88.(C)
anoitulos
.4XNA particles
4gof metal contains 4XN
40
voids,
Solld State (103)
=0.1 x NAA particles.
Particlesoso5iuo
n-2
hem
crystal,
For bcc
2
particles El
0.1 xNA particles
unitcell
=X
olredb lebieo
9.(B)
oitnloefabioloo
=
a
For FCC,
21.414*125
353.6 pm.
s
diamagnetic while
others are paramagnetic
91.(A)
Relation between edge length
4r
a
(a) and radius (T) in
Crystal lattice
For FCC
I2
94.(C)
=
1
2
unit cell,
0
2
4
4
T
E
C
onoolA g.3 bipil
e
biupt
0
2
teoi9gpr srizagile
viogorg
0.53x 6.022x102 x (3.5x10 )" Aonytulos a
T
nH
M -1.752500
M
25.81x0.53
6.94
2
BCC crystal
5.D)
b
u
io
BCC is given .252.
by
biupis
nM
-PN,a
T
02 nt
0uloe oul ovode 20g sr to qweeie
x620-219.20
N,a
For
s
t
in nature. 0
contains 1.208 x 10 unit cells.
ofcrystal is BCCn=2
toiulo2 biloe
No. of atoms
present in BCC unit cellsg larus muihoe g.s 5iloe
nt bipe
2x1.208 x 10=2.416 x 1023
atomseyolle istoM 39 biloz ai biloe
Type
93.(D)
s
e
o
D
1838
92.(D)
is
touoeguosgo1915
90.((A)
Benzene is
13.68
6.94
n
o
unit cells.
o
6.94
= 1.97iou
allsp a olotsg
20096
30 oue1
e
structure,
om=0.433 x 500
okoa to teoiteogno
19
soga
2tool
to-giee
pm10.Piopil
O000to
odt 1e
imoitoh fop
sotsiss
2. Solutions
Shortcut
ImportantFormulae and
Methods
of the particlesof
Depending on the sizes
components.
two or more
Solutions are the mixture of mixtures are classified into three types
components of the solution, the
1. A coarse mixture
2. A colloidal dispersion
sugar
3. A true solution
solution of NaCl or
a
e.g.
solution:
Homogenous
starch
colloidal solution of
Heterogenous solution: e.g. a
Different Types of Solutions
s
t
Gas in gas e.g. air
mixed with Na gas
ii. Liquid in gas e.g. CHCl
fumes, smoke
i. Solid in gas. e.g.
i.
onule
b
u
Liquid Solution
water
Gas in liquid e.g. CO2 in
Alcohol in water
ii. Liquid in liquid e.g.
NaCl or sugar in water
ii. Solid in liquid e.g.
i.
Solid Solution:
o
D
metal
Gas in Solid e.g. H2 gas in palladium
amalgam
sodium
ii. Liquid in solid e.g.
such as brass, bronze
ii. Solid in solid e.g. Metal alloys
1
2
is
s
e
Gaseous solution
n
o
Solubility of Gases in Liquids:
a
temperature is proportional to the
Henry's law The solubility of gas in a liquid at constant
pressure of the gas above the solution.
SocP or S=Ku
S
Where,
P
=
xP
0
2
Solubility of a gas in mol
dm
Pressure in bar
KH= Henry's law constant
Colligative Properties:
The property of a solution which depends on the total number of particles of the solute
(molecules, ions) present in the solution and does not depend on the nature
or chemical
composition of solute particles is called colligative property of the solution.
e.g. (a) lowering of
relative lowering of vapour pressure of a solution (b) elevation
in the boiling point (C)
depression in the freezing point (d) osmotic pressure.
T
H
L.
M
T
E
C
Lowering of Vapour Pressure
.Vapour pressure The pressure exerted by the vapour
of a liquid when it 1s
equilibrium with the liquid phase at
a constant temperature is called
the vapour presSu
of the liquid.
Lowering of vapour pressure
AP:
Raoult's law: PsolnXPo,
Po=vapour pressure of pure
X1
solvent
mole fraction of component
in the solution
(C20
P--W,M
Po
wM
Thus, the relative lowering
of vapour pressure is
equal to the mole fraction
of the so
i.
of
Solutions (105)
Elevation of Boiling Point
he elevation in the
The
boiling point of a
solution
hoiling point of the
souttonand the pure solvent is defined as the difference between e
at a given pressure.
. If To and T are the boiling
points of a pure solvent
and a solution, then the elevauon
boiling point, AT,= T-To
"
Kb.m
Ebullioscopic constant, m
molality
KxX1000
ATb
Where, Kb
ATb
s
e
ii. Depression of Freezing Point
The depression in the freezing point of a solution
is defined as the difference between
freezing points of a pure solvent and that of the
solution.
o
To-T
AT
AT
s
t
(T<To)
Kr. m
Cryoscopic constant, m = molality
x1000
Where, K
KxW
KWxM2
AT
iv. Osmotic Pressure
Since ti
MRT,
=
Tt2,
o
D
The solutions having same osmotic pressure are called isotonic
Isotonic Solutions:
solutions.
T1
M
=
1
2
T2
M2
M2RT
0
2
sribero
If the solutes are present in equal volumes of the solutions, then,
Vi
n
V2
n2
T
E
C
the
b
u
8
b0
Units of K= K kg mol
n
o
is
WxM,
Units of Ka-K kg mol
having equal volumes, the number
Hence isotonic solutions at same temperature and
must be equal.
moles or number of molecules of two solutes
one having a lower osmotic pressure is said
M2 then, Mi < M2 or
Hypotonic Solution: Among two solutions,
Hence if concentrations are Mi and
to be hypotonic to another.
nbebrtog
n n2.pn
T
H
higher osmotic pressures is
Among two solutions, one having
n2.
another. Hence, M1> M2 or nj>
said to be hypertonic to
Hypertonic Solution
M
Osmotic Pressure
MRT
RT
vrgilas
:
of Solution
and Concentration
othe obsle
(Where, M = Molarity)
M2
WRT (Where, W2 - Mass of solute,
M,V
wl&ooiA)
ot av (0)
Molar mass of solute)
ovatelolo2.01
11
MHT-CET Exam
Questions
(106)
Multiple Choice
Questions
12
non-electrolyte
a
solution
of
molal
MHT-CET 2004
(D)0.093°C
(C)0.93°C
0.05
point ofa
The freezing
(B) 1.86°C
1.
in water is
n
o
(A)-0.093°C
1sotonic with 10 cane
is
solution
aqueous
MHT-CET 2006
per litre, if
urea dissolved
of
amount
the
(D) 16.7 g/L
urea- 60)?
2. What is
g/L
wt.
(C)17.54
of
(mol.
sugar solution
(B) 19.2 g/L
(A) 200 g/L
MHT-CET 2007
colligative
following is not a
3. Which of the
boiling point
(A) Elevation in
(C)Osmotic pressure
sulphate
(D)magnesium carbonate
(A)potassium chloride
(C) magnesium sulphate
1.5 g of
o
D
a non-volatile solute (mol. wt.= 60) in 250 gof
Dissolution of
molal depression constant of the solvent.
point by 0.01°C. Find the
5.
1
2
(C)0.0001
(B)0.001
(A)0.01
MHT-CET 2015
a solvent reduces its freezing
D)0.1
litres
of solute, mass of solute and volume of solution in
0
2
6. If M, W and V represent molar mass
respectively, which among following equations is true?
MWR
(A) T=
TV
(B) TIMR
T
E
C
*7. van't Hoff factor
wV
s
t
b
u
caused by
depression in freezing point is
4. Maximum
(B) sodium
MHT-CET 2010
s
e
property7
vapour pressure
(B) Lowering of
(D) Freezing point
MHT-CET 2008
is
(C)
TWR
n=-
VM
(D)
RTRV
WM
of centimolal solution of Ka[Fe(CN)%] is 3.333. Calculate the percent
dissociation of K3[Fe(CN)6].
(A)33.33
(B)0.78
(C) 78
ateatt
(D)23.33
MHT-CET 2016
8. Identify the compound amongst the following
T
H
boiling point.
(A) Glucose
of which 0.1 M aqueous solution has higne
(B) Sodium chloride (C) Calcium chloride
(D) Ferric chloride
9. The relation between
solubility ofa gas in liquid at constant
temperature and external pressu
stated by which law?
(A)Raoult's law
(B)van't Hoff Boyle's law
(C)van't Hoff Charles'
law
M
fs
MHT-CET 2017
(D)Henry's law
10. Solubility of which
among the following
(A) KNO
solids in water changes
(B) NaNO
slightly with temperauu
ure?
(C) KBr
(D) NaBr
osmou nressure of solution
t 20° Cis (Given,containing 34.2 g of cane
Solutions (107)
11. 1 fsolution at
0.082 L atm
sugar (molar
R=
IL
atm
(B)3.6 atm
mass 342g mol
(A)2.40
Kmol)
(C)24
atm
which among the following equimolar
(D)0.0024
For
12.Value?
aqueous solutions
(A)Aluminiumchloride
(C)Ammoniumchloride
o
13.
The com et
relation between elevation
W
(A)M =Ah.
AT, W
(B)Ma=K,.W
ofboiling point and molar
(C)Ma
AT.W2
MHT-CET2019
oda
n
o
(B) Potassium
sulphate
(D)Urea
MHT-CET 2018
% cane
atm
van't Hoff factor has the
lowest
,K
mass of solute is
WW
K,.Wa
s
t
fosmo TO
is
s
e
W
(D)M, AT,
alenlate van't Hoff factor for 0.2 m aqueous solution
of KCI which freezes at-0.680°C.
Yomg
(K = 1.86 K kg mol)
(B)
s (C)3.72wnodufo
(A) 1.86
(D) 1.83
constant
has
KH
the
and
Henry's
unitloe
is
15.
q
6.8alke
(A) atm mol dm
16.
ezing
(B) mol dm atm
Which of the following sets
(A)Silver chloride + Water
(C)Ethyl alcohol+ Water
b
u
(C) atm mol dm
o
D
D) mol dm' atm
of components form homogeneous mixture?
(B) Sugar+Benzene
(D) Phenol + Water
17. If the van't Hoff factorfor 0.1M Ba(NO3)2 solution is 2.74, the degree of dissociation is
(A)0.91
(B)0.87
(C)0.74ouutoa lal(D) 87
1
2
anhydrous oxalic acid (Mol. Wt = 90) was dissolved in 9.9 moles of water. If vapour
pressure of pure water is Pi', the vapour pressure of solution is
(B) 0.99P 0.8d) (C) 0.90Ps T(D) 0.1P
(A) 1.1P
18.9 gram
litres
0
2
urea (mol. mass. 60 g mol") and sucrose (mol.
of the following sets of solutions of
342 g mol) is isotonic ?
(B)3.0 gL urea and 3.0 gL sucroseo
(A)3.0 gL urea and 17.1 gL sucrose
(D) 6.0 gL urea and 9.0 gL sucroseCA)
(C)9.1 gL" urea and 6.0 gL sucrose
dissociation (a) is
(i) and degree of
20. Relationship between vant Hoff factor
19.
cent
Which
(A)
T
H.
hest
e is
M
T
E
a-i
C
n-1
(B)
i=1-n
(C)i=
(D)a-
n-1
n-1
ate
water at 300 K. If R
dissolved in 100 ml of
is
180)
21.1
1 18 gram glucose (Molar massosmotic pressure of solution'?
(D) 0.821 atm
-atm mol K', what is the
(C) 24.63 atm
atm
8.21
(A) 2.463 atm
(B)
substance is
aqueous solution of a
molal
0.25
The
elevation in boiling point of
(D)0.15 Kpenog
(K0.52 K kg mol")
C)0.50 K a80(8
(A)0.13 K
(B)2.08
solute is
molar mass of the
and
A1,W
point
23. Relation
depression of freezing
(D)
K0800
Detween
W,
(A)AT
M,
KW2
Ma
(B)Ma
K,WL
TW2
(C)Ar
M,Wi
M-
mass.
KW
0.0821
(108)MHT-CET Exam Questions
34. Osm
a
followings. pressure
solvent
of
property among the
Vapour
colligative
the
(B)
24. Identify
pressure of a solution
Osmotic
a solvent
of
point
Boiling
(D)
(A)
ofurea?
with 6.6 g
(C)Freezing point of a solvent
isotonic
is
which
1L solution
mass of sucrose in its
16)
A)
25. What is the
D) 34.2 g
12, N = 14, O(C) 68.2 g
(Atomic mass: H 1, C-
(A)1
35. Whi
L
(A) 37.62 g
(B)30.1g
(A)i
(B)
highest
following solutes has
m
the
Which
of
26.
(B) Gluco0se
chloride
sulphatee
Potassium
(A)
(D) Aluminium
chloride
(C) Ammonium
MHT-CET 2020
is
s
e
s
t
correct about solution?
following statement is NOT
substances with fixed composition
27. Which of the
mixture of two or more
heterogenous
a
either solute or solvent
(A) True solution is
may play the role of
gas
and
liquid
solid,
matter
solute
(B) The three states of
constitute smaller part is called
which
solution
of
(C)The component
as hydration
process of solvation is known
(D)When water is solvent, the
pressure of l molal aqueous K
cause increase in vapour
will
changes
following
28. Which of the
solution at same temperature?
obyoto19y 12 (A
(A)addition of 0.1 molal solution of NaCl
(B) addition of I molal KI solution
b
u
o
D
C) addition of water
NazSO4
(D) addition of 0.5 molal solution of
29. Which of the following pairs of solution is isotonic?
1
2
0
2
mol dm
atm. If partial pressure of oxygen
is 0.46 atmosphere, what is the concentration of dissolved oxygen at 25°C and
CeD (A)2.82 x 10 mol dm
(B)5.98 x 10 mol dm
dm
D)5.98 mol dm
()3.53 x 10 mol
M
T
H
36. Va
dre
(A
37. W
fr
(
38..A
39.
40.
41
30. According to Raoult's law, relative lowering of vapour pressure for a solution containing a nat
volatile solute is equal to
Jge0)
(B) mole fraction of solute
(A)moles of solute
D)mole fraction of solvent gideaousfs05
(C) moles of solvent
T
E
C
(D)
AOCA)
(Molar mass: urea = 60, sucrose= 342 g mol)
(B)3.0 gLurea and 17.19 gL sucrose
(A)0.3 gLurea and 17.19 gL sucrose
(D)30 gL urea and 17.19 gL sucrose
(C)3.0 gL urea and 1.719 gL sucrose
31. The Henry's law constant for oxygen is 1.3 x 10
n
o
C)
solution2
molal aqueous
value in its 0.05
1
atm pressure
32. 38.4 g of unknown substance (molar mass 384 g mol") and 116 g of acetone is used to prepa
a solution at 313 K. If vapour pressure of pure acetone (molar mass
58 g mol) is 0.
atmosphere, what is the vapour pressure of solution?
(A)0.7999 atm
(B)0.880 atm
(C)0.650 atm
(D)0.958 atm
33. 0.5 molal aqueous solution a weak
acid (HX) is 20% Ionized. If Kr of water is 1.30 *
of
mol, the lowering in freezing point of solution is
(A)0.56 K
(B)1.12 K
(C)-1.12 K
D)-0.56 K
42
4
Osmotic pressure of
34. C
lar solutionat
27°C is
Solutions (109)
(B) 1.21 atm
(R 0.082)
(C)2.46 atm
ong following is true
Wh
for the value
(D)24.6 atm
35.
of Henry's law
(A)is same for all gases
constant
(B)is greater for gases with higher solubilities
(C) increases with increase in temperature
(D) first creases and then decreases
with increase
in temperature
aour pressure of solvent "A
is 0.90 atm, when
a non-volatile solute
iroj to 0.60 atm. What is mole fraction
is added, vapour pres sure
of A in solution?
(A)0.500
(B)0.667
(C)0.300
(D)0.333
hat is the value of Ke if 30 g urea
(molar
mass
60)
dissolved in 0.5 dm of water decreases
freezing point by 0. 15 K?
(A)0.30 K kg mol
(B)0.030 K kg mol
(C)0.15 K kg mol
(D)0.015 K kg
18. An amalgam of mercury with sodium is
an example of
(A) liquid in liquid solution
(B) solid in liquid solution
(C) solid in solid solution
(D)
(A) 12.1 atm
K?e
ns
is
s
e
s
t
n
o
moltoatlotel
b
u
liquid in solid solution
Solution of chloroform in nitrogen is an example
of
(A) liquid in solid
(B) liquid in gas
(gas in liquid
(D) liquid in liquid
40. Which of following 0.1 m aqueous solution exhibits highest
osmotic pressure at 25°C?
(A) urea
(B) CoClh
(C)glucose
(D) KCI
39.
ios
41. Identify
o
D
the correct relation between depression in freezing point and freezing point of pure
solvent.
(A) T° = T
-
ATr
1
2
(B) T° AT-T
0
2
(C)T°= AT+T(D)
T°
=
Tx AT
42. If a centimolal aqueous solution of Ka[Fe(CN)6] has degree of dissociation 0.78, what is the
value of van't Hoff factor?
go
4.0
(A) 3.34
(B) 2.5
C)12ogee
lo
43. What is
osmotic
(A)4.96 atm
at 27°C? (R=0.082)
(D)20.5 atm
(C)12.3 atm
pressure of a semi molar solution
T
E
C
(B) 2.46 atm
0.10 M NaCl, 0.05 M BaClh and 0.05 M
44. Solutions A, B, C and D are respectively 0.2 M urea,
except
AlCl3. All solutions are isotonic with each other
dato2.t2
(C)A
upil nr D)B
(B)D
(A)C
45.
b
Henry's law is a relation between
D23qi (B)pressure and solubility
(A)temperature and pressure
TUsogd (D)volume and solubility
(C)pressure and volume
containing non-voli
olatile solute is the ratio of
a solution
pressure
46. Relative lowering
of
vapour
in
of moles of solution
to total number
solute
moles
of
number of
moles of solute
to number of
solvent
moles
solution
of
of
number
number of moles of
total
solvent
to
solvent
number of moles of
number of moles of
to
solute
moles
of
of
M
T
H
number
OE
(112) MHT-CET Exam Questions
3.42
72. Solution of 'A' containing
solutionof
g of it in 100
with a 6.840
cm of water is found to be isotonic
(At. wt: C- 12,
sucrose, what is the molar mass of 'A'?
1,
16)
0-
1
freezing point depression urea
highest
have
will
(D)I M
the following solution
(C)1 M glucose
73.Which ofsucrose
MKC
(B)I
What is it's percentag
(A)1 M
K3[Fe(CN)6] is 3.333.
of
solution
factor () for centimolal
*74. van't Hoff
dissociation?
(A) 70%
is
s
e
(D)77.7%
(A)
For
n
o
(D)342
(C)171
(B) 180
(A)68
H-
Fre
(C
Is
C) 80%
(B) 33.33%
non-electrol
1
isotonic with % solution of
is
342)
mass
cane sugar (molar
75. A 5 % solution of
substance X is
(D)68.4 g mol
substance X, the molar mass of
(C)136.8 g mol
mol
g
171.2
(B)
(A)34.2 g mol
vapour
statement from the following:
is always less than
76. Identify the correct
containing a non-volatile solute
solution
a
(A)Vapour pressure of
solution containing a
pressure of pure solvent.
than boiling point of it's
greater
always
is
solvent
(B) Boiling point of pure
non-volatile solute.
points.
forces have lower boiling
(C)Liquids having greater intermolecular
always greater than vapour
is
solute
containing a non-volatile
solution
a
pressure
of
(D)Vapour
pressure of pure solvent.
water?
urea is dissolved in 0.1 dm' of
77. What is the value of Ky if 6g of
urea = 60)
augey
(AT= 0.15° C and molar mass of
(B)0.15 K kg
(A)0.030 K kg mol0
(D)0.30 K kg mol
(C)0.015 K kg mol
Hot
to determine osmotic pressure using van't
78. Which of the following equation is correct
equation?
s
t
b
u
sal
(A) rV=
W,RT
T
E
C
M
RT
(C)T
1
2
0
2
o
D
molua
otl
o
ato
sule
(B) TC= VRT
6
(D) rV k
M
kg urea dissolved in water to make 500 mL aqueous solution and it is isotonic win
cane sugar solution. What quantity of cane sugar is present in it's 1 lit. solution?
79.30x 10
T
H
(Atmass: H=1,N=
(A)171 g
16, C
17.1
g
(B)
14,
O=
12)
(C)3.42 g
(D) 34.2 g
80. What is freezing point of a solution containing 1.8 g ghucose dissolved in 1000 g of water?
M
(Kofwater= 1.86 K kg mol
(A)-0.0093°C
(C)-0.0186°C
1
H=1,0
(B)-0.0372°C
and at. mass C
12,
16)
D)0.0186C
notie
urea and sucrose is dissolved in 250 mL of water having oSmo
nsis
pressure
T2 and
ts respectively, the decreasing order of osmotic pressure of these solutions
(A)T 2 T3
(B) 72T>Ta
1T 10
g each of glucose,
t,
(C)12TT31
(D) T312
84
SOLUTIONS
I.(A)non-electrolyte AT
For
Freezing point of
2.
Kr x m
AT 1.86 x 0.05
0.093° c
solution=0-AT=0-0.093-0.093°C
Isotonie solutions have same osmotic
pressure.
W2
Molecular
Molecular weight x V
yte
x V,
weight
10
WL
60x1
Solutions (113)
60x1011.54
342x0117.54 g/L
WI
342 x0.1
(D)
3.enression in
e
ur
4
freezing point
is
a colligative property
(B)
o
Na:SO produces maximum number particles.otulo2 lo vankMnlok
of
s
t
b
u
3 particles
Thus, it causes maximum
s
e
is
but freezing point is not a colligative property
Na,SO2Na +S)
5.
one
n
o
o
D
depression in freezing point.
D)
Weight of solute x 1000
1.5x1000 =
Molecular weight of solute x wt. of solvent 60x 250 0.1 molal
Depression in freezing point,
Molality
Kxm
ATr
Ksx 0.1
0.01
6.
(C)
The osmotic
1
2
0
2
Kr
=
=0.1
b lon) eiidulog
feae plho tial
o1weesyt
0.1
pressure follows the equation,
T
E
C
RT
But,
n
W
M
WRT
VM
7.
(C)
T
H
K3
[Fe(CN),]
a
M
3K+[Fe(CN)6P
T80
(n-
4)
l3.555-1=0.78
n-1
4-1
percentage dissociation= 0.78 x
25lo
100=
78 %
.0910oio
parts has
Will break into the m0st
concentration, the one that
They all are having same
2ll4
L
will ionize.
parts (I Na, 1CI)
highest boiling point. Ionic compounds
2
B
3
I
4 parts (1 Fe, C)
part (covalent, does not ionize)
a
D
C
parts (1 Ca, 2 C)
8. (D)
(114) MHT-CET
9.
Exam Questions
between
the relation
D)
Henry's Law states
19. (A)
Ure
Mas
is
external pressure.
10. (D)
11. (A)
T
x0.082
MRT= 342x1L
x
2.40
293
13. (A)
K,
T
AT
W
s
t
14. (D)
W
X
AT,x W
AT=im K
0.68 ix 0.2
x 1.866
0.68
1.827
0.2x1.86
0
2
15. (B)
S
Solubility (mol dm)
Unit of Ky = mol dm
.
T
E
Ca
1.83
02
M
T
H
192
10.0
+2Nog
2.124-087
18. (B)
:. Moles of water
Mole fraction
P=P
xx
90g
(n,)=0.1
90
(n) = 99
of solvent (x)=
D +n
. P=0.99xP
25.
slolM
Total ions after dissociation, n = 3
oles ofsolute
21. (C)
26.
P
Pressure (atm)
atm
Mass= 9 g, molecular mass =
Moles of water 9.9
moles
20. (D)
23.
17.(B)
Ba
Mo
A
16. (C)
Ba(NO3)h
Mo
22. (A
75209h,adt
K= 1.86 K kg moll
1
2
m=0.2, Tr0.680°C,
17,
W
-K MxW
b
u
of solvent in kg
o
D
Molar Mass of Solute
M2
Ma
M2
Wt.
No. of mole of solute
Wt of solute in solution
Where nz
s
e
atm
12. (D)
dissociate into its ions.
Urea does not
x m (m is molality)
n
o
constant temn
liquid at onstant temperatute
solubility of gas in
-0
10
99
jnol nmog seifiods
29
perature
Solutions (115)
an
19.(A)
Urea
Mass-3
Molar mass
Moles
Sucrose
Mass 17.1
Molar mass
60
0.05
60
no. of
When
Moles-
342
moles are same then solutions
are isotonic.
is
20. (D)
21.(C)
Mass
mass
18 g, Molar
of glucose
Moles-=0.1, Volume - 100ml
=
22. (A)
AT ?,
m= 0.25m,
AT m
Ks =
Ky =
0.25 x 0.52
0,1 L,
Molarity==1L
0.1
x 300 24.63 atm
MRT=1 x0,0821
K.
b
u
24. (D)
23.(C)
25. (A)
mol
Sucrose (molar weight)= 342 g
of urea = 60 0.11
Moles
s
t
0.52 K kg mol'
0.13
s
e
180 g
180
T =
o
D
00.0
with 6.6 g/L of urea =0.11 x 342 -37.62
Mass of sucrose in 1L isotonic
1
2 ot
28. (C)
27. (A)
26. (D)
29. (B)
0
2
For isotonic solution, Turea7Tsucrose
Dureansucrose
17.19-0.05mol
3.0
343
6.0
30. (B)
31. (B)
T
E
C
Ku
S=1.3
T
H
S
KHxP
atm
x 10 mol dm
noilo xeor
10 mol dm
x 0.46 atm
38.4
M
384
116
=
O2
TT
eog gonoft toreubyf
(acetone)
mol solvent
2
2+0.1
is given by
the solution
of
pressure
vapour
-0.7999 atm
Dy Kaoult's law, the
0.842 atm
Mole
P
=
fraction; X1
X1
x Po
09
= 5.98
0.1 mol solute
58
g
0
32.(A)
n2
2+0.
n, +n
=0.95 x
n
o
0.05
342 0.05
= 0.95
Questions
43. (C)
For a semim
MHT-CETExam
(116)
n
(B)
H +X
HX
For
dissociation ofan
a-
i-
i-1-0.2
i-0.2+1 1.2
ikm=
AT
Now,
x
1.2 x 1.86
0.5-
MRT
-I mol
s
t
b
u
35.(C)
36. (B)
0.9-0.6 0.333
=1
1
-X2 =1- 0.333
37. (C)
Mass of water
Moles
0.5
of urea=
dm
T
E
C
AT Kx m
38.(D)
0.5 kg
0
2
0.5mol Imol/
0.5kg
1
2
= 0.667
0.5mole
50
Molality ofurea =
K=
o
D
0.15K0.15K
Imol/ kg
kg
D)
TAIC,
Allso
45. (B)
By Henr
Where,
46. (A)
anoou
Po-P
Po ?
Accor
P-P
Po
(
P
(
(6
48. (C)
Due
O
49.(D)
ATb
ore 20 0
Ka
AT
mol kg
39. (B)
40.(B)
Due to more number of ions in solution.
50. (D)
41. (C)
AT T-
M
(A) TUrea
(B) TNaC
(C) Tpucly
47.(A)
loiew 1slo)
0.9
T
H
ook
Molarity)
Now, X +X2
n
o
is
s
e
1.12 K
24.6 atm
x 300K=
mol
(Matm
K'
dmx0.082 dm'
34.(D)
MRT
44. (A)
Osmotic pr
electrolyte,
:0.2
=
p
T
W
T-AT+T
T-freezing point of pure solvent
T
freezing point of
solution
AT depression
in
freezing point
42. (A)
K[Fe(CN)%)
n =4
van'tHofffactor
suloe lorm
(osoe) a9zloelore
3K'+ (Fe(CN),J
(i)1+a
E09
oot loM
(n-1) =1+0.78 (4 100q8
1)=3.34
M
43.(C) mimolar solution,
Molarity (M) =
Fora
0.5
x 0.082 L atm
MRT 0.5 mol
Solutions (117)
K mol
x 300 K
44. (A)
12.3 atm
Osmotic pressure, t= iMRT
=
x 0.2 RT = 0.2 RT
(A) TUrea
B) ENaCI 2 x0.I RT= 0.2 RT
C) TgaCl3 xO.05 RT=0.15 RT
1
D)
45.
RT=0.2 RT
x 0.05
solutions are 1Sotonic with each
other except
All
.
4
TAIC
(B)
By Henry's Law, S
S
Where,
=
0009240
C.
s
e
Ka xP
Solubility of gas, P =
Pressure of gas, KH=
s
t
Henry's law constant
46.(A)
b
u
n, +n2
10 mm of Hg
Po-P
X20.2
Po-?
According to Raoult's Law
P
10 mm of HE
2
=
Po
Po=50
0.2
1
2
mm of Hg
48. (C)
Due to more
a2
ovloe)5ruprooe
47.(A)
o
D
22
9119oiq vigilo
02
0
2
number of ions in solution.
49.(D)
=
(100.18 +273) -(100 +273) 0.18 K
Ks = 0.512 Kkg mol', m=?
AT
AT,
K^
m
T
E
C
AT
m
xm
0.18 K
=
0.35 mol kg
0.512 K kg mol
T
H xP
50. (D)
Mi
mm Hg, P=400 mm Hg,
W 30 g, W2= 1.5 g, M2=?
Ma
450
M
W
= 78
PP)
M-1578
30
450
(450-400)
= 35.1
gmol
mass of benzene),
g mol (molar
M200-a
HOsd
OTA
n
o
is
H000
M C0.0
MED-
A and
(118) MHT-CET Exam Questions
51. (D)
,
Mf
ix
Thei
W
Kam -Ks M
M,W
AT
K
n
o
XM, xWM
is
W
52. (D)
i-1.076, a-?
CH,FCO0
CHFCOOH
+
s
e
H'
s
t
n-2
0.076
1076-11.076-=
2-1
b
u
53. (B)
54. (A)
Benzoic acid Solid
Benzene liquid (solvent)
It is solid in liquid type.
o
D
(2
56. (A)
i=3.33
Ka[Fe(CN)s).
Ka[Fe(CN)6]
1
2
0
2
[Fe(CN)6]
3K+
0
0
oi te Tde
a
3a
1-o
no.
of Particles =1-a+3a+a
Total
T
E
C
=
1+3a
3a=
3.33
2.33
T
H
M
x100
th
A)
BaCl2
AICl
62.
63.(
9T05 or oud
n
x
TA
64
M.W
NaCl
(C)
(D)
61. (A
77.7%
CgH1206
(B)
va
57. (D)
with
Solubility of a gas in liquid decreases with increase in temperature and increases
in pressure.
58. (D)
A - 0.1 MM
B 0.05 M
C
0.05 M
D 0.1 MM
(A)
1+3a
2.33
a%-
The
Hoff
60. (B)
lowering of
on the surface. Relative pressure are
particles
solute
number
of
Colligative property depends on
osmotic
point, depression in freezing point,
vapour pressure, elevation in boiling
colligative properties.
55. (A)
59. (C)
i= 1)
i- 2)
i 3)
i-4)
o
008-02
M
incre
B
are isotonic as they give
same number
A and
M factor
ix
The
i
x
actor for
M
Solutlons (119)
per unit volume
which is given by
of particles per
A -Ix0.1-0.1
B -2x 0.05-0.1
C -3x0.05-0.15
D -4x0.1-0.4
The salts which dissociate to give same number
of ions and concentrations
off factor for Ka[Fe(CN)%]- 5
have same
ions
(A) MgSO42
(B)Na;SO4= 3= ions
(C) Al:(SO4)3 5 ions
(D) Al(NO:)s 4 ions
60.(B)
s
e
TheoriticalColligative Property
van't Hoff factor (i)
Van
Observed Colligative Property
s
t
Observed molar mass
Theoritical molar mass
b
u
61. (A)
cetic
acid molecules in benzene undergoes association,
so its observed molar mass is greater
than actual molar mass.
lowering of
pressure are
o
D
62.(D)
An aqueous solution of non-electrolyte does not produce
any ions.
So, its
van't Hoff factor (i) =
1
63.(A)
kg mol
K= 0.52K
xm
1
2
ATr-Kr
Molality= 0.186
AT
1.86
0.1
m
0.186°C
0
2
AT
ulg
Kyx mo =
=0.52 x 0.1 0.052
AT
T-T,
= 0.052
T
E
C
Boiling point
of solution T,
002 rüiw oiroto ai tojtuloe eu
Meco0
o
T, -100 0.052
=
100.052°C
0
64.(B)
Kxm
Kg=41
AT
T
H
ith increas
M
K = molal elevation constant
point
Al = Increase in boiling
nmolality of solution.
sue to 9eegoog
vloestuloe
lo oiber lot
o 90m
Jvioe 1020otlo dua
65.(D)
TA()sucrose
(CRT)A
1.73
=(CRT)Sucrose
1000 3.42 1000
M
100
MA
R&Tare
constant.
,
1.73
342
x 100 173
100
ouvalo
ens
Bie potufo
to
ra enoc
edmoro
n
o
is
59.(C)
(CE
MHT-CET Exam
Questions
(120)
11
66. (C)
12
nA
ml, d 1.58
V 100
Po-143,
158
x
1.58
Mass 100
143-P 0.5 154
65 158
143
x 143- 1.07
=0.007
143-P
141.42 mm Hg
67. (A)
n
XkPa,
V
10.5
m,
-RT
i
X
10.5
b
u
By dividing equation () by (i)
x8.314x 300
10.5
X/10
10
1/V'x8.314x300
V'
10.5
=
V
68.(D)
s
t
x8.314x 300
i
x8.314x300;
s
e
V=?
r'-kPa,
105 m
1
2
n
o
is
-143-1.07
P
o
D
AE
mass of urea (g)
molar mass of urea x volume of solution (L)
Molarity of Urea
1.5 0.025 M
0
2
60 x1
Now, 0.025 M urea solution is isotonic with 500 mL glucose solution.
Molarity of glucose = 0.025 M
Molar mass of glucose = 180 g
1
M> 1000 cm glucose 180 g
T
E
C
O.025
M-
180x0.025x500
500 cm glucose=
1000
2.25 g
ouloz
to
oq
geili
69. (C)
Relative lowering in vapour pressure,
T
H
AP
po
Where,
M
2
P
n,+D
PP
vapour pressure of pure solvent, P =
vapour pressure of solution,
mole fraction of solute,
n2= number of moles of solute,
number of moles of solvent.
X2
n
70.(C)
MgSO4, KCI, NaCl gives 2 ions (particles)
on dissociation whereas
(particles) on
dissociation
Al,(SO),
2AP
Al,(SO,), gves
+3So
More number of ions in solution
will have maximum elevation
in boiling point.
io
71.(A)
Solutlons (121)
72. (C)
Molecular mass of Sucrose
CiHa:O-342gmolT
Molarity ot Sucrose Solution
Molarity of 'A
Wx1000
342x100 -0.2
of sucrosesolution
molarity
Molarity of 'A" solution
6.84x1000
MxVm
0.2
Wx1000
M
Mx 100
Mx100
34.2
0.2
M
73. (B)
171
s
e
g mol
s
t
K* +CI
KCl
is
3.42x 1000
0.2
n
o
M
KCl undergoes dissociation to give ions,
it means produces more particles
in solution.
Colligative property depends upon number of solute particles.
Depression
freezing
of
point will
be high for KC1.
Since
b
u
74.(D)
n
K+[Fe(CN),PF
5.555- 255 =0.7766
K,[Fe(CN),l
a
%
i-
3
n-1
4-1
dissociation = 0.7766 x 100 = 77.66 %
1
2
75. (D)
o
D
-4
08
sugar
Solution of non-electrolyte is isotonic with solution of cane
solution
Molarity of cane sugar solution = Molarity of non-clectrolyte
5
=
0.4162
342x0.1L
0
2
noitlpa lo roe giioee
810.0-
T
E
C
Molar mass of non-electrolytee
76. (A)
0210.0-
Molarity
x 0.1
8
0.1462x0.1
68.399 g mol » 68.4 g mol
0.01462
Vapour pressure of solution
pure solvent, P=
surface are of the pure
uppose, Po = Vapour pressure of
solvent, it covers the
pure
the
added to
between of which vapour
when nonvolatile solute is
vapour phase decreases
T
H
DOvent, mumber
M
going in
of molecules compare to pure solvent.
Pressure of solution is lowered as
Lowering of vapour pressure,
con
efoinq lo
APPo- P
77.B)
Ma
1000 K,W.
AT,W
K
= 60x0.15x 0.1
6000
60-000X6xK
60
0.15x0.1
0.15 K kg mol
fo
tu
o
(122)MHT-CET
Exam
Questions
78. (A)
Osmotic pressure
follows the equation,
orosloM
=n,RT
T
V
T
n2 (moles of
solute)
M,
rV-RT
is
M
sugar solution
= Molarity of cane
Molarity of urea solution
Because they are isotonic.
Molar mass of urea =CONH)2
x 2) +(2x 2)
79. (D)
s
e
=12+16+(14
60 g
= Ci2H2011
cane
sugar
Molar mass of
- (12 x 12) +22 +(16 x 11)
342 g
egu
Molarity of cane sugar
Molarity of urea
342gx1L
342x5= W
60x0.5
1026
W2
30
34.2 S
1
2
80. (C)
Kg. m
AT
AT
=
=
W
K M,W,8
1.86 x 0.01
=
1.86x-
b
u
0
2
o
D
180x1000x103
0.0186°C
AT 0.0186°CC
Freezing point of solution = 0°C-
.
1.8
AT- -0.0186°C
s
t
bgagob yhego1G 9gito
W
3g
60gx0.5 L
A0Xot 1gd sd
(0) 2
olo-2on to roitulo8
sotogooie
81. (B)
Molar mass of glucose = CsH1206 180 g
T
E
C
10-0.056
Moles of glucose
180
=
mass
Molar
of urea cO(NHa)h = 60 g
oug s
Moles of urea=
10
0.167
yloe
euig si of bobbo e stuioe aitslovnog 13
09tpa to admu gnavioe
60
Molar
Molar mass of sucrose CpHO1-342
=Ci2H220 542
Moles of Sucrose 10 = 0.029
342
of moles o no. of particles
M
T
H
n
o
o gialoM
ooa boeo
coulo to
No.
Decreasing order of osmotic pressure
of solution is
glucose
sucrose
000
WTA
000
3.lonic Equilibria
ImportantFormulae and Shortcut
ww
Methods
Types ofelectrolytes
n
o
electrolytes-strong acids, strong bases and
salts
electrolytes-weak
acids, weak bases
Weak
:Strong
is
Degree of dissociation (oc):
number of moles dissociated
oc
total number of moles
oc x 100
dissociation=
Percent
s
e
Acids and Bases:
OH-10H
Arrhenius Theory
s
t
HO,H04
Acid It is a substance which contains hydrogen and on dissolving in water produces
hydrogen ions, (H). e.g. HCI
b
u
HCla)H)+Cl)
Base It is a substance which contains OH group and on dissolving in water produces
hydroxyl ions (OH). e.g. NaOH
Na" (aq) + OH (aq)
NaOH(aq)
=
Bronsted Lowry Theory:
HC1+H,O =H,0' +CI
1
2
Acid
NH
+H,O=NH; +OH
Base
0
2
Lewis Theory:
electrons.
ACId can accept a pair of
e.g. BF3, AICl
Base can donate a pair of electrons.
e.g. NHs, CaHsNH2
T
E
C
Ostwald's dilution law:
For weak acids,
T
H
a
o
D
p
K,V
sizsa tolos slT
0
pa)
bocot eesd is
(pe g
be bron
enuutotlludho eogyt
For weak base,
M
dm
base in mol dm
centration of an acid or a
Where, c
base in dm' mol
V=Volume of an acid or a
Autoionization of water:
1.0x 10
1,
at 25°C K.OH
-H,o
O
hoisato otiee
Questions
(124) MHT-CET Exam
pOH
Relationship between pH and
pH+pOH
ol
= 14
pOH=-logio[OHJ
pH--logio[H'],
n
o
Hydrolysis of salts:
Salts:
1.
and a strong base:
Salt of strong acid
NaCl+ H,O
NaCl: NaOH+ HCI
S.B
Sat
S.A.
a strong base CH,COONa +H,O
Salt of a weak acid and NaOH
CH,COOH+
CHCOONa:
s
e
:
2.
S.B.
W.A.
Salt
and a weak base
3. Salt of a strong acid
NHCI:
WB
S.A.
Salt
WB.
Salt Hydrolysis
Salt of strong acid and strong base
s
t
b
u
a weak acid and a weak base:
NH,OHCH,COONH, +HO
CH COONH4: CH,COOH+
Salt
W.A.
ses
b
cbisA
oalTauinsd
NH,OH+HCl=NH,CI+H,O
4. Salt of
i
is
a
eonfeggED
o
D
(aq) + CI (aq)
+OH (aq)
Na (aq)+Cr (aq) + H,O ()=Nat (aq)
solution is neutral.
In this solution [H"] = [OH], hence the
+H
1
2
ii. Salt of weak acid and strong base
(aq9
CH,CO0aq) + Na* (aq)+H,O()= CH,COOH (ag)+ Na (aq) +OH
0
2
The solution is basic.
ii.
Salt of a strong acid and a weak base
NH (ag)+ CI (ag) + H,0()=NH,OH (aq) + H (aq) +Cl (aq)
The solution is acidic.
T
E
C
s0sdTo
b
iv. Salt of a weak acid and a weak base
CH,COO(aq) + NHZ (a2) +H,O(0=CH,COOH(aq) + NH,OH(aq)
T
H
blavt0
The solution may be acidic, basic or neutral depending on the relative strength of
acid and weak base formed in the hydrolysis.
M
Types of buffer solutions:
i.
Acidic buffer solution:
pH
=
[salt]
pK, +log10
[acid]
Lwhere, pK, = -logo
K,]
u
salt)
ii. Basic buffer solution: pOH=pK, + lo810
[base]
where, pK,=- logio Ksl
wes
lonic Equilibrium (125)
Relationship between solubility and solubility
product:
n
o
Molar solubility (mol/L)-so lubility in g/L
molar mass in g/ mol
Solubility product (K):
B,Ay
is
xB)+yAR)
s
e
K-B"TA
If S is the molar solubility of the compound, the equilibrium concentrations
the saturated solution will be
B-xS mol/L, Ays
of the
s
t
mol/L
K =[xS[ysy" = x*y>sa+y)
1ons
in
b
u
Common
ion effect : The common ion effect states that the ionization of a weak
electrolyte is suppressed in presence of a strong electrolyte containing an ion common to the
weak electrolyte
e.g, CH COOH and CHCOONa have common ion CH,COO
o
D
Multiple Choice Questions
1
2
This topic has been included in the CET syllabus for the first time for CET 2021. Find sample
questions below:
1. According to Ostwald's dilution law, the degree of dissociation of weak acid given by
(A)
1
0
2
dd(B) CIK,
KC
2. The relation between pH and pOH is
(A)pH/pOH 14(B)
T
E
C
14-pH pOH
3. The solubility product of CaF2 is
(B)[Ca"](2FT
(A)[Ca j2F
(A)K
of
S
6. The solution
M
(C)pH
x
pOH=
(D)14/p0H- pH
14
(D)[Ca"IF]
(C[Ca"IFT
substance which acts as
4. According to Lowry-Bronsted concept, base is a
an electron donor
(B)
(A) a proton donor
(D) an electron acceptor
(C) a proton acceptor
product by the equation
Pbla is related to its solubility
S. The solubility
T
Hne
at
Cngtá
D)K,C
C) K,7V
(A)KNO
pH
(A)0
(B)Kp = 4S
(D)K 4S
(C)Kp= 27s
be
of a salt is basic. The salt must (C)CH,CH0ONH (D) NH,NO
(B) NaCN
potassium acetate will
of the mixture of acetic acid and (C) less than 7
(B)7
be
(D)more than 7
in NHOH. For NH4OH, pks
solution is 2 M each in NH,CI and
solution will be
(D)9
(C) 5.8
(A)4.7
(B)9.3
A
E
= 4.7.
The pH of the
M
(B)
hydroxyl 1ons, its pH.
hydrogen ion and
(126)
concentrations
of
solution contains equal
(D) 0
9. When
(C)7
around
10
(B)
would be
(A) 14
25°C, its solubility
at
dm
mol
dm
1.6 x 10
10. If Kp of Agl is
(B) 4x10 mol
MHT-CET Exam Questions
6. NaCN
sa
It is a b
When
will
o
(A)4x10moldm
(D) 0.8x10
(C)0.8x10 gdm
as
a solution is correctly defined
11. The pH of
pH
o adt boon (B)
(A)pH-log.[H]
g dm
1
logiolH
Joa
s
t
be
(D) pH log1o[H*]
(pH=log10H1
s
e
211
afont odt
b
u
oth
product (L,)
relationship of its solubility
ApBq
the
soluble salt
12. For a sparingly
ol
solubility (S) is
(B)Ls SP*4.p.qp
(A)Ls = SP.pP.q
(D)Ls = SP. (pq)P*4
r(C)Ls
=
(C)6
(B)4
(A)2
14. BF is a
(A) Lewis acid
at
(C)Amphoteric compound
15. Na2CO is a salt of
T
E
C
1
2
T
H
Ca
CaF
+2F
5. (B)
Pb+2
1, y
=2.
y-(n?
ot bonibn
d t2a ise 9d
productCa
(C)uhotem(
Pbla
Here, x
Here,
p
=
9. (C)
IfE
10. (A)
Ag
(D)7
ld
gibtoouk
11. (C
p
12. (
13.(
od- grrod orgaibsooo/
Solubility
4.
(B)
Accor
e3o tbose oilidoloe ott
14-p-Ptyioe
3. (C)
8.
SOLUTIONS
aKc
pHpOH =14
M
o
D
(B) strong acid and weak base
D)weak acid and weak base
For weak acid,
2. (B)
zoree)
19sd eed iqo
ol esd (B) Lewis baseahalsi
Electrolyte
D)
0
2
(A) strong acid and strong base
(C)weak acid and strong base
1. (A)
with
nionsolo
the pa
acid and the salt. If Ka1x 10,
the
of
concentrations
contains equal
S. pP.q
13. A buffer solution
of the buffer is
is
n
o
7. (C) mi
The
sl2=4S3
ot tocs
p
14.
15.
GVbermentioimodo
(B)
will
be
lonleEquilibrlum (127)
Na +CN
NaCN
strong base (NaOH) and weak
NaCof
acid (HCN). vog
is a
It
is
Vhenbase
7.
(C)
The
strong, solution is basic.
mixture is an acidic buffer, hence the pH would
be less than 7.
o- pK
+lo810 salt]
[base]
t
[salt][base]
Here,
p-pK,-4.7
14-p= 14-4.7 9.3
9.
ith
-[OH),
10.(A)
thepH
S=
V1.6x10
S-
1. (C)
pH
pH-log1olH
log0;
H
ienob
(C)
1
pK6
o
D
o: 2otogort
1
2
12.(4)
K =1x 10
pk,
[salt
+log10se
ase]
[salt)-lacid)n
pH= pK, = 6
Here,
14.
(A)
BF
T
E
C
is electron pair
15.(C)
0
2
-TH
e
arienstnt
anio9ubod bns
Hasselbalch equanion,s
Now, according to Henderson
pH
b
u
sothl
= v16x10-l6
mol dm3
S= 4x10
13.
s
t
then solution will be neutral and its pH will he around 7.a
AglAg+T
tetaoa 1A
aceptor hence it 1s Lewis acido
gaiism
sgogovied
0011
raee
ag
191 2ee
ittdaihi
anoltanut
breqol caiiw aotmeyot
hon
+cO
(NaOfH).gbovuollo iheg od
Na,CO
base
strong
and
(H2CO3)
1s a salt of weak acid
2Na
M
T
H
s
e
oeof
tp
enoiaua
oiotgon
selapa0gab ote
o abowotor ug
n
o
is
(B)
According to Henderson Hasselbalch equation,
W
W
Thermodynamics
4. Chemical
Methods
Wo
Wo
Important Formulae and Shortcut
Thermodynamic Terms:
tative
forms of energy and the quantitati
deals with the study of different
Branch of science which
relationships between them.
investigation
universe which is under
system.
System: Specified part of the
universe which can interact with the
Surrounding: Remaining part of the
matter and energy.
Open system: Can exchange both
energy but not matter.
Closed system: Can exchange
energy can be exchanged.
Isolated system : Neither matter nor
Matter
s
t
Energyzg
Energy
Motter
()
(b)
(a)
is
b
u
Laolated ayatem
Closed ayatem
Open ayatem
zz
o
D
n
o
Mode
differe
s
e
Insulator
Bnergy
Heat
He
He
First
F
F
Inter
Whe
Entt
Properties of System
the
upon the quantity or size of matter present in
i. Intensive Properties: Do not depend
heat,
specific
viscosity,
tension,
system. e.g, pressure, temperature, density, surface
1
2
melting and boiling points, etc.
ii. Extensive
matter present in the
Properties: Depend upon the quantity or size of
system.
e.g., mass, volume, internal energy, entropy, enthalpy, etc.
Extensive properties are additive but intensive properties are not.
0
2
Thermodynamic Processes
Isothermal Process : At constant temperature, AT = 0 and AU =0
i. Isobaric Process: At constant pressure, AP = 0
ii. Isochoric Process: At constant volume, AV = 0
aop
iv. Adiabatic Process : Completely insulated, AQ =0
State Functions
depend on
Properties which depend only on the initial and final states of a system i.e., do not
internal energ
the path followed. e.8, pressure, volume, temperature, entropy, enthalpy,
T
H
etc.
T
E
C
Path Functions
g
ODDD
Th
.
ii
Properties which depend upon the path followed, e.g, work, heat.
M
Work
presssure
result
of
a
as
surroundings
system
the
and
the
energy exchanged between
Mode of
difference between them.
iv.
Chemical Thermodynamics (129)
.W--Pext(V2- V)
2.303
nRT
logor
2.303 nRT log
Work done by the system is -ve.
Work done on the system is +ve.
titative
n
o
at
e
Mode 0f energy exchanged between the
system and the surroundings
difference between them.
as a result of temperature
out
by the system is -ve.
.Heat given
Heat absorbed by the system is +ve.
s
t
For isochoric change, AU = Q, as AV = 0
internal Energy Change (AU):
is
s
e
First Law of Thermodynamics: AU= Q+ W
For isothermal process, AU = 0
W -Q
For adiabatic change, AU = W as Q= 0
b
u
U-U
Where, U and U are internal energies of initial and final
states, respectively.
change (AH):0el-
Enthalpy
o
D
Heat absorbed or evolved by the system at constant pressure.
AH Qp, AH -AU+PAV or AU+An,RT
inthe
1
2
Work done in chemical reaction
heat,
stem.
W=-An RT
Enthalpy Change during Phase Transformation : Enthalpy change accompanying the
conversion of 1 mole of a substance from one state to another.
Solid
A
0
2
He
T
E
C
Gas
Liquid
Asub
Hrter
Thermochemistry:
Reaction Enthalpy: Enthalpy change accompanying a
M
Ssure
AH= 2Hproducts2Hreactants
T
H
d on
ergy
reaction.
i. Standard Enthalpy of Reaction (A,H°): Enthalpy change of
states.
participating substances are in their standard
dard
one1
mole
Enthalpy change accompanying
Enthalpy of Formation (A,H°): in their standard states.
from its constituents
of a substance
bond enthalples
thalpPy change for a reaction from
A,H
2
a reaction when all the
AH reactant bonds)-2AH product
bonds)
the formation of
MHT
W
Exam Questions
(130) MHT-CET
Summation
in.
of Constant Heat a reaction is equal to sum of enthalpy changes ofindividu
v. Hess's Law
for
change
enthalpy
the
Overall
steps in the reaction.
9 (A
10. H
AH
AH
AH
AH2
AH
AH
2rey
s
e
Entropy increses
Multiple Choice Questions
MHT-CET 2004
1. If the heat of formation of CO2
is
-393 kJ. The amount of
0.176 kg of CO2 is
3. For the reaction, PCl,(g)
1
2
AU
T
E
C
D)-1165.5 k
M
15.
0
2
(C)AH< AU
16.
(D)None of these
(B)+433 k
energy of
kJ. How much is the bond dissociation
(C)-216kJ
6. 2 moles of helium gas expanded isothermally and irreversibly at 27°C from volume
Im at constant pressure of 100 kPa. Calculate the work done.
(B)99900 J
(A)99900 k
C) 34464.65 kJ
D) 34464.65 J
18
1
dm
M
19
MHT-CET 2006
7. The standard molar heat of formation
M
17
(D)+216 k
5. Heat of formation of SO2 is-298 kJ. What is the heat of combustion of 4 g of S?
(C)+298 kJ
(D) 18.6 kJ
(B)-37.15 kJ
(A)+37 kJ
T
H
14.
olste
4. Bond energy of hydrogen gas is433
0.5 mole of hydrogen gas?
(A)-433 k
b
u
PC1, (8)+Cl, (8)
AU
(B)AH>ottonm
MHT-CET 2005
12. F
MH
(B) product of pressure (P) and volume (V) of gas
D)work (W) done by a system
(A) internal energy (U)
(C)internal energy (U)+ PV
11. F
13.
heat evolved in the formation of
o
D
C)-1572.0 kJ
(B)-1275.9 kJ
2. Enthalpy (H) is equal to
(A)AH
s
t
Liquld
Solld
T
(A)-1357.9 kJ
is
+ AH2 + AH;
Entropy (S):
Measure of randomness or disorder of the system.
AS =
n
o
(A
of ethane, CO and water () are -21.1,94.1
kcal respectively. The standard molar heat of combustion of ethane will be
(B) 162 kcal
(A)-372 kcal
(C)-240 kcal gl D) 183.5 kcal
and
-683
2
the
of
8. In a closed container, a liquid is stirred with a paddle to increase the temperature. WhiCh
following is true?
yolertind
(A)AU W#0,Q=0
(B) AU = W= Q #0
A
(C)AU = 0, W = Q#0
(D)W 0, AU Q#0
da
M
2
MHT-CET 2007
owing is a path function?
Whichof the
9.
(A) Internal energy (B) Enthalpy
ndividua
10.
Hess's law is based on
r
(A) Law of conservation of mass
Chemical Thermodynamics
(131)2
(C)Work
(D)Entropy
A
(B)Law of conservation
of energy
(D)None of these
(C)First law of thermodynamics
H+PAV
(C),Q+AnRT
s
e
(D)None of these
12. For the
reaction, 2Ha(8)+O:(8)2H,0(g).
kJ
The heat of decompoSition of water per mole AH--573.2
is
(A)286.6 kJ
(B) 573.2 kJ
(C)-28.66 kJ
(D)zero
energy
1s the energy required to
13. The bond
(A) dissociate one mole of the substance
(B) dissociate bond in 1 kg of the substance
(C) break one mole of similar bonds
(D)break bonds in one mole of substance
MHT-CET 2008
14. If AU is the heat of reaction for C2H,OH() +302(g)
2C0:(g) +3H20) at constant volume,
the AH (heat of reaction at constant pressure), at constant temperature is
(A)AH= AU + RT
(B)AH= AU- RT (C)AH= AU -2 RT (D)AH = AU+2RT
MHT-CET 2009
15. Heat of combustion of methane is 800 kJ. What is the heat of combustion for 4 x 10kg of
s
t
b
u
1ation of
of gas
methane?
(A)-800kJ
16. 16 g
(B)-3.2
x 10* kJ
1
2
(B)-2875J
(A)zero
ergy of
17.
o
D
(C)-20kJ
(D)-1600k
of oxygen gas expands isothermally and reversibly at 300 K from
work done is (in J)
0
2
(C)+2875
J
10 dm to 100
dm. The
D)infinite
is maximum for which
At the same conditions of pressure, volume and temperature, work done
gas if all gases have equal masses?
.
(A)NH3
(B)N
(C)Ch
energy
process, work is done at the expense of internal
adiabatic
C)
(B) isochoric
(A)isothermal
18. In
T
E
C
dm' to
MHT-CET 2010
nd-683
MHT-CET 2011
(D)H;S
(D) isobaric
by 130 kJ of heat?
decomposed
How much H;O is
19The heat of formation of water is 260 kJ.
(D)2 mol
(C)0.5 mol
(B)1 mol
(A)0.25 mol
T
H
M
TIBT0-TRM
released upon the formation of
-393.5 kJ/mol. The heat
20.1
heat of combustion of carbon
oxygen gas 1s
(D)+31.5 kJ
(C)-315 k
.2g of CO2 from carbon and kJ
(B)-31.5
(A)+315 kJ
reaction depends upon
21.
of
heat
final condition of reactants
the
law,
ccording to Hess's
(B) initial and
reactants
A) initial condition of reactants
end conditions of
D)
intermediate path of the reaction
ne
the
chof
n
o
is
.Eor an ideal gas, the heat of reaction at constant
pressure and constant volume
(A)H +U=PV
are related as
(B)U
is
ww
www.T
wwww
A
it
www
D
etmsen
wNN1
N i
law of
(132)MHT-CET
The first
35. (A)Q--w
Exam Questions
equation.
22. Find the correct
(A)U-U-H2+H n,RT-nRT
niRT
(C)H-H
-U2 +U1 n2RT-
(B)U2-Ui- H2- H
(D)H- H -U2+Ui
36.(A)AH
n>RT + n^RT
n2RT + nRT
s
e
s
t
b
u
MHT-CET 2015
than zero?
reactions, change in entropy is less
following
the
among
which
25. For
(B) Dissociation of Hydrogen
Carbonate
(A) Sublimation of Iodine
(D)Thermal decomposition of Calcium
(C)Formation of water
combustion of 0.090 kg of ethane
=
the work done during
26. Given R 8.314 JK mol,
(D)-6.234 kJ
(Molarmass 30) at 300 K is
(C)6.234 kJ
(B) 18.7 kJ
(A)-18.7k
expansion?
following is a feature of adiabatic
(D)AT 0
27. Which among the
(C)AU>0
1
2
(B)AU<0
o
D
from a volume of
moles of ideal gas is compressed
two
when
done
work
28. What is the amount of
a pressure of 100 kPa?
I m to 10 dm' at 300 K against
(D)-114.9 k
(B)-99 kJJ
(A)99 kJ
MHT-CET 2016
T
E
C
0
2
first law of
29. Mathematical equation of
(A)AU-Q
(B)-AU=Q
(C)114.9 kJ
thermodynamics for isochoric process is
(C)Q=-W
T
H
M
(B)-4988J
AU+
C)
(D)AH AU
MHT-CET 2018
37.
Which among
condition?
(A) AU=
C) AU= W
38. Two moles
against a pre
(A)-201.6k
39. Calculate th
Given: R
(A)-7482J
MHT-CET 20
40. For
a proce
(A) T
41. Calculate
D) AU=W
<0
spontaneous process is
D) ASwtal
*30. The criterion for a
(C)AG =0
0
AG
<
(B)
(A) AG> 0
property amongst the following.
(D) Surface tension
31. Identify an extensive
(C) Density
Heat capacity
(B)
Viscosity
(A)
combustion
mole of methane, CH4g), is subjected to
0.5
when
done
work
of
32. What is the amount
J K mol)
at 300 K ? (Given, R -8.314
(D)+2494J
J
(A)-2494J
is
22H
(B)AH=
AH(reaction)
-286 kJ and enthalpy of fusion of ice
combustion of hydrogen at 273 K is
100 g of
of
enthalpy
Assuming
23.
enthalpy change during formation of
calculate
kJ,
+6.0
be
to
temperature
at the same
(D)-292 kJ
ice.
(C)+292 kJ
(B)-1622 kJ
(A)+ 1622kJ
a volume of Sm to 1dm at
an ideal gas is compressed from
moles
of
two
when
24. The work done
100 kPa is
300 K, under a pressure of
D)42495 kJ
C)-99.5 k
(B)-499.9 kJ
(A)499.9 kJ
(A)AV<0
n
o
Identify the IN
MHT-CET 2014
)C)+4988
MHT-CET 2017
kg of ethane, CaHs (g) at 300 K is
33. The work done during combustion of 9 x 10
mass: C=12, H= 1)
(Given: R =8.314 J Kmol, Atomic
(D)-18.71 k
(C)18.71 kJ
(B)-6.236 kJ
(A)6.236 kJ
to
of Im
volume
an
a
i
from
gas
ideal
2
of
34. Calculate the work done during compression of mol
10 dm at 300 K against a pressure of 100 kPa.
(D)-22.98 k
C) +22.98 k
(B)+99 kJ
(A)-99 kJ
pressure a
(A)27 cal
42. Three mo
300 K ag
(A)-4.18
43.Identifyt
(A)N2
(C) 2H0
44.If Co+
formatio
(A)Y-X
45. "The ma
(A) Mod
(C) Firs
46. Based
o
(A)For
(C)For
. The first law of thermodynamics
for isothermal
(A)Qprocess is
(B)AU-w
(C)AU-Q
36. Identify the INVALID
Chemlcal Thermodynamies
(D)AU0.
equation.
(A)AH2prodocts2t
00g
(B)AH AU+
(C)
PAV
AHemction)2Pmotect
(D)AH
AU
(133)
bomdk)2(
+
AnRT
n
7.Which among the following
condition?
equations represents
(A) AU-Q-Pen. AV
(C) AU-W
38.Two moles of an ideal gas
s
e
the first law ofthermodymamics
under isobaric
s
t
(B)Q,-AU
(D)W--Q
are allowed to expand
from a volume of 10 dm'
against a pressure of 101.325 kPa. Calculate
to 2m at 300
the
work
done.
(A)-201.6 k
(B)13.22kJ
Onate
b
u
(C)-810.6 J
0.138 kg of ethanol, CH,OH
Given: R-8.314 J K
at 300
mol, molar mass of ethanol 46 g
mol.
(A)-7482 J
(B) 7482 J
(C)-2494 J
MHT-CET 2019
40. For a
o
K
D)-18.96
39.Calculate the work done during combustion of
me
n
o
is
MHT-CET 2018
o
D
K
(D)2494
process, entropy change of a system is expressed
as
(A)
1
2
(B)Orev x T
41. Caiculate the
C)H-TS
difference between heat of combustion of carbon monoxide gas at
constant
pressure and at constant volume at 27°C ? (R -2 cal K mol'
(A)27 cal
(B)-300cal
C)54 cal
(D)-600cal
2.Three
0
2
moles of an ideal gas are expanded isothermally from a volume of 300cm' to 2.5
300 K against a pressure of 1.9 atm. The work done in joules is
(D)-423.563
(C) +4.8J
(A)-4.18J
(B)+423.56J
T
E
C
L
a
43. Identify the equation in which change in enthalpy is equal to change in internal energy
ud(B)Co)+OgCO
(A)Na+3Hag2NHs
C) 2H-020+2H;0g+ Oo
ISU
T
H
4. If C+ Ozp
formation
(A)Y-X
M
COp
AH
(D)PCls
-X,
(B)X+Y
CO+;0
(C)-Y-X
PCb+Clh
COAH =-Y, calculate al
(D)X-Y
an isolated system", is the statement of
mass and energy both are conserved in
thermodynamics
thermodynamics (B) Second law ofthermodynamics
of
first
law
Modified
(D) Third law of
(C)First law of thermodynamics
is correct?
46. Bas on first law of thermodynamics which of the following
process, AU-w
an
(B)For adiabatic
process, Q+W
(A)For an isochoric process, AU-Q
(D)Foran isothermal
C) For an isobaric process, Q,-AU+ W
he
for
CcO
ALA
(134)MHT-CET Exam Questions
absorbs 120
47. A gas performs 0.320 kJ work on surrounding and
Hence change in internal energy is
(C) 200 J
(B) 120.32 J
(A)440 J
J
60.
of heat from the surroundin.
Ang
(A) Ha
D)-200J
51.If
CO2g),
AH =
-393.5 kJ.
C(diamond)
C(gphit)(dianmond)
What is enthalpy of transformation of
(C) 1.9 kJ
(B) 788.9 kJ
k
(A)-1.9
is
s
t
+Oztg)CO2(g,
?
61.
s
e
b
u
D) 589.5 k
(A)-679.3
o
D
T
H
reaction
58. For the following
M
>2Fe
Fe,O10)+3CO
of ASiotal) at 298 K?
(A)29.8 J K
AS°
+3CO2(g) ;AH°=-29.8 kJ and
(B) 298.0 J
K
C)100.0
JK
15
JK.
D)115.0
sublimation?
equations is correct for heat of
59. Which of the following
(B)AvapHAubH
(A)AubH- AnuH+AvapH
What is the
JK"
+AruHwatsi)
(C) AaH-
AnabH
x AvapH
ed
D)AubH AtuH-AvapH
re
(A)666.
66. In an
300
K
(A)-5
1-0A)
=
Which of
(A) Surfa
a re
63. For
spontane
62.
bond is
(A)929
ntage0
are 6.01 kJ mol
vaporization for water respectively
of
enthalpy
and
57. Enthalpy of fusion
sublimation at 0°C?
What is enthalpy of
D)39.06 kJ mol
45.07 kJ mol at 0°C.
(C)27.50 kJ mol
mol
kJ
51.08
(B)
(A)48.07 kJ mol
(A)-1924
65. Averag
0
2
MHT-CET 2020
against co
pressure
(A) CaC
is enthalpy of
heat is required. What
following properties is extensive? Melting point
D) Boiling Point
55. Which of the
(C)
Density
(B)
to 10L
(A) Volume
reversibly at 300 K from 1L
and
isothermally
an ideal gas is expanded
56. Two moles of
sem
is
D)4.8 kJom
The enthalpy change in kJ
kJ
C)Zero
(B)-11.4 kJ
(A)11.4 kJ
T
E
C
When 2 m
64. Which
kJ of
gaseous sodium is ionized, 49.4
52. When 2.3 g of
mol (D) 404 kJ mol
ionization of sodium?
C) 48.4 kJ
mol
kJ
(B)494
(A)49.0 k mol
on its surrounding
and does 1.5 kJ of work
heat
kJ
of
6
absorbs
system
53. For a particular reaction, system?
change
of
D)- 1.5 kJ
What is enthalpy
(C)+4.5 kJ
+6.0 kJ
(B)
kJ
(A)+7.5
AcH'(CsH6)»=- 3267 kJ,
formation of benzene if,
of
enthalpy
(H20)=-285.8kJ mol.
54. Calculate standard
AH(CO2)=-393.5 kJ mol and AH" (C)48.6 kJ mol
(D) +32.67 kJ mol
mol
kJ
B) -38.6
kJ mol
1
2
2CO%
n
o
(C)
of formatio
kcal. Calculate heat
Harg)+ Clap >2HCl + 44
48. Consider the following reaction
for 36.5 g of HCl.
(D)11 kcal
(C)-22 kcal
kcal
kcal
(B)-88
(A)-44
ot
condition with liberation
standard
under
elements
from its
*49. One mole methanol is formed
value of ASmu.?
is
(D)238.9 J
238.9 kJ of heat energy. What the
(C)472.8 J
801.7J
(B)
J
(A)711.7
AH and AS respectively are
all temperatures, values of
at
non-spontaneous
be
to
(D) positive, negative
50. For a reaction
positive (C) negative, positive
positive,
(B)
negative
(A)negative,
AH=-395.4
C(gaphite) + O2g)
Which ofth
an
67. For th
pressu
(R
(A)
68. For
f&
280
(A)A
(C)
69. Heat
form
va
(A)
70. Ene
O=
(A)
71. Wh
(A)
(C)
yunding
60.
of the following equationshas
Wh
(A)Hau0za) H,O0
Tmation
)
o
moles of
61.When 2moles
ttion
OB) Nac +Ox
D)CHA+20Cl
2C02()
2Co%+O2)
an ideal gas are
expanded isothermally
ternal pressure of 760
st constant exter
mm Hg.
(A)-1924.0J
of
(B)-25.325J
Which of the following1s NOT an intensive
(A)
y are
Surface tension
(B) Density
(135)
N,ON
froma volume of 12.5
L to 15.0 L
amount
Calculate the
C)-253.25J
k.
py of
is
of work done in joule?
(D)-190.0J
s
e
property?
(C)Heat capacity
a
s
t
b
u
at 25°C and
pressure?
(A) CaCOs)
65.
nding
(B) CHOHo
(C)HO
o
D
1
atmosphere
(D)COp
enthalpy of water is 464.5 kJ mol. If the energy
required to break first O-H
bond is 502 kJ mol", then how much energy per
mol is required to break second O-H bond?
(A)929 kJ
(B) 678 kJ
(C) 427
(D)251 k
Average bond
66. In
ko3-(0
isothermal and reversible process, 1.6 x 10 kg Oz expands from 10 dm' to 100 dm' at
work done in the process is (R =8.314 JK mol)
(A)-5744 J
(D)-4308J
(C)-2872 J
(B)-1436
an
1
2
300 K,
JH
67.
10 L
For the
k
%, For
(B)-672.8
T
E
C
following reaction, relation between AH and AU 1s
230g+Ozg)
(A)AH
and
0
2
combustion of mole of liquid benzene at 298 K, the heat of reaction at constant
pressure is-3268 kJ mol'. What is heat of combustion at constant volume?
(R8.314 x 10 kJK mol
(C)-3264.2 kJ mol (D)-1632 kJ mol
mol
(4)-6728
kJ mol
1
C)AH
T
H
69. Heat
=
250,
D)AH-AU +2RT
AU - RT
are
o
of
Ccombustion
of Co, Hag and CaHeo
formation
of CaH) is
value
M
4)-+2x1+3x2
70.Energy
(B)-X-Xt3
1
to dissociate 16 g
quired
i
1.
kJ
-Xi,
respectively. Hence heat of
-K and-Xg
(C)x tX2-X3
(D)-2x1 - 3x2+X
bond enthalpy
is x kJ. The value of
Oztp) into free atoms
0-0bond
(A)4x
er
(B)AH-AU+RT
AU-2RT
(C) 16x kJ
(B)2x kJ
ch is true for heat and nperature?
e
(A)Both
areiintensiveproperties
C)Both
are extensive oroperties
diue
n
o
CH,Clh+2o
(D)Refractive index
reaction AH -30
kJ and As=-45 J
K", at what temperature reaction
spontaneous to non-spontaneous?
changes from
(A)666.6 K
(B) 375.0 K
C)675.0 K
(D)777.0 K
Which
the
following
of
4.
compounds is Not present in its standard
state
Eor
5.4
ChemicalThermodynamics
AH and AH° same?
of
D
respectively
extensive properties
Intensive and
respectively
B)
intensive properties
Extensive and
(D)
Equilibriur
MHT-CET Exam
(136)
between
72. Relation
Questions
AH and AU
entropy
84. If absolu
(A)
Standard
85.
from its C
(A)2.861
sulphur to
combines with
carbon
when 6 g
heat evolved
of
quantity
the
reaction
according to the
kJ mol
C+SCS, AH--92
kJ
(A)11 kJ
(B)46
(D)22 kJ
(C)32 kJ
indicates the reaction
following conditions
the
temperature
*74. Which of
at all
AG<0
AH
<0,
(A)AS>0,
temperature
AG>0 at low
(B)AS <0, AH>0,
temperature
at high
(C)AS <0, AH>0, AG>0
at all temperature
s
t
b
u
300 K?
AS(coa) for following reaction at
What is the value of
AH°=-25kJ, AS° =15JK")
Fe,O3+3CO2Fe
(A) 8.32 JK
+3C02)
(B)98.3 JK
(C) 68.2 JK-
(A)-607.8 J
(B)-60.8J
(C)-30.4 J
o
D
(D)-6.0J
1
2
AH =-1368kJJ
CHOH +302()2C02(p)+3H,O0
AH° =1410kJ
(i) CHAg+302g)2CO2() +2H,0
(C)+42.0kJ
(B)-1326.0 kJ
(A) +2778.0 kJ
0
2
10 m
x
78. An ideal gas expands from
work done is
pressure of 1 x 10° N
(B)-9x 10
(A)-0.7 x 10 J
1
T
E
C
m,
to
J
1
x
x
10J
T
H
extems
(D)-1 x 10
80. If 38.55 kJ of heat is absorbed when 6.0 g of O, react with CIF according to reaction
iRsra
2CIF+Oz)CL+OF
M
(C) 72.28 kJ
D)
49.80 kJ
Wha
Sample,
81. A sample of gas absorbs 4000 kJ of heat and surrounding does 2000 J of work on samp
is the value of AU?
(A) 4002 kJ
(B) 4000 k
2000
6000 k
(C)
change
(A)-2k
89. Whatis
N
odaidAHH(A)23
90. When
(A)
(D)-4188.0kJ
the
calculaic
79. When a system absorbs 8 kJ of heat and does 2.2 kJ of work on surrounding,
internal energy change
(B) 10.8 kJ
(A) 5.8 k
(D) 8.0 kJ
(C)-10.2 kJ
What is the standard enthalpy of reaction?
(B) 102.8 kJ
(A) 205.6 kJ
87. If 2 kJo
What i
10 m' at 300 K against a constant
C)-9
(A)-92.
(A)AU
D)-10.0 JK-
water from
from ethene gas and liquid
ethanol
formation
of
the
for
77. What is the value of AH
following data?
)
the
86. From
N2(g)+3
88. For the
a volume of 4
isothermal expansion of a gas from
during
done
work
76. Calculate the amount of
external pressure of 3 atmosphere?
to 6 dm against a constant
dm
n
o
is
s
e
is spontancous?
(D)AS<0, AH>0, AG>0
75.
83. (A)-7.191
-RT
(B)AH +AU== RT
(D)AH-AU
(A)AH+AU = RT
(C)AH-AU= 2RT
73. What is
2S0+O2(g)
reaction, 250
for the
is
kJbes(D)
82. An ideal gas expands isothermally and reversibly from 10 m to
20 m at 300 K, P
5.187 kJ of work on surrounding. Calculate number of moles
of gas used.
(A) 3
(B) 2
(C)1.5
(D) 1
eR
-
91. When
follow
(A)W
(C)A
92. What
from
(A)
93. The
Calc
(At.1
(A)1
*94. Whe
(A)A
(B)
C)4
(D)
form
Chemical Thermodynamies
Equilib anstant for a reaction is 20. What the
(137)
(B)
mol
k
value
is
0t
of AG at 300
A)-7.191 kJ moll (B)-2.763 kJ mol"
K? (R-8x 10 kJ)
(C)-5.527kJ mol
16.63 kJ mol
(D)
of a solid is greater than zero,
at T 0, it
84 Ife
is called
A)ahsohute entropy (B) formal entro
(C)residual
CS
Standard enthalpy of
8
entropy (D)standard
entropy
fomation
of water is-286 kJ mol
s
e
s6. From
3Hael
2NH() AH=-92.6 kJ,
(A)-92.6 kJ
(B)-46.3 kJ
heat
the enthalpy offormation NH,
of
(C)-185.2 k
released from system and kJ
1f2
6 of work
change of system?
(B) +8 kJ
(A)-2k
(C)-8
kJ of
is
is
For
(A)AU-RT
me of 4
89. What
is
N2(g)+ 3H2g)
k
o
D
(D)+6 k
(D)AU -2RT
AH°-83kJ
389 kJ
1
2
(B) 435 kJ
(C)946 kJ
(D) 1305
k
90. When 6.0 g of graphite reacts with dihydrogen to give methane gas, 37.4 kJ of heat
What is
1
92.1
what
1s
T
E
C
J, Q
(A)-34.58 k
T
H
ate
M
(C)-37.4 kJ mol
(D)112.2 k mol
-500 J
RAC
(B)Q-500 J, W- 0
(D)Q=-500 J, AU 0
of an ideal gas
is expanded isothermally and reversibly
=
m' at 300 K? (R 8.314 JK mol")
C) 3.458 k
(B)-3.458 kJ
D)-1.725 k
and water is -1172 kl mol
acetaldehyde to carbon dioxide
acetaldehyde were completely oxidized.
amount of heat liberated when 66 g of
AL Mass C = 12, H 1, 0 = 16)
(D) 1758 k
2344 k
(C)
(A)1172 kJ
(B) 6600 kJ
temperatures?
94.Whe
spontaneous at all
the reaction becomes
31The
orming
=
the work done when 2 mole
rom 5 m to 10
What
liberated.
mole of gas is heated at constant volume and heat supplied is 500 J then which of the
C)AU -0.5
the
0
2
(B)-112.2 kJ mol
following is correct?
(A)W 500 J, AU =0
ate
is
standard enthalpy of formation of CH42
(A)-74.8 kJ mol
91. When
enthalpy
standard N =sN bond enthalpy from following reaction?
2NH
N3H
k, AHH)
AH-435
(A)2334
er from
(C)AU+RT
is
b
u
2NH(), AH is equal to
B)AU+2RT
s
t
done on the system, what
k
the reaction,
is
(D)-138.9 k
of combustion of
be
A)AH+ve,
B)AH
+ve,
C) AH -ve,
D)AH-ve,
AS=+ve,
AS-ve,
AS--ve,
AS=+ve,
A
AG- +ve
AG--ve
AG--ve
n
o
is
When 1800 mg
ent elements in their standard
fromits constituen
of water is formed
states
the
amount of energy liberated
(A)2.86 kJ
(B) 57.2 kJ
is
(C)5.72 kJ
(D)28.6 kJ
the given reaction,
w
108. He
(138) MHT-CET Exam Questions
-395
20 m at 300 K performine
ming
isothermally and reversibly from 10 m° to
expands
gas
expansion.
ideal
undergoing
95. An
gas
Calculate number of moles of
5.187 kJ of work on surrounding.
(R 8.314JK mol
(A)2
175.8 JK mol
N,O4()2NO2() is 57.24 kJ and
*96. If AH and AS° for the reaction
at 298 K?
What is the value of AG° for this reaction
(D)-4.85 kJ
(C) 4.85 kJ
-17.58
kJ
kJ
(B)
(A) 57.24
property?
97. Which of the following is an extensive
Specific heat
(B) Surface tension (C)
(A) Density
(D) Volume
98. For the reaction, CH,OH
RT
Which among the following is true?
(C) AH- AU-2 RT (D) AH= AU= AU + RT
AH
(B)
RT
AH
AU+2
1
Rh(A)
from a volume of 5 m to dm at
compressed
is
gas
ideal
an
99. Work done when 2 moles of
is
ao 22
300K, under a pressure of 100 kPa
D) 499.9
(C) 424.95 kJ
(B)-99.5kJ
kJ
s
t
b
u
(A)-409.9
AU?a
AH is not equal to
100. In which of the following reactions,
(B) Na+Oac)
>SOi +NO
(A) SO+ NO
C)
(D)
2H
H+
kJ
101. If heat of combustion of methane is -800
of 4 x 10 kg of methane.
(B)-3.2
(A)-800 k
(C)-280 kJ
T
H
M
(B) 650.0
KK
V
(B
(C
113.
c
molirnos
114.
cota
115.1
taod sd
DH
a
(C)Q= W 000(6) (D) Q> w
mol.
What quantity of water is converted to
(C) 5.5 mol
(C) 823.0 K
H2 and
(D) 0.275 mol
of
*107. At what temperature, a chemical reaction will have following values
AG -5.2 KJ mol, AH = 145.6 kJ mol, AS=-216 kJ mol
(A) 698.1 K
00(A
(D)-20 kJ
latso
106. Heat of formation of water is -272 kJ
by 750 kJ of heat?
(B) 2.75 mol
(A) 7.5 mol
(A
(A
are 191.5, 130.5 and 192.6 J Kmol
(B)
F
eth
111.
gto alomt psi
OCcuo
*104.The standard entropies ofN2()H2p and NH(
respectively. The values of AS° for formation of NH, is
(B) Zero
(A)-98.9JK"mol
D)- 29.4 JKfo
K' mol
105. For an isothermal process
Q=- W
(A) Q< W
(A)
2S0)
indicte spontaneity of rection at all temperatures?
*103. Which of the following set of parameters
(B) AH +ve, AS = -ve, AG = +ve
(A) AH = +ve, AS = +v e, AG =-ve
(D) AH =-ve, AS =-ve, AG =+ve
(C) AH=-ve, AS = +ve, AG = -ve
T
E
C
110. F
112.
ooieml 1o gglirtno basbote ef isrt
102. Thermodynamics deals with
(A) microscopic properties of system
(B) macroscopic properties of the system
(C) rates at which physical and chemical processes
system
(D) the path between the two states of the
0
2
(D)
combustion
mol, calculate enthalpy change for
1
2
10 kJ
x
o
D
kJd
>2NO(
2S02) +Ocg)
n
o
is
s
e
2C02)+3H;O0%
+302()
(A)
(B)
(C)
respectively
o
WH
109.
(D)1
(C)1.5
(B) 3
(A)
AG, AS and AH
(D) 425.0K
HAC
l16.
K performing
pansion
Chemical Thermodynamics
of formation of ethane, ethylene
(139)
acetylene and
kJ)
carbon dioxide are
respectively most stable
395 (all in
among them
-136, 66, -228 and
is
(B) Acetylene
(A) Carbon dioxide
(C)Ethylene
(D)Ethane
109. Which of following is residual entropy
of a substance?
entropy
solid
equal
of
to
A)
0 at T-0
B)entropy of solid equal to 0 at T-273 K
entropy of solid greater than 0 at
T-273 K
D)entropy of solid greater than 0 at T 0 K
at
respectively
110 For a reaction,
(A)+ 10 kJ
AH=-50 kJ, AS-150JK"
(B)-110 kJ
is
s
e
at 400 K. What is
the value of AG ?
(C)-10 kJ
s
t
(D)-50.15 k
From the following reaction, calculate the
amount of heat liberated
during formation of 75 g
ethane
1
RT
C,H+H)
to I dm
(At mass C=
CHs)iAH--124 k
12, H
112.
mol
(B) 310 kJ
(C) 372 kJ
o
D
Which of the following reactions is NOT exothermic?
(A)
b
u
1)
(A) 248 kJ
2
Ha0to
H,Oo +286 kJ
(B) 2KCIO,s)
(D) 284 k
2KCI
+302(+78 kJ
(C) Na+202)
2NO2(- 66.4 kJub botoed
D) CHp +202)
CO0+2H,0 +890 k
combustion
1
2
0
2
For combustion of I mole of liquid benzene at 298 K, the heat of reaction at constant volume
-3264.2 kJ. What is the heat of combustion at constant pressure? (R = 8.314 JKmolr')
(A)-3267.9 k mol (B)-816.9 kJ mol
(C)-2439.2 kJ mol (D)-1633.9 kJ molr
113.
Standard entropies of N2(g), Ha) and
value of AS° for formation of NHs(?
114.
itures?
n
o
T
-1 E
C
(A)a,-a+
Kmo
T
H
200
NH3) are a, a, and as JK mol respectively. What
is
is
(B)a
H
(D)a,-
to react at
mL of ethylene gas and 200 mL of HCI gas are allowed
2
atmosphere pressure
as per given reaction,
M
HandO
AH ?
C,Ha+HCl
pressure volume work in Joule.
ate
dC)
(A) 20.26 J
116.How
gram of
286Lany
kJ moll?
(A) 27
o
CHCl
g
40.52 J
(D) 26.20 J
(B) 54.40 J
decomposition of water is
429 kJ of heat it heat of
by
decomposed
water is
(B) 40 g
vroo
(C) 36g
308
0(D)
)
22.5 g
t
Whe
(A)AH
129.
Questions
(140) MNT-CET Exam
n
o
following
reaction from
117. ldentify endothemic
(B) Na+20
)CH+20
D)
(B)AH
2KC+30,+78kJ
(A) 2KCIO
CO+2H,O,+890k
s
e
H,0,+286k)
H+
118.At what temperature, a
following values?
chemical reaction will have
AG-4k, AH--60 k), AS-160
K
J
s
t
(D)400 K
(C) 350 K
(B) 250
(A) 300 K
is
2NO66.4kJ
I
119. Standard molar entropy is
and 25 °C
nmole
a pure substance at atm
(A) the absolute entropy of one mole of pure substance at 1 atm and 298 °C
of
(B) the absolute entropy of one
pressure and 25 °C
one
mole
of a pure substance at 700 mm
of
entropy
(C)the absolute
substance at atm and 298 °C
(D)the absolute entropy of one gram of a pure
K
reversibly from 10 m' to 20 m at 300
and
isothermally
expand
ideal
gas
an
mole
of
120. Three
calculate the work done. (R- 8.314 JK mol)
b
u
a
1
(A)-1037.4kJ
o
D
(C)-51.87 k
(B)-2593.5 kJ
1
2
10 kJ work
121.A system releases 15 kJ of energy as heat and does
nternal energy change.
(C-25
(B)-5 k
(A) 5 k
0
2
kJ
122.Calculate the amount of heat liberated during formation of 2.7 kg
water is-284.5 kJ mol.
(C) 1.896 x 10 kJ
(B)4.267 x 10 k
(A) 4.267x 10° kJ
of
123. For which of the following reaction, AH AU?
2 COp
(B) HOu
(A)2
T
E
C
CO+Ox
(C)Ha+Bra
2
HBr
(D) PCls
(D)-5.187 k
on surrounding, calculate
of water if heat of formation
(D) 2.896 x 10kJ
T
H
OoCOo
0.154 kg of CO
(A)1386.0 kJ
AH--396
(B)346.5 k
126. The H-H bond energy is 430 kJ mol
-90 kJ, then H-Cl bond energy is
(B) 180 kJ mol
(A)213 kJ mol
M
AnRT
mol", calculate heat liberated during formation of
(C)693.0 kJ
(D) 1039.5
and CHCI bond energy is 240 kJ mol
(C) 360 kJ mol
of SO
(A)
131. Ider
(A)J
132.The
(A)
133. He
heat
(A)
(A)
(B)
(C)
(D
ist
Clh
-
kJ
130. Heat
135. A
124. Which of the following equations shows the relationship between heat of reaction at constant
pressure and heat of reaction at constant volume if the temperature is not constant?
(B)AH AU
(A)AH-An- AURT
RT
AnRT
C)AH
(D)AH AU
125.If Co+
(D)AF
134.Wh
(D) 25 k
H,O
PCl+
C)AH
k
136. V
(A
(B
(C
(D
137.
AH for HC
(D)425 kJ mol
127. Heat of combustion of liquid benzene to carbon dioxide and water
is-3266 kJ
the amount of heat liberated when 780 mg of benzene is fully oxidised?
12, H-1)
(At mass of
(B) 326.6 kJ
(A)65.32 kJ
(C)16.33 kJ
(A
2
mol. Wha
C-
(D)32.66 k
128. Which of the following is an intensive property?
(A) Internal energy (B) Mass
(C)Volume
(D) Melting point
138.2
11l change
he change in Gibb's free
Chemical Thermodynamics
will be
energy always
(141)
129. When
negative?
AS
both
positiv
and
at low temperature.
A)AH
(B)AH
negative, AS
(C)AH positive, AS
=
formation of SO2 is
Heat of format
of SO2.
A)-32.8 k
O
m at 300 K,
-298 kJ mol". Calculate
(B) -18.6 kJ
n
o
ratures.
is
s
e
enthalpy change during formation
(C)-37 kJ
of 4 g
(D)-20.4 kJ
Identify the unit used for measurement
of energy according to
international system of units?
(A)J K mol
(B)kg s2
1
25 °C
negative at all
th negative at high temperature
(D)AH and AS
130.
positive, at all temperatures.
m
s
t
(C)kgm's2
(D)kg m
s
112.The equilibrium constant for a reaction is 10, value
of AG" at 300 K is (R = 8 x 10 kJ)
(A) 11.054 kJ mol
(B) 2.763 kJ mol
(C)5.527kJ mol
(D)-5.527 kJ mol
Heat of formation
heat?
(A) 45 g
133.
ding, calculate
b
u
of H;0 is -270 kJ mol". How much water can be decomposed
(B) 33 g
o
D
C) 40 g
by 675 kJ of
(D) 27 g
134.When will be the reaction becomes spontaneous at all temperatures?
it
1
2
AH=+ve or -ve, AS = 0, AG =0
(A)
of formation
(B)AH=-ve, AS = +ve, AG =-ve
05hmol hrod= +ve, AS = -ve, AG = +ve
togoibgo to yno brod sio
(D) AH=-ve, AS = -ve, AG =-ve or tve olom
10 gro cotuooeeih beo
(C) AH
10 kJ
135. A
is
on at constant
so
sample of gas absorbs 4000 kJ of heat and surrounding does 2000 J of work on sample, what
the value of
(A) 4000 kJ
AU?
T
E
C
136
0
2
EE
(B) 6000 k
(C) 2000 kJ
(D) 4002
kJ(
Which of the following statements does not represent first law of thermodynamics?
spontaneous flow of heat is always unidirectional from high to low temperature.
total internal energy of an isolated system is constant. co
he
formation of
ne
Total energy of universe is constant.
amount of other form must appear.
one form of energy disappears, exactly equivalent
when
T
H -2
is
H for HCI
aol
137. Given
that,
Co+O2g)CO2
20
Ma
ol.
point
What 1s
)+O2e)
(A)Y-2X k
>2C0,
AH--Xk
AH=-YkJ, then standard enthalpy of
(B) 2X- Yk
formation of carbon monoxide is
l
HA
What is the change in
releases 1500 J of heat.
it
and
system
done on the
internal energy? is
(D)2500 J
(C)1500 J
(A)4000
J
(B)1000
138.2.5
kJ of
J
(142) MHT-CET Exam Questions
SOLUTIONS
1. (C)
absorbed or evolved when
Heat of formation is amount of heat
from its elements.
Given, mass of CO - 0.176 kg = 176 g
I
Molecular weight of CO; = mole of CO;44 g
CO-393
C+O
2 x 16g
44g
12 g
kJ
1
mole of substance is ormed
for
kJ
Heat evolved when 44 g of CO; is produced =-393
393
kJ
produced=-x176=-1572
Heat evolved when 176 g of C0, is
44
Enthalpy is total heat content of system.
Uinternal energy)
H
tPv 0Lt nou
3. (B)
om
b
u
=AU+PAV=AU +An RT
AH
PCls(g)
PCl(g) +Ch(g)
Ang
P ),2-1
AH=
AH>
=
1
AU+1x RT
AU
o
D
0
2
nalWEr
odoisr orh sd lbw
4. (D)
Bond dissociation energy=- bond formation energy
Given, bond energy of hydrogen =-433 kJ
. Bond dissociation energy of one mole of H = 433 kJ
433
+216.5
Bond dissociation energy of 0.5 mole of H2=
1
2
s
e
s
t
2. (C)
n
o
is
om
kJt
afque
A2E
C06(C
0003 (8
009S 10)
5. (B)
accompanying
when one mole of substance undergocs
changes
is
heat
total
Heat of combustion
complete combustion in excess of oxygen.s
to
asoosltoq sd'f (A)
S+O2 SO2, AH= 298 kJ
=
mass of S 32 g
SO,
Atomic
of combustion of
Heat of formation of SO; heat
1
Combustion of 32g of S (= mole of S) gives heat =-298 kJ
T
E
C
tso
a td
Combustion of 4 g of S gives heat =
T
or
H
M
6. (B)
W
-PAV
Given, P = 100 kPa= 10° Pa, Vi
W
=
1dm'
-298
32
=
x4=-37.25 kJ
10m',
V2=
10x (1- 10) J=99900 J
7. (A)
AHeaction
-2
oll
2 AH of reactants
AHCO-94.1 kcal,
00
1m00
0+0
AH of products
AH CaH=-21.1 kcal,
CaHs+02
200+3H,0
AH H0=-68.3
kcal
[2 AHCO,+ 3AH
AHpombustion
Chemical Thermodynamics
(143)
H,0)-|AH,CH,+AHO
- (2x(-941)+3(-68.3)--21.1x
ve is
(-188.2-204.9)
+21.1-393.1+21.1
formed
AU Q+w
C: temperaure
0
Q+W 0+
W0, Q-0
is
W
to De increased, no
heat should enter
or leave the
=
AU W
is
system)
s
e
9.(C)
Taternal energy, enthalpy
and entropy are state functions
but work and heat are path functions
s
t
.(B)
Hess's law is
based upon
law of
conservation of energy.
b
u
11.(C)
The
heat of reaction for ideal gas, at constant pressure and volume
Q-Qt
12.
AnRT
o
(A)
Heat of decomposition of water is
88.2=286.6kJ/ mol001og
AH= T
o
D
H,O(g)H(g)
10
1
2
+
The bond
i15,
bar
o,(.
a00-
noliaonot ort aoau boenoln
00103 3ooeot
13. (C)
elt
nce
boere
energy is the energy required to break one mole of similar bonds.
0
2
14.B)
We know that, AH = AU+AnRTisqal
undergoes
Where, An =
T
E
C
-2-3--1
So,
15.(C)
AH
AU-RT
16g
0
AH,-800kJ
kg CH-800
10
Heat of combustion of 16 x
CH will be
Heat of combustion of 4 x 10 kg
M
0-
T
rU- H-R 10 (T
CH4+20>CO2+2H20;
T
H
number of moles of gaseous reactants
number of moles of gaseous products
kJ
800x 4x10
-=-20kJ
16x103
(90
16.(B)
300log
W= 2.303 nRT
log2-2.303xx8.314x
2872 J-2875 J
n
o
-372 kcal
8.(A
100
0
ounslnc
E
(144)MHT-CET Exam Questions
depends only upon
is also same, work done
When P, V and T are same and mass
M molecular mass)
W
1s maximum for
lowest molecular mass, so work done
Among the given gases, NH, has
24. (A)
Work d
molecular
17. (A)
(Where,
Here,
i
is
18. (C)
supplied from the surrounding, Q0
We know that, AU- Q+ W. Ifheat
AU- W
i.e. Work is done at the expense
19. (C)
water is as
The reaction for the formation of
AH 260 kJ
s
t
93o facn
)
b
u
On reversing Equation (), we get
H01 mol
H,+o.
