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Chemistry Regents Exam Review2

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Chemistry Regents Review
Study Slides
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Atomic Structure
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Subatomic Particles
 protons
 electrons
 neutrons
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Protons
 positively charged (+).
 1 atomic mass unit ( 1 amu)
 Located in the nucleus
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Neutrons
 no charge (0)
 1 atomic mass unit (1 amu)
 Located in the nucleus
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Electrons
 Negatively charged (-)
 No mass (0 or 1/1826th amu of a proton)
 In orbital outside the nucleus
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Nucleons
 Particles in the nucleus
 Protons and neutrons
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Atomic number
 The total number of protons
 Identifies each element
28.0855
Si
14
2–8–4
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Mass number
 protons + neutrons
protons
neutrons
Mass number = 14
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Isotopes
 Atoms of the same element
 Same atomic number (protons)
 Different mass numbers (difference in # of neutrons)
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Comparing Two Sodium Isotopes
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Atomic mass
 Weighted average mass of all the naturally
occurring isotopes of an element
 Depends on mass numbers and abundances
of each isotope.
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Atomic Models
Earliest Model
Current Model
Hard Sphere
Plum Pudding
Empty Space
Electron Shell
Wave-mechanical
(no structure)
(+ and – all over)
(+ nucleus)
(electrons in orbit)
(e- in specific region)
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John Dalton: Solid sphere model
 An atom is uniform throughout
 No internal structure and is indivisible
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J.J. Thompson: Plum-pudding model
 Cathode ray experiment
 Positive and negative particles spread
throughout entire atom
 Discovered electrons
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Ernest Rutherford: Empty space model
 Gold foil experiment
 An atom is mostly empty space
 The nucleus is small, dense and positive
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Neil Bohr: Bohr’s Model
 Electrons in planet-like orbits (shells)
 Each orbit corresponds to the energy of the
electrons
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Wave-mechanical: Current model
 Electrons are in orbitals or “clouds”.
 Work of many scientists over hundreds of years
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Orbital
 a region where electrons are likely to be found
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Electron Shells
 Energy levels of an atom
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Electron Configuration
 A way of showing the arrangement of electrons in
an atom
2–8–4
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Interpreting Electron Configuration
28.0855
Si
2–8–4
first second
shell shell
2 e- 8 e-
third
shell
4 e-
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Ground State Atom
 Low energy and stable state
 The periodic table configurations
2 – 8 – 4 (Silicon)
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Excited State Atom
 High energy and unstable state
28.0855
Si
2–8–4
Ground state
2 – 8 – 3 – 1 Excited state
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Electron Transition
 An electron absorbs (gains) energy to go from a
low to higher shell (3rd to 4th )
 An electron releases (emits) energy to go from a
high to lower shell (4th to 3rd)
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Bright-line spectra (band of colors)
 energy released by an excited electron
dropping to a lower (ground) state
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Bright-line spectra (band of colors)
The mixture consists of Sr and Li
 Lines in the mixture match those of strontium and lithium
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Flame Test
A lab test to identify the metallic ion
in a compound
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Types and
Physical Behavior of Matter
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Pure substances
 Elements and compounds
 Matter with fixed composition
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Elements
 Composed of atoms with the same atomic number
 Cannot be decomposed by any method
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Compounds
 Two or more different atoms chemically
bonded in a fixed ratio
 Can be broken down by chemical methods
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Binary Compounds
 Composed of just two different atoms
 Ex. NH3, NaCl, CO2
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Mixtures
 Two or more substances physically combined
 Composition can vary (not fixed)
 can be separated by physical methods
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Homogeneous mixtures
 Made by dissolving a salt in water
 Uniform composition
 Aqueous solution (made with water)
 Ex. NaCl(aq), CO2(aq)
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Aqueous Solution mixtures
 Made by dissolving a salt in water
 Ex. NaCl(aq), CO2(aq)
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Heterogeneous mixtures
 Non uniform composition
 Ex. sand in water
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Particle Diagrams of Matter
Atom X
Element (X2)
Atom Y
Compound (XY)
Mixture (X2 and Y)
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Separation of Mixtures
 by physical methods
 filtration, decantation (heterogeneous)
 distillation, chromatography (homogeneous)
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Filtration (heterogeneous mixture separation)
 by particle sizes
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Decantation (heterogeneous mixture separation)
 Pouring off layers of liquids
 by density difference
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Distillation (homogeneous)
 Boiling and evaporating of liquids
 by large boiling point difference
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Solid Phase
 definite volume, definite shape
 regular geometric arrangement of particles
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Liquid Phase
 definite volume but no definite shape
 particles flow over each other
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Gas Phase
 No definite volume, no definite shape
 Particles expand and fill container
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Endothermic (energy absorbing) phase changes
Melting
Au(s) → Au(l)
Evaporation
H2O(l) → H2O(g)
Sublimation
CO2(s) → CO2(g)
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Exothermic (energy releasing) phase changes
Freezing
Au(l) → Au(s)
Condensation
H2O(g) → H2O(l)
Deposition
CO2(g) → CO2(s)
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Heating Curve
D
E
A: Solid
C: Liquid
E: Gas
Temperature increases
Kinetic energy (KE) increases
Potential energy (PE) stays constant
B: Solid and Liquid
D: Liquid and Gas
Temp stays constant
KE stays constant
PE increases
Melting Point = 0oC
Boiling Point = 100oC
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(for 6 minutes)
(for 10 minutes)
Cooling Curve
E
E: Gas
C: Liquid
A: Solid
D
C
Temperature decreases
Kinetic energy (KE) decreases
Potential energy (PE) stays constant
D: Gas and liquid
B: Liquid and Solid
B
A
Freezing Point
Temp stays constant
KE stays constant
PE decreases
= 30oC
Condensation Point = 50oC
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(for 3 minutes)
(for 7 min.)
Temperature
 A measure of the average kinetic energy (KE)
of particles in a substance
30oC
Higher Temp
Greater KE
20oC
Lower Temp
Lower KE
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Temperature Conversion
T
K=
oC
+ 273
Table T
Table
What is -50oC in Kelvin?
K = -50 + 273 = 223 K
350 K in oC?
oC = K – 273
oC = 350 – 273 = 77oC
Entropy
 Measures randomness or disorder of a system
Increase in temperature = Increase in entropy
H2O(s) at 0oC
Lowest Entropy
Least Random
H2O(l) at 30oC
H2O(g) at 100oC
Highest Entropy
Most Random
Heat
 A form of energy that flows from
High to Low temperature
50oC
Heat
40oC
 measures in Joules or calories
Heat Unit
1 kJ
= 1000 Joules
2 kiloJoules = ____Joules
250 J = ____ kJ
(2 x 1000) = 2000 Joules
250
------- = 0.25 kJ
1000
Heat Problems
 Use Table T Equations
and Table B Constants
to set up and solve heat problems involving water.
Factors that Affect Gas Behavior
Volume
Temperature
(space of container)
(Kinetic energy of particles)
Pressure
(force)
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Avogadro’s Law
Gases with the
 same volume
 same temperature
 same pressure
have equal # of molecules
Comparing Two gases
H2
CO2
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Kinetic Molecular Theory
(KMT)
 describes behavior of ideal gas particles
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KMT
 Particles are far apart
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KMT
 Particles move in constant, random,
straight-line motion
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KMT
 Particles transfer energy to another
when they collide
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KMT
 Particles have no attraction to one another
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KMT
 Particles have no or insignificant volume
too small
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Ideal Gas
 Has all KMT characteristics
Real Gases (O2, H2)
 Do not obey all KMT properties
 Deviate from (do not behave exactly like) and
Ideal Gas
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Deviation from an Ideal Gas
Comparing Gases and Conditions
Low molar mass
H2
O2
High molar mass
Low Pressure
0.5 atm
0.8 atm
High Pressure
High Temperature
300 K
273 K
Low Temperature


