\ Second Quarter Module 2 Week 2 SDO TAGUIG CITY AND PATEROS Introductory Message For the facilitator: This module was collaboratively designed, developed and evaluated by the Development and Quality Assurance Teams of SDO TAPAT to assist you in helping the learners meet the standards set by the K to 12 Curriculum while overcoming their personal, social, and economic constraints in schooling. As a facilitator, you are expected to orient the learners on how to use this module. You also need to keep track of the learners' progress while allowing them to manage their own learning. Furthermore, you are expected to encourage and assist the learners as they do the tasks included in the module. For the learner: This module was designed to provide you with fun and meaningful opportunities for guided and independent learning at your own pace and time. You will be helped to process the contents of the learning resource while being an active learner. The following are some reminders in using this module: 1. Use the module with care. Do not put unnecessary mark/s on any part of the module. Use a separate sheet of paper in answering the exercises. 2. Don’t forget to answer Let’s Try before moving on to the other activities included in the module. 3. Read the instruction carefully before doing each task. 4. Observe honesty and integrity in doing the tasks and in checking your answers. 5. Finish the task at hand before proceeding to the next. 6. Return this module to your teacher/facilitator once you are through with it. If you encounter any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator. Always bear in mind that you are not alone. We hope that through this material, you will experience meaningful learning and gain deep understanding of the relevant competencies. You can do it! Let’s Learn This module was designed and written with you in mind. It is here to help you master Variation. The scope of this module permits it to be used in many different learning situations. The language used recognizes the diverse vocabulary level of students. The lessons are arranged to follow the standard sequence of the course. But the order in which you read them can be changed to correspond with the textbook you are now using. After going through this module, you are expected to: 1. illustrate situations that involve the following variations: (a) joint and (b) combined; 2. translate into variation statement a relationship between two quantities given a mathematical equation; and 3. solve problems involving variation. Let’s Try Directions: Read each question carefully and solve if necessary. Choose the letter of the correct answer and write it before the number. 1. The statement, β varies directly as ππ and inversely as ππ is an example of _________. A. direct variation C. joint variation B. inverse variation D. combined variation 2. Which of the following is an equation of joint variation? A. π¦π¦ = π₯π₯ B. π¦π¦ = 8π₯π₯ 8 C. π¦π¦ = 8π₯π₯π₯π₯ D. π¦π¦ = 8π₯π₯ 2 3. Find the value of the constant of variation if ππ varies jointly as ππ and ππ, and ππ = 24 when ππ = 3 and ππ = 4 A. 2 B. 4 C. 6 D. 8 4. If ππ varies directly as ππ and inversely as ππ. Find k when ππ = 2, ππ = 1 and ππ = 4 A. 8 B. 4 C. 2 D. 1 5. The mass of a concrete block varies jointly as its length, width and thickness. If the mass of a 10 in by 6 in by 4 in concrete block is 120 kg, find the mass of 12 in by 5 in by 6 in concrete block. A. 120 B. 140 C. 160 D. 180 6. In the equation π€π€ A. ππ = ππππ π£π£ , π£π£ ≠ 0, what varies directly as π€π€? B. π€π€ C. π£π£ D. π’π’ 7. Express the statement “ ππ varies directly as ππ and inversely as ππ2 ” in equation. A. ππ = ππ ππ2 B. ππ = ππππππ2 C. ππ = ππππ ππ2 D. ππ = ππππ2 8. Suppose π·π· varies directly as ππ and inversely as ππ, and π·π· = 10 when ππ = 5 and ππ = 2. What is A. 3 4 ππ ππ when π·π· = 3? B. 1 4 C. 1 D. 3 9. If π€π€ varies directly as the square of π₯π₯ and inversely as ππ and ππ. If π€π€ = 12 when π₯π₯ = 4, ππ = 2 and ππ = 20, find π€π€ when π₯π₯ = 3, ππ = 8 and ππ = 5. A. 10 B. 9 C. 27 4 D. 5 10. The amount of gasoline used by a car varies jointly as the distance travelled and the square root of the speed. Suppose a car used 25 liters on a 100 km trip at 100 kph, about how many liters will it used on a 1000 km trip at 64 kph? A. 100 L B. 200 L C. 300 L https://forms.gle/zDWi33wEkwk8C1AE8 D. 400 L Lesson 2 Joint Variation and Combined Variation Let’s Recall Answer the following: 1. If ππ varies directly as ππ, give the equation of variation? 