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Answer to Question #117752 in Atomic and Nuclear Physics for Lohith
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Answers > Physics > Atomic and Nuclear Physics
Programming
Question #117752
Math
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atom
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Physics
nc =
EF (0) =
Nρ
M
2
h
2m
=
6.02⋅1026 (970)
23
2
3
c
( 3n
) =
8π
= 2.5 ⋅ 1028 m−3
−34 2
(6.625⋅10 )
2(9.11⋅10−31 )
)
( 3(2.5⋅10
)
8π
28
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Chemistry
2
3
Biology
EF (0) = 5.11 ⋅ 10−19 J = 3.1 eV
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