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hydrostatics formula sheet

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ENG1005
Hydrostatics Formula Sheet
Dr Ben Wetenhall
School of Engineering
Viscosity, μ
y
u
• Viscosity/shear stress
ο‚Άu
 =
ο‚Άy
where πœ‡ is dynamic viscosity, 𝜏 is shear
stress and
πœ•π‘’
πœ•π‘¦
is velocity gradient
• Kinematic viscosity 𝜈, 𝜈 =
Solid Boundary
πœ‡
𝜌
Pressure
• In a confined system the pressure in liquids is always the same across a horizontal.
𝐹 𝑓
𝑝= =
𝐴 π‘Ž
𝑝 = πœŒπ‘”β„Ž above atmospheric pressure
𝑓
𝐹
h
area π‘Ž
area 𝐴
r
Hydraulic Thrust and Centre of Pressure
• The Hydraulic Thrust F acts through the Centre of Pressure (COP)
𝐹 = πœŒπ‘”π΄β„Žΰ΄€
Fluid
where A is the area of the object and β„Žΰ΄€ is the depth to the
centre of gravity G
Plane surface
Centre of pressure:
Pressure
distribution
G
COP
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Find COP from either:
1. The centre of gravity of the pressure diagram
or…
4
Centre of Pressure
2. From the formulas for the location of the
COP along the slope (π‘₯0 ) and the depth to the
COP (β„Ž0 )
𝐹π‘₯0 = πœŒπ‘” sin πœƒπΌ0
β„Ž0 = β„Ž +
0
β„Ž0
πœƒ
β„Ž
𝐼𝑔 sin2 πœƒ
π΄β„Ž
A
COP
G
π‘₯0
π‘₯
0
where 𝐼0 , 𝐼𝑔 are the second moment of areas of the orange
area about 0-0 and the centre of gravity (G) respectively and β„Žΰ΄€
is the depth to G
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5
Second moments of area of common shapes
Parallel Axis Theorem
𝑏𝑑3
𝐼𝑔 =
12
d
O
O
b
𝐼𝑔 =
h
x
b
d
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x
𝐼π‘₯π‘₯
π‘₯
π‘β„Ž3
36
π‘β„Ž3
=
12
πœ‹π‘‘4
𝐼𝑔 =
64
G
πΌπ‘œ = 𝐼𝑔 + π‘₯ 2 𝐴
6
Horizontal Thrust on Curved Surfaces
𝐹π‘₯ = πœŒπ‘”β„Žπ΄π‘‰
𝐹𝑦 = π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ 𝑓𝑙𝑒𝑖𝑑 π‘‘π‘–π‘ π‘π‘™π‘Žπ‘π‘’π‘‘ 𝑏𝑦 π‘‘β„Žπ‘’ π‘ π‘’π‘Ÿπ‘“π‘Žπ‘π‘’
= π‘£π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘¦π‘’π‘™π‘™π‘œπ‘€ π‘ π‘’π‘Ÿπ‘“π‘Žπ‘π‘’ × πœŒ × π‘”
where 𝐴𝑉 is the vertically projected area of the
curved surface and β„Ž is the depth to G of the
vertically projected area
𝐡
𝐴𝑉
β„Ž
𝑃
𝐹π‘₯
Centre of pressure:
• Fx acts through the centre of gravity of the
pressure prism
• Fy acts through the centre of gravity of the fluid
displaced by the surface (G of the yellow surface)
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𝐴
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