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TEXT TE XTBO BOOK OK SO SOLU LUTI TION ONS S EXPE EX PERT RT Q&A NEW! PRAC PR ACTI TICE CE Search home / study / science / chemistry / chemical engineering / chemical engineering solutions manuals / introduction to chemical engineering thermodynamics / 7th edition / chapter 10 Introduction to Chemical Engineering Thermodynamics Thermodynamics (7th Edition) Post a question Answers from our experts for your tough homework questions Problem Enter question Assuming the validity of Raoult’s law, do the following calculations for the benzene(1)/to benzene(1)/toluene(2) luene(2) system: Continue to post (a) Given x1 = 0.33 and T = 100°C, ﬁnd y1 and P. 20 questions remaining (b) Given y1, = 0.33 and T = 100°C, ﬁnd x1, and P. My Textbook Solutions (c) Given x1, = 0.33 and P = 120 kPa, ﬁnd y1, and T. Manufacturi ng Processes (d) Given y1, = 0.33 and P = 120 kPa, ﬁnd x1, and T. Introduction Manufacturin Foundatio to Chemical... g Processes of Finance (e) Given T = 105°C and P = 120 kPa, ﬁnd x1 and y1. 7th Edition 3rd Edition 8th Edition View all solutions (f) For part ( e), if the overall mole fraction of benzene is z1 = 0.33, what molar fraction of the twophase system is vapor? Chegg tutors who can hel right now (g) Why is Raoult’s law likely to be an excellent VLE model for this system at the stated (or computed) conditions? Sanjay Indian Institute of ... Ritu Step-by-step solution C.H.S. P. Sc. & N. In... Ryan Step 1 of 12 University of South... The given binary mixture system is benzene (1)/ toluene (2) system. Write the mathematical expression of Raoult’s law as follows: …… (1) Here, is the total pressure, fraction, is the vapor phase mole fraction, is the liquid phase mole is the vapor pressure of pure species. Write the expression for total pressure by using Raoult’s law. At , Then, For binary species, …… (2) Write Wri te the exp expre ressi ssion on for the sat satur urati ation on pre pressu ssure re using usi ng Ant Antoin oine e equa equatio tion. n. …… (3) Here, is in , temperature is in , and are constants. 26 218 26 From table B.2, the values of and for benzene and toluene is as follows: Comment Step 2 of 12 (a) The given temperature is bubble pressure as follows: and the liquid phase mole fraction is The mole fraction of benzene in the liquid solution is i n the liquid solution is . Then, calculate the and the mole fraction of toluene . Now, calculate saturation pressures of benzene and toluene in following manner: Comment Step 3 of 12 Calculate the total pressure of the system from equation (2) as follows: Substitute the known values in equation (1) and calculate the value of Therefore, the values of and are and . respectively. Comment Step 4 of 12 (b) The given vapor phase mole fraction is dew pressure as follows: The mole fraction of benzene in the vapor phase is and the temperature is in the vapor phase is . Then, calculate the and the mole fraction of toluene . Now, calculate the saturation pressures of benzene and toluene from equation (3). Comment Step 5 of 12 To calculate liquid phase mole fraction, substitute the known values in equation (1). Calculate the total pressure of the system from equation (2) as follows: Therefore, the values of and are and respectively. Comment Step 6 of 12 (c) The given liquid phase mole fraction is and the total pressure of the system is Then, calculate the bubble temperature as follows: The mole fraction of benzene in the liquid solution is in the liquid solution is . and the mole fraction of toluene . Now, calculate the saturation pressure as follows: To calculate the vapor phase mole fraction, substitute the known values in equation (1). Calculate the total pressure of the system from equation (2) as follows: Step 11 of 12 (f) The overall concentration of benzene is fraction of vapor is equal to . . For the fraction of liquid be and the The expression for the overall balance is as follows: Write the expression for the mole balance of benzene as follows: Solve equations (6) and (7) and calculate the values of . The molar fraction of two phase system in vapor phase is . Comment Step 12 of 12 (g) Benzene and toluene are both non-polar and similar in shape and size. Therefore, there will be very little interaction between them and more over high temperature and low pressure also favors for the ideal behavior. Comment Was this solution helpful? 21 0 Recommended solutions for you in Chapter 10 Chapter 10, Problem 28P Chapter 10, Problem 18P An equimolar mixture of n-butane and n-hexane a t pressure P is brought to a temperature of 95°C, where it exists as a vapor/liquid mixture in equilibrium. If the mole fraction of n-hexane in the liquid phase is 0.75, what is pressure P (in bar)... A liquid mixture of cyclohexanone(1)/phenol(2) for which x1 = 0.6 is in equilibrium with its vapor at 144°C. Determine the... View this solution View this solution Chapter 10, Problem 1P (31 Bookmarks) Show all steps: ON