10/05/2021 Genetics Patterns of Inheritance Mendelian Genetics Non-Mendelian Genetics 1 is a field in Biology that deals with heredity, or the passing of traits from parents to offspring. 2 Mendel used the scientific approach to identify the laws of inheritance ◦ Mendel discovered the basic principles of heredity by breeding garden peas: Pisum sativum Mendelian Genetics ◦ Advantages of using peas: 1. has distinct character variations (traits) 2. Mating can be controlled 3. Each plant can reproduce by itself (self-fertilize) 4. Can cross-fertilize via pollen transfer 3 4 Mendel used the scientific approach to identify the laws of inheritance Mendel’s Experiment Mendel mated two contrasting, true breeding varieties (hybridization) ◦ true-breeding parents: P generation ◦ hybrid offspring: F1 generation ◦ Offspring of F1 self-pollination: F2 generation ◦ Mendel discovered the basic principles of heredity by breeding garden peas: Pisum sativum ◦ Advantages of using peas: 1. has distinct character variations (traits) 2. Mating can be controlled 3. Each plant can reproduce by itself (self-fertilize) 4. Can cross-fertilize via pollen transfer 5 True-breeding white x purple flowered peas > F1 generation all purple ◦ Where did the white flower trait go? 6 1 10/05/2021 Mendel’s Experiment Mendel’s results in the modern context F1 x F1 hybrids --> F2 had purple, some had white Alternative versions of a gene is responsible for the variations in traits or inherited characters called ALLELES ◦ Purple: DOMINANT ◦ White: RECESSIVE Each gene is found in a specific location or locus in a chromosome Observed in other traits 7 8 What else did Mendel conclude? Punnett Squares ◦ For each trait, an organism inherits two alleles, one from each parent. devised by Reginald C. Punnett possible combinations of sperm and egg can be shown, predicting results of a genetic cross between individuals of known genetic makeup ◦ If alleles are similar: HOMOZYGOUS ◦ If alleles are different: HETEROZYGOUS ◦ If the alleles differ, the dominant allele determines the appearance, and the recessive allele has no effect on the appearance ◦ UPPERCASE LETTERS: dominant allele ◦ lowercase letters: recessive allele 9 10 Practice Problem 1: PTC tasting Practice Problem 1: PTC tasting The ability to taste a bitter chemical, phenylthiocarbamide (PTC), is due to a dominant gene. Use T and t to symbolize the two alleles of this gene. The ability to taste a bitter chemical, phenylthiocarbamide (PTC), is due to a dominant gene. Use T and t to symbolize the two alleles of this gene. Question 1. What is the genotype of a nontaster? What are the possible genotypes of a taster? 11 Question 2. If your mom is a heterozygous taster and your dad is a homozygous nontaster, what are the chances that you are a taster? Question 1. What is the genotype of a nontaster? What are the possible genotypes of a taster? Question 2. If your mom is a heterozygous taster and your dad is a homozygous nontaster, what are the chances that you are a taster? Genotype of non-taster: tt Genotype of tasters: TT, Tt 50% chance of you being a taster 12 2 10/05/2021 Practice Problem 2: Polydactyly Polydactyly is a dominant trait. A woman homozygous for polydactyly, is married to a normal man. What are the chances of producing an offspring that has extra fingers or toes? Use the letters P and p to represent alleles. Practice Problem 2: Polydactyly Polydactyly is a dominant trait. A woman homozygous for polydactyly, is married to a normal man. What are the chances of producing an offspring that has extra fingers or toes? Use the letters P and p to represent alleles. A: 100% chance 13 14 Practice Problem 3: Albinism Practice Problem 3: Albinism Albinism, the total lack of pigment, is due to a recessive gene. A man and a woman plan to marry and wish to know the chances of them having any albino children. What are the chances if the man is an albino, the girl is normal, but her father is an albino? Use the letters A and a to represent alleles. Albinism, the total lack of pigment, is due to a recessive gene. A man and a woman plan to marry and wish to know the chances of them having any albino children. What are the chances if the man is an albino, the girl is normal, but her father is an albino? Use the letters A and a to represent alleles. A: 50% chance of having albino children 15 16 Dihybrid Crosses: individuals with different alleles of two genes are crossed Dihybrid Crosses: individuals with different alleles of two genes are crossed • ◦ 4 x 4 Punnett square • ◦ Forked-line method • ◦ 4 x 4 Punnett square • ◦ Forked-line method Curly hair in poodles (G) is dominant over straight hair (g), and black fur color (B) is dominant over white fur (b). Curly hair in poodles (G) is dominant over straight hair (g), and black fur color (B) is dominant over white fur (b). Two heterozygous black, curly haired poodles were mated. What are the chances of the offspring to have white, straight hair? Two heterozygous black, curly haired poodles were mated. What are the chances of the offspring to have white, straight hair? A: 1 of 16 chances (6.25%) 17 18 3 10/05/2021 Gregor Mendel established the Principles of Inheritance Gene: sequence of DNA that codes for a trait Alleles: versions of one gene; usually two Homozygous: identical alleles of a gene Heterozygous: different alleles of a gene Genotype: set of alleles Phenotype: observable characteristics Dominant: masks its accompanying allele Recessive: is masked by its accompanying allele Trihybrid Crosses Forked-line method 19 20 Mendel’s Postulates • Unit factors are in pairs. • Genetic characters (traits) are controlled by unit factors existing in pairs (alleles) in individual organisms. Smooth RR Rough X Non-Mendelian Genetics rr the exceptions to Mendel’s Laws • Dominance and Recessiveness • When two unlike unit factors responsible for a single character are present in a single individual, one unit factor is dominant and can mask the other, which is said to be recessive. • Segregation Rough Smooth RR X rr • During the formation of gametes, the paired unit factors separate, or segregate, randomly so that each gamete receives one or the other with equal likelihood. 