4/13/22, 3:50 PM

Solved: An experiment has three steps with three outcomes possi... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
1 Bookmark
Chapter 4, Problem 1E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
An experiment has three steps with three outcomes possible for the first step, two outcomes
Continue to post
possible for the second step, and four outcomes possible for the third step. How many
1 question remaining
experimental outcomes exist for the entire experiment?
My Textbook Solutions
Step-by-step solution
Step 1 of 1
Statistics for
Business &...
A First
Course in...
Differential
Equations..
outcomes possible for the second step, and four outcomes possible for the third step.
14th Edition
8th Edition
6th Edition
The number of experimental outcomes is (3)(2)(4) = 24.
View all solutions
Given that an experiment has three steps with three outcomes possible for the first step, two
Comment
Was this solution helpful?
35
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1E-solution-9781337901062
1/3
4/13/22, 3:50 PM


Solved: An experiment has three steps with three outcomes possi... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1E-solution-9781337901062

2/3
4/13/22, 3:50 PM


Solved: An experiment has three steps with three outcomes possi... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1E-solution-9781337901062
3/3
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 1CP1
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Hamilton County Judges
Continue to post
1 question remaining
Hamilton County judges try thousands of cases per year. In an overwhelming majority of the
cases disposed, the verdict stands as rendered. however, some cases are appealed, and of
those appealed, some of the cases are reversed. Kristen DelGuzzi of the Cincinnati Enquirer
conducted a study of cases handled by Hamilton County judges over a three-year period. Shown
in Table 4.8 are the results for 182,908 cases handled (disposed) by 38 judges
My Textbook Solutions
TOTAl CASES DISPOSED, APPEALED, AND REVERSED IN HAMILTON COUNTY COURTS
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
in Common Pleas Court, Domestic Relations Court, and Municipal Court. Two of the judges
(Dinkelacker and hogan) did not serve in the same court for the entire three-year period.
The purpose of the newspaper’s study was to evaluate the performance of the judges. Appeals
are often the result of mistakes made by judges, and the newspaper wanted to know which
judges were doing a good job and which were making too many mistakes. you are called in to
assist in the data analysis. use your knowledge of probability and conditional probability to help
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
1/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
with the ranking of the judges. you also may be able to analyze the likelihood of appeal and
Study
tools
Mycourts.
courses
for cases
handled
by different
reversalHome


My books
My folder
Career
Life

Managerial Report
Prepare a report with your rankings of the judges. Also, include an analysis of the likelihood of
appeal and case reversal in the three courts. At a minimum, your report should include the
following:
1. The probability of cases being appealed and reversed in the three different courts.
2. The probability of a case being appealed for each judge.
3. The probability of a case being reversed for each judge.
4. The probability of reversal given an appeal for each judge.
5. Rank the judges within each court. State the criteria you used and provide a rationale for your
choice.
Step-by-step solution
Step 1 of 10
1.
Consider the case of Hamilton country Judges. Judges in Common Pleas court, Domestic
relations court and Municipal court are considered. Data of cases disposed, appealed, and
reversed are collected. Part of data collected is shown below:
Judge
Disposed Appealed Reversed Court
Fred Cartolano
3037
137
12
Common
Thomas Crush
3372
119
10
Common
Patrick Dinkelacker 1258
44
8
Common
Timothy Hogan
1954
60
7
Common
Robert Kraft
3138
127
7
Common
Comment
Step 2 of 10
Now, use excel web file to have the desired values. So, the total number of cases appealed in
Common pleas court is obtained by the formula:
The total number of cases reversed in Common pleas court is obtained by the formula
The screenshot is given as below:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
2/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 10
Hence probability that cases are appealed and reversed in Common pleas court is:
Similarly total number of cases appealed and reversed in Domestic relations court is:
Hence probability that cases are appealed and reversed in Domestic relations court is:
Similarly total number of cases appealed and reversed in Municipal court is:
Hence probability that cases are appealed and reversed in Municipal court is:
Comment
Step 4 of 10
2.
Probability that a case is appealed is obtained by:
Where,
Number of cases appealed
Number of cases disposed
In excel enter the following formula in cell F2 and copy till F41:
So, the probability that case is appealed for each judge is given below:
Judge
Probability of Appealed cases
Fred Cartolano
0.045110306
Thomas Crush
0.035290629
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
3/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
Patrick Dinkelacker

Home
0.034976153
Study tools

My courses
Timothy Hogan
0.030706244
Robert Kraft
0.040471638
William Mathews
0.040194346
William Morrissey
0.039907652
Norbert Nadel
0.044271713
Arthur Ney Jr.
0.038831935
Richard Niehaus
0.040858932
Thomas Nurre
0.040333333
John O'Connor
0.043448973
Robert Ruehlman
0.04524181

My books
My folder
Career
Life

J. Howard Sundermann Jr. 0.062827225
Comment
Step 5 of 10
Ann Marie Tracey
0.040432983
Ralph Winkler
0.028488184
Penelope Cunningham
0.002565042
Patrick Dinkelacker
0.003166139
Deborah Gaines
0.005455165
Ronald Panioto
0.002467232
Mike Allen
0.006993007
Nadine Allen
0.004352279
Timothy Black
0.005154639
David Davis
0.005558428
Leslie Isaiah Gaines
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
4/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
0.006626278
Home
Karla Grady
Study tools

My courses

My books
My folder
Career
Life

0.001142204
Deidra Hair
0.001974724
Dennis Helmick
0.003670886
Timothy Hogan
0.005632582
James Patrick Kenney
0.002144389
Joseph Luebbers
0.005321413
William Mallory
0.004591035
Melba Marsh
0.004136756
Beth Mattingly
0.004375631
Albert Mestemaker
0.005628141
Mark Painter
0.003126396
Jack Rosen
0.005263158
Mark Schweikert
0.006107718
David Stockdale
0.004096071
John A. West
0.001430104
Comment
Step 6 of 10
3.
The probability that a case is reversed is obtained by:
Where,
Number of cases reversed
Number of cases disposed
In excel enter the following formula in cell G2 and copy till G41:
So, the probability that case is reversed for each judge is given below:
Judge
Probability of Reversed Cases
Fred Cartolano
0.003951268
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
5/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
Thomas Crush

Home
0.002965599
Study tools

My courses
Patrick Dinkelacker
0.0063593
Timothy Hogan
0.003582395
Robert Kraft
0.00223072
William Mathews
0.00795053
William Morrissey
0.007255937
Norbert Nadel
0.00675904
Arthur Ney Jr.
0.004349177
Richard Niehaus
0.004771846
Thomas Nurre
0.002
John O'Connor
0.004041765
Robert Ruehlman
0.005616225

My books
My folder
Career
Life

J. Howard Sundermann Jr. 0.010471204
Ann Marie Tracey
0.004138809
Ralph Winkler
0.001942376
Penelope Cunningham
0.000366435
Patrick Dinkelacker
0.000666556
Deborah Gaines
0.001022844
Ronald Panioto
0.000231303
Mike Allen
0.000650512
Nadine Allen
0.000768049
Timothy Black
0.000754337
David Davis
0.000646329
Leslie Isaiah Gaines
0.002461189
Karla Grady
0
Deidra Hair
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
6/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
Dennis Helmick

Home
0.000632911
Study tools

My courses
Timothy Hogan
0.000866551
James Patrick Kenney
0.000357398
Joseph Luebbers
0.001702852
William Mallory
0.00108735
Melba Marsh
0.000851685
Beth Mattingly
0.000336587
Albert Mestemaker
0.001809045
Mark Painter
0.001339884
Jack Rosen
0.001668806
Mark Schweikert
0.001110494
David Stockdale
0.00074474
John A. West
0.000715052

My books
My folder
Career
Life

4.
Probability that a case is reversed given an appeal is obtained by:
Where,
Number of cases reversed
Number of cases appealed
In excel enter the following formula in cell G2 and copy till G41:
So, the probability that case is reversed given an appeal for each judge is given below:
Judge
Probabiliy of Reversed cases that are Appealed
Fred Cartolano
0.087591241
Thomas Crush
0.084033613
Patrick Dinkelacker
0.181818182
Timothy Hogan
0.116666667
Robert Kraft
0.05511811
William Mathews
0.197802198
William Morrissey
0.181818182
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
7/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
NorbertHome
Nadel
Study tools

My courses
0.152671756
Arthur Ney Jr.
0.112
Richard Niehaus
0.116788321
Thomas Nurre
0.049586777
John O'Connor
0.093023256
Robert Ruehlman
0.124137931

My books
My folder
Career
Life

J. Howard Sundermann Jr. 0.166666667
Ann Marie Tracey
0.102362205
Ralph Winkler
0.068181818
Penelope Cunningham
0.142857143
Patrick Dinkelacker
0.210526316
Deborah Gaines
0.1875
Ronald Panioto
0.09375
Mike Allen
0.093023256
Nadine Allen
0.176470588
Timothy Black
0.146341463
David Davis
0.11627907
Leslie Isaiah Gaines
0.371428571
Karla Grady
0
Deidra Hair
0
Dennis Helmick
0.172413793
Timothy Hogan
0.153846154
James Patrick Kenney
0.166666667
Joseph Luebbers
0.32
William Mallory
0.236842105
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
8/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
Melba Marsh

Home
0.205882353
Study tools

My courses
Beth Mattingly
0.076923077
Albert Mestemaker
0.321428571
Mark Painter
0.428571429
Jack Rosen
0.317073171
Mark Schweikert
0.181818182
David Stockdale
0.181818182
John A. West
0.5

My books
My folder
Career
Life

Comment
Step 7 of 10
5.
Judges whose probability of reversal given an appeal is lowest are ranked higher. This is
obtained using sort and filter. The steps are given as below:
STEP 1: Copy data in sheet 2 and select whole data and click sort and filter
STEP 2: Click Down arrow near court
STEP 3: Deselect “Select all” and select “Common”
STEP 4: Select data of column H.
STEP 5: Click Sort and Filter. Click Sort smallest to Largest.
Judges are sorted with lowest probability to highest as follows:
Judge
Disposed Appealed Reversed Court
Fred Cartolano 3037
137
12
Common
Thomas Nurre
3000
121
6
Common
Robert Kraft
3138
127
7
Common
Ralph Winkler
3089
88
6
Common
Thomas Crush 3372
119
10
Common
John O'Connor 2969
129
12
Common
Comment
Step 8 of 10
Ann Marie Tracey
3141
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
9/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
127
13
Home
Study tools

My courses

My books
My folder
Career
Life

Common
Arthur Ney Jr.
3219
125
14
Common
Timothy Hogan
1954
60
7
Common
Richard Niehaus
3353
137
16
Common
Robert Ruehlman
3205
145
18
Common
Norbert Nadel
2959
131
20
Common
J. Howard Sundermann Jr.
955
60
10
Common
Patrick Dinkelacker
1258
44
8
Common
William Morrissey
3032
121
22
Common
William Mathews
2264
91
18
Common
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
10/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 9 of 10
Similarly Judges in Domestic court are sorted as follows:
Judge
Disposed Appealed Reversed Court
Ronald Panioto
12970
32
3
Domestic
Penelope Cunningham 2729
7
1
Domestic
Deborah Gaines
8799
48
9
Domestic
Patrick Dinkelacker
6001
19
4
Domestic
Comment
Step 10 of 10
Judges in Municipal court are sorted as follows:
Judge
Disposed Appealed Reversed Court
Karla Grady
5253
6
0
Muni
Deidra Hair
2532
5
0
Muni
Beth Mattingly
2971
13
1
Muni
Mike Allen
6149
43
4
Muni
David Davis
7736
43
5
Muni
Timothy Black
7954
41
6
Muni
Timothy Hogan
2308
13
2
Muni
James Patrick Kenney 2798
6
1
Muni
Dennis Helmick
7900
29
5
Muni
Nadine Allen
7812
34
6
Muni
Mark Schweikert
5403
33
6
Muni
David Stockdale
5371
22
4
Muni
Melba Marsh
8219
34
7
Muni
William Mallory
8277
38
9
Muni
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
11/12
4/13/22, 3:49 PM

Solved: Hamilton County JudgesHamilton County judges try thousa... | Chegg.com
Jack Rosen
7790
Home
Study tools

41

13
My courses

Muni
My books
Joseph Luebbers
4698
25
8
Muni
Albert Mestemaker
4975
28
9
Muni
Leslie Isaiah Gaines
5282
35
13
Muni
Mark Painter
2239
7
3
Muni
John A. West
2797
4
2
Muni
My folder
Career
Life

Comment
Was this solution helpful?
2
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP1-solution-9781337901062
12/12
4/13/22, 3:50 PM

Solved: Rob’s Market (RM) is a regional food store chain in the... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 1CP2
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Rob’s Market (RM) is a regional food store chain in the southwest United States. David White,
Continue to post
Director of Business Intelligence for RM, would like to initiate a study of the purchase behavior of
1 question remaining
customers who use the RM loyalty card (a card that customers scan at checkout to qualify for
discounted prices). The use of the loyalty card allows RM to capture what is known as “point-ofsale” data, that is, a list of products purchased by customers as they check out of the market.
David feels that better understanding of which products tend to be purchased together could lead
My Textbook Solutions
to insights for better pricing and display strategies as well as a better understanding of sales and
the potential impact of different levels of coupon discounts. This type of analysis is known as
market basket analysis, as it is a study of what different customers have in their shopping
baskets as they check out of the store.
As a prototype study, David wants to investigate customer buying behavior with regard to bread,
jelly, and peanut butter. RM’s Information Technology (IT) group, at David’s request, has provided
a data set of purchases by 1000 customers over a one-week period. The data set is in the file
MarketBasket, and it contains the following variables for each customer:
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
• Bread—wheat, white, or none
• Jelly—grape, strawberry, or none
• Peanut butter—creamy, natural, or none
The variables appear in the above order from left to right in the data set, where each row is a
customer. For example, the first record of the data set is
which means that customer 1 purchased white bread, grape jelly, and no peanut butter. The
second record is
which means that customer 2 purchased white bread, strawberry jelly, and no peanut butter. The
sixth record in the data set is
which means that the sixth customer did not purchase bread, jelly, or peanut butter.
Other records are interpreted in a similar fashion.
David would like you to do an initial study of the data to get a better understanding of RM
customer behavior with regard to these three products.
Managerial Report
Prepare a report that gives insight into the purchase behavior of customers who use the RM
loyalty card. At a minimum your report should include estimates of the following:
1. The probability that a random customer does not purchase any of the three products (bread,
jelly, or peanut butter).
2. The probability that a random customer purchases white bread.
3. The probability that a random customer purchases wheat bread.
4. The probability that a random customer purchases grape jelly given that he or she purchases
white bread.
5. The probability that a random customer purchases strawberry jelly given that he or she
purchases white bread.
6. The probability that a random customer purchases creamy peanut butter given that he or she
purchases white bread.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP2-solution-9781337901062
1/3
4/13/22, 3:50 PM

Solved: Rob’s Market (RM) is a regional food store chain in the... | Chegg.com
7. The probability that a random customer purchases natural peanut butter given that he or she
Home
white Study
bread. tools
purchases

My courses

My books
My folder
Career
Life

8. The probability that a random customer purchases creamy peanut butter given that he or she
purchases wheat bread.
9. The probability that a random customer purchases natural peanut butter given that he or she
purchases wheat bread.
10. The probability that a random customer purchases white bread, grape jelly, and creamy
peanut butter.
Step-by-step solution
Step 1 of 2
Given the data “Market basket” on the purchase behaviour of customers who use an RM loyalty
card.
From the data, the total number of customers is 1000.
The pivot tables can be constructed using Insert, then pivot table in excel as follows:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP2-solution-9781337901062
2/3
4/13/22, 3:50 PM

Solved: Rob’s Market (RM) is a regional food store chain in the... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 2 of 2
Here the event is that a random customer does not purchase any of the three products.
From the given data, out of a total of 1000, the number of customers who do not purchase any of
3 products, that is, bread, jelly, or peanut butter is 278.
Thus, the probability that a random customer does not purchase any of the three products is
0.278.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-1CP2-solution-9781337901062
3/3
4/13/22, 3:50 PM

Solved: How many ways can three items be selected from a group ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 2E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
How many ways can three items be selected from a group of six items? Use the letters A, B, C,
Continue to post
D, E, and F to identify the items, and list each of the different combinations of three items.
1 question remaining
My Textbook Solutions
Step-by-step solution
Step 1 of 1
Three items can be selected from a group of six items in ways.
That is, = =
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
=
=
= 20.
Let the six items be A,B,C,D,E, and F.
The following are the different combinations of three items
ABC, ABD, ABE, ABF, ACD, ACE, ACF, ADE, ADF, AEF,
BCD, BCE, BCF, BDE, BDF, BEF,
CDE, CDF, CEF,
DEF.
Comment
Was this solution helpful?
31
1
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-2E-solution-9781337901062
1/3
4/13/22, 3:50 PM


Solved: How many ways can three items be selected from a group ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-2E-solution-9781337901062

2/3
4/13/22, 3:50 PM


Solved: How many ways can three items be selected from a group ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-2E-solution-9781337901062
3/3
4/13/22, 3:51 PM

