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AQA Physics Paper 2 Higher Predicted Exam 2022

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AQA Physics Paper 2
Higher
Separate Science
Predicted Paper 2022
Name
………………………………………………
Date
………………………………………………
1 hour 45 minutes allowed
Similar to your real exam, each question in this paper gets harder towards the
end of each question, so if you find you can’t do the last part of a certain
question, try the next question – they all start off easier and then get harder.
Grade boundaries
These are VERY rough guesses! Getting an 8 or 9 on this paper does not
guarantee you the same mark in the exam.
•
•
•
•
•
9
8
7
6
5
75
65
55
45
35
The information from the exam board gives us a broad overview of what is
covered in the exam. If a topic is not listed as a ‘major focus’ it can still come
up in a question, but that question might not be worth many marks. There are
questions in this paper that cover topics that are not a ‘major focus’ for the
exam, but don’t let that worry you!
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1
Exam Analysis
Marks
Marks
Question
available gained
1
16
Topic
Advanced
information for
2022
Waves
Waves in air,
fluids and solids
2
11
Gravity
Forces and their
interactions and
describing motion
along a line
3
22
Momentum
Momentum
4
8
Mass
calculations
Work done and
energy transfer
5
6
Ray boxes
Required Practical
Activity 9
11
Pressure and
pressure
differences in
fluids
7
7
Red shift
Solar system;
stability of orbital
motions;
satellites and
Red-shift
8
19
Extension of a
spring
Forces and
elasticity
Total
100
6
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What do you
need to do to
improve?
2
Equation sheets
Equation
W = mg
W = Fs
Symbols
Units
W = weight
W = N (newton’s)
m = mass
m = kg (kilograms)
g = gravitational field
strength
g = N/kg (newtons per
kilogram)
W = work done
W = J (joules)
F = force
F = N (newtons)
s = distance
s = m (meters)
F = force
F = ke
k = spring constant
e = extension
Ee = elastic potential
energy
Ee = ½ ke2
M = Fd
p=F
A
F = N (newtons)
k = N/m (newtons per
meter)
e = m (meters)
Ee = J (joules)
k = spring constant
k = N/m (newtons per
meter)
e = extension
e = m (meters)
M = moment
M = Nm (newton-meters)
F = force
F = N (newtons)
d = distance
d = m (meters)
p = pressure
p = Pa (pascals)
F = force
F = N (newtons)
A = area
A = m2 (meters squared)
p = Pa (pascals)
p = hρg
p = pressure
h = m (meters)
h = height
ρ = density
ρ = kg/m3 (kilograms per
meter cubed
g = gravitational field
strength
g = N/kg (newtons per
kilogram)
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s = vt
a = Δv
t
s = distance
s = m (meters)
v = speed
v = m/s (meters per second)
t = time
t = s (seconds)
a = acceleration
Δv = change in velocity
Δv = m/s (meters per
second)
t = time
t = s (seconds)
v = final velocity
v2 – u2 = 2as
u = initial velocity
a = acceleration
s = distance
F = force
F = ma
p = mv
m = mass
Δt
v = m/s (meters per second)
u = m/s (meters per second)
a = m/s2 (meters per second
squared)
s = m (meters)
F = N (newtons)
m = kg (kilograms)
a = acceleration
a = m/s2 (meters per second
squared)
p = momentum
p = kg m/s (kilograms metre
per second)
m = mass
v = velocity
F = m Δv
a = m/s2 (meters per second
squared)
m = kg (kilograms)
v = m/s (meters per second)
F = force
F = N (newtons)
m = mass
m = kg (kilograms)
v = velocity
v = m/s (meters per second)
t = time
t = s (seconds)
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Equation
Period =
Symbols
1
.
Period = s (seconds)
Frequency
T=1
F
Frequency = Hz (hertz)
T = Period
T = s (seconds)
f = frequency
f = Hz (hertz)
v = velocity
f = frequency
v = fλ
Units
λ = wavelength
(lambda)
Magnification = image height
object height
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v = m/s (meters per second)
f = Hz (hertz)
λ = m (meters)
Ratio, so has no units
5
Equation
F = BIl
Note this is a capital I and a
lowercase l
Vp = np
Vs
ns
Symbols
Units
F = force
F = N (newtons)
B = magnetic flux density
B = T (tesla)
I = Current
I = A (Amps or Amperes)
l = length
l = m (meters)
Vp = potential difference
across the primary coil
Vp = V (volts)
Vs = potential difference
across the secondary coil
np = number of turns on
the primary coil
Vs = V (volts)
np and ns have no units as they
are just numbers
ns = number of turns on
the secondary coil
Vs Is = Vp Ip
Vs = potential difference
across the secondary coil
Vp = potential difference
across the primary coil
Is = current in the
secondary coil
Vs = V (volts)
Vp = V (volts)
Is = A (Amps or Amperes)
Ip = A (Amps or Amperes)
Ip = current in the primary
coil
Vs Is = power output
Vp Ip = power input
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Question 1
a)
Waves can be either transverse or longitudinal. Give an example of a transverse
wave.