2. If ππ varies inversely as the square of ππ, and ππ = 6 when ππ = 3. Find ππ? 3. If ππ varies directly as the square of ππ, what is a when ππ = 4 and ππ = 3? 4. If ππ varies inversely as the cube of ππ, and ππ = 5 when ππ = 2, what is ππ when ππ = 4? 5. If ππ varies directly as the square of ππ, and ππ = 16 when ππ = 8 a. find ππ in terms of ππ. b. find ππ when ππ = 4. c. find ππ when ππ = 5. Let’s Explore Do these vehicles have the same tires? Why do you think tires vary from one vehicle to another? What do you think are the factors affecting the kind of tires used in a specific vehicle? The size of a tire and thickness of the rubber used consider the weight of the vehicle to balance and maximize its efficiency. The weight of the vehicle is said to varies jointly as the size of tires and thickness of the rubber in fabricating the wheels. Also, the terrain where the vehicle will primarily be used, among others are taken into consideration. Tire pressure also varies. The formula ππ = 0.25ππ π΄π΄ gives the recommended tire pressure for each tire for the total weight (ππ) of a vehicle and the area (π΄π΄) of the ground covered by tire. Notice that pressure varies directly as the weight of the vehicle and inversely as the area of the ground. The formula ππ = 0.25ππ π΄π΄ is an example of combined variation. Let’s Explain, Analyze & Solve Relationship between one variable over another variable were given emphasis in the previous discussion. Relationship could be directly or inversely proportional, but sometimes one variable may vary directly /or inversely with more than one variable. One variable may vary as the product of several variables (even if it is raised to a certain exponent). The variable is said to vary jointly as the others, thus the relation is called joint variation. In the equation, ππ = ππππππ, y is said to varies jointly as x and z, likewise in ππ = ππππππ 2 , a varies jointly as b and the square c. In the equation π²π² = π€π€π€π€ π³π³ , y is said to vary directly as x and inversely as z. Equation composed of both direct and inverse variation is called combined variation. Example 1: If y varies jointly as x and z, and π¦π¦ = 6 when π₯π₯ = 10 and π§π§ = 8, find y when π₯π₯ = 4 and π§π§ = 40. Solution: The equation is Solve for k π¦π¦ = ππππππ 6 = ππ(10)(8) 6 = 80ππ 6 = ππ 80 3 ππ = 40 The equation is Solve for y 3 π₯π₯π₯π₯ 40 3 π¦π¦ = (4)(40) 40 π¦π¦ = 12 π¦π¦ = To watch a video tutorial on Joint Variation by Teacher Justin (2020), visit this link https://youtu.be/w-HYWEpdsc Examples 2: The volume of a right cylinder varies jointly with the square of its radius and its height. When the radius is 2cm and the height is 6 cm, the volume is 75.36 ππππ3 . a. What is the constant of variation? b. What is the equation of variation? c. What is the volume if ππ = 3 ππππ and β = 5 ππππ? Solutions: ππ = ππππ 2 β 75.36 = ππ(2)2 (6) 75.36 = ππ 24 Volume varies jointly with the square of the radius and height 3.14 = ππ ππ = 3.14ππ 2 β ππ = 3.14(3)2 (5) ππ = 3.14(45) ππ = 141.3ππππ3 This is the constant of variation This is the equation of variation. If π¦π¦ = 3 ππππ and β = 5 ππππ, then the volume is 141.3ππππ3 To watch a video tutorial on Joint Variation and Word Problems by Highschoolreviewer (2019), visit this link https://youtu.be/ZdEudOOuU6I Example 3: If y varies directly as x and inversely as z. If π¦π¦ = 4 when π₯π₯ = 6 and π§π§ = 3, find y when π₯π₯ = 15 and π§π§ = 10. Solutions: ππππ π§π§ ππ(6) 4= 3 π¦π¦ = 12 = 6ππ 2 = ππ 2π₯π₯ π§π§ 2(15) π¦π¦ = 10 π¦π¦ = 3 π¦π¦ = Replace y with 4, x with 6, and z with 3 Cross multiply This is the constant of variation This is the equation of variation. To watch a video tutorial on Combined Variation by Teacher Justin(2020), visit this link https://youtu.be/QNpTNPO00A0 Let’s Dig In Activity 1. Write the equation for each of the following statements. 