See discussions, stats, and author profiles for this publication at: https://www.researchgate.net/publication/321727612 CHROMATOGRAPHY ( HPLC ) LAB REPORT Article · January 2017 CITATIONS READS 0 46,603 1 author: Dyah Wulandari Suranaree University of Technology 12 PUBLICATIONS 10 CITATIONS SEE PROFILE Some of the authors of this publication are also working on these related projects: Instrumentation View project Gelrite Media for Cultivation of Archaea and Thermophilic Acidobacteria View project All content following this page was uploaded by Dyah Wulandari on 11 December 2017. The user has requested enhancement of the downloaded file. CHROMATOGRAPHY ( HPLC ) LAB REPORT By : 1. Sakullapat Homkhao M6030063 2. Pongsatorn Poopisut M5930333 3. Dyah Wulandari D5930166 1. Purpose 1.1.Study principles of chromatography 1.2.Study how to use high performance liquid chromatography (HPLC) 2. Introduction 2.1. Chromatography Chromatography’ is an analytical technique commonly used for separating a mixture of chemical substances into its individual components, so that the individual components can be thoroughly analyzed. There are many types of chromatography e.g., liquid chromatography, gas chromatography, ion-exchange chromatography, affinity chromatography, but all of these employ the same basic principles. Chromatography is a separation technique that every organic chemist and biochemist is familiar with. I, myself, being an organic chemist, have routinely carried out chromatographic separations of a variety of mixture of compounds in the lab. In fact, I was leafing through my research slides and came across a pictorial representation of an actual chromatographic separation that I had carried out in the lab. I guess that picture would be a good starting point for this tutorial! 2.1.1. Principles of chromatography Let’s first familiarize ourselves with some terms that are commonly used in the context of chromatography: Term Definition Mobile phase or carrier solvent moving through the column Stationary phase or adsorbent substance that stays fixed inside the column Eluent fluid entering the column Eluate fluid exiting the column (that is collected in flasks) the process of washing out a compound through a column using Elution a suitable solvent mixture whose individual components have to be separated and Analyte analyzed Now let’s try to understand the principle of chromatography. Let us draw a pictorial representation of a column chromatographic separation set up. As depicted above, the analyte is loaded over the silica bed (packed in the column) and allowed to adhere to the silica. Here, silica acts as the stationary phase. Solvent (mobile phase) is then made to flow through the silica bed (under gravity or pressure). The different components of the analyte exhibit varying degrees of adhesion to the silica (see later), and as a result they travel at different speeds through the stationary phase as the solvent flows through it, indicated by the separation of the different bands. The components that adhere more strongly to the stationary phase travel more slowly compared to those with a weaker adhesion. Analytical chromatography can be used to purify compounds ranging from milligram to gram scale. 2.1.2. Different types of chromatography Throughout this article we are dealing with what we refer to as normalphasechromatography, implying that our stationary phase is polar (hydrophilic) in nature and our mobile phase is non-polar (hydrophobic) in nature. For special applications, scientists sometimes employ reverse-phase chromatographic techniques where the scenario is reversed i.e. the stationary phase is non-polar while the mobile phase is polar. There are several types of chromatography, each differing in the kind of stationary and mobile phase they use. The underlying principle though remains the same: differential affinities of the various components of the analyte towards the stationary and mobile phases results in the differential separation of the components. Again, the mode of interaction of the various components with the stationary and mobile phases may change depending on the chromatographic technique used. The commonly used chromatographic techniques are tabulated below. 2.2. High performance liquid chromatography (HPLC) High performance liquid chromatography is a powerful tool in analysis. This page looks at how it is carried out and shows how it uses the same principles as in thin layer chromatography and column chromatography. High performance liquid chromatography is basically a highly improved form of column chromatography. Instead of a solvent being allowed to drip through a column under gravity, it is forced through under high pressures of up to 400 atmospheres. That makes it much faster. It also allows you to use a very much smaller particle size for the column packing material which gives a much greater surface area for interactions between the stationary phase and the molecules flowing past it. This allows a much better separation of the components of the mixture. The other major improvement over column chromatography concerns the detection methods which can be used. These methods are highly automated and extremely sensitive. 2.2.1. The column and the solvent Confusingly, there are two variants in use in HPLC depending on the relative polarity of the solvent and the stationary phase. 