21 22 Incomplete Dominance Incomplete Dominance Occurs when the phenotype of heterozygous individuals are a blended version of both parents Occurs when the phenotype of heterozygous individuals are a blended version of both parents In plants known as “four o’clocks”, the alleles for the dominant red flower color (F) is incompletely dominant over the allele for white flowers (f). Heterozygous individuals exhibit pink coloration. In plants known as “four o’clocks”, the alleles for the dominant red flower color (F) is incompletely dominant over the allele for white flowers (f). Heterozygous individuals exhibit pink coloration. Identify the flower color genotypes and phenotypes if a red four o’clock is crossed with a pink four o’clock. Identify the flower color genotypes and phenotypes if a red four o’clock is crossed with a pink four o’clock. A: 50% red (FF), 50% pink (Ff) 23 24 4 10/05/2021 Co-dominance Co-dominance Occurs when the phenotype of heterozygous individuals are both the parents’; no allele is recessive Occurs when the phenotype of heterozygous individuals are both the parents’; no allele is recessive In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c); heterozygotes (CWCB) are spotted. In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c); heterozygotes (CWCB) are spotted. Identify the coat color genotypes and phenotypes between a heterozygous blackcoated rabbit and a homozygous white-coated rabbit. What are the chances that the offspring has a black coat? Identify the coat color genotypes and phenotypes between a heterozygous blackcoated rabbit and a homozygous white-coated rabbit. What are the chances that the offspring has a black coat? A: 0% chance (CB CB) 25 26 PRACTICE PROBLEM: Mendelian Genetics PRACTICE PROBLEMS: Incomplete Dominance Achondroplasia (dwarfism) is due to a dominant gene. A man with achondroplasia, but whose mother is of normal height, and a woman with achondroplasia, but whose father is also of normal height, decide to have children. In snapdragon flowers, having a red pigment (R) is incompletely dominant over the allele for a white pigment (r). Heterozygous individuals have pink colored flowers. If you have a red snapdragon and a white snapdragon, what are the chances that you’ll produce pink flowers if you cross the two varieties? What are the chances that they have children with achondroplasia? Use the letter D and d for the alleles. 27 28 PRACTICE PROBLEMS: Co-dominance Blood types display codominance. When a pure red cow (CR)is mated with a pure white bull (CW), all the offspring is a roan (CRCW), which has both red and white hair. Both alleles are dominant over c, which produces a brown color. ABO blood group Which type is the universal donor? What are the chances of getting a browncolored cow if you mated a roan with a heterozygous white bull? 29 Which type is the universal receiver? 30 5 10/05/2021 Codominance in blood types Codominance in blood types If a person with an AB blood type mates with another person with an AB blood type, what are the possible blood types of their offspring? If a person with an AB blood type mates with another person with an AB blood type, what are the possible blood types of their offspring? A: 50% AB, 25% AA, 25% BB 31 32 Practice Problem: Blood Types X Chromosome-linked Disorders A woman with an A blood type marries a man with a B blood type. Later on, she gives birth to an offspring with an O blood type. Alleles on the X chromosome are inherited and expressed differently in males and females • Males cannot transmit X-linked alleles to their sons (contributes Y chromosome) • Females pass X-linked alleles to male and female offspring However, upon looking at the child, he was convinced that it wasn’t his. Using their blood types, can you determine whether the child is his or not? 33 • Male offspring: will 100% express the trait • Female offspring: only homozygous females will express the trait; heterozygous are carriers 34 Practice Problem: Hemophilia Practice Problem: Hemophilia A woman who is heterozygous for recessive X-linked hemophilia mates with a non-hemophiliac, and bears a child. What is the probability that: A woman who is heterozygous for recessive X-linked hemophilia mates with a non-hemophiliac, and bears a child. What is the probability that: A. Their daughter has hemophilia? B. Their son has hemophilia? A. Their daughter has hemophilia? B. Their son has hemophilia? A: 0%, but 50% carrier, 50% normal B: 50% normal, 50% hemophiliac 35 36 6 10/05/2021 Practice Problem: Colorblindness Practice Problem: Colorblindness Red-green colorblindness is a recessive X-linked disorder. A colorblind woman mates with a normal man and bears a child. What is the probability that: A. Their daughter is colorblind? B. Their son is colorblind? Red-green colorblindness is a recessive X-linked disorder. A colorblind woman mates with a normal man and bears a child. What is the probability that: A. Their daughter is colorblind? B. Their son is colorblind? A: 0%, but all are carriers B: 100% colorblind 37 38 39 40 7