Deviates Least from
Behaves most like


Deviates Most from
Behaves Least like
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Two Reasons Real Gases Deviate
 Particles of real gases do have volume
 Particles of real gases do attract each other
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At Constant Temperature
 A gas volume is inversely proportional to its
pressure
As pressure decreases, volume increases
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At Constant Pressure
 A gas volume is directly proportional to the
Kelvin temperature
As temperature increases, volume increases
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At Constant Volume
 A gas pressure is directly proportional to the
Kelvin temperature
As temperature increases, pressure increases
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Solving Gas Law Problem
Use the Combined Gas Law Equation (Table T).
to set up and solve for unknown.
V1P1
V2P2
------- = -------- Combined Gas Law Equation
. erase whatever is constant
T1
T2
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Pressure Conversion
1 atm = 101.3 kPa
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Volume Conversion
1 L = 1000 mL
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Physical Property
 Observe without changing chemical compositions
Ex: melting and boiling points
density, mass
solubility, conductivity
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Physical Changes
 No change in chemical composition
 No new substance is formed
 Most are reversible
Ex: Phase change:
H2O(l) → H2O(s)
Dissolving
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Chemical Property
 Observe by changing chemical composition
Ex: It reacts, it rusts, it burns, it decomposes
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Chemical Change
 A change in chemical composition
 New substances are always formed
Ex: Chemical Reaction
H2O → H2 + O2
Decomposition
The Periodic Table
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Periodic Law
 elements are arranged by increasing atomic numbers
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Periods - horizontal rows
 Same period elements = same electron shells
Na and Al both have 3 electron shells
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Groups - vertical columns
 Same group
 Same valance electrons.
 Same chemical reactivity.
Ex: Mg and Ba have similar chemical properties
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Malleable
 Able to be hammered into a thin sheet.
Au (Gold) is malleable.
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Ductile
 easily drawn or molded into thin wire.
Cu (copper) is ductile
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Brittle
 Breaks or shatters easily when struck
Sulfur (S) is a brittle element
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Luster
 Shininess of a substance.
Silver (Ag) has luster
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Conductivity
 Able to conduct heat or electrical current.
Copper (Cu) has high electrical and thermal (heat) conductivity.
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Ionization Energy (IE)
 Energy to remove the most loosely bound e-.
Use Table S to compare
Li 520kJ = Lowest IE (most likely to lose and form +ion)
B 801 kJ
C 1086 kJ = Highest IE (least likely to lose and form +ion)
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Electronegativity (EN)
 Measures attraction of an atom to electrons.
Use Table S to compare
N 3.0 = Highest EN (most likely to attract or gain and form -ion)
C 2.6
B 2.0 = Lowest EN (least likely to attract or gain and form -ion)
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Density
 The mass per unit volume.
 Use Table S to compare
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Atomic Radius
The size of a neutral atom.
Use Table S to compare.
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Metal Properties






Majority of the elements
Most are solids (Hg the only liquid metal)
Malleable, luster and ductile
High conductivity
Low electronegativity & Low ionization energy
Lose electrons & form positive (+) ions
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Nonmetals





Can be a solid, liquid or gas
Brittle and dull
Low conductivity
High electronegativity and high ionization energy
Gain electrons and form negative (-) ions
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Metalloids
 Have properties of both metals and nonmetals.
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Diatomic Elements
 Two-atom elements
 Br2, I2, N2, Cl2, H2, O2, F2 (BrINClHOF)
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Monatomic Elements
 One-atom elements
 All Noble (Group 18) gases
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Group 1 - Alkali metals





