IDEAL TRANSFORMERS
An ideal transformer is a unity-coupled, lossless transformer in which the primary and
secondary coils have infinite self-inductances.
➢ It consists of two (or more) coils with a large number of turns wound on a common core
of high permeability.
V1 = jωL1I1 + jωM I2
→
I1 = (V1 – jωM I2)/jωL1
V2 = jωM I1 + jωL2I2
Subst. I1
𝑉2 = 𝑗𝜔𝐿2 𝐼2 +
𝑀𝑉1 𝑗𝜔𝑀2 𝐼2
−
𝐿1
𝐿1
for perfect coupling (k = 1), 𝑀 = √𝐿1 𝐿2
2
𝐿2
√𝐿1 𝐿2 𝑉1 𝑗𝜔(√𝐿1 𝐿2 ) 𝐼2
𝑉2 = 𝑗𝜔𝐿2 𝐼2 +
−
= √ 𝑉1 = 𝑛𝑉1
𝐿1
𝐿1
𝐿1
𝐿
Where: 𝑛 (𝑡𝑢𝑟𝑛𝑠 𝑟𝑎𝑡𝑖𝑜) = √𝐿2
1
Properties of Ideal Transformer:
1. Coils have very large reactances (L 1, L2, M →∞).
2. Coupling coefficient is equal to unity (k = 1).
3. Primary and secondary coils are lossless (R1 = 0 = R2).
Consider:
When a sinusoidal voltage is applied to the primary winding, the same magnetic flux φ goes through both
windings.
According to Faraday’s law:
𝑑∅
𝑑∅
𝑣1 = 𝑁1 𝑑𝑡
Take
𝑑∅
𝑑𝑡
Then,
𝑣2
𝑣1
=
=
𝑣2 = 𝑁2 𝑑𝑡
𝑑∅
𝑑𝑡
𝑁2
𝑁1
=𝑛
where n is the turns ratio or transformation ratio.
In phasor:
𝑉2
𝑉1
=
𝑁2
𝑁1
=𝑛
Since there are no losses in an ideal transformer,
v1i1 = v2i2
𝑣2
𝑣1
=
𝑖1
𝑖2
𝑉2 𝐼1
= =𝑛
𝑉1 𝐼2
Note:
1. n = 1, the transformer is an isolation transformer.
2. n > 1, the transformer is a step-up transformer, the voltage is increased from primary to
secondary (V2 > V1).
3. n < 1, the transformer is a step-down transformer, the voltage is decreased from primary
to secondary (V2 < V1).
➢ A step-down transformer is one whose secondary voltage is less than its primary
voltage.
➢ A step-up transformer is one whose secondary voltage is greater than its primary voltage
Sign of n:
1. If V1 and V2 are both positive or both negative at the dotted terminals, use +n. Otherwise,
use −n.
2. If I1 and I2 both enter into or both leave the dotted terminals, use −n. Otherwise, use +n.
Expressing V1 in terms of V2 and I1 in terms of I2, or vice versa:
The complex power in the primary winding is
The ideal transformer is lossless that is why it absorbs no power. Then, input impedance
𝑉
1 𝑉
𝑍
𝑉
(reflected impedance) as seen by the source is 𝑍𝑖𝑛 = 1 = 2 2 = 𝐿2 , where 2 = 𝑍𝐿 .
𝐼1
𝑛 𝐼2
𝑛
𝐼2
This appears as if the load impedance is reflected to the primary side. The ability of the
transformer to transform a given impedance into another impedance provides us a means of
impedance matching to ensure maximum power transfer.
Eliminating the transformer by reflecting impedances and sources from one side of the
transformer to the other.
Consider reflecting the secondary side of the circuit to the primary side.
Obtain VTh at terminals a-b, terminals a-b are open, I1 = 0 = I2 so V2 = Vs2.
𝑉1 =
VTh = V1
𝑉2
𝑛
𝑉𝑇ℎ =
𝑉2
𝑛
=
𝑉𝑆2
𝑛
To determine ZTH
\
𝑍𝑇ℎ =
𝑍𝑇ℎ
𝑉1
𝐼1
but I1 = nI2 and V1 = V2/n
𝑉2
𝑉2
𝑍2
= 𝑛 = 2 = 2
𝑛𝐼2 𝑛 𝐼2 𝑛
“The general rule for eliminating the transformer and reflecting the secondary circuit to the
primary side is divide the secondary impedance by n 2, divide the secondary voltage by n, and
multiply the secondary current by n.”
“The rule for eliminating the transformer and reflecting the primary circuit to the secondary side
is: multiply the primary impedance by n 2, multiply the primary voltage by n, and divide the
primary current by n.”
Also note that if the locations of the dots are changed, we might have to replace n by −n to obey
the dot rule.
Sample Problems:
1. A 480/2,400-V rms step-up ideal transformer delivers 50 kW to a resistive load.
Calculate: (a) the turns ratio (b) the primary current (c) the secondary current
2. For the ideal transformer circuit shown, find: (a) the source current I 1, (b) the output
voltage Vo, and (c) the complex power supplied by the source
3. Determine I1 and I2 in the circuit.
4. Calculate the power supplied to the 10-ohm resistor in the ideal transformer circuit.
5. In the ideal transformer circuit shown, find Vo.
6. Determine all indicated voltages and currents.
7. Determine I1, I2, V1, and V2