Solved: How many permutations of three items can be selected fr... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 3E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
How many permutations of three items can be selected from a group of six? Use the letters A, B,
Continue to post
C, D, E, and F to identify the items, and list each of the permutations of items B, D, and F.
1 question remaining
My Textbook Solutions
Step-by-step solution
Step 1 of 1
The number of permutations of three items can be selected from a group of six is given by
=
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
=
=
= 120.
Let the six items be A, B, C, D, E, and F.
The following are the permutations of items B, D, and F.
BDF, BFD, FBD, FDB, DBF, DFB.
Comment
Was this solution helpful?
43
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-3E-solution-9781337901062
1/3
4/13/22, 3:51 PM


Solved: How many permutations of three items can be selected fr... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-3E-solution-9781337901062

2/3
4/13/22, 3:51 PM


Solved: How many permutations of three items can be selected fr... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-3E-solution-9781337901062
3/3
4/13/22, 3:51 PM

Solved: Consider the experiment of tossing a coin three times.a... | Chegg.com

Home
Study tools
My courses


My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 4E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Consider the experiment of tossing a coin three times.
Continue to post
1 question remaining
a. Develop a tree diagram for the experiment.
b. List the experimental outcomes.
c. What is the probability for each experimental outcome?
My Textbook Solutions
Step-by-step solution
Step 1 of 4
a)
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
The objective is to construct a tree diagram for tossing a coin for three times.
Here,
Represents Head and
Represents Tail.
Comment
Step 2 of 4
b)
The objective is to list the experimental outcomes.
The outcomes are,
Hence, the total number of outcomes is
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-4E-solution-9781337901062
1/3
4/13/22, 3:51 PM

Solved: Consider the experiment of tossing a coin three times.a... | Chegg.com
Home
Comment
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 4
c)
The objective is to find the probability of each experimental outcome.
Comment
Step 4 of 4
Hence, the required probability of each experimental outcome is
Comment
Was this solution helpful?
28
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-4E-solution-9781337901062
2/3
4/13/22, 3:51 PM


Solved: Consider the experiment of tossing a coin three times.a... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-4E-solution-9781337901062
3/3
4/13/22, 3:51 PM

Solved: Suppose an experiment has five equally likely outcomes:... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 5E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Suppose an experiment has five equally likely outcomes: E1, E2,E3, E4, E5. Assign probabilities
Continue to post
1 question remaining
to each outcome and show that the requirements in equations (4.3) and (4.4) are satisfied. What
method did you use?
My Textbook Solutions
Step-by-step solution
Step 1 of 1
Given that an experiment has five equally likely outcomes, they are E1, E2, E3, E4, E5.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
P(E1) = P(E2) = P(E3) = P(E4) = P(E5) =
View all solutions
.
Since the outcomes are equally likely.
Here, 0
P(E1) = P(E2) = P(E3) = P(E4) = P(E5)
1.
That is, 0 < P(Ei) < 1 , for all i =1, 2, 3, 4, 5.
Also, P(E1) + P(E2) + P(E3) + P(E4) + P(E5) = 1.
The classical method was used, because this method of assigning probabilities is appropriate
when all the experimental outcomes are equally likely.
Comment
Was this solution helpful?
34
2
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-5E-solution-9781337901062
1/3
4/13/22, 3:51 PM


Solved: Suppose an experiment has five equally likely outcomes:... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-5E-solution-9781337901062

2/3
4/13/22, 3:51 PM


Solved: Suppose an experiment has five equally likely outcomes:... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-5E-solution-9781337901062
3/3
4/13/22, 3:51 PM

Solved: An experiment with three outcomes has been repeated 50 ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 6E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
An experiment with three outcomes has been repeated 50 times, and it was learned that E1
Continue to post
1 question remaining
occurred 20 times, E2 occurred 13 times, and E3 occurred 17 times. Assign probabilities to the
outcomes. What method did you use?
My Textbook Solutions
Step-by-step solution
Step 1 of 1
From the given information, E1 occurred 20 times out of 50, E2 occurred 13 times out of 50 and
E3 occurred 17 times out of 50.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Therefore, P(E1) =
P(E2) =
= 0.26
P(E3) =
= 0.34
= 0.4
The relative frequency method was used, because this method of assigning probabilities is
appropriate when data are available to estimate the proportion of the time the experimental
outcome will occur if the experiment is repeated a large number of times.
Comment
Was this solution helpful?
26
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-6E-solution-9781337901062
1/3
4/13/22, 3:51 PM


Solved: An experiment with three outcomes has been repeated 50 ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-6E-solution-9781337901062

2/3
4/13/22, 3:51 PM


Solved: An experiment with three outcomes has been repeated 50 ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-6E-solution-9781337901062
3/3
4/13/22, 3:51 PM

Solved: A decision maker subjectively assigned the following pr... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 7E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
A decision maker subjectively assigned the following probabilities to the four outcomes of an
Continue to post
experiment: P(E1) = .10, P(E2) = .15, P(E3) = .40, and P(E4) = .20. Are these probability
1 question remaining
assignments valid? Explain.
My Textbook Solutions
Step-by-step solution
Step 1 of 1
No, these probability assignments are not valid.
Because the basic requirement for assigning probability
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
is not satisfied.
That is,
Comment
Was this solution helpful?
62
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-7E-solution-9781337901062
1/3
4/13/22, 3:51 PM


Solved: A decision maker subjectively assigned the following pr... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-7E-solution-9781337901062

2/3
4/13/22, 3:51 PM


Solved: A decision maker subjectively assigned the following pr... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-7E-solution-9781337901062
3/3
4/13/22, 3:52 PM

Solved: In the city of Milford, applications for zoning changes... | Chegg.com

Home
Study tools
My courses


My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 8E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
In the city of Milford, applications for zoning changes go through a two-step process: a review by
Continue to post
the planning commission and a final decision by the city council. At step 1 the planning
1 question remaining
commission reviews the zoning change request and makes a positive or negative
recommendation concerning the change. At step 2 the city council reviews the planning
commission’s recommendation and then votes to approve or to disapprove the zoning change.
Suppose the developer of an apartment complex submits an application for a zoning change.
My Textbook Solutions
Consider the application process as an experiment.
a. How many sample points are there for this experiment? List the sample points.
b. Construct a tree diagram for the experiment.
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 2
a.
According to given information, at step 1 the planning commission reviews the zoning change
request and makes a positive or negative recommendation’s concerning the change and at step
2 the city council reviews the planning commission’s recommendation and then votes to approve
or to disapprove the zoning change.
Therefore, we have four possible outcomes for this experiment.
The following are the possible sample points.
(Planning commission positive, council approves), (planning commission positive, council
disapproves), (planning commission negative, council approves), (planning commission negative,
council disapproves).
Comment
Step 2 of 2
b.
Let P denotes positive, N denotes negative, A denotes approve, D denotes disapprove.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-8E-solution-9781337901062
1/2
4/13/22, 3:52 PM

Solved: In the city of Milford, applications for zoning changes... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The above tree diagram represents about the sample points of the experiment.
Comment
Was this solution helpful?
9
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-8E-solution-9781337901062
2/2
4/13/22, 3:52 PM

Solved: Simple random sampling uses a sample of size n from a p... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 9E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Simple random sampling uses a sample of size n from a population of size N to obtain data that
Continue to post
can be used to make inferences about the characteristics of a population. Suppose that, from a
1 question remaining
population of 50 bank accounts, we want to take a random sample of four accounts in order to
learn about the population. How many different random samples of four accounts are possible?
My Textbook Solutions
Step-by-step solution
Step 1 of 1
The number of ways of random samples of size n from a population of size N is
.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
=
The number of random sample of four accounts from a population of 50 accounts is
Therefore,
.
=
=
= 230,300 .
Comment
Was this solution helpful?
26
2
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-9E-solution-9781337901062
1/2
4/13/22, 3:52 PM


Solved: Simple random sampling uses a sample of size n from a p... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-9E-solution-9781337901062
2/2
4/13/22, 3:52 PM

Solved: Code Churn. Code Churn is a common metric used to measu... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 10E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Code Churn. Code Churn is a common metric used to measure the efficiency and productivity of
Continue to post
software engineers and computer programmers. It’s usually measured as the percentage of a
1 question remaining
programmer’s code that must be edited over a short period of time. Programmers with higher
rates of code churn must rewrite code more often because of errors and inefficient programming
techniques. The following table displays sample information for 10 computer programmers.
My Textbook Solutions
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
a. Use the data in the table above and the relative frequency method to determine probabilities
that a randomly selected line of code will need to be edited for each programmer.
b. If you randomly select a line of code from Liwei, what is the probability that the line of code will
require editing?
c. If you randomly select a line of code from Sherae, what is the probability that the line of code
will not require editing?
d. Which programmer has the lowest probability of a randomly selected line of code requiring
editing? Which programmer has the highest probability of a randomly selected line of code
requiring editing?
Step-by-step solution
Step 1 of 4
a.
Step 1:
Using the definition of probability, it follows that:
Apply this formula to obtain the probability of editing the code for each programmer. THE final
values will be as shown below.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-10E-solution-9781337901062
1/3
4/13/22, 3:52 PM

Solved: Code Churn. Code Churn is a common metric used to measu... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 2 of 4
b.
The above table gives the values for the probability of editing a code for each programmer. From
the first row of the table, a code written by L1 is 0.1929. Therefore, there is a 0.1929 probability
that a randomly picked code written by L1 will need editing.
Comment
Step 3 of 4
c.
The table in part (a) gives the values for the probability of editing a code for each programmer.
From the first row of the table, a code written by S is 0.1451. Therefore, there is a 0.1451
probability that a randomly picked code written by S will need editing.
By the complement rule of probability, the following holds:
Therefore, the probability that a line of code written by S will not require editing is 0.854894.
Comment
Step 4 of 4
d.
Peruse the values in the last column o the table in part (a). A comparison of the values reveals
the A2 value. Therefore, the probability of a code written by A2 requiring an edit is maximum.
.
Comments (1)
Was this solution helpful?
0
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-10E-solution-9781337901062
2/3
4/13/22, 3:52 PM


Solved: Code Churn. Code Churn is a common metric used to measu... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-10E-solution-9781337901062
3/3
4/13/22, 3:52 PM

Solved: Tri-State Smokers. A Gallup Poll of U.S. adults indicat... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 11E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Tri-State Smokers. A Gallup Poll of U.S. adults indicated that Kentucky is the state with the
Continue to post
highest percentage of smokers (Gallup website). Consider the following example data from the
1 question remaining
Tri-State region, an area that comprises northern Kentucky, southeastern Indiana, and
southwestern Ohio.
My Textbook Solutions
Statistics for
Business &...
A First
Course in...
Differential
Equations..
b. What is the probability of an adult in each state of the Tri-State region being a smoker? Which
14th Edition
8th Edition
6th Edition
state in the Tri-State region has the lowest probability of an adult being a smoker?
View all solutions
a. Use the data to compute the probability that an adult in the Tri-State region smokes.
Step-by-step solution
Step 1 of 4
a.
Step 1:
Note the given information.
From the given data:
The total number of smokers in the tri-state region is 118.
The number of nonsmokers in the tri-state region is 492.
Comment
Step 2 of 4
Step 2:
Use the definition of probability to obtain the required probability.
The probability that an adult in the Tristate region smokes is 0.1934.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-11E-solution-9781337901062
1/3
4/13/22, 3:52 PM

Solved: Tri-State Smokers. A Gallup Poll of U.S. adults indicat... | Chegg.com

Home
Study tools

Step 3 of 4
My courses

My books
My folder
Career
Life

b.
Step 1:
Use the definition of probability to obtain the required probabilities.
For the state of Kentucky:
There is a 0.2108 probability that an adult in Kentucky is a smoker.
For the state of Indiana:
There is a 0.1928 probability that an adult in Indiana is a smoker.
For the state of Ohio:
There is a 0.1765 probability that an adult in Ohio is a smoker.
Comment
Step 4 of 4
Step 2:
Compare the probabilities for each state and infer.
The above calculations show that the probability that an adult in Kentucky is a smoker is 0.2108,
in Indiana is 0.1928, and in Ohio is 0.1765. Therefore, Ohio has the lowest probability of an adult
being a smoker compared to the remaining two states.
Comment
Was this solution helpful?
0
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-11E-solution-9781337901062
2/3
4/13/22, 3:52 PM
COMPANY


Solved: Tri-State Smokers. A Gallup Poll of U.S. adults indicat... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-11E-solution-9781337901062
3/3
4/13/22, 3:53 PM

Solved: A company that manufactures toothpaste is studying five... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 12E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
A company that manufactures toothpaste is studying five different package designs. Assuming
Continue to post
that one design is just as likely to be selected by a consumer as any other design, what selection
1 question remaining
probability would you assign to each of the package designs? In an actual experiment, 100
consumers were asked to pick the design they preferred. The following data were obtained. Do
the data confirm the belief that one design is just as likely to be selected as another? Explain.
Step-by-step solution
My Textbook Solutions
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 2
Assuming that, one design is equally likely to be selected by a consumer. Because one of the
five equally likely to be selected, the probability of selecting a design is 1/5 = 0.20
Comment
Step 2 of 2
The probability of a design to be selected is given by,
No. There seem to be a good preference for Design 4 and least preference for design 1.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-12E-solution-9781337901062
1/3
4/13/22, 3:53 PM


Solved: A company that manufactures toothpaste is studying five... | Chegg.com
Home
9
Was this solution helpful?
Study tools

My courses

My books
1
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-12E-solution-9781337901062

2/3
4/13/22, 3:53 PM
COMPANY


Solved: A company that manufactures toothpaste is studying five... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-12E-solution-9781337901062
3/3
4/13/22, 3:53 PM

Solved: The Powerball lottery is played twice each week in 31 s... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 13E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
The Powerball lottery is played twice each week in 31 states, the District of Columbia, and the
Continue to post
Virgin Islands. To play Powerball, a participant must purchase a $2 ticket, select five numbers
1 question remaining
from the digits 1 through 59, and then select a Powerball number from the digits 1 through 35. To
determine the winning numbers for each game, lottery officials draw 5 white balls out a drum of
59 white balls numbered 1 through 59 and 1 red ball out of a drum of 35 red balls numbered 1
through 35. To win the Powerball jackpot, a participant’s numbers must match the numbers on
My Textbook Solutions
the 5 white balls in any order and must also match the number on the red Powerball. The
numbers 5–16–22–23–29 with a Powerball number of 6 provided the record jackpot of $580
million ( Powerball website, November 29, 2012).
a. how many Powerball lottery outcomes are possible? (hint: Consider this a two-step random
experiment. Select the 5 white ball numbers and then select the 1 red Powerball number.)
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
b. What is the probability that a $2 lottery ticket wins the Powerball lottery?
View all solutions
Step-by-step solution
Step 1 of 2
The Powerball lottery game is played twice in each week in 31 states; the possible lottery
outcomes and the probability of winning the lottery are calculated below.
a.
The calculation for possible lottery outcomes is as follows:
Ways to select the white balls are:
The number of ways to select the red Powerball from 1 to 35 digits is 35.
Total number of possible lottery outcomes is
.
Comment
Step 2 of 2
b.
The probability of winning the lottery game is calculated as follows:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-13E-solution-9781337901062
1/2
4/13/22, 3:53 PM

Solved: The Powerball lottery is played twice each week in 31 s... | Chegg.com

Home
Study tools

My courses

My books
Thus, the probability of winning the lottery game is
My folder
Career
Life

.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-13E-solution-9781337901062
2/2
4/13/22, 3:53 PM

Solved: An experiment has four equally likely outcomes: E1, E2,... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 14E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
An experiment has four equally likely outcomes: E1, E2, E3, and E4.
Continue to post
1 question remaining
a. What is the probability that E2 occurs?
b. What is the probability that any two of the outcomes occur (e.g., E1 or E3)?
c. What is the probability that any three of the outcomes occur (e.g., E1 or E2 or E4)?
My Textbook Solutions
Step-by-step solution
Step 1 of 3
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
(a)
We have 4 possible equally likely outcomes are
It would be seem reasonable to conclude that the four possible outcomes are equally likely, and
hence each outcome is assigned a probability of 1/4. This probability is between 0 and 1.
Therefore the probability that
that occurs is,
Comment
Step 2 of 3
(b)
The probability that any two outcomes will be selected is,
Comment
Step 3 of 3
(c)
The probability that any three outcomes will be selected is,
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-14E-solution-9781337901062
1/2
4/13/22, 3:53 PM

Home
Comment
Solved: An experiment has four equally likely outcomes: E1, E2,... | Chegg.com
Study tools

My courses
Was this solution helpful?

