5th Year Maths Higher Level Kieran Mills Algebraic Expressions No part of this publication may be copied, reproduced or transmitted in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without prior written permission from The Dublin School of Grinds. Ref: 5/maths/h/lc/Algebraic Expressions notes EASTER REVISION COURSES Looking to maximise your CAO points? Easter is a crucial time for students to vastly improve on the points that they received in their mock exams. To help students take advantage of this valuable time, The Dublin School of Grinds is running intensive, examfocused Easter Revision Courses. Each course runs for five days (90 minutes per day). All courses take place in Stillorgan, Co. Dublin. The focus of these courses is to maximise students’ CAO points. EASTER REVISION COURSE FEES: 6TH YEAR & 5TH YEAR COURSES PRICE TOTAL SAVINGS 1st Course €295 €295 - 2nd Course €180 €475 €115 3rd Course FREE €475 €410 4th Course €70 €545 €635 5th Course €100 €645 €830 6th Course €100 €745 €1,025 7th Course €100 €845 €1,220 8th Course €50 €895 €1,465 9th Course €50 €945 €1,710 3RD YEAR COURSES PRICE TOTAL SAVINGS SPECIAL OFFER 1st Course €195 €195 - 2nd Course €100 €295 €95 To avail of this offer, early booking is required as courses were fully booked last year. 3rd Course FREE €295 €290 4th Course €85 €380 €400 5th Course €50 €430 €545 6th Course €50 €480 €690 7th Course €50 €530 €835 8th Course €50 €580 €980 BUY 2 COURSES GET A 3 RD COURSE FREE What do students get at these courses? 99 90 minutes of intensive tuition per day for five days, with Ireland’s leading teachers. 99 Comprehensive study notes. 99 A focus on simple shortcuts to raise students’ grades and exploit the critically important marking scheme. 99 Access to a free supervised study room. NOTE: These courses are built on the fact that there are certain predicable trends that reappear over and over again in the State Examinations. DSOG Easter 2017 8pg A4 FINAL PRINT.indd 2 25% SIBLING DISCOUNT AVAILABLE. Please call 01 442 4442 to avail of this discount. FREE DAILY BUS SERVICE For full information on our Easter bus service, see 3 pages ahead. Access to food and beverage facilities is also available to students. To book, call us on 01 442 4442 or book online at www.dublinschoolofgrinds.ie 20/02/2017 13:25 Timetable An extensive range of course options are available over a two-week period to cater for students’ timetable needs. Courses are held over the following weeks: » Monday 10th – Friday 14th April 2017 » Monday 17th – Friday 21st April 2017 All Easter Revision Courses take place in The Talbot Hotel, Stillorgan (formerly known as The Stillorgan Park Hotel). 6th Year Easter Revision Courses DATES 5th Year Easter Revision Courses SUBJECT LEVEL TIME SUBJECT LEVEL Accounting H Monday 10th - Friday 14th April 12:00pm - 1:30pm DATES TIME English H Monday 10th - Friday 14th April 12:00pm - 1:30pm Agricultural Science H Monday 10th - Friday 14th April 10:00am - 11:30am Maths H Monday 10th - Friday 14th April 10:00am - 11:30am Applied Maths H Monday 10th - Friday 14th April 8:00am - 9:30am Art History H Monday 10th - Friday 14th April 2:00pm - 3:30pm Note: 4th Year students are welcome to attend any of the 5th Year courses listed above. Biology Course A* H Monday 10th - Friday 14th April 8:00am - 9:30am Biology Course A* H Monday 17th - Friday 21st April 10:00am - 11:30am Biology Course B* H Monday 10th - Friday 14th April 10:00am - 11:30am Biology Course B* H Monday 17th - Friday 21st April Business H Monday 10th - Friday 14th April Business H Monday 17th - Friday 21st April Chemistry Course A* H Chemistry Course B* 3rd Year Easter Revision Courses SUBJECT LEVEL 8:00am - 9:30am Business Studies H Monday 17th - Friday 21st April 2:00pm - 3:30pm 12:00pm - 1:30pm English H Monday 10th - Friday 14th April 10:00am - 11:30am 8:00am - 9:30am English H Monday 17th - Friday 21st April 12:00pm - 1:30pm Monday 17th - Friday 21st April 8:00am - 9:30am French H Monday 17th - Friday 21st April 12:00pm - 1:30pm H Monday 17th - Friday 21st April 10:00am - 11:30am Geography H Monday 17th - Friday 21st April 8:00am - 9:30am Classical Studies H Monday 10th - Friday 14th April 2:00pm - 3:30pm German H Monday 17th - Friday 21st April 2:00pm - 3:30pm Economics H Monday 10th - Friday 14th April 8:00am - 9:30am History H Monday 10th - Friday 14th April 8:00am - 9:30am Economics H Monday 17th - Friday 21st April 10:00am - 11:30am Irish H Monday 10th - Friday 14th April 12:00pm - 1:30pm English Paper 1* H Monday 17th - Friday 21st April 8:00am - 9:30am Maths H Monday 10th - Friday 14th April 8:00am - 9:30am English Paper 2* H Monday 10th - Friday 14th April 8:00am - 9:30am Maths H Monday 17th - Friday 21st April 10:00am - 11:30am English Paper 2* H Monday 17th - Friday 21st April 10:00am - 11:30am Maths O Monday 10th - Friday 14th April 2:00pm - 3:30pm French H Monday 10th - Friday 14th April 10:00am - 11:30am Science H Monday 10th - Friday 14th April 12:00pm - 1:30pm French H Monday 17th - Friday 21st April 8:00am - 9:30am Science H Monday 17th - Friday 21st April 8:00am - 9:30am Geography H Monday 10th - Friday 14th April 8:00am - 9:30am Spanish H Monday 10th - Friday 14th April 2:00pm - 3:30pm Geography H Monday 10th - Friday 14th April 2:00pm - 3:30pm German H Monday 17th - Friday 21st April 12:00pm - 1:30pm Note: 2nd Year students are welcome to attend any of the 3rd Year courses above. History (Europe)* H Monday 17th - Friday 21st April 2:00pm - 3:30pm History (Ireland)* H Monday 17th - Friday 21st April 12:00pm - 1:30pm Home Economics H Monday 10th - Friday 14th April 12:00pm - 1:30pm Irish H Monday 10th - Friday 14th April 10:00am - 11:30am Irish H Monday 17th - Friday 21st April 12:00pm - 1:30pm Maths Paper 1* H Monday 10th - Friday 14th April 8:00am - 9:30am Maths Paper 1* H Monday 10th - Friday 14th April 12:00pm - 1:30pm Maths Paper 1* H Monday 17th - Friday 21st April 8:00am - 9:30am Maths Paper 2* H Monday 10th - Friday 14th April 10:00am - 11:30am SUBJECT Maths Paper 2* H Monday 17th - Friday 21st April 10:00am - 11:30am French H Sunday 12th March 9:00am - 1:00pm Maths Paper 2* H Monday 17th - Friday 21st April 12:00pm - 1:30pm German H Saturday 11th March 9:00am - 1:00pm Maths O Monday 10th - Friday 14th April 10:00am - 11:30am Irish H Sunday 19th March 9:00am - 1:00pm Maths O Monday 17th - Friday 21st April 12:00pm - 1:30pm Spanish H Saturday 11th March 2:00pm - 6:00pm Physics H Monday 17th - Friday 21st April 10:00am - 11:30am Spanish H Monday 10th - Friday 14th April 12:00pm - 1:30pm Spanish H Monday 17th - Friday 21st April 10:00am - 11:30am Note: 5th Year students are welcome to attend any of the 6th Year courses above. * Due to large course content, these subjects have been divided into two courses. For a full list of topics covered in these courses, please see 3 pages ahead. To book, call us on 01 442 4442 or book online at www.dublinschoolofgrinds.ie DSOG Easter 2017 8pg A4 FINAL PRINT.indd 3 DATES TIME 6th Year Oral Preparation Courses With the Oral marking component worth up to 40%, it is of paramount importance that students are fully prepared for these examinations. These courses will show students how to lead the Examiner towards topics they are prepared for. This will equip students with the information they need to maximise their performance in the State Examinations. FEES: €140 VENUE: The Talbot Hotel, Stillorgan (formerly The Stillorgan Park Hotel) LEVEL DATES TIME BUY 2 COURSES & GET A 3RD COURSE FREE! 20/02/2017 13:25 Section 2: Algebraic Expressions Paper 1 Topics Section 1. Number Section 2. Algebraic expressions Section 3. Algebraic equations Section 4. Sequences and Series Section 5. Financial Maths Section 6. Complex Numbers Section 7. Functions Section 8. Differentiation Section 9. Integration Section 10: Proof by Induction Paper 2 Topics Section 1. Geometry Section 2. Measurement Section 3. Trigonometry Section 4. Co-ordinate Geometry Section 5. Probability Section 6. Statistics Contents Chapter 3: Working with Algebraic Expressions...............................2 Chapter 4: Polynomial and Rational Expressions..............................18 Chapter 5: Exponentials and Logs.....................................................29 Exercises.............................................................................................39 Answers.................................................................................................58 Leaving Certificate Exam questions (All the algebra questions are at the end of Section 3) ©The Dublin School of Grinds Page 1 Mills & Kelly (Power of Maths) Chapter 3. Working with Algebraic Expressions 1. Algebraic Basics Some important key terms: 3x2 - 2xy + 5 is an expression. 