Vegsel HAL ETE 201 Aufgabel ) Beth __ , Really a In , -10in , 5. In Im = , = , -101mn -_ -1155m = 28 5,6A 17050403ft lnuertierte -10 , Direction 15s __ MI Mi :] / m-rs-%1E-I.FI Me 15 15s Biiyiietas Aaat 60 "SIM -20 f- , 3. 5,6A - -10 -21^2--12=>9 In ' ZIM , -131m , -_ - h -41m , , -6*36 -16*2=-8 - 2Imz= 12 = → 16,8-12=2 Imz 4,8--2 Ime zh=In~=2hA=Im 1- Ia GAIT In A- 1- Ic=Ia+Ib - -_ = 3,2A ) ' - I - - - Avfgabe 2) a) Rab ?%r A a c Vegsel HAL ETE 201 R.h+Ry+R.R_ B - RL Wenn 170504031W I" Isn |•# RER ; a mwandei t e schal t . n o/ f z Rk#/ U amyp-p ÷→ Thai -iñÉ; . . at-1¥ HI ,, ¥PÉ^± " #④b b) Biiyiietas ATp µi¥¥% 1-1=-1 -1¥ - Azat a-yyn-i-IFY%r .io ¥Ñ¥•% " = Ue " It 2 ve : "" v. ✗ % % ?⃝ Vegsel HAL ETE 201 Autgabe 3) 11,55£ " ( < § "" AZIZA < " %Aa.AM F- } ✗ = g- a) Ii In Um I - Spanning 4017311 -_ , - Z 20++259-4=80 M3 V. i = 40,73 . / - g- - - - I 2,12A 4=1621924 , , 4A , 12,01 c) Quelle + 17,97 -1 969,37 leistung-V.ie Pa -1110 -1,551W , le 8 - - 5. l = i von pg 120 ✗ 4,555+1.412,125+20 (3,6711+14,88)^+715,57=514,634 211,75 -_ , b) 2- - $ ! ::÷:÷:¥÷÷:÷÷ 7 25 - , M3 20 so µ, v14 ) 5,55A -32 µ, air 17050403ft the it , 2,12A Biiyiietas Azat 186 -1 Pa -1Pa , , pqi-180.KZ/W1b9i6Pqg- (h.h0i73/WH492 3 3,53 -1 Pq = + , µ 514,03° AUFGABE Vegsel HAL ETE 201 4) Azat Biiyiietas 170504031W Therein - ¥-1 HE IRTH-is-F-T-T-mit.ie → , ks☒25r =:# . g¥t_a b ÷i¥¥t÷ * Norton - Igoe . Kann Sein " " 8.2° 11=364 : 611 • $Ñ-f=b - vii. R as b = VTH=h_ .÷=lso=b " 7- by be ¥É;%s