2.2.2. Normal phase HPLC This is essentially just the same as you will already have read about in thin layer chromatography or column chromatography. Although it is described as "normal", it isn't the most commonly used form of HPLC. The column is filled with tiny silica particles, and the solvent is non-polar - hexane, for example. A typical column has an internal diameter of 4.6 mm (and may be less than that), and a length of 150 to 250 mm. Polar compounds in the mixture being passed through the column will stick longer to the polar silica than non-polar compounds will. The non-polar ones will therefore pass more quickly through the column. 2.2.3. Reversed phase HPLC In this case, the column size is the same, but the silica is modified to make it non-polar by attaching long hydrocarbon chains to its surface - typically with either 8 or 18 carbon atoms in them. A polar solvent is used - for example, a mixture of water and an alcohol such as methanol. In this case, there will be a strong attraction between the polar solvent and polar molecules in the mixture being passed through the column. There won't be as much attraction between the hydrocarbon chains attached to the silica (the stationary phase) and the polar molecules in the solution. Polar molecules in the mixture will therefore spend most of their time moving with the solvent. Non-polar compounds in the mixture will tend to form attractions with the hydrocarbon groups because of van der Waals dispersion forces. They will also be less soluble in the solvent because of the need to break hydrogen bonds as they squeeze in between the water or methanol molecules, for example. They therefore spend less time in solution in the solvent and this will slow them down on their way through the column. That means that now it is the polar molecules that will travel through the column more quickly. Reversed phase HPLC is the most commonly used form of HPLC. 2.2.4. Injection of the sample Injection of the sample is entirely automated, and you wouldn't be expected to know how this is done at this introductory level. Because of the pressures involved, it is not the same as in gas chromatography 2.2.5. Retention time The time taken for a particular compound to travel through the column to the detector is known as its retention time. This time is measured from the time at which the sample is injected to the point at which the display shows a maximum peak height for that compound. Different compounds have different retention times. For a particular compound, the retention time will vary depending on: the pressure used (because that affects the flow rate of the solvent) the nature of the stationary phase (not only what material it is made of, but also particle size) the exact composition of the solvent the temperature of the column That means that conditions have to be carefully controlled if you are using retention times as a way of identifying compounds. 2.2.6. The detector There are several ways of detecting when a substance has passed through the column. A common method which is easy to explain uses ultra-violet absorption. Many organic compounds absorb UV light of various wavelengths. If you have a beam of UV light shining through the stream of liquid coming out of the column, and a UV detector on the opposite side of the stream, you can get a direct reading of how much of the light is absorbed. The amount of light absorbed will depend on the amount of a particular compound that is passing through the beam at the time. You might wonder why the solvents used don't absorb UV light. They do! But different compounds absorb most strongly in different parts of the UV spectrum. Methanol, for example, absorbs at wavelengths below 205 nm, and water below 190 nm. If you were using a methanol-water mixture as the solvent, you would therefore have to use a wavelength greater than 205 nm to avoid false readings from the solvent. 2.2.7. Interpreting the output from the detector The output will be recorded as a series of peaks - each one representing a compound in the mixture passing through the detector and absorbing UV light. As long as you were careful to control the conditions on the column, you could use the retention times to help to identify the compounds present - provided, of course, that you (or somebody else) had already measured them for pure samples of the various compounds under those identical conditions. But you can also use the peaks as a way of measuring the quantities of the compounds present. Let's suppose that you are interested in a particular compound, X. If you injected a solution containing a known amount of pure X into the machine, not only could you record its retention time, but you could also relate the amount of X to the peak that was formed. The area under the peak is proportional to the amount of X which has passed the detector, and this area can be calculated automatically by the computer linked to the display. The area it would measure is shown in green in the (very simplified) diagram. If the solution of X was less concentrated, the area under the peak would be less - although the retention time will still be the same. For example: This means that it is possible to calibrate the machine so that it can be used to find how much of a substance is present - even in very small quantities. Be careful, though! If you had two different substances in the mixture (X and Y) could you say anything about their relative amounts? Not if you were using UV absorption as your detection method. In the diagram, the area under the peak for Y is less than that for X. That may be because there is less Y than X, but it could equally well be because Y absorbs UV light at the wavelength you are using less than X does. There might be large quantities of Y present, but if it only absorbed weakly, it would only give a small peak. 2.2.8. Coupling HPLC to a mass spectrometer This is where it gets really clever! When the detector is showing a peak, some of what is passing through the detector at that time can be diverted to a mass spectrometer. There it will give a fragmentation pattern which can be compared against a computer database of known patterns. That means that the identity of a huge range of compounds can be found without having to know their retention times. 