.(i)
AH=-260 kJ
.
1
2
kJ/mol
AH -393.5
C+OcO
formation of 44 g of
the
upon
Heat released
CO%
CO2
Heat released upon the formation oflgof
Heat
0
2
25. (C)
For th
2
m
Three
beco
26. (B)
o
D
= 1 mol
By 260 kJ heat water decomposed
=.1x130 0.5 mol
130 kJ heat will decompose water
260
20. (C)
s
e
0 for adiabatic process
Q
of only internal energy and
n
o
W
No
Ca
=-393.5 kJ
393.5
27. (B
44
released upon the formation of 35.2 g of CO2
-395.35.2 -315
n
kJ
44
28.(
21. (B)
conditions of reacta
According to Hess's law, the heat of reaction depends upon the initial & final
T
E
C
22. (C)
We know that, AH
H2-H U-Ui
T
H
23. (B)
AU + AngRT
+ (n2RT- niRT)
=
Hg)+;0-(8)
H;0(0;
(I) HO(9)H,O();
M
U00
18 g
Hag)+0,(g)
:
or
Ha- Hi -U,+U1
= n>RT
H,O0)
- nRT
0SC3e089
AusH=+ 6
k oiadco to lill
AH--286 kJ
to
On subtracting (1) from ()
On
29.
odeadmoo to 1
AH--286-6--292 kJ
formation of 18 g ice, change in enthalpy-292 kJ
o
kJ
On formation of 100 g ice, change in enthalpy=-410-1622
18
S
30.
22
31.
32.
(A)
24.rk
done,
ass
100 kPa
Here, Pext
1
dm'
1
L
-100 x (l -500)=
=499900 J = 499.9 kJ499900kPa L
1
25. (C)
For the reaction
2H:(g)+Oz(g)
kPaL
HO()
2
more ordered state
Three
(145)
Sm=5= x 10 L
Vi
V2
W
Chemical Thermodynamics
W=-Pext (V2- Vi)
1
AS negative
less disorderd sate
s
e
(
gas-phase moles are
converted into two moles
hecomes less disordered
of liquid. The more disorderd state
state. The entropy
of the system decreases because
disorder decreases.
I:8)
AS positive
>2H(8)
Hg)
AS positive
CaO+CO2 (g)
CaCOs (8)
b
u
AS positive
re
26. (B)
-AnRT
W
No. of mole =
0.090
30x10
=3
COg+3H,0() for
CHa)+7;(g)2
An=
W
n2
--2.5
- n 2-4.5 -2.5
1
2
=
x 8.314 x
28. (A)
ants.
0
2
adiabatic expansion, AT *0, AU # 0.
W
-
29. (A)
AUQv
30. (B)
PAV =
-
100 (1- 0.01) =-
T
E
C
100
o
D
mole
30010
10x 300 x 3) =
27.(E
In
1
s
t
18.7
kJ0-UA
0
(A8E
1240101 o122E.10f-9
(VA)
(-0.99) = 99 k
9s2sc101)s00E101-)
thermodynamics for isochoric process.
is the mathematical equation of first law of
process.
AG<0 is the criteria for spontaneous
31.(B)
T
H
t capacity is the only extensive
32.(D)
property out of the given
CH4)+202g)CO2zg+2H,O0
M
options.
LCOAC006PIC (0)
8
orob bow locas
CO2
1 moles of
-AnRT
oxygen to produce
moles
of
mole of CO
I mole of methane reacts with 2
O% to produce l
1 mole of
with
Hence
mole of CH4 reacts
Dmoles of reactants= 1.5
nmoles of product
Amount of work done =
0.
An =n2-nj =
1
=l
-1.5=-0.5SJKmol=+2494 J
0.5) x 300 x 8.314
g
n
o
is
kJ)
(146)MHT-CET Exam
Questions
33. (C)
reaction is
Work done in chemical
W--An RT
3H;O(
IC,H(8)+0; (8)> 2C0,(8)+
An-2-4.5-2.5
s
e
For 30 g=1 mole
18.71 kJ
For90 g=3 moles=
34. (B)
m
W--PeaxAV, AV= (0.01
Im) =
-
35. (A)
thermodynamics is, AU
First law of
isothermal process, AU = 0
For
36. (C)
AHreaction)
-
(-0.99) m'=
0.99 m'=-100 kPa
wralpetb
=
Q-w
bonds
o
D
AHrEaction)2AH(reactant bonde)2AH(product bonds)
1
2
37. (A)
First law of thermodynamics is
AU Q+P. AV
0
2
When P is constant i.e. isobaric process
AU=
38. (A)
Qp-Pex. AV
T
E
C
=
P 101.325 k Pa 101325 Pa
Vi 10 dm' = 10x 10m' = 10
energy necessary to break
00.0 olom 10 of
0x0EE82-
W
m', V2= 2 m
= -101325 x (2-0.01)
=(-101325) x (+1.99) J=-201.636 kJ
T
H
39. (B)
CgH,OH
M
xesl8s0995
-P (AV)
W
An
.
99 kJJ
s
t
b
u
Q+w
bonds
energy necessary to break reactant
Q- Q
is
6.2355 kJ
W-+2.5 x 8.314 x 300
= 6.2355 kJ
=
+ 302(g)
2002) +3H00
2-3--1
W=-An RT
300 2494.2 J
For 46 g ethanol work done 2494.2 J
W=+(1) x 8.314 x
138
gethanol work donexJ
138x24942 7482.6J
46
40. (A)
n
o
vnaitonanol arotosb0
0E
product
Chemical Thermodynamics (147)2
41.(8)
CO
co+
An,
-1-1.5-0.5
AHAU+An,RT
AU = AnRT =-0.5) x 2x 300-300 cal
V300cm', V,=2.5L, T=300 K, P=1.9
atm,n-3
As
gas expands against constant external
pressure,
W
99 kJ
-PAV=
-1.9(2.5 -0.3)=
=4.18
L atmx 101.3
-423.43 J
atm
6
s
t
43.
AH
AU+ PAV or
.. AH= AU at An = 0
In the
to break product
AH= AU + AnRT
reaction, Co) + Og)>CO),
s
e
-1.9(2.2)
0 01 ei0.16
b
u
A, =0
4.(A)
45. (A)
o
D
According to modified first law of thermodynamics mass and energy
are interconvertible when
mass decreases, energy increases in some process.
46. (C)
AU
=Q+ W
For isochoric process, AV =0
For adiabatic process, Q =0
For isobaric process AP =0
For isothermal process AU=0
47. (D)
1
2
120 J
AUU
W
AU=
.
Q- AU+ W
Q--W
vontood
0
2
W=-0.320 kJ = -320 J
Q
Q
bos Ra eo
Ato.000 orods oouog
oun
AU=Q+W 120-320-200 J
T
E
C
48.(C)
49.(B)
O
AH= TAS
AS=
ca).1e
M
T
H
50. (D)
AH
238.9x10-801.7J
298 K
56. (C)
For isothermal reaction
53. (B)
52. (B)
51. (C)
of ideal gas
enthalpy change zero.
57.(B)
AruH
6.01 kJ mol
kJ mol,
45.07
For
sublimation at 0°C,
,0
AsabH
HO
54. (C)
x001
ApubH = 7
H,O»
6.01+45.07 51.08 kJ mol
b 01V
55. (A)
n
o
is
42.(D)
(148) MHT-CET Exam Questions
For
58. (D)
the entropy
o the
y of
system loses heat to surrounding. Hence
Since the reaction is exothermic,
surrounding increáses.
AHgur+29.8 kJ = 29800 J
29800
ASu A
ASTotal
T
= AS,ys +
ASur
+100
= 15
61. (C)
n2
Vi = 12.5L= 12.5 x 10
mol,
P 760 mm of Hg 1.013 x 10° Nm
W
-Pext (V2-Vi)= -1.013
= -2.5325 x 10x 103
W
-253.25
m,
V2 = 15.0 L = 15.0 x
s
e
10 m,
s
t
10 (15.0 - 12.5)10
x
is
115 JK
60. (A)
59.(A)
b
u
J
63. (A)
-0.045 kJ K
AH--30 kJ, AS = -45 JK=
-30 kJ
AH
=
-0.045 kJ K
1
2
666.67 K
o
D
AS
AH
and AS are both negative, the reaction is
Since
0
2
spontaneous above 666.67 K.
64. (C)
Water at 25° C is present in liquid state.
65. (C)
T
E
C
T
H
H
464.5
M
66. (C)
t0C-
me
L0S1
toE-0-04
(a1.e
2ATH
2
moluo vglaiteeg lsabiogots l
Mo
-0.5mol
32
69.
+AH
Vi 10 dm
,V=100 dm, T 300 K,
R 8.314 JK mol,
mo.- 1.6 x 10 kg= 16g
n
().
0E.0--W
x 2 502+AH2
AH2= 929 502-427
68.
spontaneous at low
AH-?
+O
Average bond enthalpy = AH
Q
0-9 er0o1 9pdsiba t01
GA 0014 sdoero
temperature and non
Average bond enthalpy of H0 is 464.5 kJ molr
H,O H
AH 502 kJ mol
+OHo
OH
C
el nt
matter present in the system)
Extensive property - heat capacity (depends on the amount of
refractive index (independent of the amount of
old i. Intensive property - surface tension, density,
matter present in the system)
i.
T
67. (C
HA
roiteror
62. (C)
sd
n
o
100 JK
=
298
o
T2
ion 1e
70.
12.
For
ofthe
isothermal and reversible process.
Chemical Thermodynamics
-2.303 nRT logto
Wa
- 2.303x 0.5 x 8.314
x
300 xlog1o
67. (C)
s
e
Q-3268kJ mol, Ang-1.5
298
T
K,
R=8.314
x
s
t
10 kJK molr,
=?
Q
Now,
b
u
-Q+An RT
Q, QpAn RT
Qp
-
tem)
-3268-[-1.5) x 8.314 x 10
x 298]
--3268 +3.716
Q, -3264.284 kJ mol
unt of
68. (C)
AU+ AngRT
2S02 +O2)
2S0
AH
An
non
=np-n= 2-3 =-1
AHAU RT
-
69.
i.
AH-X
T
E
C
AH2-X2
i H,+0,H,O
CH,+o,200,+3H,0
ii.
T
H
AH
AH
70. (B)
CH
2AH +3AH2 -AH
-2x-3x2 +X3
71. (D)
72.(D)
M
SOs
An
2S020+O)
3-2=1
Now, AH
AU+AnRT
AH-AU =RT
(E)
AH-X3
3
ultiply equation (i) by 2+multiply equation (i) by
2C+3H,
o
D
0
2
CO,
C+0,
1
2
n
o
is
-2872J
>6CO20+3H,O
O
CH
(149)
-
equation (i1)
wrw
MHT-CET Exam
Questions
(150)
73. (B)
W=
CS,
(Endothermic reaction)
mol
AH--92 kJ evolved = 92 kJ
heat
For 12 g C,
kJ
heat evolved - 46
For 6 g C,
C+S,
.
74. (A)
oe 203-
75. (B)
exothermic,
The reaction the
=
25000 83.33 JK
AHuT
T
ASys
AStotal
s
t
300 K
t+ASqu
+83.33 JK
AStotal =98.33 J K
= 15 JK
76. (A)
b
u
PIEC211-2
atm
Pex
4 dm, V2=6dm',V1) =3 4)
=-3(6Now, W= -Pex (V2-
V
=
L.
-6
atm=-6 x
607.8
W
101.3 J
J
7. (C)
1
2
Subtract equation (1) from equation (ii)
AH = 1410 - 1368 = 42 kJ
78.(B)
V= 1x
10
m
=
0.001 m
V =1x 10 m' = 0.01 m
o
D
0
2
Pex1x 10 Nm2
W =-PeV2-Vi)=-1x 10° (0.01 -0.001)
W
T
E
C
-0.009 x 10°
-9x 10J
79. (A)
Q +8 kJ,
W
AU= Q+W
T
H
80. (A)
2CIF+O21
For 6.0g of O2
M
For
O.
32.0g of O2
AH°= 38.55x32 = 205.6
kJ
6
81. (A)
Q=+4000 kJ, W = +2000 J= +2 kJ
AU Q+ W= 4000+2 4002 kJ
82. (A)
VI= 10 m' = 10 x 10' dm
V2 20 m = 20 x 10 dm
n
83. (A)
K=2
AG°
84. (C)
85. (D)
H
86. (B)
Na
004
0H
00R
87. (A)
Q=
0
No
88. (D)
-2.2 kJ
8-2.2 5.8 kJ
Cl,0+OFg)
AH +38.55 kJ
n
o
is
s
e
25000 J
AHu=+25 kJ
ASsur
300
T
Na
-AEHAS
ar-H4
(a) at
89. (C)
N
A
T
Chemical Thermodynamics (1531)
W=-5.187 kJ= -5187
300 K,
W--2.303 nRTlog
5187-2.303
x
n x 8.314 x 300 x logi
0
5187
2.303x8.314 x 300 x 0.301
moles
20x10
10x10
alo
3
n
00
s
e
83.(A)
10 kJ K mol
K 20, T= 300 K, R 8x
= -2.303 RT logio K
AG
:-2.303 x 8 x 10 x 300 x logio(20))
s
t
AG-7.191 kJ mol
b
u
84.(C)
85.(D)
H,O
AH =-286 kJ mol
18g
For 18 g
o
D
of H0, amount of energy liberated = 286 kJ mol
energy liberated=
: For 1.8 g of H,O, amount of
1
2
86. (B)
0
2
Enthalpy of formation of NH,
87.(A)
Q--2 kJ,
T
E
C
W
286
28.6
18
kJ+O0
AH=-92.6 kJ
2NH3()
Natg)+3H2g
=
-92.6
=46.3
kJ
ar t faote a
+6 kJ
AU=Q+W=-2 +6=4 kJ
Now, AH =AU- W = 4-6=-2
H.2
kJ
88. (D)
Na1p)+3H2
T
H
M
HA
An
89.C)
=
is
2-4
2NH)
AH= AU + An RT = AU
N+3H2
AH
AH
gol0
-2
-
2RT
007
2NH3p
AH
E2ntoE
a
Jos
AH°=-83kJ
(reactant bonds)-AH
(N=N) +3AHH-]-[6AH
-83
AH'NN)+3(435)-6(389)
-83
AHNNI + 1305-2334
KJ
an NN) =-83 1305 +2334 = 946
(product bonds)
N-H
n
o
H
tie
(152)MHT-CET
Exam Questions
(A)
97.
graphite, AH-37.4
For 6.0 g of
AH
For 12.0g of graphite,
91. (B)
Q500
J, At constant
kJ
-37.4 x12=-74.8 kJ mol
92. (B)
n-2
R
300 K,
s
t
m
0.-
8.314 JK mol
b
u
WmAx2.303 nRT log10
.
WmAx
=-2.303
x 2 x 8.314 x 300
o
D
log1o
=-3457.97J
-3.458 kJ
Wmax
1
2
93. (D)
s
e
lor
volume, AV=0
Vi=5 m', V2= 10
mole,
is
6
W--PAV =0
T
AH-1172 kJ mol
2co, +2H,0
CH,CHO+2.50,
For 44 g of CH,CHO, AH=-1172 kJ mol
g
T
E
C
94. (D)
0
2
m', V2 = 20 m', T = 300 K
Wmax-5.187 kJ = -5187 J, n=?
10
W0
Wmax-2.303 nRT log1o2
T
H
-5187 =-2.303 xnx
M
n
n
8.314 x 300 log10
5187
2.303x8.314x 300 xlog102
3mol
10
5187
2.303x8.314x300x0.3010
96. (C)
N,O4g)2NO
AG AH TAS
57.24-298 (0.1758)
- 4.8516 k
=
99.
OHto 20
95. (B)
=
98.
10
AH==1172x66
--1758 kJ mol
66 of CH CHO,
44
: The amount of heat liberated when 66 g of acetaldehyde were completely oxidis
1758 kJ mol
VI
n
o
CH)
Co+2H
AH 57.24 kJ
AS 0.1758 kJ K" mol
1
Chemical Thermodynamics
(153)
97. (D)
Propertyof atter that depends on the amount
of matter in the
Volume is an xtensive property.
system.
98.(1
2C02g+
302(g)
C.H OHo +
= -1
Ang
2-3
99.(
+
An, RT
RT
AH
AU
AH
AU-
(D)
No.
of moles = 2
0
aro
=
=l dm 102m
= 10° Pa
100
kPa
Pressure=
W
=-PAV =-P (V2 - Vi)
=
W
s
t
10 (10-5)
b
u
=499.9 kJ
on 2
100.(D)
AH
AU+ An RT
If An, = 0, then AH = AU
2S0
250, +Oat
An,-1
AH
AU
In all
other reactions An, =
1
2
0AH
101.(D)
xidised
CH,+20
is
>CO, +2H,O
16 gm
0
2
AU
o
D
006x8.0
of methane=-800 kJ/mol.
Given Heat of combustion of 16 x 10 kg
methane =?
Enthalpy change for combustion of 4 x 10 kg of
102.
T
E
C
(B)
number
macroscopic systems involving a large
deals with energy changes of
containing a few molecules.
ofrOlecules rather than microscopic systems
103. (C)
T
H
AH-TAS
For spontaneity,
AG-Vve
l AH -ve,
M
104.
AG
-ve
AS = +ve then
at all temperatures.
(A)
NHg
As (AS)products(AS
A80
-800x 4x10-20 kJ mol.
16x10
Ther
eTmodynamics
AG
is
s
e
m
Initial volume Vi = 5
Final volume V2
n
o
3H;O
)reactants
ww
mm
(154) MHT-CET
w
axa
112. (C)
Exam Questions
Nz()
The ab
113. (A)
As°-192.6-x191.5+x130.5
2
192.6-(95.75 + 195.75)
=
AS--98.9 J/mol
105. (B)
For an isothermal
-
process AT 0
s
e
Q--W
s
t
106. (B)
mole of
I
AH-272 kJ
H,0-272 kJ
b
u
750 kJ
?
-2.75
moles.
272
O2
2.75 mole of H2O is converted to H2 and
107.(A)
=AHTAS
4G
T
216
145.6- 1000
145.6 =1O
1000
-5.2
-5.2
150.8x1000
T
216
=698.1 K
T
is
AU =0
AU Q+W
0 Q+W
H,0H,O
1
2
o
D
0
2
108.(A)
More the energy released (exothermic) during the formation, more stable it is. So CO% 15 m
stable among them.
T
E
C
109. (D)
n
o
192.6-291.5
C,H
Qp
A
Q
114.(B)
N2c
Stan
ASO
115.(C)
C,
200
116.(A
Fo
Residual entropy is the difference in entropy between a non-equilibrium state and crystal s
of substance close to absolute zero.
of solid> 0 at T
Entropy
T
H
110. (A)
AG
=
M
AH
0K
117.1
n
TAS
-50-400) 1D=-50+60
10 kJ
1000
A
111.(B)
C,H+H
118. (
C.Hds
AH--124kJ mol
6
For mole of formation of ethane =30 g=-124 kJ
For 75 g ethane =?
1
=-75 x 124-310 kJ
For 75 g of ethane formation, 310 kJ of heat is liberated.
119.
112. (C)
Na
Chemical Thermodynamics
Oc-66.4 kJ
+20)
(155
AH-+66.4kJ
above reaction is endothermic as AH++ve.
n
o
13.(A)
6CO)
Q,
+3H,O
Q+An,RT
An 6-7.5-1.5
s
t
114(B)
2NH)
Nag+3H)
Na)tHa
NH
b
u
Standard entropies
Asndt-2As
AS
115.(C)
CHp+HCl
C,H,Cl
200 mL
200 mL
200 mL
=
200-400
-200 mL=
W
-P.AV
-0.2 L
0
2
0.4L atmbg
101.32540.53 J
-2x (-0.2)
is
0.4x
most
116.A)
ror
stal state
1
2
o
D
=Volume of Product (V2)- Volume of reactant (Vi)
AV
aoas
required.o5 0o
of H,0 = 286 kJ of heat is
Xg of H20= 429 kJ of heat is required.sed Liolt
T
E
C
18 g
X
429x18=27g
286
117.B)
dOthermic reaction
T
H
the following
heat is absorbed, In
absorbed
reaction 66.4 kJ of heat is
2NO0)-66.4 kJ
Nau)+2024
118.(D)
AG AH-TAS
M
4000
60000-T(-160)
64000
T
119.(A)
160 T
=
64000
400 K
160
Theabsolute entropy
mole of a
pure
is
s
e
-3264.2+-15x 8.314 x 10 x 298)
3264.2-3.716-3267.9 kJ mol
and
substance at I atm
25°C.
(156)MHT-CET Exam
Questions
120. (D)
W-2.303 n RT logIo
-2.303
-2.303
x 3 x
x 3 x
8.314
8.314
20
x
300
x
300 x 0.3010
10
W=-5187.027 J
=-5.187 kJ
121. (C)
According to first law of
s
e
Q+ W
AU
=-15+(-10)
AU=-25
kJ
s
t
energy-25 kJ
Intermal
122. (A)
Since, 18
10 kg of H,0
2.7 kg of HO
x
=-284.5 kJ
-284.5 x 27
18x 10
42.675 x 10 = 4.2675
o
D
123. (C)
Since, AH= AU+ An RT
For the reaction,
2
H2g+Brag)
An 2-2 0
AH
HBr(g)
1nse o 9mlo
oubor'l
1
2
AU
124. D)
b
u
x 10*
kJ
2o a
VA
AU+AnRT
Where, An = No. of moles of gaseous product -no. of moles of gaseous reactant.
AH
125. (A)
For formation of
mol
4
T
H
mol
T
E
C
154
126. (D)
I
0
2
CO%
96x154
=
44
Ch
=
396 kJ heat is
liberated3o Lo6 s 0830g
1386 kJ heat is liberated.
M
o
Ouoa7
HC
AHHCID:O H-H BE.of CI-CI -[B.E.of
-90
d
2
-BE
-(B.E. ofH-C
-90 215 + 120-[B.E. of H -CI]
-90 335 [B.E. of
Cl]
. B.E. ofH- Cl 335H+ 90 425 kJ mol
H-CI]
081-1000800
ostomso
n
o
is
thermodynamicS
Chemical Thermodynamics
(157
127.(D)
6CO)+3H,O
CH
!
AH-3266kJ
78 g mol
780 x 10
benzene
= 0.01
mol
Moles of
78
mole of benzene liberates 3266 kJ of heat
3266 x 0.01=32.66
0.01 of benzene liberat
mass of CGH6
Molar
RmeJnohao
n
o
1
118.
Melting noint does
kJ of heat
not depend on the amount substance,
of
it is an intensive property.
AHTAS
-ve-ve +ve
AG
.at
all temperatures.
bo
mole
I
of SO; =-298 kJ mol
of
64
SO-298 x
4
64
b
u
-18.625 kJ
oobto
131.(B)
132.(D)
AG
mol
of H,0 =
270 kJ mol
18 g
X
=675 kJ
-ve)
TAS
AH
135. (D)
AU=
136.
(A)
137. (C)
0
2
+ve)
-ve)
615x18
= 075x18
1
2
134. (B)
AG
o
D
awrge
-2.303 RT logioK=-2.303 x 0.008x 300 logio10 = -5.527 kJ mol
133. (A)
I
s
t
t
130(B)
Q+W= (4000 kJ) + (2000x 10
T
E
C
270
kJ)
=
tavlao
laomo (oialo)
-45
4002 kJ
13etoota01301s lo ztga
sitbh
Multiply equation (1) by (2)
2C+2019
to tolo. ()ogtoeal
2C02p10 AH=-2X kJhog
Reverse equation (2)
3o
2C0
2C+O2tp)
Forthe
M
T
H
2C0+O
AH Y kJ
si(i)
AH Y-2X kJltiAdd
2C0
mation of l mole of CO io
formationard enthalpy of
138.
.(B)
=
W2.5 kJ 2500 J, Q
=
-150oJ
aU=Q+W=-1500 +2500 1000
o
is
s
e
129.(B)
Eq. ()
& (ii)]
Electrochemistry
5.
Shortcut Methods
ImportantFormulae and
or S
Electrical conductance (G)0
.
n
o
(or m)
Cell constantcm
a
Cell constant
is
.Conductivity (K)=- Resistance
Molar conductivity (Am)(K in
Am-
C
(K in Q'
.Kohlrausch's Law :Ao
Degree
em
a
Qmand Cin mol m)OR
and C in mol dm)
s
t
+
of dissociation (a) =
n
b
u
Ao
Electrochemical cell:
Energy change
Type
Electrolytic cell
Galvanic
Electrical energy
energy
(voltaic) Chemical energy
cell
1
2
energy
Cell representation:
Anode
X()x(aa)
LOxidation
o
D
chemical
(8).1E
Anode Cathode
Electrical
0
2
Cathode
|I (aa)IY)
J
s
e
ATRAOL
HA
04
(v
(v-)
Reduction
T
E
C
Quantitative aspects of electrochemistry:
The mass of reactant consumed or the
mass of product formed at an electrode
electrolysis can be calculated by knowing
stoichiometry of the half reaction at the elecu
Mass of product moles
of product x molar mass of product
t(s)
I(A)x
W
x
po ee
96500(C/ mole") mole ratio x molar mass of product
a.
M
T
H
b. Suppose two cells
containing different electrolytes
sane
are connected in series
quantity of electricity is
erateda
passed through them
then the masses of the substances
the electrodes ofthe
two cells are related as
dayol 3o valaio busbae
W
mole ratio) x M
a
W2
(mole ratio)2 xM2
(M and Ma are the molar masses
0et-o
of substances produced
10026
ec
es of
at the electrodes
cells 1 and
2)
Electrochemistry (159)
EMF of cell
(In terms of
standard reduction electrode
potential)
.Nernstequation
n
o
X()+Y(aq) - xn- (aq) + Y(8)
Foell Fell
og
s
e
.Thermodynamics of Galvanic cells:
AG--nFEoell
ii) AG-RT tn K
CK=
b
u
n
.Standard hydrogen electrode (SHE):
EH, -0.00OV
atm) |Pt
is primary reference electrode)
H (IM) |Ha(g,
EE(It
1
Electrochemical Series
i. Metals having higher positive
oxidizing agents.
ii.
s
t
Equilibrium constant)
O.0591og oK
at 25°C
ii) Eel
is
n
o
D
nson ionouber bol
Eed Values,
1
2
undergo reduction more readily and are good
-H
oxidation more readily and are good
Metals having higher negative Eed Values, undergo
reducing agents.
0
2
Multiple Choice Questions
T
E
C
MHT-CET 2004
uring
Ode
1. Standard
(A)0.8 V
T
H
is (EAt IAg = 0.80V)
electrode potential of cell H2 |H"| Ag|Ag
a(0)
(B)-0.8 V
oC)-1.2Va
D)1.2V
MHT-CET 2005
4
edst
M
V, 0.34 V and -2.37 V respectively.
D are 0.8 V, 0.79
Reduction potentials of A, B, C and
three elements?
(D)C
Which element displaces all the other
(A) B
(B)A
S Na is used in reduction
(A) EZa(oxi) > ENa(Oxi)
(C) Eza(oni) < Eša(oni)
of Zn salt because
(C)D
<ENa(red)
(B) EZn(red)
(D) Both (A) and (B)
od
(160) MHT-CET Exam Questions
MHT-CET 2006
4. The reduction electrode potential, E of 0.1 M solution of M
(A)-4.82
(B)-2.41
V
VV
MHT
ions (ERp=-2.36 V.
V) is
is
of Ba
and Cr are respectively 127 and 76 ohm Cm
At
dilution. The equivalent conductance (in ohm cm) of BaClh at infinite dilution will
be
(A) 139.5
(B) 203
C) 279
(D) 101.5
5. The ionic conductance
MHT-CET 2007
6. The standard Ered values of A, B
and C are +0.68 V, -2.54 V,
of their reducing power is
(A)A> B>C
(B)A>C>B
7. EMF of hydrogen electrode
in
-0.50 V respectively. Then
heorte
b
u T-on
(C)C>B>A
(D)B>C>A
tem of pH is (at 1 atm pressure)
RT
(A)Es,xpH
(C) E
s
e
s
t
RT
2.305 RT pH
o
D
(D) EH,
F
(d)
MHT-CET 2009
1
2
s
1
=
sbo3els msgezbyd bysbust?
Boog
(A)+2.03
VE
0
2
(B)-2.03 V
MHT-CET 2010
Cu/
Cu is 0.337. The
luoirmorioo12o1
C)-2.7 Vgt298
iD)+ 2.7.VM
Au/
T
H
10. According to Faraday's
x
(A) w=6500 E
Ixt
11. A button cell used in
M
MHT
14. W
(A
15. T
su
(A
16. W
MHT
17. H
ch
(A
18. In
(A
*19. In
(A
(C
ETs6
(C)
96500
watches functions as
If half-cell potentials are,
following:
+ Zn
20. Id
E=Xtx96500
W
(D)
E=Ix
tx
(aq) + 20H (ag)
w
(A
21.
965000
W
(A
22. W
acc
Zn (ag)+2e" Zn(s);
Ag:O(8)+HO)+2e2Ag()+2OH
The cell potential will be
(A)1.10 V
(B)0.42
(A
MHT
W=xtxE
Zn(s)+ Ag:0(6) + H:O0)=2Ag(6)
H
cC
(D)-2.55
first law
(B)
13.
C)-1.35
MHT-CET 2011
(A
(A
9. Given, for Sn
/Sn, standard reduction potential
reductionpotential
is 0.15
is 1.5 V. Forthe
V and for
reaction, 3Sn°+2Au"
the value of Ecell is;
standau
-> 3Sn4* +2Au. 3000 Au,
(A)+1.35
(B)+2.55
T
E
C
9.
de
MHT
-0.591 pH
8. The standard reduction
potential for Mg*"/Mg
is -2.37 V
Ecel for
and for
the following reaction is
Mg+Cu>Mg*+Cu
n
o
12. At
(D) None of these
(C)+2.41 V
Vv
(aq);
(A
E-0.76V
E-0.34
v
MHT
23.
Th
(C)0.84 V
(D)1.34
V
ele
(A
MHT-CET 2013
at
Tbe infinite
Electrochemistry
(161)
lar conductance
25°C mol
25°
of 0.l molar
12.At ohm cm mol and
at infinite dilution aqueous solution
9.54
ammor
aisation
of ammonium hydroxide
1onisation
of
ammonium hydroxide its molar conductance
degree of
at
is 238 ohm cm
%
the
m mol.
(B)
(A)2.080
20.80 %
same
The
(C)4.008% concentration
and temperature
1s
MHT-CET 2014
(D)40.80%
electrical conductand
13. How is electrical conductance of a conductor
related with length
conductor?
and area of cross-section
of the
(A)G 1.a.k
(B)G-k.l.a
ornu(C)G -k.a.l
.Theorder
(D)G
MHT-CET 2015
lowing complexes has
Which of the follov
lowest molar conductance?
4 COCl.3NH
B) CoCl.4NH
(A)
(C)CoClh.5NH
n
o
is
kl.a
s
e
(D)CoCl.6NH
s
t
The overall reaction taking place at anode during
electrolysis of fused
suitable electrode is
sodium chloride using
chloride
(A)Oxidation of
(B) Reduction of sodium
(C) Reduction of chlorine
ions
biete d
(D)Oxidation of sodium
atoms
16 Which among the following solutions is NOT
used in determination of the cell
constant?
(A) 10 M KCI
(B) 10 M KCI
(C)1 M KCI
(D) Saturated KCI
MHT-CET 2016
b
u
337. The
o
D
sbrollo tutbos aluoo
17. How many faradays of electricity are required
to deposit 10 g of calcium from molten
calcium
chloride using inert electrodes? (Molar mass
of calcium = 40 g mol)
bns ay
(A)0.5 F
(B)1F
1
2
18In the cell represented by Pb)| Pb
O(B)Pb*
(A) Pb
standard
0
2
(IM) l|
Ag
19. In dry cell, what acts as negative electrode?
(A)Zine
(C)Ammonium chloride
MHT-CET 2017
T
E
C
20. Identify
(A)Li
(B) Na
(A)Sm
T
H
(IM)l
Folto
go),
(B)Sm
(0)2F siuols)56
the reducing agent is
aeso.cCA
(C)Ag020.8)D)Ag
(B)Graphite
(D) Manganese dioxidetb
lorm
2
the weakest oxidising agent among the following.
21. What is the SI
unit of conductivity
Which
lop
(C)0.25
(C)Cd2
stinni de bios
o2.08c(A)
iwollot ori gnoms tior
De(D)1
oboiliso is bo
E
A
(C)Sm20.0 piv D)S m2om dft t
among the following equations represents the reduction reaction taking place in lead
as
positive electrode, while it is being used a source of electrical energy?
Pb
D)Pb
Pb
(C)Pb
Pb
Pb
(B)Pb
aCcumulator at
(A)Pb
MHT-CET
M
2018
3.Thenumb
1s passed through an solution of
moles of electrons passed when current of 2 A
for 20 minutes 1s
(A)4.1
mol e" (D) 2.487 x 10 mole
x
e (B) 1.24 x 10 mol e" (C) 2.487 x 10
24.Whatmol
accumulator?
is the density
acid used as an electrolyte in lead
(A)1.5
(A)] sdensity of solution of sulphuric
g
mL"
(D)2.0
(C)1.8 g mL
g mL
(B) 1.2 g mL
Ciectrolyte
(162)MHT-CET Exam
Questions
37. Fo
MHT-CET 2019
CusO4 solution and
An
in series containing
connected
are
cells
of first cell, the numben
cathode
on
25. Two electrolytic
deposited
'Cu' are
If in electrolysis 0.4 moles ofthe second cell is
on cathode of
(D)0.18 moles
(C)0.27 moles
Al' deposited
moles
(B)0.4
(A)0.6 moles
to
solution decreases on dilution due
electrolytic
an
conductivity
of
26. The
unit volume
(A)increase in number of ions per
(B) increase in percentage ionization
(C) increase in ionic mobility of ions
volume
(D) decrease in number of ions per unit
27. The resistance
solution is 2.5
ofM
10
x
s
e
s
t
(B)5.0 ohm cm mol
(D) 3.5 ohm cm mol
28. Standard Hydrogen Electrode (SHE) is a
(A)Metal-Metal ion electrodebor)
(C) Primary reference electrode
b
u
9dT 2
19/0
1
2
olo to
31. Calculate EMF. of following cell at 298 K, Zn,ZnSO%(0.01M)|
E2.0V.
B)
(A)2.0296 V
T
E
C cm
(A)0.08165 Ncm
(C)0.008165
35. The standard emf
M
(C) 2.0592V
Cuso%(1.0 M)
of Cu Cu
pee(B)
0.81652 cm
(D)8.165 Q cm
C
41.
e101
MH
43.
46.
47.I
gapn
e
|Agm)Ag cell is 0.463V. If the standard electrode potential
Cu' electrode is 0.337 V, what
is the standard
electrode potential
of 'Ag' electrode
(C)0.626
V
56. In Ha-02 fuel
(D)0.800 V
cell, reaction taking
place at negative electrode
(A) 2H20+ 40H
is
4H,O +4e
(B) 40H
C)2H+20H
0tp) + 2H,O +4e
(A)-0.126V
F
40.
45.
(D)2.0 V
sd
og
V
Cu
32. The molar conductivities at infinite dilution for sodium acetate,
HCl and NaCl are 91 S
mol, 425.9 S cm mol and 126.4 S cm mol respectively.
The molar conductivity of a
acid at infinite dilution is
(A)530.9 S cm mol" (B) 390.5 S cm mol
(C)930.5 S cm mol (D) 300.5 S cm mol
33. Which among the following is
correct for electrolysis of brine solution?
(A)Ch gas is liberated at cathode
(B) H2 gas is liberated at cathode
(C)O2 gas is liberated at cathode
(D) Sodium metal is collected at anode
T
he
molar
conductivity of 0.05M HCI
34.
is
solution is 163.3 Q em? moll
conductivity of the solution at
at 298K. WDat
the same temperature?
T
H
bed
0
2
1.0508 V
39. Si
44.
Ch and Na
C)O, and Nal(D)
n
o
(A
42.
oxygen fuel cell?
29. Which of the following acts as oxidizing agent in hydrogen(C) KOH
D)H
(B)C
(A)O
30. In the electrolysis of aqueous sodium chloride with inert electrodes the products obtainei
anode and cathode respectively areobe
(A) Na and Clh
(B) Ch and H
38.If
oT0919 9louniu
(B) Metal-Sparingly soluble salt electrode
(D) Secondary reference electrode
o
D
A
is
of soluti
on
10 ohm. What is the molar conductivity
(Cell constant 1.25 cm)
(A)2.5 ohm cm mol
(C)2.0 ohm cm mol
if
48.
g(B)-0.860 V
o
2H,O+2 b
D) O0+ 2H,040H)
49.F
B*
17.For tho - 0.403V,
ca (1M)
thecorrectprediction
H
fE'cd
(A)AGve, E"cell--ve
Ch
esof
)4G
+ve, E'cell =
+ 2e
'of Zn "(aq)+2e
3V
Zn(S)
Electrochemistry
about AG (IM)1Halg) (1
atm) Pt,
and
and E"
(B) AG -ve,cell is
(D) AG=+ve,E'cel +ve
0e0
is-0.763 V then
(B)+ 1.026V
(16
E'cell +ve
E" of 2
Zns)2Zn()+2e will be
(C)-0.703V
oduction potentials elements
(D)-1.506V
Standard redu
of
A, B, C and
9, respectively. Which element
D are
displaces
(B) A
4) C
(B)4166.0C
(A) 41.66 C
EMF of
(A) 2.46 V
what is
5 g
s
e
C)4020.2 C
(D) 40202.0Dc
a cell having AllAP" (E"=1.66V) and Ag'lAg (E°-0.80VY
(B)-0.86v
is
of magnesium from magnesium
s
t
(C) 0.86 V
(D)-2.46V
How many Faraday of electricity 1S required
for the reduction of 3 moles Zn22
of
(B)8 Faraday
(A) 4 Faraday
(C)6 Faraday
2
D) Faraday
42.
b
u
MHT-CET 2020
43. What
is the common unit of conductivity
(A).2 cm
(B)N cm
at
from their salt?
(D) D
C)B
coulomb of electricity
is required to produce
mass Mg = 24)
many
40. How
chloride? (At.
n
o
other three elements0.799 V, 0.690v, 0.34V and-2.37
V
4. What is
o
D
if the dimensions are expressed in centimeter?
cm
(C)
D)
cm
the molar conductivity of 0.1 M NaCl if it's conductivity is 1.06 x 10
cm mol
cm mol
10
sds B) 5.3 x 10'2
(A)1.06 x
2
C) 1.06 x 10 Q cm mol
1
2
d les
D)9.4
x 10
Q cm
Q cm'?
mol
of the following statements is true for electrolytic cell?
A)Oxidation occurs at negative electrode
lotteoloqbscltoesogaweot
5) Reduction occurs at positive electrode
C)Oxidation occurs at positive electrode
a
D)Anode is negative and cathode is positive electrode
constant of NaCl
solution if resistance and cell
Wnat 18 the conductivity of 0.01 M NaCl
cm respectively at 298 K?
301ution are 375 ohms and 0.5
45.
m
etic
Which
(A)1.333 x
the
T
H
M
A
O(D
D) 1.333
aqueous sodium chloride the
e electrolysis of
(C)Cla
(A)02
(B) Hg)
What
is Standard potential of cell, Ni | Ni
IfECu
o
cm
10 Qem
(B)7.50 x 10
em
10a
2cm
91875x 10
41.During
1 of
T
E
C
0
2
V.
x
product obtained at anode is
(D) Na
l|Cu"M)Cu?
(D)0.573 V
.337 V and E°Ni--0.236
(C)0.101 V
(A)-0.753
to Al?
V
(B)-0.136
V
one mole of A"
of
reduction
.How much
for the
D)1.930 x 10'c
charge in coulombs is required (C)2.895 x 10'C
(A)1.930x
10'C
(B)2.895 x 10'C
Questions
484 Q and conduc
(164)MHT-CET Exam
gives a resistance of
0.01 M KCl
with
filled
constant?
50. Conductivity cell is
What is cell
cm
25°C.
cm
(D)0.341 cm
at
0.00141 Q
(C)0.510
(B)0.751 cm
(A)0.682 cm
of
conductivity and resistance
e of
asolutiga
solution at 25°C, if
ofKCI
constant
cell
the
What
is
51.
10
em and 55.0 Q respectively?
is 0.0112 Q
(D)2.0 cm
(C)0,491 cm
cm
cm
(B)0.2
(A)0.616
conductivity of ca
dilution of CaCh, if the molar
infinite
at
conductivity
52. What is the molar
71
2 cm mol'?
infinite dilution is 119 and
ion
andC
at
(A)126.0 Qem'
(D)431.0
(C)341.0 Q em mol
53. How many electrons flow when a current
(B) 1.60 x 10
(A)9.65 x 10
(A)350 Q cm mol
cm mol
C)250
s
e
of 5 amp is passed through a cell for 200 sec?
(D)3.12 x 10
(C)6.24 x 10
54. If the conductivity of 0.08 M KCI solution is
solution?
b
u
n
o
is
s
t
mol
cm molr
(B)261.0 Qcm
mol
62.
TH
1.
(A
63.
W
64. H
65. N
66.
2x 10 N, what is the molar conductivity of te
o
D
(B) 25.0
2
67.
cm mol
D)0.25 Q cm mol
01a0-TH
55. What is the relation between cell constant, conductivity and electrical resistance?
(A)k
1
2
(C)k-
(B) k= R.b
avbubao
(D)k = Rb
68.
56. What is the standard free energy change for the cell, having following cell reaction?
2Ag)Cd
(A)-260.8 k
0
2
2Ag
0U.FO)
e
(D)-160.8 kJd
Caa), Fel =1.20V
(B)-115.8
kJ
(C)-231.6 kJ
69.
57. For the following cell, standard potential
of copper electrode is 0.337 V and standard cel
potential is 0463 V.
T
E
C
Cu Cu(IM)|| Ag'(IM) 1Ag
obotosls svdteoe nn anuoso no
What 15 the standard potential of silver electrode?boa
ritigapar
(A)-0.463V
os
(B)-0.126v
(D)
albixO0
obork(0
Vol
a
(C)0.126 V
0.800
58. What will be the concentration
of NaCl solution, if the molar conductivity and conductviy
NaCI solution is 124.32 cm
mol and 1.243x 10 Q cm* respectively?
(A) 0.01 mol L
B) 0.02 molL
(C) 0.1 mol
(D) 0.001 mol L
59. How many electrons are involved
in the reaction when 0.40 F
of electricity is passed throu
electrolytic solution?
(A) 6.022x 103
(B) 1.505 104
M
T
H
Lmo
71
72
x
(C) 2.4088 x 10
D) 6.642 x 10
60. If resistivity of 0.8 M KCI
solution is 2.5 x 10 Q cm. Caleulate
olution
molar conductivity ors
em mol
(A)5 x 10
(B)4 x 10°Q cm
C)2x 10
70.
N
cm mol
D)3 x
10°
2
moly
cm
mol"
A
61. A solution CusSO4 is
elo doua
electrolyzed using a current
of
of 1.5 amperes for 10 minutes
of Cu is deposited at cathode? (At.
Mass of Cu - 63.7)
(A)0.150 g
(B)0.395 g
(C)0.637 g8
(D)0.297 g
73
mass
74
activh
Electrochemistry (165))
tance between electrodes of a conductivity
cell
is 0.98 cm and area
of cross section is
1.960cm?. What is the cell constant?
cm
cm
1.5
(B)
(A)2
(C)0.5 cm
(D)1 cm
rochemical equivalent?
What is the SI unit for
62. The
ofa
sului
63.
(B)JS-
(A)Kg C
ofCa
C)JC(D) Kg C1
many
faradays
of
tlaw
electricity 1s required to
produce 4.8 g of Mg at cathode in
ectrolysis of molten MgCl,? (Molar mass of
the
Mg- 24 g/mol)
(B)1 F
(A)0.4 F
(C) 10 F
(D)4 F
65. Number of electrons involved in the reaction when
faraday of electricity is passed through an
electrolytic solution is
6
1046
(A)12 x
(B) 96500
(C)8 x
106d
vity
ofte
(A) Pbo) is oxidized to
(C)
Pbg
Pb(aq)
is reduced to
Q cm
Q cm
(C)8.0 x 10
oreoR()
68. Conductivity of a conductor is
ot(B)
(A) inverse of resistance
(C)inverse of resistivity
1
2
s
t
(D)PbO20) is reduced to
b
u
67.Molar conductivity of 0.01 M HCI solution is 400.0 Q
of HCl solution.
(A)2.5x 10
1023
lead accumulator is
is oxidized to PbO20)
(B) Pb
Pbo80o)
s
e
(D)6.022x
h6. During discharging the change taking place at cathode in
(B)4.0x 10
(D)4.0x 10
o
D
cm
mol.
em
o cm
n
o
is
1
Pba)
Calculate the conductivity
2 m
inverse of conductance
(D) equal to resistivity
69.E'cellis 1.040 V and involves transfer of 2 electrons, calculate equilibrium constant of cell.
(A)2.75 x 10
(B)0.524 x 1035
(D)2.098 x 100
(C)2.75 x 1035
gg
zdc(B)
T
E
C
an
How many coulombs
ofAu
197 g mol)
(A) 289.5 C
DIuion
M
Au
2. Consider the following half-cell reaction: Au" +3e
T
H
ough
at
go
71. When dry cell is in use the change taking place at cathode is
ions are reduced
(B) NH
(A) Zn is reduced
(D) Zn is oxidized
C) MnO is oxidized
tivityof
mas
0
2
70. In 2 hours, a certain current liberates 0.504 g hydrogen. How many grams of copper can be
deposited by the same current flowing for the same time in a CuSO4 solution?
(Molar mass of Cu = 63.5 g mol, Ha =2.0 g mol
(C) 31.8 g
(D) 32 g
(A) 63.5
16.0
dard cell
of electricity
(B) 579.0
is required to deposits 0.394 g of Au. (Given
C0
C) 386.0
C(e
Molar mass
(D) 193.0 C
resistivity is 2.5 x 10
3
is the molar conductivity of 0.4 M solution of KCI10*if it's em mol
What
(B) 1.0 x
cm
a
10
(A)2.1x
)1.0x 10
o
74.The standard
mol
cm mol
IAO)(D) 2.1 x 10'2
m
em* mol
What is the maximum electrical work obtained
emf of Daniel cell is 1.10 volt.