1 valence electron
Strongest metallic properties
Francium is the most metallic element
Halide formula = XY
Oxide formula = X2O
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Group 2 - Alkaline Earth Metals
 2 valence electrons
 Halide formula = XY2
 Oxide formula = XO
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Group 3 – 12: Transition Metals
 Form multiple oxidation numbers
 Form colorful compounds
NiCl is greenish color
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Group 17 (Halogens)
 Seven valence e Very reactive, diatomic elements
 Has elements in all three phases at STP
Gases: F2 and Cl2
Liquid: Br2 (the only liquid nonmetal)
Solid : I2
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Group 18: Noble Gases
 Full and stable valence shell
 Non reactive
 Monatomic Gases (He, Ne)
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Electronegativity Trends
 Left to Right: Increases due to
decreasing atomic size
 Top to bottom: Decreases due to
increasing atomic size
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Ionization Energy Trends
 Left to Right: Increases due to
decreasing atomic size
 Top to bottom: Decreases due to
increasing atomic size
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Metallic Properties Trend
 Left to Right: decrease
 Top to bottom: increases
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Nonmetallic Properties Trend
 Left to Right:
Increases
 Top to bottom: decreases
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Atomic Radius Trend
 Left to Right: decrease due to
increase in nuclear charge
 Top to bottom: increases due to
increase in electron shells
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Summary of Trends
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Allotropes
 Different molecular forms of an element
 Different physical and chemical properties
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Common Allotropes
Phosphorous: Red, Black and White
Oxygen: O2 (air) and O3(Ozone)
Carbon: Diamond, graphite, fullerene
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Oxygen Allotropes
Oxygen: O2 (air) and O3(Ozone)
 Different molecular forms
 Different physical and chemical properties
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Carbon Allotropes
Diamond, graphite, fullerene
 Different molecular forms
 Different physical and chemical properties
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Phosphorous Allotropes
Red, Black and White
 Different molecular forms
 Different physical and chemical properties
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Chemical Bonding
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Why do Atoms Bond?
 to get a full valence shell of electrons,
and become more stable.
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Octet Rule
 atoms need 8 electrons in their valance
shell to be stable.
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Properties of a Bonded Atom
 Lower energy than that of the unbonded atom.
 More stable than the unbonded atom
 Similar to the nearest noble gas (Group 18)
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Potential Energy
 Stored energy in bonds of substances.
 Depends on compositions and structure
of the substance.
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Bond Formation
 Bond formation is exothermic (release energy)
H + I → H–I + energy
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Bond Breaking
 Endothermic (absorbs energy)
H– I + energy → H + I
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Intramolecular Forces




Bonding between atoms
Ionic
Covalent
metallic
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Ionic bonds: Transfer of electrons
Metal loses e- and become + ion
Nonmetal gains e- and become – ion
Electronegativity difference of 1.7 or greater
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Covalent bonds: sharing of electrons
 Two nonmetal share electrons
 Electronegativity difference is less than 1.7
 Can be polar, nonpolar, or network solid
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Single Covalent bond
H–H
H2
Two shared electrons
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Multiple Covalent bonds
Double O = O O2
Four shared electrons
Triple N ≡ N
N2
Six shared electrons
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Polar Covalent bond
 Unequal sharing of electrons by different nonmetal atoms.
 Electronegativity difference is less than 0 but
greater than 1.7.
 Ex. H2O (water), NH3 (ammonia)
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Nonpolar Covalent bond




Equal sharing of electrons by same nonmetal atoms.
Electronegativity difference is 0.
Found in diatomic (two-atom) molecules
Ex. H2 (hydrogen), O2 (oxygen), F2 (fluorine)
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Network Solid Covalent bond
 Found in hard substances with high melting points
 Ex. Diamond (C) and Silicon dioxide (SiO2)
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Metallic bond




A force holding atoms in a metallic substance.
Describes as “positive nuclei immersed in sea of
mobile electrons.”
Ex. Ca (calcium), Cu (copper), Fe (iron)
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Polar substances
 asymmetrical charge distribution in the molecules
 charges are not evenly distributed
 molecules have + and – ends (dipole)
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Nonpolar substances
 have molecules with symmetrical (even)
charge distribution.
 may contain nonpolar or polar bonds
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Nonpolar substances with nonpolar bonds
 nonpolar bonds between atoms (same nonmetal)
 nonpolar molecules (symmetrical charge distribution)
All diatomic elements
F2 (fluorine)
H2 (hydrogen)
O2 (oxygen)
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Nonpolar substances with polar bond
 Polar bonds between atoms (different nonmetal)
 nonpolar molecules (symmetrical charge distribution)
Examples
CH4 (methane)
CO2 (carbon dioxide)
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Degree of Bond Polarity
 Describes the extent of + and – charges of a bond or
molecule
 Depends on the electronegativity difference (ED)
between the atoms
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Relative Polarity: Compare ED
KCl
Electronegativity
Difference (ED)
3.2 - 0.8
2.4
Largest ED (KCl)
 most ionic
 most polar
 least covalent
KBr
3.0 – 0.8
2.2
KI
2.7 – 0.8
1.9
Smallest ED (KI)
 least ionic
 least polar
 most covalent
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Summary of Properties of Solids
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Valence Electrons
 electrons in the outermost energy level of an atom
26.981
Al
2–8–3
Al has 3 valence e- (last number).
Use the Periodic Table.
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Valence Electrons
 Valence electrons are lost and gain in ionic bonding,
and are shared in covalent bonding.
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Electron-dot Diagrams for Atoms
 symbol of an atom surrounded by dots equal
to the number of valence electrons
F
26.981
S
2–7
K•
••
 F


2–8–8-1
Ne
2–8–6
••
•S•

2–8
••
Ne


K
32.099
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
18.998
26.981
Electron-dot Diagrams Ions
-1
18.998
F
K+
2–7
2–8–6
••
F