(1 mark)
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b)
Sketch and label a transverse wave.
c)
Define the term “frequency” with regards to waves.
(3 marks)
(2 marks)
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d)
What type of wave is a sound wave?
(1 mark)
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e)
A sound wave has a frequency of 50Hz. It is travelling at 57.5m/s. Calculate the
wavelength of this sound wave.
(4 marks)
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f)
Humans have a limited hearing range. We can hear noises with a frequency
between 50Hz and 50GHz. Explain how the structure of the human ear causes this.
(3 marks)
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g)
Explain why refraction occurs when a wave moves between two different mediums.
(2 marks)
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Question 2
a)
Describe the difference between mass and weight.
(2 marks)
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b)
The force of gravity is due to the gravitational field strength. Give the units for
gravitational field strength.
(1 mark)
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c)
Gravity is a non-contact force. Give two examples of other non-contact forces.
(2 marks)
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The velocity time graph for a falling object is shown below.
d)
Write labels for the axes:
i.
X-axis
(1 mark)
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ii.
Y-axis
(1 mark)
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e)
The value for gravitational field strength is 9.8. Give the final acceleration reached
by an object falling to earth.
(2 marks)
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f)
Describe the velocity-time graph for the falling object.
(2 marks)
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Question 3
a)
Velocity is a vector quantity; however, speed is scalar. Explain the difference
between a scalar and vector quantity.
(2 marks)
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b)
For each of the following, state if it is a vector or a scalar quantity:
i.
Momentum
(1 mark)
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ii.
Mass
(1 mark)
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c)
A driver is preparing to start their car and start their journey. State the momentum
of the car.
(1 mark)
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d)
Calculate the difference in momentum between two cars, both of mass 850kg. Car
A is travelling left at 40m/s and car B is travelling right at 60m/s.
(6 marks)
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e)
Car A and Car B move off as one object after the collision. Give the speed and
direction.
(6 marks)
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f)
Car A breaks suddenly and after 35m comes to a stop. Calculate the acceleration
of the car as it stops. Give your answer to one decimal place.
(5 marks)
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Question 4
A ball falls from a dog’s mouth and rolls across a park. The ball decelerates at a rate of
127m/s2. It takes 64.77J to stop the ball from rolling, and it comes to a complete stop
after 0.5m. Calculate the mass of the ball.
(8 marks)
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Question 5
A student was studying refraction and set up the following experiment.
They have drawn the shape of the block; the normal and the path of light as it enters
the block. Complete the student’s diagram.
(6 marks)
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Question 6
a)
Describe the atmosphere.
(3 marks)
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b)
Explain the change in pressure as you move away from the earth.
(4 marks)
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c)
Sketch a graph to show atmospheric pressure as you move away from the earth.
(4 marks)
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Question 7
a)
Explain how the phenomenon of “red-shift” has helped to support the following
ideas:
•
•
The universe is expanding
The Big Bang was the origin of the universe
(4 marks)
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b)
Explain how an object in orbit around earth can have a changing velocity but an
unchanged speed.
(3 marks)
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Question 8
A student carried out an experiment to find the spring constant of a spring. The table
shows the data collected.
For this question length can be kept in cm, for ease of answering.
Mass added (g)
0
100
200
300
400
Length of spring (cm)
17.0
23.5
30.0
36.5
43.0
a)
Draw a second table to determine the values needed to plot a graph to find the
spring constant. Use the value of 10 N/kg for gravity.
(5 marks)
b)
There are two ways to determine the spring constant of a spring, from the data
collected. Give both of these methods.
(2 marks)
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c)
Draw a graph that will allow you to determine the spring constant.
d)
Determine the spring constant for this spring in N/cm.
(4 marks)
(4 marks)
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e)
State how you could determine the work done when stretching this spring.
(2 marks)
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f)
Thus, calculate the work done to stretch a spring to 26cm.
(2 marks)
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You’re made of star dust!
Honestly!
You’re a star!
Now go and take a break!
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Answers
Question Answer
Number
1a
- Waves on the surface of water
- Electromagnetic waves (general or named)
1b
Guidance
Any reasonable
example
Amplitude
wavelength
1c
1d
1e
1f
1g
2a
2b
2c
-
Mark for correct amplitude
Mark for correct wavelength
Mark for general shape
Number of peaks/troughs
Per second
Longitudinal
Mark for correct formula
Mark for correct substitution
Mark for correct rearrangement
Mark for answer AND units
Velocity = Wavelength x Frequency
57.5 = Wavelength x 50
Wavelength = 57.5 / 50
Wavelength = 1.15m
- Sound waves causes the ear drum to vibrate
- Nerve converts this into information
- Only works at certain frequencies
- Speed changes
- When there is a change in direction
One mark for each
bullet point
One mark for each
bullet point
One mark for each
bullet point
One mark for each
bullet point
-Mass is fixed
-Weight is dependent on gravity
N/ Kg
-electrostatic
-magnetic
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2di
2dii
Time (seconds)
Velocity (m/s)
2e
2f
9.8m/s/s
-increasing velocity
-levels off
3a
- Vector includes direction
- Scalar merely being figure
3bi
3bii
3c
3d
Vector
Scalar
Zero
- Mark
- Mark
- Mark
- Mark
- Mark
- Mark
for
for
for
for
for
for
Both label and units
needed to score 1
mark, alternative
can be given for time
One mark for each
bullet point
correct formula
correct substitution
answer for car A
answer for car B
correct use of units once
calculating difference
Momentum = Mass x Velocity
Car A momentum = 850 x 40
Car A momentum = 34,000 kg m/s
Car B momentum = 850 x 60 = 51,000 kg m/s
Difference = 51,000 – 34,000 = 17,000 kg m/s
3e
-mark for
-with one
direction
-mark for
-mark for
-mark for
-mark for
total momentum before collision
number being negative to show
Allow ecf from last
part
momentum after event
mass after collision
new velocity
correct direction
51,000 - 34,000 = 17,000 kg m/s
Momentum is conserved so after collision it is also
17,000 kg m/s
Mass = 850 + 850 = 1700 kg
Momentum / mass = velocity
17,000 / 1700 = 10m/s right
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3f
-
Mark
Mark
Mark
Mark
Mark
for correct formula
for correct substitution
for correct rearrangement
for answer AND units
correct rounding
22.857… loses one
mark
v2 – u2 = 2as
02 – 402 = 2 x a x 35
a = (02 – 402) / (2 x 35)
a = - 22.9 m/s2
4
-
Mark
Mark
Mark
Mark
Mark
Mark
Mark
Mark
for
for
for
for
for
for
for
for
correct formula
correct substitution
correct rearrangement
answer AND units
correct formula
correct substitution
correct rearrangement
answer AND units
Work = Force x Distance
64.77 = Force x 0.5
Force = 64.77 / 0.5
Force = 129.54N
Force = Mass x Acceleration
129.54 = Mass x 127
Mass = 129.54 / 127
Mass = 1.02kg
5
-labelled normal
-line through block
-refracted ray out the other side
-angle of incident labelled
-angle of refraction labelled
-appropriate angles used
6a
-thin layer around the earth
-air
-less dense with increasing altitude
-decrease in pressure as move away from earth
-particles colliding with the surface creating
pressure
-further up, less particles
-total number of particles contributes to total
pressure
6b
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One mark for each
bullet point
23
6c
-x-axis should be altitude or distance in km
-y-axis should be pressure in kPa
-smooth curve
-starting top left to bottom right
No need for numbers
or grid lines
7a
-
One mark for each
bullet point
7b
8a
8b
8c
8d
Observing distant stars / galaxies
Moving further away / accelerating away
Expansion / universe expanding
Starting from single point
Orbital speed is related to radius
Velocity is a vector, and has direction
Direction is changing, but not speed
One mark for each
bullet point
-
Mark for converting g to kg
Mark for using weight = mass x gravity
Mark for correct values weight column
Mark for finding extension
Mark for correct values in extension column
Weight (N)
Extension (cm)
0
0
1
6.5
2
13
3
19.5
4
26
- Using force = spring constant x extension
- From the inverse of the gradient of the graph
- Mark for label (extension) and scale on x axis
- Mark for label (weight) and scale on y axis
- Mark for plotting all point correctly
- Mark for line of best fit
Answer of 6.5 N/cm
Either method from 8b can be used to gain marks
-
Mark
Mark
Mark
Mark
for
for
for
for
correct formula
correct substitution
correct rearrangement
answer AND units
OR
-
Clear triangle drawn on graph
Calculation shown
Inverse found
Mark for answer AND units
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8e
8f
- Elastic potential energy = 0.5 x spring constant
x (extension)2
- Mark for correct substitution
- Mark for answer AND units
Work done = 0.5 x 6.5 x 0.262
= 0.2J
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