Chapter 2 Probability, Counting & Binomial 2 Probability Probability is a numerical measure of the likelihood that an event will occur. Probability is the study of chance. e.g. What is the chance that I will pass Stats? What is the chance that it will rain tomorrow? What is the chance of an earthquake in LA this year? What is the chance of getting 0 on the roulette wheel? We want to attach a number to each of the above examples. Probability values are always assigned on a scale from 0 to 1. A probability near zero indicates an event is quite unlikely to occur. A probability near one indicates an event is almost certain to occur. Hopefully, the chance of passing this class will be 100%. Terminology Random Experiment An action or process that leads to one of several possible outcomes. E.g. rolling a pair of dice. Outcome/Sample Point A particular result of an experiment. E.g. rolling pair of sixes with two dice. Sample Space All the possible outcomes of an experiment. Section 1 - Chapter 2 - Lecture Notes by Panayiotis Skordi 53 Chapter 2 Probability, Counting & Binomial Event Outcomes that are of interest for an experiment. They are a subset of the sample space. A collection or set of one or more simple events in a sample space. The probability of an event occurring is equal to the sum of the probabilities of the outcomes giving rise to that event. If we identify all the outcomes of an experiment and assign a probability to each, we can calculate the probability for that event. Complement of an Event The complement of event A is defined to be the event consisting of all outcomes that are not in A. The complement of A is denoted by , and is referred to as A prime. Section 1 - Chapter 2 - Lecture Notes by Panayiotis Skordi 54 Chapter 2 Probability, Counting & Binomial Classical Probability This occurs when we know all the possible outcomes to an experiment and the number of outcomes for a particular event. Here the probabilities are assigned on the assumption of equally likely outcomes. The probability of a particular event, A, occurring is denoted P[A] . P[A] = Number of possible outcomes in which event A occurs Total number of outcomes from the sample space So if an experiment has n possible outcomes, the classical method would assign a probability of to each outcome. Example Consider the experiment of rolling 1 die. The sample space will look like this (1) (2) (3) (4) (5) (6) This experiment has a total of 6 outcomes. The total outcomes form the sample space. P[rolling of rolling any of the possible outcomes] = 1 6 Section 1 - Chapter 2 - Lecture Notes by Panayiotis Skordi 55 Chapter 2 Probability, Counting & Binomial Example Consider the experiment of rolling 2 dice. Consider the event of rolling a total of 3,4,5 or 6 with 2 dice. The sample space will look like this (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) This experiment has a total of 36 outcomes. The total outcomes form the sample space. We have 14 outcomes, underlined, corresponding to our event of rolling 3, 4, 5 or 6 with 2 dice. Applying the formula gives P[rolling 3,4,5 or 6 with 2 dice] = 14 = 0.39 36 The 0.39 could be expressed as 39.0% Section 1 - Chapter 2 - Lecture Notes by Panayiotis Skordi 56 Chapter 2 Probability, Counting & Binomial Empirical Probability/Relative Frequency Method Empirical comes from the Greek word meaning “experience”. Probabilities are assigned based on experimentation or historical data. This method may use data built over past experience e.g. the motor claims for a particular company. We do not totally understand the underlying process of who will crash their car or have it stolen. We just take the actual past data, our experience, and work out the percentage of people that have crashed their cars or had them stolen. To work out the empirical probability we observe the number of occurrences of an event through an experiment and calculate the probability from a relative frequency distribution: P[A] = Frequency in which event A occurs Total number of observations Subjective Probability Used when other two methods are not available. We base our numbers on guesstimates. This may be based on intuition or gut feel. E.g. a new type of insurance for domestic pets that has never been sold before. We have no experience of past claims so we need to subjectively arrive at a premium. Requirements/Properties of Probability If P[ A ] = 1 (100%) then event A will occur with certainty. If P[ A] = 0 (0%) then event A will not occur. Probability of event A must be between 0 and 1 (0% to 100%). The sum of all the probabilities for the events in the sample space must equal 1 (100%). The complement to an event A, are all events in the sample space, which do not include event A. The complement of A is referred to as A ′ . P[ A] + P[ A′] = 1 Section 1 - Chapter 2 - Lecture Notes by Panayiotis Skordi 57 Chapter 2 Probability, Counting & Binomial The rule is useful as sometimes it is easier to calculate the probability of an event happening by determining the probability of it not happening and then subtracting the result from 1. Example An automatic machine fills plastic bags with a mixture of beans, broccoli and other vegetables. Most of the bags contain the correct weight, but because of the variation in the size of beans and other vegetables, a package may be underweight, overweight or have the correct weight. A check of 4,000 packages resulted in the following results: Probability A, of being underweight is 0.025 or 2.5% Probability B, of having satisfactory weight is 0.90 or 90% Probability C, of being overweight is 0.075 or 7.5% What is the probability of choosing a satisfactory weight bag using the complement rule? The probability the bag is unsatisfactory equals the probability the bag is overweight or underweight. That is P ( AorC ) = P ( A) + P (C ) = 0 .025 + 0 .075 = 0 .100 The bag is satisfactory if it is not underweight or overweight, so P ( B ) = 1 − [ P ( A) + P (C )] = 1 − [0 .025 + 0 .075 ] = 0.900 This result can be seen from the Venn diagram below. Section 1 - Chapter 2 - Lecture Notes by Panayiotis Skordi 58