My books
25
My folder
Career
Life

0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-14E-solution-9781337901062
2/2
4/13/22, 3:54 PM

Solved: Consider the experiment of selecting a playing card fro... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 15E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Consider the experiment of selecting a playing card from a deck of 52 playing cards. Each card
Continue to post
corresponds to a sample point with a 1/52 probability.
1 question remaining
a. List the sample points in the event an ace is selected.
b. List the sample points in the event a club is selected.
c. List the sample points in the event a face card (jack, queen, or king) is selected.
My Textbook Solutions
d. Find the probabilities associated with each of the events in parts (a), (b), and (c).
Step-by-step solution
Step 1 of 6
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
a.
Consider the experiment of selecting a playing card
There should be four sample points in the event that an ace is selected. The sample space
is as follows:
.
Comment
Step 2 of 6
b.
There should be 13 sample points in the event that a club is selected. The sample space is
as follows:
Comment
Step 3 of 6
c.
There should be 12 sample points in the event that a face card is selected. The sample
space is as follows:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-15E-solution-9781337901062
1/3
4/13/22, 3:54 PM

Solved: Consider the experiment of selecting a playing card fro... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 4 of 6
d.
The probability that an ace is selected is
Comment
Step 5 of 6
The probability that a club is selected is,
Comment
Step 6 of 6
The probability that a face card selected is
Comment
Was this solution helpful?
26
2
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-15E-solution-9781337901062
2/3
4/13/22, 3:54 PM
CHEGG
NETWORK


Solved: Consider the experiment of selecting a playing card fro... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-15E-solution-9781337901062
3/3
4/13/22, 3:54 PM

Solved: Consider the experiment of rolling a pair of dice. Supp... | Chegg.com

Home
Study tools
My courses


My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 16E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Consider the experiment of rolling a pair of dice. Suppose that we are interested in the sum of
Continue to post
the face values showing on the dice.
1 question remaining
a. How many sample points are possible?
b. List the sample points.
My Textbook Solutions
c. What is the probability of obtaining a value of 7?
d. What is the probability of obtaining a value of 9 or greater?
e. Because each roll has six possible even values (2, 4, 6, 8, 10, and 12) and only five possible
odd values (3, 5, 7, 9, and 11), the dice should show even values more often than odd values. Do
you agree with this statement? Explain.
f. What method did you use to assign the probabilities requested?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 6
(a)
If an experiment can be described as a sequence of k steps with
step,
possible outcomes on first
possible outcomes on the second step, and so on, then the total number of experimental
outcomes is given by
Therefore, the total possible sample points are = (6) (6) = 36
Comment
Step 2 of 6
(b)
The sample points are as follows:
Comment
Step 3 of 6
(c)
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-16E-solution-9781337901062
1/3
4/13/22, 3:54 PM

Solved: Consider the experiment of rolling a pair of dice. Supp... | Chegg.com
7 can be obtained in 6 ways:(1,6),(2,5),(3,4),(4,3),2,5),(6,1).
Study tools
My courses
HenceHome
the probability of obtaining a value of 7 =


My books
My folder
Career
Life

.
Comment
Step 4 of 6
(d)
A value of 9 or greater than 9 can be obtained in 10 ways:
(3,6), (4,5), (4,6), (5,4), (5,5), (5,6), (6,3), (6,4), (6,5), (6,6),Probability of obtaining value of 9 or
greater than 9 =
.
Comment
Step 5 of 6
(e)
No. Probability of each of the points is the same. Hence we can’t simply count the number of
outcomes for even and odd events and conclude.
Comment
Step 6 of 6
(f)
Since all the outcomes are equally likely we assign equal probabilities. The method we used for
these equally likely outcomes is classical method.
Comment
Was this solution helpful?
31
5
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-16E-solution-9781337901062
2/3
4/13/22, 3:54 PM


Solved: Consider the experiment of rolling a pair of dice. Supp... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-16E-solution-9781337901062
3/3
4/13/22, 3:54 PM

Solved: Refer to the KP&L sample points and sample point probab... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 17E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Refer to the KP&L sample points and sample point probabilities in Tables 4.2 and 4.3.
Continue to post
1 question remaining
a. The design stage (stage 1) will run over budget if it takes 4 months to complete. List the
sample points in the event the design stage is over budget.
b. What is the probability that the design stage is over budget?
c. The construction stage (stage 2) will run over budget if it takes 8 months to complete. List the
My Textbook Solutions
sample points in the event the construction stage is over budget.
d. What is the probability that the construction stage is over budget?
e. What is the probability that both stages are over budget?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 5
(a) There are three sample points in the event the design stage is over budget.
The sample points are (4, 6), (4, 7), (4, 8).
Comment
Step 2 of 5
(b) The probability that the design stage is over budget is
Comment
Step 3 of 5
(c) There are three sample points in the event that the construction stage is over budget. The
sample points are (2, 8), (3, 8), (4, 8).
Comment
Step 4 of 5
(d) The probability that the construction stage is over budget is
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-17E-solution-9781337901062
1/2
4/13/22, 3:54 PM

Solved: Refer to the KP&L sample points and sample point probab... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 5 of 5
(e) There is only one sample point in the event that both the stages are over budget.
The sample point is (4, 8). The probability that both the stages are over budget is
P (4, 8) =
Comment
Was this solution helpful?
17
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-17E-solution-9781337901062
2/2
4/13/22, 3:54 PM

Solved: Corporate Headquarters Locations. Each year Fortune mag... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 18E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Corporate Headquarters Locations. Each year Fortune magazine publishes an annual list of
Continue to post
the 500 largest companies in the United States. The corporate headquarters for the 500
1 question remaining
companies are located in 38 different states. The following table shows the 8 states with the
largest number of Fortune 500 companies (Money/CNN website).
My Textbook Solutions
Suppose one of the 500 companies is selected at random for a follow-up questionnaire.
a. What is the probability that the company selected has its corporate headquarters in California?
b. What is the probability that the company selected has its corporate headquarters in California,
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
New York, or Texas?
c. What is the probability that the company selected has its corporate headquarters in one of the
eight states listed above?
Step-by-step solution
Step 1 of 6
a.
Step 1:
Note the given information.
From the given data, the total number of companies is 500.
The number of companies with headquarters in California is 53.
Comment
Step 2 of 6
Step 2:
Use the definition of probability to obtain the required probability.
Let C be the event that a company's headquarters is in California.
The probability that the selected company has its corporate headquarters in California is 0.106.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-18E-solution-9781337901062
1/3
4/13/22, 3:54 PM

Solved: Corporate Headquarters Locations. Each year Fortune mag... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 6
b.
Step 1:
Note the given information.
From the given data, the total number of companies is 500.
Comment
Step 4 of 6
Step 2:
Use the definition of probability to obtain the required probability.
Let C, NY, and T be the event that a company's headquarters is in California, New York, or
Texas.
The probability that the selected company has its corporate headquarters in California, New York,
or Texas is 0.31.
Comment
Step 5 of 6
c.
Step 1:
Note the given information.
From the given data, the total number of companies is 500.
Comment
Step 6 of 6
Step 2:
Use the definition of probability to find the required probability.
The probability that the selected company has its corporate headquarters in one of the eight
states listed is 0.566.
Comment
Was this solution helpful?
0
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-18E-solution-9781337901062
2/3
4/13/22, 3:54 PM


Solved: Corporate Headquarters Locations. Each year Fortune mag... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-18E-solution-9781337901062
3/3
4/13/22, 3:54 PM

Solved: Impact of Global Warming. Do you think global warming w... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 19E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Impact of Global Warming. Do you think global warming will have an impact on you during your
Continue to post
lifetime? A 2014 CBS News/New York Times poll of 1000 adults in the United States asked this
1 question remaining
question (CBS News website). Consider the responses by age groups shown below.
My Textbook Solutions
a. What is the probability that a respondent 18–29 years of age thinks that global warming will
not pose a serious threat during his/her lifetime?
b. What is the probability that a respondent 30+ years of age thinks that global warming will not
pose a serious threat during his/her lifetime?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
c. For a randomly selected respondent, what is the probability that a respondent answers yes?
d. Based on the survey results, does there appear to be a difference between ages 18–29 and
30+ regarding concern over global warming?
Step-by-step solution
Step 1 of 7
a.
Step 1:
Note the information available in the problem.
The number of respondents aged 18-29 who think warming will not pose a threat is 131.
The total number of respondents is 1000.
Comment
Step 2 of 7
Step 2:
Use the definition of probability to obtain the required probability.
The probability that a respondent 18-29 years of age thinks that global warming will not pose a
serious threat during his/her lifetime is 0.131.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-19E-solution-9781337901062
1/3
4/13/22, 3:54 PM

Solved: Impact of Global Warming. Do you think global warming w... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 7
b.
Note the information available in the problem.
The number of respondents aged above 30 who think warming will not pose a threat is 432.
The total number of respondents is 1000.
Comment
Step 4 of 7
Step 2:
Use the definition of probability to obtain the required probability.
The probability that a respondent 30+years of age thinks that global warming will not pose a
serious threat during his/her lifetime is 0.432.
Comment
Step 5 of 7
c.
Step 1:
Note the information available in the problem.
The total number of respondents is 1000.
Comment
Step 6 of 7
Step 2:
Use the definition of probability to obtain the required probability.
The probability that a random respondent answers yes is 0.427.
Comment
Step 7 of 7
d.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-19E-solution-9781337901062
2/3
4/13/22, 3:54 PM

Solved: Impact of Global Warming. Do you think global warming w... | Chegg.com
From the above calculations, the probability that a respondent 18-29 years of age thinks that
Study
toolsa serious
My
courses
Mylifetime
booksis 0.131.
My folder
warming will
not pose
threat
during his/her
The same
global Home


Career
Life

probability for a respondent aged above 30 is 0.432. Since the probabilities of the two age
groups differ, it suggests a difference in the two age groups regarding the concern for global
warming.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-19E-solution-9781337901062
3/3
4/13/22, 3:55 PM

Solved: Age of Financial Independence. Suppose that the followi... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 20E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Age of Financial Independence. Suppose that the following table represents a sample of 944
Continue to post
teenagers’ responses to the question, “When do you think you will become financially
1 question remaining
independent?”
My Textbook Solutions
Consider the experiment of randomly selecting a teenager from the population of teenagers aged
14 to 18.
a. Compute the probability of being financially independent for each of the four age categories.
b. What is the probability of being financially independent before the age of 25?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
c. What is the probability of being financially independent after the age of 24?
d. Do the probabilities suggest that the teenagers may be somewhat unrealistic in their
expectations about when they will become financially independent?
Step-by-step solution
Step 1 of 4
a.
From the definition of probability, it follows that:
Apply this formula to obtain the probability of being financially independent. The final values will
be as shown below.
Comment
Step 2 of 4
b.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-20E-solution-9781337901062
1/3
4/13/22, 3:55 PM

Solved: Age of Financial Independence. Suppose that the followi... | Chegg.com
The above table gives the values for the probability for each group to be financially independent.
Home ofStudy
courses
My
My folder
Career
being tools
independentMy
before
25 is the sum
of books
the probabilities
for the age groups
The probability


Life

16 – 20 and 21 – 24.
The probability of being financially independent before 25 years is 0.697034.
Comment
Step 3 of 4
c.
The above table gives the values for the probability for each group to be financially independent.
The probability of being independent after 24 is the sum of the probabilities for 25 – 27 and 28
age groups.
The probability of being financially independent after 24 years is 0.302966.
Comment
Step 4 of 4
d.
The probability of becoming financially independent in teenage years, that is, in the age group
16-20, is merely 0.202330508. This value is less than 5% and thus seems unlikely. Therefore,
probabilities suggest that teenagers are unrealistic in their expectations of being financially
independent in their age.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-20E-solution-9781337901062
2/3
4/13/22, 3:55 PM
Solved: Age of Financial Independence. Suppose that the followi... | Chegg.com
© 2003-2022 Chegg Inc. All rights reserved.


Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-20E-solution-9781337901062

3/3
4/13/22, 3:55 PM

Solved: Fatal Collisions with a Fixed Object. The National High... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
3 Bookmarks
Chapter 4, Problem 21E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Fatal Collisions with a Fixed Object. The National Highway Traffic Safety Administration
Continue to post
(NHTSA) collects traffic safety-related data for the U.S. Department of Transportation. According
1 question remaining
to NHTSA’s data, 10,426 fatal collisions in 2016 were the result of collisions with fixed objects
(NHTSA website, https://www.careforcrashvictims.com/wp-content/uploads/2018/07/TrafficSafety-Facts-2016_-Motor-Vehicle-Crash-Data-from-the-Fatality-Analysis-Reporting-SystemFARS-and-the-General-Estimates-System-GES.pdf). The following table provides more
My Textbook Solutions
information on these collisions.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Assume that a collision will be randomly chosen from this population.
a. What is the probability of a fatal collision with a pole or post?
b. What is the probability of a fatal collision with a guardrail?
c. What type of fixed object is least likely to be involved in a fatal collision? What is the probability
associated with this type of fatal collision?
d. What type of object is most likely to be involved in a fatal collision? What is the probability
associated with this type of fatal collision?
Step-by-step solution
Step 1 of 7
a.
Step 1:
Not the information available in the problem.
The number of Collisions by pole/post during a year is 1416.
The total number of collisions by all fixed objects is 10426.
Comment
Step 2 of 7
Step 2:
Using the definition of probability, it follows that:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-21E-solution-9781337901062
1/3
4/13/22, 3:55 PM

Solved: Fatal Collisions with a Fixed Object. The National High... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 7
The probability of a fatal collision with the pole/post is 0.13581431.
Comment
Step 4 of 7
b.
Step 1:
Note the information available in the problem.
The number of Collisions by guardrail during a year is 896.
The total number of collisions by all fixed objects is 10426.
Comment
Step 5 of 7
Step 2:
Using the definition of probability, it follows that:
The probability of a fatal collision with the guardrail is 0.085938999.
Comment
Step 6 of 7
c.
Using the definition of probability, it follows that:
Apply this formula to obtain the probability of fatal collisions with the fixed objects. The final
values will be as shown below.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-21E-solution-9781337901062
2/3
4/13/22, 3:55 PM

Solved: Fatal Collisions with a Fixed Object. The National High... | Chegg.com
The above table reveals that the bridge has the lowest probability of colliding. Therefore, the
Home
My books
folderthat theCareer
leastStudy
likely totools
be involvedMy
in acourses
collision is a bridge.
The tableMy
indicates
fixed object


Life

probability of collision with a bridge is 0.022156148.
Comments (1)
Step 7 of 7
d.
The above table reveals that the Shrubbery/Tree has the lowest probability of colliding.
Therefore, the fixed object most likely to be involved in a collision is the Shruberry/Tree. The
table indicates that the probability of collision with a Shrubbery/Tree is 0.247937848.
Comment
Was this solution helpful?
1
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-21E-solution-9781337901062
3/3
4/13/22, 3:55 PM

Solved: Suppose that we have a sample space with five equally l... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 22E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Suppose that we have a sample space with five equally likely experimental outcomes: E1, E2, E3,
Continue to post
1 question remaining
E4, E5. Let
My Textbook Solutions
a. Find P(A), P(B), and P(C).
b. Find P(A ⋃ B). Are A and B mutually exclusive?
c. Find Ac, Cc, P(Ac), and P(Cc).
d. Find A ⋃ Bc and P(A ⋃ Bc).
e. Find P(B ⋃ C).
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 7
(a)
We have 5 possible experimental outcomes:
The five possible outcomes are equally likely, and hence each outcome is assigned a probability
of 1/5
The event A is given by
Comment
Step 2 of 7
The event B is given by
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-22E-solution-9781337901062
1/3
4/13/22, 3:55 PM

Solved: Suppose that we have a sample space with five equally l... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 7
The event C is given by
Comment
Step 4 of 7
(b)
The events A and B have no sample points in common. Therefore we can say that these are
mutually exclusive events.
Comment
Step 5 of 7
(c)
The event, complement of A can be written as
The event, complement of C can be written as
Comment
Step 6 of 7
(d)
The event, complement of B can be written as
.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-22E-solution-9781337901062
2/3
4/13/22, 3:55 PM

Solved: Suppose that we have a sample space with five equally l... | Chegg.com

Home
Study tools

My courses
Step 7 of 
7
My books
My folder
Career
Life

(e)
There is one sample point belonging to both B and C.
Comment
Was this solution helpful?
33
7
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-22E-solution-9781337901062
3/3
4/13/22, 3:56 PM

Solved: Suppose that we have a sample space S = {E1, E2, E3, E4... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 23E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Suppose that we have a sample space S = {E1, E2, E3, E4, E5, E6, E7}, where E1, E2, . . . , E7
denote the sample points. The following probability assignments apply: P(E1) = .05, P(E2) = .20,
Next
1 question remaining
P(E3) = .20, P(E4) = .25, P(E5) = .15, P(E6) = .10, and P(E7) = .05. Let
My Textbook Solutions
a. Find P(A), P(B), and P(C).
b. Find A ⋃ B and P(A ⋃ B).
c. Find A ⋂ B and P(A ⋂ B).
d. Are events A and C mutually exclusive?
e. Find Bc and P(Bc).
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 7
(a)
The event A is given by
Comment
Step 2 of 7
The event B is given by
Comment
Step 3 of 7
The event C is given by
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-23E-solution-9781337901062
1/3
4/13/22, 3:56 PM

Solved: Suppose that we have a sample space S = {E1, E2, E3, E4... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 4 of 7
(b)
The event
can be written as
Comment
Step 5 of 7
(c)
There is one sample point belonging to both A and B.
The event
can be written as
Comment
Step 6 of 7
(d)
The events A and C have no sample points in common. Therefore we can say that these are
mutually exclusive events.
Comment
Step 7 of 7
(e)
The event, complement of B can be written as
.
We can do this in another way as follows:
Comment
Was this solution helpful?
32
1
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-23E-solution-9781337901062
2/3
4/13/22, 3:56 PM


Solved: Suppose that we have a sample space S = {E1, E2, E3, E4... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-23E-solution-9781337901062
3/3
4/13/22, 3:56 PM

Solved: Clarkson University surveyed alumni to learn more about... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 24E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of
the survey asked respondents to indicate whether their overall experience at Clarkson fell short
Next
1 question remaining
of expectations, met expectations, or surpassed expectations. The results showed that 4% of the
respondents did not provide a response, 26% said that their experience fell short of expectations,
and 65% of the respondents said that their experience met expectations.
a. If we chose an alumnus at random, what is the probability that the alumnus would say their
My Textbook Solutions
experience surpassed expectations?
b. If we chose an alumnus at random, what is the probability that the alumnus would say their
experience met or surpassed expectations?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 2
(a)
We are given that
P (No response) = 0.04
P (Short of expectations) = 0.26
P (Met expectations) = 0.65
The probability that the alumnus would say their experience surpassed expectations is given by,
P (Surpassed expectations) = 1– P (No response)
+P (Short of expectations)
+P (Met expectations)
= 1 – 0.04+0.26+0.65
= 0.05
Comment
Step 2 of 2
(b)
The probability that the alumnus would say their experience met or surpassed expectations is
given by,
P (Met expectations or surpassed expectations) = P (Met expectations)
+P (Surpassed expectations)
= 0.65+0.05
= 0.70
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-24E-solution-9781337901062
1/3
4/13/22, 3:56 PM


Solved: Clarkson University surveyed alumni to learn more about... | Chegg.com
Home
Study tools

My courses
Was this solution helpful?

