# toaz.info-10-1112-01-ms-tcm143-430011-pr 88c76b7af002d43868dbd29836b5a9e0

```Cambridge International Examinations
Cambridge Secondary 1 Checkpoint
1112/01
MATHEMATICS
Paper 1
October 2017
MARK SCHEME
Maximum Mark: 50
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the
examination. It shows the basis on which Markers were instructed to award marks. It does not indicate the
details of the discussions that took place at a Markers’ meeting before marking began, which would have
considered the acceptability of alternative answers.
Mark schemes should be read in conjunction with the question paper and the End of Series report.
Cambridge will not enter into discussions about these mark schemes.
This document consists of 11 printed pages and 1 blank page.
IB17 10_1112_01/2RP
&copy; UCLES 2017
[Turn over
M1
A1
B1
FT
dep
oe
cao
isw
soi
method mark
accuracy mark
independent mark
dependent
or equivalent
ignore subsequent working
seen or implied
Mark scheme annotations and abbreviations
1112/01
Page 2 of 12
Checkpoint Secondary 1 – Mark Scheme
Published
October 2017
Question
Question
Question
4
3
2
1
0.75
1.1
1.2
2.1
56
6 + e2
2e + 6
2 + 6&times;e
8e

Page 3 of 12
An attempt to subtract 7 from both sides (e.g. 3r = 34  7)
7 34
or correct first step, e.g.: r  
3 3
(r =) 9
0.7
Question
Further Information
Further Information
1
Marks
Further Information
1 Allow any unambiguous indication of the correct
Marks
2
Marks
M1
Further Information
October 2017
1 All correct for 1 mark.
Allow any unambiguous indication of the correct
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
Question
Question
7
6(b)
6(a)
5
&divide; 1000
&times; 1000
&divide; 10


litres
grams
centimetres
Time spent doing homework
Favourite subject
Age of student
Name of student
0.856 (km)
millilitres
kilograms
millimetres
(C =) np
Page 4 of 12
Question
Further Information
Further Information
Further Information
October 2017
1 Award 1 mark for both boxes ticked and no
Marks
1
1 Both correct for 1 mark.
Marks
pn
np
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
11
oe
12
12
63
and
12
28
3
Page 5 of 12
Marks
1
140
and 2
2
10(b)
12
M1
M1
2
Marks
1
or 5
4
12
4
15
or 4
and 2
12
12
oe
e.g.:
Correctly finding a common denominator.
2
Correctly converting to a common denominator.
10
2 35
 7 
and
oe
e.g.:   and
,
50
10 50
 10 
9
oe
10
1
19.18
9(b)
9(a)
6
10(a)
Question
Question
8
Question
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
Accept
12
35
or 1
for 2 marks.
Further Information
12
23
Further Information
Further Information
October 2017
Question
Question
13
12
11
2
5
7
20
2
9
5
6
1
Any two correct.
4
–5
8
Four fractions correctly placed.
30
3
 
4
 1
 
3
13 cm
Terminating
decimals
12 cm
Recurring
decimals
5 cm
Page 6 of 12
30 cm
Question
2
Marks
B1
Further Information
Further Information
2 Award 2 marks if all fractions are in the correct
column.
Marks
B1
Further Information
October 2017
1 Accept any unambiguous indication of the correct
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
15
16(b)
16(a)
Question
Question
14
64
73
100
31
50
Page 7 of 12
 Jamila has more results.
 Jamila opened twice as many packets of biscuits.
Ticks Jamila and gives a correct reason relating to the
number of times they carried out the experiment, e.g.:
One column correct.
Jamila’s
estimate
Lily’s
estimate
2
Further Information
Only award either B1 or M1
Further Information
Accept any unambiguous indication of the correct
1 Do not allow just ‘Jamila has 100.’ oe
Note that the reason must make a comparison
between Lily and Jamila’s estimates.
73% 0.73
2 Accept equivalent fractions, percentages or
decimals, e.g.:
62
62% 0.62
100
Marks
B1
Further Information
October 2017
1 Both answers must be ringed and no others for the
award of the mark.
Marks
M1
36
Correct intersection shown on grid.
9
B1
8
One correct coordinate.
(3, 5)
6
Question
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
Question
Question
22
21
20
0
7
7
Page 8 of 12
1
Marks
1
Marks
1 Ignore units.
Marks
Further Information
Further Information
Further Information
1 Accept 1995 – 1997 inclusive.
1996
19(b)
Question
1
Further Information
A correct comment relating to the line for 65 years and
above, for example:
 The line for 65 years and above slopes up.
 There has been an increase in the percentage of
people aged 65 and above.
Marks
Further Information
Further Information
19(a)
1
23
18(b)
Question
1
Marks
M1
2
20
5 &times; 22 = 20 (seen or implied) by 20 – 10.
36
18(a)
Question
17
Question
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
October 2017
2
+ 35%) correctly evaluated by converting
2
Page 9 of 12
Further Information
1 Allow follow through from part (a), i.e. 12 &times; their 19
Marks
For example:
 0.4 and 0.35
 40% (and 35%)
8
7

and
or equivalent fractions with equal
20
20
denominators.
M1
228 (g)
and 35% to the same form.
implied by sight of:
1

of students got grade C, oe
4
 40 students in total
M2
Further Information
25(b)
5
2
and
3
Marks
1 Do not accept 20 m = 380 v
Correct conversion of
5
5
35% to the same form to get 0.25, or equivalent
1
(e.g. 25%, ).
4
1–(
16
B1
2 Accept 62 or 6  6 or 36  6 for indicating a
square number, or ‘36 is a square number’.
(m =) 19 (v)
24
Finding 15 or 21 or 36
The 5th and 6th terms are 15 and 21
15 + 21 (= 36) = 62
Further Information
October 2017
25(a)
Question
Question
23
Question
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
Question
27
26
M1
1 correct boundary
or
2 incorrect boundaries with the correct form and correct
follow through indication of the region.
Page 10 of 12
1
Do not accept
Further Information
2
3x
Further Information
October 2017
Notes on correct form:
 sight of an arc centre on the tree,
 a vertical line inside the garden stretching at
least as far as their arc.
3 Allow lack of label, R, if intended region is clear.
Marks
M2
Patio
Both correct boundaries
or
1 correct boundary, 1 incorrect boundary with follow
through correct region, provided the incorrect boundary is
of the correct form i.e., arc or line.
R
Tree
Correct region, R:
3
2x
Question
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
28
M1
An attempt at eliminating either m or n
e.g.
 attempt to re-arrange one of the equations to make one
variable the subject and then substitute their
arrangement into the other equation,
 attempt at making the coefficients of m or n equal with
no more than 1 error, arithmetic or sign, followed by an
appropriate, consistent subtraction or addition across all
3 terms.
 correct substitution and evaluation from incorrect first
value i.e. two values satisfying one of the original
equations.
Page 11 of 12
M2
An algebraic method leading to either
m = 7 or n = –2
(m =) 7
(n =) –2
Question
Further Information
October 2017
3 Do not accept trial and improvement as a method.
Marks
Checkpoint Secondary 1 – Mark Scheme
Published
1112/01
1112/01
Page 12 of 12
BLANK PAGE
Checkpoint Secondary 1 – Mark Scheme
Published
October 2017
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