3x2, 2xy and 5 are terms. This expression has three terms. x and y are variables. x and y can take on different values. In the term 3x2, 3 is the coefficient of the term. In the term 2xy, 2 is the coefficient of the term. 5 is a constant. Example 1: Write down the number of terms, the coefficient of a given term and the constant term in the following algebraic expressions: Solution Number of terms Coefficient (a) 4 + x2 + 4xy xy (b) 3x2y + 5xy - 3 x2y (c) 4ab - 3a2b + 5a3b2 - 5 a2b x2 (d) x3 - 2x2 + 3x 2. Constant Combining like terms Some important points: 1. The order in which you multiply two numbers does not matter. x × y = y × x = xy = yx The big 3 and the little 3: Write out in long hand: 3×2= = 23 = = 2. The coefficient in front of the variable tells you how many times you add the variable to itself. 3x = x + x + x 5x2 = x2 + x2 + x2 + x2 + x2 ©The Dublin School of Grinds Page 2 Mills & Kelly (Power of Maths) 3. Combining powers: The little number (power) tells you how many times you multiply a number by itself. x3 = x × x × x x2 × x3 = x × x × x × x × x = x5 = x2 + 3 ap × aq = ap + q Example 2: Multiply the following terms together to produce a single term Solution (a) 4x × 5y = (b) 5ab × 4ab = (c) (-2xy)(-5x) = (d) x2 × x4 = (e) 3xy3 × -4x2y = You only add like terms. 2x + 3x = x + x + x + x + x = 5x [2 terms are combined into 1 term] 2a2b + 5a2b - ba2 = 6a2b [3 terms are combined into 1 term] But 2x + 3y = 2x + 3y [2 terms remain as 2 terms] Example 3: Simplify the following. Solution (a) 2a + 3a + 5a = (b) 4x - 5x - 7x = (c) 4x + 3y + 2y - 10x = (d) 4(a - 2b) - 3(b - 3a) = = (e) 3x2y + 4x2y - 11yx2 = You can only add like terms. Unlike terms can be multiplied. 4ab + 2ab2 = 4ab × 2ab2 = ©The Dublin School of Grinds Page 3 Mills & Kelly (Power of Maths) 3. Multiplying out Brackets (2 x + 3 y )(2 x − y ) = 2 x(2 x − y ) + 3 y (2 x − y ) = 4 x 2 − 2 xy + 6 yx − 3 y 2 = 4 x 2 − 2 xy + 6 xy − 3 y 2 = 4 x 2 + 4 xy − 3 y 2 ∴ (2x + 3y)(2x - y) = 4x2 + 4xy - 3y2 (2x + 3y) and (2x - y) multiply together to give 4x2 + 4xy - 3y2. (2x + 3y) and (2x - y) are called the factors of 4x2 + 4xy - 3y2. Example 4: Expand the following. Solution (a) (2a + 3b)(2c + d) Number of terms: (b) (2a + 3b)(a - 2b) Number of terms: Trinomial (c) (2a + 3b)(2a - 3b) Number of terms: Difference of 2 squares Special situations 1. Difference of two squares: (Difference of two terms) × (Sum of the same two terms) (2 x − 5 y )(2 x + 5 y ) = 2 x(2 x + 5 y ) − 5 y (2 x + 5 y ) = 4 x 2 + 10 xy − 10 xy − 25 y 2 = 4 x 2 − 25 y 2 = (2 x) 2 − (5 y ) 2 Remember as: (First - Second)(First + Second) = (First)2 - (Second)2 ©The Dublin School of Grinds Page 4 Mills & Kelly (Power of Maths) Example 5: Expand the following. Solution (a) (3x + y)(3x - y) 2. (b) (5x + 3y)(5x - 3y) (c) (ax + by)(ax - by) Perfect square: Consists of two identical brackets. (3 x − 2 y ) 2 = (3 x − 2 y )(3 x − 2 y ) = 3 x(3 x − 2 y ) − 2 y (3 x − 2 y ) = 9 x 2 − 6 xy − 6 xy + 4 y 2 = 9 x 2 − 12 xy + 4 y 2 = (3 x) 2 + 2(3 x)(−2 y ) + (−2 y ) 2 Remember as: (First term + Second term)2 = (First term)2 + 2(First term)(Second term) + (Second term)2 Example 6: Expand the following. Solution (a) (3x + y)2 (b) (3x - 4y)2 (c) (ax + by)2 ©The Dublin School of Grinds Page 5 Mills & Kelly (Power of Maths) 3. Harder multiplication Example 7: Expand the following. Solution (a) (x - 1)(2x + 3)(x + 1) (b) (x - 2)3 4. Finding the value of an algebraic expression To find the value of an algebraic expression, simply fill in the given value(s) of the varible(s). Example 8: Evaluate 4x2y - 2xy2 + 5xy - 7, if x = 2 and y = -3. Solution For you to practice Exercise 1: page 39 ©The Dublin School of Grinds Page 6 Mills & Kelly (Power of Maths) 2. Binomial Theorem An expression with two terms is called a binomial. The binomial theorem is a quick way to multiply out (expand) binomials raised to a power. Examples: (x + y)6, (2a - b)10 How nCr is calculated 1. Factorials Factorials are represented by ! Example: 4! = 4 × 3 × 2 × 1 = 24 Doing factorials on the calculator: Casio fx-83GT PLUS Example: 4! Press 4 Press SHIFT x-1 (This is x!) Press = Calculate the following manually and then check the answers on your calculator: 5! = = 6! = = 1! = Write out: n! = Combinations We will deal with combinations (C) or selections in greater detail when we do the section on Probability. n Cr = n! r !(n - r )! Formula and Tables Book: Page 20 (Algebra) Example: How many way can you select two people from 10 people when forming a committee? n Cr gives you the answer where n = 10, r = 2. C2 = 10 C2 = 6 C3 = 9 10 ! 10 ! 10×9×8× 7 × 6×5× 4×3× 2×1 10×9 = = = = 45 2 !(10 - 2)! 2 ! × 8! 2×1×8× 7 × 6×5× 4×3× 2×1 2×1 6×5 = 3×5 = 15 2×1 = ©The Dublin School of Grinds = Page 7 Mills & Kelly (Power of Maths) C4 = = 10 C3 = = 12 = = Doing combinations on the calculator: Casio fx-83GT PLUS Example: 12C3 Press 12 Press SHIFT ÷ (This is nCr) Press 3 Press = n Alternative way of writing combinations: nCr = r 2. Using the Binomial Formula and Tables Book: Page 20 (Algebra) n n n n n ( x + y ) n = x n + x n-1 y + x n-2 y 2 + ... + x n-r y r + ... + y n 0 1 2 r n Example 9: Expand (x + y)5. Solution Handy coefficients Coefficients of (x + y)2: 1, 2, 1 Coefficients of (x + y)3: 1, 3, 3, 1 Coefficients of (x + y)4: 1, 4, 6, 4, 1 Coefficients of (x + y)5: ©The Dublin School of Grinds Page 8 Mills & Kelly (Power of Maths) Example 10: Expand (2a - b)4. Solution Example 11: Expand (3x + 2y)3. Solution 3. Picking out terms General term: (r + 1)st term is nCr (x)n - r (y)r Example: The fifth term in (p – q)7 has a binomial coefficient of 7C4. Fifth term = 7C4 (p)3(–q)4 = 35p3q4 Example: The fourth term in (2x + y)8 has a binomial coefficient of 8C3. Fourth term = 8C3(2x)5(y)3 = 56(32x5)y3 = 1792x5y3 ©The Dublin School of Grinds Page 9 Mills & Kelly (Power of Maths) Example 12: In the expansion of (p + q)7, what is the term with q5? Solution Example 13: What is the term with a4 in the expansion of (a − 2b)9? Solution 2 x + y , what is the term with y3? 4 5 Example 14: In Solution For you to practice Exercise 2: page 40 ©The Dublin School of Grinds Page 10 Mills & Kelly (Power of Maths) 3. Factorisation 1. Factorisation technique 1: HCF Factorise the following by taking out the highest common factor: 5x + 10y + 15 = 5x2y2 − 10xy = 7x(x − 2y) − 3y(x − 2y) = 2. Factorisation technique 2: Grouping Example 15: Factorise ax - bx + ay - by by grouping. Solution Example 16: Factorise 3x - 8y - 2 + 12xy by grouping. Solution Example 17: Factorise ax - bx - ay + by + a - b by grouping. Solution ©The Dublin School of Grinds Page 11 Mills & Kelly (Power of Maths) 3. Factorisation technique 3: Trinomials Example 18: Factorise 2x2 - 5x - 12. Solution Rough work Rough work ( )( ) Example 19: Factorise 4x2 - 13x - 12. Solution Rough work Rough work ( ©The Dublin School of Grinds )( Page 12 ) Mills & Kelly (Power of Maths) 4. Factorisation technique 4: Difference of two squares a2 - b2 = (a - b)(a + b) Remember as: (First)2 – (Second)2 = (First – Second)(First + Second) 25 x 2 - 4 y 2 = (5 x) 2 - (2 y ) 2 = (5 x - 2 y )(5 x + 2 y ) 400 x 2 - 49 y 2 = = x 2 - a 2b 2 = = Example 20: Factorise (x + y)2 - z2. Solution 5. Factorisation technique 5: Difference and Sum of two cubes a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2) Remember as: (First)3 + (Second)3 = (First + Second)((First)2 – (First) × (Second) + (Second)2) (First)3 – (Second)3 = (First – Second)((First)2 + (First) × (Second) + (Second)2) x3 + 8 y 3 = ( x)3 + (2 y )3 = ( x + 2 y )( x 2 - 2 xy + 4 y 2 ) 8 x3 - 27 = = 125 x3 - 64a 3b3 = = ©The Dublin School of Grinds Page 13 Mills & Kelly (Power of Maths) Example 21: Factorise (a - 1)3 + (a + 1)3. Solution 6. Factorisation technique 6: Harder factors Example 22: Factorise x2 + 2xy + y2 - 1. Solution Example 23: Factorise 9a2 - 12ab + 4b2 - 25c2. Solution ©The Dublin School of Grinds Page 14 Mills & Kelly (Power of Maths) Example 24: Factorise the following fully: (a) 1 − 3x − 4x2 (b) 7x2 − 28y2 2 (d) 154x − 50x + 4 (e) (x + 2y)2 − (x – 2y)2 Solution (c) 2a2 + 6ac − 4ab − 12bc (f) 15a3 + 120a3b3 For you to practice Exercise 3: page 41 ©The Dublin School of Grinds Page 15 Mills & Kelly (Power of Maths) 4. Algebraic Modelling Algebraic modelling means translating a problem, stated in words, into an algebraic expression. Guidelines for modelling 1. 2. 3. 