My books
26
My folder
0
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-24E-solution-9781337901062
2/3
4/13/22, 3:56 PM
CHEGG
NETWORK


Solved: Clarkson University surveyed alumni to learn more about... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-24E-solution-9781337901062
3/3
4/13/22, 3:57 PM

Solved: Americans Using Facebook and LinkedIn. A 2018 Pew Resea... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
2 Bookmarks
Chapter 4, Problem 25E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Americans Using Facebook and LinkedIn. A 2018 Pew Research Center survey (Pew
Research website) examined the use of social media platforms in the United States. The survey
Next
1 question remaining
found that there is a .68 probability that a randomly selected American will use Facebook and a
.25 probability that a randomly selected American will use LinkedIn. In addition, there is a .22
probability that a randomly selected American will use both Facebook and LinkedIn.
a. What is the probability that a randomly selected American will use Facebook or LinkedIn?
My Textbook Solutions
b. What is the probability that a randomly selected American will not use either social media
platform?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 4
a.
Step 1:
Define the events and not the information given in the problem.
Let A, B, and C be the events as defined below.
Therefore, the probability that a randomly selected American will use Facebook or Linkedln
would be given by
, which is the required probability.
Comment
Step 2 of 4
Step 2:
Use the inclusion-exclusion formula to find the required probability.
By the inclusion-exclusion formula, the following applies.
Substitute the known values in the above expression to get the required probability.
Therefore, the probability that a randomly selected American will use Facebook or Linkedln is
0.71.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-25E-solution-9781337901062
1/3
4/13/22, 3:57 PM

Solved: Americans Using Facebook and LinkedIn. A 2018 Pew Resea... | Chegg.com

Home
Study tools

My courses
Step 3 of 
4
My books
My folder
Career
Life

b.
Step 1:
Note the required probability.
The probability that a randomly selected American will use Facebook or Linkedln is given by
. Using the complement rule of probability, it follows that:
Comment
Step 4 of 4
Step 2:
Substitute the values and obtain the required probability.
Therefore, the probability that a randomly selected American will neither use Facebook nor
Linkedln is 0.29.
Comment
Was this solution helpful?
1
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-25E-solution-9781337901062
2/3
4/13/22, 3:57 PM
Solved: Americans Using Facebook and LinkedIn. A 2018 Pew Resea... | Chegg.com
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-25E-solution-9781337901062
3/3
4/13/22, 3:57 PM

Solved: Information about mutual funds provided by Morningstar ... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 26E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Information about mutual funds provided by Morningstar Investment Research includes the type
Continue to post
of mutual fund (Domestic Equity, International Equity, or Fixed Income) and the Morningstar
1 question remaining
rating for the fund. The rating is expressed from 1-star (lowest rating) to 5-star (highest rating). A
sample of 25 mutual funds was selected from Morningstar Funds 500 (2008). The following
counts were obtained:
• Sixteen mutual funds were Domestic Equity funds.
My Textbook Solutions
• Thirteen mutual funds were rated 3-star or less.
• Seven of the Domestic Equity funds were rated 4-star.
• Two of the Domestic Equity funds were rated 5-star.
Assume that one of these 25 mutual funds will be randomly selected in order to learn more about
the mutual fund and its investment strategy.
a. What is the probability of selecting a Domestic Equity fund?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
b. What is the probability of selecting a fund with a 4-star or 5-star rating?
c. What is the probability of selecting a fund that is both a Domestic Equity fund and a fund with a
4-star or 5-star rating?
d. What is the probability of selecting a fund that is a Domestic Equity fund or a fund with a 4-star
or 5-star rating?
Step-by-step solution
Step 1 of 4
2009-4-26E SA: 0472
SR: 3226
a)
Comment
Step 2 of 4
b)
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-26E-solution-9781337901062
1/3
4/13/22, 3:57 PM

Solved: Information about mutual funds provided by Morningstar ... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 4
c)
Comment
Step 4 of 4
d)
Comment
Was this solution helpful?
8
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-26E-solution-9781337901062
2/3
4/13/22, 3:57 PM


Solved: Information about mutual funds provided by Morningstar ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-26E-solution-9781337901062

3/3
4/13/22, 3:57 PM

Solved: Social Media Use. A marketing firm would like to test-m... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 27E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Social Media Use. A marketing firm would like to test-market the name of a new energy drink
targeted at 18- to 29-year-olds via social media. A study by the Pew Research Center found that
1 question remaining
35% of U.S. adults (18 and older) do not use social media (Pew Research Center website,
October 2015). The percentage of U.S. young adults age 30 and older is 78%. Suppose that the
percentage of the U.S. adult population that is either age 18–29 or uses social media is 67.2%.
a. What is the probability that a randomly selected U.S. adult uses social media?
My Textbook Solutions
b. What is the probability that a randomly selected U.S. adult is aged 18–29?
c. What is the probability that a randomly selected U.S. adult is 18–29 and a user of social
media?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 6
a.
Step 1:
Define the events.
Let A, B, and C be the events as defined below.
Therefore, the probability that an adult American uses social media would be given by
,
which is the required probability.
Comment
Step 2 of 6
Step 2:
Use the complement rule connecting the above probabilities.
By complement rule of probability, it follows that:
Given:
The probability that an adult American uses social media is 0.65.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-27E-solution-9781337901062
1/3
4/13/22, 3:57 PM

Solved: Social Media Use. A marketing firm would like to test-m... | Chegg.com

Home
Study tools
Step 3 of 6

My courses
My books

My folder
Career
Life

b.
Step 1:
Refer to the events defined in part (a) and note the required probability.
From part (a):
Since C is the event that young adults age 30 years or older, the probability that a randomly
selected adult is of age 18-29 will be given by
.
Comment
Step 4 of 6
Step 2:s
Use the complement rule connecting the above probabilities.
By complement rule of probability, it follows that:
Given:s
The probability that a randomly selected adult is of age 18-29 is 0.22.
Comment
Step 5 of 6
c.
Step 1:
Note the required probability.
From parts (a) and (b), an adult American uses social media is given by
selected adult is of age 18-29 is given by
, and a randomly
. Therefore, by the multiplication rule of
probability, the probability that a randomly selected American adult is of age 18-29 and user of
social media is
, which is the required probability.
Comment
Step 6 of 6
Step 2:
Substitute the values of the probabilities obtained in parts (a) and (b).
The probability that a randomly selected American adult is of age 18-29 and user of social media
is 0.143
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-27E-solution-9781337901062
2/3
4/13/22, 3:57 PM


Solved: Social Media Use. A marketing firm would like to test-m... | Chegg.com
Home
0
Was this solution helpful?
Study tools

My courses

My books
1
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-27E-solution-9781337901062
3/3
4/13/22, 3:58 PM

Solved: A survey of magazine subscribers showed that 45.8% rent... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 28E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
A survey of magazine subscribers showed that 45.8% rented a car during the past 12 months for
Continue to post
business reasons, 54% rented a car during the past 12 months for personal reasons, and 30%
1 question remaining
rented a car during the past 12 months for both business and personal reasons.
a. What is the probability that a subscriber rented a car during the past 12 months for business or
personal reasons?
My Textbook Solutions
b. What is the probability that a subscriber did not rent a car during the past 12 months for either
business or personal reasons?
Step-by-step solution
Step 1 of 3
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
(a)
The probability that a subscriber rented a car during the past 12 months for business is given by,
P (Business) = 0.458
The probability that a subscriber rented a car during the past 12 months for personal is given by,
P (Personal) = 0.54
The probability that a subscriber rented a car during the past 12 months for both personal and
business is given by,
P (Business and personal) = 0.30
Comment
Step 2 of 3
The probability that a subscriber rented a car during the past 12 months for business or personal
is,
P (Business or personal) = P (Business) + P (Personal) – P (Business and personal)
= 0.458+0.54 – 0.30
= 0.698
Comment
Step 3 of 3
(b)
The probability that a subscriber did not rent a car during the past 12 months for business or
personal is,
P (Neither for business nor for personal) = 1 – P (Business or personal)
= 1 – 0.698
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-28E-solution-9781337901062
1/3
4/13/22, 3:58 PM

Solved: A survey of magazine subscribers showed that 45.8% rent... | Chegg.com
= 0.302

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Was this solution helpful?
31
1
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-28E-solution-9781337901062
2/3
4/13/22, 3:58 PM


Solved: A survey of magazine subscribers showed that 45.8% rent... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-28E-solution-9781337901062
3/3
4/13/22, 3:58 PM

Solved: High school seniors with strong academic records apply ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
1 Bookmark
Chapter 4, Problem 29E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
High school seniors with strong academic records apply to the nation’s most selective colleges in
greater numbers each year. Because the number of slots remains relatively stable, some
Next
1 question remaining
colleges reject more early applicants. Suppose that for a recent admissions class, an Ivy League
college received 2851 applications for early admission. Of this group, it admitted 1033 students
early, rejected 854 outright, and deferred 964 to the regular admission pool for further
consideration. In the past, this school has admitted 18% of the deferred early admission
My Textbook Solutions
applicants during the regular admission process. Counting the students admitted early and the
students admitted during the regular admission process, the total class size was 2375. Let E, R,
and D represent the events that a student who applies for early admission is admitted early,
rejected outright, or deferred to the regular admissions pool.
a. Use the data to estimate P(E), P(R), and P(D).
b. Are events E and D mutually exclusive? Find P(E ⋂ D).
c. For the 2375 students who were admitted, what is the probability that a randomly selected
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
student was accepted during early admission?
d. Suppose a student applies for early admission. What is the probability that the student will be
admitted for early admission or be deferred and later admitted during the regular admission
process?
Step-by-step solution
Step 1 of 6
Let
represent the events that a student who applies for early admission is admitted
early, rejected outright and deferred to the regular admissions pool.
Total number of applications is 2851.
a)
Find the values of
Therefore, the value of
is
Comment
Step 2 of 6
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-29E-solution-9781337901062
1/3
4/13/22, 3:58 PM

Solved: High school seniors with strong academic records apply ... | Chegg.com
Therefore, the value of

Home
Study tools
is

My courses

My books
My folder
Career
Life

Comment
Step 3 of 6
Therefore, the value of
is
Comment
Step 4 of 6
b)
From the given information the events E and D are mutually exclusive, because only one event
can occur at a time.
Here, the events and are mutually exclusive events. So,
Comment
Step 5 of 6
c)
The probability that a randomly selected student was accepted for early admission is,
Therefore, the probability that a randomly selected student was accepted for early admission is
Comment
Step 6 of 6
d)
The probability that the students will be admitted for early admission or be deferred and later
admitted during the regular admission process is,
Therefore, the probability that the students will be admitted for early admission or be deferred
and later admitted during the regular admission process is
Comment
Was this solution helpful?
15
2
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-29E-solution-9781337901062
2/3
4/13/22, 3:58 PM


Solved: High school seniors with strong academic records apply ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-29E-solution-9781337901062
3/3
4/13/22, 3:58 PM

Solved: Suppose that we have two events, A and B, with P(A) = .... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 30E
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Suppose that we have two events, A and B, with P(A) = .50, P(B) = .60, and P(A ⋂ B)= .40.
Next
a. Find P(A | B).
1 question remaining
b. Find P(B | A).
c. Are A and B independent? Why or why not?
My Textbook Solutions
Step-by-step solution
Step 1 of 3
(a)
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
We are given that
Comment
Step 2 of 3
(b)
Comment
Step 3 of 3
(c)
No. A and B are not independent. Because
.
Comment
Was this solution helpful?
23
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-30E-solution-9781337901062
1/3
4/13/22, 3:58 PM


Solved: Suppose that we have two events, A and B, with P(A) = .... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-30E-solution-9781337901062
2/3
4/13/22, 3:58 PM
CHEGG PRODUCTS AND SERVICES

Home Study tools
CHEGG NETWORK

Solved: Suppose that we have two events, A and B, with P(A) = .... | Chegg.com

My courses

My books
My folder
Career
Life

CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-30E-solution-9781337901062
3/3
4/13/22, 3:58 PM

Solved: Assume that we have two events, A and B, that are mutua... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
1 Bookmark
Chapter 4, Problem 31E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Assume that we have two events, A and B, that are mutually exclusive. Assume further that we
know P(A) = .30 and P(B) = .40.
Next
1 question remaining
a. What is P(A ⋂ B)?
b. What is P(A | B)?
c. A student in statistics argues that the concepts of mutually exclusive events and independent
My Textbook Solutions
events are really the same, and that if events are mutually exclusive they must be independent.
Do you agree with this statement? Use the probability information in this problem to justify your
answer.
d. What general conclusion would you make about mutually exclusive and independent events
given the results of this problem?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 4
(a)
We are given that
. Because A and B are mutually exclusive.
Comment
Step 2 of 4
(b)
, Because A and B are mutually exclusive.
Comment
Step 3 of 4
(c)
No. Mutually exclusive events and independent events are conceptually different.
Let
. In this problem A and B are mutually exclusive but they are not necessarily
independent.
If A and B are mutually exclusive then
If A and B are independent then
.
.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-31E-solution-9781337901062
1/2
4/13/22, 3:58 PM

Solved: Assume that we have two events, A and B, that are mutua... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 4 of 4
(d)
We are given that A and B are mutually exclusive then
.
If A and B are independent then,
Comment
Was this solution helpful?
22
1
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-31E-solution-9781337901062
2/2
4/13/22, 3:59 PM

Solved: Living with Family. Consider the following example surv... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 32E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Living with Family. Consider the following example survey results of 18- to 34-yearolds in the
United States, in response to the question “Are you currently living with your family?”
Next
1 question remaining
My Textbook Solutions
a. Develop the joint probability table for these data and use it to answer the following questions.
b. What are the marginal probabilities?
c. What is the probability of living with family given you are an 18- to 34-year-old man in the
United States?
d. What is the probability of living with family given you are an 18- to 34-year-old woman in the
United States?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
e. What is the probability of an 18- to 34-year-old in the United States living with family?
f. If, in the United States, 49.4% of 18- to 34-year-olds are male, do you consider this a good
representative sample? Why?
Step-by-step solution
Step 1 of 6
a.
The total number of records in a row or a column is 500.
Therefore, to obtain the joint probability table, divide the value in each table cell by 500. The final
joint table would appear as below.
Comment
Step 2 of 6
b.
Refer to the joint probability table above and note the marginal probabilities.
In the joint probability table, the marginal probability is at the margins of the table. For example,
the marginal row at the bottom shows the probabilities for Yes and No as 0.396 and 0.604,
respectively.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-32E-solution-9781337901062
1/3
4/13/22, 3:59 PM

Solved: Living with Family. Consider the following example surv... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 6
c.
The probability of a person being a man living with his family is given by the common cell for the
row for Men and the column Yes. This value in the above table is 0.212. Therefore, the
probability of an 18 – 34 year man living with his family is 0.212.
Comment
Step 4 of 6
d.
The common cell for the row for Women and the column Yes gives the probability of a person
being a woman and living with her family. This value in the above table is 0.184. Therefore, the
probability of an 18 – 34 year man living with a family is 0.184.
Comment
Step 5 of 6
e.
The probability of a person being 18 – 34 aged living with family is given by the common cell for
the row for Total and the column Yes. This value in the above table is 0.396. Therefore, the
probability of an 18 – 34 year living with family is 0.396.
Comment
Step 6 of 6
f.
The marginal probability of total men aged 18-34 years old in the survey is 0.494. Therefore, this
survey sample suggests that 49.4% in the age of 18-34 are male seems to be a good
representative, but the sample size here is only 500, which is very small to reach any conclusion.
Comment
Was this solution helpful?
0
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-32E-solution-9781337901062
2/3
4/13/22, 3:59 PM


