QUANTITY SURVEYING
CE 2225
Prepared by: Engr. Kyra Kamille A. Toledo, CE Department
MODULE 5
STRUCTURAL WORKS
Formworks and Scaffoldings
CE 2225 – Quantity Surveying
ESTIMATING FORMWORKS & SCAFFOLDING = CONTACT AREA
Checklist for Concreting Works which is also for F&S
❑ General construction notes
❑ Foundation plan
❑ Structural framing plans
❑ Structural details
❑ Schedule (Footing, Wall Footing, Column, Beam, Slab)
❑ Stair, Retaining Wall, Shearwall, Underground tanks, etc.
❑ Architectural Elevations
CE 2225 – Quantity Surveying
CE 2225 – Quantity Surveying
Prepare a list of all the scopes of work
that involves concreting which also
involves formworks and scaffoldings
This is an example of a list of the
scopes of work.
Preferably, estimates should be
done from bottom to top or from
foundation to columns.
Other drawings (stair, retaining
walls, etc.) that need to be
concreted should be included.
CE 2225 – Quantity Surveying
Column Footing
Wall Footing
Column
Beam
2F Beams – Upper Floors
Roof Beams
Slabs
Slab on Fill / Slab on Grade
2F Slabs – Upper Floors
Roof Deck
Stair, Retaining Wall, Shearwall,
Underground tanks, etc
FORMWORKS (Phenolic Board)
SCAFFOLDING (Wood)
Contact Area = Perimeter * length/depth/thickness
Perimeter = (a+2b) + lapping length (50mm)
OR = 2(a+b) + lapping length
# of pcs = depends on plywood size; in this discussion, 4’ x 8’
was used
1 BD.FT = 1’ x 1’ x 1”
BRACING or FRAME of Forms (Wood)
Qty of SCAFFOLD = Height/Length/Contact
Area * Factor
Qty of BRACE/FRAME = Contact Area * Factor OR # of plywood * Factor
CE 2225 – Quantity Surveying
Column Footing, Column
A. FORMWORKS
Contact Area = Perimeter * height/thickness
Perimeter = 2(a+b) + lapping length (50mm)
= 2(a+b) + (4*0.05)
# of pcs = depends on plywood size; in this discussion,
4’x8’ was used
1 BD.FT = 1’ x 1’ x 1”
a
b
b
a
B. BRACINGS or FRAME: Assume as 2”x2” lumber
Amount of Bracing in BD.FT. = Contact Area * Table 5.2
C. SCAFFOLDING –
Column footing: no scaffolding
Column: Amount of Scaffolding in BD.FT. = Column height * Table 5.5
CE 2225 – Quantity Surveying
Example: F1 (FORMWORKS)
Perimeter = 2 (3.1+3.1) + (4*0.05) = 12.6 m
Total Contact Area = 12.6 *0.3 * 2 = 7.56 sq.m
# of pcs = 7.56/2.88 = 2.625 say 3 pcs of 4’x8’ board size
2
CE 2225 – Quantity Surveying
12.6
0.3
7.56
3pcs, 4’x8’
Example: F1 (BRACING)
Perimeter = 2 (3.1+3.1) + (4*0.05) = 12.6 m
Total Contact Area = 12.6 *0.3 * 2 = 7.56 sq.m
# of pcs = 7.56/2.88 = 2.625 say 3 pcs of 4’x8’ board size
BRACING/FRAMES = 7.56 * 12.71 = 96.09 BD.FT.
Assume 1pc 2”x2”x12’ = 4 BD.FT.
# of pcs = 96.09/4 = 24.02 say 25 pcs of 2”x2”x12’ lumber
OR
96.09 BD.FT of 2” x 2” x 1ft lumber
Example: F1 (SCAFFOLDING)
No scaffolding for footings
CE 2225 – Quantity Surveying
Column Estimates
Column Estimates
Perimeter = 2 (0.2+0.4) + (4*0.05) = 1.4 m
Contact Area = 1.4 * (1.5-0.3+0.8+3.2+3.15) * 8 = 93.52sq.m
# of pcs = 93.52/2.88 = 32.47 say 33pcs of 4’x8’ board size
8
CE 2225 – Quantity Surveying
1.4
8.35
93.52
33pcs, 4’x8’
Column Estimates
Perimeter = 2 (0.2+0.4) + (4*0.05) = 1.4 m
Contact Area = 1.4 * (1.5-0.3+0.8+3.2) * 5 = 36.4sq.m
# of pcs = 36.4/2.88 = 12.6 say 13pcs of 4’x8’ board size
8
5
CE 2225 – Quantity Surveying
1.4
1.4
8.35
5.2
93.52
36.4
33pcs, 4’x8’
13pcs, 4’x8’
Example: C1 (BRACING)
Contact Area: C1(pink) = 93.52 ; C1(blue) = 36.54
SCAFFOLDING (Wood)
BRACING/FRAMES(pink) = 93.52 * 12.71 = 1188.64 BD.FT.
BRACING/FRAMES(blue) = 36.54 * 12.71 = 464.42 BD.FT.
Assume 1pc 2”x2”x12’ = 4 BD.FT.
