# (Sept. 16)

```A.)
1.
Can
10,05011
=
solution :( given that ✗ is
can
CCX )
CLX )
__
( flat
=
=
a
non
negative
-
printing
cost +
less than
integer
)
or
equal
5007
To
✗
cost
(10,000+50) ✗
(10,050711
CCX )= 10,050 ✗
b.)
Yes
this relation is
,
of Eun
value
Also
.
through
passes
function
a
,
graph of
the
Vertical
the
is
It
.
because
relation
this
line test
value of
each
tells
associated
is
✗
that
it
is
a
with exactly one
function because it
.
mm
2001000
..•
a.
( 1&times;1=10,050
✗
&times;
100,000
Clot 10,050107=0
0
I
CCI )=
2
(121--10,05012)=20,100
•
•
go , ooo
10,050117=10,050
80,000
•
70,000
3
cl37=
4
cnn.io#n=iio.noo
10,050137=30,150
• oooo
501000
5
V5)
6
Che )=
10,050167=60,300
40,000
7
CG )=
10,050171=701350
30,000
8
CCD -10,050187=80,400
-40,050157=50,250
•
-
9
10
20,000
&quot;
V9 ) -10,050197=901450
•
10,000
CHOI -40,050197=100,500
MM
•
0
I
2
3
4
5
6
7
8
9
to
11B\$
MM
c.)
:{
D
✗
I
✗ ER
,
01&times;5500 }
or
D :[ 0
,
explanation
d)
R
:X should
:{ ugly
the
HI
A.
be a
non
500 bhunld
that the company
explanation
2. Evaluate
500 ]
:
is
if
a
non
-
negative
it is not possible to produce negative
integer because
be the maximum value of the domain because
it
is small
and can only
print 500 books per month
-
amount
is
of
books
stated in
7-9
10,050 that is less -1hm 502.5005
UH
10,050 X , then the domain should be
less than
is 502,500
f- ( 500 ) which
negative multiple
of
=
a
positive multiple
2
,
b. Iim 1&times;2+2&times;-17=(512-1215)-1
25+10-1=35-1--34
✗→ 5
(23-19)=1713-19--343+9
C.
Liff
a.
live.FI#--T-+t;---=fE+----fy---r-yr=Z-or1E
e.
=
352
.IE#=4fiEYI---:YE?F-,--.:EI-.-- I;&divide;,= :-(
&yen;1
solution
:
indeterminate
&yen; My.IE?z---l2k?x-f2#h--2x-?---2l-Ef-B&gt;
Iim
✗→ -312
f.
&quot;&yen;&yen;=
=
)
-6
-6
limf.EE#xis---YIF+-zEI.?-c.n+s----------+-s-- -4+1-1-+5=3--4--8-1 indeterminate )
✗
problem
.
and
01&times;4-500
that is
7-3137
Also ,
the
following limits
(7-311)
.
→ -1
solution !
&yen;&yen;,&yen;I&yen;&divide;i+s=&yen;&yen;Y&yen;+&Eacute;
,
-_
2&times;-1=21-11-1
✗ 2-1&times;+5
(-154-14)-15
&yen;&yen;&yen;+&yen;&divide;*= -1
=
-4-+1--5+57=-1
of
10,050
```