Daniel
= 96500 C) 0S(8)
(A) 106.15 cell? (F
(C)175.4 kJ
kJ
(B)212.3 kJ
ndard
Q cm ?
tEA)
(D) 57.07 kJ
solution?
Exam Questions
displace zinc from it's
NOT
does
(D) Na
metals
(C) Al
the following
of
Which
75.
(B) K
undergo ovi.
idation
(A) Fe
tendency of metals to
relative
fron
of
decreasing
correct
the
Identify
76.
(166)MHT-CET
Fe
(B) Cr> Al> Mg>
>
Mg
(D) Fe>Cr> Al
following
Mg
(A) AI> Fe> Cr>
Mg> AI> Cr> Fe
)
77. What
is
of
conductivity
the molar
cm'mol
2 cmmol
D) 1.01x 10 2
10Nem?em'mol
1.01 x
(A) 1.01 x
n
o
its condsae
ctivity
M NaCl solution of
0.1
is
(B) 1.01 x 10
107 Q
cmmol
(C)1.01 x 10°
nt.Wita
out by passing 0.01 A current
solution of NaCl was carried
aqueous
dilute
of
Electrolysis
78.
cathode?
0.01 moles of H2(g) at the
is the time required to liberate
(D) 9.65 x 10' sec
19.3 x 10 sec
(B) 28.95 x 10" sec (C)
(A) 38.6 x 10° sec
the conductivity
KC1 gives a resistance of 250 ohms. If
0.5
M
dipped
in
cell
conductivity
79. A
cell constant?
KClsolution is 6.68 x 10 S cm, what is the
D) 0.270 cm
(C)0.810 cm
cm
(B) 0.364 cm
2
s
e
s
t
b
u
(A) 1.67
gives a resistance
80. A conductivity cell dipped in 0.01 M AgNO; solution
constant is 0.47 cm, what is the conductivity of AgNO3 solution?
cm
cm
(B) 1.487 x 10
(A)6.723 x 10
2
(C)1.487x 10acm
o
D
D) 7.10x 10
1
2
of 3160 ohms. If cel
Q
Q cm
81. What is the equilibrium constant of the reaction involving two electrons if the standard emf d
the cell is found to be 0.296 V at 25°C?
10
(D) 2.95 x 1010
(B) 2.95 x 10
(A)
(C)1x 10
1x
0
2
82. Emf of cell having following cell reaction at 298 K is 0.059 V.
Zno+2H
Zn"
+H2
What is the value of AG?
(A) -5.7 kJ
(B)-14.1
003500
C)-8.3 kJ
(D)-11.4 kJ
83. What is the time required to deposit one millimole of aluminium
by passage of 9.65 amy
through aqueous solution of aluminium ions?
(A)10 sec.
(B) 300 sec.
(C) 30 sec.
D) 100 sec.A
84. For the following cell,
Zn Zn (1IM) ||H' (1M) |H2g(latm)
Cell potential is 0.763 V. What is the potential
of Zn"|Zn electrode?
(A)-0.763V
(B) 0.242 V
()0.3815 V
(D) 0.0 V
85. During the electrolysis of molten sodium
chloride, the product obtained cathode 15
(A) Hap
at
(B) Na
(C) Clh
D) O
86. Which element among the following
three
is used as reducing
elements from their oxides?
agent for reduction of re
(A) Mg
(B) Zn
T
H
M
T
E
C
k
0
bep
(C)
ro
Al
(D) Hg
87.If theresistivity of 0.1 M KCl solution
is
50 2 cm, what is
(A) 160 2 cm mol
ity?
its molar conductiviy
(B) 240 Q cm molr
(C) 290 2 cm mol
lo
(D)200 Q cm? mol
1
iso
00
8
oquired to deposit one
Electrochemistry (167)
millimole of
monovalent metal
aqueous lution of metal ion
is
throug
by the passage of 9.65 amperes
(B) 10 sec.
sec.
(A) 100
(C) 300 sec.
lar Conductivity at infinite
(D)30 sec.
the enectively,
dilution
9.If
the molar conductivity for NaCl, KCI and KBr are 126, 150
and 152 S cm
at infinite dilution for NaBr
moascm?
cm mol (B) 176
S cm' mol
is
(A) 303 S
(C) 128 S cm mol
(D) 278 S cm mol
the valu
value of cell constant conductance
is
What
if
90.
and
conductivity
cm
cm
(B) 1.0
of a solution is same?
(A) 10.0
(C)0.5 cm
(D) 0.1 cm
hich among the following electrical properties
has SI unit Siemens per meter?
(B) Resistivity
(A) Conductance
(C)Resistance
(D)Conductivity
Ca O2 ()
CO2 (
92.1f
AH=-396 kJ mol", calculate heat liberated
during formation of
CO2 .
88. The
ation
from
uctivity
is
Tent.What
s
e
+
uctivity
(A) 1386.0 kJ
of
(B) 346.5 kJ
0A10
IM
ifE-0.25v, Eu 1.50V.
(B)-1.75 V
(A)1.75 V
i
JBitei
o
D
(C)1.25
6.0 x 10
to tato(D)-1.25
V
V
ncm
conductivity of Nal solution is
and molar conductivity is
Calculate the concentration of Nal solution.
cm'mol".
(A)0.05 M
(B)7.2x 10 M
C)0.005 M
orfoi(D)2 x 10 M
94. The
120
rd emf of
95. Which
(A)Mg
96. During
(B) Ag
electrolysis of aqueous NaCl, the product obtained at cathode
T
E
C
C)H-Og
is
(D)O2(
10ohm cm
T
H
AESIStance of
M
0
2
(B) Ch
The
(C)
three
(D)AI0
(C)Fe
standard electrode potential of Zn and Ni are -0.76 V and -0.25 V respectively. If the
is spontaneous. What is
reaction takes place in the cell constructed between these two electrodes
the standard emf of the cell?
(D) 1.01 V
C)5.1 V
(A) 0.101 V
(B) 0.51 V
an electrolyte is 100 N at 298 K. What is the conductivity
.Ihe resistance of 0.01 M solution of
of solution? (Given: b =l cm')
cm
(B) 10 ohm
(A) 10 ohm cm
cm
(D) 10 ohm
7.
ampere
1
2
metal from following has highest tendency to undergo oxidation?aosbro
(A)H2(
ung
(D) 1039.5 k
b
u
Nia)llAu)lAu
IM
Ifcell
(C)693.0 kJ
the standard emf of following cel1?
93. What is
Ni)
ms.
s
t
0.154 kg of
sec
is
0.013 S cm
(A) 3.0 cm
conductivity cell is 300 ohm and conductivity is
0.1 M KCI solution in a
What is cell constant
(B) 1.5 cm
(D) 3.9 cm
(C)4.5 cm
1s molar conductivity of
1.061 x 10 S cm. What
is
solution
0.01
M salt
e Conductivity of
the solution?
cm mol
(B) 1.061
(A) 10.61
cm
cm' mol
Q'
mol
(D) 1.061 x 10
(C)106.1 Q cm
mol
101.What
(D) Volt
is tthe unit of electrical conductance (C) Siemens -1
(A
(A)
at
Ohm
(B) Siemens
2
2
n
o
(168) MHT-CET Exam Questions
potential of
102. What is the electrode
298 K ? (E
0.2808BV
0,34
V
Cu)Cu) electrode,
at 298 K)
(D) 0.170 V
(C) 0.399 V
(B) 0.222 V
(A)
containing 0.01 M CusSo
solutien
n
o
SOLUTIONS
1.
(A)
Given,
EtA=0.80 V, H H
Ag
teolotai anogddw
Hydrogen is anode and silver is cathode.
V)
(EH0.00
0.80-0.00
s
t
0.80 V
2
s
e
Ecathode-EAnode
Eell
is
|Ag
(C)
The element having lower reduction potential can displace metal having higher reduction potential
Reduction potential of A = 0.8 V
Reduction potential of B = 0.79 V
Reduction potential ofC = 0.34 V
Reduction potential of D= -2.37 V
Reduction potential of D is least among given elements.
It can displace all other metals.
b
u
3. (C)
o
D
Metals having higher oxidation potential (or
lesser Eyed) can replace metals having lesse
oxidation potential.
dgoreolof motfare
: Oxidation potential of Na is more than that
of Zn.
Na is used to reduce Zn salts.
4. (B)
E
Ep+
0
2
n
Given,
T
E
C
ERP
n
E
5. (A)
T
H
-2.36V,
1
(for
1
2
log
[M*
ngieog boiools bosbnse odt
(M)-0.1 M
M> M)
VE0(8
Ep+
log[M*] =-2.36+
n
-2.36-0.0591-2.419V
Equivalent conductance
equivalent of electrolyte
is
rO0(A)
log 0.1=-2.36+0.0591 x(-)
defined as conducting
power of all the ions produced
gra
by onc
The equivalent weight of BaClh =molecular weight
M
A for BaCl,
Agfor BaClh
Ba" 2CT
Ba"+C-
2
127
76-139.5ohm lem?1o.0
6. D)
Reducing character is based upon
higner
Order of reducing character is B>C>A.negative value of reduction electrode potential
7.(
Electrochemistry (169)
2H+2eH
bnoonalorn
According to Nernst equation,
RT
=E°+2.303
E
nF
oboobobM
1
mo
Fcathode
anode E
cu2
pH
s
e
Cu)EM2Mo 0.337--2.37) V =2.7 V
s
t
9. (A)
EeEcathodeanode15-0.15=1.35 V
b
u
(B)
Faraday's first law,M
E
ZIt and Z96500
According to
W
=
is
RT.
-log[H*)-2.303
(D)
E
1.0,4 gieve be
Elt
a3nalen
o
D
iolsso slom I 2eogob ot boTpet o
96500
olao to esM
oalo
Where, I= current, t = time, E = equivalent weight, w = weight deposited
W
1
2
11. (A)
Anode is always the
site of oxidation thus anode half cell is
Zn"(aq) +2e Zn(s),
Cathode half-cell is
Ag:O($) + H,O(1)
Fcell
12.(C)
+2e2
T
E
C
0
2
Ecathode-Eanode
rurolso E
1
M
T
H
-0.76
=
gnieol bnuograog sd
x100 = 4.008 %
238
where, k is specific
=k.a.l
G
Conductance is given by,
iemob aa
e 2r
bs
x100=
Ag x100
A
a6
0.34 V
0.34--0.76)= +1.10 V
=
101 boztpon
poo
V
2.0
Ag(s)+20H (aq); E
ionisation, a
c Know that, degree of
13.(C)
fon to off
onI
conductance at 0.1 M concentration,
Ac= 9.54 Qcm mol
Molar conductance at infinite dilution,
A=238 Q cm mol
Given, molar
n
o
[H*1
2.303 RT
2xF
bvo vlobalo oho slort
()
conductance.ooM
oglonooloasoet otoloa0ee
betizogsb 92 1tw
(170)MHT-CET
Exam Questions
is the conducting
Molar conductance
molar
electrolyte. Therefore,
mole of an
14. (A)
lg
Werner Complex
CoCl.3NH
COCl4NH
CoCl.5NH
COCl.6NH
produced by
power of all the ions
soving
prododissoh
ions
huced.
conductance oc number of
lonisation
[Co(NH):Cl](No ionisation)
[Co(NH)Cli] [Co(NH).Cl]
+ CI(2 ions)
[Co(NH)C1,]CI
(3 ions)
[Co(NH:)5CI) Clh[Co(NH:):CIJ"+2C1
[Co(NH)6+3Cr(4 ions)
[Co(NH)%JCl
Modern-Notation
that, molar conduction of the
From the above table it is clear
n
o
is
complexes will be in the falrowin
order a < b<e<d.
s
e
15. (A)
electrolysis of fused sodium chloride.
eusing
The overall reaction taking place at anode during
(g).
suitable electrode is oxidation of CI ions to Cl;
Clh (g)+ 2e (overall oxidation at anode)
2 CT()
s
t
16. (D)
b
u
The cell constant is determined by using 1M, 0.1 M, or 0.01 M KCl solution.
17. (A)
Ca+2e
Ca
o
D
2 moles of electrons are required to deposit I mole of calcium.
Mass of calcium deposited = 10 g
Molar mass of calcium= 40 g moltaior oleviups
No. of moles =.
3 ah
10
1
2
= 0.25 mol
40g mol
2 F are required for 1 mole of calcium
x F are required for 0.25 mole of calcium.
x 2 0.5 F
x=0.25
18. (A)
0
2
ou/
0023e
oul
url ao
a(pa)
Bao-sd oboru
PboPbim)|Agim)|Ago)
T
E
C
T
H
The compound losinge is called reducing
PbPb"
+2e
agent.
19. (A)
In a dry cell, zinc acts as negative electrode.
20. (A)
It is strongest reducing agent.
21. (B)
1itnt3e sonatoubico1sl0
22. (D)
23. (C)
M
No.
of molesofe"-
24. (B)
20x60 =2.487
2x96500
x 10
HSO4 solution used as electrolyte has
25. (B)
Moles of Cu deposited=0.4,
will get deposited.
as
mol e
density 1.2 gL-1
botn the
cell are in series,
same moles of both tne
olyte
issolvinq
(D)
#v
17.(B)
R-2.5 x
depends on no.
10' Q
Electrochemistry (171)
of ions per unit
volume.
1.25 cm
C-0.1, b =
-?
of electrolytic solution
n
o
1.25
R 2.5x10
lowing
USing
10x1.25
1000k
A
0.1x10 x2.5
C
-50
28.(C)
Electrode potential of
SHE
ther several electrodes is
s
e
arbitrarily taken as
zero and by using
calculated thus SHE
SHE, electrode potential of
is called as primary
reference electrode
29.(A)
1s
s
t
30.(B)
In electrolysis of aq. NaCl
Atcathode: Na)+e
At anode:
H2
2C+2eCl
2H,0
+20H)
+2e
O2g+4H +4e°
o
D
gas is evolved at anode and H2 gas
evolved at cathode.
31.(C)
Zn ZnSO, CuSo, | Cu,
I
1
2
E2V
Zn*
Eo-0.0592
log
2
2-O.0592lo
=
b
u
Na
2H,0+2e
Ch
orele
0
2
-2+0.0592 2.0592 V
32.(B)
T
E
C
AHCI= 425.9, A CHcOONa = 91, A NaCl= 126.4, A CH cOOH =?
ACH,C0OH
A CH,COONa+ AHC1- ANaCI =425.9+91-126.4
33.(B)
In electrolysis
390.5 S cm
of aq. NaCl
+e
Na)
+20H
2H,O,+2e>H2
At anode:
M
4.(C)
41.(A)
2C1+2e>Cl
is
+2e
evolved at anode and
35. (D)
42. (C)
mol
218100
T
H 2H,00+4H+
At cathode: Na
gas
is
cm mol
36. (A)
4e
H2 gas
evolved at cathode.
37. (B)
38. (A)
39. (D)
40. (D)
(172)MHT-CET Exam Questions
43. (C)
is a
Ifp
specific conductance, then
resistivity andx is conductivity or
p-Rx
am
a
(In C.G.S. system, the units of K are Qcm
or S cm
s
e
o cm,C=0.1 M
Molar conductivity, Am
=A*100
s
t
C
1.06x10x10001.06 x 10 a cm mol
siAm
is
which are used commonlv
44. (A)
k=1.06x 10
0.1
b
u
45. (C)
The anode of electrolytic cell is positive on which oxidation takes place.
46. (D)
o
D
cm
k= ell constant0.5
R
3752
=1.333x 10 Q cm
Conductivity,
k
1
2
abodo
47. (C)
During the electrolysis of aqueous NaC1,
i. Hz is liberated at
cathode
ii. Clh gas is released
at anode
48. (D)
Eel
T
E
C
49. (B)
Al +3e
1
M
E
V--0.236 V) =
0.573 V
Al
mole of electron = 1F
3e=
T
H
0
2
EahodeE E0.337
=
3F
=
96500 coulombs
3x96500-2,89,500
2.895 x 10
50. (A)
C 0.01 M, R=484 Q, k=0.00141
Q cm
Cell constant, b
kxR
0.00141
cmx 484 Q
b
0.682 cm
2
51. (A)
k 0.01122 cm,R
n
o
m or Sm')
(OR ohm
55.0 Q
Cell constant, b kxR
0.0112 2 cm
0.616 cm
b
x
5.0
Q
coulombs
21DHA
o000A
b?
ieyiooie
52.(B)Kohlrausch Law
By
+2
Ao(cC)
of independent migration
Electrochemistry (173)
of ions,
-119+2(71)
261.0
53.(C)
=Ixt=5
200= 1000
x
The charge
cm mol
2
C
1.602 x 10-1C
1000 C
1.602 x 10"C 6.24 x 101
No. of electrons passed
54.(C)
1000 k
1000x 2 x102
C
0.08
s
t
56. (C)
0
2Ag +Cd
2Ag+Cd
b
u
n=2
96500 x 1.20
AG--nFE-2x
-231600J-231.6 kJ
57.(D)
Eel0.463V
EE-Eo
Ee
=
124.3 Q
cm
1000 k
T
E
C
C
0
2
=
C
edoto oluco
1.243x 10
oioeelslo7 CegtMtoat
2cm
1000 k
1000x1.243x10
C
1
2
mol,k=
C=?
=
o
D
d Joeno
(olbolto te) sM
0.463 +0.337 0.800 V
+E
58.(D)
A
0.337 V
Eo
=
0,001 mol
124.3
100-0
L-tomo9000
59.(C)
O001
1F=96500C
T
H
0.4
NOw,
M
F= 96500
96500 C
=
38600 C
x 0.4
6.022x
10
6.022x10
38600 C
electrons
no201x0
x 38600
96500
=
2.4088
is
s
e
250 2 cm mol 0000
55. (A)
EA
n
o
ofone electron is
x 10
electrons
10.0%00
000
ivoboo)
(174) MHT-CET Exam Questions
60. (A)
Conductivity (k)
2.5x10 2 cm
resistivity
1000k
(Am)=
Molar conductivity
Q cm
0.4 x 10
=
1000cm L'x0.4x10 Qcm
0.8 mol
C
LC
is
61. (D)
The half reaction at cathode is
Cu+2e
Mole ratio=,
Cu
s
e
10 min = 600 s
t-
Ixt
Xmole
Mass of Cu deposited
s
t
ratio x molar mass of Cu
96500
1.5x600
96500x 63.7 = 0.297 g
0.98 cr
cmn
0.5
1.96 cm2
a
0001
b
u
62. (C)
Cell constant, b-
n
o
10n cm mol
-5x
o
D
63. (D)
Electrochemical equivalent is the mass of substance deposited or liberated
on an electrode pe
coulomb of charge.
1
2
64. (A)
Mg
(
+2e Mg
(at cathode)
24 g of Mg = 2 F of electricity
4.8
0
2
g of Mg 4.8X2 =0.4 F of electricity.
24
T
E
C
65. (D)
1 Faraday
is the electric charge on one
66. (D)
67. (B)
T
H
C
k-?
A
M
k
0.01 M,
A= 400.0
1000 k
k
C
=
2
cm mol
=
400.0x0.01 =
4.0
1000
68. (C)
Conductivity =
mole of electrons (6.022 x 104 electrons).
xC
A1000
x 10
Qcm
20020o
o00
resistivity
69.(
Feell
Eel
:
Electrochemistry (175)
- 1.049 V, n= 2, K=?
0.0592
log K
1.049 x 2
0.0592
Eel Xn
logioK
0.0592
35.439
logioK
-
v
ot
=2.75 x 1035
70.(B)
Mass of HydrogenEquivalent mass
of copper
0.504
1
Mass of copper
=
0.504 x
=
16
sonebo
b
u
71. (D)
In dry cell
Zn+2e
Anode: Zn
Cathode: 2MnO,
+2NH)+2e
72.(B)
1
2
Au)
o
D
Mn,0, +2NH, +H,O
MnO; is reduced.
Au+3e
s
t
63.5/2
Amount of copper deposited
is
s
e
of hydrogen
Equivalent mass
Mass of Copper
rode per
oubro
Charge required to produce 197 gm of Au = 3F.
Charge required to produce 0.394 gm of Au =?
0
2
O.594X SF
197
3.(C)
T
E
C
Specific conductance (K) =
T
H
K
0.006 F
=
0.006 x 96500 C=579 C
Resisitivity
Kx1000
M
=
74.(B)
=
25x10
Molar conductivity Am
M
1.0x 10°2
Ix1000
2.5x10
x 0.4
cm* mol
Eell1.10volt
For Daniel
cell, n
Electrica
15.(A)
The
The
n
o
Antilog (35.439)
=2
work done
nFE2
1.10
x 96500 x
-212.3 kJ
Zn> Fe
solutions.
K>Na >Al>
ctivity series of metals given above: metals above from respective salt
the
etals placed below cannot displace
neseest
(176)MHT-CET Exam Questions
76. (C)
The metal placed above in the reactivity series undergoes oxidation easily.
n
o
77. (D)
1.01x10x1000
Kx1000
Am
C(Molarity)
Molar conductivity Am
1.01x 10
cm'mol"
s
e
78.(C)
0.01 moles of H2 will requires 0.02 moles
Ixt
10
of electrons or 0.02 F.
s
t
=0.02
96500
xt
1000
=
is
0.1
b
u
0.02
96500
t= 19.3x 10" sec.
79. (A)
o
D
Conductivity=Conductance x cell constant
K
Cx cell constant
K
x cell constant
1
2
6.68 x 10
250 cel constant
Cell constant =6.68 x 10 x 250 = 1670 x
0
2
00
10=
bou
1.67
cm
beouboz ai On
80. (C)
Conductivity =Conductance x cell constant
x cell constant
R
T
E
C
0.0001487Qm
81. (A)
2.303RT log
E
nF
0.295
M
T
H
logKc
Kc
=
0.0591
1
=
0.0591
logK
n
96500
x
0.059
=-11387J
=-11.387 kJ -11.4 kJ
egu
Q'm
ongtbuod oihiog
009
x 1010
AG-nFEcell
x
x 10
10
82. (D)
AG--2
=1.487
log Ke
=2x0,295
=
K,
3160
ng or botper
x0.47
Electrochemistry (177)2
83.
oles of product
Mole
formed=xt
96500 mole ratio
Al
Al+3e
0.33
Mole ratio
0.001 mol
9.65xt0.3
=
96500
0.001x96500
=t
9.65 x0.33
30.30 sec.
t
84.(A)
Eell
batiedilatad bioRei
Eanode
=
C
=0-0.763 V
=
s
t
0.000 V)
-0.763 V
Eell
is
s
e
Ecathode
Ep,
n
o
85.0
During the electrolysis of molten sodium chloride pale green Clh
gas is released at anode and
molten silvery white sodium is formed at cathode.
b
u
86. (A)
obonA
isOn
EM-2.37,
E2-0.763
E-1.66,
EH+0.79
EM
9dto or he
87.(D)
k
T
E
C
M
T
H
0-
0
2
50
1000 k
1000x0.02
C
0.1
10
96500
sec.
Ao(NaCI) + Ao(KBr)
=
=
2002 cm mol
e beniosde pbeoot
96500
9.65xt1
According to Kohlrausch Law,
olNaBr)
yito
TE
eer.0r
It x mole ratio sbore
0.001
=126+ 152
latastog
itbibooe
89. (C)
aNaBr)
sMto
0.02
Moles of Product deposited
alol
qrmoo a wol
gev.ei
Resistivity
Molar Conductivity
88. (B)
1
2
1
Conductivity (k)
(O).
o
D
is very small it undergo oxidation, it means it acts as a reducing agent.
150
128 S cm mol
-
Ao(KCI)
=
(. For monovalent metal, mole ratio
1)
eee
AÄS
(178)MHT-CET
Exam Questions
90. (B)
=
Conductivity (k)
Conductance x cell
Conductivity
constant
n
o
Cell constant
Conductance
conductance
When, Conductivity=
Cell constant=
is
I
91. (D)
S. I. unit
or S m
=
of conductivity Qm"
92. (A)
CO% = 396 kJ heat is liberated
For formation of I mol
154
396 *I54 = 1386 kJ heat is liberated.
mol
44
Ee
Fatode-Em
anode
= 1.50-(-0.25)
=
=
Molar conductivity ()=
1.75 V
1000 K
C
1000 x6.0 x 10
C
1
2
0.6
=0.005
C
M
120
b
u
EAu- EN
94. (C)
120
s
t
44
93. (A)
s
e
o
D
95. (A)
Reduction potential of Mg is very low
as compared to other given elements.
0
2
EM-2.37, E+0.799, E, -0.440,
96. (A)
At anode, Oxidation
2C)
T
E
C
Clhg +2e
At cathode, Reduction
2H,0+2
H2
2C+2H0 Cl0
Hence, Hg obtained
M
T
H
+20H
+Hp +20H
at cathode.
97. (B)
E
-0.76 V,
E
E -E
E-E
E-0.25 V
-0.25--0.76)
-0.25+0.76
0.51
VV
E=-1.66
98.(C)
Electrochemistry (179)2
R
-xb
100
10ohm cml
K
9..(D)
Conductivity,
k
= Cell
n
o
constan
R
is
0.013=Clconstant
300
constant= 3.9 cm
Cell
s
e
100.(A)
Molar
1000 k
conductivity
s
t
C
1000x1.061x104
0.01
10.61
SQ
of electrical conductance
=
=
b
u
cm* mol
101. (B)
Unit
Electrical conductance
=
Q =S
=Q
102.(A)
1
2
log.Product]
Eoell
[Reactant]
For reaction
Cu+2
34-
Ecell
Cu
T
E
C
0
2
n-
1
l0g10TO.011
0.34-0.0296 logio 100
0.34 0.0296 x 2
0.34 0.0592
0.2808 V
=
M
T
H
2
o
D
(Siemens)
eren
6.
Chemical Kinetics
Important Formulae and Shortcut Methods
Rate
n
o
of Reaction
is
>cC+dD
For a reaction, aA + bB
Average rate of reaction
Rate law:
dA]1
Idt
b
d[B]_ 1 d[C]_1 d[D]
dt
c dt
d dt
s
e
C+dD
For a reaction, a A +bB
Rate of reaction o [A}'[B}'
s
t
Ratek[AJ" [B]' 00
Where, k is the rate constant which is independent of concentration and
varies with temperatre
The powers x and y may be simple whole numbers, zero or fraction
which are experimentalh
determinedd
Order of the reaction:
For a reaction, a A+ bB
cC+dD
Rate k[AJ" [B}'
Overall order of reaction= x +y
b
u
rvcosbr09.2al
OLxO0.I0001
o
D
100
toro mo0
16.01
Molecularity of reaction:
(Eyt01
It is the number of reactant molecules
taking part in an elementary
reaction. It is an integer.
For Example: i. O3g) +Og)202g)
(Molecularity 2)itool
ii. C,Hs
H4g)
1
2
+Hl)
rate law:
Integrated
1.
(Molecularity
1)
0
2
(A).301
1.
Integrated rate law for the first order
reaction in solution:
Consider first order reaction, A > Product
k 250ogAlo
10
t
T
E
C
[A
[A]o-The initial concentration of the reactant A,
[A]= The concentration of A that remains unreacted
The units of k will be will be
s,
MH
2. V
at time t
min or (hour) because
logoAlo
2. Half-life of the first order reaction:
T
H
M
MH
693
k/2
[AJ, 1S unitless quantity.
seeo.o-bEO
The half-life of the first order reaction is independent of initial
reactant concentration.
3. Integrated rate law for gas phase reaction:
For the gas phase reaction,
B)+C
k25108102P-P
3.
MHT
4
Ag)
A
5.
t
Where, P
P
=
Initial pressure of A
Total pressure of the reaction mixture at time
F
t.
T
A
C
Integrated rate law for zero
order
4.
For zero order
reaction,
A
K
A-P
Chemical Kinetics (181)
reaction:
units of K will be mol dm
The
Half-life of zero order reaction:
2k
half-life of zero
order reaction
a
CH,COOCH+H,O
mperature.
is proportional
to the initial concentration
Pseudo-first order reaction:
Consider hydrolysis of methyl
acetate,
6.
CH,COOHaq) +
is
of reactant.
s
e
CH,OH(9)
reaction was expected to follow
the second order kinetics,
because the solvent water 1s
however, obeys the first
present in such large
excess that the change in its
concentration is negligible compared
to initial one or concentration
its
remains constant.
Hence this is a pseudo-first order reaction.
The
rimentally
s
t
arder
b
u
Effect of catalyst on Rates of
Reaction :
catalyst is a substance that increases the rate
of the reaction without being itself consumed
in
the reaction. It functions by
providing on altermative mechanism of lower
activation
energy
for
the reaction to occur.
A
eger.
Multiple
MHT-CET 2008
1.
CO8.&(O1
1
2
10s
MHT-CET 2009
Which is a
(A)k=
C)-d
quantity.
o
D
Choice Questions
LO(E
how many seconds will the concentration of the reactant in a first order reaction be halved
the rate constant is 1.155 x
(A)600
(B) 100
(C)60owato (D) 10
After
if
2.
ME)
-2.302
jog
log
82oi1oo11(B)
t =
equations (
(a-x) k dt
d Ceo0/0) (D)All are integrated rate
is
order reaction, the unit of rate constant time?
order
log
T
E
C
hich
(A)Zero order
T
H
0
2
sT t
correct integrated rate equation?
.303,
-
MHT-CET
kk=
(C) Second order
(B) First order
(D)Third
2010
are
4. The
units
D)Lmols
ofrate constant for first order reaction mols
(C)L
(A)mol L s
168
(B)s
oe(6)
n0q0goteg
on.
M
Thef
n
o
[Alo
t/a
uer
A)k=
integrated rate equation isdgog
(B) k=iros
na
(O
(Ck-in
-x
(D)
log
ka(a-X)
a-x
or
ww
(182)MHT-CET
Exam Questions
17. The
MHT-CET 2011
6. In a
0.080M,
the
steP
fastest
(B) rate of
(D)the rate of last stcpP16
overall rate of reaction
multistep reaction, the
(A)rate of slowest step
(C) average rate of various steps
is equal to
.
s
t
k [AJ B). What is the rate nstat
product is rate
8. Rate law for the reaction A + B
and [B]=0.25 M?
the rate of reaction at a given temperature is 0.22 Ms when [A]=IM
if
D)0.05 M's
(C)1.136
(B)0.88 Ms
(A)3.52
=
Ms
b
u
MHT-CET 2015
9.
For the reaction
if the rate law expression is, rate
Os(g) +Og20:(g)
molecularity and order of the reaction are respectively
(D)1 and2
(A)2 and 2
(B)2 and 1.33
(C)2 and 1
o
D
oa
10. The relationship between rate constant and half-life period
(A)
t
=[Alo2k
(B)
,
0.693
k
1
2
k
[O;]
[0] t
of zero order reaction is given by
(D)t=4A%
2k
k
2
11. Half-life period of a first order reaction, A > product is 6.93
hour. What is the value of rae
constant?
(A)1.596 h
(B)0.1 h
C)4.802 h
MHT-CET 2016
0
2
12. The reaction takes place in two steps as
i) NO,Cl NO2)
+Cl
T
E
C
D)10 h
(C)Cho
13. The rate constant and half-life of a first order
reaction are related
0693
(A)tia
2=
k
B)tu
14. Average rate of reaction
(A) 1S0,]
T
H
At
MHT-CET 2017
M
0.693 k
2SO2)t Og)
(B)-0,
At
(C)k = 0.695 tun
>2
SOs
won teA
o08(A
i) NO,Clg)
+Clg
Identify the reaction intermediate.
(B) NO0
(A)NO2Cl
is
is
s
e
MHT-CET 2014
NO2) +Cla
dedl
(D)Cl
to each other as
(D)ktin0.693
written as
C)aso,
2 At
(D)
AS0,]sA
At
0-188
15. Which among the following reactions is an example of
pseudo first
(A)Inversion of cane sugar
(B) Decomposition
order reaction?
C)Conversion of cyclopropane to propene (D)Decomposition of H2O2
ofNOs
*16. Which among the following equations represents Arhenius
equation?
(B) k=A eRT/E,
(A) k=Ae,/RT
(C)k
RT
e
(D)kTE
s
MHT-CET 2
nu or
is
the temperature is
a reaction if its rate doubles when
raise
*7. What is the activation energy for
J
K)
from 20°C to 35°C ? (R 8.314 mol'
(D) 15.1 kJ mol
(C) 34.7 kJ mol
(B) 269 kJ mol
(A)342 kJ mol
Ms
n
o
(A) 990
MHT-CET 2013
,
rate c
18. A
certain
1)
2SO2
In the rea
(A) NO2
C)
NO
Slope oft
19. (A)-Ea
MHT-CET2
el
relations
20. For thee
+d[S
(A)-
+1
(C)
d
ar
(A) 2NH
21. Which
(B) Ci2H
(C) H2g)
(D)
2HC
22. The acti
constant
(A)1.6 x
23. For
a cht
of reactic
(A)incre
(C) incre
24. For
the e
followin
(A)3d
C)2d
25.The
3
integ
(A)k=2
C)k=2
nt for
constant
for aa first order reaction
Chemical Kinetics (183)
is 7.0 x 10
what is the half-life of reaction?
If initial concentration reactant
of
1s
(B) 79.2 s
(A)990 s
(C)12375 s
(D)10.10 x 10s
MHT-CET2018
reaction occurs in two steps as
certain
2s02g)+2NO2(g)> s03()+2NO()
ii) 2NO( +O,(8)>2NO2)
reaction,
the
In
1S intermediate
(A) NOg)
(B) NO is intermediate
(C)NO) is catalyst
(D) Ozg is intermediate
straight line obtained by plotting
the
logiok against 1/T
19. Stop
represents what term?
(B)-2.303 E/R
(C)-E/2.303 R
(A)-E
(D)-E,/R
MHT-CET 2019
The rae
17.0.080
M,
ature
is raised
rate constant
25 M?
[Os] [O]the
s.
the elementary reaction
20. Forthe
relations
2sO
t
Og)
-djsO3g»l-2d|02(g)
(4)
+1
(C)
given by
dSOg
value of ate
dt
D)s2g)dO2g)
o
D
dt
Pt
dt
azero order reaction?
(B)CpHz2O11()+ H,OgCHI20s4 +CoHi2Osaq)
T
(C)
Hag
1
2
tIag)> 2Hlg
D)2H;02002H;00 + Og)
2.
is 1.6 x
activation energy of a reaction is zero. Its rate constant at 280 K
constant at 300 K is
D)Zero
(C)3.2 x 10
(A)1.6x 10'
(B) 1.6x 10 s
0
2
The
s
2)
b
u
+d[SO(g-d02
21. Which among the following reaction is an example of
(A) 2NH3()
s
t
identify the correct among the following
t
dt
dt
2
s
e
2S0(g)»,
(B)
dt
d[sO2(g
t
is
10
s", the rate
s
constant [B], the rate
chemical reaction rate law is, rate = k [A]' [B]. If [A] is doubled at
of reaction
(B) increases by a factor of 3
(A)increases by a factor of 4
(D)increases by a factor of 2
(C
increases by a factor of
the correct relation among the
the elementary reaction, 3 H2e) +Narg >2 NH3) identify
25. For
a
T
E
C
rOr
following
8
relations.
A)3dH
d NH
T
2dHd NH
H
A
2
M
dt
dt
dt
dt
Their
aled
dt
tlog1oA],
a
+ A
i 1el
log1o
dt
.-1dH
dt
3
oD)HdNH]
rate equation for first order
(A)k=2.303
C)k
(B)
dt
15
reaction, A> Product,
B) k=-.
D)
k=;
n
o
(184)MHT-CET Exam Questions
following reactions is NOT one?
Order which among the
26.
of
(A)2H;0202H,O
+Oztg)
(C)2N;Osg)2NOg) +Ozg
(B) Cyclopropane> CH3- CH=CH
+HCI
D(D)CHC) t Chg)>CClug
When conc.
27. Consider the reaction 2A+B-> product.
n
o
is
alf-life
of °B alone was doubled, the hales
the rate inCreases by two times, order
not change. When conc. of "A" alone was doubled,
reaction is
(D)0
(C)1
(B) 1.5
(A)2
s
e
s
t
concentration of A is doubled at constant [B) z
28. Consider the reaction 2A +2B C+2D,
is
doubled at constant [A] the rate is doubled p.
increases by a factor 4. If concentration B
law of the reaction is
[B}* (Drate k[A]B)
(A)rate-k[A (B] B)rate= k{A] [B (Crate
if
[A
b
u
29. If the half-life period of a first order reaction is 200 minutes,
(A)9.605 x 10 min
(B)3.465x 10
the rate constant will be
(C)1.374
x
10 min
30. If the rate of reaction is expressed as, -
(A)3A +2B » C
o
D
1d[AII2 dB| -q,
the reaction is
(C) 2B + C>
(D) 3A2B
(B)2B3A +C
31. A>B
dt
is first order reaction with rate equal
to 6.6 x
constant of the reaction is
(A) 9x 10s
1
2
(B)9x 10s
MHT-CET 2020
M
T
H
min
(D) 288.6 min
(C) 1.1 x 10
dt
3A
10
s.
M
slwol
0
2
(B)6.6 min
36. The rate law for the reaction
40
42
10 s
toth?
(A)66.56 min
39
+C
32. Which of the following is a character
of catalyst?
(A)It increases the rates of both forward
and backward reactions
equally in reversible reaction
(B) It increases the activation energy of
reactants
(C)It affects the energies of reactants and
products of the reaction
(D)It changes the position of equilibrium
33. In the reaction, N, +3H,
2NH3, the rate of disappearance
of H2 is 0.02 M/s. The rate
appearance of NH, is
(A) 0.0133 M/s
(B)0.004 M/s
(C)0.032 M/s
*34. Which among the following 1s correct
(D)0.023 M/s
when energy of activation,
decreases at constant temperature and
Ea of the catalyzed reactou
for same concentration?
(A)eaRTdecreases (B)/RT decreases
(C)K decreases
(D)/RT decreases
35. Half-life of first order reaction is 20 minutes.
What is
the time
concentration of the reactant
taken to reduce
initial
T
E
C
38.
41
When [A] is 0.6 M,
(D) 1.1 x
37
43
44
6
the
(C) 150 min
2NO)+Og)
2NO
(D)79.68 min
47
is rate -k[NOJ
among the following statement is correct?
which
[O:] then
,
(A)The reaction is first order in 02, first order in NO
and cond
(B)The reaction is second order in NO, zero order in O2 and order overall
second
(C)The reaction is second order in NO, first order in
in O
(
and third order overall
(D)The reaction is zero order overall
order overall
48
49
e
www
e
ae
tws
87.59% of
Chemical Kinetics (185)
er reaction 87.5%
of reactant
In a first order
is converted into
37 constant for the reaction is given by
product in 15 minutes. The ra
28)
(B) 0.693 min
A)6O3min
e half-lifedid
mes,
order
stant[B),
rate
ioubled.Rate
D)4.25
s,
s
d
(B)0.30 s
is
s
e
s
t
(C)2.25 s()(D)0.075
s
Eorthe reaction 4NH3+502
4NO + 6H;0, the rate of disappearance NH
40.
of
is 3.6
rate
of
formation
of
the
water?
is
What
(B)54x 10 M/s
(A)6.0 x 10M/s
(C)3.6 x 10 M/s
(D)4.0x 10 M/s
+B+C-
is
C
law for the reaction A
the overall order of the reaction?
(B)1
(A)3
s0.6 M, rate
42. The
reaction
What is
7.75
x
10
x
10
The rate of
(B)
reaction
ases
T
H
initial
ce the
which
M
then
10 M/s.
(CP. What
(D)0
is first order in N.Os having rate constant 6.2x10s
of reaction when concentration of N-O, is 1.25 mol L"?
(B) 8.15 x 10 mol Ls
h at
sed0
(D)2.01 x 10 mol Ls
mol L s
mol L-1 s-1
olot
1
2
rate constant for
0
2
Inversion of Ci2Hz2O11
T
E
C 0B)-ke
Decomposition of N,O in presence of catalyst
TO
(D) Decomposition of N0s
tna
for the zero order reaction?a.Fat
rate
constant
mol dmt
of
the
(D)
unit
is
.What
(C)mol
(A)
(B) mol dm't
Vs. time is equal to
the graph of logio[A].
of
slope
the
reaction
first
order
rOr
(D)
1ooto
2.303
(A)k
acetaldehyde? 0: 6A)
gaseous
of
decomposition
1
47. What
loiufW
gnivollo D)
is the order oof reaction for
becomes 100 times.
to
(A) 0
2
obuseg
reaction
(B)
of
rate
the
times,
by 10
48. If concent
is increased = k[AJ?
Whontration of reactant 'A' rate
rate
(D) 4
law is,
is the order of reaction
reactant to
(C)3
for 20 g of
(A)2
take
it
will
(B) 1
What time
1 x
49. A
constant
first order reaction has rate
rat
D) 346.5 S
reduce
to 5 g?
(C) 693.0 SoH
(A) 138.6
(B) 238.6 s
(
yzed
o
D
[BY'
x
for 75%
first order reaction is 0.02232 min. Calculate the time required
completion of the reaction.
(D)12.77 min
(C)48.12 min
(B)38.31 min
(A)62.12 min
zero order reaction?
Which among the following is an example of
(A) Hydrolysis of CH3COOCH3
43. The
44.
b
u
Product is expressed as Rate- k{AS
(C)2
2NO +0,
the value of rate
(C)4.96
(A)
le reaction
N,O, -
dmr
A
k
2303mb
(C)03
s(91.i
if
10s.
s
n
o
x 5 min
ar
41.The rate
s.
(C)0.693
min
D)
5
a
half-life
of
first
order
reaction is 6.0 hour, How
I
38. The
long will it take for the concentration ot
reactant to decrease from 0.4 M to 0.12 M?
B)9.51 h
(A) 10.42 h
(C) 30.36 h
h
the first order reaction A B,
the rate constant is 0.25
if the concentration of A is
reduced to half, the value of rate constant will be oae 00
(A)0.25
B]
e
15
t
n
o
(186)MHT-CET Exam Questions
50. What is the value
minutes for
it takes 15 minutes
for consum
e
of rate constant of first order reaction, if
of 20% of reactants?
(A) 1.07 x 10 min
(C)1.84 x 10 min
too51. A
(D)1.38 x 10 min
D)98.7 min
s
t
(C) 62.77 min
B) 56.35 min
s
e
how long will it take
first order reaction has a rate constant 0.00813 min,
completion?
(A)112.7 min
is
-1
(B) 1.48 x 10 min
r
red
52. Half-life of first order reaction X
Y+Z is 3 minutes. What is the time required toreduce
the concentration of X° by 90 % of it's initial concentration?lsv odt
(A)9.969 minutes
(B) 4.12 minutes
(D) 12.05 minutes
(C)9.105 minutes
ei
b
u
53. A first order reaction is 25% completed in 40 minutes. What is the rate constant
k
reaction?
2.303
2.303x log 1.33
log 4
B)
(D) 2.303x log
40
40
for
t
C)303x
(A)xlogE
o
D
40x3
54. For first order reaction the concentration of reactant
decreases form 0.2 to 0.1 M in 100 minuts
What is the rate constant of the reaction?
(A) 144.3 min
(B)6.93 min
(C)69.3 min
D)6.93 x 10 min
55. A first order reaction is 75% completed in
60 minutes, the time required
for it's 50% completion s
(A)30 min
(B) 60 min
(C)120
D)40 min
56. What is the molecularity and order
of the following reaction
if rate law is, rate k [Os]10
respectively?
otberOg+O
(A)3 and
1
1
2
0
2
2021
ebno jed
(B)3 and 2
57. For a first order reaction, AB,
1t
constant of the reaction?
(A) 4 x 10s
(B) 0.4 x 10s
T
E
C
mins
(C)4 and 2
LAJ
58. For the reaction, 2NOB)>2NO)+
M
T
H
00
101
I
D)2 and 2
M and rate
is
4x
C) 2x 10s
B)
102 M s
What is the rae
(D) 2.5 x 10 s
Tate law is
r
=k [NOBr?,
rate constant is 1.62 M sand concentration
oG)
If
of NOBr
is
reaction?
o A6 10
2.00
Ms
(B)5.24 x 10 Ms
x
10 M, what is therate
(6.48x 10 Ms
(D)4.05 x 1o-S Ms
the reaction 2S02 +0
2S0 the rate of appearance
disappearance of O is
of SOg is
4 x 10 M/s, rate o
(A) 1.0 x 10 M/s
the
(B)4,0 x 10 M/s (C)2.0x
59. In
of
10 M/s
(D) 6.0x
60. Which among the following is an example of pseudo
pseudo first
order reaction?
N,Osg)
t
(A)2
4NO) Oa)
(8) CH,
-H,
CH,
-CH-CH,
(C)H2Oco2H200+ Oxo
(D) CHCOOCHs) + H,O
CH,COOH) +CH,OH
.
10 M/s
esfor
consumption
erage rate of reaction
average
What
hat is the
when the change
61. seconds?
(B) 0.05 M/s
(A) 4.0 M/s
the reaction
it take
for 60%
in
toreduce
log
64.
(B) a
The reaction 2NO;Cl
65. In
the reaction
(A)
is
66.
[O-][0]
What is the
rate
2.56
(C)a+b
+ Cl
0 Ms
T
H
M/s, the
M/s
M
rate of
s
t
NO)+Clh
2S0+O2S0SO3?
b
u
(C)Clo0ot0.o(D) Clap
(8
(B) NO,Clo
the rate
appearance of
(B) 1.25 x 10 M/s
M/s
10
of disappearance of SO
o
D
(C) 0.64
x
10
M/s
(D) 0.32
is 1.28 x
x
10 Ms.
10 M/s
first order
10 minutes. What percentage does the
certain zero order reaction is 50% completed in
reaction completes after 15 minutes?
(D)60%
(C)75%
(B)25%
(A) 65%
of N2 is 2.6 x 10 M/s,
2NH), if the rate of disappearance
68. In a reaction Na(g)+3H2)
in M/s is
the rate of disappearance of
(D) 7.8 x 10 M/s
(C)2.6 x 10 M/s
(A) 8.6 x 10
(B) 5.2 x 10 M/s
M/s
time is expressed in seconds?
for the first order reaction if
69. Which is the unit of rate constant
(D) mol dm's
mol dm"s
67.
1
2
A
T
E
C
.
rate of
vhat is the
x
(D)
+ Clh takes place in two steps
as
is
reaction takes 40 minutes for 30% decomposition. What is the half-life of reaction?