# of pcs (pink)= 1188.64/4 = 297.16 say 298 pcs of 2”x2”x12’ lumber
# of pcs (blue)= 464.42/4 = 116.105 say 117 pcs of 2”x2”x12’ lumber
OR
1188.64 BD.FT of 2” x 2” x 28ft lumber
464.42 BD.FT of 2” x 2” x 17ft lumber
Example: C1 (SCAFFOLDING)
Assumption: 2”x3” V; 2”x2” H & B
Vertical = (8.35*8) * 7.00 = 467.5 BD.FT
Horizontal = (8.35*8) * 21.00 = 1402.8 BD.FT
Brace = (8.35*8) * 11.67 = 779.56 BD.FT
CE 2225 – Quantity Surveying
Vertical = (5.2*8) * 7.00 = 291.2 BD.FT
Horizontal = (5.2*8) * 21.00 = 873.6 BD.FT
Brace = (5.2*8) * 11.67 = 485.472 BD.FT
Wall footing
A. FORMWORKS
Contact Area = Perimeter * length
Perimeter = (a+2b) + lapping length (50mm)
# of pcs = depends on plywood size; in this discussion, 4’x8’ was used
1 BD.FT = 1’ x 1’ x 1”
B. BRACINGS
Amount of Bracing in BD.FT. = Contact Area * Table 5.4
b
b
C. SCAFFOLDINGS – No scaffolding
a
CE 2225 – Quantity Surveying
CE 2225 – Quantity Surveying
Beams
A. FORMWORKS
Contact Area = Perimeter * length
Perimeter = (a+2b) + lapping length (50mm)
# of pcs = depends on plywood size; in this discussion, 4’x8’ was used
1 BD.FT = 1’ x 1’ x 1”
B. BRACINGS
Amount of Bracing in BD.FT. = # of plywood * Table 5.4
b
C. SCAFFOLDINGS – No scaffolding
Amount of Scaffolding in BD.FT. = Length of beam * Table 5.5
CE 2225 – Quantity Surveying
b
a
Beam Estimates
Perimeter = [0.2 + (2*0.4)] + (2*0.05) = 1.1 m
Contact Area = 1.1 * 3.625 * 2 = 7.975sq.m
# of pcs = 7.975/2.88 = 2.77 say 3pcs of 4’x8’ board size
2
CE 2225 – Quantity Surveying
1.1
3.625 7.98
3pcs, 4’x8’
Example: 2G-1 (BRACING)
# of plywood = 3 pcs
BRACING/FRAMES = 3 * 32 = 96 BD.FT.
Assume 1pc 2”x2”x12’ = 4 BD.FT.
# of pcs = 96/4 = 24 pcs of 2”x2”x12’ lumber
OR
96 BD.FT of 2” x 2” x 12ft lumber
Example: 2G-1 (SCAFFOLDING) Assumption: 2”x3” V; 2”x2” H & B
Vertical = (3.625*2) * 6.00 = 43.5 BD.FT
Horizontal = (3.625*2) * 4.67 = 33.86 BD.FT
CE 2225 – Quantity Surveying
SCAFFOLDING (Wood)
CE 2225 – Quantity Surveying
Slabs, Stairs
b
A. FORMWORKS
Contact Area = a * b
a
# of pcs = depends on plywood size; in this discussion, 4’x8’ was used
1 BD.FT = 1’ x 1’ x 1”
B. BRACINGS
Amount of Bracing in BD.FT. = # of plywood * Table 5.4
C. SCAFFOLDINGS – No scaffolding
Amount of Scaffolding in BD.FT. = Contact Area * Table 5.5
CE 2225 – Quantity Surveying
Slab Estimates
Clear spans = 3.7m & 2.7m
Contact Area = 3.7 * 2.7 * 2 = 19.98sq.m
# of pcs = 19.98/2.88 = 6.94 say 7pcs of 4’x8’ board size
2
CE 2225 – Quantity Surveying
19.98
7pcs, 4’x8’
Example: 2S-1 (BRACING)
Contact Area: 19.98 sq.m
# of plywood = 7 pcs
BRACING/FRAMES = 7 * 32 = 224 BD.FT.
Assume 1pc 2”x2”x12’ = 4 BD.FT.
# of pcs = 224/4 = 56 pcs of 2”x2”x12’ lumber
Example: 2S-1 (SCAFFOLDING) Assumption: 2”x2”
Flooring = 19.98 * 6.1 = 121.878 BD.FT
CE 2225 – Quantity Surveying
SCAFFOLDING (Wood)
CONCRETE STAIRS
*same methodology as beams
Treated as flat slab- thickness is the distance between the underside of the stair and a
parallel line that passes thru the centerline of the treads and risers.
CE 2225 – Quantity Surveying
CONCRETE STAIRS
*same methodology as beams
CE 2225 – Quantity Surveying
CONCRETE STAIRS
CE 2225 – Quantity Surveying
RETAINING WALLS
*same methodology with columns
Basement Floors
Elevator Pit
Escalator Pit
CE 2225 – Quantity Surveying
SHEARWALL
*same methodology with columns
CE 2225 – Quantity Surveying
UNDERGROUND TANKS
*same methodology with columns
Cistern
Sump Pit
Septic Tank
Manhole
Domestic Tank
Fire Reserve
CE 2225 – Quantity Surveying
CE 2225 – Quantity Surveying
End
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ofModule
Module
Thank
Thankyou!
you!
Reference: Vertical Construction Estimate by Cesar Balisado
CE 2225 – Quantity Surveying