Unit 3 RATIO AND PROPORTION LESSON OBJECTIVES ο Define ratio and proportion ο Perform the techniques in solving ratio and proportion ο Deepen the knowledge in ratio and proportion by solving different applications About Ratios Things around us can be paired or compared if they are of the same kind and can be expressed mathematically through what we called ratio. Ratio is defined as comparison of two quantities, usually expressed as a quotient. The ratio of “x to y” can be denoted by “x : y or x/y” since ratio is a quotient, then y ≠ 0. Ratios can be reduced to its simplified form. For instance, you want to compare the interest of your money in the bank as to the number of years “2000 : 5 or 2000/5” can be simplified as “400 : 1 or 400/1”. Example 1: Simplify the given ratios. 1. 12 cm : 2 m 2. 100 m : 2 km Solution: Since the given ratios contain different units, we can convert them to like units and simplify or reduce the ratio as possible. 1. 12 ππ 2π = 2. 100 π 2 ππ = 12 ππ 2ππ₯ 100 ππ 1π = 100 π 2 ππ π₯ 1000 π 1 ππ 12 ππ 200 ππ = = 100 π 2000 π 12 ÷4 200 ÷4 = = 3 50 100 ÷100 2000 ÷100 = 1 20 Applying the Ratios 1. The perimeter of a rectangle is 48 cm. Find the length of each side if the ratio of their sides is 1 : 3? Solution: Since the ratio is 1 : 3, then we can represent their lengths in x and 3x. x + x + 3x + 3x = 48 8x = 48 x = 6 cm., so the length of the other side is 3(6) = 18 cm. 1 Ratio and Proportion //vvfernandez Unit 3 RATIO AND PROPORTION Applying the Extended Ratios 2. The angles of a rectangle has a ratio of 1 : 2 : 3 : 4. Find each angle, if the sum of the angles of a rectangle is 3600. Solution. The ratio of their angles can be represented by x, 2x, 3x and 4x, thus xo + 2xo + 3xo + 4xo = 360o 10xo = 360o xo = 36 So, the angle measures are 36o, 2(36o) = 72o, 3(36o) = 108o, and 4(36o) = 144o PRACTICE AND APPLICATIONS A. Simplify the following ratios by making the units alike. 12 ππ. 20 ππ. a. 20 ππ‘. b. 300 π. B. Use the number line to find the ratio of distances. 1. 4. π΄πΆ πΈπ» π·πΉ π΅π· A B C D E F G H I 1 2 3 4 9 5 π΅π· 6 7 8 = _____ 2. πΆπ» = _____ = ______ 5. 3. π΄πΉ π΅πΌ = _____ π΄πΊ πΆπΌ C. Word Problems. 1. The area of a rectangle is 100 cm2. The ratio of the width to its length is 1 : 4. Find the length and the width. 2. The measure of the angles in a triangle are in the extended ratio of 1 : 4 : 7. Find the measures of the angles. 2 Ratio and Proportion //vvfernandez Unit 3 RATIO AND PROPORTION About the Proportion On the other hand, when two ratios are equal then it is called proportion. Properties of Ratio and Proportion 1. Reciprocal Property. If two ratios are equal, then their reciprocals are also equal. π π π π If = , then = π π π π 2. Cross Product Property. The product of the means is equal to the product of the extremes. If π π π = π , or a : b = c : d, then ππ = ππ ππ ππ = ππ where (b and c) are the means & (a and d) are the extremes. Here are the practical procedures in solving the ratio and proportion. Example If your car can go 350 miles on 20 gallons of gas, then at that rate how much gas would you have to purchase to take a cross country trip that was 3000 miles long? Step 1. Establish a ratio of the given units. Miles : Gas Step 2. Provide a detailed proportion of the given units and let x to be the unknown variable. Miles : Gas = Miles : Gas 350 : 20 = 3000 : x Step 3. Apply the cross product property to solve for x. 350 3000 = 20 π₯ 350x = 20(3000) 350x = 60,000 x = 171. 43 gallons of gas 3 Ratio and Proportion //vvfernandez Unit 3 RATIO AND PROPORTION Solving the Extended Proportion When three or more ratios are equal, thus it is called an extended proportion Solve for the value of y and z. 6 : y : z = 10 : 30 : 50 Solution: In fraction form, 6 10 = π¦ 30 = π§ 50 Solving for y Using the cross product 1. 6 : y = 10 : 30 ==> 10y = 6(30) 6 π¦ = 10 30 ==> 10y = 6(30) 10y = 180 y = 18 10y = 180 y = 18 Solving for z 2. 6 : z = 10 : 50 ==> 10z = 6(50) 10z = 300 z = 30 6 π§ = 10 50 ==> 10z = 6(50) 10z = 300 z = 30 Thus, the resulting ratio is 6 : 18 : 30 which is equivalent to 10 : 30 : 50. Checking the proportion and reducing the ratios to its lowest terms. 6 10 = 18 30 = 30 50 ==> 3 5 = 3 5 = 3 5 When solving the extended proportion, express the ratios in fractional form and select which one contains only one unknown/variable and solve using cross product property. Summary of Terms a. Ratio – is a comparison of the two quantities, denoted by “ a : b” or “a/b”, where b ≠ 0. b. Proportion - is the equality of two ratios, such that “ a : b = c : d” or “a/b = c/d”. c. Extended Proportion - is the equality of three or more proportions, such that π π π “a : b : c = x : y : z” or π₯ = π¦ = π§ . 4 Ratio and Proportion //vvfernandez