1 KE = mv 2 2 GPE = mgh 1. A bow can shoot a 0.042 kg arrow at a speed of 16.5m/s. What is the kinetic energy of the arrow? 2. A high jumper has a mass of 62 kg. She jumps to a maximum height of 2.3 m. If the acceleration due to gravity is 10 m/s2, calculate the gravitational potential energy of the jumper. 3. A cheetah can run with a speed of 34 m/s and has a kinetic energy of 32946 J. What is the mass of the cheetah? 4. In an elevator, it takes 33 kJ of energy to lift a group of people up 6 m. What is the total mass of the group of people? 5. A climber has a potential energy of 11000 J. If the mass of the climber is 85 kg determine their height above the ground. 6. On a particular planet, it takes 850 J for a 50 kg remote probe to launch itself up 2 m. What is the gravitational field strength on the planet? 7. It takes 338000 J of energy to move a car of mass 1000 kg at a speed of v. Calculate v. 8. A stone is dropped down a well. When it hits the bottom of the well it is travelling at 20 m/s. The mass of the stone is 0.02 kg. a. Calculate the kinetic energy of the stone as it hits the bottom of the well. b. What is the gravitational potential energy of the stone at the top of the well? c. Calculate the height of the well. 9. There are two remote control toys – a car and a truck. The truck is twice as heavy as the car, but the car is travelling at twice the speed of the truck. Assume the batteries in each have the same power. Which battery will go flat first? Why? 1 KE = mv 2 2 GPE = mgh 1. A bow can shoot a 0.042 kg arrow at a speed of 16.5m/s. What is the kinetic energy of the arrow? 2. A high jumper has a mass of 62 kg. She jumps to a maximum height of 2.3 m. If the acceleration due to gravity is 10 m/s2, calculate the gravitational potential energy of the jumper. 3. A cheetah can run with a speed of 34 m/s and has a kinetic energy of 32946 J. What is the mass of the cheetah? 4. In an elevator, it takes 33 kJ of energy to lift a group of people up 6 m. What is the total mass of the group of people? 5. A climber has a potential energy of 11000 J. If the mass of the climber is 85 kg determine their height above the ground. 6. On a particular planet, it takes 850 J for a 50 kg remote probe to launch itself up 2 m. What is the gravitational field strength on the planet? 7. It takes 338000 J of energy to move a car of mass 1000 kg at a speed of v. Calculate v. 8. A stone is dropped down a well. When it hits the bottom of the well it is travelling at 20 m/s. The mass of the stone is 0.02 kg. a. Calculate the kinetic energy of the stone as it hits the bottom of the well. b. What is the gravitational potential energy of the stone at the top of the well? c. Calculate the height of the well. 9. There are two remote control toys – a car and a truck. The truck is twice as heavy as the car, but the car is travelling at twice the speed of the truck. Assume the batteries in each have the same power. Which battery will go flat first? Why? Answers 1 1. πΎπΈ = ππ£ 2 = 0.5 × 0.042 × 16.52 = 5.7 J 2 2. πΊππΈ = ππβ = 62 × 10 × 2.3 = 1426 J 1 2πΎπΈ 32946 3. πΎπΈ = ππ£ 2 ⇒ π = 2 = = 57 kg 2 2 4. πΊππΈ = ππβ ⇒ π = 5. πΊππΈ = ππβ ⇒ β = 6. πΊππΈ = ππβ ⇒ π = 1 π£ πΊππΈ πβ πΊππΈ ππ πΊππΈ πβ πΎπΈ = = = 0.5×34 33000 10×6 11000 10×85 850 = 550 kg = 12.9 m = 8.5 N/kg 50×2 338000 7. πΎπΈ = ππ£ 2 ⇒ π£ = √1 = √ = 18.3 m/s 2 0.5×1000 π 2 8. This question relies on the conservation of energy. Because the stone is dropped from a height the total amount of GPE to begin with is turned into KE at the end. 1 a. gf πΎπΈ = ππ£ 2 = 0.5 × 0.02 × 202 = 4 J 2 b. By energy conservation, GPE at the top is 4 J as well. πΊππΈ 4 4 c. πΊππΈ = ππβ ⇒ β = = = = 20 m ππ 0.02×10 0.2 9. This is a hard question mainly because there aren’t any numbers only ratios. It can be simplified if the students choose a number of the mass and speed say 1. So the car has a mass of 1 kg and the truck has twice this (2 kg) The truck has a speed of 1 m/s, and the car has three times this (3 m/s) So the kinetic energy of the car is And the kinetic energy of the truck is 0.5 × 1 × 32 = 4.5 J 0.5 × 2 × 12 = 1 J So the car has more kinetic energy therefore, More energy needs to be transferred from the battery, Therefore the battery in the car will run out first (both batteries have the same power from the question). (In fact the battery will be used up 4.5 times more quickly in the car!)