Page |1 MATHEMATICAL LITERACY GRADE 10 SCHOOL BASED ASSESSMENT ASSIGNMENT 1 TOPIC: BASIC SKILLS MARKS: 50 SUGGESTED TIME: 60 MINUTES EXAMINER: Ms N. Phillips MODERATOR: Mr W. Block INSTRUCTIONS: 1. This question paper consists of THREE questions. Answer ALL the questions. 2. Number the answers correctly according to the number system used in this question paper. 3. Start each question on a NEW page. 4. You may use an approved calculator (non-programmable and non-graphical), unless stated otherwise. 5. Show ALL calculations clearly. 6. Round off all final answers appropriately. 7. Indicate units of measurement where indicated. 8. Write neatly and legibly. Page |2 QUESTION: 1 1.1 There was one helicopter flying above the Black Sea. Its height was 1500 m. It crashed into the sea and a body was found at 600 m deep. Calculate the vertical distance between the height at which the helicopter was flying and the depth at which the body was found? (2) 1.2 Jason is solving a mathematical puzzle. He chooses the colour codes for each question according to difficulty. The details for the colour codes are as follows: White: 5 points Yellow: 6 points Orange: 8 pints Red: 9 points Black: 10 points Jason has answered: 4 white, 3 yellow, 4 orange and 5 black level questions. What is his final score? (4) 1.3 Alice recorded the amount of liquid she has consumed for today. These are the details: Breakfast : 128 ml tea After breakfast : 225 ml coffee Lunch : 194 ml water Evening : 212 ml water 188 tea Estimate the total amount of liquid that was consumed by Alice. (2) 1.4 The grade 12 class at a school consists of 63 learners in the ratio of 4 boys to 5 girls. 1.4.1 Determine the number of girls in the class. (3) [Total: 11] Page |3 QUESTION: 2 Look at the following receipts collected by the Zilwa family then answer the questions that follow. 2.1 Write the total car insurance to the total petrol as a ratio. (2) 2.2 Divide the total amount spent on fruit and vegetables in the ratio 2:3 (5) 2.3 The Zilwa family’s rent increases by 7.5%. Calculate the new rent after the increase. (3) 2.4 Round off “Pic & Pac” to the nearest 100. (2) 2.5 Decrease the “General motor vehicle cover” with 15%. (3) 2.6 Express the following ratio in its simplest form: (3) 26 : 65 : 117 [Total: 18] Page |4 QUESTION: 3 In nature there are cold-blooded animals, such as reptiles. The body temperature of these animals depend on the temperature of the environment. However, when the environment reaches a certain minimum temperature, and the animals are without cover, they can die. The graph below illustrates the relationship between body temperature and environmental temperature of cold-blooded animals. Environmetal Temperature vs Body Temperature of Cold-Blooded Animals 45 Body Temperature (oC 40 35 30 25 20 15 10 5 0 0 10 20 30 40 Environmental Temperature (oC) 3.1 Identify both the Dependent and Independent variables and state whether the graph is increasing or decreasing. (3) 3.3 Name and describe the relationship between the two variables. (2) 3.4 Use the introduction of this question as well as the graph to explain: 3.5 3.4.1 the trend of the graph (2) 3.4.2 why a dotted line is used to indicate the lower temperatures. (2) The table below also illustrates the relationship between the two variables: Environmental Temperature (oC) Body Temperature (oC) 10,8 A B 29,7 35,1 C 40,2 40,2 Determine the value of: 3.6 3.5.1 A 3.5.2 B 3.5.3 C. In the midst of the Covid-19 pandemic, measuring your body temperature, is part of safety protocol. (2) (2) (2) 3.6.1 Explain the importance of measuring your body temperature. (2) Page |5 3.6.2 You are also made aware of normal body temperature. Write down this temperature. (2) 3.6.3 When compared to reptiles, does our body temperature also change as the environmental temperature changes? Explain your answer. (2) [Total: 21] Total mark: 50 Page |6 MATHEMATICAL LITERACY GRADE 10 SCHOOL BASED ASSESSMENT ASSIGNMENT 1 MEMORANDUM TOPIC: BASIC SKILLS MARKS: 50 SUGGESTED TIME: 60 MINUTES EXAMINER: Ms N. Phillips MODERATOR: Mr W. Block Page |7 Q 1.1 1.2 Solution 1500 + 600 = 2100 m Explanation 1 Method 1 Answer (2) W (5 x 4) +Y (6 x 3)+O (8 x 4) + B (10 x 5) 20 + 18 + 32 + 50 = 120 2 Method 2 Answer 128≈130; 225≈230; 194 ≈190 ; 212≈ 210; 188 ≈190 130 + 230 + 190 + 210 + 190 = 950 ml 1 Method 1 Answer (4) 1.3 (2) 1.4 4:5 = 9 5 ∴ Girls = 9 × 63 = 35 1Method 1Method 1Answer (3) 2.1 500 : 231 1 Method: Correct order 1RT : Correct values (2) 2.2 2+3=5 2 R126 x 5 = 𝑅50,40 3 R126 x 5 = 𝑅75,60 2.3 Increase = R 3500 x 7,5% = R 262,50 New Rent = R 3500 + R 262,50 = R 3762,50 2.4 R 1000 2.5 R 500 x 85% = R 425 2.6 ( 26 ∶ 65 ∶ 117 ) ÷ 13 =2 : 5 : 9 3.1 3.1.1 3.3 Body temperature Environmental temperature Increasing Direct relation As the environmental temperature increase, the body temperature also increases. 1 Method: Adding correct values 2 1 for multiplying by 5 1 CA Answer 2 1 for multiplying by 5 1 CA Answer (5) 1 CA Answer 1 Method: Adding 7,5% to R 3500 1 CA Answer (3) 2 Correct rounding (2) 1 Method: calculating 1 Method: Multiplying by 85% 1 CA Answer (3) 1 Method: HCF 2 Answer (3) 1 Answer: Dependent variable 1 Answer: Independent variable 1 Answer (3) 1A relation 1A description (2) 3.4 3.4.1 An increase in the environmental temperature, results in an increase in the body temperature of cold-blooded animals. 2 Answer: trend (2) Page |8 3.4.2 At the lower temperatures, these animals might end up dying. 2 Answer: conclusion (2) 3.5 3.5.1 10,8oC 1 Answer: temperature 3.5.2 29,7 oC 1 Answer: temperature 3.5.3 35,1 oC 1 Answer: temperature (2) (2) (2) 3.6 3.6.1 The measurement is to verify whether our body temperature is not too high – indicating fever, which is one of the symptoms of the virus. 2 Answer: explanation (2) 3.6.2 35oC – 38oC 2 Answer: temperature (2) 3.6.3 No Our body temperature remains the same, no matter what the environmental temperature is. TOTAL: 50 1 Answer: No 1 Answer: reason (2)