Uploaded by Developer Cindy

HA1 - Veysel Azat Büyüktaş

advertisement
Vegsel
HAL
ETE 201
Aufgabel )
Beth
__
,
Really
a
In
,
-10in ,
5. In
Im
=
,
=
,
-101mn
-_
-1155m
=
28
5,6A
17050403ft
lnuertierte
-10 ,
Direction
15s
__
MI
Mi
:]
/
m-rs-%1E-I.FI
Me
15
15s
Biiyiietas
Aaat
60
"SIM
-20
f-
,
3.
5,6A
-
-10
-21^2--12=>9 In
'
ZIM ,
-131m ,
-_
-
h
-41m
,
,
-6*36
-16*2=-8
-
2Imz=
12
=
→
16,8-12=2 Imz
4,8--2 Ime
zh=In~=2hA=Im
1- Ia
GAIT In A-
1-
Ic=Ia+Ib
-
-_
=
3,2A
)
'
-
I
-
-
-
Avfgabe 2)
a)
Rab
?%r
A
a
c
Vegsel
HAL
ETE 201
R.h+Ry+R.R_
B
-
RL
Wenn
170504031W
I"
Isn
|•#
RER ;
a
mwandei
t
e
schal
t
.
n
o/
f
z
Rk#/
U
amyp-p
÷→
Thai -iñÉ;
.
.
at-1¥
HI
,,
¥PÉ^±
"
#④b
b)
Biiyiietas
ATp
µi¥¥%
1-1=-1
-1¥
-
Azat
a-yyn-i-IFY%r
.io ¥Ñ¥•%
"
=
Ue
"
It
2
ve
:
""
v.
✗
%
%
?⃝
Vegsel
HAL
ETE 201
Autgabe 3)
11,55£
"
(
<
§
""
AZIZA
<
"
%Aa.AM
F- }
✗
=
g-
a)
Ii
In
Um
I
-
Spanning
4017311
-_
,
-
Z
20++259-4=80
M3
V. i
=
40,73
.
/
-
g-
-
-
-
I
2,12A
4=1621924
,
,
4A
,
12,01
c) Quelle
+
17,97
-1
969,37
leistung-V.ie
Pa -1110 -1,551W
,
le
8
-
-
5.
l
=
i
von
pg
120
✗
4,555+1.412,125+20 (3,6711+14,88)^+715,57=514,634
211,75
-_
,
b)
2-
-
$
!
::÷:÷:¥÷÷:÷÷
7
25
-
,
M3
20
so
µ,
v14 )
5,55A
-32
µ,
air
17050403ft
the
it ,
2,12A
Biiyiietas
Azat
186
-1
Pa -1Pa ,
,
pqi-180.KZ/W1b9i6Pqg- (h.h0i73/WH492
3
3,53
-1
Pq
=
+
,
µ
514,03°
AUFGABE
Vegsel
HAL
ETE 201
4)
Azat
Biiyiietas
170504031W
Therein
-
¥-1
HE
IRTH-is-F-T-T-mit.ie
→
,
ks☒25r
=:#
.
g¥t_a
b
÷i¥¥t÷ *
Norton
-
Igoe
.
Kann Sein
" " 8.2°
11=364
:
611
•
$Ñ-f=b
-
vii. R
as
b
=
VTH=h_
.÷=lso=b
"
7- by
be
¥É;%s
Download