9/2/2019 Chem 110 Chem 110 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 1/250 9/2/2019 Chem 110 01 Matter and Energy Chemistry is all about matter, its properties and transformations and the associated energy changes. The properties of a sample of matter are dictated by its composition and structure. For chemists, the smallest functional building blocks of matter are atoms. For a defined grouping of atoms (a system), the identity of atoms involved and their spatial (3dimensional) arrangements determine, among other properties, the energy of that assembly. Changes in those arrangements are accompanied by changes in energy. For transformations where atom identities are preserved, the mass-conservation and energy-conservation laws govern the changes. For nuclear reactions, where atoms may change their identity, mass-energy is preserved (E = mc2). 01-1 Atomic structure An atom consists of a nucleus, occupied by neutrons and positively-charged protons, and a negatively-charged electron cloud that surrounds the nucleus and is attracted to the protons within it by electrostatic force. The chemical identity of an atom (its assigned element symbol) is determined by the number of protons in the nucleus (i.e. its atomic number). The elements often exist as a mixture of isotopes—variants of atoms with the same atomic number but a different number of neutrons. 01-2 Avogadro’s number On a macroscopic scale, chemists “count” atoms by weighing. Since the atomic mass unit (amu) is defined such that 1 g of a substance contains Avogadro’s number of such units, the mass in g that is numerically equal to the atomic mass in amu (for atoms) or molecular mass in amu (for molecules) contains Avogadro’s number of atoms or molecules. Such a number of atoms or molecules is defined as a mole. 01-3 Ions and molecules Atoms rarely exist in unchanged atomic form. Their electronic structure is modified when they become ions by loss or gain of electrons, or when they combine to form molecules or extended networks by rearranging their electron clouds. The details of the 3-dimensional arrangements of atoms in such compounds are responsible for overall energy and other properties. 01-4 Introduction to energy Chemical systems have two dominant energy components: the potential energy of the electrostatic interactions between charged particles, and the kinetic energy of particles in motion. Energy can be exchanged with the surroundings through the transfer of heat and work. Adding heat or performing work on the system increases the energy of the system (ΔE > 0), while removing heat or having the system perform work decreases its energy (ΔE < 0). 01-5 Enthalpy For processes taking place under constant pressure, the heat exchanged between the system and the surroundings is called enthalpy. Enthalpy is an extensive function (dependent on the amount of matter) and is a function of state. It depends on the state (P, V, T), but not on the path used to reach that state. Changes in enthalpy are a convenient measure of changes in the internal energy of a system that is undergoing a chemical or physical transformation. Processes with ΔH < 0 are called exothermic, and those with ΔH > 0 are endothermic. 01-6 Light energy Electromagnetic radiation, the purest form of energy, sometimes exhibits wave-like properties and is typically characterized by its wavelength (λ) or frequency (ν). The electromagnetic spectrum covers a wide range of frequencies, all of which have energies proportional to ν. A narrow part of that spectrum, the visible range, is detectable by human eyes. Under other conditions, electromagnetic radiation behaves as a stream of photons (small packets of energy). This situation-dependent dual behavior (wave-like and particle-like) is common in the atomic world, where energy is granular rather than continuous. The emission of light from material objects (black-body radiation) and the light-induced ejection of electrons from metal surfaces (the photoelectric effect) provide windows on the quantum nature of that microscopic world. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 2/250 9/2/2019 Chem 110 01-7 Spectroscopy The study of how photons of light interact with matter is called spectroscopy. Light may be transmitted or reflected by the system under study, typically without energy being exchanged, or it may be absorbed or emitted by the system in processes that convert one form of energy into other forms. These energy conversion processes are quantized, providing an opportunity to probe the internal structure of matter. Visible light spectroscopy illustrates how the intensity of light of all colors is affected when the light beam passes through a sample, with some wavelengths being absorbed by the molecules in its path. In general, the results of light absorption depend strongly on the energy of the absorbed photons. Typically, highly energetic photons (gamma, X-ray, ultraviolet) ionize atoms and molecules, and break bonds whereas lower energy photons (visible, infrared, microwave, radio waves) do not damage the molecules, but in all cases most of the delivered energy eventually leads to increased kinetic energy of the sample, i.e. it is converted to heat. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 3/250 9/2/2019 Chem 110 01-1 Atomic structure Atoms are composed of protons and neutrons held in the nucleus surrounded by an electron cloud Ordinary human senses perceive the world on a macroscopic scale (down to 10–3 m sizes), but the actual chemistry happens on a nanoscopic scale (10–9 m or less). On this scale, the basic building blocks of matter are atoms. The kinds of atoms present (composition) and their arrangements (structure) are responsible for the observed macroscopic properties and behavior of matter. Chemists must think in terms of miniscule and directly invisible atoms to be able to understand the workings of the tangible substances of the macroscopic world. Atomic sizes and masses are very small. Atoms are 100 to 500 pm in diameter (1 to 5 Å where 1 Å = 100 pm = 10– m), with the heaviest having masses on the order of 10–22 g. They are built from even smaller subatomic particles, only three of which have bearing on chemical behavior: the proton, the neutron, and the electron. Protons and neutrons reside in the extremely small nucleus of the atom (ca. 10–14 m) and account for virtually all of the mass of the atom. The vast majority of volume of the atom, on the other hand, is essentially empty space occupied by a “cloud” of rapidly moving electrons, which contribute negligibly to the mass of the atom. 10 Figure F01-1-1. The structure of an atom showing the nucleus (composed of protons and neutrons) surrounded by the electron cloud. In all drawings the nucleus is shown out of proportions to the size of the atom. If drawn on scale, it would be unnoticeably small. Electrons and protons are held together by an attractive electrostatic force The electrons do not fly away from the atom because they are attracted to the protons in the nucleus by an electrostatic force that is proportional to the magnitude of the charges (Q1 and Q2) on the interacting particles and inversely proportional to the square of the distance (r) between them. That relationship, known as Coulomb’s law, is shown below, where k is just a proportionality constant: Fel = kQ1 Q2 r E01-1-1 2 An electron has a negative charge of –1.602 × 10–19 coulombs (C). The charge of the proton is equal in magnitude to that of an electron, but has the opposite sign (+1.602 × 10–19 C). Neutrons, as the name indicates, have no charge (are neutral). Atoms, as a whole, have no net charge, as the number of electrons is equal to the number of protons. Because both the masses and charges of the elementary particles comprising atoms are so small, for convenience atomic units have been defined in such a manner that electric charge (au) is expressed as a multiple of the electron charge, and the atomic mass unit (amu or just u) is 1.66054 × 10–24 g; exactly 1/12 of the mass of carbon-12 which contains 6 protons and 6 neutrons in its nucleus (see below). The charge and masses of the components of atoms are collected in Table T01-1-1. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 4/250 9/2/2019 Chem 110 Table T01-1-1. Atomic components Particle Charge (C) Charge (au) Mass (kg) Mass (amu) proton p+ +1.602 × 10−19 +1 1.6726 × 10−27 1.0073 neutron n0 0 0 1.6749 × 10−27 1.0087 electron e− −1.602 × 10−19 −1 9.1094 × 10−31 5.486 × 10−4 The chemical identity of an atom is designated by an atomic number, and is determined by the number of protons in the nucleus. Any one element from the periodic table is a collection of one or more atoms with the same number of protons in their nuclei. The variety of material objects in our world is the result of various combinations of any of just about 100 different elements. Isotopes are atoms with the same atomic number but a different number of neutrons Atoms of a given element can differ in the number of neutrons in their nuclei and consequently in their mass. Such atoms are called isotopes of one another. For example (Figure F01-1-2), in addition to the most abundant isotope of hydrogen, protium (99.98%), two other isotopes are known: deuterium, with one neutron in the nucleus (0.0156% abundance), and unstable (radioactive) tritium, with two neutrons in the nucleus (4 × 10–15% abundance). To distinguish all the possibilities, chemists have introduced a special notation. The mass number superscript lists the number of protons and neutrons, while the atomic number subscript lists the number of protons. Figure F01-1-2. The naturally occurring isotopes of hydrogen: protium, deuterium (2H = D), and tritium (3H = T). For illustration purposes, nuclei are out of proportion to atomic sizes. Since the atomic number corresponds to the atomic symbol, the use of both is redundant, and the atomic number is typically omitted (Figure F01-1-3). For example, both 12C and carbon-12 are unambiguous representations of the dominant isotope of carbon (atomic number 6). Figure F01-1-3. Examples of isotopes of carbon, oxygen and uranium. For readability nuclear sizes are out of proportion to atomic sizes. Essentially all elements have multiple isotopes that occur naturally or can be synthetically produced in nuclear reactions, but the majority of them are unstable. When an element occurs in nature as a mixture of isotopes, its atomic weight (AW) is the average of the masses of all isotopes present (E01-1-2). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 5/250 9/2/2019 Chem 110 AW = ∑ [(isotope mass) × (f ractional natural abundance)] E01-1-2 For example, naturally occurring carbon is composed of 98.93% of the carbon-12 isotope with atomic mass of 12 amu (exactly ) and 1.07% of the carbon-13 isotope with atomic mass of 13.00335. The atomic weight of carbon, as found in the periodic table, can be calculated as follows (E01-1-3): AW (C) = (0.9893)(12 amu) + (0.0107)(13.00335 amu) = 12.01 amu E01-1-3 The atomic masses and natural abundances of various isotopes can be very precisely determined in this day and age using mass spectrometry. In this technique, electrons are “kicked out” of atoms in a vacuum and the resulting ions travel in a magnetic field that bends their paths according to their mass/charge ratio. Special ion detectors are then used to calculate the ratios of ions with different masses. It is important to note that in chemical reactions the nuclei of atoms remain unchanged. Only the electron clouds are modified. Thus, no atoms can be transformed into other atoms, and, of course, no atoms may be destroyed or created. This observation is the basis of the law of conservation of mass. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 6/250 9/2/2019 Chem 110 01-2 Avogadro’s number Avogadro's number is a conversion factor for relating grams to atomic mass units Let’s return for a moment to the idea of the atomic mass unit (amu). The unit is defined as exactly 1/12 of the mass of one atom of the carbon-12 isotope. From precise measurements we now know that 1 amu = 1.66054 × 10–24 g. We can “invert” that number, 1 g = 6.02214 × 1023 amu, to learn how many atomic mass units there are in one gram. That number should look very familiar. Indeed, it's Avogadro’s number (NA)! This number, which is fundamental to chemistry, was originally defined by studying gases (see Lesson 12-3) and trying to connect macroscopic measurements (such as the mass of the sample) with the nanoscopic world (such as the number of atoms or other matter particles in that sample). Imagine that you are asked to count identical small yellow plastic spheres in a large container. It would take a long time, and the chance of making errors would be large. How would you do it if the spheres were of atomic size? It turns out that we can use a balance for counting purposes. If the mass of one sphere were known, then a simple division of the total mass (obtained by weighing all of the spheres together) by the mass of one sphere would give a count of the spheres. By analogy, if the mass of an individual atom is known, then the atom count of any element's sample can be obtained by measuring its total mass. Figure F01-2-1. Weighing of yellow spheres. How many spheres are there in the Erlenmeyer flask, if the total mass of the spheres is 336.336 g? Click on the image for a close up. Playing along with our imaginary example, let’s assume that the yellow sphere (an atom) has a mass of 1 amu, and we have separate collections of red spheres (also atoms) with a mass of 7 amu each, and green spheres weighing in at 19 amu each. We can now prepare samples of yellow, red, and green spheres containing exactly the same number of spheres in each by weighing samples with total masses in a 1:7:19 ratio, respectively, for example, 1 g of yellow spheres, 7 g of red spheres, and 19 g of green spheres. How many spheres would these samples contain? We don’t need a calculator to determine this; each sample would contain Avogadro’s number of spheres (E01-2-1): 1 g 7 g = 1 amu 19 g = 7 amu = 6.02214 × 10 23 E01-2-1 19 amu A mole is a sample containing Avogadro's number of objects A collection (or a sample) containing Avogadro’s number of objects (spheres, atoms, electrons, molecules, or anything else ) is called a mole. It is a convenient measuring unit (not unlike a baker’s dozen) of nanoscopic objects that can be employed on the macroscopic scale. You may notice that for elements, one mole of atoms will be contained in a sample weighing the same number of grams as its atomic mass in amu units. The same is true for groupings of atoms called molecules, but the mass of the sample in grams must now match the molecular mass (molecular weight) in amu. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 7/250 9/2/2019 Chem 110 Figure F01-2-2. Samples of various compounds: (a) the large flask in the back contains hydrogen gas, H2 (2.016 g, 22.4 L), (b) the medium sized bottles from left to right: sucrose (a.k.a table sugar, C12H22O11 (342.30 g)), copper sulfate (CuSO4 (159.60 g)), sulfur (S8 (256.51 g)), aluminum oxide (Al2O3 (101.96 g)), copper sulfate pentahydrate (CuSO4•5H2O (249.68 g)), and (c) small vials in the front from left to right: water (H2O (18.02 g)), aluminum (Al (26.98 g)), zinc (Zn (65.39 g)), iron (Fe (55.85 g)), and copper (Cu (63.54 g)). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 8/250 9/2/2019 Chem 110 01-3 Ions and molecules Atoms gain or lose electrons to form anions or cations which are attracted to each other by electrostatic forces Even if atoms are the simplest representatives of an element, under typical conditions only the noble gas atoms exist as individual separate entities in unchanged form. In other forms of matter atoms are converted into ions or exist as collections of atoms bonded together into molecules or extensive networks. The formation of ions or assemblies of atoms is the result of changes in the electron arrangements around atomic nuclei while the nuclei remain unchanged. Atoms may change identity (changes in proton or neutron count) only through nuclear reactions. Structurally, the simplest chemical changes in atoms are the formation of ions. Atoms may gain or lose electrons to become ions, charged species with an excess or deficiency of electrons as compared to the number of protons in the nuclei. An ion with a net negative charge (excess of electrons) is called an anion (AN-ion) and an ion with a net positive charge (deficiency of electrons) is called a cation (CAT-ion). Figure F01-3-1. Ions are formed by the gain or loss of an electron. The chlorine atom gains one electron, resulting in an anion with 17 protons in the nucleus and 18 electrons in the electron cloud. The sodium atom loses one electron, yielding a cation with eleven protons in the nucleus and 10 electrons in the electron cloud. Other atoms may gain or lose multiple electrons, yielding ions with higher charges (for example, 2–, 3–, or 2+, 3+). These net charges on ions are represented by corresponding superscripts. Ions have different chemical properties than neutral atoms. Their behavior is dominated by strong electrostatic interactions with other charged particles. Ions with opposite charges are strongly attracted to each other, and form extended ionic solids (salts). For example, sodium cations and chloride anions combine to form a highly ordered (crystalline) solid of sodium chloride, known as table salt (F01-3-2). The formula of this solid, “NaCl,” makes the empirical ratio of sodium to chlorine obvious, but it gives us no clues as to the actual structure of the crystal they form. In general, ionic compounds are 3-dimensional arrangements of ions extending in space, which can reach macroscopic sizes—as illustrated by the crystals of sodium chloride found in everyday saltshakers. Figure F01-3-2. Sodium cations and chloride anions form ionic bonds when sodium atoms transfer an electron to chlorine atoms. When multiple such interactions take place, the result is an extended 3-dimensional arrangement (organized lattice) of alternating ions where each cation is electrostatically attracted to multiple anions (and vice versa). The 3dimensional arrangements may reach macroscopic sizes, as seen in NaCl crystals (click for a closeup). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 9/250 9/2/2019 Chem 110 Ions may also take the form of more complex multi-atom entities (see below); in addition to simple, single-atom derived ions, there are polyatomic ions composed of multiple atoms. Simple examples of such ions include NH4+ (ammonium ion), HO– (hydroxide ion), or SO42– (sulfate). In such ions, the total number of electrons does not match the total number of protons in all nuclei. The numerical excess or deficit of electrons defines their overall charge. Atoms combine to form molecules or extensive solids Atoms may also combine with other atoms without forming ions. Atoms of the same element or of two or more elements may bond together to form molecules or extensive solids. For example, the simplest element, hydrogen, exists as a diatomic molecule, H2. The most stable form of oxygen is diatomic oxygen, O2, but another form is the triatomic version O3, which is called ozone. These different elemental forms, called allotropes, have different structures and different physical and chemical properties. Carbon has a variety of allotropes, from molecular buckminsterfullerene (C60) to extended solids of diamond and graphite where carbon atoms form exquisite 3-dimensional networks, reaching macroscopic sizes (Figure F01-3-3). Formation of extended solids made of many atoms that share electrons is common for the metallic and metalloid elements. Figure F01-3-3. Examples of allotropes of carbon: a molecular version composed of 60 carbon atoms (buckminsterfullerene), a diamond network where the whole solid is one huge molecule, and graphite with its hexagonal “chicken-wire” layers. To appreciate the nuances of these 3D structures, you may interact with these models using your mouse. Molecules constructed with more than one type of atom are called molecular compounds. The number of possible combinations is practically infinite, and millions of compounds have either been isolated from natural sources or synthesized and characterized. The atoms in these compounds bond together following well-defined chemical rules that we will explore in depth in later Lessons. For now, it suffices to notice that when elements combine they have a preferred number of bonds to other atoms. For example, hydrogen and all halogens (F, Cl, Br, I) typically form just one bond, oxygen tends to form two bonds, nitrogen prefers to form three bonds, and carbon does four. The number of bonds formed is called the valence of the atom. Atoms can be “connected” via single or multiple (double or triple) bonds. Chemists commonly use a notation where each bond is represented by a line between elements to make structural drawings. Such drawings show atom connectivity, but ball-and-stick models are usually employed in order to truly appreciate the shapes of molecules. These models show bonds as sticks and identify atoms (balls) through color differentiation. Alternatively, space-filling models are used to show the space occupied by the electron clouds surrounding the nuclei of all atoms participating in formation of the molecule (Figure F01-3-4). You may have noticed that a large proportion of molecules in Figure F01-3-4 contain carbon. This is not an accident. Carbon is able to form four bonds to other carbon atoms or to atoms of many other elements, resulting in a large variety of diverse and occasionally very complex structures. Indeed, life on Earth is based on compounds of carbon — these are called organic molecules. A paragon example of such molecules is a small DNA fragment, shown much scaled down in the central panel of Figure F01-3-4. For now we can just admire its beauty, helical symmetry, and complexity while we begin our journey to comprehend molecular structures. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 10/250 9/2/2019 Chem 110 Figure F01-3-4. Examples of simple molecules in different representations. The molecular formula lists all atoms present in the molecule and their proportions. The structural formula shows how the atoms are connected, with the lines representing the bonds between atoms. In perspective formulas, the bonds may be shown as solid wedges indicating that the bond is pointing out of the page, or with dashed wedges showing a bond extending "behind" the plane of this page. Ball-and-stick models are well suited to show bond angles, while space-filling models illustrate relative sizes of atoms. Atoms are colored according to a standard scheme (check it in our interactive periodic table) that we are going to follow consistently throughout the course. You may interact with the 3D models in the central panel by clicking on stick-and-ball or space-filling pictures in the figure (the models are not to scale; they were set to fill the viewing window). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 11/250 9/2/2019 Chem 110 01-4 Introduction to energy Energy is the capacity to do work and transfer heat The concepts of matter and energy are very familiar to most of us in the context of everyday life or in science. While the concept of matter is relatively easy to define and grasp (as we can see and touch material objects), energy is much more abstract and harder to precisely define. In the broadest sense we can say that energy is the capacity to do work and transfer heat. Or, in colloquial terms, it is the ability to make something happen. Energy exists in two basic forms: potential and kinetic. Potential energy is related to the positioning of an object in relation to other objects, while kinetic energy is related to the motion of objects. The two forms of energy can interconvert, but no energy can be lost or created in any chemical or physical process. The law of energy conservation is known as the first law of thermodynamics. The SI unit of energy is the joule, (1 J = kg·m2/s2). Since energy is an extensive property (i.e. it depends on the amount of substance present), kilojoules (1 kJ = 103 × J) are often used on the molar scale (kJ/mol). Alternatively, calories (1 cal = 4.184 J) or kilocalories (kcal) are employed. There is also a nutritional Calorie unit (with a capital C), equal to 1 kcal. The kinetic energy of particle motion and electrostatic potential energy dominate chemical processes Potential energy can be thought of as “stored” energy and can manifest itself in many forms, such as electrostatic, nuclear, or gravitational energy. These types of energy are directly linked to the corresponding fundamental physical forces. On the other hand, kinetic energy (Ek) is determined only by the mass (m) and velocity (v) of a moving object (E014-1): 1 Ek = 2 2 mv E01-4-1 In terms of potential energy, chemistry is completely dominated by electrostatic forces, where the relative positioning of charged particles (nuclei, electrons, or ions) decides their energy. We already know that the force of interaction between two charged particles (with charges Q1 and Q2) is conveyed by Coulomb’s law (E01-1-1). From basic physics, we also know that work (w) is equal to force (F) multiplied by distance (r), and that energy is "equivalent" to work (w). Thus, potential electrostatic energy (Eel) can be expressed by equation E01-4-2, with the charges Q1 and Q2 in coulombs (C). The proportionality constant is called Coulomb's constant, k = 1/4πε0 = 8.99 × 109 J·m/C2 where ε0 (= 8.86 × 10−12 F/m) is vacuum permittivity. Eel = kQ1 Q2 E01-4-2 r Since electrons within atoms, atoms themselves, atoms within molecules, and whole molecules are in constant motion, kinetic energy is another energy component crucial to the understanding of chemical interactions and transformations. In fact, atomic and molecular motions constitute the “thermal” component of energy; the average kinetic energy of particles in a sample is directly related to the temperature of that sample. A “hotter” sample has faster moving particles (on average) than a “cooler” one. Heat (designated by the symbol q) may be transferred from a hotter sample to a cooler one by transferring some of the kinetic energy, for example by collisions between particles. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 12/250 9/2/2019 Chem 110 The change in internal energy of a system results from the exchange of heat or work with the surroundings The internal energy of a system (E) is the total energy associated with the system, the sum of all sources of kinetic and potential energy. In most situations, chemists do not care about “absolute” internal energy of a sample, but instead are more interested in the internal energy changes (ΔE) directly connected to a physical or a chemical process under consideration (Figure F01-4-1). Since energy cannot be created or lost, chemists define the system and the surroundings and observe the energy flow between the two to determine the energy changes from the initial state to the final state. The system is defined as a collection of particles of interest, examples of which could be an atom emitting light energy, or a mole of molecules undergoing a chemical reaction. The surroundings are defined as everything else. The energy flow is always referenced with respect to the system, in a way analogous to the balance in a bank account. Thus, if the energy of the system is lowered (by transferring some of it to the surroundings) the energy change has a negative sign (energy has been “withdrawn” from the system). On the other hand, if energy is added to the system (from the surroundings) the energy change has a positive sign (energy has been “deposited” into the system). Figure F01-4-1. Energy flow (a) from and (b) to the system. The lower the final energy, the more stable the system is in its final state. Processes where ΔE < 0 are described as being spontaneous (we will define that concept more precisely in later Lessons). Let’s consider a system constructed of two charged particles with charges Q1 and Q2, as shown in Figure F01-4-2. At infinite separation the electrostatic energy of the system is zero, as the two particles do not experience any electrostatic forces from each other. If the two particles have like charges (+/+ or –/–), bringing them closer requires work against a repulsive force. That work is done on the system (by the surroundings) and it results in an increase in the energy of the system. Conversely, if the charges are opposite (+/–), the work of bringing them closer by the attractive force is done by the system, and the result is a transfer of energy to the surroundings and a lowering of the energy of the system. Figure F01-4-2. Electrostatic energy of two interacting charges as a function of separation between them. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 13/250 9/2/2019 Chem 110 We have now discussed the two major ways in which energy is transferred between a system and its surroundings, heat (q) and work (w). Adding heat (+q) to the system and doing work on the system (+w) both increase the overall energy of the system. E01-4-3 ΔE = q + w Conversely, removing heat from the system (–q) and having the system do the work (–w) lowers the overall energy of the system. The sign convention followed in such energy transfer processes are illustrated in Figure 01-4-3. Figure F01-4-3. Illustration of sign conventions for system where (a) the heat is added to the system and work is done on the system and (b) the heat is removed from the system and work is done by the system. The internal energy of a system is a function of state The internal energy of the system does not depend on the path or method (i.e., the mechanism) used to get to the current state. It is a state function; it depends only on the existent state of the system (its temperature, volume and pressure). Let’s look at a simple example in Figure F01-4-4. The internal energy is lowest for ice, and highest for hot water, but the internal energy of the samples at 25 °C is the same, regardless whether prepared by cooling the hot water or by heating and melting the ice. In a simple analogy, the overall change in altitude when traveling from State College, PA (370 m above sea level) to Boulder, CO (1650 m above sea level) is always 1280 m, regardless of the road chosen for our trip. In this example, the altitude behaves as a state function. Figure F01-4-4. Samples of identical masses of H2O in different states: ice at 0 °C, water at 25 °C, and water at 99 °C, close to a boiling point. The internal energy of the samples at 25 °C is the same. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 14/250 9/2/2019 Chem 110 We use capital letters to signify state functions like P (pressure), T (temperature), E (internal energy), and H (enthalpy). However, heat and work (q and w) are not state functions. Depending on how we set up a process, we can release lots of heat and do little or no work, or we can force the process to do more work and release less heat. Consider the combustion of a gallon of gasoline. We could light a gallon of gasoline on fire and it will generate a great deal of heat as it burns. However, if we burn the gasoline in a car engine we can use the released energy to power the car. Some heat will still be produced, but a substantial fraction of the energy will be used to do work. In each case the total amount of energy released by the burning of the gasoline will be the same, but the relative amount of heat and work produced is different (ΔE = q + w). Figure F01-4-5 This figure depicts a process where the internal energy of the system is lowered by two different paths. Path 1 (blue) may correspond, for example, to the situation where a reaction produces heat, but does not do any work. Path 2 (orange) may represent (for example) the process where the system does work and produces a small amount of heat. Despite the different paths, the change in internal energy is the same. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 15/250 9/2/2019 Chem 110 01-5 Enthalpy Enthalpy is the heat exchanged with the surroundings under constant pressure Let's assume we have two flasks that start in the same state, and contain the same amount of dry ice (solid CO2) at room temperature. One flask is closed with a stopper and one has a deflated plastic bag over the mouth of the flask. Let's further assume that the same amount of heat (q) enters each of these systems at the same rate. Room temperature (25 °C) is higher than the temperature of the dry ice (−78 °C), and the solid will change into a gas as it warms up. The internal energy of both systems will increase as the samples warm up, but will the two systems end up with the same amount of internal energy? The one with the stopper remains at constant volume because it cannot expand; the pressure rises (F01-5-1a). The system with the bag remains at constant pressure (at least initially) because its volume can expand (F015-1b), while performing work against the ambient pressure. Figure F01-5-1. (a) The system absorbs heat from the surroundings at constant volume. No work is done by the system. (b) The system absorbs heat from the surroundings at constant pressure (until the bag is fully inflated). The work done by the system on the surroundings, against ambient pressure (P), is w = PΔV. At any point in time (before the bag fully inflates) after an equal amount of heat is absorbed by both systems, which one will have the higher internal energy? The system that absorbs heat at constant P (F01-5-1b) does work on the surroundings that lowers its internal energy. The system that absorbs heat at constant V does no work and therefore will have a higher internal energy. Anyone watching the flasks will be waiting for the cork to pop off the flask in Figure F01-51a. And it does! Eventually, when the bag is fully filled, it breaks as well under the increasing pressure of CO2. In chemical and physical changes occurring under constant pressure, it is indeed quite common that the only work done by the system is due to volume change (ΔV). This P-V work term is particularly important when the transformation leads to a significant change in the volume of a system, as often happens for processes involving gases. Since P and V are state functions, P-V work is also a state function, and under constant pressure, when only heat and P-V work contribute to energy changes, we can write (E01-5-1): ΔE = qp + w = ΔH − P ⋅ ΔV E01-5-1 The heat exchanged with surroundings under such conditions is called enthalpy (qp = ΔH). Like internal energy, enthalpy is a state function. It is a very useful quantity as it is relatively easy to measure (we will learn how in later Lessons), and for many reactions in liquids or solids where change in volume is small or zero, it directly matches the changes of the internal energy of the system. Internal energy and enthalpy are both extensive properties, as they depend on the quantity of the matter in the system. Transfer of heat to and from the system during chemical and physical processes is so common that chemists use special names to indicate the direction of the heat flow. Processes where ΔH > 0 (i.e., the heat flows into the system) are called endothermic (endo means “into”), while processes where ΔH < 0 (with heat transfer to the surroundings) are called exothermic (exo means “out of”). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 16/250 9/2/2019 Chem 110 01-6 Light energy Light is an electromagnetic wave Light is the “purest” form of energy, as it may exist “outside” of matter. On one hand it is an electromagnetic wave traveling with enormous speed (approximately 3 × 108 m/s). On the other hand, it interacts with matter as a stream of energy packets (or photons). This dual behavior (wave-like and particle-like) is dependent on the situation, and is characteristic of the quantum world we are about to enter in order to learn more about the detailed structure of atoms and molecules. An electromagnetic wave propagates in a direction that is at right angles to the vibrations of both the electric and magnetic oscillating fields, carrying energy from its source. The two fields are mutually perpendicular. Their amplitudes oscillate through a repeating pattern of peaks and troughs. Figure F01-6-1. A schematic representation of an electromagnetic wave. The magnetic and electric fields oscillate in planes perpendicular to each other and to the direction of propagation. The wavelength (λ) is the distance between two adjacent peaks (or troughs). The maximum amplitude of the waves is a measure of intensity of the radiation. Waves have characteristic wavelengths (λ), as measured by a peak-to-peak distance. Regardless of their wavelengths, all electromagnetic waves move with the same speed, c (c ≈ 3 × 108 m/s in a vacuum). Thus, instead of using wavelengths, the waves can be characterized by the frequency ν, which is the number of cycles that pass a given point per second (E01-6-1). The frequency is usually expressed in cycles per second (s−1) or in hertz (1 Hz = 1 s−1). c = λν E01-6-1 The properties of waves depend on their wavelengths. The wavelengths of electromagnetic radiation span an enormous range, from kilometer-long radio waves to subatomic-length gamma rays. The "visible" light spectrum, a very narrow range of electromagnetic radiation detectable by human eyes, has wavelengths of 400—750 nm (1 nm = 10−9 m), with different wavelengths perceived as different colors of the rainbow. Figure 01-6-2 shows the whole spectrum of electromagnetic waves arranged by their wavelengths with the visible part of the spectrum expanded for emphasis. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 17/250 9/2/2019 Chem 110 Figure F01-6-2. The spectrum of electromagnetic radiation with the visible spectrum emphasized. Both wavelength and frequency ranges are shown. For the sake of convenience, different wavelength units are commonly used for various regions of the spectrum (top). Electromagnetic radiation exhibits typical wave behavior. The light waves diffract when they encounter small obstacles or small openings to pass through, generating interference patterns in a way similar to those commonly observed in water waves (Figure 01-6-3) wherein overlapping wave peaks increase in intensity and overlapping peaks and troughs diminish the wave amplitudes. . Figure F01-6-3. Diffraction of light waves, producing an interference pattern of alternating dark and light regions on the screen. The "arriving" wave (left) passes through two slits and two propagating waves form. The propagating waves' crests are shown as arcs (partial circles). Most sources of light in the visible range produce collections (spectra) of different wavelengths with different relative intensities. For example, the unique combination of all “rainbow” colors delivered from our sun is perceived as “white” light. There are some sources that produce just a few discrete wavelengths, and there exist monochromatic sources (such as lasers) that emit just one wavelength of light. Soon we will learn how we can use the interactions of light with matter to gain an understanding of the fine structures of matter. The study of these interactions is called spectroscopy. Light is also a stream of photons which are quantized energy packets Not all light-involving phenomena can, however, be explained in terms of wave characteristics alone. For example, the distribution of frequencies of radiation emitted by a heated body, so called black-body radiation, cannot by accounted for by classical wave physics. This distribution depends on the temperature of the solid. At lower temperatures infrared frequencies are emitted, but with increasing temperature the heated body starts emitting visible light, brown at first, then, red, orange, yellow, and white at high enough temperatures. Only in 1900 did German physicist Max Planck realize that objects couldn’t gain or lose energy in arbitrary or continuous amounts, but could only transfer energy in discrete “packets” of some minimum size (or its multiple). The packets of energy were named quanta, and thus quantum physics and quantum chemistry were born. Planck proposed that the energy, E, of a single quantum is proportional to the frequency of the radiation, with the proportionality constant, h (now known as Planck’s constant) equal to 6.626 ×10–34 J·s. E = hν https://genchem.science.psu.edu/sites/default/files/filefnlBYE E01-6-2 18/250 9/2/2019 Chem 110 In quantum theory, matter can emit or absorb energy only in whole-number multiples of hν (hν, 2hν, 3hν, …. or NAhν, for a mole of quanta). This limitation means that on a microscopic (nanoscopic) scale the energy transfer is “granular” rather than continuous. On a macroscopic scale, we do not perceive this granularity simply because the quanta of energy are so small. Even so, the quantization of energy rules at the atomic level. With this new insight we can now understand how wavelengths govern the properties of electromagnetic waves. Long waves (large λ or, alternatively, small v) carry small amounts of energies while short waves (small λ or large v) are very energetic. Radio waves are low on the energy scale; they barely deliver any energy and are unable to affect chemistry in any significant way. At the other extreme, gamma rays, X-rays, or even ultraviolet radiation (UV) carry a big punch, with energies equal to or exceeding the energies typically involved in chemical interactions. These high-energy waves can be quite destructive. We have just learned that matter (as exemplified by the black body) can only emit electromagnetic radiation in a quantized fashion. Is the same true when material objects absorb light waves? Einstein provided the first affirmative answer to this question when he explained the photoelectric effect, the phenomenon in which only light of proper frequency can eject electrons from an illuminated metal surface. The effect was accounted for by the fact that the light, despite its apparent continuous nature, can only deliver energy to a metal’s electrons in a quantized form. A packet (quantum) of light energy, called a photon, has to be energetic enough to at least match the energy holding the electron within the metal in order to be able to eject the electron. These phenomena, black-body radiation and the photoelectric effect, illustrate that light (electromagnetic radiation) can exhibit a “corpuscular” nature in its interaction with matter. We also seen light behaving like a classical wave when it diffracts and forms interference patterns of light and dark areas. This wave-particle duality turns out to be the governing phenomenon in the quantum word, and as we will see shortly, it also applies to elementary particles such as electrons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 19/250 9/2/2019 Chem 110 01-7 Spectroscopy Spectroscopy is the study of how light interacts with matter We have just learned about light carrying energy as an electromagnetic wave or a stream of photons. When light interacts with matter its energy may be converted to other forms of energy, and energy contained within matter may be converted into light. We have already described two examples of such energy conversions, the photoelectric effect and black-body radiation. In general, such energy-conversion processes are quantized (the energy exchanged is delivered in discrete "packages"), and therefore provide a great opportunity to study energy levels within the material to be investigated, probing its internal structure. To do it effectively, we need precise information about the incoming and outgoing light energy. What wavelengths (energies) are involved? Do they all interact with our sample to the same extent? Let us consider a very familiar part of the electromagnetic radiation, the visible spectrum (Figure F01-7-1). The range of wavelengths from around 400 nm to 750 nm is called visible light because it is detected by human eyes. Any photons in that range are detected by the cone and rod cells in the retina, the detected signal is processed by the optic nerve in the back of the eye, and then interpreted by our brain. If all wavelengths in the visible range are represented, we perceive it as white light. Isaac Newton (in 1665 at age of 23!) using prisms and mirrors showed that the white light can be split into colors that can then be recombined back into the white light. He also arranged colors into the color wheel (Figure F01-7-1), discovering their "complementary nature". Typically, the colors we see are the result of some sort of filtering of portions of the visible spectrum that reaches our eyes. For example, if the orange light is filtered, we see the blue color from the opposite side (180°) of the color wheel while filtering red results in green color. Thus, our color perception most often depends on the part of the spectrum of white light that is "missing". Figure F01-7-1. The visible spectrum can be represented as a color wheel. If the range of wavelengths represented by a certain color are filtered, the complementary color (across the wheel) is observed. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 20/250 9/2/2019 Chem 110 When visible white light interacts with macroscopic transparent objects it can be transmitted through it (the light is usually refracted as well). If the object is clear (like glass), all wavelengths of visible light are transmitted. If the medium is colored (such as a colored solution), then light of that color is transmitted while the wavelengths of light corresponding to the complementary color are absorbed by the medium (Figure F01-7-2a). Similarly, an opaque material reflects the wavelengths of light that correspond to the observed color which is complementary to the color being absorbed by the sample. For example, a white piece of paper reflects all wavelengths of visible light, a black piece of paper absorbs all wavelengths of light, and a green piece of paper reflects green light while absorbing (mainly) red (Figure F01-7-2b). Finally, when light is emitted by matter, e.g., the radiation from a light stick (Figure F01-7-2c), the perceived color matches the wavelengths given off by the system. If an object can be seen when it is otherwise completely dark, then the object is emitting visible light. Figure: F01-7-2. Macroscopic objects appearing green: (a) a solution that transmits green light, absorbing red, (b) an object that is reflecting green light (and absorbing red), and (c) a light stick that is emitting green light. The absorption of light is measured by a spectrophotometer To measure the energy exchanged with the material under study we need an instrument that can quantify the portion of light absorbed at all wavelengths of interest. The instrument that accomplishes that task is called a spectrophotometer. In our example, it is used to measure the absorption and transmission of light by the sample over the the visible range of wavelengths. In a way, our eyes are nature's spectrophotometers (see above); they can distinguish wavelengths (colors) with 3-10 nm resolution and detect light with intensity differences of 10 orders of magnitude. What our eyes lack are the measurement scales. A simplified diagram of a spectrophotometer is shown in Figure F01-7-3. A light source is used to produce wavelengths needed to examine the sample. A monochromator (such as a prism or a diffraction grating) is used to separate the wavelengths of light, and a movable slit can be used to select the specific wavelengths to be measured in turn while exploring the full spectrum. The light then passes through a sample cell and is detected on the other side. The detector measures the intensity of light transmitted through the sample and determines the decrease in its amplitude for each wavelength as compared to the original intensity at the source (measured with a "blank" sample). The absorption spectrum obtained is a plot of absorbance (the logarithm of fraction of light absorbed) as a function of the wavelength of the light (see Figure F01-7-3). The absorbance at a given wavelength depends on how many molecules are in the path of the light beam (i.e. concentration of the sample), the length of the path (i.e. the sample "width"), and the probability that the molecules absorbs a photon of this wavelength. Figure F01-7-3. Schematic representation of a simple spectrophotometer. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 21/250 9/2/2019 Chem 110 As explained above, in visible spectroscopy, the wavelengths of light transmitted correspond to the complementary color of the light absorbed. Figure F01-7-4 shows the spectrum of two dye solutions. The spectrum on the left represents a solution of a blue dye. The maximum absorbance is in the range of 620 – 640 nm (corresponding to orange and red). The complementary color (across the color wheel from this range of wavelengths) is blue, so the sample appears to be blue. In the spectrum on the right the maximum absorbance is in the range of 480 – 540 nm (mainly green). The complementary color for this range of wavelengths is red. Not surprisingly, this solution appears to be red. Figure: F01-7-4. Absorption spectra of a blue (left) and red (right) dyes. The blue dye absorbs mainly in the orange and red region, while the red dye absorbs mainly in the green region. Light energy absorbed by atoms or molecules is converted into various forms of kinetic or potential energy What happens on a molecular level when light interacts with matter? When light is transmitted or reflected both the light and the medium are mainly unchanged (sometimes the light is bent by the medium, as a result of its speed being changed). The outcome is dramatically different when the light is absorbed by the material: the energy is transferred and changes occur at the atomic and molecular level. The specific changes depend on the energy of the incoming photons and the structure of the molecules in the absorbing medium. Indeed, much of what we know about the structure of matter is the result of studies of how atoms and molecules change when photons are absorbed. When an atom or molecule absorbs energy, the photon energy is converted into different forms of kinetic or potential energy. In most absorption processes the light energy eventually is converted into kinetic energy, referred to as translation, increasing the velocity of the particles. This type of energy is directly related to the temperature of the collection of molecules, so an increase in translational kinetic energy is perceived as an increase in heat. High-energy photons such as gamma, X-rays and ultraviolet rays can damage or break molecules by causing ionization or bond scission when a photon is absorbed. In these situations, the energy of the absorbed photon is converted into potential energy by creating high-energy ions or molecules with unpaired electrons (free radicals). The absorption of visible light also results in the photon energy being converted into potential energy when electrons in atoms or molecules move to higher energy states called excited states (a concept we will explore more in Chapter 2). Photons of lower energy (infrared and microwave) do not damage molecules, but increase amplitudes of their vibrations and speed of their rotations, respectively. Absorption of photons in all of these situations increases the total energy in the system and much of the energy is eventually converted to heat through particle collisions. Table T01-7-1 describes the possible molecular changes upon absorption of energy. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 22/250 9/2/2019 Chem 110 Table T01-7-1. The types of changes that occur at a molecular level when photons are absorbed. Radiation λ gamma < 0.01 nm X-ray 1 − 10 nm ultraviolet 10 − 400 nm visible 400 − 750 nm infrared 750 nm − 1 mm microwave 1 mm − 1 m radio >1m Interaction with matter Ionizes atoms and molecules Breaks chemical bonds Ionizes atoms and molecules Breaks chemical bonds Ionizes atoms and molecules Breaks chemical bonds Promotes electrons to higher energy (electronic transitions) Promotes electrons to higher energy (electronic transitions) Increases amplitudes of vibrations (kinetic energy increases) Increases speed of molecular rotations (kinetic energy increases) Flips the nuclear spin https://genchem.science.psu.edu/sites/default/files/filefnlBYE 23/250 9/2/2019 Chem 110 02 Hydrogen Atom Based on everyday experience, we often assume that nature is continuous and precisely measurable. Given a good enough scale, we think, we could measure any amount of graphite (carbon), or equipped with a powerful enough microscope we would be able to observe electrons in atoms with ease equal to watching bouncing ping-pong balls in a lottery machine in slow motion. On the atomic and molecular scale, however, these assumptions break down. We find that not only mass and charge, but also energy all come in discrete packets. We cannot have a half of a carbon atom (it would not be a carbon atom anymore), or an imperfect proton with just ⅔ positive charge, and the energy of an electron in an atom can only change in a stepwise manner. Moreover, we learn that there is a limit to the precision of our measurements. We cannot know simultaneously the momentum and position of an electron in an atom with a satisfactory certainty. Instead of the neat deterministic Newtonian mechanics we enter a weird granular and probabilistic quantum world. In that unintuitable world, light shows particle-like behavior and small particles display wavelike properties in their motion. The light and matter interact by exchanging quantized amounts of energy, and probability replaces certainty. In this Chapter we begin to explore some basic ideas of quantum chemistry in order to understand the electronic structure of atoms and their chemical properties. 02-1 Line spectra Atoms emit characteristic colors of light when excited with some forms of energy. For atoms in the gas phase, these colors correspond to light with discrete individual wavelengths whose collections are called line spectra. Each line represents uniform packets of energy sent out when electrons within an atom transition from one energy level to another with lower energy. The observation of a number of sharp spectral lines indicates that an electron can have only precisely defined energy in the atom and that it can change energy only in a stepwise manner. 02-2 Bohr's model To explain line spectra of hydrogen atom, Bohr proposed a “planetary” model wherein the electron is allowed to circle the nucleus only in specific orbits with set (quantized) energy described by the principal quantum number (n). If an electron changes its orbit (change in n), energy is absorbed or emitted in the form of a photon (quantum of electromagnetic radiation) matching the energy difference between the orbits. Bohr’s model works very well for the hydrogen atom and ions with just one electron, but fails for atoms or ions with more electrons. 02-3 Matter waves On the atomic scale, matter has dual particle-like and wave-like properties. Positions and momentum of small particles, including electrons in atoms, cannot be simultaneously determined with sufficient precision (Heisenberg’s uncertainty principle). Instead, electrons are described by standing waves around atomic nuclei. The squared values of these wavefunctions at any given point of space correspond to the probability of finding the electron in an immediate vicinity of that point. That probability density is called electron density. For atoms (and molecules) electron densities and allowed energies of electrons are found by solving the Schrödinger equation that describes the potential energy of all electrostatic interactions between electrons and nuclei, and the kinetic energy of electrons. 02-4 Quantum numbers The solutions of the Schrödinger equations for atoms are called orbitals. The orbitals have discrete energies and they mathematically describe the spatial distribution of electron density (where the electrons are likely to be in the relation to the nucleus). These orbitals can be distinguished in a short-hand notation by a set of quantum numbers that include the principal quantum number (n), the angular momentum quantum number (ℓ), and the magnetic quantum number (mℓ). In the hydrogen atom, only n determines the energy of the orbital, while ℓ and mℓ control the shape and spatial orientation of the orbital, respectively. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 24/250 9/2/2019 Chem 110 02-5 Orbitals The atomic orbitals have characteristic shapes, sizes and energies associated with their quantum numbers. The wavefunctions, their squares (electron densities), and radial probabilities are used to visualize the electron distribution around the nucleus. These graphical representations allow us to see what the most probable spaces for electrons are, and where electrons are not allowed to be (nodes). In a simplified pictorial version, we present only artificial “skins” (isosurfaces) selected in such a way that the probability of finding an electron inside the demarcated space is 90%. These boundary surfaces may be labeled with the algebraic sign of the wavefunction from which they are derived. Such qualitative graphical representations are in most cases satisfactory for understanding of the basic electronic structure of atoms (or molecules). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 25/250 9/2/2019 Chem 110 02-1 Line spectra Excited atoms in the gas phase emit light of discrete wavelengths Imagine that you are given a sealed black box and you would like to find out what’s inside. You do not have any tools to open it, yet curiosity pushes you to explore. You might lift the box to see how heavy it is, or shake it and see if something rattles inside. Perhaps you may bang it with your hand, or even kick it if it is too large to lift, to see how it responds. When probing matter, scientists tend to do the same, although in a bit more sophisticated way. For example, they may provide some energy to the sample they want to explore to see if any information comes back. We have seen how in the photoelectric phenomenon the light energy sent to the sample resulted in release of electrons with different kinetic energies. We have briefly explored visible light spectroscopy to see which colors (energies) are absorbed. We have also encounter a reverse situation in black-body radiation. When given energy in the form of heat, the sample responded by emitting light, which could be studied for its distribution of frequency and intensity. These experiments teach us that light when it interacts with matter, behaves as a "stream" of photons and that matter sends out energy in quantized forms. Similar experiments can tell us about the internal structure of matter. The analysis of conversion of thermal and electromagnetic forms of energy within samples under study opens a window on the inner workings of atoms and molecules. For heated solid samples (black-bodies) continuous spectra are observed (see F01-4-2) without any fine features, and therefore, without much detailed structural information. We can suspect that strong interactions between closely-packed atoms in solids complicate the analysis. However, when separate atoms of various elements are excited in the gas phase, the observed emission patterns are much simpler. Figure F02-1-1. Neon lights made out of discharge tubes filled with Ne (left image) and glowing discharge tubes containing different gases (from left to right): H2, Ne, N2, O2, and Hg (vapor). We are all familiar with the neon lights commonly encountered in the commercial and entertainment districts of our cities (F02-1-1). These lights are sealed glass tubes fitted with metal electrodes at the ends and filled with various gases, with neon (Ne) being a common one because of the attractive color it generates when excited. When a high-enough electric potential is applied to the electrodes, an electric discharge takes place inside the tube, and the energy is emitted in the form of radiation with characteristic colors and wavelengths. Figure F02-1-1 shows glowing tubes of several different gases. A closer analysis of the emitted light with the help of a diffraction grating reveals that the light sent out by the atoms is composed of several distinctive wavelengths, resulting in what we call a line spectrum. Each element produces a unique set of these spectral lines (F02-1-2), although one (or more) lines can be more intense than the rest and dominate the spectrum, giving the glowing light its characteristic color. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 26/250 9/2/2019 Chem 110 Figure F02-1-2. Line spectra of several elements. The lines have been enhanced for better visibility. For an expanded view of more elements click on the image. You may explore authentic, unenhanced line spectra of all of the elements in our interactive periodic table (click on the periodic table button above this page, then click on an element). These characteristic atomic emission colors are not limited to elements that are gases under normal conditions. Color spectra may be obtained even for metallic elements, provided that enough metal atoms get vaporized and excited. The flame tests (F02-1-3) are a simple illustration: many salts inserted into a hot, reducing flame have flame colors characteristic of the metallic atoms. The most spectacular demonstration of atomic emissions are fireworks (F02-1-4) where the reds are characteristic of strontium or lithium, greens are due to barium, blue are due to copper, orange are due to calcium, and yellow is due to sodium. Figure F02-1-3. Alcohol burning over salts of calcium (left), lithium (center), and barium (right). The Fourth of July firework shows get their colors from various metal salts. Wavelengths of light emitted by hydrogen atoms follow a simple mathematical formula called the Rydberg equation Let's take a closer look at the line spectra produced by excited hydrogen atoms, which are the simplest of them all. The four lines observed in the visible range (called the Balmer series) are just a part of the story. It turns out that a similar series of lines are detected in the ultraviolet range (the Lyman series) and several sets of lines (the Paschen, Brackett and Pfund series) are found in the infrared if proper spectroscopes are employed. Indeed, these spectra sets were discovered in the second half of 19th century and are named after their discoverers. In 1885, Johann Balmer, a Swiss school teacher, realized that the wavelengths of the lines follow an unusually simple mathematical formula. That formula was easily extended to cover all series and it is called the Rydberg equation (E02-1-1). In this equation λ is the wavelength of the spectral line (in m), RH is the Rydberg constant (1.097 × 107 m–1) and n1 and n2 are positive integers, with n2 being larger than n1. 