-
••
S


2–8–8-1
S

K
-2
32.099

+1

26.981
2-
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Electron Dot Diagrams for Ionic Compounds
 must show electron dots for both the +ion and –ions,
and the correct number of each ion.
-
K+
••
S




K+
••
F

potassium sulfide (K2S)

potassium fluoride (KF)
2- K+
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Electron-dot Diagrams Covalent Compounds
 must show all shared and unshared valence electrons
for both atoms.
carbon dioxide (CO2)




••
••
O C O


••
••
O =C= O








-

H

H

•• ••
Br Br
 
•• ••
Br – Br
 

••
Br

••
Br


bromine (Br2)

hydrogen bromide (HBr)
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Hydrogen Bonding
 A very strong intermolecular force that
exists in highly polar substances
 H2O (water),
 NH3 (ammonia)
 HF (hydrogen fluoride)
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Hydrogen Bonding
 Accounts for much higher boiling of water (H2O)
when compared to similar substances (H2S, H2Te)
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Hydrogen Bonding
 Accounts for much higher boiling of water (H2O)
when compared to similar substances (H2S, H2Te)
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Chemical Formulas
and Equations
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Chemical Formula
 Qualitative and quantitative composition of
pure substances (elements & compounds)
Ex. NaCl , H2O, KNO3
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Counting Atoms
H2SO4
2H 1S 4O
7 Total atoms
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Counting Atoms: Formulas with Parenthesis
(NH4)2O
2N 8H 1O
11 Total atoms
(4 x 2)
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Counting Atoms in hydrates:
CuSO4•5H2O
1Cu 1S 10H 9O
5x2
(4O + 5O)
‘21 Total atoms
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Types of Chemical Formulas
 Molecular
 Structural
 Empirical
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Molecular formula
 Shows the true composition of a known
substance.
H2O
C2H6
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Structural formula
 Shows arrangement of atoms in a substance
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Empirical formula
 shows atoms in the simplest whole-number ratio.
CH4
P2Cl3
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Types of Formulas
Molecular
H2O
C2H6
Structural
Empirical
O
H2O
H
H
H H
I I
H–C–C–H
I I
H H
CH3
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Reducing Molecular to Empirical
 Find the Greatest Common Factor (GCF) to all subscripts
 Divide each subscript of the formula by the GCF
Molecular
GCF:
Empirical Formulas:
NO2
K2S2O4
1
2
NO2
KSO2
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C3H6
3
CH2
Binary Compounds
Magnesium fluoride
Barium oxide
Mg2+F1-
Ba2+O2-
Mg1F2
Ba2O2
MgF2
BaO
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Polyatomic ion (Table E) Compounds
Sodium sulfate
ammonium sulfide
Na1+(SO4)2-
(NH4)1+S2-
Na2(SO4)1
(NH4)2S1
Na2SO4
(NH4)2S
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Compounds with multiple oxidation # atom
Titanium(II) oxide
Titanium(III) oxide
Ti2+O2-
Ti3+O2-
Ti2O2
Ti2O3
TiO
Ti2O3
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Naming Binary compounds
ZnBr2
zinc bromide
SrO
strontium oxide
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Naming Polyatomic ion Compounds
Table E
NaClO3
sodium chlorate
NH4Cl
ammonium chloride
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Types of Equations
Chemical change
2H2(g) + O2(g) → 2H2O(l)
Physical change
H2O(l)
Nuclear change
.
220Fr
→
→
4He
H2O(s)
+ 216At
.
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Chemical equation
 Shows changes in chemical composition
of one more substances
2H2(g) + O2(g)
→
2H2O(l)
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Types of Chemical reactions




synthesis
decomposition
single replacement
double replacement
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Synthesis
 Two or more substances combine to one
2H2
+ O2 →
2H2O
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Decomposition
 One substance breaks apart
2KClO3 →
2KCl
+
3O2
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Single replacement
 A more reactive element replaces
another element of a compound
Zn +
2HCl → ZnCl2 +
H2
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Double replacement
 Ions of two solutions switch to produce
a precipitate (solid)
NaCl + AgNO3 → NaNO3 + AgCl
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Law of Conservation
 Atoms, mass, charge and energy are
neither created nor destroyed in a reaction.
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Balanced Equations
 Equations that show conservation of atoms and charges.
N2
+
3 H2 → 2 NH3
2N
2N
6H
6H
atoms of reactants = atoms of product
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Unbalanced
Balanced
Li3N
2Li3N
Sum of coefficients = 2
→ Li
+ N2
→ 6Li + N2
+
6
+ 1 = 9
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Unbalanced Ca(OH)2 +
Balanced
Sum
H3PO4 → Ca3(PO4)2 + H2O
3Ca(OH)2 + 2H3PO4 → Ca3(PO4)2 + 6H2O
= 3
+
2
+ 1
+
of coefficients
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6 = 12
Unbalanced
C3H4 + O2 → CO2 + H2O
Balanced
C3H4 + 4O2 → 3CO2 + 2H2O
Sum of
coefficients
1
+ 4
+ 3
+ 2 = 10
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Moles Interpretations
and Calculations
Gram Atomic Mass
Mass of 1 mole of element = Atomic Mass
107.868
Ag
47
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Gram Formula Mass
 Mass of 1 mole of Compound
 Gram-formula mass = the sum of atomic masses
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Calculating Gram-formula Mass
What is the gram-formula mass of Al2(SO4)3 ?
Gram-formula mass = 2(Al) + 3(S)
numerical setup
+ 12(O)
= 2(27 g) + 3(32 g) + 12(16 g)
Gram-formula mass = 342 g
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Mass from Moles Calculation
Mass = moles x formula mass
What is the mass of 2.5 moles of Al2(SO4)3 ?
Mass =
2.5
x
342 = 855 g
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Moles from Mass Calculation
Mass
Moles = ---------------formula mass
Table T
How many moles are represented in 200. grams of Al2(SO4)3 ?
200.
Moles = -------- = 0.580 mol
342
Percent Composition by Mass
Total mass of an atom
% = ---------------------------- x 100
Formula mass
Table T
.
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What is the percent composition of Al, S, and O
in the formula Al2(SO4)3 ?
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Percent Composition of a Hydrate Calculation
Portion of a hydrate’s mass that is due to the mass
of the water (or the anhydrous).
Total mass of H2O
% H2O = --------------------- x 100
Formula mass
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What is the percent of water in the
hydrate CaCO3  4H2O ?
Find the mass of 4H2O:
8 H = 8(1) = 8 g
72 g H2O
4 O = 4(16) = 64 g
72
% H2O = -------- = 42 %
172
Mole Ratios in Equations
4NH3 +
5O2 →
4NO +
6H2O
Mole ratio of NH3 to O2 is 4 : 5
Mole ratio of NO to H2O is 2 : 3
(reduced from 4 : 6)
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Mole-mole Problems - Example
4NH3 + 5O2 → 4NO + 6H2O
How many moles of H2O is produced when
2 moles of NH3 react with excess oxygen?
6 mol H2O
2 mol NH3 x ---------------- = 3 mol H2O
4 mol NH3.
Aqueous Solution
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Solution
a homogeneous mixture
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Aqueous Solution
 A mixture made with water as the solvent
NaCl(s) + H2O(l) → NaCl(aq)
solute
solvent
Aqueous solution
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Properties of solution