1. N varies directly as P and inversely as Q. 2. Y varies jointly as R and T. 3. B is directly proportional to the square of A and inversely proportional to the cube of C. 4. The area (A) of a triangle varies jointly as the base (b) and the height (h). 5. The time (t) required to dig a ditch of fixed width and depth varies directly as the length (l) of the ditch and inversely as the number of man (m) working on the job. 6. The volume (V) of a circular cone varies jointly as its height (h) and the square of the radius (r) of its base. 7. The pitch (P) of a stretched vibrating string varies directly as the square of the tension (T) and inversely as the length (l) of the string. 8. The pressure (P) of a gas varies jointly as its density (d) and its absolute temperature (t). 9. The volume (V) of right circular cylinder varies jointly as its height (h) and the square of the radius (r) of its circular base. 10. The current (I) varies directly as the electromotive force (F) and inversely as the resistance (R). Activity 2. Find the equation then solve for the missing value. 1. ππ varies directly as q and t, and ππ = 60 when ππ = 24 and π‘π‘ = 5. Find ππ when ππ = 12 and π‘π‘ = 4. 2. π£π£ varies directly as π€π€ and π’π’, and π£π£ = 28 when π€π€ = 8 and π’π’ = 7. Find π£π£ when π€π€ = 14 and π’π’ = 9. 3. Suppose π¦π¦ varies jointly as the square of π₯π₯ and π§π§, and π¦π¦ = 21 when π₯π₯ = 3 and π§π§ = 2 7. Find y when π₯π₯ = 6 and π§π§ = 3. 4. Suppose π¦π¦ varies jointly as π₯π₯ and the square of π§π§, and π¦π¦ = 4 when π₯π₯ = 50 and π§π§ = 2 . 5 Find y when π₯π₯ = 1 and 4 π§π§ = 4. 5. π¦π¦ varies directly as π₯π₯ and inversely as z, and π¦π¦ = 6 when π₯π₯ = 8 and π§π§ = 4. Find y when π₯π₯ = 12 and π§π§ = 9. 6. ππ varies directly as ππ and ππ, and ππ = 90 when ππ = 6 and ππ = 3. Find ππ when ππ = 1 4and ππ = 2. 7. ππ varies directly as ππ and inversely as ππ, and ππ = 5 when ππ = 2 and ππ = 4. Find a when ππ = 5 and ππ = 25. 8. ππ varies directly as ππ and inversely as ππ, and ππ = 8 when ππ = 1 and ππ = 1. Find ππ 3 4 when ππ = and ππ = 3. 2 4 9. ππ varies directly as ππ and inversely as ππ, and ππ = 6 when ππ = 12 and ππ = 0.5. Find 1 p when ππ = 8 and ππ = 3. 10. ππ varies directly as ππ and inversely as ππ and ππ = 5 when ππ = 3 and ππ = 1. Find m 4 5 when ππ = 9 and ππ = 6. Let’s Remember • In joint variation, one variable may vary directly or indirectly with more than one variable or the first variable is said to vary jointly as the others, if one variable varies as the product of several other variables (even if the variable is raised to a certain exponent). • Combined variation shows combination of direct and inverse variation. • In the equation, ππ = ππππππ, y is said to varies jointly as x and z, likewise in ππ = ππππππ 2 , a varies jointly as b and the square c. • In the equation π²π² = , y is said to vary directly as x and inversely as z. Equation π³π³ composed of both direct and inverse variation is called combined variation. π€π€π€π€ Let’s Apply Solve the following problems: 1. The weight of the rectangular block (ππ)of metal varies jointly as the length (ππ), the width (π€π€), and the thickness (β). If the weight of a 12 cm by 8 cm by 6 cm block of metal is 18 kg, find the weight of a 16 cm by 10 cm by 4 cm block of metal. 