

TEXT
TE
XTBO
BOOK
OK SO
SOLU
LUTI
TION
ONS
S
EXPE
EX
PERT
RT Q&A
NEW!
PRAC
PR
ACTI
TICE
CE

Search

home / study / science / chemistry / chemical engineering / chemical engineering solutions manuals / introduction to chemical engineering thermodynamics / 7th edition / chapter 10
Introduction to Chemical Engineering Thermodynamics
Thermodynamics (7th Edition)
Post a question
Answers from our experts for your tough
homework questions
Problem
Enter question
Assuming the validity of Raoult’s law, do the following calculations for the benzene(1)/to
benzene(1)/toluene(2)
luene(2)
system:
Continue to post
(a) Given x1 = 0.33 and T = 100°C, find y1 and P.
20 questions remaining
(b) Given y1, = 0.33 and T = 100°C, find x1, and P.
My Textbook Solutions
(c) Given x1, = 0.33 and P = 120 kPa, find y1, and T.
Manufacturi
ng
Processes
(d) Given y1, = 0.33 and P = 120 kPa, find x1, and T.
Introduction Manufacturin Foundatio
to Chemical... g Processes
of Finance
(e) Given T = 105°C and P = 120 kPa, find x1 and y1.
7th Edition
3rd Edition
8th Edition
View all solutions
(f) For part ( e), if the overall mole fraction of benzene is z1 = 0.33, what molar fraction of the twophase system is vapor?
Chegg tutors who can hel
right now
(g) Why is Raoult’s law likely to be an excellent VLE model for this system at the stated (or
computed) conditions?
Sanjay
Indian Institute of ...
Ritu
Step-by-step solution
C.H.S. P. Sc. & N. In...
Ryan
Step 1 of 12
University of South...
The given binary mixture system is benzene (1)/ toluene (2) system.
Write the mathematical expression of Raoult’s law as follows:
…… (1)
Here,
is the total pressure,
fraction,
is the vapor phase mole fraction,
is the liquid phase mole
is the vapor pressure of pure species.
Write the expression for total pressure by using Raoult’s law.
At
,
Then,
For binary species,
…… (2)
Write
Wri
te the exp
expre
ressi
ssion
on for the sat
satur
urati
ation
on pre
pressu
ssure
re
using
usi
ng Ant
Antoin
oine
e equa
equatio
tion.
n.
…… (3)
Here,
is in
, temperature is in
,
and
are constants.
26
218
26
From table B.2, the values of
and
for benzene and toluene is as follows:
Comment
Step 2 of 12
(a)
The given temperature is
bubble pressure as follows:
and the liquid phase mole fraction is
The mole fraction of benzene
in the liquid solution is
i n the liquid solution is
. Then, calculate the
and the mole fraction of toluene
.
Now, calculate saturation pressures of benzene and toluene in following manner:
Comment
Step 3 of 12
Calculate the total pressure of the system from equation (2) as follows:
Substitute the known values in equation (1) and calculate the value of
Therefore, the values of
and
are
and
.
respectively.
Comment
Step 4 of 12
(b)
The given vapor phase mole fraction is
dew pressure as follows:
The mole fraction of benzene
in the vapor phase is
and the temperature is
in the vapor phase is
. Then, calculate the
and the mole fraction of toluene
.
Now, calculate the saturation pressures of benzene and toluene from equation (3).
Comment
Step 5 of 12
To calculate liquid phase mole fraction, substitute the known values in equation (1).
Calculate the total pressure of the system from equation (2) as follows:
Therefore, the values of
and
are
and
respectively.
Comment
Step 6 of 12
(c)
The given liquid phase mole fraction is
and the total pressure of the system is
Then, calculate the bubble temperature as follows:
The mole fraction of benzene
in the liquid solution is
in the liquid solution is
.
and the mole fraction of toluene
.
Now, calculate the saturation pressure as follows:
To calculate the vapor phase mole fraction, substitute the known values in equation (1).
Calculate the total pressure of the system from equation (2) as follows:
Step 11 of 12
(f)
The overall concentration
of benzene is
fraction of vapor is equal to
.
. For the fraction of liquid be
and the
The expression for the overall balance is as follows:
Write the expression for the mole balance of benzene as follows:
Solve equations (6) and (7) and calculate the values of
.
The molar fraction of two phase system in vapor phase is
.
Comment
Step 12 of 12
(g)
Benzene and toluene are both non-polar and similar in shape and size. Therefore, there will be
very little interaction between them and more over high temperature and low pressure also favors
for the ideal behavior.
Comment
Was this solution helpful?
21
0
Recommended solutions for you in Chapter 10
Chapter 10, Problem 28P
Chapter 10, Problem 18P
An equimolar mixture of n-butane and n-hexane a t
pressure P is brought to a temperature of 95°C,
where it exists as a vapor/liquid mixture in
equilibrium. If the mole fraction of n-hexane in the
liquid phase is 0.75, what is pressure P (in bar)...
A liquid mixture of
cyclohexanone(1)/phenol(2)
for which x1 = 0.6 is in
equilibrium with its vapor
at 144°C. Determine the...
View this solution
View this solution
Chapter 10, Problem 1P
(31 Bookmarks)
Show all steps:
ON