COMPANY
Solved: Living with Family. Consider the following example surv... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-32E-solution-9781337901062
3/3
4/13/22, 3:59 PM

Solved: Students taking the Graduate Management Admissions Test... | Chegg.com

Home
Study tools
My courses


My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 33E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Students taking the Graduate Management Admissions Test (GMAT) were asked about their
Continue to post
undergraduate major and intent to pursue their MBA as a full-time or part-time student. A
1 question remaining
summary of their responses follows.
My Textbook Solutions
a. Develop a joint probability table for these data.
b. Use the marginal probabilities of undergraduate major (business, engineering, or other) to
comment on which undergraduate major produces the most potential MBA students.
c. If a student intends to attend classes full-time in pursuit of an MBA degree, what is the
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
probability that the student was an undergraduate engineering major?
d. If a student was an undergraduate business major, what is the probability that the student
intends to attend classes full-time in pursuit of an MBA degree?
e. Let A denote the event that the student intends to attend classes full-time in pursuit of an MBA
degree, and let B denote the event that the student was an undergraduate business major. Are
events A and B independent? Justify your answer.
Step-by-step solution
Step 1 of 10
Let
denote the event that a student’s undergraduate major is Business.
Let
denote the event that a student’s undergraduate major is engineering.
Let
denote the event that student’s undergraduate major is neither Business nor Engineering.
Let
denote the event that a student intends to be full-time.
Let
denote the even that a student intends to be part-time.
Comment
Step 2 of 10
a)
Construct a joint probability table for the given data.
The probability that a randomly selected student had a major of Business and intends to be fulltime is computed as,
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-33E-solution-9781337901062
1/4
4/13/22, 3:59 PM

Solved: Students taking the Graduate Management Admissions Test... | Chegg.com
The probability that a randomly selected student had a major of Engineering and intends to be
Study
is computed
as,tools
full-timeHome

My courses

My books
My folder
Career
Life

The probability that a randomly selected student had a major other than Business and
Engineering and intends to be full-time is computed as,
Comment
Step 3 of 10
The probability that a randomly selected student had a major of Business and intends to be parttime is computed as,
The probability that a randomly selected student had a major of Engineering and intends to be
part-time is computed as,
The probability that a randomly selected student had a major other than Business and
Engineering and intends to be part-time is computed as
Comment
Step 4 of 10
The marginal probability that a randomly selected student intends to be full-time is computed as,
The marginal probability that a randomly selected student intends to be part-time is computed as,
The marginal probability that a randomly selected student had a major of Business is computed
as,
The marginal probability that a randomly selected student had a major of Engineering is
computed as,
Comment
Step 5 of 10
The marginal probability that a randomly selected student had a major other than Business and
Engineering is computed as,
Comment
Step 6 of 10
The joint probability distribution table is as shown below:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-33E-solution-9781337901062
2/4
4/13/22, 3:59 PM

Solved: Students taking the Graduate Management Admissions Test... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 7 of 10
b)
From the joint probability distribution table in part (a), the marginal probabilities for three
undergraduate majors is as shown below:
The Business major has the largest marginal probability, which means the major produces the
most potential MBA students.
Comment
Step 8 of 10
c)
Find the conditional probability that a student is an undergraduate engineering major given that
the student intends to attend classes full-time in pursuit of an MBA degree.
That is,
Therefore, the conditional probability that a student is an undergraduate engineering major given
that the student intends to attend classes full-time in pursuit of an MBA degree is
Comment
Step 9 of 10
d)
Find the conditional probability that a student intends to attend classes full-time in pursuit of an
MBA degree given that the student was an undergraduate business major.
That is,
Therefore, the conditional probability that a student intends to attend classes full-time in pursuit
of an MBA degree given that the student was an undergraduate business major is
Comment
Step 10 of 10
e)
Let be the event that the student intends to attend classes full-time in pursuit of an MBA degree,
and let be the event that the student was an undergraduate business major.
According to the Multiplication Law for independent events, the following equation needs to hold
in order for and to be independent with each other:
From the joint probability table in part (a), we have
Here, it can be observed that . Hence, the events and are
not independent.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-33E-solution-9781337901062
3/4
4/13/22, 3:59 PM

Solved: Students taking the Graduate Management Admissions Test... | Chegg.com
Comment

Home
Study tools

My courses
Was this solution helpful?

My books
8
My folder
Career
Life

0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-33E-solution-9781337901062
4/4
4/13/22, 4:00 PM

Solved: On-Time Performance of Airlines. The Bureau of Transpor... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 34E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
On-Time Performance of Airlines. The Bureau of Transportation Statistics reports on-time
Continue to post
performance for airlines at major U.S. airports. JetBlue, United, and US Airways share terminal C
1 question remaining
at Boston’s Logan Airport. Suppose that the percentage of on-time flights reported was 76.8% for
JetBlue, 71.5% for United, and 82.2% for US Airways. Assume that 30% of the flights arriving at
terminal C are JetBlue flights, 32% are United flights, and 38% are US Airways flights.
a. Develop a joint probability table with three rows (the airlines) and two columns (on-time and
My Textbook Solutions
late).
b. An announcement is made that Flight 1382 will be arriving at gate 20 of terminal C. What is
the probability that Flight 1382 will arrive on time?
c. What is the most likely airline for Flight 1382? What is the probability that Flight 1382 is by this
airline?
d. Suppose that an announcement is made saying that Flight 1382 will now be arriving late. What
is the most likely airline for this flight? What is the probability that Flight 1382 is by this airline?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 5
a.
Step 1:
Construct the matrix of flight distribution.
Let n be the total number of flights arriving at terminal C. Then, using the information given in the
problem, the flight distribution would appear as shown below.
Comment
Step 2 of 5
Step 2:
Construct the joint probability table. The total number of records in a row or column is n.
Therefore, to obtain the joint probability table, divide the value in each table cell by n. The final
joint table should appear as below.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-34E-solution-9781337901062
1/3
4/13/22, 4:00 PM

Solved: On-Time Performance of Airlines. The Bureau of Transpor... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 5
b.
In the joint probability table, the marginal probability is at the margins of the table. The marginal
row at the bottom shows the probability for ‘On Time’ as 0.771156. The problem does not
mention the company to which flight no. 1382 belongs. Therefore, its probability of arriving on
time is the same as the marginal probability of arriving on time, i.e. 0.77156.
Comment
Step 4 of 5
c.
For a Jet Blue flight:
For a United flight:
For a US Airline flight:
Flight 1382 arrived on time. The above calculations show that the Jet Blue and United flights
have almost the same probabilities to arrive on time. The US Airline has the highest probability of
arriving on time. Therefore, it is most probable that flight no. 1382 belongs to the US Airline. The
probability of the flight belonging to a US Airline is 0.404842.
Comment
Step 5 of 5
d.
For a Jet Blue flight:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-34E-solution-9781337901062
2/3
4/13/22, 4:00 PM

Solved: On-Time Performance of Airlines. The Bureau of Transpor... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

For a United flight:
For a US Airline flight:
Flight 1382 was delayed. The above calculations show that the United flight has a higher
probability of getting delayed than the other two airlines. Therefore, it is most probable that flight
no. 1382 belongs to the United airline. The probability of the flight belonging to United Airlines is
0.39923.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-34E-solution-9781337901062
3/3
4/13/22, 4:00 PM

Solved: Better at Getting Deals. To better understand how husba... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 35E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Better at Getting Deals. To better understand how husbands and wives feel about their
Continue to post
finances, Money magazine conducted a national poll of 1010 married adults age 25 and older
1 question remaining
with household incomes of $50,000 or more (Money website). Consider the following example
set of responses to the question, “Who is better at getting deals?”
My Textbook Solutions
a. Develop a joint probability table and use it to answer the following questions.
b. Construct the marginal probabilities for Who Is Better (I Am, My Spouse, We Are Equal).
Comment.
c. Given that the respondent is a husband, what is the probability that he feels he is better at
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
getting deals than his wife?
d. Given that the respondent is a wife, what is the probability that she feels she is better at
getting deals than her husband?
e. Given a response “My spouse” is better at getting deals, what is the probability that the
response came from a husband?
f. Given a response “We are equal,” what is the probability that the response came from a
husband? What is the probability that the response came from a wife?
Step-by-step solution
Step 1 of 10
a.
The total number of respondents is 1010.
Therefore, to obtain the joint probability table, divide the value in each table cell by 1010. The
final joint probability distribution table would appear as below:
Comment
Step 2 of 10
b.
In the joint probability table, the marginal probability is at the margins of the table. For example,
the marginal row at the bottom shows the probabilities for ‘I am,’ ‘My spouse,’ and ‘We are Equal’
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-35E-solution-9781337901062
1/4
4/13/22, 4:00 PM

Solved: Better at Getting Deals. To better understand how husba... | Chegg.com
as 0.562376, 0.235643, and 0.20198, respectively. Comparing these marginal probabilities
Study tools
courses
books
My folder
that the probability
for ‘I am’ isMy
greater
than for theMy
other
two responses.
Therefore,Career
it can
shows Home


Life

be concluded that the respondents consider themselves to be better at getting deals than their
spouses.
Comment
Step 3 of 10
c.
Step 1:
Note the required probability.
Comment
Step 4 of 10
Step 2:
Substitute the values from the joint probability table.
The probability that the husband feels he is better at getting deals than the wife is 0.548323.
Comment
Step 5 of 10
d.
Step 1:
Note the required probability.
Comment
Step 6 of 10
Step 2:
Substitute the values from the joint probability table.
The probability that the wife feels she is better at getting deals than her husband is 0.548323.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-35E-solution-9781337901062
2/4
4/13/22, 4:00 PM

Solved: Better at Getting Deals. To better understand how husba... | Chegg.com

Home
Study tools

Step 7 of 10
My courses

My books
My folder
Career
Life

e.
Step 1:
Note the required probability.
Comment
Step 8 of 10
Step 2:
Substitute the values from the joint probability table.
The probability that the response ‘My spouse’ came from a husband is 0.533613.
Comment
Step 9 of 10
f.
Step 1:
Note the required probability.
Comment
Step 10 of 10
Step 2:
Substitute the values from the joint probability table.
The probability that the response ‘We are equal’ came from a husband is 0.5.
Comment
Was this solution helpful?
0
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-35E-solution-9781337901062
3/4
4/13/22, 4:00 PM


Solved: Better at Getting Deals. To better understand how husba... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-35E-solution-9781337901062
4/4
4/13/22, 4:01 PM

Solved: NBA Free Throws. Suppose that a particular NBA player m... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 36E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
NBA Free Throws. Suppose that a particular NBA player makes 93% of his free throws. Assume
Continue to post
that late in a basketball game, this player is fouled and is awarded two shots.
1 question remaining
a. What is the probability that he will make both shots?
b. What is the probability that he will make at least one shot?
My Textbook Solutions
c. What is the probability that he will miss both shots?
d. Late in a basketball game, a team often intentionally fouls an opposing player in order to stop
the game clock. The usual strategy is to intentionally foul the other team’s worst free-throw
shooter. Assume that the the team’s worst free-throw shooter makes 58% of his free-throw shots.
Calculate the probabilities for this player as shown in parts (a), (b), and (c), and show that
intentionally fouling this player who makes 58% of his free throws is a better strategy than
intentionally fouling the player who makes 93% of his free throws. Assume as in parts (a), (b),
and (c) that two shots will be awarded.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 7
a.
Let A be the event that the player makes a free throw.
Given:
The probability of making a free throw is 0.93.
The event that he makes both the free throws would be obtained as below:
The probability that he will make both the free throws is 0.8649.
Comment
Step 2 of 7
b.
Let
be the event that the player makes and misses, respectively, the
throw, where
.
The player will make at least one throw if he makes either the first or second or both throws. Add
the intersections of the events, 'makes first but misses second,' 'makes second but misses first,'
and 'makes both shots' to obtain the required probability.
Since all the events are independent, hence multiplication rule of independent events can be
used.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-36E-solution-9781337901062
1/4
4/13/22, 4:01 PM

Solved: NBA Free Throws. Suppose that a particular NBA player m... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The probability that he will make at least one free throw is 0.995.
Comment
Step 3 of 7
c.
The probability of making a free throw is 0.93. By the complement rule, the probability of missing
it will be given by its complement.
For the event is that he will miss both the free throws, the probability of 'misses a shot' must be
multiplied twice.
The probability that he will miss both the free throws is 0.0049.
Comment
Step 4 of 7
d.
Step 1:
Note the given probability.
Given:
The probability of the worst free-throw shooter is 0.58.
Comment
Step 5 of 7
Step 2:
As calculated in part (a), obtain the probability of the player making both the free throws.
The probability that he will make both the free throws would be given by:
The probability that he will make both the free throws is 0.336.
Step 3:
As calculated in part (b), obtain the probability that the player makes at least one throw.
Since the event of making a throw is complementary to the event of missing a throw, it follows
that:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-36E-solution-9781337901062
2/4
4/13/22, 4:01 PM

Solved: NBA Free Throws. Suppose that a particular NBA player m... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The probability that he will make at least one free throw is 0.823
Comment
Step 6 of 7
Step 4:
As calculated in part (c), obtain the probability of the player missing both the throws.
The probability that he will miss both the free throws is given by:
The probability that he will miss both the free throws is 0.1764.
Comment
Step 7 of 7
Step 5:
Compare the probabilities in the above parts and conclude on fouling which player would be
more preferred.
In the initial case, the player's probability of making at least one free throw is 0.995. The
probability that the worst free-throw shooter makes at least one free throw is 0.823. The worst
free-throw shooter has a lesser probability of making a free throw. Therefore, intentionally fowling
the worst free-throw shooter is a better strategy than intentionally fowling the player who makes
93% of his free throws.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-36E-solution-9781337901062
3/4
4/13/22, 4:01 PM


Solved: NBA Free Throws. Suppose that a particular NBA player m... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-36E-solution-9781337901062
4/4
4/13/22, 4:01 PM

Solved: Giving Up Electronics. A 2018 Pew Research Center surve... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
5 Bookmarks
Chapter 4, Problem 37E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Giving Up Electronics. A 2018 Pew Research Center survey found that more Americans
Continue to post
believe they could give up their televisions than could give up their cell phones (Pew Research
1 question remaining
website). Assume that the following table represents the joint probabilities of Americans who
could give up their television or cell phone.
My Textbook Solutions
a. What is the probability that a person could give up her cell phone?
b. What is the probability that a person who could give up her cell phone could also give up
television?
c. What is the probability that a person who could not give up her cell phone could give up
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
television?
d. Is the probability a person could give up television higher if the person could not give up a cell
phone or if the person could give up a cell phone?
Step-by-step solution
Step 1 of 4
a.
Refer to the joint probability table. The first row of the table indicates the total for 'could give up
as 0.48. Therefore, the probability of giving up the cell phone is 0.48.
Comment
Step 2 of 4
b.
The event is that person who could give up her cell phone could also give up her television. This
event is the intersection event of 'could give up her cell phone' and 'could give up her television.'
Therefore, from the joint probability table, it follows that:
The probability that a person who could give up her cell phone will also give up television is 0.31.
Comments (7)
Step 3 of 4
c.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-37E-solution-9781337901062
1/3
4/13/22, 4:01 PM

Solved: Giving Up Electronics. A 2018 Pew Research Center surve... | Chegg.com
The conditional probability that the person could give up her television giver that the person could
Study
tools
courses
up her cell
phone
is given asMy
follows:
not giveHome


My books
My folder
Career
Life

The above values are available from the joint probability table.
Substitute the above values to find the required probability.
The probability of a person giving up her television given that she could not give up her cell
phone is 0.731.
Comments (3)
Step 4 of 4
d.
The conditional probability that the person could give up her television given that the person
could give up her cell phone is given as follows:
The probability that the person could give up her television given that the person could give up
her cell phone is 0.646.
From (c), we found the probability that the person could give up her television given that the
person could not give up her cell phone is 0.731.
Therefore, the probability of giving up a television if the person could not give up her cell phone is
higher.
Comment
Was this solution helpful?
5
2
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-37E-solution-9781337901062
2/3
4/13/22, 4:01 PM


Solved: Giving Up Electronics. A 2018 Pew Research Center surve... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-37E-solution-9781337901062
3/3
4/13/22, 4:01 PM

Solved: Payback of Student Loans. The Institute for Higher Educ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 38E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Payback of Student Loans. The Institute for Higher Education Policy, a Washington, D.C.-
Continue to post
based research firm, studied the payback of student loans for 1.8 million college students who
1 question remaining
had student loans that began to become due six years ago (The Wall Street Journal). The study
found that 50% of the student loans were being paid back in a satisfactory fashion, whereas 50%
of the student loans were delinquent. The following joint probability table shows the probabilities
of the student loan status and whether or not the student had received a college degree.
a. What is the probability that a student with a student loan had received a college degree?
b. What is the probability that a student with a student loan had not received a college degree?
My Textbook Solutions
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
c. Given the student had received a college degree, what is the probability that the student has a
delinquent loan?
d. Given the student had not received a college degree, what is the probability that the student
has a delinquent loan?
e. What is the impact of dropping out of college without a degree for students who have a student
loan?
Step-by-step solution
Step 1 of 5
a.
Refer to the joint probability table. The first column of the table indicates the total for ‘Yes’ is 0.42.
Therefore, the probability that a student with a student loan has received a college degree is
0.42.
Comment
Step 2 of 5
b.
Refer to the joint probability table. The second column of the table indicates the total for ‘No’ is
0.58. Therefore, the probability that a student with a student loan has not received a college
degree is 0.58.
Comment
Step 3 of 5
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-38E-solution-9781337901062
1/3
4/13/22, 4:01 PM

Solved: Payback of Student Loans. The Institute for Higher Educ... | Chegg.com
c.
Home
Study tools

My courses

My books
My folder
Career
Life

The conditional probability that a student has a delinquent loan given that the student received a
college degree is given by:
The probabilities are found using the joint probability table.
The probability that a student has a delinquent loan given that the student received a college
degree is 0.38.
Comment
Step 4 of 5
d.
The conditional probability that a student has a delinquent loan given that the student has not
received a college degree is given by:
The probabilities are found using the joint probability table.
The probability that a student has a delinquent loan if the student has not received a college
degree is 0.59.
Comment
Step 5 of 5
e.
From the joint probability table, the following can be calculated.
These values show that 41% of the students did not receive a college degree, but their loan was
satisfactory. The loan of the remaining 59% of students was delinquent.
Comparing the above values shows that most students who did not complete their degree could
not pay their loans back.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-38E-solution-9781337901062
2/3
4/13/22, 4:01 PM


Solved: Payback of Student Loans. The Institute for Higher Educ... | Chegg.com
Home
Study tools

My courses
Was this solution helpful?