D) 82.2 min
(C)67.8 min
(B) 77.8 min
(A) 59.5 min
A
(A) mol
0
b
What is the rate of
min
rate k
-
2NO2)
NOg)
NO;Cl
() NO;Cl+Ckp
(A) NO:(g)
% completion
in 20
n
o
s
e
r2/?
20-b)
Identify the reaction intermediate.
M in 100 minutes.
0.05 M
AB+B,
ntration
(A)
for th
is
(D) 1.0 M/s
the rate of reaction
is directly proportional to the
of A and independent on the
concen
concentration
of
k[A]
B. What is the rate law expression
(B) rate k[B;]
(A) rate(C)rate- k[A] [B,] (D) rate- k[A)TBa)
rate for the reaction is
k[AJBJ'. If the concentration
63. The
of A is doubled and that of B is
halved, the new rate is ra then what is the ratio of
A+B,
In
ninutes
0
of product
(C)0.0025 M/s
r-
required
onstant k
Chemical Kinetics (187)
in concentration
dm's
0
2
(B)
Hz
s
(C)
+O2
order kinetics: 2 N024NO2
M and rate of reaction
0.05
is
N;O2
if concentration of
Keaction given below follows first
Calculate rate constant of reaction
1.5x 10 mol
(B)3.0x
(A)2.5x 10 s
Ls?
10s
(C) 1.5
x
10
s
is
D)2.0x 10s
will be the concentration of
0.025 M s What
constant
rate
certain zero order reaction has
concentration is 0.50 M?
initial
(D)0.060 M
" Adctant'A'after
15 seconds, if
(C)0,375 MM
(B)0.125 M
the rate law for
(A)0.50 M
in B. What is
order
first
and
order in A
P, is second
=
eaction A +B
(D) Rate k[A] [B
Rate-k[A]"[B]
the reaction?
Rate=k[AP B]'" (C)
constant ofthe reaction?
(B)
[B]
=k[A]
What is the rate
Kate
minutes.
completed in 50
73. A first
10min
orde reaction is 50 %
(B) 3.465 x
10 min
reaction.
x
(A)7.215x 10 min
(D) 1.386
the half-life of
completion. Calculate (D)57.8 min
(C)1.386x 10 min
minutes for 30%
(C)42.7 min
first order reac
caction takes 40
min
(B)23.1
(A)77.7 min
Order
w
ecers
ww
(188) MHT-CET Exam Questions
n
o
Ls.
75. Rate constant for zero order reaction is 2 x 10 mol
If the concentration
ionof
oftheTeact
concentration
after 25 sec. is 0.5 M, what is the initial
of reactant?
(C)1.25 M
(A)0.125 M
(B)0.5 M
(D)1.0 M
76. The slope of a graph, log [A] versus t for a first
constant for the reaction is
(A)-25x
10
s(B)
2.5 x 10s
order reaction is-2.S
(C)1.086x 10s
x
10-
(D) 5.757 x
Therae
77. The slope of a graph, log [A]: versus t' for a first order reaction
is 2.5 x
Therae
constant for the reaction is
s
(A)-2.5 x 10 s(B) 2.5 x 10
(C) 1.086 x 10
(D) 5.757x 10 s
78. A first order reaction, A
>B takes 100 minutes for it's 90o completion.
What is the r
constant of reaction?
ate
min
(A) 0.0460
(B) 0.0230 min
10sT
s
t
s
(C)0.2303
79.0.0210 M solution of N,Os is
(A)-k
1
2
(B)-kt
82. A first order reaction
in 32 minutes is
(A)75 %
is 50 % completed
0
2
ti/2
ti/2
(D) 0.4606 min
o
D
10s
2.
2 dt
R)dB
k
3.
(B)
5.
(C)
For first
of
Rate
(C)k
in 16 minutes. The
percentage
D)[A]
A
On integ
of reactant that will reat
dE
In[R]
D)dc
(C)Ea
RT creasesiro
On puttin
0
M
RT
In[R]
0,
[Where,
In [R
la
C)
dt
dt
85. The time required to decompose
3 dt
to
Cl2
half
rate constant for this first ordeT
of it's initial
reaction.
amount
(A) 4.158x10 min
is 60 min
ninutes. Calculate
(B) 2.651x
(C)1.155 x 10 min
10 min
(D)1.551x
1080
10
min
86. The rate constant for the first order
reaction is 1.15
M0200
take to reduce to 3 g?
x 10
(A) 414 sec
(B) 444 sec
long will 5g ofthe eactan
(C) 424 sec
*87. When the temperature of first order
reaction
(D)
which among the following is corect?
increases
then according 434 sec
(A) e decreases (B) Ea/RT increases
dol
to Arrhenius equation
T
H
Att
10M/sto
dD
(B)
For first
(B)12-5%
(C)25%
83. Consider the reaction;
(D) 100%
2N,Os)
4NO,)+O2g What
concentration of NO2 increases
is the rate of reaction, when
to 5.2 x 10 M
(A) 2 x 10 M/s
in 100 sec.?
(B) 7.6 x 10 M/s
(C) 5 x
84. For the reaction 2A +B
D) 1.3 x 10 M/s
3C+ D, which among
expression?
the
following
n coitoas
is NOT the correct rate
d[A]
T
E
C
(A)
Rate co
a
b
u
min2
allowed to decompose at 43°C. How
long will it take to reducet
0.0150M ? (Given k = 6.0 x
10
sec)
(A)3364 sec
(B) 360.0 sec
(C)560.0 sec
(D) 5600 sec
80. The rate of first order reaction A
B
>
is
6.3
x
10 Ms', if [A] = 0.3 M, what is the rate
constant of the reaction?
(A)1.3x 10 s
(B) 2.1 x 10S s
C)1.2x 10 s(D)1.6x
81. For zero order reaction, when
[AJ is plotted against
obtained is equal to
time (t), the slope
the straight line
eso
is
s
e
10s
1.
(D) k decreases
kt
=
6. (A)
Rate of re
equal to t
.
(C)
Given,
Final in
tem
Since,
rate
As rate
co
(A) onstant k= 1.155 x 10
Rate
2.303log a
O
k
.Therate
is the rate
klog=2.303
2-2.303
1.155x 10-3 O8 155x10-3 X0,3010
600s
ti/2
in
(B)
to reduce
For first
to
4. (B)
(B)
.
(C)
For first
=kIR:
line
On
dt
integrating equation (1)
dR)
at will react
R
, when
Where,
R =
On
ect rate law
Calculate
1
2
[Ro]
0
2
T
E
C
kt
=
M
Ius
ses
In[Ro]- In[R]
or
k-n
i.e. a].
n
a multistep reaction is
hence the overall rate of
step;
slowest
the
Of reaction depends upon
cqual to the rate of slowest step.
(A)
dc
T
H
reactant
kt
In[R]- In[Ro] and
1. (C)
the
i)
C
we get
putting the value of C in equation (i),
In[R] = -kt + In [Ro]
-
.
ter
otstnsonos ibiiniofAlbogtt
kt +C
In [Ro] =
M/s
o
D
kdt
O
concentration,
- x and Ro is the initial
i.e.
a
concentration,
final
R] =
Att=0,
the
d[R
B ODa8 [R
kdt
=-
In[R]
or
is
b
ue
order,
Rate
1.155
s
t
a
t
=
O.693x 103
s
e
order reaction is
=
k
t1s the rate
s.
n
o
a,(a-x)=
rate
ti/2
traight
s
(a-x)
0s
1.The
Chemical Kinetics (189)
SOLUTIONS
thereactant
20+273 293
Cn,temperature T, =35+273 =308 K
inal
J mol' K
Initial temperature, Ti
=
R 8.314
Since
nce, rate becomes double on raising
equation
2
AS
rate constant,
2r
or
temperature,
2
2a
ka-2
k
Cr
K
Ki
aoue
(190) MHT-CET Exam Questions
From Arrhenius equation, we know that
ET-T
log
2.303 R
TT2
n
o
293-308
E
log2
2303 8.314 293x308
is
E,
-15
2.303x8.314 293x 308
0.3010x 2.303 x 8.314x 293 x 308
0.3010
E
16
34673.48 J
mol-
s
e
34.7 kJ mof
15
8. (B)
s
t
Forreaction, A + B product
-kAB]
dt
0.22k
(0.25)
k
9. (A)
0.22
=0.88 Ms-1
0.25
The rate for the reaction, Os(g) + O(g)
bimolecular and its order is 2.
O:(g) is rate
10. (C)
The relationship between half-life of zero order reaction
1
2
18
1
b
u
o
D
2
17
=
k [O3] [O]. The reaction
and its rate constant is given by
2k
Where, tun - half-life period; [A]o = initial concentration
and k = rate constant.
11. (B)
For first order reaction A > product
0.693
0.693 0.693
tan
= 0.1h-l
k
6.93
1/2
12. (D)
T
E
C
NOCI
0
2
NO2)+ Cl
(free radical)
NO,
Co+Co
NO)+Ca
The intermediate generated is CI".
13. (A)
T
H
The half-life of 1" order reaction is given as
M
14. (B)
Reaction is 2502+
tin-693
k
O0280s
Avg rate of reaction-S02-AO]1A[So,)
At
2 At
Out of four options, only (B) option is correct.
15. (A)
2
At
2
2
Chemical Kinetics (191)
(C)
J6Arrheniusequation isk =Ae Ea/RT
17.(4)
0.693
k
t/2
1/2
18.(B)
A
eEa/RT
0.693
7.0x104
4990 sec
formed during reaction and
again consumed
As. NO is
it is intermediate.
19.(C)
Ink=nA
y= mx
Ea
2.303RT
-Ea
2.303R
slope= -Ea
logA
logiok
+C=logiok
logioA
b
u
C-logioA
-Ea
m-slop2.303R
(A)
reaction
250,+O2
For the
2SO
1
2
(8)
Rate=21.(A)
Lero
T
E
C
(8)
2.(A)
Ea
6)-an,ai
-0, K 1.6
M
T
H
Ka=1.6 x
3.()
1/T
coitocst od
not
iM0olaM01
waloi
xdo
01LI-
0
2
x
10,
T =
280,
T 300K,
oto
Ka=?0
Ea_o8K2.303RTTJ
K,
log
K2 = log 1.6x 10
1.6x10 =0 log
log
(C
<rate of reaction does not depend on concentration of reactant.
to ste
N2 +3H2
order reaction
eg 2NH
o
D
so,]--[0,1-20,
--0,1so,]
Rate
s
t
2.303R
T
n is
s
e
RT
k = log10A
ngin
n
Ea
10
4.(C)
For the
reaction
3H,+N,
>2NH,
m ORED 0
n
o
is
bo
(192)MHT-CET
Exam Questions
d[H,d[N,]1 dNH,
dt
so06ape
1 dt
dt
d[NH,]
1 dH.1
dt
dt
Rate
3
2
3
d|NH,J
2 d[H
dt
dt
reaction A
25. (B)
first order
Integrated rate equation for
>P
29. (B)
For first order reaction,
0.693
=
k=93
=
30. (A)
31. (C)
Rate law for the reaction is, Rate =k [A]
6.6 x 10 Ms =kx 0.6 M
k=1.1
32.(A)
33. (A)
N2 +3H
1
2
s
x 10
0
2
o
D
T
E
C
dNH,) dt
dt
3
2d,)
=
x0.02
dt
=
0.0133 M/s
35. (A)
For first order reaction,
=0.693 0.693
k
0.0346 min
20
/2
if [A]o= 1, [A]= no ?
10
-2.303ogA
Here,
.
t
ti/10
[A],
2.303
0.0346 log 10=66.56 min
wi
00
-
34. (D)
k
qp
noilane sd
)=_I d(H,)_1
From rate expression,
M
HE0E
2NHonoo tto broob ion esob not asst to s181e otoos 00
d(NH, )
Rate of reaction=-
T
H
b
u
3.465 x 10 min
/2
.
s
t
orgof
(A)
27. (A)o28.
is
s
e
2.303A
k=
t
26. (D)
n
o
mus bom
is
08
01 0d
0-
9
[O:]
Rate -k[NO]
J6(C
x 2,y=1
Chemical Kinetics
Here,
Overall order of reaction
37.(D)
87.5 %
i converted
actant is
of reactant
into
[AJo- 100,
k
)e
[A]= 100 87.5 product in 15 minutes,
12.5
means 12.5
2.303 o0[Ah
% remains unreacted.
15
2.303
15
A
Oto n
100
go12.5
10d
2.505log
k
15
8
=
0.693
min
rblom
38.(A)
order reaction,
0.693
0.693
=0.1155 h
6.0 h
For first
k
Here,
001
x+y=3
s
t
b
u
[A]o=0.4 M, [A] = 0.12 M
2.5051o
n
o
is
s
e
blora
bfobistoos euo6 to ooideogpmoon
Ah- 2.303 xlog 0.42.305 0.5224
[A]}
0.12 0.11550.5224
0.1155h
t
t10.42 h
39. (A)
o
D
OF
A0-1001
constant for first order reaction is
independent of initial concentration.
Thus, k 0.25 s
Rate
1
2
. (B)
4NH+502>4NO + 6H20
Rate of reaction
0
2
=-1
d[NH,]
-1dO,] 1
T
E
C
noitoasto 1obiu ds
d{NO]
5 dt
dt
4
Rate of formation of water, dLH,0- 6 d[NH]
dt
4 dt
(A
1 d[H,O]
dtg6
o
dt
0130831 2o0 3eih o
-x3.6x10=5.4 x 103 M/s
41.(A)
0.8E101 x 08.0
42(A)
M
T
H
N,O,
2NO,+0,
2
For first
Rate
(193)
order reaction,
k[N,Os]
6.2 x 10sx
te=7.75x10
001nstane7 1o
0 0
Jsome lecrgiO
0botossznu gniismen
A
A)
1.25 mol L
molL"s
t0E.C
innB100-
zso
0E
0l-
()0e
MHT-CETExam
Questions
(194)
[AJ=
43. (A)
If[A]%= 100,
100-7525
t=7
0.02232 min, -2.5051og 100
2.303ogAh
23010sA 0.02232 25
k
t
-001A00
reaction rat
62.12min
t
catalyst
molecules on the
44.(
Because only the N,O
concentration of N,O.
the total
kinetics.
follows zero order
Therefore, the reaction
s
t
E0E
oo08a202
45. (C)
For zero order reaction,
kA-[A)_
= mol
mol dm
dm'r
b
u
t
46. (C)
47. (C)
Decomposition of gaseous acetaldehyde,
CH,CHO
+cO
CHg
Rate k[CH,CHO?
The order of the reaction is 1.5
1
2
48. (A)
r=k[A,
100 r = k[10
AJ
100
x=2
0
2
The order of reaction
49.(A)
T
E
C
k=1x 10,
=
o
D
MSIO-A
te anobnoquan
si
1
M
0.2
M0oA
101 estanou sta
O-R0-OMA0
[AJo= 20 g
.[A]=5g
noitoset h
797w t0
noitsoot10 916
2.3031o0
t
50. (B)
[AJo
[A
1x107020
2.303x0.602 x 10= 138.6
s
Original amount
of reactant
Reactantremaining
100
For first order
reaction,
unreacted=
2.303oA
k
.k
19010 3eul 10
02.0ceo:0
Roaae10610 ta
2.5008[A
k
T
H
odoss
2
For first order reaction,
t
isindependeu
s
e
001 got00
n
o
is
surface react, the
MA
100-20 80
2.303
15 min 08
=0.0148 min
1.48x 10 80
min
otCa
4lom02S
Chemical Kinetics (195)
Original amount of reactant=
100
aining unreacted
(A =Reactant
(Ak order reaction
100-6040
For first
LA
2.301og
S1.(A)
[A
2.303
ependent
of
ogio
100
=
40
0.00813 min
112.7 min
minn
=3
0.693
0.693
=
For first
order reaction,
logTAL
2.303
=100 25
100, [A])
-logAL
=
k
.
2.30log
100
1
2
2.303x log 1.33
40
40
54.(D)
k
0.695=6.93
min6.93 x 10 min
T
E
C
100 min
%.(A)
i
0
2
100, 20 [A]= 100
AJo
For first order reaction,
T
H
k
250
ai
O2c002
obuoe
rotose1 bro teit
etaW ioiiv ii
oo0.M0
ae
75 =25, t= 60 min
oruit at egr
1og
t
.303108 100
k
25
60 min
A
k2.303x0.6020 0.0231 min
1. The
time
tun
o
D
first order reaction)3020 broooe s
(For
.
b
u
109.969 minv
75,t-40 min
s
t
10
100
0.231 min
53.(B)
[A
s
e
0.231 min
3
/2
rAl=Original amount of reactant = 100
FAL=Reactant remainingunreacted =100-90
M
is
52.(A)
1/2
60 min
required for 50 % completion
0.693
0.0231 min
- 30 min
of reaction is,
n
o
MHT-CET Exam
Questions
(196)
56. (D)
2028)
Oe)+O)
[O]
= k[O3]
taking part in
reaction=2
Orderof
reactantmolecules
rate
reaction) =2
Molecularity (No. of
ii.
n
o
57. (A)
reaction,
For a first order
k[A]
4x10-4x 10s
Rate
[A]
Ro.0
C0
s
e
s
t
58. (C)
2NO( +Br()
2NOB
k=
1.62
Now,
M's,[NOBr] =
r=1.62k[NOBr]
2.00 x 10 M
Msx
6.48 x
2S02+O
10Ms
o
D
2S03
Rate of appearance of SO=
2
dSO,] -4[0,]
dt
-
dt
dt
=4
dt
0
2
T
E
C
61. (C)
Average reaction rate
T
H
62. (A)
A+B,
M
=.
dt
CH,CoOH
+CH,OH
Changein concentration
1o
20
0.0025
298.
001
of reactants.
ti
k [AJ [B
n-k
i091
of products0.05
Change in time
63. (A)
[2A
=2x 10 M/s
taken in excess.
Given Rate oc [A]
and not on [B]
Rate depends on
concentration
IfA is doubledand
AT 00
to behave like a first order reacau
AB + B
Rate-k[A)
E0E
A
x 103 M/s
60. (D)
Pseudo first order reaction is a second
order than is made
which one of the reactant is present
in excess.
Eg.: Ester hydrolysis in which water is
CH,COOCH,)+H,O
tortosor olbnodeih
00
dO-x4x10
1
2
1dSO,]
2
b
u
M
(2.00 x 10
59. (C)
1
is
B
A
Rate
B is halved
1eso.0 O00.002.
oitoontocoitolpoo
e02 301 besiape
pot amitafl
Ee0.0
ciun 0
0.0
tin 1ec0.0
64
wwwww
N
[B
-2*k[Ar
2K[AJ (B- 2a-b
kA
Chemical Kinetics
[B
...(1)
(197)
k[AJ [B]°
n
o
64.(C)
NO;Cl RDSNOg)+ Ck
NO;Cl+Cle)
NO(g)+ Cl2
(1)
..(2)
+Cl
2NO,C
k[NO;CI]
Rate intermediate is formed and gets
reaction
The
consumed in the reaction.
= Clg)
intermediate
Reaction
2NO
s
t
2s0, +0,2S03
I d$O,
b
u
dt
dtthe above reaction,
In
Rate
of disappearance of SO2
66.(B)
First order
t= 40 min
gobs91sb1oorS
Rate of formation of SO3
0
1.28 x 10 M/s = 1.25 x 10
MWs0
=
reaction,
40
A
1
2
100
tp
=
0.693
0.693
67.(C)
For zero
=
0
2
A-020
278
Ap- kt
For 50% completion
-Ag-k(10
0-020
MESI0
A
=
Ao
nil ai Eio b0
10k- -
bos bnoooa
OfOE.0
3Ag
Completion
x100
75%
OE
C0E
O
0
arf
A
a0x
ance left after 15 min = Ap- A
A 1o zsbno
(O) E
200
A
21
(aAon
After 15 mins
M
2
order reaction
T
E
C
AA--A
T
H
A
et
C0.0
200.0
77.8 min
0.00892
k
o
D
yot
Ag -2.303og
2.0108100 A 2505 log-0.00892 min
A
40
70 Ao
70
30
AJ
k-2501og
ler reaction in
s
e
olons tobro Jenh ho
65.(B)
is
A
o8EIReF00
A
Al
e0.0 80tJorgoi tere.0
800
Questions
MHT-CETExam
A
(198)
68. (D)
2NH)d[NH,]
3Hr) d[H,]
dN,)._1
Na)+
dt
1 dH]
dt
dt
dN,)
12
dt
10-dH,]
2.6x
3
q-3x
M/s
10-7.8 x 10
2.6 x
s
e
69. (B)
For first order reaction
-o-
s
t
ORSe
k
The units of rate constant is time"
=
sec.
b
u
70. (B)
For the
1
order reaction
rate
4NO
k[N Os]
1.5 x
10kx
+O208 1o nobamoliooia
0.05
5X10-= 3.0 x 10s
k
0.05
1
2
71.(B)
For zero order reaction,
k
A-[A)
=
15
0
2
0.3750.50-[A]
[A
[AJ
=
0.50-0.375
=
0.125 M
T
E
C
72. (C)
The
is
dt
dt
2 NO
order of A is second
Rate-k [AJB]
o
D
0.025=.0-A]
and order of B is
00
15
Ce0.0
eaoo.0
first, therefore the rate
000
law become
73. (C)
M
T
H
k-
-
2.303
log LAla-2,303
t
[A
2.303
500
100
-01
(O19-
50
22303 x0.3010
log,250
- 0.01386
74.(A)
50
1.386 x
10min
2.303og
k 2.303
2.303
100
8A
A0810
0
0.05757
70
in
n
o
3
dt
0.693
logiol.428
0.05757x0.1547
0.0089 77.865 min
0.0089 min
noiralg
(D)
Chemical Kinetics
15 For zero order reaction.
Ah-[A]
t
k
[A,-0.5
2x 102
1.0M
[A
of a graph, log[AJ. versus
't for a first order
Slope
2.5x
k
10x
reaction is given
2.303
2.303
=5.757 x10s k
E pplethae
o
a
-2.5 x 103x 2.303=
5.757 x 10s
k
-k
s
t
order reaction,
logA
[A
k
=
k
k
=
0.02303 x 1
0.02303 min
19.(C)
2501og
t
A
2.303100
1
2
0
2
2.303
6.0x100
b
u
o
D
d0
78.(
0.021]
(0.015]
3838 logio 1.4 3838 x 0.1461 =560 sec
80.(B)
For first
T
E
C
order reaction,
Rate-k[AA]
6.3x10 k[0.3]
=
T
H
k
81.(A)
For zero
M
k
.5X 10-21 x 104-2.1x 10$
0.3
order reaction
Y
0
Aaoisupe uiasA
[Ao
-A[A
Slope-k
t
Alp-[A)- kt
A
LALICCOxot00
[A
-kt
+ [AJo
mx
C
Time(t)
is
s
e
by
.(D)
The slope of graph, lo8LAJ
Versus t' for a first order
reaction is given by
k
Slope
001
2.303
For first
n
o
25
[AJo
0.5+0.5
Thesslo
(199)
e(200)
Questions
MHT-CET Exam
82. (A)
order
For the first
reaction
2.3030gA) 2,30
t
[A)
16
100
10A
32
100
log
A
1og
MO
logio100-logio[A]
0.0188 x 32
0.0188 x 32 2-logiolA]
0.602 2- logio[A]
to
logro[A] = 2-0.602 1.398
By taking antilog
[A 25.00
after 32 minutes
% reactant that will react
of
tm
yAol
oferta
=
s
t
100-25 75%
b
u
4NO2(¢) +O2()
ety
1 d[NO,] - x5.2x10- 13 x 10 M/s
4x100
dt
Rate
84. D)
2A+B
3C+D
Rate
2dt
0.693
0.693
=
60
86. (B)
k
1
2
dt
dt
0
2
1.155 x 10
T
E
C
2.3051og0
10
2.303
t
T
H
C08.S
gol
IxE0EC00
1210.01
E0ES
01x0.0
log,, 1.66
87.(C)
M
3dt
2.303
tT.15x10
L.15x103X0,2218 = 2002.6
Arrhenius equation,
sgole
min
t
1.15x
o
D
Alaof digse a to snpls
-_dB)_ dD)_ dC]
85. (C)
tin
is
s
e
ogole
83. (D)
2N,Os
n
o
A)
k = Ae E,/RT
sqole
x 0.2218
=
444.17 sec.
o1xIS-0Lx
E.0-0
IS
otkEe
LA-LA
7.Elements
ofGroups 16,
Important Formulae
Group 16
Elem
(Oxygen Family)
.ns np"O (0,to Po
17 and 18
andShortcut
Methods
OH
S, Se, Te, Po)
Atomic size,
From
electronegativity
Hydrides
decreases
(HX): Bond angle,
bondenergy
Reducing power
decrease
increases
Oxides (EO2, EO,) (E -S,
Halides (EX6, EX4,
ns
s
t
b
u
Te: crystalline, amorphous
Po:c, B (both metallic)
17
is
s
e
Se, Te, Po)
EX;) (E = S, Se,
Te)inliu mo
Reacts with metals to formcompoundsoed00
Allotropes
O: Oz, O
S: rhombic, monoclinic obiign
ti
Se: red,greyon
Group
Elements (Halogen family)
o
D
2
2oit1oqot faoigodO
np (F, CI, Br, I, At)
From F to I (At)
1
2
size, Density increases
wtouose
Atomic
Ionisation enthalpy, electronegativity decreases
> (Haloacids, HX): Acidity, reducing character increases, stability
decreases
Oxides of halogens (most of them are unstable)
Interhalogen compounds
Metal halides
HOaM d roitoeoi
Group 18 Elements (Noble gases)
np' (He, Ne, Ar, Kr, Xe, Rn)
ns
T
E
C
From He to Xe (Rn)
0
2
Atomic
lonisation
T
H
to sopeog50
Oxoacids
M
of Sulphur
n
o
M.P.,
lonisation enthalpy,B.P., Densityincreasesobaobg
O0
size, density, M.P., B.P., increases
enthalpy decreases
Chemically inert towards
hydrogen, oxygen
Krypton and Xenon form fluorides00b
HA02
Sulphurous acid- HS0s
ii. Di or yrosulphur acid- HS07
v. Peroxy
disulphuric acid- HS2Os
- H2SO4
ii. Sulphuric acid
monosulphuric acid-HSOs
iv. Peroxy
HS,03
vi. Thiosulphuric acid-
Questions
(202)MHT-CET Exam
of chlorine
Oxoacids
Oxyacids of chlorine
HCIO4
HCIO
HCIO
HOCI
increases
Thermal stability, Acid strength
a.
From sulphur
ii. From sulphite
Na,sOg +H,sOa(09)
Na,SO, + H,0
2ZnS+302(g)
b. Chemical Properties:
Reaction with Cl2
ii. Reaction with NaOH
2NaOH+S0,
NaSOg +H,0
otot
Na,SO,+
H,0 +S0
M
T
H
ergolsrl to 2obix0
2obiad lasrov
iv. Reaction
with Na,SO3
V.
o
D
enesC osie
S0,Cl2(
0
2
2s02g) +O2cg)
T
E
C
1
2
Charcoal
ii. Reaction with
O
b
u
2ZnO( +2S02(6
4FeS20+11020)2Fe,Os(o) +8S02
s
t
+SO2(p)
ii. From sulphides (Industrial method)
SO2)+Clhg)
s
e
SOg)
So+Ozg)
i.
is
Preparation
i.
Reducingproperty-
2NaHSO,codseo
SO2 acts
as a reducing
e.g. 1. 2Fe*
agent in the presence
+SO2 +2H,0
ofmo1isture
2Fe
2. 2KMnO4
Sulphuric
n
o
dioxide (SO)
Sulphur
+ 5S02 +2H,0
acid (H,SO)
+S0Ž +4H*
KSO4 +2MnSO4 la1o
alblaaor0
+2H2SO4d
a. Preparation:
O.2.H-biceonudglteuneg
It is manufactured
by Contact
process;
in presence
ofcatalyst V205
h.
Chemical properties
Elements of Groups
C+2H,SO
$+
Co, +24,0+2S0,
2H,SO
3S0,+2H,0
Cu+2H,SO
2HX
HSO
XBr,
+H,SO,
cone
NaCl+H,SO
KNO,
CuSO,+SO, +
2H,0
X, +S0, +
1)
CH,O
+H,So,KHSo, +HNO,
By the oxidation of HCl with
MnO +4HC1
s
t
MnO
b
u
ii. By the oxidation of HCI with KMnO4
ii.
2KCl+2MnClh +8H,0+5Clh
iv. By Deacon's process
2Cl2 +2H,0
4HCI+O
1
2
723K
V.
b.
0
2
2Al+3C1,
+6Ci,
4PCI
H2
+Cl,
2HC
T
E
C
Cl
2AICl
P
8NH
M
+2H,0 +Cl2
By electrolysis of brine (concentrated NaCl solution)
Chemical properties
T
H
o
D
action of conc. HSO4 on NaCl and MnO2
4NaCl+MnO, +4H,SO,
4NaHSO + MnCl,
By the
o
s
e
CaSO, +2HF
MnClh +Cl, +2H,0
2KMnO4 + 16HCI
+3Cl
6NH,CI+N
(Excess)
Ca(OC), +CaCI, +2H,0
2Ca(OH), +2C1
CH, +CI,
Methane
is
NaHSO, +HCI
Chlorine (C1)
a. Preparation:
CH,C1+ HCI
Methylchloride
2FesO, + H,sO, +Cl
HCI+ HOCI
Clh+H,O
Fe,(S0,) +2HC1
Interhalogen compounds
Interhalogencompounds
XX's (IF5)
Structure
StructureX (ICI) XX'3 (BrF3) Square
trigonal
linear
bipyramidal pyramidal
(or T-shaped)
XX, (IF)
pentagonal
bipyramidal
n
o
2H,0
,S0, 12C+11H,0
CaF, + H,SO
i.
16 17 and 18 (203)
brote
MHT-CET Exam
Questions
Questions
Multiple Choice
(204)
16
is
MHT-CET 2005
electrons in sulphur
(C)8
unpaired
Number of
(D)1
M
(B)6
1.
(A)2
MHT-CET 2006
ore of
2. Apatite is an
(A) fluorine
MHT-CET 2011
not
following property does
3. Which of the
(A) Themal stability
s
e
s
t
MHT-CET 2012
of Xenon does not exists?
4Which of the following compound
(C) XeFs
(B) XeF4
(A)XeF
MHT-CET 2013
5. Which is the strongest acid in the following?
(C)HCI04
(B) HCIO3
(A)HSO4
1
2
7. Which is the most abundant element
on earth?
is
,02,
(C)Oxygen
Identify a metalloid from the following
list of elements.
(A)Carbon
(B) Neon
(C) Sodium
9. Which halogen forms
an oxyacid that contains
the halogen
(A)Fluorine
(B)
0
2
Chlorine
T
E
C
(C) Bromine
MHT-CET 2016
10. The element that
does NOT form
acidic oxide is
(A) Carbon
(B)
(D) XeF2
b
u
o
D to
MHT-CET 2015
6. Electronic configuration of only one P block element
element consists of how many atoms of it?
(A)One
(B) Two
C)Three
(B) Nitrogen
(D) HSO3
exceptional. One molecule
(D)Silicon
O-1DHE
(D)Tellurium
atom in tripositive oxidationSaie
(D)Iodine
Phosphorus
T
H
(A) Neon
13. What is the highest
M
(A)+1
(B) Bromide
(C)lodide
(D)Barium
noble gas in
atmosphere
is
(B) Argon
D)Fluoride
oxidation state
(D) Krypton
(B)+3
(C) Xenon
exhibited
MHT-CET 2017
14. Whichamong
the following
(A)H,O
compounds
(B)
HS
15. Which halogen
has
the highest
(A)Fluorine
value
by group 17 elements?
(C) +5
(D)+7
does not
act as
(C)HSe a reducing agent
(B) Chlorine of negative
of s
toD)Four
(C)Chlorine
11. Which halide magnesium
of
has highest ionic
(A) Chloride
character?
12. The most abundant
is
Hl < HBr <
H <HP
<HCI
correspond to the orderr Hl<
(B) Reducing power
(D)Dipole moment
(C)lonic character
(A)Hydrogen
n
o
(D)iodine
(C)bromine
(B) chlorine
(D)HTe
electron
(C) Brominegainenthalpy
(D)lodine
1
2
Which element among the following
Elements
0B) Oxygen does NOTform diatomic of Groups 16 17 and 18(205)
(A) Argon
molecule
(C)Nitrogen
ules?
MHT-CET2018
8(D)Bromine
element that forms
Tdentify
amphoteric
17. Carbon
oxide.
(B) Zinc
(A)
(C) Calcium
MHT-CET 2019
(D) Sulphur
umber of sulphur in
oxidation numt
18. The
Sg molecule
is
(B)2
(A)0
16.
19. The
IF ?
o(C)6a 2t o w D)3
is
(A)+4
(B)+6
OH (
(C)+5
among the following does
not form polyhalide
(B) Iodine
ion?
(A) Bromine
(C)Fluorine
21. Which mixture is sed for respiration
by deep sea divers?
(A)Kr+O;
He
20.
(B)
+O,
woH
(D)Chlorine
s
t
(C)Ar+O2
O0H D)Ne +O
the following in the increasing
order
of
their acidic strength.
(A) HBr < Hl< HF < HCl
(B)
HCl< HBr <Hl <HF
<
Hl
<
(C)
HBr HCI< HF
(D) HF <HCI< HBr
<HI
23 Which substance is used to
bleach wood pulp into white
paper?
(A) H:02
(B) NaOI
(C) Chlorine gas
D) H,SO4 /KMnO4
24. Which of the following
oxides is amphoteric in nature?
oligt ert guoine
(A) Ca0
Amange
of
OHA
s
e
(D)+7
Which
b
u
that
(B)Na,007
25.
1
2
The shape of BrFs molecule
isoeggd
(A)Trigonal bipyramidal
C)Trigonal pyramidal
26.
Which
o
D
C)AlLO30efE)(D) SO,
doiIE.
aireo
0
2
(B) Square planar
(D) Square pyramidal
of the following oxyacid of sulphur contains S =S linkage?
(A)H,S05
(B) HS02
(C)HSO3
D)HS04
MHT-CET 2020
uiloH(
1, In resonance
hybrid of ozone molecule, O-O bond length is
(A)148 pmn
C121 pm
a)(B)134.5 pm
(D) 128 pm
tate?
28. Which
T
E
C
of the following oxyacid of sulphur contain both S-S and S-O bonds?
A)H,S;03
29.
1
B)H,S;04
)(C)HS02
(D)H;S;0s(A
0W many lone pair of electrons are present on chlorine atom in chlorus acid?
T
H
A)3
()D)1
(B)4
OOC)2
hich of the following
oxyacid of chlorine has highest thermal stability?
(A)HCIO
M
31.Chlorine
(B) HCIO
is manufacture by
(A)Haber process
00)(C)
HCIO4
ebe
(B) Ostwald's process
(D) Contact process
(D)HCIO,
to 2oditUEA
C)Deacon
process
32.Which
to 2ocon )
among
does not form polyhalide ion'?o
halogen
followin
the
A)CI
oRag (D)I
(C) Br
(B)F
a
n
o
is
xidation state of sulphur in HaS207
02
MHT-CET Exam
Questions
and oxidizing agent2
bleaching
is powerful
following
(C)Clh
Which among the
(206)
33.
(A)PH
the
34. Which among
(A)SnO
(D) HI
(B) SO
amphoteric in nature?
following oxides is
(D)Clh0
(C)BO
(B) CaO
mineral
of chlorine?
n
o
following is NOT a
(D)Cryolite
(C)Horn silver
35. Which among the
Sylvine
(B)
(A) Carnallite
ectron
not contain lone pair of elee.
oxyacids of chlorine does
onchlor
the following
is
36. Which of
(D) HOCI
atom?
(C) HOCIo
(B) HOCIO
(A) HOCIO
hypochlorous aci
cid?
are present on chlorine atom in
37. How many lone pair of electrons
3
D)
(C)
2
(B)
(A) 4
power.
38. Identify correct decreasing order of oxidizing
(B) HCIO > HCIO
(A) HCIO> HCI0, > HCI03
(D) HCI0 > HCIO > HCIO
(C) HCIO> HCIO3> HCIO2
s
e
1
s
t
>HCIO3dn
b
u
39. What is the oxidation state of chlorine atom in chloric acid?
(B) +5
C)-1
(A)+1
40. Which among the following pairs
XX,?
(A) Br and F
of halogen forms the interhalogen compound of the
(B) I and CI
o
D
(C) Cl and F
41. Which among the following is used as an oxidizing
agent to
(A)Mn(OH
1
2
(B) H02
(B)+2su2(
0
2
C)+1
of vitriol?
(B)+2
(C)+6
44. Identify the inert gas
used for filling balloons?
(A)Krypton
T
E
C
(B) Helium
(A) HS.0
(D)C
atom in hypochlorous acid?
43. What is the oxidation
state of sulphur in oil
(A)+3
45. Which of the following oxyacid
(D) I and F
bleach wood pulp into white pae
(C) NaOCl
42. What is the oxidation state chlorine
of
(A)-1
(D) +3
(C)Argon
of sulphur contain
abi (D)+3g
lsbi
D)-3ode
D)Neon T0-1
S-O-S linkage?
(B) HS;0s
C) HSO3
46. Which of the following
(D) H;S,0
noble gas molecules
(A) Helium
is
more
(B) Neon
polarized by water?
47. Which among
(C)
Argon
the following
(D) Krypton
is pale yellow
(A) F2
gas?
(B) Br
48. How many lone
(C)Ch
pair of electrons
(A) 3
(D) 1
are present
(B) 1
on each oxygen
49. The oxidation
atom in any
any oxy acids of ch
state of chlorine
(C) 0
(A) number
in its oxyacid
of lone pair electrons
(D)
(B) oxidation
on oxygen depends upon
state of oxygen
(C) number
in molecule atom
of
(D) number chlorine atoms per
of oxygen atoms
molecule
50. What is the colour
per molecule
of gaseous
(A) Yellowish
ozone?
white (B)
Blue black
(C) Blue
M
T
H
2oOHA
6
6
ndbond angle and hybridization of Sulphur Elements of Groups 16 17 and 18(207)
TheO-S-0
(B) 134, sp
sp
in SOg
a
(A)
119°,
negative electron
Highest
(B)F
(A) C
ron on
molecule is respectively
(D) 1170,sp
is possessed by
(C) 105°,sp'd
enthalpy in halogens
(C)I
(D) Br
dioxide combines
ur dioxide
sulphur
atol
with chlorine in the
Uhen
presence of charcoal
catalyst, the product
formed is
(B)
(A) S,C
SOClh
Colloidal Sulphur
C
(D) SO,Clh
follow
oble gases is least soluble
ich of the
in water?
(B) Ar
Ne
(C) Kr
(4)
chlorine
id?
eaeD)
is
s
e
He
n
o
the ratio of volumes of gases involved
in the preparation
of sulphur trioxide
dioxide and dioxygen respectively
under similar conditions of temperature from
and
What
r
s
t
sulph
pressure?
(A)1:3: 1
(B) 2:1:2
(C)1:1:1
(D)
1:2:1
hybridiza
is observed in interhalogen compounds
ne of hybridization
56. What type
of the type XX'3?
(B) sp
(A)sp
(C)sp'd
b
u
(D)sp'd
d of the type
among the following gases is used to produce and sustain
powerful super conducting
magnets for NMR and MRI systems?
hich
white paper?
60.
Which is
61.
Which
1
2
0
2
the lowest oxidtion state possessed by chlorine in it's oxyacids?s
(B) +5
(A)+1
-2H1
o
D
odgud e (C) Heun noitsbi (D) Ne eonie
8. Which of the following oxyacid of chlorine is thermally least stable?
(A) HCI0O
(B) HCI03
(C) HCI02
(D) HCIO
59. The oxidizing power of oxyacids of chlorine depend upon
oold-q a
(A) number of oxygen atoms per molecule
slo emolo loold-qo hoom
B)number of chlorine atoms per molecule
C)Oxidation state of oxygen in molecule
(D)number of lone pair of electrons on each oxygen atom
(B) Ar
(A) Kr
(D)
(C)+3
among the following catalysts is used in manufacture of sulphuric acid by contact
T
E
C
process?
A)Ni
(A)+5
(B) +1otabizo
(D)V,0ssnod
C)MnO
(B)Fe with Mo
. The maximum positive oxidation state shown by halogen is
3
o2aa
t
(C)+7
xo
ao
sinene
(D) +3
type OX;? (X = halogen)
among the following halogens does not form the oxide of
(D)I
(A)F
muis
(C) Br
(B) CI
"Ch
of
T
H
chlorine?
(Athe
)+5
M
65.Inthe
its oxyacids?
highest oxidation state possessed by chlorine in
part (D) +3
130 (C) +7oagti
(B)+1
heating
ateosald
rogen chloride is prepared by
ont
concentrated sulphuric acid.o0 obovdteom
and
powdera
(B)
s dium chloride and concentrated sulphuric acid.
C) bleac
solution.
(D) Dotag powder and ammonia
sulphuric acid.
chlorate and ncentrated
labora
A)bleaching
ogu
A
MHT-CETExam
Questions
SOLUTIONS
(208)
15. (B)
16. (A)
Not
3p
1. (A)
=16
Atomic number of S
17. (B)
3s, 3p
16S1s,2s, 2p°,
electrons.
n
o
It has 2 unpaired
2.
It is an ore of
(A)
CaF2.3Ca;(P01)2
Apatite is
3. (B)
Reducing power increases
HF < HCl< HBr < HI
fluorine with calcium.
.
bond length increases from HR
in the order as H-X
4. (C)
XeF2, XeF4 and XeF6. It does not exist as
Xenon forms following fluorides
5.
is
s
e
Xe.
s
t
(C)
be decided with the help of the oxidation number n ce
The strength of oxyacids can also
central atom, more aCidic is the oxyacid.
atom. Higher the oxidation number of
b
u
H,SO ,HCI0, HC10, H,SO,
Since, in
o
D
of
6. (A)
18. (A
19. (B
In
A
20. (C
F
21.
25.
1
o
Helium (He) is a p-block element but its electronic configuration does not follow the arnm
trend of p-block element electronic configuration. Since it is monoatomic it consists cf
atom of it.
1
2
26.
(C)
Oxygen is the most abundant of all the elements
on the earth. Oxygen forms about 46.0
mass of earth crust.
8. D)
Tellurium is metalloid.
9. (B)
T
E
C
0
2n
a1e (tosibxo biow
(83
beat al etavissng
iollol
gon
Fluorine forms oxyacids in +1
oxidation state.
Chlorine forms oxyacids
in +1, +3, +5, +7 oxidation
Bromine and lodine forms
states.
oxyacids in +5, +7
oxidation
state.
10. (D)
Barium does not form
acidic
T
H
11. (D)
Magnesium fluoride
M
Ca
Zn
mong
HCIo, oxidation number of Cl is highest, so HCIO, is the strongest acid amg
given.
7
Ca
12. (B)
Argon
13. (D)
oxide.(
has highest ionic
isthe most abundant noble gas
The highest oxidation
14. (A)
Except H20, all
27.
state by group
hydrides of group
character.
28.
in atmosphere.
17 elements
16 act as
0 bs 1olwo
nog bas ebiroiaabo 0
is +7,
oq gtoas0
e.g.e.g. IF,
IF7
reducing agent.
ie
15.(B)
lements of Groups
16.0(A)
Noble gases are
monoatomic.
16 17 and 18 (209)
17.(B)
acidic oxide
forms basic oxide,
forms amphoteric oxide.
and S form
C
Ca
Zn
HI.
19.(B)
Oxygen atoms
O.S of S = +6
As 4
.
ber of central
mdo not have vacant d-orbitals,
F
22. (D)
21.(B)
hence does not
23. (C)
form polyhalide ion.
b
u
24. (C)
25.(D)
id among the
o
D
snioto
F
the
nomal
sists of one
s
t
(C)
20.
s
e
acid, all oxygen
atom show
O.S is-2.
attached to S atom,
the pyroSulphurie
In
1
2
26. (B)
HS02 contains
S
=
46.6% by
(A)
0
2
HO-Š-0-Š-OH
(H,S,0)
C)
S linkage.
T
E
C
HO-Š-OH
(H,SO,)
27.D)
T
H
(B)
cooo
HO-Š-OH
(H,S,O,)
anoosle 1lo iag
(D)
1.0.
HO
-
-
OH
(H,S,0)
0%
28.(A)
M
Ihiosulphuric
acid, H2S,03
CO
HO
OH
n
o
is
18.(A)
(210)MHT-CET
Exam Questions
29. (C)
42. (C)
Hy
H
Oxi
Chlorous Acid (HCIO;)
state
increase in oxidation
Thermal stability increases with
30. (C)
1+
HCIO<HCIO, <HCIO,
<
i.
ii.
Haber process NH
ii. Deacon process Cl
iv.
32. (B)
Due to absence of d-orbital.
33. (C)
34. (A)
SnO Amphoteric,
CaO
Ostwald's process HNO
Contact process- HSO
Basic,
Cryolite is a mineral of fluorine.
36. B)
1
2
:0:
b
u
C:
T
E
C
(Hypochlorous acid)
38. (A)
1+
o
D
M
H
Ha
46. (D
X
47. (A
F
CI
0
2
BI
48. (I
3 lone pair
of electrons
on chlorine atom
Al
49. (
T
S+
HCIO>HCIO,
> HC10,
Oxidizing power
of oxyacids of chlorine
decreases as
39. (B)
the oxidation
T
H
44. (B)
45. No
B,03, Cl%0;> Acidic
OH
37. (C)
H
s
e
s
t
35.0
(HOCIO,)
is
HCIO,
31. (C)
n
o
Oil
7t+
5+
3+
43. (C)
of chlorine,
m
50. (C
O
no. of chlorineine reases
51. (A
HOCIO,
Chloric acid
40. (D)
The only known
41. (D)
interhalogen
compound
of the type XX,
is IF7.
52.(A
Ne
www
e
Elements of Groups
Hypochlorus acid> HOCI
Oxidation state of
(
Oil of
16 17 and 18 (211)
Cl =+1
is
4.(B)
45. No
answer
HS,O, -Throsulphurous acid
H,S,0s-Disulphurous
HO-S-OH
s
t
0
HSO-Dithionous acid
HO-S -OH
b
u
HO-S-S-OH
46.(D)
Xenon is the
o
D
most polarized noble gas due to its large size.
47. (A)
1
2
Fluorine (F2) is a
v-bOH
pale yellow highly toxic diatomic gas.
Clh-Yellowish green gas
Br-Reddishbrown liquid
h
Purple solid
-
48.(D)
Oxyacids of
49.(D)
s
e
acid
HO-S-S-OH
HS0-Thiosulphuric acid
All
0
2
chlorine HOCI, HCIO2, HCI03, HCIO4
oxygen atoms in each acid have 2 lone pairs.