3. Material and Method 3.1. Material - Micropipette - Tip - HPLC Machine - Syringe - Filter 0.2µm - Eppendorf tube - Vial tube and cap 3.2. Reagent - Sucrose 10mg/ml - Samples 24.25.1 & 24.25.2 - H2SO4 0.005N liquid as mobile phase - DI water 3.3. Method 3.3.1. Sample preparation 1. Sucrose standard: The sucrose standard was done by the dilution from the sucrose stock in concentration 2.5mg/ml, 5 mg/ml, 7.5mg/ml and 10mg/ml. 2. Sample preparation The samples have to dilute in 20X and 50X V total Calculation = 20𝑥 = V sample, so if the V total 1000µl, the volume sample we use 50µl, and add the DI water 950 µl V total 50𝑥 = V sample, so if the V total 1000µl, the volume sample we use 20µl and add the DI water 980 µl 3. After the sucrose standard and the samples already prepared, then we do the filtration by the filter paper connect with the syringe with the d = 0.2µm, then put in the vial then close with the caps and labelled the samples 4. After all preparation finish, run the samples with HPLC machine. 5. Before use, set the condition of HPLC machine first with the injection volume 10ul, the flow 0.5 ml/min, pressure bar 35.85, and temperature 55ºC 6. Placed the samples into the tray and don’t forget to type sample’s name. After all sett then run the machine. Each samples takes time around 50minutes to detect the chemical inside the samples. 7. After finish, collect the chromatogram data and calculate the concentration of the samples by compare with the standard curve. 4. Results & Discussions Table 1. retention time of standard sugars retention time retention time retention time avg. 1 avg. 2 avg. 3 arabinose 14.691 - - glucose 12.608 - - xylose 13.59075 - - fructose 13.66025 - - maltose 10.623 - - sucrose 10.693 12.3846 13.0716 From Table 1. retention time of standard sugars , the retention time of sucrose should have a peak but this analysis sucrose from HPLC have 3 peaks . it is error because we use sulfuric acid 0.005 N for mobile phase , sucrose can be dehydrated with sulfuric acid and maybe produce some carbon and SO3. Thus analysis of standard sucrose have 3 peaks . We should change the solution for mobile phase. Figure 1 . analysis sample 1(dilute 20 times and 50 times) from HPLC Table 2. the retention time of sample 1 (dilute 20 times and 50 times) retention time retention time retention time retention time retention time 1 2 3 4 5 result1x50 10.694 12.668 13.662 18.18 - result1x20 10.673 12.595 13.611 17.295 20.344 12.6315 13.6365 17.7375 20.344 Retention time avg. 10.6835 When we compare retention time of sample From Table 2. the retention time of sample 1 (dilute 20 times and 50 times) with standard sugars from Table 1. retention time of standard sugars and calculate sugar’s concentration from standard curves. 1. the retention time avg. 1 (10.6835 min) is nearly the retention time avg. of sucrose (10.693 min) 2. the retention time avg. 2 (12.6315 min) is nearly the retention time avg. of glucose (12.608 min) 3. the retention time avg. 3 (13.6365 min) is nearly the retention time avg. of fructose (13.66025 min) 4. the retention time avg. 4 & 5 we don’t know because the standard of sugars don’t show peaks at retention time around 17 and 20 min. Table 3 . the results of sample 1 (dilute 20 times and 50 times) sucrose (mg/l) sample 1(dilute 50 1(dilute 20 times) sample times) avg. conc. fructose conc.(mg/l) glucose (mg/l) 7.05702 0.12836 0.843763 6.45041 0.097733 0.254314 6.753715 0.1130465 0.5490385 conc. Figure 2 . analysis sample 2 (dilute 20 times and 50 times) from HPLC Table 4. the retention time of sample 2 (dilute 20 times and 50 times) retention time Retention time retention time retention time 1 retention time 5 2 3 4 result2x50 10.621 12.58 13.567 - - result2x20 10.614 12.58 13.363 17.2 20.307 12.58 13.465 17.2 20.307 Retention time avg. 10.6175 When we compare retention time of sample From Table 4. the retention time of sample 2 (dilute 20 times and 50 times) with standard sugars from Table 1. retention time of standard sugars and calculate sugar’s concentration from standard curves. 1. the retention time avg. 1 (10.6175 min) is nearly the retention time avg. of maltose(10.623 min) 2. the retention time avg. 2 (12.58 min) is nearly the retention time avg. of glucose (12.608 min) 3. the retention time avg. 3 (13.465 min) is nearly the retention time avg. of xylose (13.59075 min) 4. the retention time avg. 4 & 5 we don’t know because the standard of sugars don’t show peaks at retention time around 17 and 20 min. table 5 . the results of sample 2 (dilute 20 times and 50 times) sample 2 (dilute 50 times) sample 2 (dilute 20 times) avg. maltose conc. glucose conc. xylose conc. (mg/ml) (mg/ml) (mg/ml) 1.844376 0.863133 0.42084 1.574105 0.312792 0.137708 1.7092405 0.5879625 0.279274 5. Conclusion 1. the first sample have sucrose 6.754 mg/ml , glucose 0.549 mg/ml and fructose 0.113 mg/ml 2. the second sample have maltose 1.071 mg/ml , glucose 0.588 mg/ml and xylose 0.279 mg/ml Reference https://www.khanacademy.org/test-prep/mcat/chemical-processes/separationspurifications/a/principles-of-chromatography http://www.chemguide.co.uk/analysis/chromatography/hplc.html View publication stats