My books
0
My folder
0
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-38E-solution-9781337901062
3/3
4/13/22, 4:02 PM

Solved: The prior probabilities for events A1 and A2 are P(A1) ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 39E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
The prior probabilities for events A1 and A2 are P(A1) = .40 and P(A2) = .60. It is also known that
Continue to post
1 question remaining
P(A1 ⋂ A2) = 0. Suppose P(B | A1) = .20 and P(B | A2) = .05.
a. Are A1 and A2 mutually exclusive? Explain.
b. Compute P(A1 ⋂ B) and P(A2 ⋂ B).
My Textbook Solutions
c. Compute P(B).
d. Apply Bayes’ theorem to compute P(A1 | B) and P(A2 | B).
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 5
(a)
Yes.
Comment
Step 2 of 5
(b)
Comment
Step 3 of 5
(c)
To find P(B), we note that event B can occur in only two ways:
.
Therefore, we have
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-39E-solution-9781337901062
1/3
4/13/22, 4:02 PM

Solved: The prior probabilities for events A1 and A2 are P(A1) ... | Chegg.com

Home
Study tools

Step 4 of 5
My courses

My books
My folder
Career
Life

(d)
From the Bayes’ theorem we have
Comment
Step 5 of 5
Comment
Was this solution helpful?
26
1
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-39E-solution-9781337901062
2/3
4/13/22, 4:02 PM


Solved: The prior probabilities for events A1 and A2 are P(A1) ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-39E-solution-9781337901062

3/3
4/13/22, 4:03 PM

Solved: The prior probabilities for events A1, A2, and A3 are P... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 40E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
The prior probabilities for events A1, A2, and A3 are P(A1) = .20, P(A2) = .50, and P(A3) = .30.
Continue to post
1 question remaining
The conditional probabilities of event B given A1, A2, and A3 are P(B | A1) = .50, P(B | A2) = .40,
and P(B | A3) = .30.
a. Compute P(B ⋂ A1), P(B ⋂ A2), and P(B ⋂ A3).
b. Apply Bayes’ theorem, equation (4.19), to compute the posterior probability P(A2 | B).
My Textbook Solutions
c. Use the tabular approach to applying Bayes’ theorem to compute P(A1 | B), P(A2 | B), and
P(A3 | B).
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 3
From the information, observe that
are the three events with the probabilities 0.20,
0.50 and 0.30 respectively.
The conditional probabilities of event B given that
as follows:
a)
Calculate
Calculate
Calculate
Comment
Step 2 of 3
b)
Calculate
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-40E-solution-9781337901062
1/3
4/13/22, 4:03 PM

Solved: The prior probabilities for events A1, A2, and A3 are P... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 3
c)
Use the tabular approach to applying Bayes theorem to calculate
and
Comment
Was this solution helpful?
17
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-40E-solution-9781337901062
2/3
4/13/22, 4:03 PM


Solved: The prior probabilities for events A1, A2, and A3 are P... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-40E-solution-9781337901062

3/3
4/13/22, 4:03 PM

Solved: A consulting firm submitted a bid for a large research ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 41E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
A consulting firm submitted a bid for a large research project. The firm’s management initially felt
Continue to post
they had a 50-50 chance of getting the project. However, the agency to which the bid was
1 question remaining
submitted subsequently requested additional information on the bid. Past experience indicates
that for 75% of the successful bids and 40% of the unsuccessful bids the agency requested
additional information.
a. What is the prior probability of the bid being successful (that is, prior to the request for
My Textbook Solutions
additional information)?
b. What is the conditional probability of a request for additional information given that the bid will
ultimately be successful?
c. Compute the posterior probability that the bid will be successful given a request for additional
information.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 3
(a)
Let A denote the event that the agency requested for additional information.
Let
denote the event that the bid is successful.
Let
denote the event that the bid is unsuccessful.
The prior probability that the bid being successful is,
Comment
Step 2 of 3
(b)
We are given that
The probability that a request of additional information given that the bid will ultimately be
successful is,
Comment
Step 3 of 3
(c)
The probability that the bid will be successful given a request for additional information is,
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-41E-solution-9781337901062
1/2
4/13/22, 4:03 PM

Solved: A consulting firm submitted a bid for a large research ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Was this solution helpful?
16
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-41E-solution-9781337901062
2/2
4/13/22, 4:03 PM

Solved: A local bank reviewed its credit card policy with the i... | Chegg.com

Home
Study tools

My courses
My books

My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
1 Bookmark
Chapter 4, Problem 42E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
A local bank reviewed its credit card policy with the intention of recalling some of its credit cards.
Continue to post
In the past approximately 5% of cardholders defaulted, leaving the bank unable to collect the
1 question remaining
outstanding balance. Hence, management established a prior probability of .05 that any
particular cardholder will default. The bank also found that the probability of missing a monthly
payment is .20 for customers who do not default. Of course, the probability of missing a monthly
payment for those who default is 1.
My Textbook Solutions
a. Given that a customer missed one or more monthly payments, compute the posterior
probability that the customer will default.
b. The bank would like to recall its card if the probability that a customer will default is greater
than .20. Should the bank recall its card if the customer misses a monthly payment? Why or why
not?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 3
(a)
Let M denote the event that the customer missed payment.
Let
denote the event that the customer defaulted.
Let
denote the event that the customer does not defaulted.
The prior probability that the customer will default is,
The prior probability that the customer will not default is,
We are given that
Comment
Step 2 of 3
The probability that the customer will default given that he or she missed a payment is,
Comment
Step 3 of 3
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-42E-solution-9781337901062
1/2
4/13/22, 4:03 PM

Solved: A local bank reviewed its credit card policy with the i... | Chegg.com
(b)
Home
Study tools

My courses

My books
My folder
Career
Life

Yes. If the customer misses a monthly payment, then the bank should recall its card. Because
the probability that the customer will default given that he or she missed a payment is greater
than 0.20
Comment
Was this solution helpful?
20
3
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-42E-solution-9781337901062
2/2
4/13/22, 4:04 PM

Solved: Prostate Cancer Screening. According to a 2018 article ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 43E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Prostate Cancer Screening. According to a 2018 article in Esquire magazine, approximately
70% of males over age 70 will develop cancerous cells in their prostate. Prostate cancer is
Next
1 question remaining
second only to skin cancer as the most common form of cancer for males in the United States.
One of the most common tests for the detection of prostate cancer is the prostate-specific
antigen (PSA) test. However, this test is known to have a high false-positive rate (tests that come
back positive for cancer when no cancer is present). Suppose there is a .02 probability that a
My Textbook Solutions
male patient has prostate cancer before testing. The probability of a false-positive test is .75, and
the probability of a false-negative (no indication of cancer when cancer is actually present) is .20.
a. What is the probability that the male patient has prostate cancer if the PSA test comes back
positive?
b. What is the probability that the male patient has prostate cancer if the PSA test comes back
negative?
c. For older men, the prior probability of having cancer increases. Suppose that the prior
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
probability of the male patient is .3 rather than .02. What is the probability that the male patient
has prostate cancer if the PSA test comes back positive? What is the probability that the male
patient has prostate cancer if the PSA test comes back negative?
d. What can you infer about the PSA test from the results of parts (a), (b), and (c)?
Step-by-step solution
Step 1 of 4
a.
Given:
The probability that a male patient has prostate cancer is 0.02.
Let A denote that an adult has cancer and
denote that he does not have cancer.
Let B denote that the PSA result is positive and
denote result is negative.
The following probabilities are given.
Using Bayer's theorem, the conditional probability that the patient has prostate cancer given that
the PSA test comes back positive is given below.
Hence the required probability will be:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-43E-solution-9781337901062
1/4
4/13/22, 4:04 PM

Solved: Prostate Cancer Screening. According to a 2018 article ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The probability that the patient has prostate cancer, given that the PSA test comes back positive,
is 0.0213.
Comment
Step 2 of 4
b.
As in part (a), using Bayes' theorem, the conditional probability that the patient has prostate
cancer given that the PSA test comes back negative would be given by:
Hence the required probability will be:
The probability that the patient has prostate cancer, given that the PSA test comes back
negative, is 0.016.
Comment
Step 3 of 4
c.
The probability that the adult has a prostate is 0.3. Therefore by the complement rule of
probability, it follows that:
Using Bayes' theorem, the conditional probability that the patient has prostate cancer given that
the PSA test comes back positive is given by:
Therefore, the required probability is:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-43E-solution-9781337901062
2/4
4/13/22, 4:04 PM

Solved: Prostate Cancer Screening. According to a 2018 article ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The probability that the patient has prostate cancer, given that the PSA test comes back positive,
is 0.314.
Using Bayer's theorem, the conditional probability that the patient has prostate cancer given that
the PSA test comes back negative would be given by:
Therefore, the required probability is:
The probability that the patient has prostate cancer, given that the PSA test comes back
negative, is 0.255.
Comment
Step 4 of 4
d.
From part (a), the chance that the person has prostate cancer, given the result is positive, is
2.13%.
From part (b), the chance that the person has prostate cancer, given the result is negative, is
1.6%.
In part (c), the probabilities have increased because the probability of males having cancer has
increased.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-43E-solution-9781337901062
3/4
4/13/22, 4:04 PM
CHEGG NETWORK


CUSTOMER SERVICE
Solved: Prostate Cancer Screening. According to a 2018 article ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-43E-solution-9781337901062
4/4
4/13/22, 4:04 PM

Solved: ParFore created a website to market golf equipment and ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 44E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
ParFore created a website to market golf equipment and golf apparel. Management would like a
special pop-up offer to appear for female website visitors and a different special pop-up offer to
Next
1 question remaining
appear for male website visitors. From a sample of past website visitors, ParFore’s management
learned that 60% of the visitors are male and 40% are female.
a. What is the probability that a current visitor to the website is female?
My Textbook Solutions
b. Suppose 30% of ParFore’s female visitors previously visited the Dillard’s Department Store
website and 10% of ParFore’s male visitors previously visited the Dillard’s Department Store
website. If the current visitor to ParFore’s website previously visited the Dillard’s website, what is
the revised probability that the current visitor is female? Should the ParFore’s website display the
special offer that appeals to female visitors or the special offer that appeals to male visitors?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 2
Consider that:
It is given in the problem that,
And,
So the probability that the current visitor is a female is mentioned in the problem that is,
Comment
Step 2 of 2
Consider that:
It is given in the problem that,
And,
So, the required probability is given as below:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-44E-solution-9781337901062
1/3
4/13/22, 4:04 PM

Solved: ParFore created a website to market golf equipment and ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Was this solution helpful?
1
2
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-44E-solution-9781337901062
2/3
4/13/22, 4:04 PM


Solved: ParFore created a website to market golf equipment and ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-44E-solution-9781337901062
3/3
4/13/22, 4:04 PM

Solved: Americans Without Health Insurance. The National Center... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 45E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Americans Without Health Insurance. The National Center for Health Statistics, housed within
the U.S. Centers for Disease Control and Prevention (CDC), tracks the number of adults in the
Next
1 question remaining
United States who have health insurance. According to this agency, the uninsured rates for
Americans in 2018 are as follows: 5.1% of those under the age of 18, 12.4% of those ages 18–
64, and 1.1% of those 65 and older do not have health insurance (CDC website). Approximately
22.8% of Americans are under age 18, and 61.4% of Americans are ages 18–64.
My Textbook Solutions
a. What is the probability that a randomly selected person in the United States is 65 or older?
b. Given that the person is an uninsured American, what is the probability that the person is 65 or
older?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 4
Consider the number of adults in the United States who have health insurance are tracked. The
uninsured rates for Americans in 2018 are given as follows:
It is given that approximately 22.8% of Americans are under the age of 18 years and 61.4% of
the Americans are in the age group of 18 to 64 years.
Comment
Step 2 of 4
a.
The objective of this part is to find the probability that a randomly selected person in the United
States is 65 or older.
The probability that a randomly selected person in the United States is 65 or older can be written
as follows:
Using the given probabilities, the required probability is calculated as follows:
Therefore, the probability that a randomly selected person in the United States is 65 or older is
.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-45E-solution-9781337901062
1/3
4/13/22, 4:04 PM

Solved: Americans Without Health Insurance. The National Center... | Chegg.com

Home
Study tools

My courses
Step 3 of 
4
My books
My folder
Career
Life

b.
The objective of this part is to find the probability that the person is 65 or older given that the
person is an uninsured American.
The required probability is
.
Baye’s Theorem can be used to find the required probability. This theorem can be used to find
the posterior probabilities given the prior probabilities. The formula for Baye’s theorem can be
defined as follows:
Here,
are the prior probabilities and
are conditional probabilities.
Comment
Step 4 of 4
Using Baye’s theorem, the required probability can be written as follows:
Substitute the given probabilities into the formula.
Therefore, the probability that the person is 65 or older given that the person is an uninsured
American is
.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-45E-solution-9781337901062
2/3
4/13/22, 4:04 PM
CUSTOMER
SERVICE Home


Solved: Americans Without Health Insurance. The National Center... | Chegg.com
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-45E-solution-9781337901062
3/3
4/13/22, 4:05 PM

Solved: Time in Vacation Until Relaxed. A USA Today survey of a... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 46SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Time in Vacation Until Relaxed. A USA Today survey of adults aged 18 and older conducted by
Princess Cruises asked how many days into your vacation does it take until you feel truly
Next
1 question remaining
relaxed. The responses were as follows: 422—a day or less; 181—2 days; 80—3 days; 121—4
or more days; and 201—never feel relaxed.
a. How many adults participated in the Princess Cruises survey?
My Textbook Solutions
b. What response has the highest probability? What is the probability of this response?
c. What is the probability a respondent never feels truly relaxed on a vacation?
d. What is the probability it takes a respondent 2 or more days to feel truly relaxed?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 8
Consider a survey of adults aged 18 and older regarding the number of days taken to feel truly
relaxed on a vacation.
Comment
Step 2 of 8
a.
The objective of this part is to find the total number of adults who participated in the survey.
The total number of adults who participated in the survey is the sum of the responses collected.
Therefore, 1005 adults participated in the survey.
Comment
Step 3 of 8
b.
The objective of this part is to find the response which has the highest probability and find the
probability of this response.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-46SE-solution-9781337901062
1/3
4/13/22, 4:05 PM

Solved: Time in Vacation Until Relaxed. A USA Today survey of a... | Chegg.com
The number of responses is more or most frequent for a day or less with the highest number of
Home
Study
tools of ‘aMy
courses
My
books
My folder
of 422.
This response
day
or less’ has the
highest
probability.
responses


Career
Life

The formula for probability is defined as follows:
The number of possible outcomes is the number of responses of ‘a day or less’ is 422. The total
number of outcomes are 1005.
Comment
Step 4 of 8
Using this, the required probability is calculated as follows:
Therefore, the response of ‘a day or less’ has the highest probability and the probability is
.
Comment
Step 5 of 8
c.
The objective of this part is to find the probability that a respondent never feels truly relaxed on a
vacation.
The number of responses for a respondent never feeling truly relaxed on a vacation are 201.
The formula for probability is defined as follows:
The number of possible outcomes is the number of responses of ‘never feels relaxed’ is 201. The
total number of outcomes are 1005.
Comment
Step 6 of 8
Using this, the required probability is calculated as follows:
Therefore, the probability that a respondent never feels truly relaxed on a vacation is
.
Comment
Step 7 of 8
d.
The objective of this part is to find the probability that it takes a respondent 2 or more days to feel
truly relaxed on a vacation.
The number of responses for a respondent who takes 2 or more days to feel truly relaxed is
calculated as follows:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-46SE-solution-9781337901062
2/3
4/13/22, 4:05 PM