4. Identify the quantity to be modelled (cost, price, area, length, etc.) and give it a symbol. Draw a diagram if appropriate (unless given). Identify the number of variables (one or more) and if appropriate put them on the diagram. Write the quantity to be modelled in terms of this (these) variable(s). Example 25: The breadth of a rectangular field is 20 m longer than its length x. Write down an expression, in terms of x, for: (a) the breadth b, (b) the perimeter P, (c) the area A. Solution Example 26: A running track has two straights and two semicircular ends. If x m is the length of each straight and y m the radius of each semicircular end, (a) find an expression in terms of x and y for: (i) the perimeter P, (ii) the area A1 of the rectangular region ABCD, (iii) the total area A2. (b) If x = 100 m and y = 31∙85 m, find the perimeter to the nearest metre. (c) If a runner has an average speed of 30 km/h, how long does it take the runner to complete one full circuit of the track? xm Straight ym Semicircle ym s A ©The Dublin School of Grinds C ym Semicircle D s ym Straight xm Page 16 B Mills & Kelly (Power of Maths) Solution For you to practice Exercise 4: page 43 ©The Dublin School of Grinds Page 17 Mills & Kelly (Power of Maths) Chapter 4: Polynomial and Rational Expressions 1. Polynomial Expressions Types 1. Linear expressions Examples: 2x, 2x + 3 In general: ax + b (Standard form) 2. Quadratic Expressions Examples: x2, x2 + 1, 2x2 - 3x + 2 In general: ax2 + bx + c (Standard form) 3. Cubic expressions Examples: x3, 3x3 + 1, 3x3 + 2x2 + 3x + 1 In general: ax3 + bx2 + cx + d (Standard form) Example 1: State what type of expression is shown and write each expression in standard form. Solution Type of polynomial Standard Form (a) 2 - 2x (b) x3 + 3 - 2x (c) 1 - x2 (d) 3x3 + 3x - 2 + x2 Linear × Linear = Quadratic Example 2: Multiply (2x + 1)(3x - 5) writing your answer in standard form. Solution First × First = First: × = Last × Last = Last: × = ©The Dublin School of Grinds Page 18 Mills & Kelly (Power of Maths) Linear × Quadratic = Cubic Example 3: Multiply (3x + 1)(4x2 - 2x - 5) writing your answer in standard form. Solution First × First = First: × = Last × Last = Last: × = Linear × Linear × Linear = Cubic Example 4: Multiply (5x + 1)(3x - 2)(x - 1) writing your answer in standard form. Solution First × First × First = First: × × = Last × Last × Last = Last: × × = ©The Dublin School of Grinds Page 19 Mills & Kelly (Power of Maths) Example 5: Multiply out the following writing your answer in standard form. (a) (-3x + k)(4x + l) (b) (2x2 - kx + 3)(x + l) Solution 2. Identities (x - 3)(x - 2) = x2 - 5x + 6 When you multiply out the two brackets on the left you get an identical expression on the right. This is an identity. Identities are true for all values of the variable x. LHS RHS (x - 3)(x - 2) (1 - 3)(1 - 2) = (-2)(-1) =2 x2 - 5x + 6 (1)2 - 5(1) + 6 =1-5+6 =2 Be clever. Try x = 3: (3 - 3)(3 - 2) = (0)(1) =0 (3)2 - 5(3) + 6 = 9 - 15 + 6 =0 Be clever. Try x = 2: (2 - 3)(2 - 2) = (-1)(0) =0 (2)2 - 5(2) + 6 = 4 - 10 + 6 =0 Try x = 1: ©The Dublin School of Grinds Page 20 Mills & Kelly (Power of Maths) Example 6: If 10x2 - 9x + 2 = (5x - k)(2x - 1), find k. Solution Example 7: If x3 + 2x2 + kx + 2 = (x - 1)(x2 + ax - 2), find k and a. Solution Method 1 (Lining up) Method 2 (Choosing values) ©The Dublin School of Grinds Page 21 Mills & Kelly (Power of Maths) Example 8: If 3x2 + 5x - 1 is a factor of 3x3 + 11x2 + 9x - 2, find the other factor. Solution Example 9: If 2x - 1 and x + 2 are factors of 6x3 + x2 - 18x + 8, find the other factor. Solution Example 10: If 3x + 2 is a factor of 9x3 - 19x - 10, find the quadratic factor. Solution ©The Dublin School of Grinds Page 22 Mills & Kelly (Power of Maths) Example 11: If x2 + px - q is a factor of 2x3 + px2 - 3x + q2, find the values of p and q. Solution Example 12: If (2x - 1) is a factor of 2x3 + ax2 - bx + 1, show that a = (2b - 5). Solution ©The Dublin School of Grinds Page 23 Mills & Kelly (Power of Maths) Example 13: If 2x2 + bx - 5 is a factor of 2x3 - x2 + kx + 10, find the other factor and b and k. Solution Example 14: ax2 + 2 is a factor of 18x3 + kx2 + 6x - 2. Find k and a and the other factor. Solution ©The Dublin School of Grinds Page 24 Mills & Kelly (Power of Maths) Example 15: If (x - p)2 is a factor of x3 + qx + r, show: (i) r = 2p3, (ii) q = -3p2. Solution Example 16: If x2 - px + 1 is a factor of ax3 + bx + c, show c2 = a(a - b). Solution For you to practice Exercise 5: page 45 ©The Dublin School of Grinds Page 25 Mills & Kelly (Power of Maths) 3. Division of polynomials Cubic Cubic Quadratic = Linear , = Quadratic, = Linear Quadratic Linear Linear Always factorise first if you can. x3 - 8 x 3 - 23 ( x - 2)( x 2 + 2 x + 4) = = = x2 + 2 x + 4 ( x - 2) ( x - 2) x-2 x3 + x 2 = x +1 = 15 x 2 + 11x -14 = 3x - 2 16 x3 - 28 x 2 + 6 x = 8x - 2 = = = 3 2 Example 17: Simplify 4 x - 4 x - x + 1 . 2 x +1 Solution For you to practice Exercise 6: page 46 ©The Dublin School of Grinds Page 26 Mills & Kelly (Power of Maths) 4. Rational Expressions A rational expression is one expression divided by another. Addition and subtraction Technique for adding and subtracting rationals Find the lowest common denominator (LCD) 1 1 xy + 1 + 2 = 2 x x y x y 3 2 4 7 + , (b) 2 - 2 . Example 18: Simplify (a) x -5 5- x x -1 2 x - 3 x - 5 Solution Multiplication Technique for multiplying rationals Multiply the tops and multiply the bottoms and/or cancel. -3ab 2 15b 2 c 2 ab 4 c 2 c × = = 5b3c -9a 2b a 2b 4 c a ©The Dublin School of Grinds Page 27 Mills & Kelly (Power of Maths) a 2 - b2 ab Example 19: Simplify (a) × , (b) 2 + ab a a b Solution 2 x3 x 4 + - . x 2 2 x3 Division (Double-decker fractions) Technique for multiplying rationals Multiply above and below by the LCD of all fractions. 9 7 10 + - 2 x x . Example 20: Simplify 3 2 2+ - 2 x x Solution For you to practice Exercise 7: page 47 ©The Dublin School of Grinds Page 28 Mills & Kelly (Power of Maths) Chapter 5: Exponentials and Logs Exponential Expressions (powers) 1. An exponential expression can be written in the form ap where p ∈ . a is called the base of the expression. p is called the power, the index or the exponent of the expression. 1. The multiplication rule Formula and Tables Book: Page 21 (Indices and logs) Remember as: When you multiply two exponential expressions with the same base, you add the powers. Rule 1: ap × aq = ap + q x3 × x5 = e x+3 × e 2 x+1 = 2 x 6 × 3 x -3 = (a + 2b)3 × (a + 2b) 4 = 2. The division rule Rule 2: ap = a p -q aq Formula and Tables Book: Page 21 (Indices and logs) Remember as: When you divide two exponential expressions with the same base, you subtract the power on the bottom from the power on the top. x9 = x4 67 = 65 e 2 x-1 = e x+2 y5 = y-2 = 3. The one rule Rule 3: a0 = 1 20 = Formula and Tables Book: Page 21 (Indices and logs) (a + 2b)0 = x = 2 y 2 0 4. The power of a power rule Formula and Tables Book: Page 21 (Indices and logs) Remember as: When you put an exponential expression to a power, you multiply the two powers. Rule 4: (ap)q = apq ( 65 ) 3 = ( x3 )2 = ( e x -2 ) 4 = ©The Dublin School of Grinds Page 29 Mills & Kelly (Power of Maths) 5. Powers of products and quotients p Formula and Tables Book: Page 21 (Indices and logs) a ap Rule 5: (ab) p = a p b p and = p b b xy = 2 z 5 (2ab 2 ) 4 = a 2 = b 4 6. Negative powers -p Rule 6: a = 3-2 = 1 1 and - p = a p p a a 3 x -2 = zy-3 = 1 = x -3 4-1 = 52 Formula and Tables Book: Page 21 (Indices and logs) ( xy )-3 = = ( ) = -p a The flipping trick: b -2 3 - = 4 -3 3 x = 2 2 y b = a = p = = 7. Non-whole number powers 1 q q Rule 7: a = a Formula and Tables Book: Page 21 (Indices and logs) p 4 = 1 27 3 = -1 4 16 1 1 Other fractional powers: a q = (a p ) q = (a q ) p 1 2 = 2 83 = = ©The Dublin School of Grinds 3 16 4 = Page 30 = = = = Mills & Kelly (Power of Maths) -2 3 8 Example 21: Simplify (a ) - 1 4 2 Solution Example 22: Simplify 1 (-5) 2 × 25 2 , ( b ) -3 . 5 × (25)3 (e x ) 2 × (e 2 x-1 )-2 Solution e 4 x -2 × (e x +1 -3 , giving your answer in the form eax + b. ) Example 23: The population P of yeast cells after t hours is given by P = 106 × ( 2 )t . t (a) Show that P = 106 × 2 2. (b) Find the population P1 after n hours. (c) Find the population P2 after (n + 2) hours. (d) Find the percentage change in population from n hours to (n + 2) hours. Solution Cont... ©The Dublin School of Grinds Page 31 Mills & Kelly (Power of Maths) For you to practice Exercise 8: page 48 Surds 2. A surd expression is an expression involving square roots of variable(s) or numbers that cannot be simplified into a rational expression. Examples of surds: 2 , x , x -1 1 a = a2 Simplifying surds Use the following results: ab = a b and Simplify the following surds: 45 = × = 50 = × = 28 = × = × 16 - 4 x = 2 14 = a a = b b = = = = ©The Dublin School of Grinds Page 32 Mills & Kelly (Power of Maths) Adding and subtracting surds Add and subtract like terms only: 5 2 + 3 2 = 8 2 Write in their simplest form: 3+ 5 + 6-2 5 +5 5 = + 2 5 + 45 - 3 20 = 2 x + x3 = + - + x2 × x = = + = ( ) Multiplying surds Write in their simplest form: 2( 3 + 5 2 ) = x ( x + 3) = = (3 + 2 )(4 - 5 2 ) = = = ( 3 + 2 )2 = = ( x + y )2 = ( a + b )( a - b ) = = ( a - b ) is the conjugate surd of ( a + b ). Important result: ( a + b )( a - b ) = ( a ) 2 - ( b ) 2 = a - b ( n + 1 - n )( n + 1 + n ) = = ©The Dublin School of Grinds = Page 33 Mills & Kelly (Power of Maths) Division When you divide surds, the answer should never have a surd in the denominator. This process of getting rid of surds on the bottom is called rationalising the denominator. Write in their simplest form: 5 5 = × 2 2 = 3 3 = × 2 2 = 4+ 3 4+ 3 = × 2 2 = Example 24: Rationalise the denominators of the following: x+ y 5 (a ) , ( b) . x- y 3- 2 Solution For you to practice Exercise 9: page 50 ©The Dublin School of Grinds Page 34 Mills & Kelly (Power of Maths) Logs 3. A log is just another way to write a power. 2? = 8 ⇒ 23 = 8 or log 2 8 = ? ⇒ log 2 8 = ? 