Derivation of Kinematic Equations Sama Ehab, Mirna Amr, Nancy Mohamed, Salma Ammar ๐๐ + ๐๐ ๐๐ = ( )๐๐ ๐ Δ๐ฅ • Average velocity is represented as: ๐ฃ = • Average velocity can also be represented as: ๐ฃ = • Rearrange the equation above to solve for Δ๐ฅ Δ๐ก ๐ฃ๐ +๐ฃ๐ 2 Δ๐ฅ = ๐ฃΔ๐ก • ๐ฃ๐ +๐ฃ๐ Substitute ๐ฃ with ๐ฃ๐ + ๐ฃ๐ Δ๐ฅ = ( )Δ๐ก 2 2 in the equation above to get our first kinematic equation. ๐ฅ๐ฅ = 1 ๐๐๐ ๐ × โ๐๐๐โ๐ก + (๐๐๐๐๐กโ × ๐ค๐๐๐กโ) 2 ๐ฅ๐ฅ = 1 ๐ฅ๐ก ๐ฃ๐ − ๐ฃ๐ + ๐ฃ๐ × ๐ฅ๐ก 2 1 1 = ๐ฃ๐ ๐ฅ๐ก − ๐ฃ๐ ๐ฅ๐ก + ๐ฃ๐ ๐ฅ๐ก 2 2 1 1 = ๐ฃ๐ ๐ฅ๐ก + ๐ฃ๐ ๐ฅ๐ก 2 2 Δ๐ฅ = ( o We know that the area under the graph is the displacement (Δ๐ฅ). ๐ฃ๐ + ๐ฃ๐ )๐ฅ๐ก 2 ๐๐ = ๐๐ + ๐๐๐ Δ๐ฃ Δ๐ก • Acceleration is represented as: ๐ = • Substitute Δ๐ฃ with ๐ฃ๐ − ๐ฃ๐ ๐ฃ๐ − ๐ฃ๐ ๐= Δ๐ก • Rearrange the equation above to solve for ๐ฃ๐ ๐ฃ๐ = ๐ฃ๐ + ๐Δ๐ก ๐ฃ๐ = ๐ต๐ถ ๐ฃ๐ = ๐ต๐ท + ๐ท๐ถ ๐ฃ๐ = ๐ต๐ท + ๐ฃ๐ ๐= ๐ต๐ท ๐ด๐ท ๐= ๐ต๐ท Δ๐ก ๐ต๐ท = ๐Δ๐ก ๐ฃ๐ = ๐ฃ๐ + ๐Δ๐ก ๐ ๐๐ = ๐๐ ๐๐ + ๐๐๐๐ ๐ ๐ฃ๐ +๐ฃ๐ • Start with the first kinematic equation (XVT) Δ๐ฅ = • Substitute ๐ฃ๐ with our second kinematic equation (VAT) ๐ฃ๐ = ๐ฃ๐ + ๐Δ๐ก. Δ๐ฅ = ๐ฃ๐ + (๐ฃ๐ + ๐Δ๐ก) Δ๐ก 2 2๐ฃ๐ ๐Δ๐ก + Δ๐ก 2 2 • Expand the equation • Simplify the equation Δ๐ฅ = ๐ฃ๐ Δ๐ก + ๐Δ๐ก 2 Δ๐ฅ = 1 2 2 Δ๐ก. ๐ฅ๐ฅ = 1 ๐๐๐ ๐ × โ๐๐๐โ๐ก + (๐๐๐๐๐กโ × โ๐๐๐โ๐ก) 2 = 1 Δ๐ก ๐ต๐ท + (๐ฃ๐ × Δ๐ก) 2 ๐= ๐ต๐ท ๐ด๐ท ๐= ๐ต๐ท Δ๐ก ๐ต๐ท = ๐Δ๐ก = 1 Δ๐ก ๐Δ๐ก + ๐ฃ๐ Δ๐ก 2 1 ๐ฅ๐ฅ = ๐ฃ๐ ๐ฅ๐ก + ๐๐ฅ๐ก 2 2 ๐๐๐ = ๐๐๐ + ๐๐๐๐ • ๐ฃ๐ +๐ฃ๐ Start with the first kinematic equation (XVT) Δ๐ฅ = ( • 2 )Δ๐ก. Use the second kinematic equation (VAT) ๐ฃ๐ = ๐ฃ๐ + ๐Δ๐ก, and rearrange it to solve for t. ๐ฃ๐ − ๐ฃ๐ Δ๐ก = ๐ ๐ฃ๐ − ๐ฃ๐ • Substitute Δ๐ก in our first equation with . ๐ ๐ฃ๐ +๐ฃ๐ Δ๐ฅ = ( 2 ๐ฃ๐ − ๐ฃ๐ )( ๐ ). ๐ฃ๐2 −๐ฃ๐2 • Multiply the fractions and simplify Δ๐ฅ = ( • We can rearrange the equation above to solve for ๐ฃ๐2 ๐ฃ๐2 = ๐ฃ๐2 + 2๐Δ๐ฅ 2๐ ). 1 Δ๐ฅ = (๐๐๐ ๐1 + ๐๐๐ ๐2)(โ๐๐๐โ๐ก) 2 1 Δ๐ฅ = ๐ฃ๐ + ๐ฃ๐ Δ๐ก 2 ๐ฃ๐ − ๐ฃ๐ ๐= Δ๐ก Δ๐ก = = ๐ฃ๐ − ๐ฃ๐ ๐ 1 ๐ฃ + ๐ฃ๐ 2 ๐ ๐ฃ๐ − ๐ฃ๐ ๐ 1 ๐ฃ๐2 − ๐ฃ๐2 = 2 ๐ 2๐Δ๐ฅ = ๐ฃ๐2 − ๐ฃ๐2 ๐ฃ๐2 = ๐ฃ๐2 + 2๐Δ๐ฅ Resources “Derivation of Equations of Motion.” Byju’s, 28 June 2018, https://byjus.com/physics/derivation-of-equation-of-motion/#Derivation-of-ThirdEquation-of-Motion. “Kinematic Equations.” Pasco, https://www.pasco.com/products/guides/kinematic-equations. “What are the kinematic formulas?” Khan Academy, https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematicformulas/a/what-are-the-kinematic-formulas. “Derivation of Kinematic Equations.” https://www.muncysd.org/site/handlers/filedownload.ashx?moduleinstanceid=2437&data id=4035&FileName=Kinematic%20Eqns.pdf.