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The linear programming problem becomes,
Z=2X1+3X2+5X3+6X4+8X5+8X6
Subject to,
20X1+30X2+40X3+40X4+45X5+30X6>=70
50X1+30X2+20X3+25X4+50X5+20X6>=100
4X1+9X2+11X3+10X4+9X5+10X6>=20
with all variables non negative.
Now solve this problem, you will get that Feed F is no better than Feed
C, and Feed C is cheaper, the optimal mix will not use Feed F. Therefore
the problem can be simpli ed by using the value 0 for X6
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