Solved: Time in Vacation Until Relaxed. A USA Today survey of a... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 8 of 8
Using this, the required probability is calculated as follows:
Therefore, the probability that it takes a respondent 2 or more days to feel truly relaxed on a
vacation is .
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-46SE-solution-9781337901062
3/3
4/13/22, 4:05 PM

Solved: A financial manager made two new investments—one in the... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 47SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
A financial manager made two new investments—one in the oil industry and one in municipal
bonds. After a one-year period, each of the investments will be classified as either successful or
Next
1 question remaining
unsuccessful. Consider the making of the two investments as an experiment.
a. How many sample points exist for this experiment?
b. Show a tree diagram and list the sample points.
My Textbook Solutions
c. Let O = the event that the oil industry investment is successful and M = the event that the
municipal bond investment is successful. List the sample points in O and in M.
d. List the sample points in the union of the events (O ⋃ M).
e. List the sample points in the intersection of the events (O ⋂ M).
f. Are events O and M mutually exclusive? Explain.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 6
(a)
Four sample points exist for the experiment. They are as follows:
• Oil industry–Successful.
• Oil industry–Unsuccessful.
• Municipal bonds – Successful.
• Municipal bonds – Unsuccessful.
Comment
Step 2 of 6
(b)
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-47SE-solution-9781337901062
1/3
4/13/22, 4:05 PM

Solved: A financial manager made two new investments—one in the... | Chegg.com
Comment

Home
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 6
(c)
The sample points in O and M are as follows:
• Oil industry–Successful
• Municipal bonds – Successful
Comment
Step 4 of 6
(d)
The sample points in the union of the events is,
= {Oil industry–Successful, Municipal bonds – Successful}
Comment
Step 5 of 6
(e)
There are no events in the intersection of the events.
Comment
Step 6 of 6
(f)
Yes. Since there are no common events, O and M are mutually exclusive.
Comment
Was this solution helpful?
7
2
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-47SE-solution-9781337901062
2/3
4/13/22, 4:05 PM
CUSTOMER SERVICE


Solved: A financial manager made two new investments—one in the... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-47SE-solution-9781337901062
3/3
4/13/22, 4:05 PM

Solved: Opinions About Television Programs. Below are the resul... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 48SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Opinions About Television Programs. Below are the results of a survey of 1364 individuals
who were asked if they use social media and other websites to voice their opinions about
Next
1 question remaining
television programs.
My Textbook Solutions
a. What is the probability a respondent is female?
b. What is the conditional probability a respondent uses social media and other websites to voice
opinions about television programs given the respondent is female?
c. Let F denote the event that the respondent is female and A denote the event that the
respondent uses social media and other websites to voice opinions about television programs.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Are events F and A independent?
Step-by-step solution
Step 1 of 9
Consider the survey of 1364 individuals who were asked if they use social media and other
websites to voice their opinions about television programs. The responses are received as
follows:
Comment
Step 2 of 9
a.
The objective of this part is to find the probability that the respondent is a female.
The given survey results shows that the total number of female respondents are
. The total number of respondents are 1364.
The formula for probability is defined as follows:
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-48SE-solution-9781337901062
1/3
4/13/22, 4:05 PM

Solved: Opinions About Television Programs. Below are the resul... | Chegg.com

Home
Study tools

Step 3 of 9
My courses

My books
My folder
Career
Life

Using the probability formula, the required probability is calculated as follows:
Therefore, the probability that a respondent is female is .
Comment
Step 4 of 9
b.
The objective of this part is to find the conditional probability that a respondent uses social media
and other websites to voice opinions about television programs given that the respondent is a
female.
Let A be the event that the respondent uses social media and other websites to voice opinions
about television programs. Let F be the event that the respondent is a female.
The required probability is .
The formula for conditional probability for two events A and B is defined as follows:
Comment
Step 5 of 9
Using the formula for conditional probability, the required probability can be written as follows:
The number of female respondents who use social media and other websites to voice opinion
about television programs is 395. The total number of female respondents are 686. The total
number of respondents in the survey are 1364. Using this information and the probability formula,
the required probability is calculated as follows:
Therefore, the conditional probability that a respondent uses social media and other websites to
voice opinions about television programs given that the respondent is a female is .
Comment
Step 6 of 9
c.
The objective of this part is to determine whether the events F and A are independent.
Let A be the event that the respondent uses social media and other websites to voice opinions
about television programs. Let F be the event that the respondent is a female.
Two events A and B are said to be independent if . So, the events F and A can be independent if
.
Calculate the probability .
Comment
Step 7 of 9
The given survey results shows that the total number of respondents who uses social media and
other websites to voice opinions about television programs are . The total number of respondents
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-48SE-solution-9781337901062
2/3
4/13/22, 4:05 PM

Solved: Opinions About Television Programs. Below are the resul... | Chegg.com
are 1364.
Homefor probability
Study tools
My courses
The formula
is defined as follows:


My books
My folder
Career
Life

Comment
Step 8 of 9
Using the probability formula, the required probability is calculated as follows:
Therefore, the probability is calculated as 0.5264.
Comment
Step 9 of 9
The probability is determined as in part (b). So, this shows that . Hence, the events A and F are
not independent.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-48SE-solution-9781337901062
3/3
4/13/22, 4:05 PM

Solved: A study of 31,000 hospital admissions in New York State... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
1 Bookmark
Chapter 4, Problem 49SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
A study of 31,000 hospital admissions in New York State found that 4% of the admissions led to
treatment-caused injuries. One-seventh of these treatment-caused injuries resulted in death, and
Next
1 question remaining
one-fourth were caused by negligence. Malpractice claims were filed in one out of 7.5 cases
involving negligence, and payments were made in one out of every two claims.
a. What is the probability a person admitted to the hospital will suffer a treatment-caused injury
due to negligence?
My Textbook Solutions
b. What is the probability a person admitted to the hospital will die from a treatment-caused
injury?
c. In the case of a negligent treatment-caused injury, what is the probability a malpractice claim
will be paid?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 4
A study of 31,000 hospital admissions in New York State found that the admission led to
treatment-caused injuries. That is
One-seventh of these treatment-caused injuries resulted in death. That is
One-fourth of these treatment-caused injuries resulted by negligence. That is
Also given that malpractice claims were field in one out of 7.5 cases involving negligence. That is
The payment was made one out of two claims. That is
Comment
Step 2 of 4
a) The probability that a person admitted to the hospital will suffer a treatment-caused injury due
to negligence is given by
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-49SE-solution-9781337901062
1/2
4/13/22, 4:05 PM

Solved: A study of 31,000 hospital admissions in New York State... | Chegg.com

Home
Study tools

Step 3 of 4
My courses

My books
My folder
Career
Life

b) The probability that a person admitted to the hospital will die from a treatment-cause injury is
given by
Comment
Step 4 of 4
c) The probability that a malpractice claim will paid in the case of a negligent treatment-caused
injury is given by
Comment
Was this solution helpful?
2
1
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-49SE-solution-9781337901062
2/2
4/13/22, 4:05 PM

Solved: A telephone survey to determine viewer response to a ne... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 50SE
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
A telephone survey to determine viewer response to a new television show obtained the
following data.
Next
1 question remaining
My Textbook Solutions
a. What is the probability that a randomly selected viewer will rate the new show as average or
better?
b. What is the probability that a randomly selected viewer will rate the new show below average
or worse?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step-by-step solution
Step 1 of 2
(a)
The probability that a randomly selected viewer will rate average or better is,
Comment
Step 2 of 2
(b)
The probability that a randomly selected viewer will rate below average or worse is,
Comment
Was this solution helpful?
9
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-50SE-solution-9781337901062
1/2
4/13/22, 4:05 PM


Solved: A telephone survey to determine viewer response to a ne... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-50SE-solution-9781337901062
2/2
4/13/22, 4:06 PM

Solved: Highest Level of Education and Household Income. The U.... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 51SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Highest Level of Education and Household Income. The U.S. Census Bureau serves as the
Continue to post
leading source of quantitative data about the nation’s people and economy. The following
1 question remaining
crosstabulation shows the number of households (1000s) and the household income by the
highest level of education for the head of household (U.S. Census Bureau website,
https://www.census.gov/library/publications/2017/acs/acsbr16-02.html). Only households in
which the head has a high school diploma or more are included.
My Textbook Solutions
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
a. Develop a joint probability table.
b. What is the probability of the head of one of these households having a master’s degree or
more education?
c. What is the probability of a household headed by someone with a high school diploma earning
$100,000 or more?
d. What is the probability of one of these households having an income below $25,000?
e. What is the probability of a household headed by someone with a bachelor’s degree earning
less than $25,000?
f. Is household income independent of educational level?
Step-by-step solution
Step 1 of 9
Consider the given crosstabulation of number of households (1000s) and the household income
by the highest level of education for the head of household.
Comment
Step 2 of 9
a.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-51SE-solution-9781337901062
1/4
4/13/22, 4:06 PM

Solved: Highest Level of Education and Household Income. The U.... | Chegg.com
The objective of this part is to construct a joint probability table.
Home Study tools
My courses
My books My folder
Joint probability
is the probability of occurrence of two or more events that happen


Career
Life

simultaneously. It can be considered as the intersection of two or more events.
Joint probability is calculated by dividing the value in the intersection of the events by the table
total.
The joint probabilities are calculated as follows:
Comment
Step 3 of 9
Thus, the joint probability table is obtained as follows:
Thus, the joint probability table is constructed.
Comment
Step 4 of 9
b.
The objective of this part is to find the probability that the head of one of these households have
Master’s degree or more education.
The required probability that the head of one of these households have Master’s degree or more
education is the sum of the probabilities of the household having a Master’s degree or a Doctoral
degree.
The obtained joint probability table shows that
and
.
So, the required probability can be calculated as follows:
Therefore, the probability that the head of one of these households have Master’s degree or
more education is
.
Comment
Step 5 of 9
c.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-51SE-solution-9781337901062
2/4
4/13/22, 4:06 PM

Solved: Highest Level of Education and Household Income. The U.... | Chegg.com
The objective of this part is to find the probability that a household headed by someone with a
Home
Study
tools
courses
diploma
earns
$100,000 My
or more.
high school


My books
My folder
Career
Life

The probability that a household headed by someone with a high school diploma earns $100,000
or more is the probability that is found in the intersection of High School graduate and income of
$100,000 or more in the Joint probability table obtained in part (a).
This probability is obtained as
.
Therefore, the probability that a household headed by someone with a high school diploma earns
$100,000 or more is
.
Comment
Step 6 of 9
d.
The objective of this part is to find the probability of one of the households who have an income
below $25,000.
The obtained joint probability table shows that the probability of one of the households who have
income below $25000 is the probability in the column of household income under $25000.
Therefore, the probability of one of the households who have an income below $25,000 is
.
Comment
Step 7 of 9
e.
The objective of this part is to find the probability of a household headed by someone with a
bachelor’s degree earning is less than $25,000.
The probability that a household headed by someone with a bachelor’s degree earns less than
$25,000 is the probability that is found in the intersection of bachelor’s degree and income of
$25,000 or less in the Joint probability table obtained in part (a).
This probability is obtained as
.
Therefore, the probability that a household headed by someone with a bachelor’s degree earning
is less than $25,000 is
.
Comment
Step 8 of 9
f.
The objective of this part is to determine whether the household income is independent of
educational level.
Two events A and B are said to be independent if
.
Consider any income group and educational level. Consider income group of 25000 or less and
educational level of ‘high school degree’.
Determine whether these two events are independent. So, it has to be proved that
.
The probabilities can be obtained from the Joint probability table as follows:
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-51SE-solution-9781337901062
3/4
4/13/22, 4:06 PM

Solved: Highest Level of Education and Household Income. The U.... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 9 of 9
Determine whether the events are independent.
Therefore, the household income is not independent of educational level.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-51SE-solution-9781337901062
4/4
4/13/22, 4:06 PM

Solved: An MBA new-matriculants survey provided the following d... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 52SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
An MBA new-matriculants survey provided the following data for 2018 students.
Next
1 question remaining
My Textbook Solutions
a. For a randomly selected MBA student, prepare a joint probability table for the experiment
consisting of observing the student’s age and whether the student applied to one or more
schools.
b. What is the probability that a randomly selected applicant is 23 or under?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
c. What is the probability that a randomly selected applicant is older than 26?
d. What is the probability that a randomly selected applicant applied to more than one school?
Step-by-step solution
Step 1 of 4
(a)
The joint probability table for the given data is as follows:
Comment
Step 2 of 4
(b)
The probability that a randomly selected applicant is 23 or under is,
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-52SE-solution-9781337901062
1/2
4/13/22, 4:06 PM

Solved: An MBA new-matriculants survey provided the following d... | Chegg.com

Home
Study tools

Step 3 of 
4
My courses
My books
My folder
Career
Life

(c)
The probability that a randomly selected applicant is older than 26 is,
Comment
Step 4 of 4
(d)
The probability that a randomly selected applicant applied to more than one school is,
Comment
Was this solution helpful?
10
1
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-52SE-solution-9781337901062
2/2
4/13/22, 4:07 PM

Solved: Refer again to the data from the MBA new-matriculants s... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 53SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Refer again to the data from the MBA new-matriculants survey in exercise 52.
Continue to post
1 question remaining
a. Given that a person applied to more than one school, what is the probability that the person is
24-26 years old?
b. Given that a person is in the 36-and-over age group, what is the probability that the person
My Textbook Solutions
applied to more than one school?
c. What is the probability that a person is 24-26 years old or applied to more than one school?
d. Suppose a person is known to have applied to only one school. What is the probability that the
person is 31 or more years old?
e. Is the number of schools applied to independent of age? Explain.
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 7
(a) The joint probability table for the given data is as follows:
Comment
Step 2 of 7
The probability that a person is 24-26 years old given that the person has applied to more than
one school is
Comment
Step 3 of 7
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-53SE-solution-9781337901062
1/3
4/13/22, 4:07 PM

Solved: Refer again to the data from the MBA new-matriculants s... | Chegg.com
TheHome
probability
that atools
person applied
more than one
school
givenMy
thatfolder
the person isCareer
in the
Study
My to
courses
My
books
(b)
36 and over age group is


Life

Comment
Step 4 of 7
(c) From Addition Law of probability, we know that
Hence the probability that a person is 24-26 years old or applied to more than one school is
given by:
Comment
Step 5 of 7
(d) The probability that a person is 31 years or old and applied to only one school is given by:
Comment
Step 6 of 7
The conditional probability that a person is 31 years or old given that the person applied to only
one school is given by:
Comment
Step 7 of 7
e) Two events A and B are independent if
.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-53SE-solution-9781337901062
2/3
4/13/22, 4:07 PM

Solved: Refer again to the data from the MBA new-matriculants s... | Chegg.com
Let us consider the two events ‘a student is 24-26 years old’ and the event that the ‘a student
Study
to more than
onetools
school’
appliedHome

My courses

My books
My folder
Career
Life

From the above two probability values, we can observe that
Hence, the number of schools applied to and age are not independent.
Comment
Was this solution helpful?
4
4
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-53SE-solution-9781337901062
3/3
4/13/22, 4:07 PM

Solved: Internet Sites Collecting User Information. The Pew Int... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 54SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Internet Sites Collecting User Information. The Pew Internet & American Life project
Continue to post
conducted a survey that included several questions about how Internet users feel about search
1 question remaining
engines and other websites collecting information about them and using this information either to
shape search results or target advertising to them. In one question, participants were asked, “If a
search engine kept track of what you search for, and then used that information to personalize
your future search results, how would you feel about that?” Respondents could indicate either
My Textbook Solutions
“Would not be okay with it because you feel it is an invasion of your privacy” or “Would be okay
with it, even if it means they are gathering information about you.” Frequencies of responses by
age group are summarized in the following table.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
a. What is the probability a survey respondent will say she or he is not okay with this practice?
b. Given a respondent is 30–49 years old, what is the probability the respondent will say she or
he is okay with this practice?
c. Given a respondent says she or he is not okay with this practice, what is the probability the
respondent is 50+ years old?
d. Is the attitude about this practice independent of the age of the respondent? Why or why not?
e. Do attitudes toward this practice for respondents who are 18–29 years old and respondents
who are 50+ years old differ?
Step-by-step solution
Step 1 of 10
Consider a survey conducted about how Internet users feel about search engines and other
websites collecting information about them and then using this information to shape search
results or target advertising to them. The frequencies of response are summarized by age group
as follows:
Comment
Step 2 of 10
a.
The objective of this part is to find the probability that a survey respondent will say that she or he
is not okay with the practice.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-54SE-solution-9781337901062
1/5
4/13/22, 4:07 PM

Solved: Internet Sites Collecting User Information. The Pew Int... | Chegg.com
The probability that a survey respondent will say that she or he is not okay with the practice is the
Home
Study
tools is notMy
books
folder
Career
that the
respondent
okaycourses
from any age My
group.
So, the My
required
probability
is the
probability