2 is the base. log 8 to base 2 equals 3. In general, loga x is the power to which you must put the base a to get x. log 3 9 = , log 3 27 = , log 2 16 = , log 4 1 = , log 4 4 = Escaping from logs (Hooshing) log a y = x ⇔ y = a x log 2 16 = 4 ⇔ 16 = 24 log10 100 = 2 ⇔ = log 4 16 = 2 ⇔ log 4 1 = 0 ⇔ log 4 4 = 1 ⇔ = = log 5 125 = 3 ⇔ = log 2 12 = -1 ⇔ = = Log Rules 1. The addition rule Rule 1: log a x + log a y = log a ( xy ) Tip: You can only add logs with the same base when applying this rule. log 4 6 + log 4 12 + log 4 5 = log 4 ( ) = log 4 log a x 2 + log a y + log a 2 = log a ( ) = log a 2. The subtraction rule x Rule 2: log a x - log a y = log a y Tip: You can only subtract logs with the same base when applying this rule. log 6 18 - log 6 ( 12 ) = log 6 ©The Dublin School of Grinds = log 6 = Page 35 Mills & Kelly (Power of Maths) log k 6( x + 2) - log k 3( x + 2) = log k log a x + log a y - log a z = log a 4 = log ( k 3 ) = log k ( ) 3. Multiplication by a number rule Rule 3: k log a x = log a x k 3 log 2 5 = log 2 = log 2 1 log 16 = log 2 2 2 = log 2 4 log a x - 2 log a y = log a = log a - log a 4. Change of Base Rule 4: log a x = Change to base 2: log 3 ( x -1) = Change to base e: log a x = Change to base 8: log16 8 = log b x log b a log 2 log 2 log e log e log8 log8 = 1 log8 Tip: If you invert a log, you interchange the base with the expression inside the log. log a b = Invert: log 2 5 = Invert: 1 log b a 1 1 = log 3 6 ©The Dublin School of Grinds Page 36 Mills & Kelly (Power of Maths) All the rules together 1. Breaking logs down Technique Breaking down a log into a string of individual logs (a) Multiplication → + logs (addition) (b) Division → − logs (subtraction) (c) Power → Multiplies logs Break the following into individual logs: log 2 ( xy 2 ) = log 2 + log 2 1- x log 3 2 = log 3 ( x = log 4 = log 2 ) x + 1 x +1 = log 4 3 3 y y = log 3 x + 1 log 4 3 y = log 4 ( ) - log 4 = (log )- = log 4 ( 4 ( log 2 - log 3 )- log 3 ( + )- log 4 ) log 4 Example 25: The magnitude M of an earthquake on the Richter scale is given by 2 E 3 M = log10 , where E is the energy, in joules, released in the earthquake and E0 = 104·4 J. E0 Show that M = 23 [log10 E - log10 E0 ]. Evaluate log10 E0. The 1906 San Francisco earthquake released 6 × 1016 J of energy. What was its magnitude on the Richter scale, if log10 6 = 0∙778? Solution (a) (b) (c) Cont... ©The Dublin School of Grinds Page 37 Mills & Kelly (Power of Maths) 2. Bringing logs together Technique Combining a string of individual logs into a single log (a) + Logs → Multiply together on the top (b) – Logs → Multiply together on the bottom (c) A number multiplying a log moves into the log as a power Example 26: Evaluate log 4 8( x 2 -1) - log 4 ( x + 1) - log 4 ( x -1). Solution For you to practice Exercise 10: page 53 For you to practice (Section 2) Revision Questions: page 56 ©The Dublin School of Grinds Page 38 Mills & Kelly (Power of Maths) Exercises EXERCISE 1 (c) (x − 4)2 1. Multiply out and simplify the following: (a) (x + 2)(x + 5) (d) (5x − 4)2 (b) (3x + 7)(2x + 3) (e) (x 2 − 11)2 (c) ( y + 5)( y + 8) (f) (4y − 5)2 (d) (3x − 5)(2x − 1) (g) (ax − b)2 (e) x(x − 3)(2x + 4) (h) (a + 1)2 − (a − 1)2 (f) (2x 2 + x + 1)(x + 1) 4. Multiply out and simplify the following: 2 (g) (x − x + 5)(x − 3) (a) (x − 2)(x + 1)(x + 2) (h) (x − 1)(3x 2 + 5x − 7) (b) (2x − 1)(x + 3)(2x + 1) 2 (i) (−2x + 5x − 6)(1 − x) (c) (2x + 3)(3x − 1)(2x − 3) (d) (x + 1)3 2. Multiply out the following. The answers are a difference of two squares expression, which simplifies the process. [Hint: (x + 1)2(x + 1)] (e) (2x − 1)3 [Hint: (2x − 1)2(2x − 1)] (f) (x − 2)(2x + 1)(x − 3) (a) (x + 2)(x − 2) 5. (a) If a = x – 3 and b = 2x + 5, find the following, in terms of x: (b) (2x − 1)(2x + 1) (c) (4x − 1)(4x + 1) (i) (d) (x 2 + 1)(x 2 − 1) a+b (ii) a − b (e) (3x − 2)(3x + 2) 2 (iii) a (f) (4x – 3y)(4x + 3y) (iv) b2 (v) ab (vi) a2b (b) If p = x 2 − x + 1 and q = 2x 2 + 3x – 2, find the following, in terms of x: (g) (x 2 − 5)(x 2 + 5) (h) (xn − 3)(xn + 3) 3. Multiply out the following perfect squares: (i) p + q (iii) p + 2q (ii) p − q (iv) 2q − 3p (a) (x + 2)2 (b) (3x + 2)2 (c) If p = 2x 2 + 5x − 1 and q = 4x3 − 2x 2 + 5x − 1, find the following, in terms of x: (i) p + q (iii) 3p − 2q (ii) q − p (iv) q – xp 6. Find the values of the following expressions: (a) 3x + 11y if x = −2 and y = 3⋅5 (b) 4x − 3y + 8 if x = −1, y = −6 2 (c) 5x if x = −3 ©The Dublin School of Grinds (d) −5x 2 if x = −3 (e) (5x)2 if x = 3 (f) x 2 − 3y 2 if x = 3 and y = −2 (g) 2x 2 + 5x – 7 if x = 5 (h) −5x 2 + 7x – 3 if x = −2 (i) (2x + 3y)2 if x = −3 and y = 4 (j) 2x 2y − 3xy 2 – 7 if x = 3 and y = −2 (k) 3x 2y 2 − 5x + 7(x − y)2 if x = −2 and y = 0⋅5 Page 39 Mills & Kelly (Power of Maths) EXERCISE 2 5. (a) Find the fifth term in ( p + q)8. 1. Use your calculator to evaluate: 5 C0 , 10C0 , 18C0 , 6C0 , 8C0. What is nC0? (b) Find the fourth term in (x + y)7. (c) Find the third term in (2x + y)6. 2. Use your calculator to evaluate: 5 C5 , 10C10 , 18C18 , 6C6 , 8C8 and hence evaluate nCn 6. Find the term with: 3. Using your calculator show: (a) 5C2 = 5C3 (b) 10 (a) p3 in the expansion of ( p + q)7 (c) 7C3 = 7C4 C4 = 10C6 (d) 18 (d) Find the sixth term in ( p − q)7. (b) q5 in the expansion of ( p + q)8 C5 = 18C13 (c) (0⋅6)4 in the expansion of (0⋅4 + 0⋅6)12 Make a conclusion. (d) (0⋅85)5 in the expansion of (0⋅85 + 0⋅15)9 4. Expand out the following: (a) (x + 1)4 (e) (2x + 3y)3 (e) p6 in the expansion of ( p + q)10 (b) ( p + q)8 (f) (0⋅6 + 0⋅4)6 (f) q3 in the expansion of ( p + q)8 (c) (q + p)5 (g) (0⋅8 + 0⋅2)4 (d) (x − 2y)4 ©The Dublin School of Grinds Page 40 Mills & Kelly (Power of Maths) EXERCISE 3 1. Factorise the following by taking out the highest common factor: 4. Factorise the following difference of two squares and simplify: (a) 3x 2 + 9x − 18 (a) 4x 2 − 1 (b) 8a2 − 16a2b2 (b) 25x 2 − y 2 (c) 7x 2y 2 − 14x 2y (c) x 2 − a2b2 (d) 3(x − 2y) − 5x(x − 2y) (d) 4m2 − 81n2 (e) m(a + b) − 3n(a + b) (e) (x + y)2 − z2 (f) (2x − y)2 − (x + y)2 2. Factorise the following by grouping: (a) ax 2 + 2ax + x + 2 (g) (x + 1)2 − z2 (b) ax − bx + ay − by (h) ( Yoke)2 − (Thing)2 (c) 2x − 6 − bx + 3b (i) (3a + 2b)2 − (2a − 3b)2 (d) x 2z − 2x 2 − 2y 2 + y 2z (j) 5042 − 4962 5. Factorise the following sums and differences of two cubes: (e) 3x − 8y − 2 + 12xy 2 2 2 2 (f) 21 − 3ax − 14by + 2abx y 3. Factorise the following trinomials: 2 (a) x + 5xy − 14y 2 2 (b) 10x + 13x − 3 2 (c) 7x − 22xy + 3y 2 2 2 (d) 2a + ab − 3b (f ) 125x3 − 64a3b3 (b) x3 + 27y3 (g) (x − 2)3 + 8 (c) 8x3 − 27 (h) (x − 2)3 + (x + 2)3 (d) 1000 − 27y3 (i) x3 − (1 − y)3 (e) a3b3 + c3 (j) (Thing)3 − ( Yoke)3 6. Factorise the following fully: (e) (a − 1)2 + 2(a − 1) − 15 (a) 2x 2 − 8 (f) 30x 2 − 17x + 2 (b) 18a2 − 8b2 (g) b2x 2 + 2bxc + c2 (c) 36x 2 + 15xy − 9y 2 (h) 4p2 − 4p + 1 ©The Dublin School of Grinds (a) x3 + 64 Page 41 Mills & Kelly (Power of Maths) (d) x 2y + 2x 2 − y − 2 (f) x6 − y6 (e) 28 − 7x 2 (g) a2 − 2ab + b2 − a + b (f) 4x 2 − 24xy + 36y 2 (h) x3 + x − 2x 2 (g) −2x 2 + 4xy − 2y 2 (i) x4 + 2x 2 + 1 (h) (a + 1)2 − 9 (j) a4 − a + ba3 − b (i) 16(x − 1)2 − 4 8. (a) Derive x3 − y3 = (x − y)(x 2 + xy + y 2) from x3 + y3 = (x + y)(x 2 − xy + y 2). (j) 2a2 − 578 (b) Expand out (a − 4b)(a + b) + 3ab and hence factorise this expression. (k) 3x3 − 24 (l) x 2y3 − 27x 2 (c) Expand out (2x + 1)2 + (x − 1)2 − 2(7x − 1) and hence factorise this expression. (m) a2b4 − 8a2b (n) −2x3 − 54 (d) A is the square PQRS of side x. B is the square shown of side y. (o) cos3 q + sin3 q (a) x 2 + 2xy + y 2 − 81 y (c) a2 + 8ab + 16b2 − c2 2 y B P y 2 (d) a − 2ab + b − 16c C x Q Using Area A – Area B = Area C + Area D, show that x 2 − y 2 = (x − y)(x + y). (e) x4 − y4 ©The Dublin School of Grinds R D (b) a2 + 6a + 9 − b2 2 x S 7. Factorise the following fully: Page 42 Mills & Kelly (Power of Maths) EXERCISE 4 1. An entrepreneur bought x phones at €30 each and sold y of them at €98 each. By completing the table, find the entrepreneurʼs net profit, in terms of x and y. Sold Bought Number of phones Price/unit Total F E 2. An L-shaped flowerbed is shown with |DC| = x m and |CB| = y m. If [AB] is 1 m longer than [CD] and [ED] is 2 m longer than [CB], find expressions for: (a) the perimeter P, D x C y (b) the area A of the flowerbed, in terms of x and y. A B 3. The product of a number x and the square of another number y is greater than the product of the number x squared and the number y. Find an expression for D, the difference between the bigger number and the smaller number, in terms of x and y. 4. A petty cash box contains 10x one cent coins, 10x two cent coins, 5x five cent coins, 20x ten cent coins, 15x twenty cent coins, 7x fifty cent coins, 5x one euro coins and 3x two euro coins. It also contains 2y five euro notes, 3y ten euro notes and one 20 euro note. Complete the table below and find an expression for the total amount A of cash in the box in cents. Cash type 1c 2c 5c 10c 20c 50c 1€ 2€ 5€ 10€ 20€ Number Value in cents 5. (a) For the rectangle shown, find an expression in terms of x and y: (i) for the perimeter P of the rectangle, Rectangle (ii) for the area A of the rectangle. (b) If x = 20 and y = 30, what is the length of the perimeter? What is the area of the rectangle? ©The Dublin School of Grinds Page 43 ym xm Mills & Kelly (Power of Maths) 6. A farmer constructs a fence around a field in the shape of a trapezium ABCD with [AD] parallel to [BC] and [AB] perpendicular to [BC]. Find an expression in terms of r for: (a) the circumference of the circle, (b) the perimeter of the square, (c) the area of the circle, River A D xm (d) the area of the square, (e) the area of the shaded region. 