Are homogenous (uniformly mixed)
Are generally clear
Are transparent
Can be colorful (contain transition metal)
Particles will not settle upon standing
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Crystallization
 A process of recovering salt (solute) from a mixture by
evaporating (or boiling) off the liquid (solvent).
.
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Solubility
 Extent to which a substance dissolves.
 Solubility is a physical property.
.
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Table F: Soluble and Insoluble Ions
LiCl (lithium chloride) is soluble
KOH (potassium hydroxide) is soluble
AgCl (silver chloride) is insoluble.
Mg(OH)2 (magnesium hydroxide is insoluble
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Factors that affect solubility
 temperature
 pressure
 nature of solute
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Temperature Effect on Solubility:
Solid solute
Gaseous solute
↑ Temperature ↑Solubility
More KCl(s) will dissolve
in water at 40oC than at 25oC
↑ Temperature ↓Solubility
Fewer O2(g) will dissolve
in water at 40oC than at 25oC
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Pressure Effect on Solubility:
Solid solute
Gaseous solute
Change in Pressure has
no effect on solubility
↑ Pressure ↑Solubility
More O2(g) will dissolve in water
at 0.4 atm than at 0.2 atm.
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Solubility Curve Table G
.
Solid solutes (ex. KCl, NaNO3)
 Solubility increases as water
temperature increases
Gaseous solutes (ex. NH3, HCl )
 Solubility decreases as water
temperature increases
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Descriptions of solutions
 Saturated
 Unsaturated
 Supersaturated
- Dilute
. Concentrated
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Solubility Curve: Table G
Describing Solutions A, B and C at 60oC.
A is a supersaturated solution
(above the curve)
A
.
B
B is a saturated solution
(on the curve)
C
C is an unsaturated solution
(below the curve)
.
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Solubility Curve: Table G
Comparing the Solubility of Substances at 40oC
A
.
Substance A is the most soluble (highest up).
Solution A is most concentrated
and least dilute
C
Substance C is the least soluble (lowest down)
Solution A is least concentrated
and most dilute
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Concentration
 How much solute is in a given amount of
solution (or solvent)
 Molarity and parts per million
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Molarity (M or mol/L)
 Shows concentration moles of solute
per (for every) liter of the solution.
moles of solute
. Molarity = ---------------------- = mol/L
liter of solution
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Parts per million (ppm)
 Shows concentration in grams of solute
per (for every) one million parts of the solution.
Grams Solute
ppm = -------------------- x 1000000
Grams Solution
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Vapor
 A gas form of a substance that is normally a
liquid at STP
.
Ex. Water vapor is a gas form of water.
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Vapor Pressure
 The pressure exerted by vapor on the
surface of a liquid.
 Depends on the temperature of the samples
As temperature ↑, Vapor Pressure (VP) ↑
 Any liquid has a higher vapor pressure at
50oC than at 35oC
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Boiling Point (BP
 The temperature of a liquid at which the
vapor pressure equals the atmospheric pressure.
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Reading Table H: Vapor Pressure of Liquids
c
.
 At 75oC, ethanol has a vapor pressure
of 85 kPa.
 At atmospheric pressure of 60 kPa,
water will boil at a temperature of 87oC.
 The normal boiling point of propanone
is 56oC.
 Propanone (lowest BP at any temperature)
has the weakest IMF, and ethanoic acid
(highest BP at any temp) has the strongest
IMF of the four liquids.
Effect of Solute
When a solute is dissolved in water to make a solution:
 The Boiling Point of the solution is elevated (increased).
 The Freezing Point of the solution is depressed (decreased).
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 A solution always a lower freezing point
and a higher boiling point than water
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 A 2.0 M solution has a lower freezing point and
a higher boiling point than a 1.0 M solution
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 A 1.0 M KCl (ionic) solution has a lower freezing
point and a higher boiling point than a
1.0 M C6H12O6 (molecular) solution
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Acids, Bases and Salts
.
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Arrhenius Acids
 Produce H+ (hydrogen ion, proton) as
the only positive(+) ion in solutions
.
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Properties of Acids





