G3 | PSYCH 3A | 31/1/23 Members: Codera Colorado Cosare Dela Torre Harrid Fronteras Fernandez Mendelian Inheritance: Punnett Square & Introduction to Probability 1. Use two 5 peso coins. One coin is equivalent to a pair of genes from a single parent. (ex. Maternal). The other coin represents the same set of genes from the other parent. ( ex. paternal) a. P=head= dominant gene (purple) b. Recessive gene = p=tail (white) 2. There is heterozygosity in both parents (Pp) a. Pp is the genetic combination of a single parent b. Pp is another parent’s genes. 3. For the child of Pp X Pp, fill out the Punnett Square below. Keep a record of the outcomes in the Expected probability column of table 2. P p P PP Pp p Pp pp 4. In our coin-toss experiment, the P allele will be represented by heads, and the p allele by tails. 50 times total, toss the coins together; note the toss results in the coin toss tally column. 5. Determine the percentage for each genotype (ex.# of PP tosses/50) and record under actual probability on table 1. PP = 6x2 = 12% Pp = 31x2 = 62% pp= 13x2 = 26% = 100% Exercise 2 Mendelian Inheritance Punnett Square and Introduction to Probability WORKSHEET Table 1. Genotypic ratios for eye shape Trial Number EE 1 / 2 Ee ee / 3 / 4 / 5 / 6 / 7 / 8 / 9 / 10 / 11 12 / / 13 / 14 / 15 / 16 / 17 / 18 / 19 / 20 / total 5 9 6 % of each genotype 25% 45% 30% Table 2: Data for coin toss Coin toss tally Expected probabilit y Actual Probability PP (heads, heads) 25% 12% Pp (heads, tails) 50% 31% pp (tails, tails) 25% 26% total 100% 100% Practice Problems on Mendelian Genetics 1. The gene for normal skin pigmentation is dominant to the allele for albinism in humans. What is the probability that a child born to two heterozygotes will have a skin pigment that is normal? What are the odds of having an albino child? a. What are the odds that the child is a carrier if they are healthy? A a A AA Aa a Aa aa Normal pigment: 75% chance of AA & Aa Albino: 25% chance of aa The odds of having an albino child: 67% 2. In an unspecified animal species, one-horn is dominant and no horns are recessive. Show the cross of an individual heterozygous for horns with another individual that does not have horns? Summarize the genotypes & phenotypes of the possible offspring? H h h Hh hh h Hh hh 50% chance of Hh (horned) 50% chance of hh (no horn) 3. In humans, the brown-eye (B) allele is dominant to the blue-eye allele (b). If two heterozygotes mate, what will be the likely genotype and phenotype ratios of the offspring? B b B BB Bb b Bb bb 75% chance of brown-eyed 25% chance of blue-eyed 25% chance of BB 50% chance of Bb 25% chance of bb 4. In seals, the gene for the length of the whiskers has two alleles. The dominant allele (W) codes long whiskers & the recessive allele (w) codes for short whiskers. What percentage of offspring would be expected to have short whiskers from the cross of two long-whiskered seals, one that is homozygous dominant and one that is heterozygous? W w W WW Ww W WW Ww 0% chance of short whiskers POST LAB QUESTIONS 1. Based on the nips and coin toss activity, why is it crucial to carry out a lot of trials in an experiment? ● Based on the nips and toss activity, it is essential to run numerous trials in an experiment to increase the reliability of the results. Your average will get more closely to the true value as you perform more trials. As a result, the more trials we run, the more accurate our findings estimate will be. We can ensure that the results are consistent and unaffected by chance when we do the same experiment more than once. The experimental probability approaches the theoretical probability more closely as the number of trials increases. 2. Take a look at your punnett square cross genotypic ratio. These are the expected results. Examine these expected results against the actual percentages from your data table. Are they the same? Why or why not? ● Due to the numerous other allele combinations that can be made. The expected results against the actual percentages from the data table are not the same. ● They are not the same because there are many more combinations of alleles are possible. As when you flip a coin, there is a chance that the results get close to the expected values. Documentation while doing the lab activity: