Uploaded by Divit Kothari

Maths Cheat Sheet

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Divit’s Cumulative Revision Sheet
Laws of Indices
y y  y
a
b
(y )  y
a b
Surds
a b
a b
y y  y
y 1
a
1
y n  n
y b  b ya
y
a
ab
b
0
a a a
√𝑎 × √𝑏 = √𝑎𝑏
Rationalise the denominator
4 ×√2
√2 ×√2
√𝑎 × 𝑏 = 𝑏√𝑎
=
4√2
2
= 2√2
Converting recurring decimals to fractions 𝐿𝑒𝑡 𝑥 = 𝑡ℎ𝑒 𝑑𝑒𝑐𝑖𝑚𝑎𝑙 𝑤𝑟𝑖𝑡𝑡𝑒𝑛 𝑜𝑢𝑡 …
× 10, 100 𝑜𝑟 1000 (check how many digits recur)
Subtract by aligning the decimal points
e.g.
Upper Bounds & Lower Bounds
The lower and upper bounds are the ± margins for
rounding to the value (𝑥).
𝑀𝑎𝑟𝑔𝑖𝑛𝑠 = ± ℎ𝑎𝑙𝑓 𝑤ℎ𝑎𝑡 𝑖𝑡 ℎ𝑎𝑠 𝑏𝑒𝑒𝑛 𝑟𝑜𝑢𝑛𝑑𝑒𝑑 𝑡𝑜
𝑙𝑜𝑤𝑒𝑟𝑏𝑜𝑢𝑛𝑑 ≤ 𝑥 < 𝑢𝑝𝑝𝑒𝑟𝑏𝑜𝑢𝑛𝑑
e.g.
𝑥 = 0.2666 …
10𝑥 = 2.6666
10𝑥 − 𝑥 = 2.6666 − 0.2666
9𝑥 = 2.4
24
𝑥=
90
Direct/Inverse Proportion
𝑦 = 𝑘𝑥 2 ↔ y is (directly) proportional to 𝑥 2
𝑘
𝑦 = 2 ↔ y is inversely proportional to 𝑥 2
𝑥
lower and upper bounds of 5 are 4.5 and 5.5
respectively. (4.5 ≤ 5 < 5.5)
Histograms – the area of the bars represents the
𝐹𝑟𝑒𝑞
frequency. Frequency Density is 𝐹𝐷 |𝐶𝑊
Cumulative Frequency - plot the upper bound of the
class interval and the frequency.
Box Plots
Estimating Mean from a table
Intervals
Frequency
Midpoint x F
Sum of this
Sum of this
Mean =
𝑠𝑢𝑚 𝑜𝑓 (𝑚𝑖𝑑×𝑓𝑟𝑒𝑞)
𝑠𝑢𝑚 𝑜𝑓 𝑓𝑟𝑒𝑞
Frequency Polygons – plot the midpoint and the
frequency/
Pythagoras’ Theorem – for right-angled triangles
Square, add and square-root for the longest side
Square, subtract and square-root for a shorter side
Basic Trigonometry – for right-angled triangles only
𝑂𝑝𝑝
SOH sin 𝜃 | 𝐻𝑦𝑝 *press shift to find angles*
CAH
𝐴𝑑𝑗
cos 𝜃 | 𝐻𝑦𝑝
TOA
𝑂𝑝𝑝
tan 𝜃 | 𝐴𝑑𝑗
𝐷
Speed is distance/time 𝑆| 𝑇
𝑀
Density is mass/volume 𝐷| 𝑉
𝜃
Comparing datasets – comment on an average (median
or mean) and the spread (IQR or range).
Parts of a circle
Area of a circle is 𝜋𝑟 2
𝜃
*for sectors × 360
Circumference is 𝜋𝑑
𝜃
*for arcs × 360
Area of a circle is 𝜋𝑟 2 *for sectors × 360
Circumference is 𝜋𝑑
𝜃
*for arcs × 360
Transformations of shapes
Rotation about a point, 90° (anti)clockwise or 180°
Reflection through a line *look out for 𝑦 = 𝑥 or 𝑦 =
−𝑥
𝑥 𝑑𝑖𝑟𝑒𝑐𝑡𝑖𝑜𝑛
Translation through a vector (
)
𝑦 𝑑𝑖𝑟𝑒𝑐𝑡𝑖𝑜𝑛
Enlargement from a point, by a scale factor
* if fraction: shape gets smaller
* if negative: shape inverted through the centre
Constructions
Perpendicular Bisector
Straight Line Geometry
Angle Bisector
𝑦 = 𝑚𝑥 + 𝑐 (m is gradient, c is y-intercept)
Find c by substituting 𝑥, 𝑦 𝑎𝑛𝑑 𝑚
Gradient =
𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑖𝑛 𝑦
𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑖𝑛 𝑥
=
𝑟𝑖𝑠𝑒
𝑟𝑢𝑛
Midpoint = add the x-coordinates and divide by 2
add the y-coordinates and divide by 2
* to construct from a point, start with compass on that
point and mark onto the line first.
Percentages
The Nth Term
𝑑𝑛 + 𝑜 (coefficient of n is the common difference and
add the zero’th term)
The multiplier always goes with the change
Increase = higher multiplier and vice versa
HCF and LCM
HCF = common prime factors
LCM = HCF × leftovers
Simple Interest
New price = original × multiplier
To find an original price, divide by the multiplier
Division and Multiplication
0.8 × 0.12 = 0.096 (3 decimal places in total)
0.8 × 100 80 ÷ 4 10
1
=
=
=3
0.12 × 100 12 ÷ 4
3
3
Compound interest
New amount = original × 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑖𝑒𝑟 𝑦𝑒𝑎𝑟𝑠
Quadratic Equations
To factorise, check the sum-product
𝑥 2 − 5𝑥 + 6
sum = -5 and product = 6
(𝑥 − 3)(𝑥 − 2)
Inequalities
0≤𝑥<4
For quadratics with a co-efficient of 𝑥 2
3𝑥 2 + 8𝑥 − 3
sum = 8 and product = -9 (3×-3)
3𝑥 2 + 9𝑥 − 1𝑥 − 3
split the middle term
3𝑥(𝑥 + 3) − 1(𝑥 + 3) factorise the first 2 and last 2
(3𝑥 − 1)(𝑥 + 3)
factorise again
The difference of two squares
𝑥 2 − 64 = (𝑥 + 8)(𝑥 − 8)
4𝑥 2 − 9𝑦 2 = (2𝑥 + 3𝑦)(2𝑥 − 3𝑦)
𝑥>2
𝑥≥2
To draw a region, use a table of values to draw the
straight lines. When you multiply or divide both sides of