produce H+ ions
turn litmus red
has pH below 7
phenolphthalein is colorless (no effect)
react with some metals
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Arrhenius Bases
 Produce OH- (hydroxide ion) as
the only negative (-) ion in solutions
.
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Properties of Bases




produce OH- ions
turn litmus blue
phenolphthalein is pink
has pH above 7
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Alternate Theories
 Acids donate protons (H+, hydrogen ion)
 Bases accept protons (H+, hydrogen ion)
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Acid–Metal Reaction
 Produces hydrogen gas and a salt.
metal
+ acid
→ hydrogen + salt
 All metals above H2 (Li to Pb) will react with an acid.
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All metals above H2 (Li to Pb) will react
spontaneously with an acid.
Ex:
Zn
+ 2HCl → H2 + ZnCl2
All metals below H2 (Cu to Au) will not react
spontaneously with an acid.
Neutralization Reaction
 When equal number of moles of an
acid and a base react.
Acid + Base → Water + Salt
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Examples of Neutralization reactions
Acid + Base → Water + Salt
HCl
+ KOH → H2O + KCl
H+
+
OH– → H2O (net ionic equation)
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Titration
 A neutralization lab used in determining the
unknown concentration or volume of
acid or base solution.
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Titration Equation
 Use the Titration Equation on Table T to
setup and solve a neutralization problem.
Macid Vacid = Mbase Vbase
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Relating pH to H+ Concentration
1 value difference in pH = 10 fold difference in H+
A change in solution from:
pH 2 to pH 3 = 10 times decrease in H+ concentration
pH 2 to pH 4 = 100 times decrease in H+ concentration
pH 3 to pH 1 = 100 times increase in H+ concentration
pH 4 to pH 1 = 1000 times increase in H+ concentration
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Electrolytes
 Substances that conduct electricity when dissolved in water.
 Aqueous solutions of electrolytes conduct electricity because
they contain mobile ions.
 Acids (Table K), bases (Table L) and salts are electrolytes.
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Kinetics and Equilibrium
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Kinetics
 The study of rates and mechanisms of reactions
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Collision Theory
 For a chemical reaction to occur, reacting
particles must collide effectively
.
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Effective Collision
 Collision of particles with sufficient kinetic energy
and at appropriate orientation (angle)
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Activation Energy
 Energy needed to start a reaction
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Catalyst
 increases rate of a reaction by lowering activation
energy (alternate pathway),
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Factors that Increase rate and how.
 Increasing Concentration (↑ frequency of collision)
 Increasing Temperature (↑ energy of particles & collision)
 Increasing Pressure (↑ concentration)
 Increasing Surface Area (exposes more area for reaction)
 Adding Catalyst
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Potential Energy (PE)
 Stored energy in chemical compounds.
 Depends on the composition and structure of a
substance
.
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Potential Energy Diagram
 A diagram showing changes in energy contents
of substances in a reaction.
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.
Potential Energy (PE) Measurements Substances
(a) PE of the reactants
(b) PE of the products
(c) PE of the activated complex
(no change with catalyst)
(no change with catalyst)
(lower with catalyst)
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.
Differences in Potential Energy Measurements
(d) Heat of reaction, ∆H (b – a )
(e) Activation energy forward reaction (c – a)
(f ) Activation energy for reverse (c – b)
(no change with catalyst)
(lower with catalyst)
(lower with catalyst)
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Heat of Reaction (∆H)
 The difference (energy change) between the
PE of the products and the PE of the reactants.
∆H = PE of products
– PE of reactants
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Exothermic Reactions (–∆H)
 Reactants have less energy than products
 Energy is released (or lost) to the surrounding
 Increase in temperature of the surrounding
Mg + 2HCl
→ MgCl2 + H2 + Energy
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Endothermic Reactions (+∆H)
 Reactants have more energy than products
 Energy is absorbed (or gain) from the surrounding
 Decrease in temperature of the surrounding
NH4Cl(s) + Energy → NH4+(aq) + Cl– (aq
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Reference Table I - Heat of Reaction
. All reactions with a –∆H are exothermic (they release energy)
Making 2 moles of Al2O3(s) releases 3351 kJ of energy.
Making 1 mole of Al2O3(s) releases 1675.5 kJ (half the energy)
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Reference Table I – Heat of Reactions
All reactions with a +∆H are endothermic (they absorb energy)
Making 2 moles of NO2(g) absorbs 66.4 kJ of energy.
Making 4 moles of NO2(g) absorbs 132.8 kJ (twice the energy)
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Equilibrium
 A state of balance between two opposing forces.
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At Equilibrium
 Rates (speed) of forward and reverse reactions are
equal
 Concentration (amount) of reactants and products stay
constant
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Le Chatelier’s Principle
 A chemical or physical process will shift (speeds
up or slows down) in one direction to relieve any
added stress
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Increasing Concentration (Stress)
.
more N2 added
H2 concentration
decreases
forward rate increases
reverse rate decreases
NH3 concentration
increases
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Decreasing Concentration (stress)
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Increasing Temperature (Stress)
 Speeds up or favors the endothermic reaction.
