CE 203 Advanced Reaction Engineering Exercise 1 Instructor: Pedro Castaño Teaching Assistants: Ali M. Alkadhem, Gontzal Lezcano February 14, 2022 Problem 1: There are two reactors of equal volume available for your use: one a CSTR, the other a PFR. A→B The reaction is second order, irreversible, and is carried out isothermally. 2 −ππ΄ = ππΆπ΄2 = ππΆπ΄0 (1 − π)2 There are two ways you can arrange your system: Scheme 1: Reactors in series: CSTR followed by PFR Scheme 2: Reactors in series: PFR followed by CSTR (a) If possible, which system will give the highest overall conversion? (b) If possible, which system will give the lowest overall conversion? Problem 2: The exothermic reaction π¨ → π© + πͺ Was carried out adiabatically and the following data were recorded: x —rA (mol/dm3. min) 0 1 0.2 1.67 0.4 5 0.45 5 0.5 5 0.6 5 0.8 1.25 0.9 0.91 The entering molar flow rate of A was 300 mol/min. (a) What are the PFR and CSTR volumes necessary to achieve 40 % conversion? (b) Over what range of conversions would the CSTR and PFR reactor volumes be identical? (c) What is the maximum conversion that can be achieved in a 105-dm3 CSTR? (d) What conversion can be achieved if a 72-dm3 PFR is followed in series by a 24dm3 CSTR? (e) What conversion can be achieved if a 24- dm3 CSTR is followed in a series by a 72- dm3’ PFR? Problem 3: Construct a complete stoichiometric table and calculate the equilibrium conversion and concentration for each of the following reaction (a) Liquid phase reaction π΄+π΅ ↔πΆ With CA0= CB0= 2mol/dm3 and Kc= 10 dm3/mol. (b) The gas-phase reaction π΄ ↔ 3π΅ Carried put in a plug flow reactor with no pressure drop. Pure A enter at 400 K and10 atm and Kc = 0.25 dm3/mol at the same temperature Problem 4: The elementary irreversible organic liquid-phase reaction. A + B →C Is carried out adiabatically in a flow reactor. An equal molar feed-in A and B enter at 27°C. And the volumetric flow rate is 2 dm3/s and Cao = 0.1 kmol/m3. Calculate the PFR and CSTR volumes necessary to achieve 80% conversion. What are the reasons for the differences? Additional infonnation: HA°(273) = -20 kcal/mol, HB°(273) = -15 kcal/mol, HC°(273) = -41 kcal/mol, CpA= CPb = 15 cal/mol . K , K = 0.01 dm3/mol.s at300, CPc = 30 cal/mol.K , E = 10,000 cal/mol. Problem 5: Reactant A (A → R, CA0 = 26 mol/m3 ) passes in steady flow through four equal-size mixed flow reactors in series (ο΄total = 2 min). When steady-state is achieved, the concentration of A is found to be 11, 5, 2, and 1 mol/m3 in the four units. For this reaction, what must be ο΄plug so as to reduce CA from 26 to 1 mol/m3 what must be ο΄CSTR if a single CSTR is used? Problem 6: Xylene can be produced from toluene as written schematically: The values of οGο° were determined at 700 K. What are the equilibrium composition (including all xylene isomers) at 700 K and 1.0 atm pressure? Problem 7: For the elementary solid-catalyzed liquid-phase reaction: A ↔ B Make a plot of equilibrium conversion as a function of temperature. When pure A is fed to the reactor at a temperature of 300 what conversion could be achieved if one cooler that had the capacity to cool the exit stream to 350 K were available? Additional information: βπ»π΄0 (298 K) = -40,000 cal mol βπ»π΅0 (298 K.) = -60,000 cal/mol CPA= 50 cal. mol K CPB = 50 cal/mol • K. Ke , = 100,000 at 298 K.