1 λ = RH ( 1 2 n 1 − 1 2 ) E02-1-1 n 2 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 27/250 9/2/2019 Chem 110 Despite the apparent simplicity of the hydrogen atom’s spectra, it took about 30 years before progress was made on interpreting the line pattern in terms of an atomic model that accounts for the observations. Based on what we have described so far, what kind of model would you propose to account for the Rydberg equation? https://genchem.science.psu.edu/sites/default/files/filefnlBYE 28/250 9/2/2019 Chem 110 02-2 Bohr's model In the Bohr model the electron can only be in orbits that have quantized radii and energies In 1913, Niels Bohr proposed a theoretical model that accounts very well for the emission lines observed for hydrogen atoms (and one-electron ions such as He+, Li2+, and Be3+). Bohr followed up on Rutherford’s planetary model, in which an electron circles the nucleus, but added three important postulates: 1. Only orbits of certain radii, corresponding to discrete energies, are allowed for the electron in a hydrogen atom. 2. The electron in the allowed orbit (allowed energy state) does not radiate energy and, therefore, does not spiral into the nucleus, as was predicted by classical physics. 3. Energy is emitted or absorbed by the atom only as the electron transitions from one allowed orbit to another. That energy is emitted or absorbed in the form of a photon of matching energy E = hν, with a characteristic frequency ("color"). The model was based on the simple idea that a speeding electron can remain bound to the nucleus only if the centripetal and electrostatic forces acting on it are balanced. If the electron moved too slowly in its orbit, it would be attracted by the positive charge of the nucleus and would collapse on it; if it moved too fast the attractive force would not be able to hold it within the atom and it would fly away. The groundbreaking contribution was the postulate that only certain radii of orbits are allowed and therefore the total energy (kinetic and potential) of the electron is quantized, i.e., it can only have specific values, determined by the orbit. This quantization is expressed by the principal quantum number n, a positive integer specifying the orbit number, with the orbit closest to the nucleus having n = 1, the next one n = 2, and so on. The results derived from the Bohr postulates (as shown on a separate page) are very instructive and will help us tackle more sophisticated quantum models in the future. The first important corollary of the model is the existence of discrete orbits whose distance from the nucleus increases in a stepwise manner. In one-electron species, the radii of the allowed orbits (E02-2-1) are proportional to the square of the quantum number and inversely proportional to the charge of the nucleus as expressed by the atomic number, which indicates the number of protons (Z = 1 for H, Z = 2 for He+, Z = 3 for Li2+, etc). The radius of the smallest orbit, a0, is used as the scaling factor. 2 n rn = Z a0 E02-2-1 n = 1, 2, 3 In fact, a0 is a convenient unit of length on the atomic scale called the Bohr radius; it has a numerical value of 5.29 × 10–11 m = 0.529 Å. For historical reasons, it is marked with subscript "0", even if it corresponds to the orbit with n = 1. The kinetic energy of the electron is determined by its velocity (v), which is orbit-dependent (E02-2-2). The velocity is inversely proportional to the quantum number, with v1, the velocity in the smallest orbit, serving as a scaling factor: vn = Z v1 E02-2-2 n = 1, 2, 3 n The result tells us that electrons move the fastest in the smallest orbit (n = 1) with velocity v1 = 2.2 × 106 m/s (just about 1% of the speed of light!). Such a large velocity keeps it from "falling" on the nucleus, as the electrostatic attraction is the strongest because of small orbit radius. The electron moves slower in the larger orbits as the attraction to the nucleus decreases with the orbit size. Finally, the most important result relates the allowed values for the total energy of the electron to the quantum numbers (E02-2-3), where E1 represents the energy of the electron in the smallest orbit (n = 1): 2 Z En = − E1 2 n = −(2.18 × 10 −18 2 Z J) 2 n = 1, 2, 3 E02-2-3 n For the same reason that we introduced the Bohr radius, it is convenient to express energies of atomic levels in units of rydberg (1 rydberg = 1 Ry = hcRH = 2.18 × 10–18 J, where RH is the Rydberg constant in E02-1-1). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 29/250 9/2/2019 Chem 110 The emission or absorption of photons by hydrogen atoms result in electron transitions between orbits The energies of the allowed orbits in the hydrogen atom are all negative and inversely proportional to the square of n (the principal quantum number). The lower the energy (the more negative), the more stable the atom is, and n = 1 is the lowest energy orbit possible. When the electron occupies the orbit closest to the nucleus (n = 1), the hydrogen atom is in the ground state (the lowest energy state). As n gets larger, the energy increases by becoming less negative in steps proportional to 1/n2. In a way, we have a peculiar ladder with rungs representing the different allowed energy levels (F022-1a). The rungs are far apart at the bottom of the ladder and are increasingly closer to each other as we climb. The higher we climb, the higher the energy of the atom. Figure F02-2-1. Energy levels for the hydrogen atom. The reference point (E = 0) has the electron and proton at rest and at infinite separation. As the distance between them gets smaller, the attraction increases and the energy gets lower and more negative. In this case, negative energy is arbitrarily chosen as attractive energy. The energy of individual levels is inversely proportional to n2, resulting in unequal and decreasing spacing between energy levels at higher n values. For more details click on the pictures in Figures F02-2-1a, b, c. a) Energies and energy differences for several low n values are illustrated on a per atom and per mole basis. b) Electron transitions from a higher (less negative) energy orbit (larger n) to a lower (more negative) orbit result in the emission of photons with matching energies. Transitions to the lowest orbit (n = 1; the Lyman series) give off UV light, transitions ending at n = 2 produce photons in the visible region (the Balmer series), and transitions down to higher orbits (n ≥ 3) result in IR photons being emitted. c) Absorption of photons of the appropriate energy promotes electrons from a lower orbit to a higher one. The resulting absorption line-spectrum in the visible region is illustrated. That spectrum is complementary to the emission line-spectrum in F02-2-1b . An ultraviolet light with λ = 91 nm has sufficient energy to eject the electron from a ground-state hydrogen atom. That photon energy corresponds to the hydrogen ionization energy (IE). At the limit (n = ∞) the energy is zero. Indeed, this state is our energy reference point. We always compare the energy of the hydrogen atom to the energy of a proton and an electron that are at rest and at infinite separation. We can now return to our line spectra (F02-1-2) and illustrate what happens when the electron transitions from one energy level to another. In the emission process, energy is given off by the atom as the electron moves from a higher orbit to one with lower energy that is closer to the nucleus. The Balmer (visible light) series corresponds to transitions down to the orbit with n = 2 (F02-2-1b). The higher-energy ultraviolet Lyman series involves transitions down to the ground-state (n = 1), while the Paschen, Bracket and Pfund lower-energy infrared series have orbits with n = 3, 4, or 5, respectively, as the final electron destinations. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 30/250 9/2/2019 Chem 110 The energy difference between the final orbit (Ef) and the initial orbit (Ei) can be easily calculated using E02-2-3. This energy corresponds precisely to the energy of the emitted photon. ΔE = Ef − Ei = (−2.18 × 10 −18 J) ⋅ ( 1 1 − 2 2 n E02-2-4 ) = hν n f i For example, ΔE for the lowest-energy line in the Balmer series (nf = 2, ni = 3) is a negative number. Since this is an emission line, the negative sign is fully consistent with our convention that the system (hydrogen atom) is giving off energy to the surroundings (F01-4-1). ΔE = Ef − Ei = (−2.18 × 10 −18 1 J) ⋅ ( 1 − 2 2 2 ) = −3.03 × 10 −19 J E02-2-5 3 This energy is, of course, also the energy of the emitted photon. To calculate the wavelength of that emission we use the standard frequency-to-wavelength conversion, ΔE = hν = hc/λ. λ = hc (6.63 × 10 −34 J ⋅ s)(3.00 × 10 8 m ) s = ΔE 3.03 × 10 −19 = 6.56 × 10 −7 m E02-2-6 J Notice that we have not included the negative sign of the energy in this calculation. Wavelengths and frequencies are always expressed as positive quantities. The direction of the energy flow (from the atom to the surroundings) in such cases is indicated by stating that the photon was emitted. You may compare the calculated wavelength with one experimentally observed (F02-1-2). The Bohr model predicts that we can also excite hydrogen atoms with light. For example, if we direct a beam of white light at a sample containing hydrogen atoms and collect the light after it has passed through, we notice that some wavelengths are missing (black lines). Such an absorption spectrum is shown in F02-2-2. Figure F02-2-2. Absorption spectrum of hydrogen. Missing wavelengths (black lines) correspond to wavelengths absorbed by the sample, resulting in the promotion of electrons to higher orbits. Only the wavelengths that exactly match the energy differences between orbits are absorbed and, therefore, no longer detected by the spectroscope. This experiment illustrates nicely the complementary nature of emission and absorption spectra (compare with F02-1-2). Sufficiently energetic photons can eject electrons from atoms causing ionization We can carry out the absorption experiment to an extreme. If we use light that is energetic enough, we should be able to remove the electron completely from the hydrogen atom. The smallest amount of energy to accomplish that for the ground-state hydrogen atom corresponds to the electron jump from ni = 1 to nf → ∞. It is called the ionization energy (IE), since we are producing a separate ion (proton, H+) and an electron. It is easy to figure out (E02-2-4) without doing any calculations that the value of ionization energy for the hydrogen atom is +2.18 × 10–18 J. We may calculate the IE value for one mole of hydrogen atoms by multiplying the per-atom energy by Avogadro’s number. IE = (6.02 × 10 23 atom mol ) (2.18 × 10 J −18 atom https://genchem.science.psu.edu/sites/default/files/filefnlBYE kJ ) = 1310 E02-2-7 mol 31/250 9/2/2019 Chem 110 This prediction agrees very well with the experimentally determined value (see L04-2) and adds to our confidence that the model is at least a good approximation of the internal structure of the simplest atom. Unfortunately, that simple model fails to accurately explain the spectra of atoms and ions having more than one electron, except at the most rudimentary level. The underlying weakness of the model is that it relies on the idea that an electron behaves in a deterministic fashion as a small particle circling the nucleus in an orbit. As we will learn next, this corpuscular description of electrons does not apply on the atomic scale. Nevertheless, Bohr’s model has taught us some valuable lessons about electrostatic interactions between electrons and nuclei, the kinetic energy of electrons, quantized energy levels, sizes of orbits, and interactions of light with atoms (atomic spectroscopy). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 32/250 9/2/2019 Chem 110 02-3 Matter waves Subatomic particles and atoms exhibit dual wave-particle behavior We have already seen examples of the dual wave-photon behavior of electromagnetic radiation. For example, the photoelectric effect was explained by considering light as a stream of packets of energy called photons that may transfer their energy through collisions, quite like material particles. How about the reverse situation? Can electrons, or any small particles of matter behave as waves when in motion? In 1924 Louis de Broglie first proposed that a beam of electrons can be diffracted just like a beam of light or a water wave. Such matter waves, referred to as de Broglie waves, are at the center of quantum theory and another example of wave-particle duality. Photons, electrons, neutrons, and even atoms all have both wave-like and particle-like characteristics. How we observe or measure them decides which aspect they display. Of course, we do not have to worry that a baseball thrown 100 miles per hour will “wave” its way to the catcher’s glove. Ordinary-size objects have incredibly small and undetectable wavelengths. Indeed, the de Broglie wavelengths (λdB) may be used as a guide to distinguish the classical behavior of the macroscopic objects from the quantum world. Only objects for which λdB is comparable to the size of the object will show these dual particle-wave characteristics. Just a few years after de Broglie’s proposal, the wave properties of electrons were demonstrated through a diffraction experiment on a crystal (F02-3-1a). You may appreciate the similarity of that pattern to the one made by laser light waves passing through crossed diffraction gratings. Since then, the technique of electron diffraction has been highly developed to obtain images on the atomic scale. The electron microscope (F02-3-1b) can magnify objects by 3 × 106 times (electron waves may have wavelengths comparable to X-rays), much more than can be achieved with visible light (103 magnification). Figure F02-3-1. From left to right: (a) Electron diffraction pattern from a silicone crystal, (b) electron microscope, and (c) electron-microscope image of a flea. De Broglie postulated that in a one-electron atom the quantization may have the same matter wave origin, but in this case the electron behaves as a standing wave. In the hydrogen atom the wave would have to be circular and to be a persistent, well behaved wave, an integral (quantized) number of wavelengths would have to fit into the circumference of the circular orbit (Figure F02-3-2). Figure F02-3-2. Standing circular wave (left) and a non-integer wave structure (right). No persistent wave can form if an integral number of wavelengths do not match the circumference of the circle such as the structure on the right. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 33/250 9/2/2019 Chem 110 The inevitable consequence of the de Broglie standing wave description of the electron in an atomic orbit is that we cannot simultaneously know the precise position and the momentum of the electron. After all, even if the momentum (mv) is known precisely, the position of the electron is “spread” around the circle. (F02-3-2). That “uncertainty” was shown mathematically by Werner Heisenberg to be an unavoidable consequence of the dual nature of matter. The Heisenberg principle (called the uncertainty principle) puts a fundamental limit on the precision with which we can simultaneously determine the momentum and position of atomic-scale particles. Electrons in atoms are described by quantized wavefunctions whose squares represent electron density Even if we cannot know the exact position and momentum of the electron, we can talk about the probability of it being within certain volumes of space around the nucleus. That was the approach taken by Erwin Schrödinger, who in 1926 formulated the equation (E02-3-1) bearing his name that opened a new way of dealing with subatomic particles, now known as quantum mechanics. The applications of the Schrödinger equation require advanced calculus, but its solutions and some important basic ideas may be presented graphically in a qualitative but useful manner. HΨ = EΨ E02-3-1 At first glance the equation looks quite simple, but the “quantum devil” is in the detail. It all starts with de Broglie’s idea that electrons in atoms are described by standing waves. The mathematical expressions of these waves are called wavefunctions and are usually represented by a Greek Ψ (psi). The waves cannot be measured directly (they have no physical meaning), but their squares (Ψ2) represent the probability of an electron residing in a given tiny volume of space; this probability is called the electron density. The wavefunctions for an atom (or a molecule, or any quantum system) are found by solving E02-3-1. In that equation, “ℋ” hides a set of mathematical operators (mathematical instructions on how to manipulate the wavefunction) that calculate all energies of the system including all electrostatic interactions between all nuclei and electrons and the kinetic energies of all electrons. The results of the calculations are the energies of the quantum systems, E, and the wavefunctions describing them. Before we look at the specific solutions for a hydrogen atom, let’s play with some waves and wavefunctions (Figure F02-3-3). As you will discover, some experience at the beach may help us to conquer the quantum world. Figure F02-3-3. (a) Water wave produced by a bounced droplet and (b) the cross-section of the water wave. When "frozen" in the picture, the shape sufficiently illustrates the concept of a "standing" wave, analogous to standing electron waves in atoms. A familiar wave is created when a water drop hits the water surface and bounces back as immobilized in the picture. Here is our standing wave: tall in the middle, then dropping below the level of the undisturbed water surface, to climb again, and drop again in a series of concentric hills and valleys, frozen by the camera to be examined in detail. If we produce a cross-section trace of the water’s surface on graph paper, with the height of the water’s surface represented on the vertical axis (z) and the separation from the center on the horizontal axis (x), we get a mathematical function that has positive algebraic values in the upper part of the plot and negative values below the x axis. The function in F02-3-3b is two dimensional, for each point [x] we have a value of the wavefunction as read off of the z-axis [Ψ(x)]. If we spin our function around the z axis we can recreate the water’s surface. That surface is threedimensional; for each point [x,y] in the xy plane the function has a value expressed on the z axis [Ψ(x,y)]. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 34/250 9/2/2019 Chem 110 To transition to atomic wavefunctions we have to add another dimension. For each point in space [x,y,z] around the nucleus we have to specify the value of our wavefunction [Ψ(x,y,z)]. Unfortunately, displaying things in four dimensions is rather difficult. We will rely on various cross-sections to pare the dimensionality (as we did in our water-wave example here) or use other graphical “tricks” to simplify the presentation. The probability of finding an electron in a miniscule volume of space around a point [x,y,z] is equal to the square of the value of the wavefunction at this point. We need to use these tiny volumes (dxdydz cubes, for those mathematically inclined) as points themselves have no volume. This electron density (probability per unit volume) can be visualized as a fraction of an electron in that minuscule volume cube. Notice that squared values are never negative, as probability must be positive, even if the wavefunctions may be negative in certain regions of space. Electron density is a directly observable quantity. Many modern techniques allow us to probe it and have successfully verified the predictions of quantum theory. Now we have completed the transition of our understanding of electrons in an atom from a particle in an orbit to a probability wave. Next, we will explore these electron density distributions, called orbitals, in more detail. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 35/250 9/2/2019 Chem 110 02-4 Quantum numbers Orbitals identified by sets of quantum numbers, n, ℓ, and mℓ, represent electron density distributions in atoms Solving the Schrödinger equation for a hydrogen atom gives us a series of wavefunctions with their associated specific energies describing the ground-state and excited states of the atom. These solutions are called orbitals in order to distinguish them from the deterministic orbits of Bohr’s model. Each orbital has a characteristic shape and size reflecting the distribution of electron density. Since there is only one electron in the hydrogen atom, that electron, depending on its energy, can be described only by one of these wavefunctions at any given time. We say that the electron occupies that orbital and has the energy of that orbital. Nevertheless, for convenience, we talk about all orbitals as objects in existence all the time. Strictly speaking, the orbital "exists" (i.e. represents electron density) only if occupied, but if its electron’s energy changes (by absorption or emission of light, for example) the unoccupied orbitals "are there" ready to serve as a new “home” for that electron (now of different, “new” energy). The Bohr model arbitrarily introduced the principal quantum number n to describe an orbit. The solutions to the Schrödinger equation are characterized by three quantum numbers, which result naturally from the wave mathematics used to calculate them. 1. The principal quantum number n can have positive integral values (n = 1, 2, 3...) as in Bohr’s model. As n increases, the orbital becomes larger, and on average the electron spends more time farther away from the nucleus. Because of the diminished electrostatic attraction, the energy of the orbital increases with n and it does so in exactly the same manner as it did in Bohr’s model (E02-2-3). The energy En increases proportionally to 1/n2; En = RyZ2/n2 (the Rydberg equation), where Z is the atomic number and also the nuclear charge (Z = +1 for the hydrogen atom). 