Uploaded by Ajitha Kalidindi

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nROuP +
GROufASSIGN
MENT S EEMt03|ET
Dos:- R¢19
TR DM.
QUESTotu-6o
An OCSs
has the atlouing choracen'shis Lio
f
m
kibn
loss Pse
3da,be loss/Km
fi =5 da/km, fib
leugt,L
MOKm,Cone ctor loss
Lconds
betwten o
loss Lo
Ovaw
7da m
LED o
one coune ttor
km Fibe leMgH , A be to deeckor
- 3dn , PeceiuOr
temaiivt s = - 36d8
ducgron clsysm cepnodks tihdicah ny
tosses i d eoLwer rceid at the veceiu
a
in W o d di m
AlSo A'no th lossmatn Lm.i
we wamt to tnomase tHa los s mA n b| 3dA
whad-should
we do.
ANSWER-60
m
W - x
Xo
w
(n
dsm
, =
lole7»
3d6m
s
Zd
LEn
3L-4o
km
( fibe le )
2.
2
LCo
\d
to
lowev loss )
dnd | coh hetoy 1
used behueein a 3.
Km b e legth
S
f
05 ds dejkm (Kbn loss)
LAD
3dl (Abe to dete ctor loss)
s
3 6 dSm
(Peceio seustivi
To ind
.
Praw a dtagra al1ystem couponeut
indica
osses
recel
os
Ojin Lm
m
locs, mo
Cie-
vqo n drgvcw
dicanq o»eks
l
lysfens comfenw
36ABn
PeteOete ckov
bve locs
km)Fbe
rbe (omnecho
ogs
tos 1cd
'oqyam
6o1
d ete cH6v
(onne ch on lsg
o hne ov
oAl1 Systmm (ompgemts ivditati
Clep-Pouer Keceitol a le cune
tv
wi Hed (owev
LE0 pewe
dßm
4
R
w
Total loss CEO » jb
dna
w
T=TdBm
loss) + CTotal Abe loss)t
(Total (bnnectov locc) +CAbt h detrto
loss
ED
ctal
bors, Pe =1d
fbt los (Total leg4)(Gibelos s)
TL(10k)(o*S dB] K)
dvony N
L))
=
Total le h
Max lem
onnect
w H od
iont
cAYun
Ro d
Counectovs
mbe
-=|
C-
Total Connecvloss,kon
( A-* Low
I
Fib
ld
to deteckev loss, LFo 3 d e
Total tossL3ds # 20d & +Id
fewer
eceived an d8m
+3dß =27dB
la - r
-hota
losS
3dsm-24dB
in SI Unts
r
1 0 * 4 -3 1
x10 m
Stp-3 alulahim loss Mai'n,tm
6Lossmasgin Lm r - fs
Keceiued leweecet
Lm-4
Sep-
-
Seuuihvity
(-76) =12dB
Achn taken to iucnae Lo min by
3
Ia.
Ate iutmet total Joss main will be t'
12+3
el
1sd
1eloq l
w
mcemwt ase, ler
LEO Peu e be fr/
Subhathwg beth
the
to
looq
egh
log
T
=
L
-L
1dB
T
= R / T = 2(mw) =m
Th
o
incnaie
Wud to d ouble
loss ma
H
tn
by34B, we
as uitte peue
ANSWER MATRTx
To n
S No
Trons mtHed fowey
(T)
mW
Re ceuad Pewev
38w
3
LD&
Mayin (Lm)
W
Rds
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