T
E
C
of chlorine in its oxyacid depends upon number of oxygen atoms per
number of electronegative atoms more are the oxidation state of chlorine.
Ihe oxidation state
molecule. More the
50.(C)
eases.
Uzone (Os) is
S1.(A)
M
T
H
n
o
vitriol> H,SOb,
pale blue gas with distinctively pungent smell.
1.431A
pairs and
sp2 hybridisation with 2 bond
119
52.(A)
Negative
electron
Cl>F>Br>I
the following order:
n enthalpy decreases in
I
lone pair
MHT-CET Exam
Questions
(212)
53. (D)
SO,
Charcoal
+Cl
sO,Clh
(Catalyst)
Sulphuryl
Chloride
water and
54. (D)
sparingly soluble in
are
gases
Noble
solubility increases from 1 elium t
Kryps
n
o
Kr>Ar> Ne> He
55. (B)
2S0, +0,
Ratio:
21:2
s
e
56. (C)
XX'%(T-Shaped) sp'd-hybridized.
57.(C)
He gas is used to produce & sustain
s
t
b
u
Order of thermal stability of oxyacid of chlorine is,
HCIOHCIO, <HCI0 <HCI04
59. (A)
o
D
Acid strength of halogen oxoacids increases with the
Oxygen atom increases oxidation number of halogen.
60. (A)
1
2
HOCI-Hypochlorus acid
of Cl=+1
O
powerful superconducting magnets for NMR
58. (A)
O.S.
0
2
increasing oxidation
T
E
C
63. (D)
conversion of sulphur dioxide to s
2 bar
T
H
OF2,ClhO and Br:O
in their outermost shel
are
formed.
10-Very unstable, cannot
be ormed.
64.(C)
M
Outer E.C.
38
Since Cl has
65. (B)
7 outer electrons
H,SO+NaCl
K
oeb wesuld algarcO
3p
of CI
it's maximum
ALEN
oxidation
NaSO, +2HCI
Na,SO,+2HCIeeo
state of
besnalo
250
250+0s V,O2SOu
720 K
Halogens have 7 electrons
& 1
led wollogolig
61. (D)
Preparation of H,SO4 by contact
process involves
trioxide. In this conversion
catalyst V2Os is used.
62. (C)
is
2sO,
state is +7.
Transition andInner
ImportantFormulae
(d-block elements)
Trans ition elements
pton
I
Elements
and ShortcutMethods
are
elements are placed
.ietion elements
transition
in the periods
4 to 7 and groups
series.
6d
and
3 to 12 those constitute
Sd
4d,
3d,
sctronic
configuration
General eled
The
Ar] 3d-l0 4s-2
Sd-106s-2
Sd series: [Xe]
ii.
of four series
of d-block
elements
ii. 4d series: (Kr]
4d-10
series:
3d
I
Transition
iv,
5-2
6d Series: [Xr] 6d10
7s
systems
Series
3-d
Series
Elements
Scandium
Titaniumn
Sc
Ti
Vanadium
Chromium
halogen.
Manganese
Iron
Cobalt
Nickel
Copper
sulphur
| Zinc
4-d Series Yettreium
Zivconium
Niobium
Molybdenium
Tcllueerium
40
[Kr] 4d 5s
42
[Kr
[Kr
1
2
Palladium
Pd
Silver
Cadmium
5-dSeries Lanthanum
M
Zr
Hafnium
Nb
Mo
Tc
Ru
Rh
Ag
Cd
La
Hf
Tantalumn
Ta
Tungston
Rhenium
W
Re
Osmium
Os
ridium
Platinumn
Gold
Mercury
26
27
28
29
Pt
Au
Hg
39
44
45
46
47
48
57
72
o
D
Ar] 3d*4s
[Ar] 3d 4s
[Ar] 3d4s*
[Kr) 4d'5s
4d
5s
4d 5s
[Kr] 4d° 5s
[Kr] 4d' Ss
Kr] 4d
[Kr] 4d 5s
[Kr] 4d5s
5s
(Kr) 4d 5s
[Xe] 5d'6s
(Xe] 4f 5d 6s
[Xe] 4f" S5d' 6s
Xe] 4f*5d'6s
4f* 5d 6s
|(Xe]
(Xe] 4f" 6s
(Xe] 4r sd 6s
(Xe] 4r 5d 6s
4 5d 6s
9 (Xe] 4f"5d 6s
|(Xe]
76
80
s
t
b
u
3d 4s
Ar] 3d' 4s
[Ar) 3d' 4s
|[Ar] 3d 4s
L[Ar] 3d° 4s
Ar] 3d' 4s
Ar
30
Rhodium
T
E
C
Atomic
Electronic
Number Configuration
21
[Ar] 3d' 4s
Cr
Mn
Fe
Co
Ni
Cu
Zn
0
2
Ruthenium
T
H
Symbol
5d
is
s
e
aofronic configuration of d-block elements:
n
o
MHT-CET Exam
Questions
6-dSeries
Symbol
Elements
Series
Electronic
Atomic
(214)
Ac
Actinium
Rf
Rutherfordium
Number Configuration
[Rn] 6d 7s
89
[Rn] 5f 6d 7s
104
Db
Dubnium
Bohrium
Hassium
Meitnerum
Darmstadtium
Roentgenium
Copernicium
[Rn]5f 6d' 7s
106
Bh
107
[Rn] 5f" 6d' 7s
[Rn] 5f 6d 7s
Hs
108
| [Rn] 5f 6d 7s
Mt
109
[Rn] 5f 6d 7s
Ds
110
Sg
Seaborgium
105
[Rn)
Rg
111
[Rn]
Cn
112
[Rn]
5f
6d' 7s
s
e
5f 6d"7s
s
t
b
u
Having hep, ccp or bec metallic characters.
increases with increase in atomic number.
o
D
Show variable oxidation states [except first and last member of the series].
Most
common oxidation state of the first series is +2 [except Sc].
Most
of the metals exhibit paramagnetism (contains unpaired
1
2
es).
They form coloured compounds both in solid as well
in aqueous solution due to d
transition (i.e., incomplete d-subshell).
[except Se 3d'), Tif (3d'), Cu'(3d),zn
0
2
(3d]
are colourless].
They form complexes, interstitial
compounds and alloys.
e.g., Brass is an alloy of Cu
(60-80%) + Zn (40-20%)
Bronze is an alloy of Cu
(75-90%) +Sn (25-10%)
They also act as catalyst.
T
E
C
The spin-only formula
= yn(n+2) BM
for magnetic moment
is
Where, n is the number
Bohr Magneton (BM). of unpaired electrons and
T
H
Some
.
M
moment expr
u is the magnetic mo
useful facts :
Most abundant transition
Wonder metal
Ti
Ferrous metalsZinc metals -
metal - Fe
Fe, Co and
Zn, Cd and
Ni
Hg
Lightest metal
Se
-
leaviest metals -Os and
Coinage metals
Ir
andAu
-
n
o
is
5f 6d 7s
transition series:
Trends in properties of the first
increase in atomic number.
An atomic radius decreases with
I.E.
I1.
Ag
Cu, Ag
ansition elements
Trans
(f-block elements) ransition and
Inner transition
elements are placed
placed separately
Elements
separ
(21)
at the bottom
periods.
and 7
of the periodic
inner-transition
table. They
are a subset of
series (Lanthanoid
i. First
6
series)
Name of the
Inner
Atomie
Symbol
element
ldeal Electronie
number
Configuratlon
Lanthanum
57
Cerium
58
Praseodymium
Neodymium
Nd
Promethium
60
Pm
Samarium
Gd
Terbium
3
[Xe]
4
4
(Xe]4
Tb
Dysprosium
Xe]
4
Dy
Holmium
Xe] 4
(Xe4
Eu
Gadolinium
Xe]4f
XeJ4r
(Xe] 4r
Sm
Europium
(Xe"
b6
Ho
57
id 68
d'
d
68
Xe] 4F
5d
68
68
Xej 4
(Xe)4
Xe) 4f
Xej 4f
Xe] 4f
6s2
5d
682
5d
6s
Sd
Xe] 4f
sd'
Xe] 4f0
Sd
Erbium
Er
68
Thulium
Xe]
Tm
59
Ytterbium
Yb
Xe] 4f
Lutetium
Lu
4f
Xe] 4f3
6s2
(Xe] 4
Xe]4f
Xe]4f
sd'6s
sd'
Xe]4f
Xe]
Trends and Properties of Lanthanoids:
Show common stable oxidation state +3.
Regular decrease in atomic
and ionic radii with increase
lanthanide contraction.
They have low I.E. and high b.p. and m.p.
They form coloured compounds due to f-f transitions
La(4f), Gd* (4f'), Lu (4f) colourless
d-d
1
2
6
is
s
e
6s
6s
(Xe] 4
Sd 6s
5d 6s
6s
5d
4
b
u
6s2
Sa'
s
t
6s(Xe
o
D
Xe] 4f
Xe
Xe] 4f
5d'
n
o
Observed Electronie
Configuration
4fsd
6s
6s
in atomic number is called
0
2
Ce(4f) & Yb*" (4f*) -> Colourless despite of having unpaired electrons (exceptions).
Good conductors of heat and electricity
T
E
C
'Except Promethium (Pm), all are non-radioactive in naure.
'The Lanthanoids are strongly paramagnetic.
expressedin
T
H
All the lanthanoids from hydroxides of the general formula Ln(OH)3.
(Ln represents any
element of lanthanoid series).
unce the ionic size decreases from La" to Lu", the basicity of hydroxides decreases.
base.
1S
while, Lu(OH)3 is the weakest
s
the strongest base
i. Second
M
ad Au
inner-tr:
-transition series (Actinoid series)
Electronie
Name of
Atomic Expected Electronic(Observed)
Configuration
Symbol
Configuration
ol Number
Element
7s [Rn]| 6d 7s
Actinium
6d
[Rn]
89 [Rn 5f 6d 7s |[Rn]| 5tf6d7sS
Ac
Thorium
7s
0
Th
6d"| 7s |Rn| 5tf6d 7s
Protactinium
[Rn]
5f
91
Pa
5f6d
Uranium
[Rn]
92
Neptunium
[Rn]5f6d| 7s |[Rn]| 5f6d| 7s
93
5f6d7sRn St6d7s
Plutonium
Np
Pu
94
7s*|Rn]|
[Rn] 5f 6d|
(216)MHT-CET
Exam Questions
Americium
Curium
Berkelium
Californium
Einsteinium
Fermium
Am
Cm
Bk
Cf
Es
Fm
Mendelevium
Md
Nobelium
No
96
97
[Rn] 5f
5f
[Rn] 5fO
[Rn]|
98
99
100
101
102
103
7s[Rn]|
6d
6d
[Rn] 5f
[Rn] 5f
95
6d
5f
7s[Rn]| 5f6
7s[Rn]|
5f T
(A
5f
7s|[Rn]|
7s
9. Ce
C
5fT
7s [Rn] 5fT
7s Rn] 5fT
[Rn]|
MHT
10.1M
6d
IRn]| 5f
5f
6d'
Rn]|
Rn] 5f6d 7s|[Rn] 5fT
[Rn]| 5f 6d 7s[Rn] 5f
Lawrencium |
Lr
elements are synthetice
and from 92U, the further
ly prepey
radioactive,
are
All actinides
elements.
transuranic
called
artificial transmutation hence
properties of Actinoids
state.
All actinides show +3 oxidation
They are highly reactive metals
the metals are radioactive.
Ac"(5f),
.They are generally coloured [except
.All
s
t
Cm" (5f) and Lr" (5fs) are coloiesci
rless)
b
u
Multiple Choice Questions
MHT-CET 2004
1. Oxidation state of iron in Fe;O4 is
(A
1
2
MHT-CET 2008
(B)C
n-
o
D
ou6bpro sldeta nowieeo ete
T
E
C
and actinides is
(A) three outermost shells are partially filled.
(B) they show oxidation state of
+3 (common).
(C)they are called inner transition elements.
D)they are radioactive in nature.
bpibyot
T
H
(A)CaCO
MHT-CET 2009
M
a(B)
MgCO3
O
(C) ZnCOs
6. Most basic hydroxide among
the following is
(A)Lu(OH)
(B) Eu(OH)
(C)Yb(OH)»
7. The maximum number
of unpaired electrons is
(A)Fe
present in
(B) Cu
(C)
Co
MHT-CET 2010
8. Which gives +7 oxidation
state?
(A)Mn(25)
(B) Cr(24)
C)Cu(29)
12.1
13. V
MH
14.
ME
*16.
17.
obiro
is outoro1
5. Calamine is
(
(D)Sc
1)s2
(D)(n 1)d-10 ns!-2
4. The point of dissimilarity between lanthanides
W
Dirtsdins
C)Co2
0
2
11.
15.
3. The general electronic configuration of the transition elements is
(A) 1)d", (n +1)s*
(B) (n- 1)d'-0, (n+
(C)n- 1)d, np', ns
MHT
MH
2. Which of the following ions is colourless in solution?
(A)V3*
is
s
e
Trends and
n
o
(A
MI
boo0
*18.
tqpod
abioeineh iA
geo(D)CaCO
+Ca0
19
M
(D)Ce(OH)»
D)Ni
Uindonio
(D)Fe(26)
20
21
ransition and Inner
transition Elements (217)
stable. This is because of
Ce is
d-orbital
A)half-filled
orbital
empty
(C)
MHT-CET 2011
(B) all paired
(D)fully filledelectrons in d-orbital
d-orbital
common Oxidation states shown
by cerium are
(B)+3, +4
(A)+2, +4
10.1Most
(C)+3, +5
MHT-CET 2012
11.
Which of the
(A)Mn
epared
by
12.
follo
owing species shows
the maximum
magnetic moment
(B) Ni2*
The oxidation
fCr in KCr,0
C)Fe
i
(B) +3
(A)+4
13.
(D)+2, +3
(C)+6
Which of the folowing is not an iron
ore?
(B) Haematite
(A) Malachite
en44
s
e
(D)+5
(C) Siderite
(D)Limonite
2013
MHT-CET
14 Which of the following lanthanoid ions is diamagnetic?
(Atomicno. of Ce = 58, Sm =62, Eu = 63, Yb = 70)
201wolio
(A)Ce*
(B) Sm2
s
t
b
u
(C)Eu2
n
o
is
(D)Ag
(D) Yb
MHT-CET 2014
15. Select the coloured compound amongst the following.
(Atomic no. of Ti = 22, Cr
24,
Cu- 29, Zn = 30)
srdmee (8
(A) TICl4
(B) CrClybyd (d
(C) ZnClt 01021(D)
(O
MHT-CET 2015
sbixo t
"16. Potassium dichromate is a good oxidizing agent, in acidic medium the
oxidation state of
chromium changes
(A)2
17.
1
2
by
(B)
The only radioactive
(A) Gadolinium
o
D
(C)4
0
2
mtt
D)5
element among the lanthanoids is
(C) Promethium
(B) Holmium
MHT-CET 2016
CuCIb
D)Neodymium
sodium chromate converted into sodium dichromate in the manufacture of potassium
dichromate from chromite ore?
tsollie aonot bes bas
aigniwollot or geore doi,2g
(A)By the action of concentrated sulphuric
B) By roasting with soda ash
O(0
C) By the action of sodium hydroxide
ailove(
(D)By the action of lime stone
rp-THA
compounds.
19.Identify
the metal that forms colourless
= 24)
(Z
Chromium
(B)
(A) Iron (Z
geos ifoi
26)
(D) Scandium (Z 21)u
18. How is
T
H
T
E
C
anadium (Z
MHT-CET
M
acido
o
cos
gao
rob
rogqoO (o
23)
llol ortgoo
2018
20.The
.85
most basic hydroxide from following is
62)
(B) Sm(OH)» (Z(A)Pr(OH)
La(OH)» (Z=57)
59)
anos srl Je
C)Ho(OH)3 (Z=
their colourless
(Z=67)
copper (Z 29) in
and
41 Identify
(Z 22)
the oxidation states of titanium
(D)Ti", Cu
Compounds.
Cu
(C)
A)TP",
lo
Cu
B) TI", Cu
u(D)
T,
i240
(218)MHT-CET
Exam Questions
ion and
MHT-CET 2019
charges on chromate
ionic
The
dichromate 1on
respectively is
40
D)-4,-2
(C)-2,-4
potassisum
chlorate
potassium hydroxide and
(A)-2,-2
manganese dioxide,
is
mixture of
23. When a obtained is
D)K2SO4
(C)K2Mn04
the product
(B)KMnO permanganate 1on are respectively
(A)KMnO
manganate and
(D)-2,-2
(C)-1,-1
*24. The ionic charges of
(B)-2,-1
moment
(A)-1,-2
maximum effective magnetic
(B)-3,-2
*22.
fu
(B)V"(Z23)
(A)Mn "(Z=25)
is
transition series?
belongs to the first inner
elements
following
(D) Promethium
(C)Protactinium
26. Which of the
(B) Americium
(A)Curium
ionization enthalpy?
elements has highest second
27. Which of the following
(D) Fe-26)
(C) Co-2
(B) Zn-30)
(A) Cu-29)
has completely filled 4f subshel1?
28. Which among the following elements
(D)Gd(Z=64)
C)Yb(Z = 70)
(B)Ho(Z= 67)
(A) Tm(Z= 69)
decompos
position
following substances is used as a catalyst for thermal
s
e
s
t
b
u
29.Which among the
potassium chlorate?
(A) MnO;
(C) Fe
(B) CuClh
n
o
(D)Fe"(Z-26)
(C)Cu(Z-29)
has
25. Select the ion which
(D) V,0s
30. Cobalt- Thorium alloy is used as catalyst in the process of mo beioloo ori pols
(B) synthesis of gasoline
(A) manufacture of H,SO4
Og
(D) hydrogenation of oils
) decomposition of KC10, to
o
D
31. The highest oxidation state in plutonium (At. No
(A)+7
eho
1
2
94) is
(C)+5gg
(B)+6
*32. Limestone is used as a flux in the extraction
(A)Zinc
=
(B) Iron
0
2
ea
20 TU0-9
(D)+4i
of
C)Copper
D)Aluminium
33. Which of the following is NOT the mineral of iron?
(A)Magnetite
(B) Limonite
(C) Haematite
(D) Corundum
34. Identify the pair of flux and the slag respectively in
the extraction process of iron.
(A)Lime stone and calcium silicate
(B) Calcium silicate and lime stone
(C) Sand and ferrous silicate
(D)Ferrous silicate and sand
35. Which among the following is an
ore of iron?
te b
(A)FeS2
(B) Fe20
(C)FeCO3esaboe (D) Fe,O4
36. The mineral of iron is
(A) Limonite
(B) Cryolite
(C) Calamine oml
(D) Epsum salt
MHT-CET 2020
T
E
C
T
H
M
e
i
37. Which among the following
elements has lowest
density and is lightest?
(A) Scandium
(B) Cobalt
(C)Copper
38. Which among the following
(D) Iron
elements is a soft
(A)Zn
element as compared
(B) Mo
to others
(C)W
39. Which among the following
bizo
Co
ofn
reactions Occurs
extraction
by blast furnace?
at the zone
luoloe(A)
Co
CO
(C) CaO+SiO
of slag formation l
(
CaSiO,
(8) Fe,O, +3C
(D)
Fe,O,+3CO
41
bt
2Fe+3COo
2Fe+3CO2
4
ransition and
Inner transition
Elements(219)
to
form
is greater
complexes
Actionoid contraction is
B)
than
than lanthanoid
energy of
contraction.actinoids.
)Binding
4f orbitals is lower
than
D)Hydroxides of tinoids are less
basic than 5f-orbitals.
Lathanoid
a nosition of elements
hydroxides.
What
La
(Z = 57) and
41.
table?
Ce (Z- 58)
periodic
respectively
in the long form of
Period-7
(A)La Group-4,
(B)La-Group-3,
Ce-Group-5, Period-7
Period-6
40.
rate is
fused,
correct statement
from following.
ids
greater tendency
have
Lantnacontraction
Identit
of
s
e
s
t
occurs at 1500 K in
blast furnace for
(B) Combustion of coke extraction of iron?
of
D)Ore loses moisture
4Which among the following lanthanoids has smallest atomic
size?
43
position
(D)La- Group-3, Period-6
Ce-Group-3, Period-6
lement from followingforms colourless Ce Group-3, Period-7
compounds in +2
oxidation state7
(B)Cu(Z 29)
(A)Zn(Z 30)
(C)Mn(Z - 25)
(D)Co(Z- 27)
which among following processes
n
o
is
Ce-Group-3, Period-6
C)La-Group-3, Period-7
(A)Slag formation
ore
(C)Reduction
(B)Ce
(A)Pm
5.
the formula of calamine?
MgCOs, CaCOs (B) Fe2O3
What is
(A)
b
u
C)Sm
o
D
0C)ZnCO
D)Pr
D)FeCO
46.
Identify
47.
of the following elements exhibits oxidation states other than +3?
(A)Gd
(C)Ce
(D)Lu
hdto(B) La
correct decreasing order of ionic radii of lanthanoids.
(A)Sm> Gd> Ce> Pm
(B)Ce> Pm> Sm> Gd
C)Pm> Sm> Ce> Gd
(D)Gd> Pm> Ce> Sm
1
2
cosu
Which
0
2
48. What is the role of tuyers used in blast furnace for extraction
(A)To blowa blast of preheated air in to the furnace
of iron?
B)It enables the even distribution of charge.
C)It is used to remove molten slag and iron.
D)It prevents loss of hot gases
T
E
C
rom
T
H
49. What is the
(A)MnO
formula of pyrolusite ore?
(B) PbCrO4
(D) Cr-O
(C)CuO
50 hi
C
in the blast furnace for
reaction from following occurs at 2000 K
(B) CaO+ SiO > CaSio
(A)CaCOs>CaO
+CO2bino
1.
(C)2C+O2 2C0
form
following elements has lowest tendency to
(A) AL
52.Which
M
n of
iron
(D)Fe203+3C0
(B) Fe
of the following is a product of
extraction of iron?
2Fe+3CO
its oxide?
(D) Cr
(C) Hg
step for
is used as reactant in next
first step and
concentrated chromite ore sulphate
from
K2Cr20,
(B) Sodium chromate
(A) Sodium of
dichromate
Potassium
(C) Sodium
Chromium
chromate
oxidation state of
in
53.What
t3
found
moment
effective magnetic
is th
of
(Z 24)?
(D) 3.87 BM
BM
(C)2.84
(A) 1.73
BM
(B) 4.90 BM
manufacture
ued(D)
Value
+3 oxidation state9
lanthanoids, shows only
(D) Neodymium
following
(C) Terbium
among the
Gadolinium
Which
54.
(B)
g
atomization from followino
enthalpy
(A) Cerium
of
highest
(D)
Zn
(Z=21)
(Z-30)
element having
C) Sc
55. Identify the
(Z = 26)
Fe
(B)
transition series?
(A) Cu (Z= 29)
belongs to first inner
elements
(D)Pr
(C)Bk
Which the following
MHT-CET Exam
Questions
(220)
of
56.
(B) Fm
(A)Pu
71.
is
oxidation state?
exhibits only +3
following actinoids
(D)Pa (Z= 91)
(Z=92)
57. Which of the
(Z= 103)
(B)Lr
90)
(A)Th (Zamong allo
exhibited by any transition element
state
oxidation
highest
(C)U
58. What is the
(A)+8
state
59. What is the highest oxidation
60. Which
exhibited by actinoids?
(C)+4
(B)+3
(A)+6
of the
four S
following oxyacids of sulphur contain
(A)H;SO4
=
74
15.
O bonds?
(D)H2SOs
76.
of densities of d-block elements.
(B)Cr> Fe>V> Nio al
*77.
of elements is present in chalcopyrite?
*78
61. Identify the correct decreasing order
(A)Ni> Fe> Cr>Vse 3mole
(C)Fe> Ni> V> Cr
62. Which among the following sets
(A)AI, O
(B) Fe, S
s
t
o(E(D) +7
V
73.1
b
u
(C)HS06
(B) HS04
s
e
D)+5
C)+7
(B) +6
n
o
72.
o
D
(D)V>Cr> Fe > Ni
(D)AI, Fe, O
(C) Cu, Fe, S
1
2
63. Which among the following elements is radioactive?lno geieneroob toomoe vitns
(A) Eu
(B) Nd
(C) Pm
D)Lu
64. Identify the element if it's expected electronic configuration
is [Ar]
(A)Cd
B)Co
bt
0
2
65. Which among the following elements
possesses one
configuration?
(A)Cu(Z = 29)
T
E
C
(B)Ni(Z=28)
66. Identify the mineral iron
of
from following.
(A) Magnesite
(B) Calamine
80.
electron in 4s orbital in observed elecam
o (D)Mn(Z=25)
(C)V(Z=23)
C) Siderite
*81.
Willemite
67. Which cation from following
does
NOT
form
(Atomic number
colourless compound?
Cu= 29, Ti = 22, Zn =
30,
(A) Ti
Sc = 21)
(B) Cu
(C) Sc3*
68. Which mineral among
(D) Zn
following contains
(A) Willemite
zinc?
atwollot
(B) Malachite
(C)Corundum
69. Which among the
following actinoids
D) Azurite
(A) Pu
exhibits highest
T
H
M
79.
3d"4s.
(C) Znetrormols zn (D)Hg
(
82.
oo
70.Which element )B)Lr
among
oxidation state?
(A) Dysprosium
(C)Neodymium (Z 66)
sodaD)
the
to(C)
following
Cf
83.
oxidation state +7?
((D)
exhibits electronic
configurationa Xej4t
boe i (B) Praseodymium
(Z60)aeet(c(D)
Cerium
Th
(Z 59)
(Z=58)
9Tutots
in
o
84
85
ransition and Inner
1g the followino
following pairs
among
transition Elements
of clements in their
1. value ofeffective magnetic moment?
(221)
respective oxidation
nber: Sc=21,
states will have same
Ti=
(Ator
22, Cr-24, Co
and Cr*
(B) Ni and Ti
27,Ni
(A) Zn
Zn-30)
(C) Sc" and-28,
T
Which ofthe following compound is used
(D) Cr and Co
as an ore of iron?
72
(B) FeCO
(A) FeO4
(C) Fe,O,
(D) 2Fe,O, 3H,O
is generally employed for ores
Roa
containing
(B) carbonates
(A) Oxide
(C) nitrates
D) sulphides
ch of the following elements possesses
one
unpaired
electron in 5d orbital
electronic configuration?
in observed
(B) Gd (Z-64)
(A) Eu (Z=63)
(C) Nd(Z=60)
(D) Yb (Z=70)
Which among the following elements belongs to
second
inner
transition series?
(B) Er
(A) Nd
(C) Np
m(D) Lu
Which among the following hydroxides is most ionic in
nature?
(A) Eu(OH)
(B) Ce(OH
(C) Lu(OH
(D) La(OH)s
77 which zone of blast furnace used to extract iron, reduces MnO2
and Ca (POs)z to Mn and P?
(A)Zone of reduction
(B) Zone of combustion
(C) Zone of slag formation
(D) Zone of fusion
Which
zone
of blast furnace in extraction of iron works
78.
out the following reaction?
m
Which
)
n
o
t
3.
is
t
Fe,O, +3CO
2Fe+3CO,
(A) Zone of reduction
C) Zone of combustion
79.
Identify the
d electronic
80.
in
M
1
2
(B) Cr
Which
s
o
D
(B) Zone of slag formation
(D) Zone of fusion
ot
odh to
oi
ce
g gpivrollol o(D) Cd
(C) Mo
T
E
C
0
2
es cA
the following elements belongs to second inner transition series?
(D)Lu
(C) Dy
(B) Am
Which of the following properties is NOT of actinoids? gmvoil
hese have reater tendency to form complexes.
toaoieup
nding energy of 5f orbitals is lower than 4f orbitals.
lanthanoids.
than
ydroxides
more basic in nature
(D)Some of of theseare
the ions of these are fairly coloured.
Which
electronic configuration
4.
element mong the following has empty 5d-orbital in observed
(D) Gd (Z-64)
(A) Lu
C) Yb (Z=70)
(Z= 71)
(B) La (Z=57)
5 W'hichamor
lanthanoid?
the following elements is NOT a
(D) Pu
Which among
(A) Sm
T
H
+ 4
eg
element among the following has highest number of unpaired electrons in observed
electronic configuration?
(A) Scandium (Z 21)
(B) Copper (Z = 29)olor ott to doid2e
C) Titanium (Z 22)
(D) Chromium (Z 24)
soll dio136
OLWhich among the following hydrides have low bond dissociation energy of M-H bond
(M=Central atom)?
(A)H;0
(D)HT
(C)HS
(B) H:Se
.
02
b
u
soft element from following.
(A) W
s
e
s
t
o
A) Smong
(B)Cee3i)C)
0
Pr
0S
?
MHT-CET Exam
Questions
following reactions
(222)
among the
furnace?
*86. Which
by blast
iron
extraction of
12CaO+2A1,0;
4Ca AlO; + 30
(A)
occurs at zone
formati.
ation in
of slag
the
prote
(B)C*,02>co
(D)2C002+2Cote
1. (A
2Fe + 3CO;
lanthanoids?
is NOT of
properties
following
*87. Which of the
orbitals is higher.
(A)Binding energy of 4f electron enters in 4f-orbitals.
differentiating
(B) In these
atory
prepared in laborato
form oxOcations.
in nature but
(C)These elements can't
occur
not
do
these
(D)Most of the elements of
NOT form oxocation?
does
elements
following
D)Np
88. Which among the
(C) Pu
(B) Lu
(A)U
compounds?
following forms colourless
89. Which cation from
24, Ni = 28, Fe = 26)
olled o(D) CP*
(Atomic No.: Ti = 22, Cr=
(C) Ni2
Fes
(B)
T
(A)
from +1 to + 6?
elements exhibits oxidation states
90. Which from following
=
D) Cu (Z=29)
(C) Fe (Z 26)
(B) Cr (Z-24)
(A) Mn (Z=25)
(C)FeO +3C0
is
s
e
with dilute
91. Which of the following metals reacts
92. What is the melting point of zinc?
(B)692 K
(A)473 K
b
u
H,SO4?
o
D
(C) Fe
(B)Hg
(A)u
(C) 423 K
93. Which of the following elements has six unpaired electrons in
(C) Mn (Z = 25)
(B) Cr (Z= 24)
(A)Cu (Z= 29)
*94. Which among the following pairs
(A)4.0 % C, hard and brittle
(C)0.2 to 2.0% C, very soft
1
2
s
t
D)1193 K
of percentage of carbon and the property of cast iron is t
(B) Less than 0.2 % C, very soft
(D)0.2 to 2.0 % C, forms steel alloy
95. Which of the following methods is used for concentration of iron ore?
ibus2
(A) Washing in current of water
(B) Froth floatation
Simttnef
(C) Dissolving the ore in water solution of NaOH
or Na,CO3iot
of
D) Electromagnetic separation
st noe
*96. What is the temperature needed
exta:
(Or
for decomposition of lime stone in blast
furnac
of iron?
(A) 2000 K
(B) 1200K
(C)500 K
(D) 1500 K
*97. Which among the following
firon
changes occurs at
900K in blast furnace for exura n
(A)Limestone decomposes
(B) Reduction of ore by C
C)Reduction of ore by
CO
(D)Ore loses moisture
yab
98. Identify the formula
of lanthanoid
oxide formed when
(A) Ln2O
lanthanoid (Ln) is burn
(B) LnO
T
H
M
T
E
C
99. Which element among the
state?
(A) Neodymium
(C)Ln,O
following exhibits
(Z= 60)
(C)Praseodymium
(Z= 59)
bet
(D) LnO
electronic configuration as
(B) Terbium (Z=
65)
(D) Cerium (Z 58)
3.
D)Bi
observed electronic configurnti
D)Fe (Z-26)
0
2
n
o
2. (
5.
6.
7.
he process
Transition
SOLUTIONS
of
(A)
1.
oxidation number
be the
x
Let
3x
+4
(D)
x-2)
= 0
or
of Fe in Fes04.
3x 8
x=
Elements (Zz0)
in Fe,O
3
4s0
(two unpaired
4s
[Ar] 3d,
C
4s
4s2
3d,
4s
3d',
[Ar]
Sc(21)= [Ar] 3d', 4s2
[Ar]
Co(27)
Co
electrons)
(three unpaired
electrons)
(three unpaired
electrons)
is
s
e
Ar]
3d", 4s
(no unpaired electrons)
Thus in Sc no unpaired d-electron
is present. Hence,
colourless 10n.
no d-d transition
is possible and
huis.
3.
29)
(D)
Generally,
.
b
u
(n
6.
on is true?
C)
(D)
Due to
o
D
1
2
lanthanide contraction, the size of M" ions
(i.e., Lu", Eu", Yb*" and Ce) decreases
strength of their hydroxides decreases.
of given M ions is
0
2
Ce>Eu*>Yb* > Lu"
The order of basic strength of hydroxides is
Ce(OH); > Eu(OH)3> Yb (OH)3> Lu(OH)3
1. (A)
T
E
C
aFe[Ar)
eotab
3d4s2
4 unpaired electrons
firon?
29Cu=[Ar]
Co [Ar]
T
H
gen.
oxidation
4
1)d-0, ns2
carbonate ore of zinc (ZnCO).
and thus, the basic
The order of size
rextraction
-
Lanthanides and actinides
both are not radioactive. Except
promethium, all lanthanides are
radioactive while all actinides
nonare radioactive.
Calamine is the
6)
s
t
M
it is
d-block elements are called
transition elements as
d-subshell. Thus, their
they contain inner partially
general electronic configuration
filled
is
4 (D)
nfiguration?
n
o
[Ar] 3d', 4s
V23)
=[Ar] 3d,
[Ar] 3d',
Cr24)
Se
or
Therefore,
and Inner transition
sNi=[Ar)
3d4s
A)E
(one unpaired electron)
3d'4s2
1111 1 11
3
unpaired electrons
3d 4s
1unpaired11|1
2
ece
boio
(aoaelo boisgr
b
2
(224)MHT-CET
Exam Questions
state
elements, oxidation
d-block
For
4s
= [Ar] 3d'
Mn(25)
8. (A)
(a)
+ (n-1)delectrons
70
n
o
15. (B)
[Ar)
(b) Cr(24)
5+1 = 6
O.S
[Ar] 3d4s
(c)Cu(29)
0+1=1
O.S.
[Ar] 3d° 4s
(d) Fe (25)
+2 and +3
O.S.
among the given elements
+ 7 oxidation state
exhibits
Thus, only Mn
(C)
s
e
is
s
t
241
(T
configuration of Ce is
The electronic
(observed)
Xe] 4f Sd" 6s
Cess
(Xe] 4f sa" 6s
are empty and Ce gains th
the
all 4f, 5d and 6s orbitals
sta
Since, in +4 oxidation state,
stable.
is
most
Hence,
Ce
gas.
inert
configuration of nearest
Ce=
b
u
10. (B)
Ce is as Ce: [Xe] 4f*sd'6s
The electronic configuration of
cerium are +3 and +4.
The most common oxidation states shown by
11.
63
(Unne
npaired)
5+23d 74s'
O.S.
.
ns electron
(C)
No.
S.
(a)
b)
configuration
Mn
Thus, Fe
1
2
[Ar]3d
[Ar] 3d
Ni
(c)Fe
d)Ag
|[Ar] 3dP
[Kr] 4d
o
D
No. of unpaired
Outer-most
lon
electrons
KCr:O
T
E
C
16.
B
P
d
bf
Magnetic moment
H=yn(n+2) BM
0
2
1.73
2.83
5.91
D
17. (C
18. (
will show maximum magnetic moment.
12. (C)
(A
Si
S
19.
Let the oxidation state of Cr is x.
=
2(+1)+2x+7-2) 0
=
+2+2x2x 12
O
0
14
0
20.0
x=+6
13.
(A)
Sr. No.
T
H
(a)
(b)
Ore
Malachite
Haematitee
(C)
M
L
21.(
Formula
CuCO.Cu(OH)
Fe:0
Siderite
FeCO
(d)
Limonite | 2Fe,03.3H,O
Thus, malachite
is
C
not an ore of iron.
bi
14. (D)
Lanthanoid ion with
ssCe
Ce
Xe]4f 5d 6s
4f
62Sm
Sm
no unpaired electron
=
Xe] 4f° sd 6s
4f
22.
is diamagnetic
(2 unpaired
(6 unpaired
electrons)
electrons)
in nature.
C
Xe] 4f sd
63Eu
4f
Eu
Yb
Yb
Ar] 3d 4s
C
(Three unpaired
electron
ODHO
(All electrons paired)
Qu=[Ar] 3d4s
1 10 1 11
n
o
CP-[Ar] 3d
Cu'
is
s
e
[Ar] 3d
s
t
1
ion
(6
Ti-[Ar] 3d 4
(All electrons paired)
Cr
(22)
OnMt
hencediamagnetic
Zn Ar) 3d0
11
Since
Elements
electrons)
Zn=[Ar]3d 4s2
ns the
stable
electrons)
No unpaired
(B)
[Ar] 3d 4s
Ti unpaired electron)
(No
(7 unpaired
4r6s
[Xe]
4ft4
ransition and
Inner transition
6s?
has 3 unpaired electrons, therefore its
salt, i.e. CrCl, will be coloured.
b
u
16.(B)
Potassium dichromate 1s good oxidising agent in acidic
medium. In this process potassium
dichromate (OXidation number
of Cr=+6) is reduced to chromium sulphate (oxidation number
ofCr=+3)
Cr,0+14H* +6e
Dichromate
i1on
gain six electrons and hence act as an oxidising agent.
1
2
17.(C)
Only
o
D
2C+7H,0
Promethium is radioactive.
.(A)
0
2
conc. H,SO4
Sodium dichromate
ncrzo
2Na,CrO4 +H,SO (conc.) > Na^CrO, +Na,SO4 +H,0mtoluoloz
Sodium
chromate
19.(D)
are d-block elements which form
options chromium, vanadium and scandium
compounds. Iron forms colourless compound.
T
E
C
ut of given
coloured
20.0
Ln(OH): Basic strength decreases from La(OH)s to Lu(OH).
21.(C)
T
H
22p 3s'3p 4s3d
aTi1s
1s2s'2p°3s*3p°4s'3d'
M
C1s
Cu
fno
(No unpaired electron
2s'2p 3s3p 4s'3d
(O)
electron in d orbital)
aired
solution
(No
ls 2s 2p°3s3p°4s°3d
metal or ion then its
the transition
of
orbital
electron is present in d
cdcolourless.
Decomes
12.(A)
in d orbital)
Chromate
ion
,
CrO
()1e
Dichromateion C,0
(226)MHT-CET
Exam Questions
23. (C)
+KClO
3MnO2 +6KOH
24. (B)
Manganate ion
>3K2MnO4 +KC+3H,O
1.
MnOg
Permanganate ion
MnO,
29. (A)
28. (C)
27. (A)
26. (D)
25. (D)
52. (C)
is
31. (A)
state.
Pu exhibits +7 oxidation
32. (B)
33. (D)
Corundum
are mineral
crystallized alumina while all others
is
s
e
A
of iron.
s
t
34. (A)
103 t0ools ilA
35. (B)
Fe203 (Haematite) is an ore
36. (A)
Limonite
of iron.
b
u
(bozing anoosls
2Fe,0g 3H,0
o
D
37. (A)
In 3d-series elements, across the series density and mass increases from Sc to
Scandium has lowest density and is lightest.
ii.
ii.
53. (D
C
54. (E
(8A
The
Zn.
G
T
55.
E
th
38. (A)
All transition elements (with the exception of Zn, Cd and Hg) are very hard.
. Here, Zn is a soft element as compared
to others.
56.
39. (C)
57. 1
Zn
Zn
43. (A)
44. (C)
1
2
40. (B)
42. (A)
3d
41. (B)
0
2
(No unpaired d-electron)
forms colourless compounds in +2
oxidation
T
E
C
45. (C)
T
H
46. (B)
Along the lanthanoid series,
47. (C)
Ce
Xe]4f sd° 6s?
Ce exhibits +4 oxidation
48. (A)
49.(A)
P
9vitoscibt at moidiounofd
bo204i
there is a decrease
in
buos
enodo pbe
state.oc0)02 8+00
Atomic siZe decreases across the series
from left to right
Ce> Pr> Pm> Sm
M
n
o
30.(B)
07l 2bogo0
58.
60.
t
ionic radii.
3tsl stag o
state.
50.(C)
51. (C)
201
0
61.(
(C)Convers
of chromite«ore into sodium
ransition andInner
transition Elements
(220
chromate
4FeCrO, 8Na,CO, 70,
2Fe,0,+8C0, +8Na,CrO.
Chromite ore
Sodium chromate
rsion of sodium chromate into
sodium dichromate
2Na,CrO, +H,SO
Na,Cr,0, +Na,SO,
Sodium chromate
Sodium dichromate
usotovo
anversion of sodium dichromate to
Na,Cr0,
+2KC1-
Pot. dichromate
+2NaCl
s
e
3.(D)
3d
C
(3
unpaired electrons)
n(n +2) 33+2)
ti
oousole ao
s
t
3.87 BM
54..(B)
Gadolinium(Xe] 4f 5d'6s?
The
herefore,
extra stability of
b
u
Gd ion is due to their half-filled f-subshells.
55.(B)
o
D
n
o
is
potassium dichromate
K,CrO,
Sod. dichromate
attort
+B,ObehA
-olimebie
otSomoll
greater number of unpaired electrons, greater is
interatomic interaction and greater will be
the enthalpy of atomization.
The
56.
D)
Pr
belongs to first inner transition series, i.e. Lanthanoids
series elements.
1
2
57.(B)
Lr(Z
58.(A)
[Rn] 5f4 6d' 7s2
completely filled 5f- orbital, Lr exhibits only +3 oxidation state.
103)
Due to
=
59. (D)
60.(C)
)
T
E
C
HO-S-OH
0
2
(ii)
M
HO-S-S-OH
(H,S,O,)
ii) HO-S-S-OH
(iv)
HO-0-$-OH o aeoge
O 0
(H,SO,)(00)
(H,S,O,)
61.(A)HSO6contain four S
O bonds
the 3d- series, density of the elements increases.
Ni> Fe>
Oss
Cr>V
T
D)uD00s0-sidasisM
(H,SO,)
T
H.
o
dbos
(228) MHT-CET Exam
62. (C)
Chalcopyrite
uuesuune
CuFeS2
onoinsn
980
63. (C)
lanthanide.
Promethium (Pm) is the only radioactive
64. (C)
[Ar]3d4sZ=30 (Zn)
65. (A)
(A) Cu(Z = 29)
(B) Ni(Z = 28) =
(C)V(Z
=
23)
(D) Mn(Z =
3s 3p°4s' 3d0
Is 2s 2p° 3s 3p°4s 3d
= 1s* 2s? 2p
25)-
3s 3p° 4s
3d
1s 2s 2p° 3s 3p° 4s*
utib.boe
s
e
3d
n
o
is
2s 2p
1s
Cu(Z -29) possesses one electron in 4s orbital in observed electronic confieas.
66. (C)
Magnesite - MgCO3
M&
2.
Calamine- ZnCO
o
b
u
Siderite FeCO3
lsitdue-1 bollit-pd niod os oub 2itot
Willemite-Zn2SiO4
67. (A)
Ti3
=4s
3d
Cu
4s
3dl0
Sc3
Ti
1
2
4s 3d
Zn2*
=4s 3d10
68. (A)
T
E
C
bi
vilidety s
o
D
0
2
forms colored compounds as
Willemite- ZnSi04
s
t
toigeaeg
(C)ee
T
H
70. (D)
M
i. Dysprosium (66)
ii. Praseodymium
O-2-OH
of +7 is exhibited
DXe]
by Pu and Np.
4f°6s?
0
(59) =[Xe] 4f 6s?
ii. Neodymium (60)
[Xe] 4f 6s?
iv. Cerium (58)-[Xe]
4f sd' 6s
Cerium exhibits
7
76
Azurite-2CuCO, Cu(OH)
Highest oxidation state
7
74
it has unpaired
electrons.
Malachite- CuCO, Cu(OH),
Corundum- Al203
69. (A)
ration
+4 oxidation
state with
78.
79.
configuration
4f.
ansition and Inner
11.(D)
Contiguration
Se-4s
No. ofunpaired
3d
Cr-4s°3d |L1
N-4s 3d
1
11
1
=
V15
b
u
=3.9
(C)
Haematite is an
ore of iron: Fe203
o
D
X
Roasting is carried out for sulphide ores which on heating in presence
gases like SO2 etc. from the ore.
bionlas2i (6e S
1
2
74.(B)
Gadolinium: Gd (6u): Xe4f sd' 6s gale usiom iamot
It has one
unpaired electron in d orbital.
Neptunium= Np(93) =
76. (D)
0
2
[Rn] 5f *6d'
T
E
C
blast furnace
MnO,
In
T
H
+2C
4,(PO,)
Sio,+C
7s
stst
zone of fusion: 800°
of excess of air releases
oui9 ut
(B).08
or 3ugnng ddi
M
Lone of
OO
OACOsDSt
C).78
orft
1350 20r ob 92303 to elnorrelo
to taoM
(8)28
sis
1200°C
ammot it.nodoolo
Diuoqo0 tesluolo2
boinqu on and T
soni2
reduction or top zonc
re,O,+3Co 3K
19.(D)
Or
O
Oiee0
OlAD
zonidoo
belongs to 5f series.
Mn+2CO
3CaO+ P,0,
Si+CO,
T8.(A)
s
e
odt to oreo
bo18qorg d
is more ionic in nature.
LOH)s is the most basic of given hydroxides. It
200b (ul)
7.(D)
abiomsdinsl on 9a19ed nots3oxo mol vot
dsl at
2Fe+3CO
like Ag Cd, In, Auetc. are soft in nature.
Aetals
pbizo
is
o
ao be
(D)
75. (C)
n
o
(d).c9
s
t
have same dipole moment
have 3 unpaired electrons. bouoloo ghiat oo seorh
1o anoi
yn(n+2)
3.
0d
3
Caecies having same number of unpaired electrons
72.
electrons
RVViono2
Co-48 3'
(229)
3
T-4s°3d'
C&Co
transition Elements
wode
nos
ote
laonimaltoni anotonla
o asd
10 soti2
(230)MHT-CET
Exam Questions
No.
80. (D)
of unpaired
4s2
21Sc [Ar]3d'
22 Ti
24
29
electrons
91. (C)
Fe+
2
=[Ar]3d2 4s2
92. (B)
Melt
4s
Cr [Ar]3d'
4s'
Cu =[Ar]3d0
H and Te is
81. (D)
the bond between
electronegative,
Since Te is less
dissociate.
low energy to
electronegativity is as follows:
Order of increase in
not much
itrm
second inner transition series.
Americium (Am) belongs to
83. (D)
fairly coloured.