2y m Fence Fence B C (a) If |BC| is 4 m longer than |AD| and |DC| is 2 m longer than |AB|, find an expression for the length L of fencing in terms of x and y. 9. (a) A man can swim at 2 m/s and walk at 1⋅5 m/s. If he takes x seconds to swim from A to B and y seconds to walk from B to D, find an expression for the length of the journey ABCD, in terms of x and y. (b) Find an expression for the area A enclosed by the fence in terms of x and y. (c) Find y. D Water 7. (a) If x is a whole number, find an expression in terms of x and y for: (i) the next whole number, (ii) the sum of these two consecutive whole numbers. (b) Find the values of the sum of two consecutive whole numbers if x is the first number by copying and completing the following: x=1 x=2 x=3 x=4 x=5 x=6 x=7 Road C B Sum of two consecutive whole numbers 1+2=3 A (b) A woman can swim at 1⋅8 m/s and walk at 1⋅3 m/s. If she takes (x + 30) seconds to swim from A to C and ( y − 10) seconds to walk from C to D, find an expression for the length of the journey ACD, in terms of x and y. 10. ABCD is a rectangular frame with a picture inside, as shown. D (x + 2) m C 1m 1m Picture 1m xm 1m A Find an expression in terms of x for the area of: What conclusion can you make? 8. r is the radius of a circle, centre O, inscribed in a square ABCD. D B (a) rectangle ABCD, (b) the picture, C (c) the border. r O A ©The Dublin School of Grinds B Page 44 Mills & Kelly (Power of Maths) EXERCISE 5 3. (a) If x − 1 is a factor of x 2 − k x + 3, find k. 1. Simplify the following and give your answer in descending powers of x: (b) If x + 3 is a factor of k x 2 + 4x – 6, find k. (a) 2x − 5 + x − 2 (c) If 2x − 1 and 3x + 2 are factors of ax 2 + bx + c, find a, b and c. (b) 5x 2 − 7x − 6 – x 2 + 1 (d) If 2x − 3 is a factor of 4x 2 − 4x − 3, find the other factor. (c) 3x 2 + 2x 3 − 5x + 7x 3 − 5x 2 + 1 (d) 2 − 3x + 5x 2 − 8x 3 + 7x − 3 (e) If 4x − 1 is a factor of 8x 2 + k x + 7, find the other factor and k. (e) −x 3 + 5x 2 − 2x + 3x 3 − 2x 2 + 7x 2. Multiply out the following and give your answer in order of descending powers of x: (a) (x + 1)(x + k) (f) If ax 2 + bx + 8 = (3x − 1)(5x − k), find k, a and b. (f) (x 2 − x + 1)(x − k) (g) Find the quadratic polynomial with factors: 2 (b) (2x + 1)(k x + 1) (g) (2x − 1)(k x − 5) (c) (x − 1)(k x + 2) (h) (3x − 1)(x 2 + k x − 2) 2 (d) (1 − 2x)(x − k) (i) (2x + 1)(3x + kx − 3) (e) (x 2 + x)(x + k) (j) (x − c)(x 2 + k x + d) (i) 5x − 1 and 2x – 3 (ii) 10x − 2 and 2x – 3 (iii) 5x − 1 and 4x – 6 (c) If x 2 − px + q is a factor of x 3 + 3px 2 + 3qx + r, show: (h) Find the quadratic polynomial with factors: __ __ (i) x + √2 , x − √2 __ __ (ii) x + √3 − 1, x − √3 + 1 __ __ (iii) 2x + √3 , x − 2√3 (i) q = −2p 2, (ii) r = −8p 3. (d) If x2 − a2 is a factor of f (x) = x 3 + x 2 + px + q: 4. (a) If x 2 + x + 2 is a factor of x 3 + k x 2 + lx + 2, find the other factor and k and l. (i) show p = q = –a 2, (ii) write f (x) in form (x 2 − a 2)(x + r). (b) If 2x2 + bx − 5 is a factor of 2x 3 − x2 + kx + 10, find the other factor and b and k. (e) If 3 − x is a factor of P (x) = 6 + x − 4x 2 + x 3, find the other factors of P (x). (c) ax 2 + 2 is a factor of 18x 3 + k x 2 + 6x – 2. Find k and a and the other factor. (f) If x − a is a factor of x 3 – c, show c = a 3. (d) If x − 1 is a factor of x 3 + 2x 2 − k x + 4, find k ∈ R and the other factors. (e) If x − 2 is a factor of P (x) = x 3 − 2x 2 − 3x – k, find k and the quadratic factor of P(x). (f) If (x + 1) and (x − 3) are both factors of k x 3 − 6x 2 + bx – 6, find k, b ∈ R and the other factor. 2 (h) If (x − 1)2 is a factor of ax 3 + bx 2 + 1, find a and b. (i) If (x − a)2 is a factor of x 3 + 3rx + q, show: (i) r = −a2 (ii) q = 2a 3 3 5. (a) If (x − p) is a factor of x + qx + r, show: (i) r = 2p 3, (ii) q = −3p2. (b) If (x − 1) is a factor of x 3 + ax2 − (a + 1)2 + 12, a > 0, find a ∈ R. ©The Dublin School of Grinds (g) If x 2 − px + 1 is a factor of ax 3 + bx + c, show c 2 = a(a − b). Page 45 (j) If x 2 + ax + b is a factor of x 3 + qx 2 + rx + s show: (i) r = b + a(q − a) (ii) s = b(q − a) Mills & Kelly (Power of Maths) EXERCISE 6 1. Simplify the following: x−2 (a) _____ 2−x x 2 − 2x (b) _______ 2−x 5x 2 + 15x (c) _________ 5x 3 x +x (d) ______ x2 + 1 x3 + x2 (e) _______ x+1 15x 2 + 11x − 14 (f) _____________ 3x − 2 3 3x − 24 (g) ________ 3x − 6 3 + 3x 3 (h) ___________ 3x 2 − 3x + 3 16x 3 − 28x 2 + 6x (i) _______________ 8x − 2 2 −4x + 36 (j) _________ x−3 2. Simplify the following: x3 + x2 − x − 1 (g) ____________ x+1 6x 3 + x 2 − 2x (h) ___________ 2x − 1 27x 3 − 1 (i) _______ 3x − 1 x 3 − 7x + 6 (j) _________ x 2 + 2x − 3 3. The volume of the box shown is given by V = 2x 3 + 7x 2 + 7x + 2. x 3 + 7x 2 + 14x + 8 (a) _______________ x+2 h x 3 − 4x 2 + 5 (b) __________ x+1 2x + 1 x+1 4x 3 − 11x + 3 (c) ___________ 2x − 3 Find: (a) h in terms of x, (b) the surface area A, in terms of x. 10x 3 − 31x 2 + 27x − 30 (d) ___________________ 2x − 5 4. If x − 1 is a factor of x 3 + kx 2 − 4x + 1, show that k = 2. x 3 − 25x (e) _______ x−5 5. If x − 2 is a factor of x 3 + ax 2 + bx + 6, show that b + 2a = −7. −6x 3 − 7x 2 + x − 3 (f) _______________ 3x 2 − x + 1 ©The Dublin School of Grinds 6. If x 2 − 5x + 11 is a factor of x 3 − 2x 2 + ax + 33, show that a = −4. Page 46 Mills & Kelly (Power of Maths) 1. Simplify the following: 2p 4 (a) _____ + _____ p−2 2−p x 1 (b) __ − __ 2 x x+1 x (c) _____ − _____ x−1 x−2 α β (d) __ − __ β α EXERCISE 7 3 3 __ (h) ( __ a − 2 )( a + 2 ) ( a3 − 2b ) 2 3 x ( j) ( + )( − 4y ) x y 2 (i) (g) 2 + 2n − 2 − 2n + 1 − n2 (d) (g) y 3 − 9y b−9 2 4 x + x−3 __________ 4x 2 − 7x + 3 4 (h) (i) 4 x −y ______ x2 − y2 6 6 x −y __________________ (x 3 − y 3)(x 2 − xy + y 2) 2 3x (b) ___ _2_ x x __ 2 (c) ___ 3x 1 x − _x_ (e) 1 2 + _x_ _____ 1 2 − _x_ 3 10 1 − __ + ___2 x x (f) __________ 2 15 −1 + __ + ___2 x x at – at 2 ______ (g) a a __ __ − t t2 (d) _____ x−1 _____ x 2 x + 6x − 7 _________ x 2 − 5x + 4 2 3 y + 27 ______ 3a 2 + a _3_ x (a) __ x __ x+2 3x 2 − 11x + 10 ______ × (e) ____________ 2 x −4 3x − 5 × 2 6a + 2a ________ 2 6b − 51b − 27 _____________ 4. Simplify the following: a 2 − 3a a 2 + 8a + 15 _______ × (d) ___________ ab + 5b a2 − 9 2x 2 + 11x − 21 ) −5a 2 + 17a − 6 6x 3 − 7x 2 + 2x (e) _____________ (j) ____________ 3−a 2x 2 − x 2a 2 28b 2 (a) ____2 × ____ 4ab 35b 3x − 1 (b) ______ 3 − 9x 4b 2 − 2ab 3ab _________ (c) _________ × 8ab 3a 2 − 6ab (f ) )( 6x − 18 (c) _______ 15 − 5x 2n ______ 2. Simplify the following: 2 __ __ 3. Simplify the following: 4x 2 (f) (a) ___ 2x 2x (b) ___2 (g) 4x 2a a−1 a+1 (h) ______ − _______ + ________ 2 4a + 8 5a − 10 5a − 20 x − 2 _____ 3x 4 _____ (i) _____ − + x2 − 1 x2 + x x + 1 7 1 ( j) ___________ + _________ 2 2 x + 13x + 30 x + 5x + 6 2x − 11x + 12 ____________ __ ( 1 (f) m − __ m 1+n ______ __ 2 x x (k) __ − 1 __ + 1 (4x − 8) 2 2 1 x − 3 4x − 1 (e) __ + _____ − ______ 24x 9 18x 1−n ______ __ × y + 3y ______ y+3 ©The Dublin School of Grinds Page 47 Mills & Kelly (Power of Maths) EXERCISE 8 1. Evaluate the following without using your calculator: (a) 33 (h) (−2)4 (b) 25 (i) (c) 54 (d) 10 (j) 8 (e) 12013 (f) (−1) (k) 4 (g) (−1)21 (l) (−3)5 __ 2 (o) 2 __ 2 ( 3 _12 ) 2 ( 2 _34 ) 3 ( −2 _12 ) (n) ( 21 ) ( 32 ) ( − 12 ) __ 2 ( ) 4 (m) − __ 5 (p) 3 (c) 4 −3 (f) (3⋅6)−1 (g) (4) 3 __ −1 (h) 2−1 × 3 ©The Dublin School of Grinds (l) (c) 25 2 __4 __1 −3 __1 −2 (h) 2 × 16 2 (i) 6 × 100 (k) 3 × 4 −1 −1 3 ×2 (l) (m) (−8)−2 2 __3 __5 (o) (3 × 2 ) Page 48 ( (s) 8 ( − ___ 27 ) (t) 8 __1 3 8 − ___ 27 ) __1 3 __1 −3 0 ( 27 ) ( − 271 ) 1 − __13 ___ __1 ___ − 3 __1 −2 ( ) __1 (9) 1 __ (n) (−8) 3 −1 −3 (r) 1 (w) 2 __ 4 __1 −2 (m) (100 000 000) 4 (n) (−3)−3 8 ( ___ 27 ) (v) __1 (j) 4 × 49 2 1 ________ (q) (u) __3 −2 __1 −2 ( __94 ) (d) 8 3 __1 −2 __1 −2 (p) __3 __1 3 (k) ___ 2 (e) 2−4 __1 (g) 6 × 36 −1 (d) 5−2 (o) 100 (b) 25 2 (f) 64 (i) 2 × 3−1 2 (j) ___ −1 3 (b) 3−2 __3 (a) 9 2 (e) 36 2. Evaluate the following without using your calculator: (a) 2−1 3. Evaluate the following exactly without using your calculator: 2 ( ) (2) 25 (x) ___ 16 (y) __1 −2 3 __ ( 2) × ( 9 ) 1 – __ 0 16 ___ − __32 Mills & Kelly (Power of Maths) 6. Simplify the following, giving all your answers with positive powers: (a + 3b)2(a + 3b)6 x 2 × (xy)2 _______________ (l) (a) ________ y (a + 3b)3 4. Write: __ p (a) 8√2 in the form 2 , p > 0 __ 27 √3 p (b) _____ in the form 3 , p > 0 3 __ 4 √2 1 (c) ____ in the form __p , p > 0 32 2 __ (d) 49√7 _____ p √7 (d) __2 (e) 28x 4 (c) ____ 7x 3 in the form 7 , p > 0 __ 3 5x 3 × 6x 4 (b) ________ 15x 2 2 3 125 × __ 5 ________ 25 × √5 p in the form 5 , p > 0 23 (e) 15 (g) p ( 2 ) __× 2 × 3 4 3 __ 1 ___ in the form −2 3__ q , p > 0, q > 0 2 27 × 3 p __ in the form 3 , p > 0 (i) _______ 9√3 (j) (3) 5 __ −1 __3 −2 )3 ( 25 9 p in the form 5 , p > 0 × _____ × _____ __2 −2 3 1253 p 5. Write in the form a or 7 (a) a × a 2 (b) (a 7)3 7 −3 (c) a × a a7 (d) ___3 a __ 3 (e) √ a __ (f) a√a 3 __ (g) (a√ a )3 a14 (h) ___ a2 a (i) __3 a ©The Dublin School of Grinds 1 __ a p, (j) where p ∈R, p > 0: √a (m) 3 72x 5 42x 5 ________ 7x 2 × 3x 3 x 2_______ × 2 3x (j) (k) (o) ( ) 2 x___ y 2y 2 __3 (q) 4x 2 ___ __1 2x 2 −3 (r) 25y _____ 5y− 2 __4 __5 (s) 8x 3 y 2 ________ __1 __3 4x 3 × 2y 2 4 3z 3 7y 2 × 25y 2 __________ 2 × 22x × 3 × 3x a−2 ___ 2a 2 (p) ___ y−2 2 2x 5x (2 ) × (3 ) _____________ __3 (t) 16( x 2y) 2 _______ __ 8√y x 5xy 3 × 14xy 7. The population P of a certain strain of bacteria is given by P = 1500 × 3t, where t is the time in hours. 