2. The wind force (πΉπΉ) on a flat surface varies jointly as the area of the surface (π΄π΄) and the square of the wind velocity (π£π£). If the pressure on 1ππππ 2 is 2 lbs, when the wind velocity is 20mi/hr, find the force of the wind storm on 10 ft by 12 ft signboard that has a velocity of 60 mi/hr. 3. The area of a rhombus (π΄π΄) varies jointly as the length of the two diagonals (ππ1 and ππ2 ). If a rhombus whose diagonals are 10 cm and 8 cm long has an area of 40 ππππ2 , find the area of the rhombus whose diagonals are 11 cm and 15 cm. 4. A simple interest (πΌπΌ) varies jointly with the amount of principal (ππ) and the length of time (π‘π‘). Suppose πΌπΌ = ππβππ 600 when ππ = ππβππ 10 000 and π‘π‘ = 2 π¦π¦π¦π¦π¦π¦, how much should be deposited to get an interest of β± 1 200 in a year? 5. If five carpenters can finish 30 tables in 2 days, how long will it take for 8 carpenters to finish 100 tables? Let’s Evaluate Directions: Read each question carefully and solve if necessary. Choose the letter of the correct answer and write it before the number. 1. If ππ varies directly as π π and inversely as π‘π‘. Find ππ when ππ = 40, π π = 5 and π‘π‘ = 6 A. 48 B. 40 C. 30 D. 8 2. The weight of a rectangular block of wood varies jointly as its length, width and thickness. If the weight of a 13 dm by 8 dm by 6 dm. block of wood is 26 kg, find the weight of 12 dm by 8 dm by 3 dm block of wood. A. 10 kg B. 12 kg C. 14 kg D. 16 kg 3. Translate to a mathematical sentence, if k is the constant of variation, “the volume ππ of a pyramid varies jointly as the area of the base π΅π΅ and altitude β”. A. ππ = πππ΅π΅2 β B. ππ = ππππβ C. ππ = ππππ β D. ππ 4. Find the value of the constant of variation if π¦π¦ varies jointly as ππ and ππ, and π¦π¦ = 256 when ππ = 8 and ππ = 4. A. 2 B. 4 C. 6 D. 8 5. In the equation π§π§ = ππππππ π¦π¦ , π¦π¦ ≠ 0, what varies inversely as π§π§? a. ππ b. π₯π₯ c. ππ 6. Express the statement “ ππ varies directly as π₯π₯ 3 and inversely as π¦π¦ 2 ”. a. ππ = π₯π₯ 3 π¦π¦ 2 b. ππ = πππ₯π₯ 3 π¦π¦ 2 c. ππ = πππ₯π₯ 3 π¦π¦ 2 = πππ΅π΅2 β d. π¦π¦ d. ππ = π₯π₯ 3 π¦π¦ 2 7. Suppose π§π§ varies directly as π¦π¦ and inversely as π₯π₯, and π§π§ = 12 when π₯π₯ = 8 and π¦π¦ = 24. What is a. 1 2 π₯π₯ π¦π¦ when π§π§ = 16? b. 1 c. 2 4 d. 4 8. The statement, π€π€ varies jointly as ππ and the square of ππ and inversely as ππ is an example of a. direct variation c. joint variation b. inverse variation d. combined variation 9. Which of the following is an equation of combined variation? A. π¦π¦ = 8π₯π₯ π§π§ B. π¦π¦ = 8 π₯π₯ C. π¦π¦ = 8π₯π₯π₯π₯ D. π¦π¦ = 8π₯π₯ 2 10. The current I varies directly as the electromotive force E and inversely as the resistance R. If a current of 30 ampere flows through a system with 16 ohms resistance and the electromotive force of 120 volts. Find the current that a 200 volt-electromotive force with the same resistance will send through the system. 8 A. 100 A B. 50 A C. 18 A D. A 25 https://forms.gle/BCvjHHf2vgy6BegZA References Nivera, Gladys C., et. al., GRADE 9 MATHEMATICS (Patterns and Practicalities), Salesiana Books, 2013 Orines, Fernando B., et. al., NEXT CENTURY MATHEMATICS (Intermediate Algebra), Phoenix Publishing House, 2003 Oronce, Orlando A., et. al., E-MATH 9 (Work text in Mathematics), Rex Book Store, 2015 Tesorio, Ma. Luisa V., MATHEMATICS 2 ( An Alternative Learning System – The Modular Approach) 2018 Edition, Tru-Copy Publishing House Inc., 2008 Yeo, Joseph, et. al, NEW SYLLABUS MATHEMATICS 9, Rex Book Store, 2017 MATHEMATICS GRADE 9, LEARNER’S MATERIAL, Department of Education, First Edition, 2014 Kahaarlytskyi, M., 2016. Toy car [image] Available at: < https:// https://unsplash.com/photos/ lDkAGfmHdeI> [Accessed 2 January 2021] Development Team of the Module Writer: JOSEPH C. LAGASCA Editors: Content Evaluators: JOEY N. ABERGOS AMELIA A. CANZANA ALMA J. CAPUS JENNIFER N. CONSTANTINO MARIO D. DE LA CRUZ JR. NAUMI G. LIGUTAN DONALYN S. MIÑA JULIUS PESPES Language Evaluator: MARICAR RAQUIZA Reviewers: DR. LELINDA H. DE VERA MIRASOL I. RONGAVILLA JENNICA ALEXIS B. SABADO DR. MELEDA POLITA Management Team: DR. MARGARITO B. MATERUM, SDS DR. GEORGE P. TIZON, SGOD-Chief DR. ELLERY G. QUINTIA, CID-Chief MRS. MIRASOL I. RONGAVILLA, EPS-Mathematics DR. DAISY L. MATAAC, EPS-LRMS / ALS For inquiries, please write or call: Schools Division of Taguig city and Pateros Upper Bicutan Taguig City Telefax: 8384251 Email Address: sdo.tapat@deped.gov.ph