Some of the ions of these are
All actinides are coloured ions.
84. (C)
E.C. of 71Lu
E.C. of s7La
E.C. of 7oYb
E.C. of sGd
[Xe] 4f"sd'6s
=
=[Xe] 4f'5d'6s
[Xe] 4f
=
sd'6s
=[Xe]4f' sd'6s
85. (D)
Pu (Plutonium, Z
oidwo
=
1
2
94) is actinoid.
86. (A)
is
s
e
Te< Se< S<0
82. (B)
s
t
b
u
o
D
T
E
C
89. (A)
00S
2Ti[Ar]
T
H
26 Fe
o
aNi"[Ar]
Since Ti has no unpaired electron,
M
90. (B)
2aCr [Ar)
Since Cr has 6 electrons
muit tanld al
008
-20-0a
0.9-0Of
00+1
3d"
4s
no lanthanoids form oxocations.
O0+M
Ar] 3d
it forms colourless compound.
3d5
O0000D
in outermost
Cast
95. (A)
Was
awa
96. (B)
C
Lim
Thi
97. (C)
In z
sbideiua not tpo bormso, 21 gecenol
87. (D)
Most of the elements of these do not occur in nature but prepared in laboratory.
88. (B)
Lutetium (Lu) does not form oxocation, because
94. (A)
98. (A)
Ca0 combines with gangue to form molten slag of calcium silicate and calcium alumina
CaO+SiO,
CaSiO,
b ai mozools
+30O2
4CaA103
12Ca0+2Al,03
0
2
n
o
93. (B)
24Cr
e
shell, it can show oxidation states +1 to +ó.
sta
99. (B)
E.C
Transition
1. (0)
and Inner
transition Elements
noitenibnoo0.0
(231)
FeSO, +H, t
Fe+H,SO
(dilute)
92(B)
Melting point of Zn = 419.5°C =
692.5 K
84,B)22s 2p° 3s 3p°
equires
Cast iron
4s' 3d
contains 4.0 % carbon
eh
and it is hard and
9%(A)
g
with
Odinun
CaCO
1200 K
Limestone
HO
forms
2Ln03
.(B)
Tb4
M
T
H
(ATd) ostsibgoH(
29alqno lo 29qp
(0)coreiqmos oitgslormoli (A)
1
2
2925lqero9 oi geloosi (E)
Ln" ions; they form Ln2O3 when it burnt in oxygen.
4Ln+30
E.C. of 6sTb
b
u
o
D
of reduction the temperature is
around 900 K.
Fe,0, +3C0
2Fe +3CO,
Ln
o
) otobre (u
(reib) s3lobieT0
(aoi ateobsmeTo
zone
98.(A)
19)bneubono
(oto
occurs in zone of slag formation
HA
s
t
bottom.
Oftz
CaO +CO
Quick limme
97.(C)
In
s
e
obanibro
current of water
is gravity
concentration
current of water
method,
and heavier (ore)
particles collected where lighter particles washea
at the
in
96.(B)
This
arhoo boo/
brittle.
=[Xe] 4f 6s
= [Xe] 4f 6s
T
E
C
0
2
Y
PAB
Jatstn io 29dimor ofrmolAS.2rd
tmol os les vd 1201 enou alo he 290(g
vafotinobhenemsis toocied=y
s
:29NoRuu) ti egi90el
aoroaiosnote(A
OO0O0
soioroar mot6uns 0teemoatleusouie ()
ioat.aoiionib1002
0graco vloe)
yolgno0
(ne
d
ol
bpethrd
ert o1eborteesos os2tioro
bear
Ition lo aaro b
oel
ni anibno
Dood sonslaV ()
gnot00qD
geb
(i079/grnog sl
(A)
n
o
is
G
w
i
bre
3rono
2S)
9.
roe
Coordination Compounds
Important
.A
T
n
o
SP
Formulae and Shortcut Methods
consists ofa metal atom or 1on surroundedh
co-ordination compound or a complex
[Cu(NHs)4]SO,
by co-ordinate bonds, e.g.
molecules or anions called ligands bonded
Sp
is
s
e
Sp
or ion in the complex has primary valence.
According to Werner's theory, metal atom
s
t
sphere) and secondary valence (inner sphere).
The number of (monodentate) ligands directly bonded th
number (CN). A) 20
central metal atom or ion by co-ordination bonds is co-ordination
.Co-ordination number (CN):
b
b
u
Ligands:olod s
Monodentate ligands (Cr, OH, NH3, H;O, etc.)
i) Bidentate (en, c,of etc.)
ii)Tridentate (dien)
iv)Tetradentate (trien)
o
D
Os
ioiO
ormil
sotnol
(v) Hexadentate (EDTA)
1
2
000 bauoms s
Types of Complexes:
(A) Homoleptic complexes Ni(CO)4. [Co(NH,)«]Clh
0
2
Opl
Effective atomic number:
EAN Z-X+Y
Where,Z= Atomic number of metal.
X = Number of electrons lost by metal to form
Y= Number of electrons donated by ligands. the ion.
T
E
C
1.
MHT
0080,91
eno
2.
(A)
(A) 80
anrot nd
[Cu
3.
An
(A)
C)
5k
MHT
Isomerism in Complexes:
(A)Stereoisomerism
) Geometrical isomerism
4. Sel
(At
(A)
(B) Structural isomerism
MHT-
T
H
(ii) Optical isomerism
:()
lonisation isomerism
(ii) Linkage isomerism
(iii)Coordination
isomerism
(iv)Solvate isomerism
5. The
(A)
Bonding in Complexes
M
Wh
(A)
oqenes orh
toilouiber 30 sra
cmot ysdl
11
iii.
MHT
00Ss01Pu
00CI
(B) Heteroleptic complexes [Co(NH;).ClhH;0]CI
s
V.
gsle lo anos ai euooo 2d
O407
AP
)
Valence bond theory (VBT)
Valence bond theory (VBT):A
6.
i) Crystal field
theory (CFT)
of is
central metal ato
dsp, d'sp, etc. forming hybridised orbitals to accommodaundergoes
hybridisation
ligands.
from
(A)Inner complex: (n- 1) d orbitals of metal are
lik
used
(B) Outer complex: nd orbitals of metal are used.
C)
[Cr
(A)
C)
MHT
Whi
A)
MHT8. The
hybridizationn
Typesof
sphybridisation
hybridisatic
Sphybridisation
Sp hybridisation
dsp hybridisation
dsp
d'sp hybridisation
&'sp hybridisation
yunded
4]SO4 by neutral
y valence
y bonded
(outer
Geometry
Coordination
Linear
Triangular
Tetrahedral
Squareplanar
Trigonal
w
bipyramidal
Pentagonal
s
e
iv. In electroplating
Questions
b
u
MHT-CET 2006
Which ofthe following is diamagnetic in nature?
(A)Fe(CN)
(B)
NiCI
MHT-CET 2013
2.
(A) 8e
(C)Ni(CO)]
o
D
olqmo
[Cu(NHs)4J" shows which
of the following hybridisation?
A) dsp
(B)sp'd
(C) dsp
3.
s
t
er0 T30-T
Multiple Choice
(O)Te
is
bipyramidal
ii.
ideeW
n
o
Octahedral
Applicatio of the coordin
compounds
Biological importance
ii. In medicine
For estimation of hardness of water
to the
Compounds (233)
1
2
D)MnCl
erolo oilgnogoa loutE
(D)sp
ooh
moment of 1.73 BM will be shown by one among
the following.nun(
(A)[Cu(NH)4*
(B)[Ni(CN)J
ng add rrost dno(E0
(C)TiCl
ge nt pe(D)[CoCl]
oteog ort no1 vloe
MHT-CET 2014
(8).00
A
magnetic
0
2
Select the diamagnetic complex ion amongst the following complexes.
(At. No.: Fe =
26, Co =27)
(A)K,[Fe(CN)%]
(D)K[CoF6)
B)[Co(NH;),]Ch C)K[FeF]
T
E
C
MHT-CET
2015
ogomunoroldboneT (0
Ihe correct IUPAC
name of [Co(NH)s(NO:%]
Triamminetrinitrito-N-cobalt(I)
(A)Triamminetrinitrito-N-cobalt(1)
(B)
(D)Triamminetrinitrito-N-cobaltate(III)
C)Triamminecobalt(I)nitrite
T
H
6. CrNH
)] [Cr(SCN)6)
Ds] and
ofisomerism?
[Cr(NH;)2(SCN)4] [Cr{NH;)4(SCN);] are the examples of what type
A)lonisation
sp
sation like the
ctrons fom
M
(B) Linkage isomerism
isomerism
ordination isomerism ovso-Ho0D)Solvate isomerism
MHT-CET
2016
Which
ofthe following is a neutral complex?
(&)TPHNHS)Clh)
Ving isa
(C)[Ni(NHs)6]Ch
(B)[Co(NH:)%]Clh
MHT-CET
oio (8)
2017
ATect charge on and coord
2,4
(B)+3, 6
loib (C)
Vj
on number of 'Fe' in
(C)+2,6
opiirono(
D) K.[Fe(CN)6]
algosoidobouatsnib0
K[Fe(CN)6] is
(D)+3, 3
(234) MHT-CET
Exam Questions
to EAN rule?
complexes is an exception
coordinate
following
9. Which of
Zn = 30, Cu =29)
Pt = 78, Fe = 26,
(Given: At. No.
1o
22. 7
D)[Cu(NH,),
DCu(NH,).
()|Zn(NH;),J
(A)P(NH,),(B)Fe(CN),"
t
23.
[AuCl4]' ?
in the complex
gold
number
of
oxidation
10. What is the
(C)+2
(B)+3
(A)+4
in
11. What is the number of donor atoms
s
e
ootgg
(D)420/8
(C)3
is
D)+1
dimethylglyoximato ligand?
(B)2
(A)1
s
t
MHT-CET 2019
aques
precipitate on treatment with an uea
12. Which complex among the following gives a white
solution of barium chloride?
b
u
(B)[Co(NH,)sNO:;]SO4
(A)[Pt(NHs)%ClE]Br2
D)[CO(NH,),SO,]NO;
(C)[PNH,).Br,]Cl2
o
D
13. Which among the following is used in the treatment
of cancer?
(B) cis-[PtClL(NHs)2]
(A) trans-P(NH;);ClL]
(C) trans-[Pt(en);Clh]
0T
lot
od
-TE
1
2
T
E
C
ErOS T9O-THR
D)[Pt(NH)%Cl]
T
H
M
1s
26.
27
29
30.
Tup-R
36
o
17. IUPAC name of the complex Ba[CuCl4] is
GOOOJ(
(B) Tetrachlorobariumcuprate(l)
(A) Bariumtetrachlorocuprate(11)D
(C) Tetrachlorobariumcopper(11)
(D) Bariumtetrachlorocuprate(I)
Which among the following ligands
(A)Ammonia
C) Diethylene triamine
25.
28.
15. According to Werner's theory, the geometry of the complex is determined by
(A)number and position of the primary valences in space. er
(B) only from the primary valence in space.
C) only from the position of secondary valence in space.
(D)number and position of the secondary valences in space.
Aroc
16. The effective atomic number of Iron (Z- 26) in [Fe(CN)6]3 is
(B) 34
a soslod
(A)35
(C) 33
(D)
0
2
24.
todoit
(D)cis-[P(en);Cl,]
14. Which among the following is a neutral complex?
(A)[Ni(NH:)%]Ch
(B)[Fe(H,0)%]Cl)
CK[Ag(CN):]
18.
n
o
MH
MHT-CET 2018
A
TR
usca Tor the estimation
of hardness of water ?
(B) Ethylene diamine
(D)Ethylene diamine
19. What is the denticity of Ethylene diamine tetra-acetate
(B)2
(A)4
E)(C)1
tetra-acetate
ion?2
(D)6
(D)6
to
9rost
cetnol
20. The complex ions [Co(H;0)(ONO)and [Co(H,) NO,1+
nolbxoo
(B) geometrical
(A) linkage isomers
isomers
(D) ionization
(C) coordination isomers
isomers
[Pt(NH,);Cl.l
complex
coordinate
i
21. The IUPAC name of
diamminedichloroplatinum(11)
(B) dichlorodiammineplatinum(IV)
(A)
(D)dichlorodiammineplatinum(II)
(C) diamminedichloroplatinum(TV)
31
()
32.
33.
34.
s 1892
35.
number of Co (Z
27) in [CoNH:)61" Coordination Compounds(235)
B) 34
(A)27
is
(C)35
coordination number of Pt
ion in [Pt ChNH)h]
The
(D) 36
11,
(B)8
complex
(A)4
is
(C)2
effective atomic
HT-CET 2020
(D)6
folle
ng the following
Whi
coordination
hich among
24.
compounds
number of ligands?
does not have
to
(A)Co(NH)6**
hat is
(A)26
26.what
(B)[Cu(NH)AP*
effective atomic number
is
B)34
(C)[Co(en)»}"
of Fe in [Fe(CN)%1
(C) 36
(B)3
(C)1
(D)[PLNH,)
26)
(D)35
HO
s
t
(D)2
the type of hybridization and the
geometry respectively
found in [CoF6?
(A)sp'd' and octahedral
(B)d'sp and pentagonal bipyramidal
(C)dsp' and pentagonal bipyramidal
(D) dsp and trigonal bipyramidal
8 Which among the following is a correct formula
of Pentammineaquacobalt(11I iodide?
(A)[Co(H;OXNH;)]I
(B) [Co(NHs)s1JH,O
. What is
b
u
C[CoNH)s(H;O)]l
o
D
(D)[Co(H,O) (NH;):1]
9. Which of the following types of valences, according to Wermer's theory is also called as primary
valence?
(A)
(C)
30
Subsidiary valence
Auxiliary valence
1
2
2tAoS)(B)
0
2
Residual valence
(D)Ionisable valence
the formula of potassiumtrioxalatoaluminate(11I).
C)K4AI(Cz02)3](D)Al[Ks(C:04)]
B)[K,AI(C;04)»]
A)Ks[AI(CO.)»]
Identify
31. Which among
the
(A)KAg(CN)»]
following complexes is a homoleptic and cationic in nature?
D)[Fe(H;0),]Ch
(C)[C%Cl(en)a]C1
(B)[Fe(CO)%]
T
E
C
hexaminecobalt(11I)chloride?
from following is true for a complex
A)It is an anionic
complex
5 In this coordination number of cobalt is
this oxidation state of cobalt is +3
In
wollot not bauoo stabroeo
D) is a heteroleptic complex
zobo(i)lodop oni
láentify
[Cr(C;04»]
the Oxidation state of Cr in Ky
(D)+3
(A)oC
A)+5
(C)+6lsou
.Which statement 1
t
T
H
(B)+2
o
boo
heteroleptic and cationic
a
is
complexes
nong the following com
n(B)[Pt(NH;)Ch]
A)KAFe(CN)%)
(D)[Ni(CO)]
CCoNH,)4Cl]Cl
4.Which
M
in nature?
EAN rule?
does NOT obey
ion
metal
from following complexe
complexes, the central
Atomic
D[Fe(CN)o
Fe = 26)
number: Pt
= 29, Zn = 30, C[Cu(NH,)4*
Cu
78,
%.7hich
A)PNH)%
(B) [Zn(NH)4*"
n
o
is
equal
s
e
? (At. No. of Fe -
the value of primary valence of Co CoCli?
in
(A)4
coordination number
(236)MHT-CET Exam
Questions
[CoCl(en)»]?
L(
What is IUPAC name of
(I) ion
36. (A)Bis(ethylenediammine)dichlorocobalt
cobalt () dichloride0
(B) Ethylene diamine
cobalt chloride
(C) Ethylene diamine
ehtylenediamine cobalt (1)
(D) Dichloro
K3[Fe(CN)6]?
number of Fe in
oxidation
is
the
What
37.
+3
(B) +6
bosaT
y100d
iodt(D)-3to
roo e(C)
R Te(A)-6
geometry respectively in Cuproamm.
nium
and
behavior
magnetic
38. What is the type of
(Atomic number of Cu = 29)?
square planar
B) Paramagnetic and tetrahedral
(A)Paramagnetic and
(D) Diamagnetic and tetrahedral
(C) Diamagnetic and pyramidal
n
o
sl
splitting power
*39. Which ligand among the following has highest
(C) CO
(B) OH
(A) NCS
is
s
e
of d-orbitals of central.metal
(D)
s
t
s
40. How many water molecules are hydrogen bonded in following molecular formula
Cu(H,0), so
H,0?nste' (
A)
(B)4
5
ab )
b
Lenbodetoo bus
(C)
b
u
3 mecgcd tonogi
(D)
1
b'a
bo
41. Which among the following is a correct formula of Bariumtetrachlorocuprate(11)?
(A) Ba[CuClL]
(B) Cu[BaCl]
(C) Ba[CuCL]Clh(D) Cu[BaCIkjC
42. What is oxidation number of Ru in
ag
(A)+2
o
D
Ru (NH,), H,o Cl?
(B)+5
(D) +6oaW.e
(C)+1
43. What is the effective atomic number of Zn in
(A) 27
(B) 36
1
2
[Zn(NH3)4]SO4?sor
eibiede2
(C) 30
ooms (D) 28
44. Identify the tetradentate ligand from
the following.
(A) Triethylene tetramine
(B) Ethylene diamine tetracetato
(C) Dimethyl glyoximato
0
2
D) Oxalato
45. What is the number of =N-OH
groups present in dimethyl
glyoximato?
(A)1
(B)4
T
E
C
46. What is the secondary valence
(A)4
AA
moP)2
of Co" ion according to Werner's
Ch?
theory in [Co(NH;]4u
none (D)5
(C)6dout
47. Which coordinate compound
from
following
(A)Tris(ethylenediammine)cobalt([III)chloridehas a net negative
charge on complex n?
(B) Diamminesilver(I)chloride
C) Potassiumtrioxalatoaluminate(III)
(D)Tetracarbonyinickel(o)
2(
onqoloseron
ar
48. What is the oxidation
s
toxolono9
state and coordination
srivvollotodi
(A)+6 and6
gt
number of platinum
(B)+4 and 4
respectively in P:NHs
49. Which among the
C)+6 and 4
following is an
(D)+4 and6
ambidentate
T
H
M
(B) 3
3
(A)H0
u
(B) NH,
ligand?looou agnwolol
oo
19
(C) COo(D)
COO
NO
ldenti
0 (A)Six
What
51.
(A)6
-T3114
number ofd
f donorgroupspresent
Coordination
(B) Three
inEDTA.
Compounds
(237)
(C)Two
3o
tal number ofligandspresent
in [CoClH(NH:).]CI (D)Four
(B)2
ose eog
C)4
1g the following
Which
is a monodentate
(D)1 biT(A
ligand?do(B) Water
(A) Oxalato
of O obalt in [Co(NHs)%]Cl, (C)Ethylenediamine
What is EAN
(D)Dimethylglyoximato
(At. No. of
(B)
Co
(A)
52.
ium sulphate
27)?
(C)27
many donor groups are
54. How
present in diethylene
triamine?2
(B)4
(A)6
al metal ion?
c
28
36
s
t
b
u
st
10 2nttaligasog H0.l00D dbocs
odge
9
effective notEbo
magnetic moment
57. Identify the increasing order of
Oxidation state.
Co
Fe (Z 26),
o
D
:(AT
of following elements in their
(Z = 27), Ni (Z = 28), Cu (Z= 29) oiome
bas2mot 10 S(0)
(A) Co< Cu < Fe < Ni
(B) Cu < Ni < Co< Fe
(C) Cu< Co < Fe < Ni
(D) Fe < Co< Ni< Cu 9inoias
58. What is systematic
name of [Cr(en)3]Clh?
(A) Ethylenediamminetrichlorochromate
T19189 ug 10SulbY Sdl ett
B) Tri(ethylenediammine)chromium(II)chloride
C)
A
C) Tris(ethylenediammine)chromium(II)chlorideote
990nin
1o
(D) Ethylenediamminechromium(II)chloride
edun sai
1
2
0
2
T
E
C
dentify
M
T
tedEt
or vitrsbAT
oine)t4dorurd(A
it's quantity obtained when
1
mole
of aqueous solution of
etramminedichloroplatinum([V)bromide is treated with aqueous silver nitrate in excess.
(A) Two moles
of silver chloride
(0)
5) Two moles of silver bromide
nibnocs dotd W.ar
bromide
of silver chloride and one mole of silver
DOnoles
D One mole of silver bromide
complex?oime sid Tr
Which
among the following complexes
is NOT a heteroleptic
c
(B)[Co(NH;)%]Clh
(A) [Pt(NH)aBr2]Br2
(e)
JD0}
Oeuojo9O
C)[Co(en):Clh]
D) [Co(en);Clh]C
T
H
H)6]"?
(B)+2iT (4)(C)
the precipitate and
2:(60niI)
(NH:)%]" respectively?
is c0ordination number of Pt in [PtClkNH);] and [Pt
(D) 4 and 4
numbe
(A) 2
and 6
and 4
(B) 2 and 2
er fatW.er
3. Which
9dt
complex?o
aluminate
among the following compounds is cationic
Lithium hydrido
A) Sodiu
(B)
nitrate 0
Diammine silver ()
C) Sodiumthexanitro cobaltate (I)
D.What
)(C)4
()ia
tetrachloroo zincate (II)D
()D)
+ 2
iobl.It
.What is oxidation state of iron in potassium hexacyano ferrate (1)2
(A) +3
*6
a?
ta
tofltod D)2
among the following
oidW28
complexes carries
not net charge?
(A) [Pt(NH)%Ch]
(B) [Fe(H0)]Clh
(C) K:[Hgl4]
(D) Ni(NH),]Ch
1dentify the coordinate complex
having ambidentate ligand
(A) Tetraaquadichlorochromium(I)chloride
from following.ove
Bariumtetrachlorocuprate(II)D
000A)
C) Sodiumhexanitrito-N-cobaltate(III)
noo nemsta geiio.
to doid W.0r
D)Diamminesilver(OChloride
h
t
Chl7
is
s
e
(C)3
(B)
Jch
pbi
(D) 30
n
o
(238)MHT-CET Exam
Questions
dimethyl
ligand dimethyl olua.
glyoximato ?
in theligand
attachment are present
(D) 4
of
points
)3
64. How many
(B)1
(A) 2
diethylenetriamine is ?
(D)Bidentate
ligand
What
type
(C) Hexadentate
of
65.
(B) Tetradentate
(A) Tridentate
67. Identify cationic complex from following.
(B) K4[Fe(CN)%]
(A) K:[H,la]
(C)[Ni(CO
is
d
(D) [Ni(NH,)ajCI
s
e
central
*68.Which ligand among the following has lowest splitting power of d-orbitals of
(D) EDTA
(C)T
(B) SCN
(A) H:0
s
t
69. According to Werner's theory based on experiment the formula of coordination
CoCly 3NH then the molar conductance in mho mol and number of CI ions Dree
AgNO respectively is
(A)0,0
(B)0,2
b
u
(C)102,0
(D)102,
1
70. Which of the following statements is correct according to
Werners theory, when excessAgNG
is treated with CoCl.6NH, precipitating three moles
Ao
of AgC1?
(A)5 NH3 and 1 Cl atom are in coordination sphere
(B)3 'Cl' atoms are in ionization sphere
(C)2 Cl atoms and 4 NH; molecules are
in coordination sphere
(D)2'Cl' atoms are in coordination sphere
71. Identify anionic complex
from following.
(A) Pt(NH;)>Ch]
(B) K[Ag(CN};]|
C)[Co(NH)«]Cl
(D) [Ni(CO)
72. What is the value
of primary
(A) 3
1
2
o
D
valence of copper chloride
according to Werner's theory?
(C)4
(D)1
73. What is the number
of nitrogen atoms
and-CO0
(A)3,2
groups respectively present
(B)2,2
so
0
2
(B)2
in EDTAT
(C)2,4
74. Identify monodentate
ligand from following.
(A)Dimethylglyoximato
T
E
C
C)Diethylenetriamine
75. What is the oxidation
(A)+2
T
H
the following
(A)[PH(NH)hClh]
(C[Co(en)0NO,);
M
78. What is oxidation
(A)+2(
is NOT an
state of iron
(A
(C
82 WI
(A
(C
83. WI
(A
(B
(C
D
84. Ho
(A
85. WI
(A
(B
(C
(D
86. W
(A
1. (C)
29
Cu
(D)Ammonia
metal atom
(A1
2. (A)
(B) Ethylenediamine
number of central
(B)+6
(D)4,4
in [Cr(NH:)6]0NOs)s? af
(D) +3
G
76. Which coordinate
(C)+4
complex from
(A) Ka[H,l4]
following
has a complex
(B) K4[Fe(CN)%]
17. Which among
n
o
81. W
whena
(D)
()
(A
metals have slightly higher.energy
d-orbitals of transition
66.Which from following
?
metal ion forms at compound
(C) dyz
dax
(B)
(A) dy
WE
80.
ion
C)[Pi(NHS)hCh]with postive charge
octahedral
(D) [Ni(NH;)61C
complex?
(B)[CoCl2(en)al
(D)[r(C0,)hClh}
3. (A)
May
in potassium
(B)+4
ferrate?
number
(C)+3
of moles
nitrate is treated
of
silver
with
D)+6
[Co(NH,)4Ch]Cl? chloride
(A)4.0 mole
precipitated
(B)3.0 mole
excess
when
Cn exces5
79.What is the
e
(C)1.0 mole
of
(D)2.0 mole
aqueou
Sihe
Thu
1.73
In
isomerism is p resent between
Coordination Compounds
(239)
0[CrHO).ICl3 and (i) [Cr(H;O);CIJCL.H,0?
(A)Coordination
(B)Linkage
(C)lonisation
geometry
(D)Hydrate
and
af
magnetic
What type of
behaviour is found
= 28)
Ni
in
No. of
compound [NiCu}°?
(At
A)Tetrahedral and paramagnetic
(B) Square planar
O Pyramidal and diamagnetic
and paramagnetic
what
hen a
free
(D)Square planar
and paramagnetic
systematic name of [Co(NH).Cl,]C1?
hat
82
(A) Teraammoniumcobaltchloride
(B)Tetramninedichlorocobalt(II)chloride
C) Tetraamninecobalt(Wchloride
(D)Dichlorotetraamminecobalt(II)
chloride
Which among the following pair of compounds
is
an
example
of linkage isomerism?
A) Co(NHs)sNO2]SO4 and [Co(NHs)%SO,]NO;
.
al ion?
pound is
itatedby
and [Cr(H,0):CI]ChH,0
CrHO),]Clh
O
D)Co(NHs)sSO,]Br and [Co(NH,)sBr|So
u
many donor
How
AgNO
(A) Two
s
e
s
t
B) Co(NH)sNO:]Cl; and [Co(NH,)ONOJC;k
o0)ho omun
b
u
groups are present in dimethyl glyoximato ?
(B) Four
(C)Three
D) One
following
is
the
of
a
property
K.Which
of coordination compound and not of double salt?
(A) Aqueous solution of these gives the tests of all constituent ions
B)These show entirely different properties from their constituent ions.
(C)These dissociate into their constituent ions when dissolved in water.
These lose their identity in aqueous solution.
(D)
86.
What is
(B) 36
(A) 35
(C)
A)
sCu
Cu
1
2
the effective atomic number
T
E
C
[Ar] 3d4s
[Ar] 3d'
o
D
of Cu in [Cu(NH:)4]* ? (At. No. of Cu 29)
0
2
(C) 29
(D) 34
SOLUTIONS
3d
Ground state
T
H
3.
S
M
silver
NHs NH NH NHs
ds-nyortdisation
(A)
Magnet
moment,
unpaired
related with number of
iS
n(n+2) BM
(n +2). On solving, n=
.73=n
the complex/com
1.73
1
uNH
1
Cu-[Ar] 3d
11
2olgnoo al
Spfkoe05ta magnetic moment of
exhibits
unpaired electron
one
having
ompound
BM.
In
electrons as
n
o
is
is
(240)MHT-CET Exam
Questions
unpaired electron
4. (B)
having
Coordination compound/ion
diamagnetic.
paired, it is
all the electrons
1on
[Co(NH)%]
Cl,
27Co
Co
i.e.
1s
paramagnetic in
n sture while
it
[Co(NH:),]
[Ar] 3d 4s
[Ar) 3d° 4s
n
o
3d
is
abirolio1egittogbm
sbioldoiedocounoou
Therefore, [Co(NH:)%] Cly is diamagnetic in
natureobn
s
t
o9 bas
5. (A)
s
e
s02
UPAC name of [Co(NH,)hNO;)»] is Triammine trinitrito-N-cobalt (II)
6. (C)
In coordination isomerism same ligand
b
u
attached to different metal
7 (A)
ion
in coordination sphe
Neutral complex is the co-ordination compound with no
charge. Hence option (A) is corec
= neutral
or 0 charge and Cl, i.e., [Pt (NH3)2
auo9tp
o
D
Pt (1), NH,
8. (B)
K,[Fe(CN).J=[Fe(CN).J
ottiioe a0p
X+6-1)=-3
X= +3
Coordination number of Fe is
6 as 6 CN are attached.
9. (D)
For [Cu(NH).*, EAN
29 2+(2x 4)JJ0235
10. (B)
1
2
[AuCL
X+4(-1)-1
T
E
C
11. (B)
HO
T
Ho
Cl2]toisioz
1913
ni
0
2
X=+3
2
otnt osi00eatb s2sd13
iofsseoloesdT C
goobi
ABE A)-10
OH
Bidentate Ligand
HC
28
12. (B)
M
In complex [Co(NH3)SNO;JSO4,
BaClh it will
SO, ions are in
give white ppt.
ionization
of BaSOA
co(NH3) NO2
sphere. Therefore o
nepp
JS04 +BaCh
30
-co(NH,)5NO,
13. (B)
B00
14. (D)
The complexes
29
Treactionw
jcl+
BaSo
GteitbnuoWhite
ppt
Ppt
which carry
n0 net
charge are
called as
neutral complexes.
l up
Ma ST
31
ture while
Coordination Compounds
I5(D)
if it has
(A)
16.
Z-Complex
[Fe (CN)%]3
X-6=-3
o.N. of Fe
X=+3
35
is
17(4)
IUPACname of Ba [CuCl is bariumtetrachlorocuprate(11).
19. (D)
I& (D)
20. (A)
21. (A)
22. (D)
. (C)
Ethvlenediamine (en) is bidentate ligand.
Co(en)] No. ofligands= 3,
Coordination
EAN
A) is corect
2, Y = 12
s
e
23.(A)
s
t
number = 6
2%(C)
Z-26, X =
n
o
=
Z- X+Y 26-3 +12
AN
nation sphere.
(241)
Atomic number = 26
b
u
Z-X+ Y 26-2+12 36
=
OgH.02hfiuo-o1ariqluz muitoteno
26.(B)
Primary valence=
Oxidation state of Co = +3.
27.(A)
Formation of [CoFs1
o
D
of sp d hybridisation . An octahedral complex shows paramagnetic
behaviour.
It utilizes outer 4d orbital in
sp'd' hybridisation. It is therefore called outer orbital or high spin
or spin free complex.
It is
an example
Orbitals
of Co ion
1
2
0
2
Since F is weak ligand, there is no spin pairing effect and Co possesses 4 unpaired
electrons.
Co" undergoing sp d hybridisation
T
E
C
CoF
(Outer orbital
N
1 |Ta
sporbital
spld hybrid orbitals
of electrons from six P ions
or High spin complex)
six pairs
28.(C)
T
H
(A
with
n reaction
M
L0
of Co is +3. Hence correct
and aqua (H;O) are neutral ligands. Oxidation state
is (Co(NH;)5 (H20)]l3
sulay 39gs Van abasg1 geoele
zbsgil ioow 1o sas3 m baa s lo
30 Bo abnsgrt zomeoo
eorosb ziort to 1obro 3dt f cor9e ni bogee
eeollot
NHs)
formula
29.0
D)
30.(A)
Bidentate ligand, Oxidation state of Al +3
31(D)
3 Formula is K3[AI(C,04)3]
ARH<4 snoO09
,C1,=[Fe(H,0).J"
ligand, H20.
i i. Omoleptic
Fe is linked to only one type of
ion.
+3CT
-
tionic
Complex- due to positive charge on
complex
() 0
(242) MHT-CET Exam Questions
32. (C)
[Co(NH)6]Cl >Hexamminecobalt (III) chloride
It is an cationic complex.
Coordination number of Co
It is a homoleptic complex.
33. (D)
Oxalate
6, Oxidation state of Co =
oM.O
s
e
3)+Cr+ (-2x 3) = 0
3+Cr-6 =0
'
x
Cr
34. (C)
[Co(NH).Clh]Cl
=
+3
[Cu(NH)4]>EAN
=Z-X+Y
=
b
u
29 -2+8 =35
37. (C)
38. (A)
Cuproammonium sulphate
o
D
[Cu(NH3)4]S04. H20
[Cu(NH)4]*">Oxidation state of
Cu
= +2
3d
Cu(Z 29)
s
t
[Co(NH,), CL,I +CI
35. (C)
36. (A)
is
C,0
K [Cr(CO)] >(1
-4 21
0
4p
n
o
+3
(O12
Y+SAS
iTsbix0
1
T
H
T
E
C
2
4dsp'hybrid orbitals
3d
4p
4 electron pairs
from 4NH
dsp-Square planar, Paramagnetic- One unpaired
M
to latidnoro3)
electron.
39. (C)
Strong ligands have larger vaue
or ag
aluoto
igands can be arranged in a and case of weak ligands Ao
Series in the order
values are smaller. 1
of their decreasing
follows.
field strength, *
cO>CN> en>NH> EDTA>NCS>H0> C05
n
>OH>F>s*>ar>
40. (D)
Four water molecules are coordinated with Cu and one
is hydrogen
41. (A)
SCN> Br >I
bonded with SO
Coordination Compounds
H,O are neutral molecules.
and
NH
(243).
Oxidation number of Ru= +2
=30 -2+8
EAN=
36
n
o
44.(A)
(D)
OH
HO
dimethyl glyoximato
s
t
N- OH groups - 2)
The number of=
(C)
- Coordination number
Secondary valence
b
u
6
47.(C)
3K° +[AI(C,O,)P-
K,[AIC,0,),1
D)
PuNHs)6
Oxidation state of Pt= +4
i.
o
D
ii. Coordination number of Pt ==6
(D)
NO,
group has two donor atoms (N and O). Out of the two only one donor atom is linked to the
(A)
EDTA is
0
2
[COC%(NH)4]CI
linked to 4 NH3 molecules and 2
T
E
C
Total
52.(B)
Water is
53.(A)
T
H
M
S4.(C)
0erom aitsreur lo toiro
gate serant
O182
CI ions in coordination sphere.
number of ligands =6
to ot
potebo0
bidentate ligands.
a monodentate 1ligand while others are
EANof CoZ-X+Y
trength,
eiu)
hexadentate ligand.
51.(A)
aller. The
as
1
2
M-ONO or M-NO2.
metal as
Co is
is
s
e
H,C-C-C-CH,
ÇH,
12= 36
27-3+
gg
eu
lro sof
Xolqmoo golomoh
/10
-CH
Diethylen
dien)
donor groups)
bns
eiiO)
nt 10todatun O
9
MHT-CET Exam
(244)
Questions
55. (A)
Net charge:
(A) [Pt (NH:);Clh]
(B) [Fe(H;0)%*
+2
+
1(-2)=0lon loo
63. (D
So
Net charge: +3
Net charge:-2
Net charge: +2
()[HL]
[Ni(NH,)%1
(D)
Li
D
atom can be
ligand where the donor
-NO2 group is ambidentate
: Na;[Co(NO;)%]
sodiumhexanitro-N-cobaltate (III)
present in
56. (C)
N
ana
64. (A
is
57. (B)
3d
4s
Fe
n4
s
e
n+2)
4.89
4(4+2)
Vn
3d
Co4
n=3
-3(3+2)
n=1
H I1+2)
TG091A12
3d' ano
=
,0.0A
o
D
o Gise mitubixo
= 2.82
-22+2)
s
t
66.
bes ) anois 1onob owt 2at quorg
0
O-M10 OM0-M antee
1
2
1.73
A
Increasing order of magnetic moment:
Cu< Ni < Co< Fe nagil ottnabaoda ATd
58. (C)
(A
[Cr(en)]Ch: Tris (ethylene diammine) chromium
(III) chloride.
1OM
59. (B)
Potassium hexacyano ferrate
(II): KA[Fe(CN)%]
Oxidation state of iron = +2
ebnssil to tonu luto
60. (B)
alsdn sbrd ow
2g
2150 oiafw besgil sresnobonon el
[Pt(NH3)4Ci,] + AgNO,
Br
2AgBr+[Pt(NH,),
T
E
C
Tetrammine dichloro
Platinum (IV) bromide
T
H
61. (B)
65.
noitebop3009107 pabooos
b
u
3.87
3d
Ni4s
n -2
tor Cu>4s
Jua
n
o
0
2
67.(
0
8
68.
Cl21*
69.
Heteroleptic complex :
Complex with metal
species having more than one
Homoleptic complex
tyPe
as it has only
All other complexes are
one
type
heteroleptic in
of ligand.
nature.
62 (C)
Both Cl and NH3 are
unidentate ligands.
The coordination number
of Pt in [PtCh(NH)a]
= 4 and
in [Pt
[PLNH,).* =6.
[Co(NHs)%1Clh-
M
.
70.
71.
(D)
hexanitro cobaltate (III):
Coordination
Na,[Co(NO)%]Compounds (245)
hydrido aluminate (
: LiAIH4Anionic
AnionicComplexComplex
Sadium tetrachloro zincate (1I) Na2[ZnClu]
lver
nitrate
()
: [Ag(NH32JNO,- Anionic
Diammine
Complex
rele rua fo 10dme-Cationic Complex
64.(4)
evo
odium
N
It is
is
H,C-C-C-CH,
dimethyl
s
e
glyoximato
donor atoms per each ligand.
Tvo
(ATG)
(4)
H
Boyle's Law
6.(D)
While
000-t0d
b
u
NH,
dy, dyz,
s
t
triamine- dien is a tridentate ligand.
Diethyl
dx have same energy
d2
1
2
have lightly higher energy.
67.(D)
0
2
o
D
brte
[Fe(CN)%61*-Anionic Complex
beganelo vovingon
Neutral ldton aioHA S C3)
()NiCO)-
=
T
E
C
DNi(NH)6]Clh = [Ni(NH)6** = Cationic Complex.
6.(C)
Ker
nas
T
H
ote
10 9guur
(Cat
ai
noi
zatesoc
2rafqsoo
isnborliro0
d-orbitals of central metal ion.
strength, lower will be its splitting power of
lowest splitting power ofd-orbitals of central metal ion.
the ligand
69.(A)
elsobonoM
0
(A)KaHg L)= [Hgluj - Anionic Complex
B)KFe(CN)6)
n
o
2
OH
HO
ONO).
primary as well as
chloride ions satisty
to Werner's
theory, in CoCl3.3NH3, three
s
Therefore compound behaves as
secon
CI will be precipitated.
Therefore,
no
valency.
According
neutral
T0.B)
M .)
non-conductive molecule.
Atoms
Ap
ng
sphere.
precipitated
can be
primary valency and
satisfy
sphere
are in ionization
are present in ionization
all three Cl atoms
precipitated,
are
Dince three moles of AgCl
lsmool lnbstalo0
Since
counter
a)1s
positively
be negatively
charged, complex will
charged.
(246) MHT-CET Exam
Questionss
72. (D)
78. (D)
Potas
Copper chloride - CuCI
n
o
.
primar
O.S. of Cu = +1
oxidation number of an element is the
According to Werner's theory
is
73. (C)
HOOC-CHj-CH, -CH,
-N
HOOC-CH,
CH, -C0OH
s
e
CH, -COOH
s
t
Ethylenediamminetetraacetic acid
(EDTA)
b
u
Number of nitrogen atoms= 2
Number of-CO0 groups = 4
74.(D)
H-N
1
2
Monodentate ligand
75. (D)
[Cr(NHs)6]ONO;)»
Charge of NH =0,
Charge of NO, = -1
76. (D)
T
E
C
0
2
Since, counter ion is negatively charged
o
D
M
eletig
Sin
Ag
80. (D)
[Cr
In
sph
t
Ox
Orl
As
On
ort
(CI) & NH3 is neutral, the complex is positivelyu
hy
Ni
Ea
cO
1302ige19ol
Central Metal
lon
L
Ligands
Octahedral Geometry
[Co
81. (A)
Fo
77. (A)
Octahedral complexes are formed
with coordination
number 6.
The coordination of Pt in [Pt[NH3)>Clh]
is 4.
T
H
79. (C)
3o lo ss
p
82.(B)
Ox
(D)
is
78.(
Potass n ferrate K2FeO4,
2K
dation state
of Fe is +6.
Compounds (247)2
K-O
OR
0
Coordination
i
Structure
O-K
T9.(C)
1:).ClL]Cl=
Co(NH)
[Co(NH,),CLI +CIr
one CI
I is in the ionization
Since only
sphere only one
mole
AgNO.
D)
Cr[H:O)%]Cl3
and
s
e
of AgCl precipitated with
s
t
[Cr(H;0),CI]Ch. HO
excess of
(II)
structure
()
above
and (11) number of water
molecule in and outside
are different so it 18 an example of
the coordination
re
sphe
hydrate isomerism.
biduob sonie
b
u
Jot ob rsoeraoopotsbeo
81.(A)
Formation of [NICI
is an example
oxidation state.
t
Orbitals of
As
Cr
ot
Ni ion
4s and three
orbitals
undergoingg
hybridisation
NICL
1
2
Nickel is in +2
3d
a weak ligand, 2 unpaired electrons in Ni remain undisturtbed.
is
One
harged.
o
D
sp hybricdisaton and has tetrahedral geometry.
sp
orbitals of N
high spin complex
T
E
C
0
2
d
sp
hybrid orbitals
Four pairs of electrons from
4C
donates a pair of electrons. The compound is paramagnetio since
0ontains two unpaired
electrons.
1on
M
T
H
Structure of [NICIJ
.B)
state of Co is given by -
0.S.of Co
Name
[Co(NH3)4C12]' C1
2x CI)]
NH) + (O.S. of
1- [(O. S. of 4x+2-+3
=1-[0-2] 1
Tetramninedichlorocobalt(1)chloride
it
n
o
is
of potassium ferrate
t
N
eeeee
n
o
(AS(248) MHT-CET Exam Questions
is
83. (B)
(Co(NH)SNO,JCl; and [Co(NH),ONOJCL
In structure (1) ligand NO, is linked through 'N' whereas in
through 0' atom, so it represents the linkage isomer.
84.(A)
a
It is bidentate ligand.
HO
muteapog to
outoie
dimethyl glyoximato
1
2
s
t
b
u
OH
H.C-c-C-CH
s
e
structure (11), NO; ligand
o
D
hDiD(OF)1O
is bond.
onded
(O)e
()08
brus.1OOHh91
85. (B)
(
These show entirely different properties from their constituent
svods odt nl
Since double salt is when dissolved in water, it dissociates into its constituent ions whereas
coordination compounds do not.
86. (A)
EAN
T
E
C
=Z-X+Y
0
2
29-2+(2 x4)
27+8 35
M
T
H
ions.te
(A) 18
aloj
to nobamo
stele nofabaxo
enotoels bsvsora brisgt ew
sel0
s91
bes
86ieoob
o
A
ero
iogrobru elslictho
Mo aeido noitseibvo
altidso tud
eesg ebogo
9Gcoe
fo
10 oe3
10. Halogen Derivatives
ImportantFormulae
and Shortcut Methods
bonded
lerivatives are the organic
Halogen deriv
compounds obtained
by replacing one or more
hydrocarbonsby halogen atoms
H atoms of
the
ing
number
According to
to the
ofhalogen atoms they are
classified as:
Monohalogen derivatives
R-X e.g.
CHBr
Dihalogen derivatives
Trihalogen derivatives
CHCl
Tetrahalogen derivative
CCl
gosto
CHCl, CHI
Monohalogen derivatives are classified as
halides (may be primary, secondary, tertiary)
Allylic halides
Benzylic halide
Vinylic
Haloalkyne
.Aryl halides
whereas
Preparation of alkyl halides:
1. From alkenes:
-
+HX
s
slor a
Alkene
1
2
Alkyl halide
halides
b
u
o
D
s
e
s
t
.Alkyl
oalog
is
anc
(Addition of HX takes place according to Markownikoff's Rule in Unsymmetrical alkenes)
Kharasch (peroxide) effect:
CH3-CH= CH2
+HBr
T
E
C
R-OH+PCl5
1edue evro2 ip9ug0 5
BenzoyiCH,-CH2-CHBr-0123/30 af oB
Peroxide
301 rd botob
2. From alcohols:
3R-OH+PCl
0
2
zde eoratororasl Bina esoalo-oze
3R
-Cl+H,PO3
ban
otoowssl aj ebie
iote oaA
tio wol ol beriosi
seatos
t2u 031tde
>R-Cl+POCl3 + HClvan n9val
K-OH +SOCI, AR-CI+HCIt +so,
tDR0a 9sudozol
Thionyl
T
H
chloride
H+HCInyrousR-CI+H,O 20
R-OH+HBr- NaBr/H,SO4R-Br+H0
M
R-OH +HI HPO4>R-I+H,0
Nal
ba
eu
etedt ajuos itg
n
o
NE
Halo
Reactionsof Subs
Nucleophilic
Alky
(250) MHT-CET Exam Questions
3. Halogen exchange
i.
1.
Finkelstein reaction
R-X
+Nal
acetome
Alkyl halide
R-I
AIkyl iodide
(Where, R-X>R-CI, Rii.
Swartz reaction
such as AgF, HgaF2,
with metal fluorides
R-F+AgCI
is
s
e
eeviveb rogolait
s
t
(Electrophilic substitution)
X
hch nogoiedoso
b
u
X
Fe/ dark
:
o
D
1
2
0
2
e (ofitoop dozedz light on
the plane of a plane polarized
Dextro-rotatory and laevorotatory substances
Sn2 Reac
Alkaline
CH
This is a
R=
Hence it
Asymmetric carbon atom:
and opua
is an asymmetric carbon atom
groups
different
four
to
attached
A carbon atom
asymmetric carbon atom.
active substance must have an
e.g.2-Chlorobutane or lactic acid
M
6.
nght
which rotates
which rotates on len
The optically active substance
d or (+) and the substance
by
denoted
and
dextro-rotatory
hand side is
denoted by I or (-.
hand side is laevorotatory and
T
H
R
5
8.