2 a__ ___ (a) Find the population P1 after 4 hours. a2 (k) ___ a−3 (l) 36 x ____ x ×2 (h) _______ 2x × x3 (3xy)2 × 2xy (i) __________ 9(x 2y)3 2 3 (n) 3 4 16√2 __ in the form 2 p, p > 0 (h) _____ √8 __2 (g) x 3 x 2 70x 3(xy)4 (f) _________2 5xy × 7xy 10 × 2 × 10 p (f) _______________4 in the form 10 , p > 0 19 −2 2 × 10 × ( 10 ) xyab 2 (m) ______ abx 2 y 2 (b) Find the population P2 after 10 hours. __ (c) Compare these populations by dividing P2 by P1. √ a2 __ √a × (a 2)3 __________ 8. The mass M of a radioactive material in grams (g) left after t hours is given by 20 M = ___t . 16 (a) Show that M = 20 × 2−4t. a−2 × (a 3)−1 __1 − __1 (____________ a−2) 2 × (a 3) 2 __ (n) √a __ __3 3 −2 a × (a )2 √__________ (o) −2 2 −1 (a ) × a (b) Compare the mass M2 left after (x + 7 ) hours with the mass M1 left after (x + 6) hours by dividing M2 by M1. Page 49 Mills & Kelly (Power of Maths) 9. The mass M of a drug in milligrams (mg) in a person’s body after t hours is given by 10. The value V in € of an investment after t years is given by V = 5000(1⋅08)t. _____ M= √8 3 _____ 8000 . 3t (a) Compare the amount V2 after (t + 3) years with the amount V1 after t years, giving your answer to four decimal places. (a) Show that M = 20 × 2−3t. (b) Find M after 1 hour. (c) Find the percentage change in M between t and (t + 1). (b) Find the value of the investment after five years, correct to the nearest euro. (c) Find the value of the investment after eight years, correct to the nearest euro. EXERCISE 9 1. Write the following surds in their simplest form: ___ ____ (a) √12 (d) √512 __ ___ 8 (b) √27 (e) __ 9 ___ _____ 18 (c) √1210 (f) ___ 25 √ √ ©The Dublin School of Grinds Page 50 ____ ____ (g) √___ 100 (h) √4x 3 147 ____ _____ (i) √ 8x 2 y 3 (j) √ √ 12 x3 ____ y2 _____ (k) 16 z 61 _____ 9x 2y 2 Mills & Kelly (Power of Maths) 2. Simplify the following surds: ___ ___ ___ (a) √11 − 2√11 + 4√11 __ __ (b) 5 + 7√3 − 9 + 8√3 __ __ __ (c) x + √y − 3√y + 2x − 5√y ___ ___ ____ (d) √28 + √63 − √175 ____ ____ ____ (e) √125 − 2√180 + √245 __ ___ ___ ___ (f) √8 + √12 + √18 + √27 ___ ___ ____ (g) √75 − 3√48 +__√147 __ __ (h) √x___ + x√x −___ √x 3 ____ 3 3 (r) (s) 3 3 (i) a√ay + y√a y + √a y _____ _______ _____ ________ (j) √x − 3 − √4x − 12 + 2√x − 3 − √25x − 75 3. Multiply __ out and simplify the following surds: 3 (a) (√2 ) __ __ (b) √2 × √3 __ ___ (c) 2√6 × 5√18 __ __ __ __ (d) √6 (3√2 + 2√3 + √6 ) __ 2 (e) (√3 + 1) __ __ (f) (√3 − 1)(√3 + 1) ___ __ __ (g) √ab (a√b + b√a ) __ ___ (h) (√7 + √13 )2 __ ___ __ ___ (i) (√7 + √13 )(√7 − √13 ) __ __ (j) (2√x + 3√y )2 _____ _____ _____ _____ (k) (√x + 2 + √x + 1 )(√x + 2 − √x + 1 ) __ __ __ (l) √x (2√x − 3) + 5(√x − x) _____ _____ 1 (m) __ (√a + x − √a − x )2 2 __ __ (n) (x + √2 )(x − 1)(x − √2 ) 1 __ 1 __ (o) (x 2 + 1)(x 2 − 1) (p) (q) ( __ ) ( y__ √x − ___ ___ y √x 2 ) 2 4. Rationalise each denominator: __ 6 √ 1__ __ (f) ____ (a) ___ (k) 2√7 √5 x__ 1__ (g) ___ (b) − ___ (l) √__y √2 2__ √__x (c) ___ (h) ___ (m) 3 √ √y 4__ (d) ____ __1 (i) ______ 5√2 (n) √2 + 1 −3__ ____ 1 __ (e) (j) _______ 2√3 (o) 3 − 2√2 __________ __ 6 __ 3√ __2 − 2√3 √__5 + 1 ______ √5 −__1 5√x ________ __ 3 − 2√x __ __ √__3 + √__2 ________ √3 − √2 __________ __ x _____ √a − √a – x __ 5. If y = 2 − √3 , evaluate y 2 − 4y + 1. 6. BCD is an isosceles triangle. D 4 + x2 4 + x2 h B 8 – 2x 2 C Find: (a) the height h in terms of x, (b) the area of the triangle in terms of x. __ __ __ __ 7. If x = √3 + √2 and y = √3 − √2 , find x2 + xy + y2. _______ ______ y2 − x2 x2 √ ________ __ . 8. Show 1 − 2 = y y √ ( ___√1__x__− 1)( ___√1__x + 1__) ( 4√y + ___√3__y )( 4√y − ___√3__y ) ©The Dublin School of Grinds __ ___ √x + 2__ √x ___________ √ 1 9. If V = 20h2 ____2 − 0·05 , show that V can be 25h _______ written as V = 2h √ 4 − 5h2 . Page 51 Mills & Kelly (Power of Maths) 10. Kepler showed that the periodic time P for a satellite to make a complete orbit around a planet of mass M at a distance r from the centre of____ the planet is given by P = 2π √ 12. The mass M of an object moving at a speed M0 ______ , where M is the v is given by M = _______ 0 v2 1 − __2 √ GM , where G is a constant. (a) Show that M can be written as _______ 2 2 M 0 c √c − v ____________ M= . 2 2 c − v 5M0 4c (b) If v = ___, show that M = ____ . 5 3 r M c mass at rest and c is the speed of light. 3 r ____ 13. A simple pendulum consists of a mass M on the end of a string of length L moving back and forth as shown. (a) Write down the periodic times: L L (i) P1 for a satellite at r = R, (ii) P2 for a satellite at r = 4R. P1 1 (b) Show that ___ = __. P2 8 M The time to swing from right to left and back 11. If x, y and z are consecutive terms in a y z geometric sequence, then __x = __y . Show that the following numbers are consecutively in a geometric sequence: ___ ___ (a) 5, √35 , 7 (b) a, √ab , b ©The Dublin School of Grinds M __ √ L again is given by T = 2π __ g , where g is a constant. (a) Write down the time T1 if L = d. d (b) Write down the time T2 if L = __ . 4 T __1 (c) Show that = 2. T2 Page 52 Mills & Kelly (Power of Maths) EXERCISE 10 1. Evaluate the following exactly: ( ) ( ) 1 (f) logp __2 p (a) log10 100 −5 (b) log10 (10 ) (c) log10 (g) log3 e x + log3 e 2x − 1 y x4 __ (h) log x __ + log x y x3 3 ___ ( ) (g) log5 √ 25 ( ) 1 ___ 1 2 (i) logk (x − 1) + logk _____ x+1 (j) logx 2 x + logx 2 −x (h) log__1 16 10 __ (d) loge√e 2 (i) log√__2 4 () 1 (e) logk __ k ( ) 4. Write the following as a single log (in the form log a x): (j) log__1 27 (a) log2 6 − log2 3 9 (b) log3 3a − log3 a 2. Write the following logs in exponential (power) form: (a) log17 289 = 2 (f) log3 3 = 1 (b) log4 16 = 2 (g) loga 1 = 0 1 (c) log4 ___ = −2 16 (c) loge (x 2 − 1) − loge (x + 1) 1 (d) log5 7 − log5 __ 7 (e) log4 (x 3 − 1) − log4 (x 2 + x + 1) (h) logb a = c (f) log3 e x + 1 − log3 e x − 1 (d) log16 4 = _12 (i) log8 16 = _43 ( ) () 1 1 (e) log16 __ = − __ 4 2 () (g) log9 (3x + 6) − log9 (x + 2) (h) logb (ba + b2) − logb (a + b) __ __ (i) log√__x √xy − log√__x √y (j) log16 8 = _4 3 () 1 (j) loga x − loga __ x 3. Write the following as a single log (in the form loga x) and simplify, where possible: 5. Write the following as a single log (in the form loga x): (a) log2 3 + log2 5 (a) 3 log2 5 (b) log3 a + log3 4a (b) −2 log3 7 (c) loge (1 − x) + loge (1 + x) 1 _ (c) _12 log4 25 (d) log5 7 + log5 7 __ __ (e) log5√y + log5√y (d) − _2 log2 36 (e) 2 logk y 3 (f) log4 (x − 1) + log4 (x 2 + x + 1) ©The Dublin School of Grinds Page 53 Mills & Kelly (Power of Maths) _____ (f) 2 log5 √ 1 + x 2 1 _ 2 2 (g) − 2 log3 z y __3 (h) _23 log7 8 y 2 (v) log10 30 (vi) log10 81 ( ) ( ) () 1 (j) _12 log5 __2 y 6. (a) Write log3 5 in base 2. (x) (b) Write log7 4 in base 5. (c) Write loga y in base b. log3 12 8. (a) Write the following as a single log and hence, evaluate exactly, where possible: (d) Write log5 (x − 2) in base 7. (e) Write log10 a in base e. (f) Write log5 3 in base 3. (g) Write log4 x in base x. (i) log10 25 + log10 4 (ii) log3 21 − log3 7 (iii) _12 log10 4 + log10 35 − log10 7 (h) Write logx 5in base 5. (iv) 1 (i) Write _____ in base x. log2 x 1 (j) Write _____ in base x. loge x log3 2 + 2 log3 3 − log318 (b) Write the following as a single log: 7. (a) Write the following as a string of logs: __ 2 (i) loga x √y (i) 2 log5 x + log5 y (ii) 3 logk x + 2 logk y − _14 logk z 3 (iii) _12 log3 (x − 1) − _2 log3 ( x + 1 ) log2 (u 2v 3) __ x 3 √ (iii) log5 ____ p 2q 3 (iv) ( ) (v) 7{log3 (x + 5) + log3 2 − 3 log3(4x − 1)} __ __ 1 log4 a 2 + log4 a + log4√a x+1 1 _ _____ 1 _ 2 4 loga (x + 3x + 2) + 4 loga x + 2 ( ) ( ) (vi) ( ) (viii) x loge x − _12 loge x + e loge x 3 27x ____ (iv) log3 (v) 1 loga __2 a logk (x + 3)2(2x − 1)3 (vi) log10 60 16 (vii) log10 ___ 27 400 (viii) log10 ____ 27 (ix) log10 48 (i) x loge 2 (ii) (iv) (vii) _12{loge 9 − 3 loge(x2 + 1) + 2 loge(3x + 2)} 3y 6 ( (x + 7)7 ______ (vii) log2 ________ 4√2x − 3 ( ) x−1 (viii) log5 _____ x+1 __1 9. If log2 y = log2 x + 2, show that y = 4x. ) 10. If loge A + 2 loge y = 3 loge y + D, show that y = Ae−D. 11. If f (x) = loga x, show that 2 f (x + h) − f (x) ____________ (b) If a = log10 2 and b = log10 3, express the following in terms of a and b: (i) log10 6 (ii) log10 24 (x + h) − x ( h __ ) __1 h = loga 1 + x . 