 Rate increases in the direction away from heat
.
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Increasing Pressure (Stress)
 Favors or speeds up a reaction toward the side that
has fewer total moles of substances.
.
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Equilibrium
Graph
reaction at equilibrium
(constant concentration)
Stress (H2)
added
A new equilibrium is reached
(concentrations of H2, NH3
and N2 stay constant, again)
Organic Compounds
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Organic Compounds
 Compounds of carbon ( C )
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Hydrocarbons – Table Q
 Contain only hydrogen and carbon atoms.
 Alkanes, alkenes, and alkynes
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Alkane hydrocarbons
Each single covalent bond
contains 2 shared electrons
Propane has 10 bonds
or 20 shared electrons
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Alkene hydrocarbons
..
Propene has 9 bonds
or 18 shared electrons
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Alkyne hydrocarbons
..
.
Propyne has 8 bonds
or 16 shared electrons
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Functional Groups Table R
Isomers
 Organic compounds with the same molecular formula
but different structural formulas and properties.
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Isomers
CH3CH2CH2Br
and CH3CHBrCH3
(2-bromopropane)
(1-bromopropane)
are isomers.
 Same molecular formula.
 Same type and number of atoms.
 Same percent composition.
 Same number of bonds.
 Different compounds
 Different properties
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Isomers
 As the number of C atoms increases, the
number of possible isomers also increases.
Ex: C5H12 has more isomers than C4H10.
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Alkane isomers
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Alkyne isomers
..
Alkene isomers
.
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Alkyne isomers
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Halide isomers
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Alcohols isomers
 The –OH is on different C atoms
.
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Ether and Alcohol isomers
 An ether and alcohol of the same number of C atoms
are always isomers
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Ester Isomers
..
.
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Ketone and Aldehyde Isomers
 A ketone and an aldehyde of the same number of
C atoms are always isomers
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Organic Acids
(the two below are not isomers, but learn to
recognize and draw organic acids
.
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Amines and Amides
(not isomers, but learn to recognize and draw them)
.
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Substitution
 Reactions of alkanes
 H of an alkane is replaced by a halogen
.
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Addition: Hydrogenation
 A reaction of alkenes
 A double bond is broken up to bond two H atoms
.
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Addition: halogenation
 A reaction of alkenes
 A double bond is broken up to bond two halogens
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Esterification
Making an ester from an acid and alcohol
..
.
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Esterification
 Making an ester from an acid and alcohol
..
.
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Condensation Polymerization
 Joining small molecules by removing water
.
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Addition Polymerization
 Joining without removing water
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Saponification
 Soap making process
Fat + Base → Soap +
Glycerol
H H H
I I I
H–C–C –C–H
I I I
OH OH OH
1,2,3-propanetriol
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Fermentation
 Ethanol (an alcohol) making process
sugar
C6H12O6
enzyme
zymase
ethanol + carbon dioxide
2C2H5OH +
2CO2
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Combustion
 Burning with oxygen
Organic + oxygen → carbon + water
compound
dioxide
2C8H18
+
25O2 → 16CO2 + 18H2O
Octane
(car fuel)
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Redox and Electrochemistry
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Redox
 Reactions that involve reduction (gain of electron)
and oxidation (loss of electrons).
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Types of Redox Reactions
Synthesis
Decomposition
Single replacement
Simplified redox
.
2H2 + O2 → 2H2O
CaCO3 → Ca
+
CO3
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Cu0 + 2Ag+
→ Cu2+ + 2Ag0
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Non-redox reactions
Double Replacement KI + AgNO3 → AgI + KNO3
Ions combining
Na+ + Cl–
→ NaCl
Ionization
H2O → H+ + OH–
-
.
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The charge an atom has or appears to have in a reaction.
Oxidation Numbers
Oxidation
numberanofatom
an atom
zero (0)to
, negative
or positive
 The charge
hascan
orbe
appears
have in(-)a reaction.
I
(+).It can be a zero, + or Li has an oxidation number of 0.
Li+ has an oxidation number of +1.
P3– has an oxidation number of -3.
.
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Free element
 Oxidation number of a free element is always zero
Na + Cl2 → NaCl
Na and Cl2 are both free elements.
Their oxidation number is zero: Na0, Cl20
.
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Compounds
 Oxidation numbers of elements in compounds are given
on the Periodic Table (with few exceptions).
Na + Cl2 → NaCl
compound
Oxidation number of Na in NaCl is +1
22.989
+1
Na
11
-1
35.453
Oxidation number of Cl in NaCl is -1
Cl
17
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Compounds
 The sum of oxidation numbers in compounds must be 0.
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Oxidation
 Loss of Electron is Oxidation (LEO)
Mg0 → Mg2+ + 2e–
 Oxidation number of the oxidized substance increases
0 → 2+
.
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Reduction
 Gain of Electrons is Reduction (GER)
Cl0
+ 2e- → Cl–
 Oxidation number of the reduced substance decreases
0 → -1
.
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Voltaic Cell




