Spring - 2022 Lecture - 3 Chapter 2: First-Order Circuits Prepared By Dr. Salma Subh salma_s_mohammed@cic-cairo.com Outlines 1. 2. 3. 4. The Source-Free RC Circuit The Source-Free RL Circuit Step Response of an RC Circuit Step Response of an RL Circuit 2 Introduction • Three passive elements (resistors, capacitors, and inductors) and one active element (the op-amp) • In this chapter, we shall examine two types of simple circuits: a circuit comprising a resistor and capacitor and a circuit comprising a resistor and an inductor. These are called RC and RL circuits, respectively. • The only difference is that applying Kirchhoff’s laws to purely resistive circuits results in algebraic equations while applying the laws to RC and RL circuits produces differential equations, which are more difficult to solve than algebraic equations. • The differential equations resulting from analyzing RC and RL circuits are of the first order. Hence, the circuits are collectively known as first-order circuits. 3 There are two ways to excite the circuits: • Source-free circuits, we assume that energy is initially stored in the capacitive or inductive element. • By independent DC sources. • The two types of first-order circuits and the two ways of exciting them add up to the four possible situations we will study in this chapter. 4 The Source-free RC Circuits Find the voltage across the capacitor v(t) , circuits response π£ π = π£π 1 2 πΆπ£ 2 π ππ + ππ = 0 π€ π = ππ£ π£ πΆ + =0 ππ‘ π ππ£ π£ + =0 ππ‘ πΆπ ππ£ ππ‘ =− π£ πΆπ 5 The Source-free RC Circuits 1 1 ΰΆ± ππ£ = − ΰΆ± ππ‘ π£ π πΆ π‘ + ln π΄ πΆπ π‘ ln π£ − ln π΄ = − πΆπ π£ π‘ ππ = − π΄ πΆπ ln π£ = − π£(π‘) = π΄π − π‘ πΆπ From the initial conditions v(0) = A = π£π , Hence π£(π‘) = π£π π π‘ − πΆπ 6 RC Circuits Response .. π£(π‘) = π£π π − π‘ πΆπ Rth 7 To Solve RC Circuits.. 8 Multisim.. 9 Example 1 (page 281): Let Vc(0) = 15 V, Find Vc, Vx and Ix for t > 0 10 Example 1 (page 281): The switch in the circuit in Fig. has been closed for a long time, and it is opened at t > 0, Find v(t) for t >=0 Calculate the initial energy stored in the capacitor. 11 Example 2 (page 282): The switch in the circuit in Fig. has been closed for a long time, and it is opened at t=0 Find v(t) for t >0 . Calculate the initial energy stored in the capacitor. 12 The Source-free RL Circuits π π = ππ 1 2 πΏπ 2 π ππ + ππ = 0 π€ π = ππ + π π = 0 ππ‘ ππ π + π=0 ππ‘ πΏ ππ π ππ‘ =− π πΏ πΏ 13 The Source-free RL Circuits ΰΆ± ππ π ππ‘ =− ΰΆ± π πΏ ln i = − Rt L + ln A ln π − ln π΄ = − ππ π π‘ πΏ π π π‘ =− π΄ πΏ π(π‘) = π΄π − π π‘ πΏ From the initial conditions i(0) = A = ππ , Hence π(π‘) = ππ π − π π‘ πΏ 14 RL Circuits Response .. π(π‘) = ππ π − π π‘ πΏ 15 To Solve RL Circuits with no external source .. 16 Example 3: Assuming that i(o) = 10 A, calculate i(t) and ix(t) in the circuit of Fig. 17 Example 4: The switch in the circuit of Fig. 7.16 has been open for a long time. At t= 0 the switch is closed . Calculate i(t) fort > 0 18 Step Response of an RC Circuit π 0 = ππ ππ£ π − ππ π’(π‘) πΆ + =0 ππ‘ π ππ£ π ππ π’(π‘) πΆ + = ππ‘ π π ππ£ π ππ + = πππ π‘ > 0 ππ‘ πΆπ πΆπ ππ£ π − ππ =− ππ‘ πΆπ 19 ππ£ ππ‘ =− π − ππ πΆπ π£(π‘) π‘ ππ£ ππ‘ ΰΆ± = ΰΆ±− π − ππ πΆπ π0 0 ln π − ππ = − π πΆπ ln π(π‘) − ππ − ln ππ − ππ = − ln π‘ πΆπ π π‘ − ππ π‘ =− ππ − ππ πΆπ π‘ π π‘ − ππ − πΆπ =π ππ − ππ π€βπππ π πΆ = π π π‘ − ππ = (ππ − π‘ − π ππ ) π π‘ π π‘ = ππ + (ππ − ππ ) π −π 20 To solve RC circuits with source 21 Example 5 (page 277): The switch in Fig. has been in position A for a long time. At t = 0 the switch moves to B. Determine v(t) for t > 0 and calculate its value at t =1 and t = 4 s. 22 Example 6: Find v(t) for t> 0 in the circuit of fig. Assume the switch has been open for long time and is closed at t= 0 calculate v(t) value at t =0.5. 23 Step Response of an RL Circuit Prove !! 24 Example 7: Find i(t) for t> 0 in the circuit of fig. Assume the switch has been close for long time and is opened at t= 0 calculate i(t). Check your answer ! βΊ 25 Example 9: First-Order Op Amp Circuits For the op-amp circuit in fig. find vo for t > 0 given that v(o) = 3 V let Rf = 80 K ohm, R1 = 20 K ohm and C= 5 u F 26