Gradient of an Interval The ‘gradient’ of a line (or interval) is the measure of how steep the line is. Another word for gradient is ‘slope’ D B The interval AB is not as steep as the interval CD C A The gradient of AB < the gradient of CD Gradient is defined as ‘the ratio of the vertical rise to the horizontal run between two points on a line’ gradient m vertical rise horizontal run Page 1 Gradient of an Interval Positive and Negative gradient As you move along a line from left to right: B Vertical rise A If it slopes upwards, it has a positive gradient. Horizontal run C If it slopes downwards, it has a negative gradient. Vertical rise Horizontal run D Page 2 Gradient of an Interval - Horizontal and Vertical Lines y A horizontal line has a gradient of ‘zero’ 6 5 In this case the vertical rise is zero 4 vertical rise mAB horizontal run 0 mAB 3 3 A B Horizontal run 3 units 2 mAB 0 x 1 y 2 3 4 5 6 A A vertical line has an ‘infinite’ gradient 6 5 vertical rise 3 units 4 3 In this case the Horizontal run is zero 2 mAB B x 1 2 vertical rise horizontal run 3 0 mAB 3 4 5 mAB undefined 6 Page 3 Gradient of an Interval - Positive, Negative or Neither State whether each of the following lines has a ‘positive gradient’, ‘negative gradient’ or ‘Neither’ y y 1 y 2 3 x x Positive x Negative y y 4 y 5 x Negative Neither 6 x Neither x Positive Page 4 Gradient of an Interval - Rise over Run Calculate the gradient of each of the following lines. A 1 A 2 6 3 A 2.5 8 B 5 B B 8 3 mAB rise run mAB mAB 6 3 mAB mAB 2 NB: Positive gradient rise run mAB 8 8 mAB mAB 1 NB: Negative gradient mAB rise run 2.5 5 1 2 NB: Positive gradient Page 5 Gradient of an Interval - Rise over Run Calculate the gradient of each of the following intervals. 1 y 2 B y 8 8 7 7 6 6 6 units 5 4 3 3 A 5 units 5 4 2 A B 7 units 2 3 units 1 1 x 1 mAB 2 rise run 3 4 5 6 mAB 7 6 3 8 9 x 1 2 mAB 3 rise run 4 5 6 7 mAB 8 9 5 7 mAB 2 Page 6 Gradient of an Interval The gradient, m , of a line passing through the points A(x1,y1) and B(x2,y2) is given by: - The Gradient Formula y 7 B( x2 , y2 ) 6 Rise 5 4 mAB mAB vertical rise horizontal run y2 y1 x2 x1 y2 y1 3 Run 2 A( x1 , y1 ) C ( x2 , y1 ) x2 x1 1 y y m 2 1 x2 x1 1 2 3 4 5 6 7 x Page 7 Gradient of an Interval The gradient, m , of a line passing through the points A(1 ,2) and B(7 , 6) is given by: - The Gradient Formula y 7 B(7,6) 6 vertical rise horizontal run y2 y1 x2 x1 mAB mAB 62 mAB 7 1 4 mAB 6 2 mAB 3 Rise 5 4 4units 3 Run 2 C (7, 2) A(1,2) 6units 1 1 2 3 4 5 6 7 x Page 8 Gradient of an Interval - The Gradient Formula y The gradient, m , of a line passing through the points A(-2 , 3) and B(3 ,-2) is given by: vertical rise horizontal run y2 y1 x2 x1 4 A 3 2 1 mAB mAB 3 (2) 2 3 5 5 mAB mAB mAB 1 x -4 -3 -2 -1 1 2 3 4 -1 -2 B -3 -4 NB: The gradient will be negative Page 9 Gradient of an Interval - The Gradient Formula When using the ‘gradient formula’ you don’t need to plot the two points and draw the interval. Just substitute straight into the ‘gradient formula’ Calculate the gradient of the interval joining the points A(7,3) and B(6,5) mAB y y 2 1 x2 x1 mAB A( x1 , y1 ) B( x2 , y2 ) A( 7, 3) B (6, 5) y2 y1 x2 x1 53 67 2 1 mAB mAB mAB 2 NB: The gradient is negative Page 10 Gradient of an Interval - Using the Gradient Formula Try this one: Calculate the gradient of the interval joining the points M(-3,6) and N(4,-9) mAB y2 y1 x2 x1 A( x1 , y1 ) B( x2 , y2 ) M ( 3, 6) B (4, 9) 9 6 4 (3) 15 7 15 7 mMN mAB mAB NB: The gradient is negative Page 11 Gradient of an Interval - Using the Gradient Formula Try this one: The gradient of the interval joining the points C(-3,1) and D(-5, x) is -2 Calculate the value of x mCD y2 y1 x2 x1 x 1 5 (3) x 1 2 2 2 C ( x1, y1 ) D( x2 , y2 ) C ( 3, 1) D(5, x) mCD 2 Substituting values Simplifying 4 x 1 Multiplying both sides by -2 5 x Adding 1 to both sides x5 Reversing sides Therefore, point D has co-ordinates (-5,5) Page 12