.
Converts chemical energy to electrical energy.
Redox reaction is spontaneous and exothermic.
Oxidation and reduction occur in separate cells.
Battery is a type of a voltaic cell.
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Electrolytic Cell
 Converts electric energy to chemical energy.
 Redox reaction is nonspontaneous and endothermic.
 Oxidation and reduction occur in one cell
.
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Electrodes
 Sites on electrochemical cells where oxidation
and reduction take place
 Anode and Cathode
.
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Anode: oxidation
 Site where electrons are lost (oxidation)
 AnOx (Anode is for Oxidation)
.
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Cathode : reduction
 Site where electrons are gained (reduction)
 RedCat (Reduction occurs at Cathode)
.
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Salt Bridge (Path for ions)
 Path for ions to travel between the
two cells of a voltaic cell, only.
.
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Wire, external conduit (path for electrons)
 Path for electrons to travel from the anode to cathode
 found in both the voltaic and electrolytic cells.
.
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Battery (power supply)
 Supplies energy to force a redox reaction in
electrolytic cells, only.
.
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LEO
Loss of Electrons is Oxidation
GER:
Gain of Electrons is Reduction
.
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An Ox
Anode is the site for Oxidation
Red Cat
Reduction occurs at Cathode
.
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APE
Anode is Positive in Electrolytic
CPV
Cathode is Positive in Voltaic
.
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VAN
In Voltaic, Anode is Negative
CEN
Cathode in Electrolytic is Negative
.
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Voltaic Cells: The Electrodes
Zn: anode (+)
 oxidized
 loses e loses mass
(because Zn atoms are
changing to Zn2+ ions)
.
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Voltaic Cells: The Electrodes
Fe: cathode (-)
 gains mass
(because more Fe atoms
are being made from
Fe3+ ions)
Fe3+ ion
 reduced
 gains eCopyright © E3 Scholastic Publishing. All Rights is Reserved. Survivingchem.com
Voltaic Cells: Directions of Electrons and Ions
electrons
.
ions
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Voltaic Cells: Using Table J
More reactive than Zn.
Can replace Zn in this
reaction
Less reactive than Zn.
Cannot replace Zn in this
reaction
Zn is more active
than Fe.
Zn (the more active
of the two metals) is
always the Anode
(oxidized)
Electrolytic Cell: Electroplating
electron
Object (key) on –end of battery
 always the cathode
 gains mass
Battery
 must be present
to provide energy
.
Metal (Ag) on +end of battery
 always the anode
 loses mass
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Nuclear Chemistry
.
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Transmutation: Nuclear reactions
 Changing (converting) one atom to another.
 Particles are absorbed and/or released by the nucleus
.
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Nuclear Chemistry Particles: Table O
 Use this table to compare mass and charge of particles
.
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Radioisotopes: Table N
 Any radioactive (unstable) isotope of an element.
.
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Alpha emitters
 A radioisotope that decays by releasing an
alpha particle (+α)
See Table N
220 Fr and 238U
.
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Beta emitters
 A radioisotope that decays by releasing a
beta particle (-β)
Examples (See Table N)
60Co
.
and
14C
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Positron emitters
 A radioisotope that decays by releasing a
beta particle (+β)
Examples (See Table N)
53Fe
and
.
37Ca
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Natural Transmutation
 When a single unstable radioactive nucleus
spontaneously decays (breaks down) to another nucleus.
 alpha decay
 beta decay
 positron emission.
.
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Alpha Decay (natural transmutation)
238 U
92
.
→
4 He
2
+
234 Th
90
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Beta Decay (natural transmutation)
14 C
6
→
.
0e
-1
+
14 N
7
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Positron Emission (natural transmutation)
37Ca
20
→
.
0e
+1
+
37 K
19
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Artificial Transmutation
 When a stable non-radioactive nucleus is bombarded (hit)
with a particle to produce an unstable (radioactive) nucleus
4He
+
2
.
9 Be
4
→
12 C
6
+
1n
0
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Fission (nuclear energy)
1n
0
+
235 U
92
→
91 Kr
36
+
142 Ba
56
+ 310 n + energy
 Produces greater amount of energy than any
chemical reaction
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Fission (nuclear energy)
1H
1
+
2H
1
→
3 He
2
+ energy
 Produces greater amount of energy than any
fission reactions
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Fusion (nuclear energy)
1n
+
235 U
→
91 Kr
+
142 Ba
+ 31 n + energy
 Produces greater amount of energy than any
chemical reaction
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Completing Nuclear Equation: find X
 Nuclear equation must be balanced
 Top numbers and bottom numbers must be equal on
both sides
Given:
239 Pu
→
4 He
+
X.
Completed:
239 Pu
→
4 He
+
235U.
94
94
2
2
92
92 is the determined atomic
number for X. Use the
Periodic Table to get the correct
element symbol (U).
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Writing a Decay Equation for: Iodine -131
step 1
step 2
Write
Write
nuclide
→ decay mode
+
symbol
symbol
(Use Table N)
(Use Table N and O)
131
53
.
I
→
0e
-1
+
step 3
Determine
Top #, bottom #, and
atom symbol to balance
131
54
Xe
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Half-life
 the time it takes for half of radioisotope to decay
to new atoms.
 Pressure, temperature, or amount of a radioisotope
does not change its half-life.
 Each radioisotope has its own half-life (see Table N).
.
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Half-life
 Pressure, temperature, or amount of a radioisotope
does not change its half-life.
 Each radioisotope has its own half-life (see Table N).
.
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Table N
 Use this table to determine and compare
half-lives and decay modes for given
radioisotopes.
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Half-life Period
 The number of times a radioisotope decays by half
 The number of half-life periods must be known
(or determined) in order to solve any half-life problem
.
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Determine Half-life Period from Time
 use the equation below
Length of Time (T)
Half-life Period (n) = ------------------------Half – life (t)
.
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Determine Half-life Period from Mass
From Original Mass of 50 g to Remaining Mass of 6.25 g
 Cut original mass in half a many times as it takes to get
to the remaining mass
50 g
→
25 g
→ 12.5 g
→
6.25 g
3 cuts in half = 3 half-life periods
Note: Double the mass if going from remaining mass to original mass
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Fraction of Radioisotope Remaining
 Once the number of half period (n) is known or determined
use the equation below.
1
Fraction remaining = ------
2n
.
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Medical Field Radioisotope Tracers
 must have
short half-lives
and be
quickly eliminated
from the body
Radioisotope
Name
Radioisotope Common Applications
Symbol
and Benefits
Iodine-131
131I
Thyroid disorder;
diagnosis and treatment
Technetium-99
99Tc
Cancer tumor diagnosis
60Co
Cancer treatment
56Fe
Blood disorder
treatment
Cobalt-60
Iron-56
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Research and Dating Radioisotopes
 typically have
long half-lives
Radioisotope
Name
Radioisotope Common Applications
Symbol
and Benefits
Carbon-14 (alone)
14C
Carbon-14
14C
with
.
Carbon-12
12C
Uranium – 238
238U
with
Lead - 206
206Pb
Tracer for chemical
reactions
Fossil (archeological)
dating
Rock (geological)
dating
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