12. If log5 y = 2 log5 x − log5 (x + 1) + c, x2 show that y = _____ 5c. x+1 () 9 (iii) log10 __ 8 ©The Dublin School of Grinds Page 54 Mills & Kelly (Power of Maths) 16. Show that: 13. Use the rules of logs to show that: _____ _____ (a) loga (x + √ x 2 − 1 ) + loga (x − √ x 2 − 1 ) = 0 __ _____ __ _____ (b) logb (√ x + √ x − 1 ) + logb (√ x − √ x − 1 ) = 0 x (a) loga a = x (b) a loga x = x 14. Simplify the following: 7 (a) log3 3 (b) 3 log3 4 __ (c) log5√5 (d) 10 17. The loudness L of a sound in decibels is given I by L = 10 log10 __ , where I is the intensity of I0 () log10 3 (e) logx (x 8) 1 __ (f) e 2 the sound in W m−2 and I0 = 10−12 W m−2. loge x (a) Find: (i) the loudness in decibels of normal conversation which has an intensity of I = 10−7 W m−1, Check the answers to (a), (b), (c) and (d) on your calculator. logc a 15. (a) Using logb a = _____, solve for logc a. logc b Hence, simplify: (ii) the loudness of amplified rock music which has an intensity of 10−1 W m−2. log2 3 × log3 4 × log4 5 × log5 6 × log6 7 × log7 8 (b) Simplify: log2 2 × log2 4 × log2 8 × … × log2 2n (b) If a sound has a loudness L1 for intensity I1 and loudness L2 for intensity 1000I1, show that L2 − L1 = 30. 1 1 1 1 1 1 18. Show that _____ + _____ + _____ + _____ + _____ = _______ . log2 x log3 x log4 x log5 x log6 x log720 x 19. Evaluate the following exactly: (a) log3 354 (b) 3 log3 5 − log3 2 (c) 10 2 − log10 2 (d) log3 8 × log8 9 20. If log10 x = (1 + p) and log10 y = (1 – p), show that x y = 100. ©The Dublin School of Grinds Page 55 Mills & Kelly (Power of Maths) REVISION QUESTIONS __ __ a − b 5 3 − √__ √5 in the form _______ , a, b ∈N. 1. (a) Express ______ 3 + √5 2 (b) If 2x − 1 is a factor of 2x 3 + x 2 + k x + 6, k ∈Z, find k and the other factors. (c) If ax + b is a factor of 2ax 2 + (2b − a)x + c, find the second factor and show that b = −c. __ __ y−x _____ 2. (a) If x = 1 − √3 and __ y = 1 + √3 , express xy in the form a√b , a ∈Z, b ∈ N. x2 − 4 7. (a) If x = 999 999 999 999, evaluate ______ exactly. x−2 _____ 2009 √ 10 _____ exactly. _______________ (b) (i) Evaluate _____ 2011 √ 10 − √ 102007 ___ ___ 2 2 (ii) Simplify 1 + √2 x − √8x 2 . ( (c) Show: (i) 2n + 1 + 2n = 3 × 2n (iii) 2 2 − b 2 c______ − d2 . (c) If _a_ = _c_ , show that a______ = b d a2 + b 2 c 2 + d 2 _7_ = 32009 + 32010 3 5 × 2x − 8 × 2x − 2 _______________ 2x − 2x−1 =6 __1 __3 per week is given by N1 = 50x 2 y 2 , where x is the average number of workers that attend per week and y is the average number of hours worked by each worker per week. (a) Find the number of phones produced in a week in which the average attendance is 256 workers and the average number of hours worked is 36. ) (b) For another factory producing the same __3 __1 phone N2 = 20 x2y2 . Find the number of phones produced by this factory in a week in which the average attendance is 256 workers and the average number of hours worked is 36. N1 5y (c) Show that ___ = ___ . N2 2x (d) Show that for a 40-hour week in each factory, an attendance of 100 workers in each will produce the same number of phones per week. 3x − 5 1 4. (a) Show that ______ + _____ , x ≠ 2, simplifies to x−2 2−x a constant. __ __ √x √x __ __ + ______ as a single fraction. (b) Express ______ √x − 1 √x + 1 (c) (i) If a − b(c − x)2 = 6x − 7 − x 2 for all x ∈R. Find a, b, c ∈N. (ii) If x 2 + x + 1 is a factor of 2x 3 + ax 2 − x + b, find a, b ∈Z. 9. The stopping distances in metres (m) of a car __5 5. (a) Expand ( p + q) . 3 (b) What is the term with q 3 in the expansion of ( p + q)7? (c) Show that p3 + q 3 − ( p + q)3 = −3pq( p + q). 3 3 simplifies to a 6. (a) Show that ______p + ______ 1+x 1 + x −p constant. 6y 3 (b) (i) Express ________ − ___ as a single fraction. x(x __ + 4y) 2 x __ 2 (ii) If 2x − √3 is a factor of 4x − kx + √3 , find the other factor and k ∈R. 2 (c) If x − ax − 3 is a factor of x 3 − 5x 2 + bx + 9, find a, b ∈N. ©The Dublin School of Grinds 2011 8. The number of phones produced by a factory 3. (a) If 5x 2 − 20x + 8 = a(x + b)2 + c for all x, find a, b, c ∈Z. by cz ax (b) If _____ = _______ = _______ , show that b − c 2(c − a) 3(a − b) 6ax + 3by + 2cz = 0. __ __ 1 1 (c) Express x 2 + √2 + __2 x 2 − √2 + __2 in the x x 1 __ form x n + n , where n ∈N. x )( 2008 3 +3 ___________ (ii) 3 4 (b) Simplify ___________ . − ___________ 2 2 x + 12x + 20 x + 14x + 40 ( ) Page 56 ___ v3 travelling at v km/h is given by S1 = 20 for a wet __4 __ v3 road and S2 = 6 for a dry road. (a) Copy and complete the table below. Give the values in the last two columns, correct to two decimal places, and make a conclusion. 5 __ v km/h 4 __ v3 27 64 125 S__1 3 v3 S1 S2 __ 3√ v (b) Show that = ____ . S2 10 Mills & Kelly (Power of Maths) (c) If the speed of a car is 74⋅088 km/h, compare its stopping distance on a wet road to that on a dry road. 1000 (d) At v = _____ km/h, show that S1 = S2. 27 10. (a) Show that 6 3 log 10 x − log10 x _______________ log10 x 2 − log10 x 12. (a) A boy rows downstream for 2 km at a speed of (x − 2) km/h from a point A to point B. Write down an expression for the time of the journey in terms of x, x > 0. 2 km = 3. A log2 a log2 b log2 c (b) If _____ = _____ = _____ = log2 x, p 2p 3p (b) A man rows the same journey at a speed of (x + 2) km/h. Write down an expression for the time he takes. 2 b ___ show that ac = 1. (c) If x 2 + y 2 = 14x y, show that (x + y)2 = 16x y. loga x + loga y x+y Hence, show that _____________ = loga _____ . 2 4 1 11. The power P of a lens is given by P = __ where f f is its focal length in metres (m). (c) Which one takes the shorter time? Why? ( ) (a) The focal length of lens A is x m.Write down an expression for its power, in terms of x. (c) When lens A and B are combined, the power of the combination is obtained by adding their powers together. Find an expression for the power of the combination as a single fraction, in terms of x. (d) Write down an expression for the difference in times. Give your answer as a single a fraction in the form _______ . 2 x − b2 (e) If x = 12, find this difference to the nearest second. 13. (a) The number of bacteria in a sample A after t minutes is given by 50 × 2t + 6. Lens A (b) Lens B has a focal length of − (x + 2) m. Write down an expression for the power of lens B, in terms of x. Express this number in the form a × 2t. Find the number of bacteria initially in the sample. (b) The number of bacteria in a sample B after t minutes is given by the expression 100 × 4t. Lens B Write this expression in the form b × 22t. Find the number of bacteria initially in this sample. Lens A Lens B (c) Find the ratio of the number of bacteria in sample B to that in sample A after t minutes in the form 2 p. What is this ratio after: (i) 2 minutes, (ii) 5 minutes, 1 _ (d) If x = 2 , find the power of this combination as a fraction. If the focal length of the combination is one divided by the power, find this focal length as a fraction. ©The Dublin School of Grinds B (iii) 10 minutes? (d) Make a conclusion. Page 57 Mills & Kelly (Power of Maths) Answers Section 2 Chapter 3 Exercise 1 1. (a) x 2 + 7x + 10 (b) 6x 2 + 23x + 21 (c) y 2 + 13y + 40 (d) 6x2 – 13x + 5 (e) 2x3 – 2x2 – 12x (f ) 2x3 + 3x2 + 2x + 1 (g) x 3 – 4x 2 + 8x – 15 (h) 3x 3 + 2x 2 – 12x + 7 (i) 2x 3 – 7x 2 + 11x – 6 2. (a) x 2 – 4 (b) 4x 2 – 1 (c) 16x 2– 1 (d) x 4 – 1 (e) 9x 2 – 4 (f ) 16x 2 – 9y 2 (g) x 4 – 25 (h) x 2n – 9 3. (a) x 2 + 4x + 4 (b) 9x 2 + 12x + 4 (c) x 2 – 8x + 16 (d) 25x 2 – 40x + 16 (e) x 4 – 22x 2 + 121 (f ) 16y 2 – 40y + 25 (g) a 2x 2 – 2abx + b 2 (h) 4a 4. (a) x 3 + x 2 – 4x – 4 (b) 4x 3 + 12x 2 – x – 3 (c) 12x 3 – 4x 2 – 27x + 9 (d) x 3 + 3x 2 + 3x + 1 (e) 8x 3 – 12x 2 + 6x – 1 (f ) 2x 3 – 9x 2 + 7x + 6 5. (a) (i) 3x + 2 (ii) – x – 8 (iii) x 2 – 6x + 9 (iv) 4x 2 + 20x + 25 (v) 2x 2 – x – 15 (vi) 2x 3 – 7x 2 – 12x + 45 (b) (i) 3x 2 + 2x – 1 (ii) – x 2 – 4x + 3 (iii) 5x 2 + 5x – 3 (iv) x 2 + 9x – 7 (c) (i) 4x3 + 10x – 2 (ii) 4x3 – 4x2 (iii) – 8x3 + 10x2 + 5x – 1 (iv) 2x 3 – 7x 2 + 6x – 1 6. (a) 32·5 (b) 22 (c) 45 (d) – 45 (e) 225 (f ) –3 (g) 68 (h) –37 (i) 36 (j) –79 (k) 56·75 ©The Dublin School of Grinds Exercise 2 1. 1, 1, 1, 1, 1; 1 2. 