an inequality by a negative, flip the sign.
𝑣 = 𝜋𝑟 2 ℎ
𝑆𝐴 = 2𝜋𝑟ℎ
4
𝑣 = 3 𝜋𝑟 3
𝑆𝐴 = 4𝜋𝑟 2
Imperial to Metric Conversions
Imperial
Metric
Measurements
1 inch (1”)
1 foot (1 ft)
5 miles (5 mi.)
Measurements
2.5 centimeter (2.5 cm)
30 centimeters (30 cm)
8 kilometers (8 km)
Weights
1 pound (1 lb)
2.2 pounds (2.2 lbs)
1 stone (1 st.)
Weights
450 grams (450 g)
1 kilogram (1 kg)
6.3 kilograms (6.3 kg)
Capacity
1 pint (1 pt)
1 gallon (1 gal)
1.75 pints (1 pt)
Capacity
570 millilitres (570 ml)
4.5 litres (4.5 l)
1 litre (1 l)
Prime Factor Decomposition
Prime Factor Decomposition is the breakdown of positive integers
into prime numbers. This is done through many steps of
factorisation.
e.g.
24 = 4 × 6 = 2 × 2 × 2 × 3 = 23 × 3
Stem & Leaf Diagrams
Stem and Leaf Diagrams are used to
organise data sets by separating the
place values in the number. All Stem
and Leaf Diagrams MUST have a key.
e.g.
2 | 1 = 21
Mean – The mean is the total of all the values, divided
by the number of values
Median – The median is the middle number in a list of
numbers ordered from lowest to highest
Mode – The mode is the value that appears most often
in a set of data
Range – The range is the difference between the lowest
value and the highest value
Correlation refers to the dependance of 2 different
variables when compared together. e.g. if x increases y
increases; this is positive correlation
Ratios
Simultaneous Equations
Simplification – Divide both parts by the same number
until it cant be further divided
Bring 1 variable to a side in 1 equation and then plug
into second equation to solve.
E.g. 4𝑥 − 2𝑦 = 4
5𝑥 + 3𝑦 = 16
Using Ratios – To find proportional values divide the
number by the corresponding part of
the ratio.
E.g. 9 : ? using the ratio 3 : 4
9
= 3, 4 × 3 = 12
3
Ratios <-> Fractions – To convert from a Ratio to a
Fraction add all the parts
together and then use the part in
the question as the numerator.
3
E.g. 3 ∶ 5, 3 + 5 = 8 ∴ 3 ∶ 5 → 8
2𝑦 = 4𝑥 − 4
𝑦 = 2𝑥 − 2
5𝑥 + 3(2𝑥 − 2) = 16
11𝑥 − 6 = 16
11𝑥 = 22
𝑥=2
There is the subtraction method aswell, however this is
superior.
Angle Rules
Sum of interior angles in polygon = (𝑛 − 2) × 180
360
One exterior angle of a regular polygon = 𝑛
Properties of Parallelograms and Rhombuses
In a parallelogram all the opposite sides and angles are the same value.
In a rhombus all sides are the same value and opposite angles are the same value.
Kite Rules
- The diagonals of the kite intersect at
90°
- The lines BC and CD are equal and BA and
AD are also equal
- The angle B = D
Proof of Exterior Angle of a Triangle
Angle x is an exterior angle of the triangle:
The exterior angle of a triangle is equal to the sum of the interior angles at the other two vertices. In other words,
x = a + b in the diagram.
Proof:



The angles in the triangle add up to 180 degrees. So a + b + y = 180.
The angles on a straight line add up to 180 degrees. So x + y = 180.
Therefore y = 180 − x. Putting this into the first equation gives us: a + b + 180 − x = 180. Therefore
a + b = x after rearranging. This is what we wanted to prove.
Proof of Angles in a Triangle
Construct a line parallel to BC and label the new angles x and y. Since angle x and c are alternate they are equal
and sicne angle y and b are alternate they are equal.
Since angles on a straight line equal 180°; 𝑥 + 𝑦 + 𝑧 = 180°. Therefore angles in a triangle equal 180°
Bearings
Bearings are calculated from north. If a
bearing is less than 100° then it should
have a 0 at the front.
Transformations
There are 4 types of translations.
Enlargements and Dilations use scale
factors to transform the shape
whereas translations use vectors.
e.g.
means translate the shape
4 squares to the right and
3 squares down.
Scale Factors
In this image the blue triangle is enlarged by a scale
factor of -2 around the point P to make the pink
triangle.
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