Optical activity:
an optically active
a plane polarized light by
of
plane
rotating
a
The phenomenon of
substance is optical activity.
ast XH lo othbb)
Optical isomerism:
R-
7.
transmitted light has
a Nicol prism, the
through
passed
when
A monochromatic light
plane polarized light.
vibrations only in one plane giving a
T
E
C
R-
3.
ebiisd otvilA
a olsois
Activity:
Plane polarized light
n
o
2
Br)
or broe
heating alkyl chorides oromides
by
prepared
Alkyl fluorides are AsF3, SbF3, etc.
Preparation of haloarenes
R-X
R-3
+NaX
R-Cl+AgF
Optical
Sr.
:
No.
2180-4
This in
which d
SN2 Me
Rate o
Second
The ra
activity
having same molecular formula but different opticalo
The optical active substances
are optical isomers or enantiomers.
e.g. d and / lactic acids.
Uxturedue0
Racemic form:
nu
is a racemic
A mixture containing equimolar amount of two optical isomers
external compensation, denoted by (dl) or (£)
HO
SNl
Alka
Haloalkanes:
Halogen Derivatives (251)
Reactions of
eophilic Substitution reactions of
alkyl halides
Sr.No.
Alylhaltde
Rengent
R-X
otbromide
Substitution produet
NaOH(aq)-A
(or KOH)
NaOR'
R-X
R-0-R'+NoX
(sodium alkoxide)
R-X
R8Ag
R-C-OR
NH (alo.)
(ester)
KCN
Ag-0-N=
NH,
R-NaC
s
t
RX
+AgX
(isocyanide)
b
u
R-0-N=O
(alkyl nitrite)
-
0-
(silver nitrite)
.SN2Reaction:
1
2
o
D
s
e
HX
(nitrile Xalkyl cyanide)
potassiunm nitrito)
R-X
ha
(ale.)-A
KO-N=O
R-X
Agx
+
primary amine)
R-CN
AgCN (alo.) A
R-X
d light
R
(excess)
R-X
is
(ether)
(silver corboxylate)
R-X
KX
+AgX
(nitroalkane)
Alkaline hydrolysis of CH3Br is a Nucleophilic Substitution (SN) reaction.
CH,Br+OHCH,OH+Br
cally active
0
2
Hence it is represented as Sy2.
tht on ngh
This involves back side attack of a nucleophile on carbon atom forming a transition state
which decomposes giving CH3OH with 100% inversion.
lates on let
T
E
C
S2 Mechanism)roamimo
a
olsnsgoiato sbyitsG
This is a bimolecular second order reaction. For this rate determining step, by rate law,
R=K [CHBr] x [OH]
opticaly
-ngerinils4bofkes ar oidseer etu
(okuz hoxtge
Rate oc [Reactant] [Nu]
Second order reaction
T
H
actv
1cal
H
M
Sw1
>2° >3°
Sy2 path is CH3X
Br
-
Ho-CB
H
HO
due
Kure
o
aistos 2viaa rive noitoant
Therate of hydrolysis of alkyl halides by
Transition state
Reaction:
AIne
n
o
R- OH + NaX
(alcohol)
rKX)
Nucleophilic
hydrolysis of (CH3);C-Br is a
Walden Inversion
Substitution (SN) reaction.
(252)MHT-CET Exam Questions
It takes place in two steps.
slow
(CH,), C-Br=(CH,),
(CH),C*+OH
Step I
C* +Br
(CH3), C-OH
Step II
rate determining step. He the
fission is slow, it is a
heterolytic
Since the first step of
first order reaction.
reaction is unimolecular and
inversion as well as retaininethe
are formed by
OH
(CH3):C
The product molecules of inversion and forming a racemic mixture.
original structure giving 50%
Rate o [RCX]
First order Reaction
alkyl
The rate of hydrolysis of
halides by Syl
s
t
3°>2°>1°> CHx
path is Allyl, Benzyl >
b
u
Me
Me
Me-C-Br
Me-C +Br
(1)
Slow
Me
Me
OH
Me-c
(e)
Me
o
D
M-0-p
Me
UMe
FstMe--OH.
nouMe
(i)
1
2
Elimination reaction: Dehydrohalogenation
2.
alc.KOH
A
T
E
C
Alkyl halide
o
This reaction is called
to Saytzeff rule)
T
H
B
-
-20
arolis
180991
HO8eHDI29
+KX + H,O
Alkene
elimination or
1,
2- elimination. (Elimination takes place accor
3. Reaction with active metals
i.
M
Reaction with magnesium
+ Mg
R-X
Alkyl halide
R-Mg-X
Alkyl magnesium halide
(Grignard reagent)
ii. Wurtz reaction
2R-X +2Nay
Allkyl halide
is
s
e
Snl Mechanism
n
o
R-R+2NaX
Allkane
hoitos
etaolol
of
Reaction
1.
a.
Haloarenee.
Halogen Derivatives (253)
tions of haloarenes with
metals:
Wurtz-Fittig reaction
x
2Na +
X-Rdether
Alkyl halide
Aryl halide
(Substituted
aromatic
compound)
b. Fittig reaction
-X
+ 2Na
CH
+2NaX
Aryl halide
b
u
Biphenyl
2.
s
e
s
t
dry ether
Nucleophilic substitution of haloarenes:
o
D
The presence of electron withdrawing group at ortho and/or para
position greatly increases
the reactivity of haloarenes towards substitution of halogen atom.
QHonoriloloci
1
2
(iyNoOH433
(p-nitrochlorobenzene)
ii.
0
2
NO,
NO,
T
E
C
CI
NO,
(p-nitrophenol)
QH
NO
haq.Na, CO, 403 K
rd
NO
T
H
O
(2,4-dinitrochlorobenzene)
O-HOR
NO, NO
i.
M
(2,4-
NO
olin gniepo o boiban te
NO
dinitrophenol)
002ONA
01-80R(O
OH
ROS
NO,
P-THM
warm
H,O
NO,
(2,4,6-trinitrochlorobenzene)
NO
e
ogooue a baed
2-9
ort abrbd19V
(2,4,6-trinitrophenol)
ooiavoa oroe heod-20
0-0(0
n
o
is
R+2NaX
MHT-CET
(254) MHT-CET Exam Questions
in Haloarenes:
3. Electrophilic Substitution
Chlorobenzene
Reactions of
1-Chlo
but-
A)
4.
MHT-CE
C
Which
n
o
5.
1,2-dichlorobenzene
1,4-dichlorobenzene
is
NO
2HNO/
comc. H,SO
g
nosaot
conc
1-chloro-2-nitro
NO
Denzene
2-charooenaeae
sulphonic acid
s
t
19
o
D
CH
1-Chlorotoluene
Ethan
6.
(A)de
C)d
MHT-C
Xi
majo
7.
(A)
3e dtest pigosionM
salphonic acid
anhyd. AlCI
MHT-C
b
u
SOH
4-chiorobenzene
CH
CH,C
s
e
I-chloro-4-mtro
benzene
conc. H,50
goe sgoisl to n
d
(A)1(C)1-
(C
4-Chlorotoluene
1
2
COCH,
CH,COC
anhyd. AICl
T
E
C
MHT-CET 2004
2-chloroacetophenone
0
2
T
H
M
Re
Ide
0D2olinot o-g
C
A
chloride is
(lousdgoutinih (B) ROH +PCls
ooziib
(D) ROH+HCIAnhy ZnClh
OM
fiuxX. What is X?
(A)2-Bromopropane (B) Propane
3.
8.
4-chloroacetophenone
MHT-CET 2005
2. 2-propanol+ NaBr
0
Multiple Choice Questions
1. Best method of preparing alkyl
(A)ROH+ SOCIh
(C)ROH+PCl3
COCH,0
(D
(C)Propene
(D) Propanone
C-CI bond is stronger than C-I bond, because
(B) C-Cl bond is polar covalent bond
(A)C-Cl bond is more ionic than C-I
than
covalent
C-I (D)C-Cl bond length is longer than C(C)C-Cl bond is more
9.
Halogen Derivatives (255)
MHT-CET 2006
Chlorobutane on reaction with alcoholic potash gives
(B)butan-1-ol
(A)but-1-ene
(C)but-2-ene
(D)butan-2-ol
MHT-CET 2008
of the following compounds is not chiral?
Which
(A)1-chloro-2-methylpentane
(B)2-chloropentane
(D)3-chloro-2-methylpentane
(C)1-chlonropentane
d
MHT-CET 2010
Ethanolic KOH gives
6.
(A) dehalogenation reactions
(C) dehydrohalogenation reactions
s
t
MHT-CET 2014
7.
the
is an opticaly active alkane having lowest molecular mass, predict the structure of
monochlorination
on
'X*.
of
major product obtained
X
CH
b
u
CH
(A)
CH-CH-CH--CH-CH
(B)
CH-CH-CH-CH-CHCH
fo e3o
CI
hof
CH
C)CH-CH-CH-CH-CH-Ch-C
D)
0
2
alc. KOH
CH-CH CH-CH2-Br
A
'B' + C
0Conc.H,S04
H20,4
i)
(A)
T
H
Major
product
T
E
C
-H20
D
(Major product)
+
Minor
product
M
thar
zger
(B)
n els
T
to oniog srtodto 18be 1o
CE
ole fotv beuo
CH-C-CH-CH
CH
aelooe
(D)CH-CH-CH-CH-
formation of a
compounds leads to the
following
the
which among
ond-
(A)1-bromo-1-phenylethane
(C)Bromoethane
etocrp-10
E
(9CH-CH-CH-CH--I
hydrolysis of
C
(Minor product)
CH
racemate?
alfir
wot oiilosor leoi
CH-CH-CH-CH
Alkaline
o
D
compound °D in the following series of reactions.
CH3
B
1
2
C-CHh-CH-CH-CH-CH-CH
8. Identify the
Popanar
is
s
e
(B) dehydrogenation reactions
(D)substitution reactions
1-chloro-3-methylbutane
(B)
(D)1-chloropropane
n
o
od-e (
(256) MHT-CET Exam
T0-TH
Questions
MHT-CET 2015
chemical
10. What is the
(A)AlLO
The
21.dry
prism?
composition of Nicol's
(D)
(C) CaCOj
(B) CaSO4
CA)
doil-A
Na,AlF
(C
MHT-
30-130M
the possible number
nie
carbon atoms in a compound,
asymmetric
of
number
total
11. If 'n' represents
compound is
(D)2n+ 2
optical isomers of the
of
is
C)2
(B)n
bromide and ethyl bromid.e
a mixture of n-butyl
when
formed
which is NOT
ilons
12. The compound
presence of dry ether is
treated with sodium metal in
(D)Ethaneb
Hexane
(C)
(B) Octane
(A)Butane
oogolao
(A) 2n
s
e
s
t
MHT-CET 2017
dry acetone,
iodide using sodium iodide and
ethyl
to
bromide
ethyl
13. The conversion of
lsotgo o
reaction is known as
(B) Finkelstein reactiono borg 3oun
(A) Swarts reaction
(D) Stephen reaction
(C) Sandmeyer reaction
MHT-CET 2018
o
D
alkanes are explosive?
14. With which halogen the reactions of
(C) Bromine
(B) Chlorine
(A)Fluorine
MHT-CET 2019
b
u
(C)Finkelstein
0
2
T
E
C
(A
o
23.
24.1
(D)Iodine
alkyl halides is
17. The correct order of boiling points of
(A)RI> RBr> RF> RCI
(C)RF> RBr> RCI >RI
am
this
prism?
form is used for making Nicol's
crystalline
in
compounds
following
15. Which among the
(D) CaCO
(C) NazAlF
(B) A1,0
(A) CaSO4
0(
halogen in alkyl chloride by iodide?
16. Which reaction is useful in exchange of
(B) Williamson synthesis
urogmoo sis hieobt
(A)Reimer-Tiemann reaction
reaction
D)Wurtz
reaction
1
2
22. W
n
o
MHT-CET 2016
(B)RI> RCI> RBr>RF
(D)RI> RBr> RCI>RF
D- R9-2
25.
26
1s
nucleophilic displacement reaction
reactivity
towards
highest
shows
which
compound
18. The
O,N
T
H
(A)
M
(B)
(C)
NO
NO,
NO
(D)
28
NO
19. Nicol's prism is made of
(A)CaSO4
27
NO
(B) CaSiO
(C) CaCO3
(D)Cas(PO4)2
presenceof
in prescu
metal
CaHgBr
on
Na
with
reaction
formula
molecular
ln
20. An alkyl halide having
ether gives 2,5-dimethylhexane. The alkyl halide is
(B) iso-butyl bromide
(A) sec-butyl bromide
(D) tert-butyl bromide
(C) n-butyl bromide
6gogelfs-1(0
2
ood
3
Halogen Derivatives (257)
reaction in which 2 molecules of chlorobenzene
reacts with metallic sodium in presence or
forming diphenyl is an example of
dry ether
(A)Rosenmund reaction
(B) Balz-Schiemann reaction
(C) Wurtz reaction
(D)Fittig reaction
n
o
MHT-CET 2020
22. Which
of the tollowing compounds
is
is obtained when t-butyl bromide is treated with alcoholic
ammonia'?
s
e
CH3
(B) CH-f=CH2
(A)CH--CH2-NH2 -0ca
s
t
Br
CH,
CH
(C)CH--CH
oD) CH--CH
b
u
NHBr
NH2
crystals used in Nicol's prism are formed of
(C) CaCOs
(B) CaClh
(A) CaC2
23. Calcite
o
D
AO2
D)CaO
boe
bromination of following
many isomers of monobromoderivaties are obtained on
3
diem o70u hib o1oldoiE (o
obitoliamtet roo
compoundd?
24. How
nolqo2g
T0eiabodom griwoliot olignoss dotlWo
(A
1
2
orli tol ldstiuz
onolfs of1OH Fo aodibbA
6a
gu
w
elonoole gniteort (E
olo(O
snel(D)4
ulgiinu (C) 3
(B) 5
molecular formula
derivatives for the alkyl halide having
monohalogen
25. The number of possible
CaHX is
to
A)
poi)2
(C)1
(B)4lokare
(A)3
(O)
evAmbru
active?opeeng
compounds is optically
following
the
one
of
26. Which
(B)3-Chloropentanerollot brl to
(A)2-Chloropropaneersd TO oo eobil (D)2-Chloropentane
Sooustsdie
C)2-Chloro-2 methylbutane
A)
3-bromopropene?
(D)CHsBr
27. What is molecular formula of
(C)CHBr
(B) CsHBr
od X-0 to 1obx0
(A)CaH3Br
formula of allyl chlonde
48. What is molecular
(B) C,HC1
(A)CHCl
(B)2-bromo-2-methylpropaneg odT.a
bromide is
isobutyl
49. The IUPAC name of
(A)2
T
H
M
T
E
C
0
2
ottW.c
(C)CHClo.B0)sH
)
0
D)2-methyl-1-bromopropane
(A)2-bromo-1-methylpropane
0q-00
bromide
C)1-bromo-2-methylpropane contCy
prepared by heating alkyl
alkyl fluorides are
which
in
of reaction
Lentify the name
reaction
with metallic fluorides.
B) Swarts
reaction
(A) Wurtz reaction
0(D) Sandmeyer
ogomoldo
(C)Finkelstein reaction
-o10109-(6)
e
(258) MHT-CET Exam Questions
Identiy
31. Identify Z in the following series ofreactions
CH-CH, CH, -IKOH(aleo,) XHBr
peroxide
42.
Y-
KCN
e
Z
alcohol
ab
A
(A)Eth
(C)CH-CH:-CH;-Br
IUPAC
CN
32. Identifjy 'A' in the following reaction: C,H,OH +HCI
(C)conc. H,SO4
(A) NaNO,
(B) pyridine
is
C,HCI+ H,O
s
e
(D) anhydrous ZnCh
33. Identify the neohexyl chloride from the following
(B) (CH)2CH-CH2-CH2-CH-CIA
(A) (CH:),C-CH-CH2-Cl
(D) (CH),C-ÇH-CH,
(C)CH-(CH;)-CH:-C
s
t
Cl
34. Identify 'B' in the following series of reactions
Ethanol
A
(B) Ethene
(D) Ethyl bromide
(A) Wurtz-fittig reaction
(C) Sandmeyer's reaction
T
E
C
0
2
C)1
Whichh
44.
and so
(A)Di
Identi
45.
CH
(A) C
o
D
C)
47.
36. Which among the following methods is NOT suitable for the preparation of alkyl chlorides?
(A) Addition of HCl to alkene
(B) Treating alcohols with Lucas reagent
(C)Chlorination of alkanes in presence of sunlight
D) By heating alcohols with thionyl chloride
37. The reaction 2R-Cl+CoF2
(A)2-
46. Whic
35. Which among the following is used as refrigerants and for air conditioning?
(B) Trichloromethane
(A) Dichloromethane
(D) Carbon tetrachloride
(C) Dichloro difluoro methane
1
2
43.
(A)C
b
u
Dryether
(A) Ethyl magnesium bromide
(C) Sodium ethoxide
Whi
(A)t
(C)
48. The
(A)
*49. Hov
(A)
2R-F+CoClh
is an example of
Finkelstein
(B)
reaction
D) Swarts reactioniot s
50. Ide
(A)
38. Which of the following pairs of aryl halides can NOT be prepared directly by electrophilic
substitution?
(B) Aryl chloride and aryl bromide
(A)Aryl bromide and aryl iodide
D)Aryl iodide and aryl fluoride sd
(C)Aryl fluoride and aryl chloride
e
39. What is correct order of C-X bond strength in CH3x- X?
(B) CH,CI> CH,Br > CH,I> CH,F
(A) CHI > CH,Br > CH,Cl> CH,F
D) CHF> CH,CI> CH,Br > CH,I
C)CH,F> CH,Br> CH,Cl> CH,I
T
H
n
o
(B) CH-CH-CH2
(D) CHÇH-CH,
(A) CH-CH-CH-CN
+SO
40. The common name of 1-Chloro-2, 2-dimethylpropane is
(B)n-pentyl chloride
(A)isopentyl chlorided-1-yli-Cr
D)neo-pentyl chloride
C) isopropyl chloride
obi 41. Which among the following compound is NOT optically active?
(B)2-Chloro-3-methylpentane
(A)3-Chloro-2-methylpentane
(D)3-Chloropentane
(C)2-Chloropentane
C)
51. Wh
(A)
(C)
52. Th
o-C
M
cabasd
(A
53.
W
su
(A
54.T
(A
42.
Identify 'A' in the following reaction.
KCN(alco)
sOCl,PneB
reflux
.
(A)Ethanol
Halogen Derivatives (259)
A
propane nitrile
(B) Propan-1-ol
JUPAC name of isobutyl chloride
(C)1-Chloropropane
(D) Propane
(A)2-chloro-2-methylpropane
(B)2-chlorobutane
C)1-chloro-2-methylpropane
(D)2-chloropropane
Which
among the following is
NOT obtained when bromobenzene
treated with bromoethane
and sodium in presence of dry ether?
(A)Dipheny
(B)n-butane
(C)Toluene
s
t
B
(A)CHCOOC;Hs
46. Which of the
(B) CH,COOCH
(C)CH,COOC;Hs
(D)CH,COOCH
b
u
following is least reactive towards SN' reactions?
(A)
CH-CH(Br)- CH,
(C)
CH-Br
orssrofon 6) CH-CH;-Bro
AOe.0/0) (D)(CH,)^C-Br
bod
o
D
among the following has highest boiling point?uwolior a p
(B)n-butyl bromide
(A) tert-butyl bromide
ce
lyras
16toigonq
bromide
(D) sec-butyl bromide
C)isobutyl
47. Which
hlondes
is
s
e
(D) Ethylbenzene
45. ldentify "B' in the following reaction.
CH
otta
-2
number of optical isomers possible for 3, 4-dichloropentan-2-ol is
(D)Two
(C) Sixteen
(B) Four
(A)Eight
49. How many chlorine atoms are present in a molecule of DDT7
(D)2
(C)4
(A)3
(B)5
1
2
48. The
0
2
alkyl halide with ammonia?
the correct decreasing order of reactivity of
(B)R-I>R-CI> Br
(A)R-CI>R(A
- I> R - Br> R-CI
S0. 1dentify
R-
Br>R-I
(C)R-Br>R-Cl>R-Iod0-()(D)R
T
E
C
freons'
S1. Which of the following is NOT an example of Chloro difluoromethane
(B)
(A)Diphenyl
difuoromethane
ueato(D) Dichloro
9Irichloro fluoromethane
belongs to
organic compound
T
H
(A) benzylic halide
B)
vinylic halide
C) aryl halide
(D) allylic halide
with concentrated
sulphonation of chlorobenzene
the
in
obtained
is the major product
obiol3-Chlorobenzene sulphonic acid
sulphuric acid?
(B)
sulphonic acid
orobenzene sulphonic
(D) Benzene
3-dichloro-4-methylpentane
acid
(C
is
(C)2- Chlorobenzene
ene sulphonic
in 2,
present
One
54. The
carbon atoms
number of asymmetric
(C) Two
as
(A) Four
(B) Three
what
M
A
Br
HC
52. The
n
o
is
acid)
HDdhD)
Tdentiff
Questions
sym-trichlorobenzene?
name
of
(B) 1,2, 4
IUPAC
MHT-CET Exam
(260)
55. What is 4-trichlorobenzene
(A)
1, 3,
(D) 1,3,5
trichlorobenzene
68.(A)R-
()R-
trichlorobenzene
trichlorobenzene
Fittig reaction?
example of Wurtz
an
presence of anhydrous AICI, form
following reactions
the
in
among
acetylchloride
56. Which
Chlorobenzene reacts with
(A)
benzenediazonium chloride.
4-chloroacetophenone.
form
-chloro-4-nitroben.
with NaNO,/HCI to
conc.H2S04 to form
(B) Aniline reacts
and
conc.HNO;
ether formi
sodium and dry ether
Chlorobenzene reacts with
in presence of
(C)
methylbromide
with
reacts
(D) Bromobenzene
(C)1,2,3-
is
toluene.
s
e
s
t
2oHO()
61. Identify the product of following reaction
CH,-Br+C.H,COOAg
?
obiraord
63. Identify the major product 'B'
Propene
in folowng
AAKOHB
T
E
C
(A)Propan-2-ol
(C)Propan-1-ol
u
(C) Propionic acid
igo to radtna
A
C)Propan-2-ol
(D) Propionamide
Whic
brom
(A) F
72.
Wha
(A)
73. Alky
Wh
(A)
(C)
14. Idet
(A
C
76. Id
B)2-Chloropropane
(D)1-Chloropropaneolotetoda
e
(
toliohro
(B) 1- Bromopropane
(D) Bromoethaneiiogroo
65.The boiling points of different alkyl halides having same alkyl group decrease in the order
(B)R-Br> R-Cl>R-I>R-F
(A)R-CI>R-I> R-F>R-Br
botmoo (C) R-F> R-Cl>R-Br>R-I
(D)R-I>R-Br>R-Cl>R-F
M
71.
75. WI
reaouonno sGieoránbitoaT03 od
Propane nitrile + Potassium bromide
(A) 2-Bromopropane
(C)2
pla
64. Identify A in the following reaction,e
KCN(alcoholie),
A
(A) 2
(A
C)
(B) Ethyl propionate bimud idodoal
(D) Methyl ethanoate
on
1
2
0
2
(B) Acetic acid
o
D
Whic
gnoe do
geiwofiol od
(A) Ethyl ethanoate ned iud-se(C
(C) Methyl propionate
oirolb
62. Identify product B in the following reaction.
KON(aleo)
A
B
Bromoethane-
(A) Acetamide
b
u
i
70.
n
o
is
sodium metal in Dres.
ence
2,5-dimethylhexane by reacting with
that gives
57. Identifjy the compound
(D) sec-butyl bromide
tert-butyl bromide
of dry ether.
(C)
bromide
isobutyl
(A) n-butyl bromide (B)
16 optical isomers?
present in a molecule if it has
are
atoms
carbon
asymmetric
58. How many
(C)
(B) 5
(A) 3
a
SN* reaction for (CH)
DIEagoiwolto
59. What is the relative rate of
(C) 2.0
(B) 37
(A) 0.0008
chlorobenzene?
in
60. What is bond length of C- Cl bond
(D) 1.70 A O
C) 0.96 A
1.77
(B)
Å
A) 1.42 Å
T
H
How D
69. A)Ze
77.W
78.I
66. What is UPAC name of neopentyl chloride?
(A)1-Chloro-2,2-dimethylpropane
(B) 3-Chloro-2,2-dimethylpropane(A
(C)1-Chloro-3-methylbutane
el)(D)1-Chloropentanerdorof)S
67. Which of the following compounds has highest C-X bond strength?tedeuse ont
O
(A)CH3-F
(B) CH3-Cl
(C)CH-Br
(D)CH-I
79.1
Halogen Derivatives (261)
correct order of reactivity of alkyl halide
with ammonia.
68. Iden
(A)R-I> R-Br> R-CI
(B)R-I>R-Cl>R-Br
(D)R-Br>R-Cl> R-I
(C)R-CI>R-Br> R-I
asyr
many asymmetric
carbon atoms are present in neopentyl
chloride?
(B) Three
(C)Two
(D)One
an
Is
the
following
of
optically
inactive compound?
hich
70.Which
2-Bromo-3-methylbutane
(A)
(B) 2, 2-dichlorobutane
(C) 2-Hydroxypropanoic acid
(D) Butan-2-ol
69. How
(A)Zero
following is NOT formed when a equimolar mixture
of romomethane and
hromobenzene is treated with sodium metal in dry ether?
(B) Ethylbenzene
(C) Diphenyl
(A) Ethane
(D) Methylbenzene
the
he
71. Which of
2.What is molecular formula of allyl bromide?
(B)C,H,Br
(A)CHBr
(C)CHBr
(D)CHBr
s
e
s
t
alkyl iodide:
73. Alkyl chloride when treated with sodium iodide in presence of dry acetone forms
bro
reaction?
name
of this
What is the
(B)Finkelstein reactionbepo
(A) Wurtz - Fittig reaction
(D)Wurtz reaction
(C) Swarts reaction
and B respectively in the following conversion.
74. Identify A
b
u
o
D
Ethyl propionate
yogtote
Drto
Bromoethane
Ethene
moo s
brs 030
er
brod 1-9
(B) Br/AIBrs, C.H,COOAg
(D) Br-/AIBr, CH;ONa
(A)HBr, CaH,ONa
C)HBr, CaH,COOAg
preparation of foamed
compounds is used as foaming agents in
*75. Which among the following
1
2
ODamide
plastic?
Blpoda Suuto8) Chlororormvibos yllieoitan sd oT
(A) Carbon tetrachloride
2522og triot- DE tO8
(C) Dichloromethane-isiro sollao o1s equo(P) Freonso
H HH H1O
following reaction.
76. Identify major product 'B' in
Br
0
2
But-1- enePeroxide
.
T
H
order
F
M
HHHH
HRDH
T
E
C
ogofit (B) n-butyl isocyanide
cyanide
D)sec. butyl isocyanide
(C)n- butyl cyanide
active?
halides is optically
chloride
Which among the following alkyl
isobutyl
(B)
bromide
(A) sec. butyl iodide
butyl
D) tert.
(C)n butyl bromide
78. Tdentify
in the following reaction.
(A) isobutyl
unthe
A AgCNB
'B'
2-Bromobutane-
KOHaloo
A-HB
oneinoqoofi)-poo
(C)
1-
Iodobutane
(D) Butan-2-ol
o
(B) 2-lodobutane
reactions.ero91 BO
of
series
following
19. Identify comp
3009891 gntstgodotedsh
mpound A in the
il ovtg bas
(A) But-1-ene
Aa
BACNn-butylisocyanide
(A) But-2-ene
(B) Butan-2-ol
(C) But-1-ene
(D) Butanal
n
o
is
1
3-met
(262)
1
Questions
MHT-CETExam
SOLUTIONS
CH3
are
which product
gaseous & hence, easy toremove.
choices in
from given
alkyl ch
reaction
T +HCI 1
easily to get pure
Finding the
ide.
removed
RCI+SO
OH+SOClh
and can be
by-products
R
are gaseous
alkyl chloride.
of
preparation
sO and HCI
method for
It is best
refhw
(A)
reacts with NaBr under
alcohol
when
2. (A)
reaction takes place,
Nucleophilic substitution
8.
rore
QH
CH-CH-CH
Br
2-bromopropane
s
t
2-propanol
3. (A)
C-CIbond
i) C-Cl bond is
of C and Cl as
b
u
difference in electronegativities
because of greater
more ionic than C-I bond
iodine.rosqpor 6brts
compared to that of carbon and
o
D
Aitebl
more will be its strength.
than C-I
because C-Cl bond is more ionic
bond is stronger than C-I bond
(i)More ionic character of bond,
4. (A)
HC-CH-CH, -CH,-Cl
-CH=CH, + KCI +H,0
OCHCH,But-l-ene
olot s0t 2oene 0W e
ahazo
1
2
carbon
5. (C)
structure should possess a chiral or asymmetric
or
compound
active,
optically
To be
called chiral-carbon.
atom and C-atom posses from different groups are
H CI H H
S o1dbog ojeit iinob/.t
CI H H HH
H-c-c-C---H;
T
E
C
0
2
H
H-C-C-C-C-C-H
alyeno
HHH HH
HH
HHH
1-CnioropentaneinusToy-(8Chioropentane
CI
CH3
T
H
H-C-
HHH
-C-C-C-H
H HHH
H
1-Chloro-2-methylpentane
M
H
o--15d
abinsseo lthudoat (A)
sbiseyo lrdn)
CH3 Cl H H
C-C-C-HoogoiebiT
C-C-C-H
bolo
broovadn(3)
HHH H
H-C- c
d ietu
H
3-Chloro-2-methylpentane
or1a
assbl
(C asymmetric C-atom)
Hence, 1-Chloropentane is not chiral.
931dolol-(a)
6. (C)
-1-18(A
Bthanolic KOH removes hydrogen and halogen atoms from a haloalkane, thus
dehydrohalogenating reagent and gives the same type of reactions.
Janstue33
fo-
8)
C
CH
as
ibor
atom is smaller in size
chlorine
because
bond length
length is shorter than C-I
compared to iodine atom.
C-Cl
n
o
is
s
e
CH-CH-CH
NaBr and conc HSO4
(B)
9.
Halogen
7. (A)
ethylhexane
an optically active alkane having
1s
H
CH,-CH2-CH2--CH-CH
lowest molecular mass.
ÇH
CH-CH,-CH,--CH, -CH
H
Cl
O-HDHDROKOJRD
8. (B)
Derivatives (263)
CH3
CH
CH3-CH-CH -CH -Br
JESROH
CH
CH-CH-CH
= CH
CH, -H-CH=CH
n
o
is
H,O +KBr
s
e
CH
CH OH
conc.H,SO4CH,-CH-CH-CH,+CH,-H-CH-CH-OH
ii) H20,A
rorto, Major (B) ou iv ote to Minor (C)
CH
CH3 OH
HI,
CH
CH- CH-CH-CH3
cos
+
cisaloln
ot onalq
CH
C
-
-CH,-CH
eosI biboi(D)iw
Major
s
t
CH I
CH- CH-CH-CH
b
u
+
o
D
Minor
(G)
sisosiom 2/A
2E970n tnioq
7ebzo 190n0
at sbilad lolls ganora niog gitod to
gaiiod.poaninot eastth
9. (A)
Alkaline ROH + KX
RX+KOHhydrolysis
1
2
OH
a) CH,-ÇH-Br+ KOH
CH,-C-H+KBrots oilaiosis to
0
2
CH
1-bromo-1-phenyl ethane
soaseong
HAHO
1-phenyl ethanol
the
this hydrolysis will lead to
having chiral carbon,
compound
Due to the production of
T
E
C
formation of a racemate.
CH-
(6)
CH-CH,-CH,CI
KOH
H0*
CH3
1-chloro-3-methyl butane
HO
()CH,CH,Br +KOH
M
()
3-methyl butanol
CH3
T
H
obitmod ud
CH3-CH-CH,-CH,OH+KCI
Bromo ethane
CH,CH,CI+
(d) CH
KOH
CH,CH,OH+KBr
Ethanol
HO
CH,CH,CH,OH +KCIomodPropanol
carbon
have any chiral
1-chloro propane
not
do
(C) & (d)
Since, products of (b),
aneudlydom-8-omo8-
racemate.
10. (C)
Nicol's prism i made
form a
atom, so these cannot
crystal
up of calcite
(CaC03).
(B)
Monohaloge
25.
Questions
by 2" where n represent
compound is given
the
optical isomers of a compound.
(C)
of
in
number
atoms
The possible asymmetric carbon
dod
of
number
It does not fom
hexane. It
octane andd hexane.
total
butane,
bromide gives
(D)
bromide and ethyl
MHT-CET Exam
11.
12.
n-butyl
Mixture of
ethane. CH,CH;Br+2Na-
Octane
CHCH
Reaction of alkane with
s
t
process.
fluorine is exothermic
15. (D)
n
o
up of calcite
Nicol prism is made
is
s
e
13. (B)
14. (A)
ii. CH,
erCHCH,CH;CH,CH;CH;CH;CH +2NaR
siNeCH,CH,CH;CH +2NaBr
CHCH,Br+2NaDy
Butane
EtherCH,CH,CH;CH;CH;CH3+ 2NaBr
2
Dry
CH,CH,Br+CH,CH,Br+2Na
Hexane
CHCH
2
CH
CH i.
(264)
26. (D)
(A)
2
b
u
o-D-
(CaCO3).
place
16. (C)
specifically with iodide takes
Halogen exchange
reaction
in Finkelstein
o
D
(C)
increases.
17.(D)
increases, boiling point
R-Cl > R-F.
As molecular mass
halide is R-I>R-Br>
alkyl
among
point
Correct order of boiling
21. (D)
20. (B)
19.(C)
18. (A)
.
1
2
to
elimination (no substitution)
undergoes
22. (B)
bromide
ammonia, t-butyl
In presence of alcoholic
give isobutylene.
CH
inoe lyreilg9t
+ NH,LBr
CH,
-=CH,
NH,
+
CH,-C-CH,
(alc.)
r
T
E
C
t- butyl bromide
23. (C)
24. (D)
T
Hso
()
M
0
2
isobutylene
Br
(i)
CH,-C-CH, - CH,
CH
CH
2-Bromo-2- methylbutane
1-Bromo-2- methylbutane
2-Bromo-3-methylbutane
H,C
3- Br
28.(D)
Allyl
Br-CH,-CH-CH,-CH,
CH, Br
(D)
CH
foatvd lerfism-
(ii) CH, -CH-CH-CH,t
36169S1- 10 200anot
27.
s
iv)
CH,-CH-CH, -CH, -Br
CH,
1-Bromo -3- methylbutane
29. (C)
C
1-1
30.(B)
Halogen Derivatives (265)
25. (B)
Monohalo
i
derivatives for CaHoX are
CH-CH-CH-CH-X
ii.
CH,-CH,-CH-CH,
n
o
CH
ii.
CH,--X
iv,
CH
lodoolsCH,-X
s
e
26. (D)
(A)
CH,-Ç-CH,
HDo
H
b
u
2-Chloropropane
3- Chloropentane
Cl
(C)
O.H
-CH,
CH,-C-CH,
(D)
2- Chloro -2- methyl butane
H,C CH-CH,
-
Br
en boatt
2- Chloropentane
(chiral carbon)
0
2
obimord muiescgs
T
E
C
gier
loosb8
-gM- H0-HO
3-Bromopropene (C,H,Br)
46.(D)
1
2
(6)
27.(D)
o
D
CH,-Ç-CH,-CH,-CH,
ornoorOt H
CH
s
t
CH,-CH, -C-CH, -CH,
(B)
is
CH,-CH-CH,
fylt
E)
(O.2e
(C-noT)(0e1)
onedom otouitb
o2olioiCg
CH,-CH-CH, -Cl
Allyl chloride
T
H
(C^H,C)
loo 39801T
ouag xolgor spovg. giue
Jnqo
29.(C) do
0
3uoithib ohdw
to onsroli0
lsoatoozoldoglog
(
CH,-CH-CH,-Br
M
CH,
methylpropane
1-Bromo
omo -22- methylpropane
O
edie oiligonois
oitsuoss saueos
(C.e
30.(B)
131D0
ea20 X0
itguste brod X03019boal
sona
40.(D)
(266) MHT-CET Exam
31. (A)
Questions
(3et
-CH,-I KOHae) CH, CH=CH,
-
CH,-CH,
A
olatonol
+ KI + H,O
(X)
Peroxide
(D)
KCN
CH, - CH,
CH,-CH,-CH, -CNN- alcohol -CH,
(Y)
()
A
is
Br
-
-
s
e
32. (D)
s
t
33. (A)
CH
CH,-C-CH, -CH,-Cl
41.
CH
Asit
42.(A)
b
u
CH
ofBgoieo1O
CH,
neohexyl chloride
34.(A)
NaBr
Bromoethane
Ethanol
1
2
(A)
nothes ise
Mg
0
2
o
D
H,O
CH,-CH,-0n H,SO,,ACH,-CH,-Br
Dry ether
-
CH, -CH Mg- Br
Ethyl magnesium bromide
35. (C)
n
o
HBr
T
E
C
Dichloro difluoro methane (CF2Cl;)
43.(C)
nt-gtol
CH
-H9-H09
(B)
-
(Freon-12)
IUP
used as refrigerants and for ar
44.(C)
conditioning.
36. (C)
T
H
Chlorination of alkanes in presence of sunlight gives a complex mixture of mono, d
polychloroalkanes which is difiicult to separate.
Di
37.(D)
M
45.(
38. (D)
Because aromatic electrophilic substitution with iodine is reversible and with fluorine 1s n
reactive.
39. (D)
(.0
arger
The size of halogen atom increases from F to I, which increases the C X bond length. L
the size, greater is the bond length and weaker is the bond formed.
Hence the order of C-X bond strength in CHX is, CH,F> CH,Cl> CH,Br> CH3I.
C
Et
46.(C
On
.(D)
Halogen Dertvatives (267)
CH
CH,-C-CH, -CI
CH
neo-pentyl chloride
(1-Chloro-2,2-dimethylpropane)
41.(D)
CH,-CH,--CH,-CH
3-Chloropentane
As it does not contain chiral carbon atom, it is optically inactive.
s
t
42.(A)
b
u
PyidineCH, -CH, -Cl+ HC11
CH,-CH,-OH +SOC
reflux
Bthanol
Chloroethane
So,
o
D
AKCN(aco)
olin 2o dgnents brod
sbisd
CH,-CH,-CN
X
1
2
otet 1owole 1s 19-
43.(C)
CH,-CH-CH, -CI
CH,
b
Propane nitrie
KCId
0
2
Isobutyl chloride
IUPACname 1-Chloro-2-methylpropane
T
B2Na+BCa
E
C
T
H
44. (C)
s
BromobenMene
0n0
Dphenyl and n-butane are
6.(A)
M
CH, Br
AIB
Ethane
46.(C)
bere
Dryetber
Bybease
Payd bromide
self-coupling products.
CH,BrCH,COOA
CH,COOAg ,CH,COOC,H, +AgBr
Ethyl bromide
(A)
4
(bo
towards
rder of reactivity in alkyl halides
Secondary> Primary
ertiary>
Ethyl Acetate
(B
SN' reaction is
is
s
e
H
T
n
o
MHT-CET Exam
(268)
Questions
54.
47..(B)
decreases with branching.
the boiling point
For isomeric haloalkanes,
H,C-CH2,3-dichloro-4
(A)
is
4-dichloropentan- 2- ol
Number of chiral carbon atoms (n) = 3
are 2" =2
Optical isomers possible
s
e
= 8
s
t
49. (B)
b
u
-a
DDT
50. (D)
o
D
X bond strength of
X bond length increases, the C
Therefore, R- I reacts at faster rate with NH3 and R -Cl at slower rate.
1
2
As the C
51. (A)
Freons are chlorofluoro compounds of methane and ethane.
52. (C)
Br
HC
0
2
is an aryl halide.
53.(A)
T
H
two
55. (D)
H
3,
n
o
There are
H--
T
E
C
odyd
+H,SO,
alkyl halide
56. (D) Wurtz-F
50
decreases
57. (B)
H,C-CH
CH
10H399-0
eudoal
tor C-o1oial19nn4901
sbisokis
It follows
SO,H
58. (D)
(fluming)
1-Chlorobenzene
Sulphonic acid
sua
C1
1,3, 5-trich
Bromo ben
diMHS
Chlorobenzene
M
(C)
minor product)
C2
So,H
4-Chlorobenzene
Sulphonic acid
(major product)
baoose
ata
If the nun
thenthe
59.(A)
3 alkyl
The relat
www
w
Halogen Derivatives (269)
54. (C)
-CH-CH-CH-CH,
o
n
o
2.3-dichloro-4-methyl pentane
is
There are two asymmetric carbon atoms.
55. (D)
CI
CI
olidn onocor
56. (D)
Wurtz-Fittig reaction:
NaBr
o9
Bromo benzene
b
u
QEHO-09
,H
dry ether
-Br +CH,Br + 2Na
Toulene
halide ta
57.(B)
1
2
o
D
H,C-CH-CH, Br+2Na + Br-CH,-ÇH-CH, qo D
-
CH,
CH
sboe
dry ether
CH,
T
E
C
2,
It follows Wurtz reaction.
58.D)
-CH, -CH-CH,
T
H
9gour1021
-4i-9
CH
5-dimethylhexane
chiral/asymmetric carbon atoms are 4,
number
of
the
16 (n =4)
lf
isomers = 2" - 2" =
then the number of optical
59.(A)
813-9-9,
qoqigdloub--o60-1
= 0.0008
halides undergo Syl reaction.
for (CHs)5C- Br
reaction
Sn2
The relative rate of
alkyl
M
16H9D
oneiteomot
quor fpltoocose sad gsbileliolls nrdii
0
2
H.C-CH-CH,
s
e
s
t
1,3,5 trichlorobenzene is symmetrical.
10-0 <4H
www
str
re
orderof
DecreasirngC-Br>
A)
C-Cl> bond
Questions
270) MHT-CET Exam
(M
bond
alk
60. (D)
has partially
benzene
TheC-Cl bond in due to resonance forms
gamBooibibon t
1.70 A.da olstagg
length in Chlorobenzene is
Sothe C-Cl bond
61. (C)
62. (C)
C,H,COOH
Jidomrga
(8)
(A)
(A)- Propane nitrile
(B)- Propionic acid.
OH
CI
o
D
Propan-2-old
2-Chloropropane
B
'A
1
2
odoned
bromide
0
2
CH
Chloride
Neopentyl carbon
AsymmetriC
(B)
70.
H,C-C-CH,C
CI
2,2-dichlorobut
no ch
Since it has
1.(B)
CH,- Br+ 2Na
1d-0-H9-9,
KB
Potassium d-s+
nitrile
CH,CH,CN
Propane
b
u
HC-CH-CH,
H,C-CH-CH,
Propene
64. D)
CH,CH,Br
Bromoethane
s
e
s
t
toliou-,
roilatt011-shu
63. (A)
H,C-CH=CH,
at o0sodo
is
(C) 22
Methyi propanoate
C,H,CN
CH,Br
HC-C-CH,-C
CH,COOCH, +AgBr
CH,-Br+C,H,COOAg
n
o
694) CH
double bond nature
CH,-CH,t
increasing atomic
65. (D)
group, the boiling point increases with
Within alkyl halides having same alkyl
in size and
increase
van der Waals force increases with
mass of halogen because magnitude of
mass of halogen.
R-I>R-
66. (A)
Ethane
Br> R- Cl> R-F
T
E
C
CH
Self-Cc
9xodleaitstutb-2S
noitose7 suWaolloh
l
12. (C)
H,C-C-H,-C
HC=CH-
CH
T
H
1-Chloro-2,2-dimethylpropane
) 3
Saoino2i tiotgo
to
1odreun sdl aedi
attraction with carbo.
67.(A)
is more electronegative, it has strong
Since size of F atom is small and it
9biier lella
follows
thstt iye0g1shod6u15
Strength of C- X bond decreases as
iulor sal
M
zotpo1p7St0
H3C-F> CH3- Cl>HC Br>HC-I trH)
Allyl b
3.B)
R-Cl+N
Alkyl
Chloride
This
reacti0
Halogen Derlvatives (271)
Oecreasing order of strength
C-Br
C-Cl
>
ofC- X bond is
C-I
bond
bond
bond
ww
n
o
(More reactive
alkyl halide)
.(A)
CH
o3
HC-C-CH, -Cl
s
e
CH
Neopentyl Chloride
Asymmetric carbon atoms
=
HC-C-CH,CH,
aoisgo ai it
Cl
b
u
oe ida su at sbiboi
2,2-dichlorobutane
o
D
it is optically inactive.
Since it has no chiral carbon atom
HOX
lyud
opul
OH0-H-9,H
s-S-i8
71.(B)
1
2
Dry
CH,-Br+2Na+ Br-
ether
CH,-CH,+
Ethane
saa
s
t
Zero.
70.(B)
Crease m
0
2
Dipheny!
T
E
C
ruaitiuroitoE-S
O-D-HO-9,
orns-Rre
Methyl bezene
(Cross Coupling)
Self-Coupling Products1a1
72.(C)
-0HONO-9
Allyl 'C
T
H
obiangaoeud-
H,C=CH-CH
M
is
italg orrs
Br
Allyl bromide
Ceouco
73.B)
Dry acetone R-I+ NaCI
R-Cl+Nal or Methanol Alkyl
Alkyl
Iodide
Chloride
reaction.
This reaction is known as Finkelstein
(272) MHT-CET Exam
Questions
74. (C)
- Br
H,C CH, HBr,H,c-CH,
A
is
Ethylpropionate
Bromoethane
Ethene
s
e
plastic.
75. (D)
in preparation of foamed
Freons are used as foaming agents
76. (B)
CH2 -CH2
HBr
CH2Peroxide CH-CH2
1-Bromobutane
CH-CH-CH=
But-1-ene
-
AgENCH -CH
n
o
c.H,COOAE,C.H,C-CH,CH, +Ag
- CH2 -CH2
-
-
Br
s
t
NC
n-butyl isocyanide
b
u
77. (A)
H,c--CH,CH,
o
D
Alcohols:
attachedto
Phenols
attached to
examp
For
HO-D-98
it is optically active.
Since secondary butyl iodide has one chiral 'C' atom,
1
2
78. (B)
HC-CH-CH,CH,KOHHCKOH
Br
79. (C)
0
2
T
E
C
H,C=CH-CH, -CH,
But-1-ene
[A]
M
T
H
Etherstwo aryl
But-2-ene
A
2-Bromobutane
9csiudaoll
H,C-CH-CH, -CH,
2-Iodobutane
HBr
2.
Bromobutane
[B]
AgCN,A
H,C-CH,CH, CH,
-
NC
n-butylisocyanide
sbiend lel
13n
1.1
-CH, -CH,
H,C-CH,
Na,O,
Br
P1-
Prep
2ootiek
ellA
alipol
anota
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