Life

sum of probabilities of the respondents saying ‘Not okay’ in all age groups.
Comment
Step 3 of 10
Using the respective probabilities from the given table of probabilities, the required probability is
calculated as follows:
Therefore, the probability that a survey respondent will say that she or he is not okay with the
practice is
.
Comment
Step 4 of 10
b.
The objective of this part is to find the probability that the respondent will say she or he is okay
with this practice given that the respondent is 30-49 years old.
The required probability is
.
The formula for conditional probability for two events A and B is defined as follows:
Comment
Step 5 of 10
Using the formula for conditional probability, the required probability can be written as follows:
Using the respective probabilities from the given probability table, the required probability is
calculated as follows:
Therefore, the probability that the respondent will say she or he is okay with this practice given
that the respondent is 30-49 years old is
.
Comment
Step 6 of 10
c.
The objective of this part is to find the probability that the respondent is 50+ years old given that
the respondent says he or she is not okay with this practice.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-54SE-solution-9781337901062
2/5
4/13/22, 4:07 PM

Solved: Internet Sites Collecting User Information. The Pew Int... | Chegg.com
The required probability is
.
Home Study tools
My courses
My books My folder
The formula
for conditional probability for two events A and B is defined as follows:


Career
Life

Comment
Step 7 of 10
Using the formula for conditional probability, the required probability can be written as follows:
Using the respective probabilities from the given probability table, the required probability is
calculated as follows:
Therefore, the probability that the respondent is 50+ years old given that the respondent says he
or she is not okay with this practice is
.
Comment
Step 8 of 10
d.
The objective of this part is to determine whether the attitude about this practice is independent
of the age of the respondent.
Two events A and B are said to be independent if
.
Consider any age group and attitude of the practice. Consider age group of 30 – 49 and the
attitude of Okay.
From part (b), it is determined that
. From part (a), the probability of
Okay is calculated as follows:
This shows that
. Hence the attitude about the practice are not
independent of the age of the respondent because the probabilities are not equal.
Therefore, the data suggests that the attitude about this practice is not independent of the age of
the respondent because the probabilities are not equal.
Comment
Step 9 of 10
e.
The objective of this part is to determine whether there is difference in attitudes towards this
practice for respondents who are 18 – 29 years old and respondent who are 50+ years old.
Compare the probabilities and
to determine whether there is any
difference in attitudes towards this practice for respondents who are 18 – 29 years old and
respondent who are 50+ years old.
Using the formula for conditional probability, the probability can be written as follows:
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-54SE-solution-9781337901062
3/5
4/13/22, 4:07 PM

Solved: Internet Sites Collecting User Information. The Pew Int... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 10 of 10
Using the formula for conditional probability, the probability
can be written
as follows:
The obtained probabilities shows that the respondents in the age of 50+ age category are more
likely to say this practice is ‘not okay’ than the respondents in the 18-29 age category.
Comment
Was this solution helpful?
1
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-54SE-solution-9781337901062
4/5
4/13/22, 4:07 PM


Solved: Internet Sites Collecting User Information. The Pew Int... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-54SE-solution-9781337901062

5/5
4/13/22, 4:08 PM

Solved: A large consumer goods company ran a television adverti... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 55SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
A large consumer goods company ran a television advertisement for one of its soap products. On
the basis of a survey that was conducted, probabilities were assigned to the following events.
Next
1 question remaining
My Textbook Solutions
The probabilities assigned were P(B)= .20, P(S) = .40, and P(B ⋂ S) = .12.
a. What is the probability of an individual’s purchasing the product given that the individual recalls
seeing the advertisement? Does seeing the advertisement increase the probability that the
individual will purchase the product? As a decision maker, would you recommend continuing the
advertisement (assuming that the cost is reasonable)?
b. Assume that individuals who do not purchase the company’s soap product buy from its
competitors. What would be your estimate of the company’s market share? Would you expect
that continuing the advertisement will increase the company’s market share? Why or why not?
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
c. The company also tested another advertisement and assigned it values of P(S) = .30 and P(B
⋂ S) = .10. What is P(B | S) for this other advertisement? Which advertisement seems to have
had the bigger effect on customer purchases?
Step-by-step solution
Step 1 of 3
(a)
We are given that,
The probability that an individual’s purchasing the product given that the individual recalls seeing
the advertisement is,
Yes. Individual seeing an advertisement increase the probability from 0.20 to 0.30.
Hence, we would recommend continuing the advertisement.
Comment
Step 2 of 3
(b)
The company’s market share,
Yes. Continuing the advertisement will increase the company’s market share from 20% to 30%.
Comment
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-55SE-solution-9781337901062
1/2
4/13/22, 4:08 PM

Solved: A large consumer goods company ran a television adverti... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Step 3 of 3
(c)
We are given that,
Hence, the newer advertisement is better than the earlier one.
Comment
Was this solution helpful?
25
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-55SE-solution-9781337901062
2/2
4/13/22, 4:08 PM

Solved: Cooper Realty is a small real estate company located in... | Chegg.com

Home
Study tools
My courses


My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 56SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Cooper Realty is a small real estate company located in Albany, New York, specializing primarily
in residential listings. They recently became interested in determining the likelihood of one of
Next
1 question remaining
their listings being sold within a certain number of days. An analysis of company sales of 800
homes in previous years produced the following data.
My Textbook Solutions
a. If A is defined as the event that a home is listed for more than 90 days before being sold,
estimate the probability of A.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
b. If B is defined as the event that the initial asking price is under $150,000, estimate the
probability of B.
c. What is the probability of A ⋂ B?
d. Assuming that a contract was just signed to list a home with an initial asking price of less than
$150,000, what is the probability that the home will take Cooper Realty more than 90 days to
sell?
e. Are events A and B independent?
Step-by-step solution
Step 1 of 5
(a)
Given that A is the event that a home is listed for more than 90 days before being sold.
Comment
Step 2 of 5
(b)
Given that B is the event that the initial asking price is under $150,000.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-56SE-solution-9781337901062
1/3
4/13/22, 4:08 PM

Solved: Cooper Realty is a small real estate company located in... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 5
(c)
Comment
Step 4 of 5
(d)
Comment
Step 5 of 5
(e)
From the above probabilities we can observe that
Hence, A and B are not independent.
Comment
Was this solution helpful?
23
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-56SE-solution-9781337901062
2/3
4/13/22, 4:08 PM
Solved: Cooper Realty is a small real estate company located in... | Chegg.com
CHEGG NETWORK


CUSTOMER SERVICE
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-56SE-solution-9781337901062
3/3
4/13/22, 4:08 PM

Solved: A company studied the number of lost-time accidents occ... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Show all steps:
Bookmark
Chapter 4, Problem 57SE
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant.
Historical records show that 6% of the employees suffered lost-time accidents last year.
Next
1 question remaining
Management believes that a special safety program will reduce such accidents to 5% during the
current year. In addition, it estimates that 15% of employees who had lost-time accidents last
year will experience a lost-time accident during the current year.
a. What percentage of the employees will experience lost-time accidents in both years?
My Textbook Solutions
b. What percentage of the employees will suffer at least one lost-time accident over the two-year
period?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 2
(a)
We are given that,
The probability that the employees will experience lost – time accidents in both years is,
0.9% percent of the employees will experience lost – time accidents in both the years.
Comment
Step 2 of 2
(b)
The probability that the employees will suffer at least one lost – time accident over the two – year
period is,
Comment
Was this solution helpful?
8
0
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-57SE-solution-9781337901062
1/3
4/13/22, 4:08 PM


Solved: A company studied the number of lost-time accidents occ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-57SE-solution-9781337901062
2/3
4/13/22, 4:08 PM


Solved: A company studied the number of lost-time accidents occ... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-57SE-solution-9781337901062

3/3
4/13/22, 4:08 PM

Solved: Students Studying Abroad. Many undergraduate students i... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 58SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
Students Studying Abroad. Many undergraduate students in the U.S. study abroad as part of
their education. Assume that 60% of the undergraduate students who study abroad are female
Next
1 question remaining
and that 49% of the undergraduate students who do not study abroad are female.
a. Given a female undergraduate student, what is the probability that she studies abroad?
b. Given a male undergraduate student, what is the probability that he studies abroad?
My Textbook Solutions
c. What is the overall percentage of full-time female undergraduate students? What is the overall
percentage of full-time male undergraduate students?
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 4
(a)
Let X denote the students who study abroad and
denote the students who do not study
abroad.
Let Y denote male undergraduate students and
denote female undergraduate students.
Given that 60% of students who study abroad are females.
Given that 49% of students who do not study abroad are females.
Given that 9.5% of all full-time U.S undergraduate students study abroad.
Comment
Step 2 of 4
To find the conditional probability that she studies abroad given that student is female.
Using Bayer’s theorem,
To find the probability of
.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-58SE-solution-9781337901062
1/3
4/13/22, 4:08 PM

Solved: Students Studying Abroad. Many undergraduate students i... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Substituting the values,
Conditional probability that she studies abroad given that student is female is
.
Comment
Step 3 of 4
(b)
To find the conditional probability that he studies abroad given that student is male.
Using Bayer’s theorem,
Substituting the values,
Conditional probability that he studies abroad given that student is male is
.
(c)
To find the percentage of female undergraduate students.
Hence the overall percentage of female undergraduate students is
.
Comment
Step 4 of 4
To find the percentage of male undergraduate students.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-58SE-solution-9781337901062
2/3
4/13/22, 4:08 PM

Solved: Students Studying Abroad. Many undergraduate students i... | Chegg.com

Home
Study tools

My courses

My books
My folder
Hence the overall percentage of male undergraduate students is
Career
Life

.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-58SE-solution-9781337901062
3/3
4/13/22, 4:09 PM

Solved: An oil company purchased an option on land in Alaska. P... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 59SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Continue to post
An oil company purchased an option on land in Alaska. Preliminary geologic studies assigned
the following prior probabilities.
Next
1 question remaining
My Textbook Solutions
a. What is the probability of finding oil?
b. After 200 feet of drilling on the first well, a soil test is taken. The probabilities of finding the
particular type of soil identified by the test follow.
Statistics for
Business &...
A First
Course in...
Differential
Equations..
How should the firm interpret the soil test? What are the revised probabilities, and what is the
14th Edition
8th Edition
6th Edition
new probability of finding oil?
View all solutions
Step-by-step solution
Step 1 of 6
An oil company purchased an option on land in Alaska. Preliminary geologic studies assigned
the following probabilities:
a) Now we have to find the probability of finding oil.
From the given data we have
Comment
Step 2 of 6
b) After 200 feet the soil is taken for test and the probabilities of finding the particular type of soil
identified by the test follow:
Soil test is conducted as
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-59SE-solution-9781337901062
1/3
4/13/22, 4:09 PM

Solved: An oil company purchased an option on land in Alaska. P... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

From the above probability value we can say that 32% of the soil can produce oil.
Comment
Step 3 of 6
The new probabilities are found as
Comment
Step 4 of 6
Comment
Step 5 of 6
Comment
Step 6 of 6
Now we have to find the probability of finding oil.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-59SE-solution-9781337901062
2/3
4/13/22, 4:09 PM

Solved: An oil company purchased an option on land in Alaska. P... | Chegg.com
From the given data we have

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Was this solution helpful?
10
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-59SE-solution-9781337901062
3/3
4/13/22, 4:09 PM

Solved: Spam Email Filters. A study by Forbes indicated that th... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 60SE
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
Spam Email Filters. A study by Forbes indicated that the five most common words appearing in
Continue to post
spam emails are shipping!, today!, here!, available, and fingertips!. Many spam filters separate
1 question remaining
spam from ham (email not considered to be spam) through application of Bayes’ theorem.
Suppose that for one email account, 1 in every 10 messages is spam and the proportions of
spam messages that have the five most common words in spam email are given below.
Also suppose that the proportions of ham messages that have these words are
My Textbook Solutions
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
a. If a message includes the word shipping!, what is the probability the message is spam? If a
message includes the word shipping!, what is the probability the message is ham? Should
messages that include the word shipping! be flagged as spam?
b. If a message includes the word today!, what is the probability the message is spam? If a
message includes the word here!, what is the probability the message is spam? Which of these
two words is a stronger indicator that a message is spam? Why?
c. If a message includes the word available, what is the probability the message is spam? If a
message includes the word fingertips!, what is the probability the message is spam? Which of
these two words is a stronger indicator that a message is spam? Why?
d. What insights do the results of parts (b) and (c) yield about what enables a spam filter that
uses Bayes’ theorem to work effectively?
Step-by-step solution
Step 1 of 3
(a)
Given that one in every 10 messages is a spam. Hence the probability of a spam message is,
To find the conditional probability that the message is a spam given that the message includes
the word ‘shipping’, use Bayer’s theorem.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-60SE-solution-9781337901062
1/4
4/13/22, 4:09 PM

Solved: Spam Email Filters. A study by Forbes indicated that th... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The conditional probability that the message is a spam given that the message includes the word
‘shipping’ is 0.791.
To find the conditional probability that the message is a ham given that the message includes the
word ‘shipping’, subtract the previous conditional probability from 1.
The conditional probability that the message is a ham given that the message includes the word
‘shipping’ is 0.209.
Given, the message contains the word shipping! the probability that the message is spam is
greater than the message is ham and thus, the word shipping! should be flagged as spam.
(b)
To find the conditional probability that the message is a spam given that the message includes
the word ‘today’, use Bayer’s theorem.
The conditional probability that the message is a spam given that the message includes the word
‘today’ is 0.694.
To find the conditional probability that the message is a spam given that the message includes
the word ‘here’, use Bayer’s theorem.
The conditional probability that the message is a spam given that the message includes the word
‘here’ is 0.632.
As, the probability that the message containing today! is spam is greater than the probability that
the message containing here! is spam, the today! word is strong indicator that the message is
spam.
Comment
Step 2 of 3
(c)
To find the conditional probability that the message is a spam given that the message includes
the word ‘available’, use Bayer’s theorem.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-60SE-solution-9781337901062
2/4
4/13/22, 4:09 PM

Solved: Spam Email Filters. A study by Forbes indicated that th... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

The conditional probability that the message is a spam given that the message includes the word
‘available’ is 0.275.
To find the conditional probability that the message is a spam given that the message includes
the word ‘fingertip’, use Bayer’s theorem.
The conditional probability that the message is a spam given that the message includes the word
‘fingertip’ is 0.5858.
As, the probability that the message containing fingertips! is spam is greater than the probability
that the message containing available! is spam, the fingertips! word is strong indicator that the
message is spam.
Comment
Step 3 of 3
(d)
By the result of part (b) and part (c), the words today!, here!, fingertips! in a mail suggests that
there is more than 50% chance of mail being spam. The spam filter with these words in the mail
should flag it as spam.
Comment
Was this solution helpful?
0
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-60SE-solution-9781337901062
3/4
4/13/22, 4:09 PM


Solved: Spam Email Filters. A study by Forbes indicated that th... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life

© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-60SE-solution-9781337901062
4/4
4/13/22, 4:02 PM

Solved: The prior probabilities for events A1, A2, and A3 are P... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Search
Find solutions for your homework
home / study / math / statistics and probability / statistics and probability solutions manuals / statistics for business & economics / 14th edition
Statistics for Business & Economics (14th Edition)
Bookmark
Chapter 4, Problem 40E
Show all steps:
Post a question
Answers from our experts for your tough
homework questions
ON
Enter question
Problem
The prior probabilities for events A1, A2, and A3 are P(A1) = .20, P(A2) = .50, and P(A3) = .30.
Continue to post
1 question remaining
The conditional probabilities of event B given A1, A2, and A3 are P(B | A1) = .50, P(B | A2) = .40,
and P(B | A3) = .30.
a. Compute P(B ⋂ A1), P(B ⋂ A2), and P(B ⋂ A3).
b. Apply Bayes’ theorem, equation (4.19), to compute the posterior probability P(A2 | B).
My Textbook Solutions
c. Use the tabular approach to applying Bayes’ theorem to compute P(A1 | B), P(A2 | B), and
P(A3 | B).
Step-by-step solution
Statistics for
Business &...
A First
Course in...
Differential
Equations..
14th Edition
8th Edition
6th Edition
View all solutions
Step 1 of 3
From the information, observe that
are the three events with the probabilities 0.20,
0.50 and 0.30 respectively.
The conditional probabilities of event B given that
as follows:
a)
Calculate
Calculate
Calculate
Comment
Step 2 of 3
b)
Calculate
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-40E-solution-9781337901062
1/3
4/13/22, 4:02 PM

Solved: The prior probabilities for events A1, A2, and A3 are P... | Chegg.com

Home
Study tools

My courses

My books
My folder
Career
Life

Comment
Step 3 of 3
c)
Use the tabular approach to applying Bayes theorem to calculate
and
Comment
Was this solution helpful?
17
0
COMPANY
LEGAL & POLICIES
CHEGG PRODUCTS AND SERVICES
CHEGG NETWORK
CUSTOMER SERVICE
© 2003-2022 Chegg Inc. All rights reserved.
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-40E-solution-9781337901062
2/3
4/13/22, 4:02 PM


Solved: The prior probabilities for events A1, A2, and A3 are P... | Chegg.com
Home
Study tools

My courses

My books
My folder
Career
Life
https://www.chegg.com/homework-help/Statistics-for-Business-amp-Economics-14th-edition-chapter-4-problem-40E-solution-9781337901062

3/3