1, 1, 1, 1, 1; 1 3. (a)–(d) nCr = nCn − r 4. (a) x 4 + 4x 3 + 6x 2 + 4x + 1 (b) p 8 + 8p 7q + 28p 6q 2 + 56p 5q 3 + 70p 4q 4 + 56p 3q 5 + 28p 2q 6 + 8pq 7 + q 8 (c) q 5 + 5q 4p + 10q 3p 2 + 10q 2p 3 + 5qp 4 + p 5 (d) x 4 – 8x 3y + 24x 2y 2 – 32xy 3 + 16y 4 (e) 8x 3 + 36x 2y + 54xy 2 + 27y 3 (f ) (0·6) 6 ‒ 6(0·6) 5 (0·4) + 15(0·6) 4 (0·4) 2 + 20(0·6) 3 (0·4) 3 + 15(0·6) 2 (0·4) 4 + 6(0·6) 1(0·4) 5+ (0·4) 6 = 1 (g) (0·8) 4 + 4(0·8) 3 (0·2) + 6(0·8) 2(0·2) 2 + 4(0·8) (0·2) 3 + (0·2) 4 = 1 5. (a) 70 p 4q 4 (b) 35x 4 y 3 (c) 240x 4y 2 (d) ‒21p 2q 5 6. (a) 35 p 3q 4 (b) 56 p 3q 5 (c) 495(0·4) 8 (0·6) 4 = 0·042 (d) 126(0·85) 5 (0·15) 4 = 0·028 (e) 210p 6q 4 (f ) 56 p 5q 3 Exercise 3 1. (a) 3(x 2 + 3x – 6) (b) 8a 2(1 – 2b 2) (c) 7x 2y( y – 2) (d) (x – 2y)(3 – 5x) (e) (a + b)(m – 3n) 2. (a) (x + 2)(ax + 1) (b) (a – b)(x + y) (c) (x – 3)(2 – b) (d) (z – 2)(x 2 + y 2) (e) (3x – 2)(1 + 4y) (f ) (3 – 2by 2)(7 – ax 2) 3. (a) (x – 2y)(x + 7y) (b) (5x –1)(2x + 3) (c) (7x – y)(x – 3y) (d) (2a + 3b)(a – b) (e) (a – 4)(a + 4) (f ) (5x – 2)(6x – 1) (g) (bx + c)(bx + c) (h) (2p – 1)(2p – 1) 4. (a) (2x –1)(2x + 1) (b) (5x – y)(5x + y) (c) (x – ab)(x + ab) (d) (2m – 9n)(2m + 9n) (e) (x + y – z)(x + y + z) (f ) 3x(x – 2y) (g) (x – z + 1)(x + z + 1) (h) (Yoke – Thing)(Yoke + Thing) (i) (a + 5b)(5a – b) ( j) 8000 5. (a) (x + 4)(x 2 – 4x + 16) (b) (x + 3y)(x 2 – 3xy + 9y 2) (c) (2x – 3)(4x 2 + 6x + 9) (d) (10 – 3y)(100 + 30y + 9y2) (e) (ab + c)(a2b2 – abc + c 2) (f ) (5x – 4ab)(25x 2 + 20abx + 16a 2b 2) (g) x(x 2 – 6x + 12) (h) 2x(x 2 + 12) (i) (x + y – 1)(x 2 + y 2 – xy + x – 2y + 1) ( j) (Thing – Yoke)((Thing) 2 + (Thing)(Yoke) + (Yoke) 2) 6. (a) 2(x – 2)(x + 2) (b) 2(3a – 2b)(3a + 2b) (c) 3(4x + 3y)(3x – y) (d) (y + 2)(x – 1)(x + 1) (e) 7(2 – x)(2 + x) (f ) 4(x – 3y) 2 (g) –2(x – y) 2 (h) (a – 2)(a + 4) (i) 4(2x – 3)(2x – 1) ( j) 2(a – 17)(a + 17) (k) 3(x – 2)(x 2 + 2x + 4) (l) x 2(y – 3)(y 2 + 3y + 9) (m) a 2b(b – 2)(b 2 + 2b + 4) Page 58 Mills & Kelly (Power of Maths) (n) –2(x + 3)(x 2 – 3x + 9) (o) (cosq + sinq )(1 – sinq cosq ) 7. (a) (x + y – 9)(x + y + 9) (b) (a – b + 3)(a + b + 3) (c) (a + 4b – c)(a + 4b + c) (d) (a – b – 4c)(a – b + 4c) (e) (x 2 + y 2)(x – y)(x + y) (f ) (x – y)(x + y)(x 2 + xy + y 2)(x 2– xy + y 2) (g) (a – b)(a – b – 1) (h) x(x – 1) 2 (i) (x2 + 1)2 ( j) (a + b)(a – 1)(a2 + a + 1) 8. (b) a2 – 4b 2, (a – 2b)(a + 2b) (c) 5x 2 – 12x + 4, (5x – 2)(x – 2) Exercise 4 1. €(98y – 30x) 2. (a) P = (2x + 4y + 6) m (b) A = (xy + 2y + 2) m 2 3. P = xy 2 – x 2y = xy( y – x) 4. (2005x + 4000y + 2000) c 5. (a) (i) P = (2x + 2y) m (ii) A = (xy) m 2 (b) 100 m, 600 m 2 6. (a) L = (2x + 4y + 6) m (b) A = (2xy + 4y) m 2 (c) y = 1·5 m 7. (a) (i) x + 1 (ii) 2x + 1 8. (a) 2πr (b) 8r (c) πr 2 (d) 4r 2 (e) 4r 2 – πr 2 9. (a) (2x + 1·5y) m (b) (1·8x + 1·3y + 41) m 10. (a) x(x + 2) m 2 (b) x(x – 2) m 2 (c) 4x m 2 Chapter 4 Exercise 5 1. (a) 3x – 7 (b) 4x 2 – 7x – 5 (c) 9x 3 – 2x 2 – 5x + 1 (d) – 8x 3 + 5x 2 + 4x – 1 (e) 2x 3 + 3x 2 + 5x 2. (a) x 2 + (k + 1) x + k (b) 2kx 2 + (k + 2)x + 1 (c) kx 2 + (2 – k)x – 2 (d) –2x 2 + (1 + 2k)x – k (e) x 3 + (k + 1)x 2 + kx (f ) x 3 + (–k – 1)x 2 + (k + 1) x – k (g) 2kx 3 – 10x 2 – kx + 5 (h) 3x 3 + (3k – 1)x 2 + (–k – 6) x + 2 (i) 6x 3 + (2k + 3)x 2 + (k – 6)x – 3 ( j) x 3 + (k – c)x 2 + (d – kc)x – cd 3. (a) k = 4 (b) k = 2 (c) a = 6, b = 1, c = –2 (d) 2x + 1 (e) (2x –7), k = –30 (f ) k = 8, a = 15, b = –29 (g) (i) 10x 2 –17x + 3 (ii) 20x 2 – 34x + 6 __ 34x + 6 (h) (i) x 2 – 2 (ii) x2 + 2√3 − 4 (iii) 20x 2 – __ (iii) 2x2–3√3 x − 6 4. (a) (x + 1), k = 2, l = 3 (b) (x – 2), b = 3, k = –11 (c) k = –6, a = 6, (3x – 1) (d) k = 7, (x – 1), (x + 4) (e) k = –6, x 2 – 3 (f ) k = 4, b = –16, (4x + 2) 5. (b) 3 (d) (ii) f (x) = (x 2 – a 2)(x + 1) (e) (3 – x), (x + 1), (2 – x) (h) a = 2, b = –3 Exercise 6 1. (a) –1 (b) –x (c) x + 3 (d) x (e) x 2 (f ) 5x + 7 (g) x 2 + 2x + 4 (h) x + 1 (i) 2x 2 – 3x ( j) –4x – 12 2. (a) x 2 + 5x + 4 (b) x 2 – 5x + 5 (c) 2x 2 + 3x – 1 (d) 5x 2 – 3x + 6 (e) x 2 + 5x (f ) –2x – 3 (g) x 2 – 1 ©The Dublin School of Grinds (h) 3x 2 + 2x (i) 9x 2 + 3x + 1 ( j) (x – 2) 3. (a) x + 2 (b) 10x 2 + 22x + 10 Exercise 7 (α − β) (α + β) x2 − 2 1 − 2x ___________ ____________ 1. (a) ( –2 (b) _____ (c) (d) ( x αβ (x − 1)(x − 2) (m − 1) (m + 1) a+1 1 (g) 0 (h) ________ (e) − ___ (f ) _____________ m 8x 20(a + 2) x+2 8 2a (i ____________ ( j) ____________ 2. (a) ___ (i) (x + 10)(x + 2) 5b x(x − 1)(x + 1) 2 y – 3y + 9 b a (b) − _13 (c) − ___ (d) __ (e) 1 (f ) 1 (g) _________ 4a y–3 b (3 + 2a) (3 − 2a) (2a − 3b) 2 _________ (h) ______________ (i) (i 36 a2 (2y + 3x) (x − 8y) ( j) ______________ (k) (x – 2) 2 (x + 2) 3. (a) 2x 2xy +1 6 1 _ _x____ (b) __ 2x (c) − 5 (d) 2 (e) 5a – 2 (f ) 3(2b + 1) (g) x − 1 6 3x 2 (h) x 2 + y 2 (i) x + y ( j) 3x – 2 4. (a) __2 (b) ( ___ (c) _16 2 x + 1 + 2 2x x (d) x + 1 (e) ______ (f ) − _____ (g) – t 3 x+3 2x − 1 Chapter 5 Exercise 8 1. (a) 27 (b) 32 (c) 625 (d) 100 000 000 (e) 1 (f ) 1 __ (g) –1 (h) 16 (i) –243 ( j) _14 (k) _49 (l) − _18 (m) __ 25 (n) 4 16 121 ___ (o) ___ 16 (p) − 8 125 49 1 1 1 __ __ 2. (a) _12 (b) _19 (c) __ 64 (d) 25 (e) 16 4 2 1 1 1 _ _ _ _ __ __ (f ) __ 18 (g) 3 (h) 2 (i) 3 (j) 6 (k) 6 (l) 6 (m) 64 (n) − 27 5 (o) __ 27 8 3 3. (a) 27 (b) 5 (c) 125 (d) 16 (e) _16 (f ) _14 (g) 1 1 _ _ (h) 8 (i) ___ 500 ( j) 28 (k) 2 (l) 3 (m) 1 000 000 (n) –32 3 3 1 2 2 2 _ _ _ _ _ (o) __ 10 (p) 2 (q) 3 (r) − 3 (s) − 2 (t) 1 (u) 3 (v) –3 (w) 3 3 3 _7_ _5_ __ _3_ 13 1 9 27 __ 2 2 6 2 (x) _5 ( y) __ 4. (a) 2 (b) 3 (c) (d) 7 (e) 5 64 _5_ 22 _3_ 6 3 (f) 1027 (g) ( __3 (h) 23 (i) 3 2 ( j) 53 5. (a) a9 (b) a21 2 _1_ _3_ _3_ 1 4 4 (c) a (d) a (e) a 3 (f ) a 2 (g) a4 (h) a12 (i) __2 ( j) a 2 a _2_ __ _7_ 23 1 __ 3 2 2 5 (k) a (l) a (m) a (n) 3 (o) a 6. (a) x 4y (b) 2x 5 a 2 1 (c) 4x (d) ___2 (e) 2 (f ) 2x 5 y (g) 2 2x (h) x × 2 4x (i) __3 x 2x 2x − 1 8 4 y x 5 3 __ b ( j) _____ (k) ___2 (l) (a + 3b) 5 (m) xy (n) _____ 12 2 81 z 2x Page 59 Mills & Kelly (Power of Maths) _1_ ( j) log5 y 9. (b) 2·5 mg (c) 87·5% 10. (a) 1∙2597 (b) €7347 (c) €9255 Exercise 9 __ __ __ ___ __ 2√ 2 ____ 1. (a) 2√ 3 (b) 3√ 3 (c) 11√ 10 (d) 16√ 2 (e) 3 ___ __ __ __ ___ 2x √ 3x 7√ 3 3√ 2 ____ ____ (f ) 5 (g) 10 (h) 2x√ x (i) 2xy √ 2y ( j) ______ y _ 30 ___ __ __ 4z √z ((k) k ______ 2. (a) 3√ 11 (b) − 4 + 15√ 3 (c) 3x − 7√ y 3xy __ __ __ ___ (d) 0 (e) 0 (f ) 5√ 2 + 5√ 3 (g) 0 (h) √ x (i) 3ay √ ay _____ __ __ __ ( j) – 4√ x − 3 3. (a) 2√ 2 (b) √ 6 (c) 60√ 3 __ __ __ __ __ (d) 6(1 + √ 2 + √ 3 ) (e) 4 + 2√ 3 (f ) 2 (g) ab(√ a + √ b ) ___ __ (h) 20 + 2√ 91 (i) – 6 ( j) 4x + 9y + 12√ xy (k) 1 ______ __ (l) –3x + 2√ x (m) a − √a2 − x 2 (n) x3 − x2 − 2x + 2 __ __ __ 9 1 4 (o) x – 1 ( p) x − 1 (q ) 16y__− y (r) x__+ x + 4 __ __ y2 x 2√ 2 5 2 2√ 3 _√__ _√__ ____ ____ __ __ (s) 2 + x − 2 4. (a) 5 (b) − 2 (c) 3 (d) 5 y __ __ __ ___ __ __ x√ y_ 3 42 √ xy √ _√__ ____ ___ ____ (e) − 2 (f ) 14 (g) y __(h) y (i) √ 2 −__1 ( j) 3 + 2√ 2 __ __ 3 + √5 10x + 15√x ______ __________ (k) 3√2 + 2√3 (l) 2 (m) 9 − 4x __ __ _____ 4x (n) 5 + 2√6 (o) √a + √a − x 5. 0 6. (a) ____ √ R3 10. (a) (i) P1 = 2π ____ __ GM _d_ 13. (a) T1 = 2π g (b) 4x(4 – x 2) ____ 7. 11 (ii) P2 = 16π √ __ √ 3 R ____ GM √ _d_ (b) T2 = π g Exercise 10 __ 1. (a) 2 (b) –5 (c) –1 (d) 12 (e) –1 (f ) –2 (g) _23 (h) – 4 3 _ (i) 4 ( j) − 2 _1_ 2 1 __ –2 2. (a) 289 = 17 (b) 16 = 4 (c) 16 = 4 (d) 4 = 16 2 (e) _14 = 16 _4_ 2 _1_ −2 _3_ (i) 16 = 8 3 ( j) 8 = 16 4 (f ) 3 = 3 1 (g) 1 = a0 (h) a = bc 3. (a) log215 (b) log3 4a 2 (c) loge (1 – x 2) (d) 0 (e) log5 y (f ) log4 (x 3 – 1) (g) log3 e 3x – 1 (h) 1 (i) logk (x – 1) ( j) 0 4. (a) 1 (b) 1 (c) loge (x – 1) (d) log5 49 (e) log4 (x – 1) (f ) log3 e2 (g) log9 3 = _12 (h) 1 (i) 1 ( j) loga x 2 ( ) ( ) 5. (a) log2 125 ___ ____ 1 1 (b) log3 49 (c) log4 5 (d) log2 216 (e) logk y 2 __ 1 (f ) log5 (1 + x 2) (g) log3 zy (h) log7 4y (i) loge 2x ( ) ©The Dublin School of Grinds log5 4 logb y log2__ 5 ___ _____ _____ ( (b) (c) log5 7 log2 3 log b a log7 (x − 2) log___ _________ ___ _____ _____ ea 1 1 (d) (d (e) (f ) (g) loge 10 log3 5 logx 4 log7 5 _____ 1 (h) (i) logx 2 ( j) log xe log5 x ( ) 1 _5_ (o) _____ ( p)) a2y2 (q ) 2x (r) y (s) x y (t) 2x2y 2 2 2a y ___ 1 7. (a) 121 500 (b) 88 573 500 (c) 729 8. (b) 16 6. (a) 7. (a) (i) 2 loga x + _12 loga y (ii) 2 log2 u + 3 log2 v (iii) log5 3 + _12 log5 x – 2 log5 p – 3 log5 q (iv) 2 + 3 log3 x – 6 log3 y (v) –2 (vi) 2 logk (x + 3) + 3log k (2x – 1) (vii) 7 log2 (x + 7) − 2 − _12 log2 (2x – 3) (viii) _12 log5 (x − 1) − _12 log5 (x + 1) (b) (i) a + b (ii) 3a + b (iii) 2b – 3a (iv) a + b + 1 (v) b + 1 (vi) 4b (vii) 4a – 3b (viii) 2a + 2 – 3b (ix) 4a + b _______ 2a + b 8. (a) (i) 2 (ii) 1 (iii) 1 (iv) 0 (x) _____ b 3 2 x y x−1 √ _______ (iii) log3 ________ (b) (i) log5 x 2 y (ii) logk ____ _1_ 4 √(x + 1)3 z 7 _____ _3_ 2(x + 5) ________ (v) log4 a 2 (vi) loga √x + 1 (iv) log3 (4x − 1)3 _1_ 3(3x + 2) x + e −2 (viii) lo g x 14. (a) 7 (vii) loge ________ e _3_ 2 2 (x + 1) __ 1 _ (b) 4 (c) 2 (d) 3 (e) 8 (f ) √x { { } ( ) ( ) } 15. (a) 3 (b) n(n – 1)(n – 2)…1 = n! 17. (a) (i) 50 dB 5 (ii) 110 dB 19. (a) 54 (b) _2 (c) 50 (d) 2 Revision Questions __ 3 7 − √5 (b) k = –13, (x – 2), (x + 3) _______ 1. (a) 2 __ ___________ 1 (c) (2x – 1) 2. (a) −√3 (b) (x + 2)(x + 4) 1 3. (a) a = 5, b = –2, c = –12 (c) x4 + __4 4. (a) 3 x _____ 2x (b) x − 1 (c) (i) a = 2, b = 1, c = 3 (ii) a = –1, 5. (a) p 3 + 3p 2q + 3pq 2 + q 3 (b) 35 p 4q 3 __ ________ 3 6. (a) 3 (b) (i) − (ii) 2x – 1, k = 2 + 2√3 2(x + 4y) (c) a = 2, b = 3 7. (a) 1 000 000 000 001 b = –3 2 (b) (i) __ 8. (a) 172 800 (b) 491 520 99 (ii) 1 + 2x __ ___1__ _______ 2 1 9. (c) 1·26 11. (a) x (b) − x + 2 (c) x (x + 2) ___2__ __2___ 8 5 (d) _5 m−1, _8 m 12. (a) x − 2 hours (b) x + 2 hours 8 (e) 3 min 26 s (c) Th The man, bigger speed (d) ______ 2 x − 22 13. (a) 3200 × 2t; 3200 (b) 100 × 22t; 100 (c) 2t – 5 (i) _18 (ii) 1 (iii) 32 (d) The number in sample B is less than the number in sample A for the first 5 minutes but after that it is always bigger 10 Page 60 Mills & Kelly (Power of Maths)