2. The angular momentum quantum number, ℓ can take on any integral value from 0 to (n–1). This quantum number defines the shape of the orbital. For historic reasons, specific values of ℓ have letter designations as shown below. For higher values of ℓ, the alphabetical order is followed with g for ℓ = 4 and so on. value of ℓ 0 1 2 3 letter designation s p d f 3. The magnetic quantum number, mℓ can have integral values between –ℓ and ℓ, including zero. This quantum number describes the spatial orientation of the orbital. Orbitals are grouped into shells of the same n and subshells of the same ℓ Although there are an infinite number of orbitals possible for the hydrogen atom, we will be mainly interested in those that have low energy, i.e. those with low values of n. The table below collects some of the possible orbitals to illustrate their characteristic pattern. Table T02-4-1. The allowed values of quantum numbers for n = 1, 2, and 3 n 1 2 ℓ 0 0 mℓ 0 0 subshell designation 1s 2s 2p 3s 3p 3d number of orbitals in a subshell 1 1 3 1 3 5 number of subshells in a shell 1 2 3 number of orbitals in a shell 1 4 9 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 3 1 −1 0 0 +1 0 1 −1 0 2 +1 −2 −1 0 +1 +2 36/250 9/2/2019 Chem 110 The collection of orbitals with the same value of n is called an electron shell. The set of orbitals that have the same n and ℓ values is called a subshell. Each subshell is designated with a number (n) and a letter corresponding to the value of ℓ (shown in bold in the table). There are (2ℓ+1) orbitals in each subshell. The total number of subshells for each shell is equal to n, and the total number of orbitals in each shell is equal to n2. You may continue to develop this pattern with n = 4, to find 4 subshells (4s, 4p, 4d, and 4f) and a total of 16 orbitals, the last 7 of them belonging to the 4f subshell. The total number of orbitals in consecutive shells multiplied by two (2, 8, 18, 32) hints tantalizingly at the structure of the periodic table (as these numbers match the number of elements in various rows). Of course, that relationship is not accidental, as we will discover in Lesson 03. The relative energies of hydrogen orbitals exactly follow the pattern of Bohr’s model (compare to F02-2-1). In Figure F02-4-1, each box represents an orbital and the boxes are grouped according to their subshell designations. As already indicated, the energies of hydrogen orbitals depend only on the value of n. Thus, all orbitals of a given shell have the same energy. Such orbitals of the same energy are called degenerate orbitals. The 1s orbital has the lowest energy. If it is occupied by the electron, the hydrogen atom is in its ground state. If the electron occupies any of the other orbitals (including those not shown in the figure with n > 3) the hydrogen atom is in an excited state. At ordinary temperatures, essentially all hydrogen atoms are in the ground state, unless energy is absorbed by the atom resulting in a transition. Transitions between orbitals (absorption or emission) follow exactly the same pattern as that described for Bohr’s model (F02-2-1). Figure F02-4-1. Energies of atomic orbitals in the hydrogen atom (s, p, d, etc.) follow the pattern of the energy levels of Bohr's orbits. Each box represents one orbital, and orbitals (boxes) of the same shell have the same color. The orbital energies are inversely proportional to n2, and the energy differences between them diminish with increasing n. For n ≥ 2, each energy level is represented by several degenerate (equal energy) orbitals. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 37/250 9/2/2019 Chem 110 02-5 Orbitals Orbitals describe the probability of finding electrons in defined areas around the atomic nucleus Imagine that we find very special 3D cameras on sale. We get a few hundred of them and give them to several sections of CHEM 110 students for a weekend project. Each student gets a camera and just one hydrogen atom in a special box. Their task is to take as many photographs of their hydrogen atom as possible. You know that in the real world this would not be possible for many reasons, but there are few limits to our imagination. We collect all the digital pictures taken and add them together in "Photoshop 3D" in such a way that all nuclei are perfectly aligned at the point where the Cartesian axes intersect. In our special pictures, the nucleus is invisible, but electrons show up as dots. Our congregate image (F02-5-1) represents a measure of the probability of finding the electron in different volumes of space around the nucleus of the ground-state hydrogen atom. F02-5-1. Pointillist representations of hydrogen orbitals obtained in an imaginary experiment, where students are "photographing" electrons (in 3D) with a special camera. Thousands of dots illustrate the probability of finding one electron in different spaces around the hydrogen nucleus located at the origin. Click on the orbital pictures to explore them in the 3D viewer. You may easily discern the probability distribution pattern. It has spherical symmetry, with high electron density toward the center (nucleus) and low and diminishing densities at the outer edges of our observation box. By taking thousands of pictures of thousands of electrons in thousands of individual positions in thousands of atoms, we have learned about the probability of finding one electron in the different regions of space surrounding the nucleus. Interestingly, the collections of pictures from students from some class sections showed different patterns (Figure F02-5-1). It turns out that some students were given imaginary boxes with an extra energy supply (batteries included!) that kept the hydrogen atoms in various excited states. Some of these probability patterns (shown here as slices) are still spherical, but they have larger spreads than that observed for the ground state hydrogen atom. They also have some white spaces in their interiors, illustrating regions where electrons are not allowed to be (these are called nodes). Other probability distributions are a bit more complicated. They have “directionality” and more complex node patterns. These pictures are our first introduction to the different shapes and sizes of hydrogen orbitals. All orbitals with spherical symmetry are s-type orbitals: 1s, 2s, and 3s with n and ℓ defined ( ℓ = 0). The dumbbell shapes are p-type orbitals, 2p and 3p (ℓ = 1) with nodes at the nucleus. They are representatives of a 3-piece set in each case. The last one illustrated in F02-5-1, 3d, belongs to a 5-member club (ℓ = 2) of even more diverse profiles. In hydrogen atoms, orbitals with the same n are degenerate, so 3s, 3p, and 3d would all have the same energy. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 38/250 9/2/2019 Chem 110 Spherical s orbitals increase in size as the value of the principal quantum number increases In reality, the shapes, sizes and directions of orbitals are obtained by solving the Schrödinger equation (E02-3-1). These mathematical functions (i.e., wavefunctions) for s-type orbitals are plotted in Figure F02-5-2 in various representations. 1s 2s 3s Figure F02-5-2. The wavefunctions (top), electron densities (middle), and radial density distribution (radial probabilities, bottom) for 1s, 2s, and 3s hydrogen orbitals as they spread out from the nucleus positioned in the center of the plots (r = 0). The distance from the nucleus (r) is given in bohrs (ao) and Å. Click on the plots to explore them in more detail. The first set of plots illustrates the wavefunctions for 1s, 2s, and 3s hydrogen orbitals. These functions have the highest value at the origin (which is at the nucleus) and they drop off equally in all directions as the distance from the center (r) grows; they have spherical symmetry. The wavefunctions for 2s and 3s extend further from the center than 1s, have regions of positive and negative values, and have nodes in spots where the wavefunctions change their sign. These functions have no physical meaning, but you can compare the 3s function to our water wave (F02-3-5b) to appreciate the analogy. The squares of these wavefunctions represent electron density. They show the probability of finding an electron in a tiny volume of space around each point of atomic space. These are given as fractional numbers (or probabilities) per unit volume. The squares of the wavefunctions are always either zero or positive; probabilities must be positive. The electron density is the highest at the nucleus and drops off as r increases. In a fashion parallel to the wavefunctions, the number of nodes increases with the value of n. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 39/250 9/2/2019 Chem 110 The relationship between these wavefunctions and our imaginary photographs (F02-5-1) is shown in the cutout 3D representations ("onion-layer" spheres) where the color intensity varies with values of electron density. These are indeed some of the “tricks” of visualizing four-dimensional constructs that we mentioned earlier. The total probability of finding an electron anywhere within the orbital must be unity, so the sum of all probability densities for all volume units must equal 1. As you may have noticed, the wavefunctions and electron density functions stretch to infinity, even though there are extremely low values of electron density at larger r values. To facilitate graphical presentations of orbitals, an arbitrary cut-off point is chosen in such a way that the probability of finding the electron inside the demarcated volume is 90%. That cutoff point corresponds to a very low value of electron density (anyway, what’s 10% difference between friends?). For orbitals, it represents an artificial isosurface that serves as an imaginary border or "skin", making the outside onion-layer smooth in our pictures, instead of the fuzzy outline shown in pointillist representations in Figure F02-5-1. We may ask what the most probable separation distance is between the electron and the nucleus. With the help of a pointillist representation (Figure 02-5-1) we may divide the space around the nucleus into narrow spherical shells ("onion layers") and count the number of dots in each layer. The results of such a count carried out on electron density values are shown by the last set of functions in Figure F02-5-2, which are called radial probability distributions or radial probability. Close to the nucleus we have high values of electron density, but the "onion layers" have small volumes. At larger distances the electron density drops off, but the volume of the layers increases As a result, the most probable distance for the electron in the ground state hydrogen atom is 0.529 Å; this is the same number as the Bohr radius, ao (E02-2-1). Bohr was almost right after all! The most probable distance increases for the other s orbitals. As we will see later, such patterns of distribution of electron density will help us to understand the chemical properties of atoms. For shells with n > 1, there are three degenerate dumbbell-shaped p orbitals perpendicular to each other The p orbitals come in sets of three, all having the same overall shape but each pointing in a different direction in space. For reasons beyond the scope of our course , we cannot assign a specific value of mℓ to each member of the set, but we will call them px, py, and pz to indicate their spatial orientation. Examples of wavefunctions and radial probability for p orbitals are shown in Figure F02-5-3. The two lobes of p orbitals have opposite signs for the wavefunction, and there is a node at the nucleus. The squares of the wavefunctions are all positive, and the radial probability distributions show the most likely distance from the nucleus for the electron. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 40/250 9/2/2019 Chem 110 2p 3p Figure F02-5-3. The wavefunctions (top), electron densities (middle), and radial density distributions (radial probabilities, bottom) for 2p and 3p hydrogen orbitals as they spread out from the nucleus positioned in the center of the plots (r = 0). The distance from the nucleus (r) is given in bohrs (ao) and Å. Click on the plots to explore them in more detail. If we spin the p wavefunction around the corresponding axis, we get a 3D representation of the shape of this type of orbital. As we have done with the s orbitals, we will only show the isosurfaces ("skins") selected in such a way as to have 90% of electron density inside the contained volume. Additionally we will paint (or otherwise label) the isosurface of the orbital with a color representing the sign of the underlying wavefunction. In fact, we do not even know which lobe is positive and which is negative (we only know the values of their squares), but that distinction is not important as long as we remember that they have opposite algebraic signs (F02-5-3). In other words, we will simplify the graphical presentations of orbitals to show only the 90% probability volumes covered by the skin marked with the sign of the wavefunction. We will leave all the detailed information of electron distribution inside the orbitals (in the form of contour plots, or other mathematical functions) only to those who want to explore it in detail. Any volunteers? https://genchem.science.psu.edu/sites/default/files/filefnlBYE 41/250 9/2/2019 Chem 110 Figure F02-5-4. The boundary surfaces and nodal planes for 2p orbitals. The lobes are colored to indicate the opposite algebraic signs of their wavefunctions. The volumes encapsulated by the isosurfaces contain 90% probability of finding an electron within. Note that the sum of the three p orbitals gives an overall spherical distribution of electron density. Click on an orbital picture to explore it in 3D (small delays are possible as orbitals are calculated). There are five degenerate d orbitals for shells with n > 2, each having four major lobes The shapes and directions in space of d-type orbitals are shown in Figure F02-5-5. To keep our promise of simplification, we will only look at their 90% probability lobes colored according to the algebraic sign of their wavefunctions. We will skip here the formal presentation of f orbitals (coming in sets of 7 ) as they are the least important for the chemistry covered in our course. All d orbitals in the hydrogen atom with the same value of n have the same energy, despite their diverse shapes. Again we are not able to assign individual m ℓ values to specific d orbitals, but use Cartesian designations to show their spatial orientations. Figure F02-5-5. The boundary surfaces and nodal planes for 3d orbitals. The lobes are colored to indicate the opposite algebraic signs of their wavefunctions. The volumes encapsulated by the isosurfaces contain 90% probability of finding an electron within. Note that the sum of the five d orbitals gives an overall spherical distribution of electron density. Click on an orbital picture to explore it in 3D (small delays are possible as orbitals are calculated). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 42/250 9/2/2019 Chem 110 To help you to recognize the orbitals, you may notice that s orbitals have 1 main lobe ("blob"), p orbitals have 2, and d orbitals have 4 (the "doughnut" lobe counts as two). For p orbitals, the direction along the axes decides their names. The d orbitals with lobes between the axes are designated by these axes' labels, and those with lobes along the axes have the axes' labels "squared" (the "doughnut " is left out of labeling). Except for the 1s orbital, all other orbitals have characteristic nodal surfaces (nodes), which could be spherical, conical, or planar. The number of nodes is (n-1), where n is the principal quantum number. It turns out that the shapes of orbitals of other atoms are identical to those of hydrogen with only an adjustment for size. These atoms have larger effective nuclear charges (see Lesson 03-2) which attract the electron closer to the nucleus on average. Thus, the corresponding orbitals have smaller lobes. Additionally, some adjustments in orbital energies are required. Nevertheless, the overall pattern of orbital shapes and spatial orientations remain the same for all atoms. As you can see, we have arrived at the point where the intricate components of even more complicated atoms, ions, and molecules are in our possession. Spend some time familiarizing yourself with these orbitals; it is good to know your tools well. After this discussion, the orbitals (or their graphical representations) may seem very real. Indeed, it is convenient to talk about them as real objects, like empty containers or boxes ready to be packed with electrons. The colored surfaces we use to visualize them give a feeling of walls behind which we can keep the electrons, such that they act in a predictable way around nuclei. However, it is important to remember that these are only visualization models and that there are no walls to keep electrons in or out of certain spaces. These orbitals do not even really exist until we have at least one electron in them. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 43/250 9/2/2019 Chem 110 03 Multi-Electron Atoms Hydrogen orbitals provide us with a blueprint for the electronic structure of multi-electron atoms of other elements. Nuclear charges and electron-electron repulsion vary among the different elements and affect their relative orbital energies. In turn, the manner in which the orbitals are filled with electrons dictates the chemical properties of elements. 03-1 Electron spin Electrons have an additional quantum number that is not associated with the orbital that they occupy. This value, called the spin quantum number, denotes the magnetic dipole moment of the electron. The spin quantum number can only be one of two values, ms = ½ or ms = –½. The Pauli exclusion principle dictates that a maximum of 2 electrons can occupy the same orbital simultaneously. Such electrons are referred to as being paired, and their spins (and thus their spin quantum numbers) must be opposite (antiparallel). 03-2 Effective nuclear charge In a multi-electron atom, the electrostatic interactions between electrons and the nuclear charge are complicated by electronelectron repulsion and mutual shielding. The various interactions are summed up by the effective nuclear charge (Zeff), which represents the average charge experienced by an electron interacting with the nucleus after being influenced by all other electrons. Differences in the effective nuclear charges account for the lifting of the degeneracy of shell orbitals (seen in hydrogen atoms) and establish the relative energies of orbitals. In general, for a given n, the subshell energies follow the pattern of ns < np < nd < nf. 03-3 Electron configuration We typically establish the electronic structure of an atom using the aufbau principle of adding electrons to the available lowest-energy orbitals to generate the ground state atoms. An orbital can hold a maximum of two electrons with opposite spins (and different spin quantum numbers). For degenerate subshells, according to Hund’s rule, the configuration that maximizes the number of electrons with the same spin has the lowest energy. Irregularities in orbital filling patterns crop up when the orbitals have similar energies and subtle factors may influence their ordering. The electrons in an atom are divided into low-energy, inner electrons (core electrons) and high-energy, outer electrons (valence electrons). 03-4 Periodic table The patterns electrons follow when filling subshells results in a periodic trend wherein the atoms of different elements can be arranged according to the configuration of their valence electrons. The main groupings of elements include the s- and p-block elements, the d-block elements (called transition metals), and the f-block elements (called lanthanides and actinides). The position of an element in the periodic table reflects its valence electron structure as well as its physical and chemical properties. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 44/250 9/2/2019 Chem 110 03-1 Electron spin The magnetic moment of an electron can only have two values, ms = +½ or ms = ‒½ Consider a beam of hydrogen atoms being sent through a non-homogeneous magnetic field produced by an unsymmetrically shaped magnet. The hydrogen atoms are neutral and they should pass through the field without any perturbation to their path. Instead, we find that the beam is split into two beams bent in opposite directions. Since the atoms are neutral, this bending can only occur if the atoms are behaving like small magnets; in other words, they have a magnetic dipole moment. Because the beam is being split into just two beams (as opposed to being spread out in all possible directions) we can conclude that the magnetic dipoles are only aligning in the magnetic field in two opposing directions. For this to happen, the magnetic moment must be quantized. Figure F03-1-1. In the Stern-Gerlach experiment a beam of neutral atoms is deflected and split into two beams as it passes through an inhomogeneous magnetic field. The original experiment was carried out with neutral silver atoms. The result of this experiment is explained by the existence of a fourth quantum number: the spin quantum number (ms). The spin quantum number refers to the orientation of the magnetic dipole moment of a specific electron; it is not an orbital quantum number, as it does not allocate an electron to any orbital. This number may only take on two values, +½ or –½. We visualize the spin quantum number as the "up" or "down" magnetic dipole moment of a spinning electron. Figure F03-1-2. The electron is visualized as a spherical charge spinning about its axis and generating a magnetic dipole moment (shown as arrows). The two directions of the magnetic dipole correspond to the two possible values of ms(+½ and –½). The picture of a spinning charged sphere is only an artificial representation as we know that electrons have wave-like properties. The Pauli exclusion principle limits the number of electrons in any orbital to two, having opposite spin Electron spin is crucial to understanding the structure of atoms and the bonds between them as it imposes certain constraints on electron configurations. It turns out that no two particles with half-integer spin may have the same quantum state. This restriction, known as the Pauli exclusion principle, means that no two electrons in an atom may occupy the same space and have all the same quantum numbers. When orbital quantum numbers are specified (n, ℓ, m ℓ ), the only variability left is in the spin quantum number, which can only have one of two possible values (ms = +½ and ms = –½). Thus, a maximum of two electrons may reside in a given orbital. If the two electrons are to occupy the same orbital, they must have opposite spins. Such electrons are called paired and their spins are antiparallel. If an orbital is singly occupied (by one electron), that electron is called an unpaired electron. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 45/250 9/2/2019 Chem 110 03-2 Effective nuclear charge Outer electrons experience diminished nuclear charge as they are screened by the internal electrons and by each other Atoms bigger than hydrogen have a larger number of electrons, and more protons in their nuclei. As the atomic number rises by one, the proton and electron counts also rise by one. The orbitals available to hold these electrons are very much like those in the hydrogen atom. They are described by the same quantum numbers, and have similar shapes. Taking into account the Pauli exclusion principle, we can easily visualize the electronic structure of any atom by apportioning all its electrons to hydrogen-like orbitals, starting with the lowest energy orbital and placing no more than two electrons in each. This “building up” construction method (called the aufbau principle, from German) assures that the atom will have the lowest possible total energy and will be in its ground state. To see how that scheme may work, let's start with hydrogen. Hydrogen’s electron is in the 1s orbital. The case for helium (2He, atomic number of two) seems straightforward. It has one more electron than hydrogen, but that electron can be simply added to the 1s orbital. We now have a pair of electrons with opposite spins (filling up 1s completely) trying to minimize their mutual repulsion by staying as far from each other as possible within the orbital. This task is harder than one might anticipate because the helium 1s orbital is smaller than the hydrogen 1s orbital. This orbital “shrinking” is due to the increase in the nuclear charge (Ζ). At first glance it seems that each of the two electrons in the helium atom is attracted to a +2 nuclear charge. Using Bohr’s model as a guide (E02-2-4), we would then conclude that the average orbit size in helium should be half of that in hydrogen, as the orbit size is inversely proportional to Z. The situation is a bit more complex, however, as we also need to account for electron-electron repulsion. In general, in multi-electron atoms, we cannot analyze all the attractions and repulsions exactly, but we can approximate how any one electron interacts with an average electrostatic force field generated by the nucleus and all other electrons. The resulting net attraction is viewed as if it were an interaction of that electron with a point charge at the nucleus, called the effective nuclear charge, Zeff. For helium, Zeff = +1.69, meaning that each of the two electrons is attracted, on average, to a +1.69 positive charge, rather than +2.00, as we had first assumed (see above). Moving on to lithium (3Li), its 3rd electron has to be placed in the next available orbital, which is 2s. The attraction of this electron to the nuclear charge is significantly modified by the presence of the electrons in the 1s orbital. The two 1s electrons are on average closer to the nucleus than the 2s electron, screening (shielding) it quite effectively from the full electrostatic attraction expected from the +3 charge on the nucleus. This shielding can be expressed by a positive number S, called a screening constant, and we can write (E03-2-1): Zef f = Z − S E03-2-1 Again, at first approximation we might assume S = 2 for the 2s electron in Li and imagine that the two 1s electrons “neutralize” +2 of the +3 nuclear charge (Figure F03-2-1). In reality, the situation is again more complex. On the one hand, the 1s electrons are shielding each other the same way they did in helium. On the other hand, the 2s electron can penetrate to the nucleus, since it has a non-zero probability of being in the vicinity of the nucleus. When we take all this into consideration, we find that Zeff for the 1s electrons in Li is +2.69 (less than the +3 value expected without any screening), and Zeff for the 2s electron is +1.28 (more than the +1 charge we anticipated when we assumed maximum screening for Z = +3 and S = 2). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 46/250 9/2/2019 Chem 110 Figure F03-2-1. Effective nuclear charge of the Li atom. The nuclear +3 charge is screened by the two inner 1s electrons. Effective charge of the outer 2s electrons is approximately, Zeff = 3 – 2 = 1. A peak between 0 and 1 Å on the plot of radial probability versus distance (right) shows that the outer 2s electrons can penetrate close to the nucleus. Therefore, the 1s electrons are not fully effective at screening the 2s electrons from the nucleus. Precise calculations show that Zeff(1s) = 2.69 and Zeff(2s) = 1.28. Orbitals in the same shell of multielectron atoms are not degenerate because the effective nuclear charge is different for each subshell The concept of effective nuclear charge is fundamental to our understanding of many atomic properties. The precise values for Zeff for various orbitals in an atom can only be obtained through sophisticated quantum calculations. However, for the highest-energy electrons (which to a large degree dictate the chemistry of atoms) an approximation where S is taken as the number of all inner core electrons is quite adequate for many qualitative considerations. We will use the concept of Zeff quite often. The effective nuclear charge is responsible for the lifting of the degeneracy of subshell orbitals. In the hydrogen atom, the 2s and the three 2p orbitals all have the same energy (see F02-4-1). Based on that information, we could have considered placing the 3rd electron of lithium in one of the 2p orbitals. It turns out, however, that although all three 2p orbitals remain degenerate, they all have higher energy than the occupied 2s orbital in Li. Plots of radial probability (compare F02-5-2 and F02-5-3) are best suited to illustrate the relative penetrations of the orbitals to the nucleus (F03-22). A small peak close to the nucleus is present in the diagram for the 2s orbital, but absent in the diagram for the 2p orbital; this shows how the electrons in the 2s are sometimes found closer to the nucleus, lowering their energy and partially screening an electron in the 2p orbital. Figure F03-2-2. From left to right: (a) Radial probability for the 2s and 2p orbitals showing the penetration of 2s electrons closer to the nucleus and their subsequent partial screening of the 2p electrons. (b) Similar radial probability plots for 3s, 3p, and 3d orbitals. The small peaks in radial probability close to the nucleus illustrate that regions of greater electrostatic attraction contribute to lowering of orbital energy in that region, and to the partial screening of electrons in orbitals that are in the same shell (in this case, shell 3). This pattern is general: for a given n, the ns orbitals are lower in energy than the corresponding np orbitals, which in turn have lower energy than the nd orbitals. The same trend is apparent in Zeff values. For example, for boron (5B) Zeff(2s) = 2.58 and Zeff(2p) = 2.42. For scandium (21Sc) Zeff(3s) = 10.34, Zeff(3p) = 9.41, and Zeff(3d) = 7.12. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 47/250 9/2/2019 Chem 110 With so many readjustments of orbital energies due to differences in Zeff from atom to atom (and even from orbital to orbital in the same atom), one may despair that the simplistic order found in the shell-subshell structure of hydrogen orbitals is lost. However, despite the complications (which do at times provide intriguing outcomes) the “onion-layer” electronic structure does survive with a few modifications. The orbital energies are still proportional to (Zeff/n)2, and the most probable nuclear-electron separations are still proportional to (n2/Zeff), just as they were in hydrogen orbitals (or even in the simple Bohr model). The major difference is that now Zeff is a complex function of both n and ℓ. The energy ordering scheme for multi-electron atoms is shown in Figure F03-2-3. The subshells are no longer degenerate within their shells, and there is some intermingling of shells. For example, there are times when the 4s and 5s orbitals have lower energy than 3d and 4d, respectively. Indeed, the similarity in energy levels between these subshells results in occasional irregularities and exceptions. Now that we better understand the ordering of energy levels for the orbitals, we are ready to start exploring the details of the electronic structure of atoms. Figure F03-2-3. Ordering of orbital energies for a typical multi-electron atom (right) as compared to the energy levels in the hydrogen atom (left, compare to F02-4-1). The subshells are no longer degenerate (as they are in the hydrogen atom. Now the energies follow the ns < np < nd pattern. Even though there are some ns subshells that are lower in energy than (n-1)d subshells (for example 4s has lower energy than 3d, and 5s is lower than 4d), the layered structure is quite apparent. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 48/250 9/2/2019 Chem 110 03-3 Electron configuration Electrons fill orbitals from the lowest energy to the highest with up to two electrons per orbital Armed with the freshly-acquired knowledge of the previous two sections, we can now build the periodic table! The rules governing the construction process can be summarized as follows: 1. The atomic orbitals are ordered in a layered structure of shells and subshells based on the energies of interactions of electrons with effective nuclear charges (Zeff). 2. The aufbau principle is applied to fill the orbitals with available electrons, starting with the lowest-energy orbitals and moving up. This filling strategy results in the ground state electronic configurations for atoms. 3. The Pauli exclusion principle restricts the maximum number of electrons per orbital to two (with opposite spins). 4. Hund’s rule (a new addition, see below) governs electron distribution among degenerate orbitals. We can translate the energy ordering scheme of Figure F03-2-3 into an orbital-filling “roadmap” to facilitate this process (F03-3-1). Each box represents a subshell: s subshells have one orbital each, p subshells have 3 orbitals, d subshells have 5 orbitals, and f subshells have 7 atomic orbitals. Any of the orbitals can hold a maximum of two electrons. We start with 1s, and follow the arrows diagonally down through 2s, 2p, 3s, 3p, 4s, 3d, etc., until we place the number of electrons equal to the atomic number of a given atom. Figure F03-3-1. The “road map” for filling atomic orbitals with electrons in multi-electron atoms. The order follows the diagonal arrows, from the top to bottom. We have already analyzed the electronic configuration of H, He, and Li (Section 03-2). We can present their configurations in a graphical fashion where boxes represent orbitals and up and down arrows represent electrons with ms = ½ and –½, respectively (Table T03-3-1). Alternatively, we can write that information in a long-form notation, indicating the subshell label and its electron occupancy with a superscript number. Thus, H would be 1s1, He 1s2, Li 1s22s1, etc. The continuation of the pattern is straightforward (Table T03-3-1). Beryllium has one more 2s electron (1s22s2), and boron starts to fill up the 2p subshell (1s22s22p1). Carbon raises an interesting issue. Where should the 2nd p electron be placed? The three 2p orbitals have the same energy, but should the new arrival be paired with the other p electron in the same 2p orbital, or should it be placed in another 2p orbital? Situations like this are governed by Hund’s rule, which states that the lowest energy is obtained, if the number of electrons with the same spin is maximized. In other words, when electrons are added to orbitals of equal energy, a single electron enters each orbital of the degenerate set before any are paired. This distribution of electrons among the orbitals of the degenerate set with parallel spin arrangements helps to minimize electron-electron repulsion, lowering the energy of this configuration. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 49/250 9/2/2019 Chem 110 The same principle reveals that nitrogen (1s22s22p3) has three unpaired electrons. Oxygen (1s22s22p4) and fluorine (1s22s22p5) continue filling up the 2p subshell, with consecutive electrons added to already half-filled orbitals, pairing their spins. Neon (1s22s22p6) concludes the filling of the 2nd shell, and sodium starts the 3rd one, with one electron in 3s (Table T03-3-1). Table T03-3-1. Electron configuration for the first 11 elements Z 1s 2s 2p 3s core valence H 1 ↑ 1s1 He 2 ↑↓ 1s2 [He] Li 3 ↑↓ ↑ 1s22s1 [He] 2s1 Be 4 ↑↓ ↑↓ 1s22s2 [He] 2s2 B 5 ↑↓ ↑↓ ↑ 1s22s22p1 [He] 2s22p1 C 6 ↑↓ ↑↓ ↑ ↑ 1s22s22p2 [He] 2s22p2 N 7 ↑↓ ↑↓ ↑ ↑ ↑ 1s22s22p3 [He] 2s22p3 O 8 ↑↓ ↑↓ ↑↓ ↑ ↑ 1s22s22p4 [He] 2s22p4 F 9 ↑↓ ↑↓ ↑↓ ↑↓ ↑ 1s22s22p5 [He] 2s22p5 Ne 10 ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 1s22s22p6 [Ne] Na 11 ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 1s22s22p63s1 [Ne] 3s1 ↑ 1s1 Note on degenerate orbitals The valence electron configuration is the same for elements in the same column of the periodic table Already, we can recognize a certain periodicity in the electronic configuration of atoms. The noble gases helium (2 electrons) and neon (8 electrons) have their respective shells completely filled. Any element following a noble gas starts over with one electron in the s orbital, repeating the pattern. Indeed, hydrogen, lithium, and sodium have one s electron (ns1) as their highest energy electron. Looking at the highest energy electrons, it is apparent that we should have a set of s-type elements (2 of them for each n) followed by a set of p-type elements (6 of them for each n). Indeed, this pattern becomes our first draft of the periodic table. The full-shell configuration is particularly stable as it has a completely spherical electron-charge distribution (F02-54). The electrons making up this noble gas configuration that has valence orbitals filled are called core electrons. Electrons in the outermost shell that comes after the core shells are called valence electrons. All elements in the second row of the periodic table (between Li and Ne) have a helium core, and all elements in the third row (between Na and Ar) have a neon core. Instead of listing these core electrons explicitly, we can use a short-hand notation by specifying the core in square brackets. For example, carbon’s configuration can be denoted [He]2s22p2, and sodium’s configuration is [Ne]3s1 (Table T03-3-1). This division of electrons into low-energy core electrons and high-energy valence electrons is not just for convenience of notation. It reflects the basic chemical principle that low-energy inner electrons are not involved in chemical processes. They experience high Zeff and are strongly attracted to the nucleus. On the other hand, the highenergy outer electrons are shielded by the core electrons, experience a lower Zeff, and are readily involved in chemical processes such as bond formation. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 50/250 9/2/2019 Chem 110 Anomalies in electron configurations are caused by subtle differences in subshell energies For elements of higher atomic number than argon ([Ne]3s23p6), a simplistic approach would predict that the highest energy electron in potassium should end up in the 3d orbital as the d-subshell becomes available for n = 3. However, our energy diagram (Figure F03-2-3) and the road map we prepared (Figure F03-3-1) indicate that the 4s subshell is lower in energy and therefore filled first. Consequently, K has a configuration of [Ar]4s1, and Ca is [Ar]4s2. Only after calcium do we place the next electron in the 3d subshell. Scandium’s electron configuration is [Ar]3d14s2, initiating a series of 10 elements that gradually fill all of the five 3d orbitals with their highest energy electrons. Therefore, as we start the 4th row, our periodic table must be expanded to include d-block elements. A very similar situation occurs in the 5th row with 4d orbitals and the 6th (n = 6) and 7th (n = 7) rows of our periodic table when the f-subshells become accessible. Each f-subshell has 7 degenerate orbitals, which may accept 14 electrons. This gives us a new f-block with 14 elements per row. Here, the ns, (n-1)d, and (n-2)f subshells are very close in energy. As you may have guessed, the ns orbitals are filled before (n-1)d or (n-2)f, but what may surprise you is that (n2)f will fill before (n-1)d. The closeness in energy of these orbitals leads to numerous anomalous electronic configurations (Figure F03-4-2). Most of these deviations are of limited chemical significance and we are going to leave them unexplored. One of the significant anomalies that illustrates a broader trend is what happens when the orbitals are close in energy and there are enough electrons to precisely half-fill or completely fill the subshells. Let’s consider only the 4th row of the periodic table. We would predict that chromium would have the electronic configuration [Ar]3d44s2, but in fact the correct configuration is [Ar]3d54s1. One filled subshell and one partially filled subshell are “traded” for two half-filled subshells. Half-filled subshells have perfectly spherical electron charge distribution (F02-5-5) and can better minimize their electron-electron repulsions, which in turn provides extra stability. Similarly, copper has the configuration [Ar]3d104s1 (with one filled and one half-filled subshell), rather than [Ar]3d94s2, which would be higher energy. It should be noted that the electronic configurations of d-elements can be written by ordering the subshells by n ([Ar]3d104s1) or by filling order ([Ar]4s13d10). Both ways are equally acceptable. With this new understanding of d-block and f-block elements, we can now return to the concept of valence electrons. Formally, the d-electrons and f-electrons are outer electrons. If the d-subshell or the f-subshell is not completely filled, we consider these outermost electrons to be valence electrons; they participate in chemical reactions, which involve ion or bond formation. However, if these subshells are fully filled, these electrons do not participate in bond formation, and behave as if they were core electrons. In such cases we do not consider these electrons to be valence electrons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 51/250 9/2/2019 Chem 110 03-4 Periodic table The s, p, d, and f blocks of elements in the periodic table are due to the periodicity of the electron configuration of atoms The relative energies of hydrogen-like subshell orbitals, coupled with the Pauli exclusion principle, are responsible for the repeating patterns we see in the organization of the atoms of various elements. The result of these patterns is the formation of periods, where any atom has the same valence electron configuration as an atom of the element directly above it in the periodic table (Figure 03-4-1). For n = 1, the only orbital available (1s) can hold up to two electrons. Thus, the first row of our table can only hold two elements. For n = 2, the 2s orbital is available (two elements), along with three 2p orbitals (6 elements); there are a total of 8 elements in the second row. The pattern gets a bit more complicated in the third row: the 3s and 3p subshells repeat the 2s/2p arrangements, but the 3d subshell drops down because its energy is higher than that of 4s, which therefore fills first. In the 4th row we gain a 10-element-wide d-block, where electrons gradually fill the five available d orbitals. Here, too, the 4f subshell’s energy is higher than that of 5s, so the f-block drops down in our table. The 5th row repeats the pattern of the 4th. In the 6th row, the f-block elements (14-elements wide) finally become available, bringing the seven f-subshell orbitals into play. Figure F03-4-1. The periodic table is constructed based on the relative energies of atomic orbital subshells, where each orbital can be filled by at most 2 electrons, based on the Pauli Exclusion Principle. The s-block elements have ns valence electrons and the p-block elements add np electrons to the valence shell. The d-block and the f-block electrons are considered valence electrons only if their subshells are not full. Figure F03-4-2. The common version of the periodic table, with the f-block dropped below the rest of the table. The members of a vertical column are said to form a group or belong to a family of elements. In groups, elements have very similar properties and exhibit clear trends in their properties down the group. The groups are numbered from 1 to 18 (the current international convention), or from 1 to 8 with A or B designations (an older scheme used in the United States). Elements with electronic configurations that deviate from the standard pattern are marked. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 52/250 9/2/2019 Chem 110 The exceedingly wide periodic table in Figure F03-4-1 is often converted to a narrower form (F03-4-2) where the f-block elements are pushed below the rest of the table, as shown in Figure F03-4-2. The s- and p-block elements are usually called the main group elements. The d-block elements are called the transition elements (or transition metals), and the two rows of f-block elements are called the lanthanides and actinides, respectively. Metals occupy most of the periodic table whereas nonmetals are located in the upper right corner We will next explore how the position of an element in the periodic table (and therefore its electronic configuration), determines its physical and chemical properties. In the most general sense, most elements in the periodic table are metals (Figure F03-4-3). They occupy the left-side and the center of the periodic table. The nonmetals are assembled in the upper-right section of the periodic table, with a few metalloids (of intermediate character) on the borderline between the two. More details on the elements can be found in our interactive periodic table which you can activate by clicking the button above the top of this page. Figure F03-4-3. The periodic table with metals, nonmetals, and metalloids marked. The elements in the same column (with the same valence electron configuration) exhibit similar chemical properties and are given "family" names. Alkali metals (group 1) are all highly reactive and readily become +1 ions, while alkaline earth metals (group 2) are less reactive and form +2 ions. Although the electronic configuration of transition metals is not the same within the block (groups 3 12), they share many characteristics that set them apart from other elements. Transition metals in a single group are similar because of their incompletely filled d-subshells. Similarly, lanthanides and actinides resemble each other due to their partially filled f-subshells. Among nonmetals we have the chemically inert noble gases (group 18 or 8A), the halogens (group 17 or 7A), the oxygen family (chalcogens, group 16 or 6A), and the nitrogen family (group 15 or 5A). We will learn more about the chemical properties of these elements in future Lessons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 53/250 9/2/2019 Chem 110 04 Periodic Properties The periodic table’s ordering of atoms according to their electronic configurations allows us to systematically explore the trends in their properties that dictate their chemical behavior. Atomic size dictates how close atoms will come to each other when making covalent bonds in molecules, while ionic size does the same for ionic solids. As we will soon learn, distance plays a crucial role in determining the strength of a bonding interaction. Ionization energies give us a quantitative measure of how easily valence electrons may be removed from atoms (thus creating positively charged cations), while electron affinities tell us how easy it is to add electrons to atoms (creating negative anions). Understanding these properties and the trends that they follow allows us to better appreciate the periodic nature of an element’s characteristics, and sets us up to explore bonding in future lessons. 04-1 Atom sizes Nonbonding radii measure how closely the atoms approach each other during collisions, while bonding radii determine the distance between the nuclei of bonded atoms. The bonding radius is dependent on the Zeff of the outermost (valence) electrons and on the number of electron shells that the atom has. As we move down any column of the periodic table the atomic radii increase significantly due to the addition of one electron shell per each row. From left to right, the atomic radii decrease due to the systematic increase in Zeff. These trends are strongly pronounced among the main group elements, but are weaker among transition metals. 04-2 Ionization energies The ionization energy (IE) of an atom is the minimum energy required to remove an electron from a ground state atom in the gas phase. The consecutive ionization energies measure the energies needed to remove additional electrons. The values of the ionization energies increase dramatically when the electron to be removed comes from a filled shell; this trend makes it quite simple to distinguish between valence and core electrons. Trends in IE1 (removal of the first electron) are dictated by atomic size (bigger atoms are easier to ionize) and Zeff (larger nuclear charge increases IE). Thus, the ionization energies generally increase from left to right in each row of the periodic table (with noble gases having the largest IEs), and decrease going down the columns, since the largest atoms have the smallest ionization energies. Small deviations from the general trends are observed in atoms with filled or half-filled subshells, as these electron configurations are more stable and result in a larger IE. The patterns for transition metals are less pronounced than those for the main group elements. 04-3 Electron affinities The electron affinity (EA) is the energy released when an atom in the gas phase accepts an electron. Most atoms in the gas phase can accept one electron to produce stable anions of charge −1. The trends are similar to those observed for ionization energies, but are less pronounced and there are some shifts in column trends. In general, EAs become more negative as we move from left to right in any row of the periodic table, with halogens having the most negative EAs. The trend down the columns is less defined, but the bigger atoms usually have more negative values. Atoms with filled or half-filled subshells have small negative or unmeasurable (and unfavorable) electron affinities, while atoms that are one electron short of having filled or half-filled subshells have highly favorable EAs. 04-4 Ion sizes Cations are always smaller than their parent neutral atoms: this is the result of removing the outermost electrons and having diminished electron-electron repulsions. Anions are always larger than their parent neutral atoms as they have increased electronelectron repulsions. Ion sizes follow the same periodic trend as bonding atomic radii: they increase down the column and decrease from left to right on the periodic table (for the same ion type). Ions most commonly have the configuration of the noble gas nearest to the parent atom. Ions with the same electronic configuration are called isoelectronic. Ion sizes decrease systematically with increasing Z, regardless of the ion type. When cations are formed, the electrons are first removed from the occupied orbital having the largest principal quantum number, n. If there is more than one occupied subshell for a given value of n, the electrons are first removed from the orbital with the highest ℓ value. In such cases the cation may end up with an electron configuration that differs from a noble gas configuration. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 54/250 9/2/2019 Chem 110 04-5 Periodic trends We can sort the elements into metals, nonmetals, and metalloids simply by examining the IE1 values; our boundary line dividing metals from nonmetals is just under 1000 kJ/mol for the ionization energy. Metals have low IE1s (below the line) and easily form cations. Nonmetals have large IE1s (above the dividing line); they do not form cations readily, but some of them form anions. The metalloids have intermediate properties and IE1 values close to the boundary line. The metals occupy the left and center part of the periodic table. Their properties are related to the presence of high energy valence electrons which are easily removable. The nonmetals occupy the right side of the periodic table. Their valence electrons are of lower energy and are held more tightly. The metalloids occupy the narrow space between the metals and nonmetals in the periodic table. These patterns dictate how these atoms will behave when bonding with other atoms of the same element, or with atoms of other elements. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 55/250 9/2/2019 Chem 110 04-1 Atom sizes Effective nuclear charges for valence electrons increase significantly from left to right within each period We learned in Lesson 03-2 how the effective nuclear charge (Zeff) influences the sizes and the energies of atomic orbitals. Let’s examine the trends in Zeff in more detail, focusing on the valence electrons. As you may recall, we can simply approximate Zeff by subtracting the number of core electrons from the number of protons in a given atom, Zeff = Z – S (E03-2-1). Z is the atomic number. For more precise answers, we must rely on sophisticated quantum calculations. We compare the results by plotting them against their atomic numbers in Figure F04-1-1. Figure F04-1-1. The approximate effective nuclear charge for valence electrons calculated using equation E03-2-1 (orange circles), and precise values obtained by quantum methods (blue circles). The open circles represent transition metals (d-block elements). Zeff increases significantly from left to right in the individual periods, but increases only slightly down the individual columns (blue circles). Plots of properties versus atomic numbers (Z) are an excellent way to observe recurring trends that repeat for every row of the periodic table. Indeed, the "saw-tooth" pattern is easily recognizable in our Zeff plots in the figure. This pattern is emphasized by the labeling of the alkali metals and noble gases which start and end each period, respectively. At first, one may be discouraged by the divergence of the readily available approximate values (orange circles) from the more realistic numbers that can only be obtained from the quantum calculations (blue circles). However, as long as we are interested in trends rather than precise values, we can be satisfied that the slopes of the blue segments are just slightly smaller than the slopes of the orange segments. A major exception is observed for the transition metals, which show a much smaller slope than expected. This “flattening” of the curve is indeed an indication that transition metals are much more similar to each other in their properties than are elements of other adjacent groups (families), as we have previously stated. We can safely conclude that Zeff values for elements steadily increase from left to right in individual rows of the periodic table. Also, the effective nuclear charge experienced by the valence electrons increases somewhat going down the columns. The effective charge experienced by the valence electrons influences chemically-significant atomic properties. The larger the charge, the more strongly and closely the electrons are attracted to the nucleus, the harder they are to remove, and, for a given n, the smaller the atom is. It is as though the outermost electrons set the atom “boundaries”. Nonbonding and bonding atomic radii are two measures of atomic sizes We have learned that electron clouds are quite fuzzy, so defining the atomic size requires some explanation. First imagine two identical atoms in the gas phase colliding with each other, with typical kinetic energy (at room temperature). They will fly apart like billiard balls because of the electrostatic repulsion of their electron clouds. The closest distance between the two nuclei in the instant of their collision corresponds to twice their nonbonding radii. Such a radius, also called the van der Waals radius, is a measure of atomic sizes for “free” atoms. We will explore it, and its molecular analogue, in more detail when we discuss intermolecular interactions. You may explore the van der Waals radii trends for many elements in our interactive periodic table (the button on the top right side of the page). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 56/250 9/2/2019 Chem 110 Figure F04-1-2. The nonbonding radius (rn) is half the closest distance between nuclei in the instant of the collision of gas phase atoms. It is also called the van der Waals radius. The bonding radius (rb) is half the distance between bonded nuclei in a compound. Bonding requires larger interpenetration of electron clouds. In contrast, when atoms form molecules, their electron clouds penetrate each other much deeper than during a simple collision. We will explore bond formation in much greater detail in Chapter 6, but the inter-nuclear distances in molecules provide another measure of the atomic size called the bonding atomic radii. These distances have been measured by a variety of scientific techniques for a large number of molecules, and then averaged for individual atoms. For example, the carbon-carbon distance in the structure of diamond is 154 pm (1.54 Å), which translates to a bonding radius of 77 pm (0.77 Å) for the carbon atom. The inter-nuclear distance in an I2 molecule is 266 pm (2.66 Å), which gives an atomic radius of 133 pm (1.33 Å) for an iodine atom. Figure F04-1-3 Determination of the bonding radius for iodine in an I2 molecule, and for carbon in a diamond lattice. Atomic radii can be added to estimate bond lengths as illustrated by the molecule of methyl iodide, H3C−I. As an example, we can now predict the C-I bond length in methyl iodide (H3C–I) to be 210 pm (77 pm + 133 pm), which is in perfect agreement with the experimentally measured bond length of 212 ± 4 pm. The benefit of understanding such data is clearly apparent; an atomic property can be used to predict molecular properties, even for molecules not yet studied. The bonding atomic radii are collected in Figure 04-1-4. For atoms that do not form molecules (such as some noble gases) or when experimental data are not available (such as for short-lived radioactive atoms) the values are estimated. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 57/250 9/2/2019 Chem 110 Bonding atomic radii decrease from left to right across the periods as Zeff increases and increase down the columns as n increases Figure F04-1-4. Bonding atomic radii for main group and d elements. The standard atom's colors are used and the size of the sphere reflects the relative size of the atom. Click on the picture to see the numerical data for the main group elements and for the transition metals. All values are in picometers (100 pm = 1 Å). Values in parentheses are estimated. Even without detailed analysis, the trends in atomic size are very apparent. . For the main group elements, the atoms “shrink” on average by about 40% from left to right across each row. The transition metals, on the other hand, are much more uniform in their sizes: they differ, on average, by less than 25% across any row, with the larger atoms distributed at the beginning, the middle, and the end of each row. Overall, these size patterns match those seen in Zeff values (discussed above). This similarity is perfectly understandable, since valence electrons that experience a greater charge are kept closer to the nucleus. For main group elements, the bonding radius significantly increases from top to bottom within each column, doubling on average from the top to the bottom (excluding H and He). A similar but much less pronounced trend is observable even in the transition metal columns. At first glance, the growing atomic size down the columns may appear to be contrary to the Zeff trend discussed above (F04-1-1). However, as we mentioned previously the increase in Zeff down the column is relatively small and is easily overwhelmed by the overall increase of orbital sizes that accompanies the increase in the principal quantum number. Increasing n by 1 adds one extra electron shell to the size for each row of the periodic table. Thus, the atomic sizes increase down each column mainly due to the increasing principal quantum number, and shrink as we move to the right in each row because of the increasing effective nuclear charge. These trends are summarized in plots in Figure F04-1-5. Figure F04-1-5. From left to right: the trends in bonding atomic radii (100 pm = 1 Å) versus (a) Zeff and (B) versus atomic number (Z). Both plots show the periodic trends of increasing atomic size as n varies. In (a) each line represents a different n. In (b), a peak indicates a new n and these peaks increase in height as n increases. Each peak is followed by a smooth decline in size across the row (constant n), reflecting the increasing effective nuclear charge. The transition metals are shown as open circles, and f-elements are omitted. The saw-tooth pattern characteristic of periodic properties is apparent in (b). Click on a plot for a larger version. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 58/250 9/2/2019 Chem 110 In Figure F04-1-5a each line corresponds to one row of the periodic table. The increasing height of the lines is due to the addition of one electron shell per each increase in n. Within each row, the atomic radii decline, following the trend of increasing effective nuclear charge. In the "periodic" plot (F04-1-5b) each "tooth" corresponds to one row of the periodic table. The sharp "spikes" happen when a new shell is added (after each noble gas), and then within each row the atomic size shrinks in a smooth, predictable pattern that coincides with increasing Zeff There are some expected minor deviations for transition metals. Since the energy of electrostatic attraction for valence electrons is directly proportional to the effective nuclear charge and inversely proportional to their average separation from the nucleus, the atomic size and Zeff trends we have just discussed are crucial to understanding the chemical behavior influenced by these electrons. The weaker the electrostatic attraction, the easier it is to remove these electrons from the atom, and the more readily they participate in bond formation with other atoms. In fact, we will next learn how to directly quantify that attraction by measuring the energy necessary to remove electrons from atoms. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 59/250 9/2/2019 Chem 110 04-2 Ionization energies Successive ionization energies demonstrate that valence electrons are much easier to remove than core electrons The ionization energy (IE) of a chemical species (an atom, an ion, or a molecule) is the minimum energy required to remove an electron from the ground state of that species in the gas phase. In other words, it is a measure of how strongly that electron is held within the atom, ion, or molecule. The first ionization energy, IE1, is the energy needed to remove the first electron. That electron is the highest in energy and easiest to remove. The second ionization energy, IE2, is the energy required to remove the second electron, and so forth, for successive removal of additional electrons. For example, the consecutive ionization processes for a magnesium atom are shown below: + Mg(g) ⟶ Mg + Mg 2 + (g) ⟶ Mg 2 + Mg − (g) + e 3 + (g) ⟶ Mg − (g) + e − (g) + e I E1 = 738 kJ/mol C04-2-1 I E2 = 1451 kJ/mol C04-2-2 C04-2-3 I E3 = 7733 kJ/mol The more strongly the electrons are held (the lower their energy within the species), the harder it is to remove them and the higher the ionization energy. In our example of Mg, the second electron is twice as difficult to remove as first, while the 3rd is about five times(!) more difficult to remove than the second electron. An increase in the energy required to remove each successive electron is expected since the electron is being pulled away from an increasingly positive ion. However, the large jump in the energy required to remove the 3rd electron in our example signifies another phenomenon in action. The electron configuration of Mg is [Ne]3s2, so the first two electrons are removed from the 3s subshell. The 3rd electron is not removed from the valence shell, but must come out of the 2p orbital of the noble gas core of the Mg2+ ion ([Ne] = [He]2s2p6). The large amount of extra energy required to remove core electrons is a general property of all atoms, as illustrated in Table T04-2-1. T04-2-1. Successive ionization energies (in MJ mol−1) of the first 21 elements Z Element IE1 IE2 IE3 1 2 3 H He Li 1.31 2.37 5.25 0.52 7.30 11.82 4 Be 5 B 0.90 1.76 0.80 2.43 6 C 7 N 8 IE4 IE5 IE6 IE7 14.85 21.01 25.03 32.83 1.09 2.35 3.66 4.62 47.28 4.58 6.22 7.48 37.83 1.40 2.86 53.27 64.36 O 1.31 3.39 5.30 7.47 9.44 10.99 71.33 9 F 1.68 3.37 6.05 8.41 11.02 13.33 15.16 10 Ne 2.08 3.95 6.12 9.37 12.18 15.24 17.87 20.00 11 Na 9.54 13.35 16.61 Mg 7.73 10.54 13.63 18.02 13 Al 0.50 4.56 0.74 1.45 0.58 1.82 6.91 12 14.84 14 Si 0.79 1.58 2.74 3.23 11.58 15 P 1.01 1.91 2.91 4.36 4.96 16 S 1.00 2.25 3.36 17 Cl 1.25 2.30 18 Ar 1.52 2.67 19 K 20 Ca 21 Sc 0.42 3.05 0.59 1.14 0.63 1.24 IE8 IE9 IE10 84.08 92.04 106.43 115.38 131.43 20.12 23.07 25.50 25.66 28.93 31.65 141.36 21.71 18.38 23.33 27.46 31.85 35.46 38.47 16.09 19.80 23.78 29.29 33.88 38.73 21.27 25.43 29.87 35.90 40.95 4.56 6.27 7.01 31.72 36.62 43.18 3.82 5.16 6.54 8.50 9.36 27.11 38.60 43.96 5.77 7.24 8.78 11.02 11.99 33.60 3.93 40.76 46.19 4.42 5.87 7.98 9.59 11.34 13.84 1494 4.91 6.49 8.15 10.50 12.27 14.21 16.96 18.19 2.39 7.09 8.84 10.68 13.31 15.25 17.37 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 48.61 20.38 21.73 60/250 9/2/2019 Chem 110 Indeed, one can readily recognize how many valence electrons each atom has by locating the specific ionization energy that shows the first dramatic jump in the consecutive IE values (as marked in the table). Every element shows a large increase in IE when the electrons start being removed from the noble gas core. This observation validates our division of electrons into valence and core electrons. Only the weakest-bound valence electrons participate in ion formation or give rise to chemical bonding and reactions. The core electrons are too low in energy, and too tightly held by the nucleus, to be lost or shared. The consecutive IEs also support the image of an onion-layer atomic structure that we introduced when building our periodic table and examining electron configurations. The logarithmic-scale plot shown below (F04-2-1) for potassium clearly demonstrates the shell structure of the atom. You may further explore ionization energies for all atoms in our interactive periodic table (button on the top of the page). Figure F04-2-1. Consecutive ionization energies for the 19K atom presented on a logarithmic scale for better visibility. The individual shells are marked on the plot. Ionization energies (IE1) increase from left to right across the periods and decrease down the columns since the further the electron is from the nucleus, the easier it is to remove it As we have previously posited, the outermost, highest-energy electrons are the most readily available for participation in chemical processes such as ion or bond formation. The values of IE1 provide us with a simple and quantitative measure of that availability, and the trends in their magnitudes give us insight into relative chemical reactivity of atoms. At the most basic electrostatic level, electrons are the easiest to remove if they are far away from the nucleus and experience the smallest effective nuclear charge. We have already explored the atom size and Zeff trends in some detail in this Chapter (see 04-1). With that knowledge, we can predict with confidence that IE1 should decrease as we move down any column of the periodic table, following the trend of increasing atomic radii. On the other hand, IE1 should increase as we move from left to right across any period, tracking the increasing effective nuclear charge and diminishing atomic size. We may also expect that variations for transition metals will mimic the main group trends, but in a muted fashion. All of these predictions are indeed true, as shown in plot F04-2-2a. Figure F04-2-2. From left to right: a) The first ionization energies and b) atomic radii as functions of atomic number (Z). The open circles correspond to d- and f-block elements. Both plots have the characteristic saw-tooth periodic character, but with "up-side-down" teeth, mirroring the inverse relationship between IE1 and atomic sizes. The dark blue points and green points in (a) mark full- and half-filled subshell exceptions, respectively. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 61/250 9/2/2019 Chem 110 The IE1 plot (F04-2-2a), has an unusual "upside-down" relationship to the analogous atomic radii plot (Plot F04-1-5b is repeated here for easier comparison). Note that noble gases and alkali metals have reversed their relative valley and peak positions. The peaks now decline in size with increasing Z (they are increasing in F04-2-2b), and the inter-peak points are on an upward trajectory (whereas they decline in F04-2-2b). These "inverted' characteristics of the plots are nothing more than the manifestation of the inverse relationship between the atomic radius and IE1 (bigger atoms have smaller IE1), and of the fact that increasing Zeff shrinks the atomic size and increases IE1. We can also see some irregularities within the periods of the saw-tooth pattern, appearing as secondary, smaller teeth, which are marked as green and dark blue points in F04-2-2a. Although quite subtle, these deviations can be rationalized in terms of subshell structure and the extra stability of filled and half-filled subshells. As a general rule, the completely filled subshells provide some added stability to the electron configuration. Thus, slightly larger IE1 values are commonly observed for atoms with a completely filled shell (ns2, nd10, and np6). This extra stability can be attributed to the perfectly spherical electron distribution in the completely filled subshells. These "filledsubshell" deviations are marked in dark blue on our plots (F04-2-2a and F04-2-3). A very similar trend is observed for halffilled subshells (marked green in F04-2-2a and F04-2-3). For example, nitrogen, with its half-filled p subshell (T03-3-10), is harder to ionize than oxygen (which has one doubly occupied p orbital ). This is true even though the latter has a larger Zeff (4.45 for 2p on oxygen vs 3.83 for 2p on nitrogen). In addition to the symmetrical charge distribution, such half-filled electronic configurations obey Hund's rule of maximum multiplicity. As previously stated, their maximum-spin configurations have lower energy, since they help to minimize electron-electron repulsion. The measured IEs are really the enthalpies (ΔH) of the ionization processes under a different name. Their positive signs unequivocally indicate that liberating electrons from the electrostatic grasp of the nuclei costs energy and is endothermic. The IE1 value is a measure of the stability of the electron configuration of the neutral atom: the bigger the value, the more stable the atom, with the highest stability exhibited by the noble gases (F04-2-3). On the other hand, the consecutive IEs measure the stability of the corresponding ions, again reaching the highest stability at the nearest noble gas configuration (with a smaller Z). Returning to our example of a Mg atom, we can easily deduce that in forming positive ions, this element would strongly prefer to form +2 cations (Mg2+), reaching the noble-gas configuration of Ne. Any further oxidation (electron removal) would be energetically prohibitive. Next, in an obvious extension of our quest to understand atomic properties, we shall explore how well atoms can accept additional electrons (i.e. undergo reduction). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 62/250 9/2/2019 Chem 110 04-3 Electron affinities Most atoms can accept one electron in the gas phase, yielding stable anions The electron affinity (EA) is the energy released when an atom in the gas phase accepts an electron. For example, in the case of a chlorine atom, the process is exothermic (C04-3-1): − Cl(g) + e ⟶ Cl − (g) EA = −349 kJ/mol C04-3-1 Most atoms, but definitely not all, can accept one electron to produce stable –1 anions in the gas phase. Atoms that have positive electron affinity cannot exist as gaseous anions; they would immediately eject the extra electron in an exothermic, spontaneous process. No atom can accept more than one electron in the gas phase, so we do not need to consider successive electron affinities. Note, however, that negative ions that are unstable in the gas phase may exist in liquid or solid states if some additional stabilization is provided (for example, electrostatic interactions with positive ions or other molecules). The EA values are collected in Figure F04-3-1. Missing values indicate that the anions are unstable in the gas phase and have unmeasurable positive EA values. The most exothermic values are found on the right side of the periodic table. Figure F04-3-1. The electron affinities (in kJ/mol) of main group and transition elements. Elements without values do not form stable anions in the gas phase (EA > 0). The color gradient (yellow → green) goes in order from atoms with least affinity to electrons (yellow) to atoms with most affinity (green). Electron affinities become more negative toward the right of the periodic table, but are near zero or positive for atoms with filled or half-filled subshells If considered as absolute values, (|EA|) the periodic trends in electron affinity largely follow those in ionization energies (IE1); the absolute numbers increase from left to right across the rows and decrease from top to bottom along the columns of the periodic table. Although the trends are much less pronounced for the electron affinities than they are for ionization energies, one interesting contrast is evident. The absolute values have their most dramatic changes (and peaks) one column earlier than what we found for IE1 values. For example, the largest IE1 values were found for noble gases (Figure F04-2-2a); now the most negative values belong to halogens (group 17). It might seem counterintuitive that the trends would be similar for energetics of removing an electron from an atom (IE1) and that of adding one (EA), but both processes are governed by the same underlying principles of changing Zeff, changing atom sizes, and shell and subshell filling patterns. In general, electron affinities do not change greatly as we move down the group. The extra electron is added to bigger and bigger orbitals as we travel down the column, and although it is more separated from the nucleus with each increase in n, that trend is compensated by the slight increase in Zeff and the fact that the bigger, more diffuse orbitals help to reduce repulsions between electrons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 63/250 9/2/2019 Chem 110 In general, the electron affinities are more favorable (more negative) as we move toward the right side of the periodic table. This trend follows the increasing Zeff in the same direction. As shown in F04-3-1, the near-zero negative or unfavorable (positive) values of EA are found for atoms with ns2 (group 2), nd5 (group 7), nd10 (group 12), np3 (group 15) and np6 (group 18) electron configurations. In all of these cases we are dealing with filled or half-filled subshells that are particularly stable. Adding one more electron would destroy that stability, so these processes are unfavorable; the highest positive affinities are found for filled-shell noble gases. On the other hand, atoms in columns just one before the filled or half-filled configurations need just one extra electron to reach that extra-stable configuration. For those atoms, EAs will be favorable (negative) and become more exothermic the further the atom is to the right of the periodic table (as Zeff increases). These trends, concluding with halogens having the most negative electron affinities, are illustrated in our now-standard periodic plot (F04-3-2). Figure F04-3-2. The electron affinity (EA) trends across a period. Although the trends are less clear than for other atomic properties, the saw-tooth pattern culminates in halogens (far right of a period in the periodic table) with most favorable (negative) electron affinities. The 1st ionization energy (IE1) plot on bottom illustrates the "mirror-image" relationship between IE1 and EA, where the plots show a peak for every change in period and show a small decrease in IE1 and EA down a column of the periodic table. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 64/250 9/2/2019 Chem 110 04-4 Ion sizes Cations are smaller than their parent neutral atoms, and anions are bigger We have learned about the trends in atomic radii (04-1) and energetics of making both positive ions (IE) and negative ions (EA). When cations are formed from neutral atoms electrons are removed from the outermost (valence) orbitals, usually in the number required to reach a stable noble gas electron configuration. Electron-electron repulsion is reduced as the total number of electrons is diminished. The removal of the most spatially remote electrons (the outer shell) and diminished repulsions result in significant size shrinkage; cations are always smaller than their parent neutral atoms. On the other hand, when electrons are added to atoms (again, usually in numbers required to reach the stable electron configuration of a noble gas) they end up in the outermost valence orbitals and electron-electron repulsion is increased. The effect is a significant increase in size; anions are always bigger than their parent neutral atoms. These trends in ion size changes are illustrated in Figure F04-4-1. Only the atoms with the most negative EAs are capable of forming stable anions, even with electrostatic stabilization from other ions in a crystalline ionic solid. Therefore, it is not surprising that the majority of ions shown in the summary are cations. For the main group elements, most of the ions included in our chart have a noble gas configuration. The ionic sizes follow the same trends as those observed for neutral atoms (04-1). Ions of the same charge increase in size down the column, mainly due to the new electron shell added with each increase in n. The ions shrink from left to right for both the cations and anions (in separate trends). As can be seen by comparison with the sizes of the neutral atoms, this trend is a combination of the increasing nuclear charge and the effect of the increasing ion charge for the cations or diminishing ion charges for the anions (see below). For d-block elements (click on F04-4-1 to see the transition metal ions), the ions are quite similar in size and there are no clear trends. As we have noted previously, the neutral atoms of transition metals do not differ very much in their sizes. Additionally, they most often make cations of similar charges. The result is a small variance in the ionic radii, with no pronounced trends. The ionic radii provide useful information for evaluating bonding arrangements in ionic crystals, much as the bonding radii allow us to predict bond lengths in molecules of interest. As we will learn, such information is beneficial even if only applied in a qualitative way based on the observed trends. You may be surprised, for example, to learn that the trend in ionic radii can be translated into a ranking of the melting points of ionic solids! We will return to that topic when we address ionic bonds in Lesson 06-3. Figure F04-4-1. Ion sizes (gray hemispheres) as compared to the neutral parent atoms (shown in their standard assigned colors). For main group elements, mostly ions with noble-gas configurations are shown. For transition metal ions, only some of the most common ions are shown (click on the picture to see the d-block elements). All sizes are in pm (1 pm = 100 Å). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 65/250 9/2/2019 Chem 110 The size of the ions in isoelectronic series decreases as nuclear charge increases As mentioned above, most of the ions in Figure 04-4-1 were selected because they have filled shells, which matches the electron configuration of the noble gases. Let's examine this choice a bit closer by concentrating on the most commonly encountered ions of the main group elements (F04-4-2). In the first row Li+ and Be2+ have the electronic configuration of He, but N3–, O2–, and F– have the electron configuration of Ne. The same [Ne] configuration is found in Na+, Mg2+ and Al3+ in the next row. Thus, we have a nicely ordered isoelectronic series: a group of ions that has exactly the same number of electrons, with the exact same ground state electron configuration. — increasing nuclear charge→ N3− 146 pm O2− 140 pm F− 133 pm Na+ 102 pm Mg2+ 72 pm Al3+ 54 pm — decreasing radius → Such ordering makes predicting their size trends quite simple: their radii decrease with increasing nuclear charge, Z. Notice that in this order, the anions of the higher row precede the cations of the lower row. Figure F04-4-2. Isoelectronic series for the most common ions of the main group elements. All ions on a common color background have the same number of electrons in the same ground-state electron configuration. Their sizes shrink as their nuclear charge Z increases. Click on the picture for a larger version. Main group elements tend to form ions with noble gas configurations, whereas transition metals can form a number of different cations Although our table of ions (Figure 04-4-1) lists specific ions for all main group elements and transition metals, in reality, the situation is a bit more complex. The number of common mono-atomic stable anions is quite limited. You may remember that in the gas phase only anions with –1 charge are thermodynamically accessible, and not even for all elements. Anions with larger charges (–2 and –3) exist only in the liquid or solid phases when they can gain electrostatic stabilization from cations or other molecules. Stable examples are strictly limited to the anions of nonmetals on the right side of the periodic table, with all anions having stable noble gas configurations (Figure F04-4-3). The mono-atomic cations are much more diverse, since they can be formed by all metals from the left and central part of the periodic table. The main group metals form cations with noble gas configurations (group 1 and 2) or with filled subshells (group 14 or 15). Transition metals form multiple ions with various electron configurations. A hydrogen atom may become a cation (proton, H+) or an anion (hydride, H−). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 66/250 9/2/2019 Chem 110 Figure F04-4-3. The most common stable ions. Metals (red and orange elements) tend to form cations, while nonmetals (green) tend to form anions. The anions shown all have noble gas configurations. Metalloid elements (brown) tend to form either cations or anions. Transition metals may have noble gas electron configuration but may form non-noble gas electron configurations as well. The hydrogen atom may become a cation (proton) or an anion (hydride). Although hydrogen is not a metal at standard conditions, experiments have proven that hydrogen forms metallic bonds at very high pressures (on order of GPa). In general, when cations are formed from neutral atoms, the electrons are always first removed from the occupied orbital having the largest principal quantum number, n. If there is more than one occupied subshell for a given value of n, the electrons are first pulled out of the orbital with the highest value of ℓ. Let's analyze some examples: 2 2 + Mg ([Ne]3 s ) ⟶ Mg 6 2 Fe ([Ar]3d 4s ) ⟶ Fe Fe 2 + 6 ([Ar]3d ) ⟶ Fe C04-4-1 − ([Ne]) + 2 e 2 + 3 + 6 C04-4-2 − ([Ar]3d ) + 2 e 5 C04-4-3 − ([Ar]3d ) + e In the case of magnesium (C04-4-1), an ns2 main group element, the valence electrons from the 3s subshell are removed resulting in a cation with a noble gas configuration. In the case of iron, a transition metal, the first two electrons are removed from the 4s subshell (C04-4-2), and only the next electron to be removed (forming Fe3+) would come out of the 3d subshell (C04-4-3). This may seem confusing if you remember first filling the lower energy 4s subshell and then the 3d subshell when we were determining electron configurations for the transition metals in the periodic table. However, this imaginary process of adding electrons one at a time as we move from element to element does not take into account the change in effective nuclear charge from atom to atom (and from orbital to orbital). We must recall that in transition metals the (n-1)d and ns orbitals are close in energy, and d-electrons actually have lower energy than s electrons once the d orbitals are occupied. When occupied, the 3d orbitals shield the 4s electrons from the nucleus so that the 4s orbital is higher in energy. Sn ([Kr]4d 2 + Sn 10 2 2 2 + 5s 5p ) ⟶ Sn ([Kr]4d 10 2 4 + 5s ) ⟶ Sn ([Kr]4d ([Kr]4d 10 10 2 − 5s ) + 2 e − )+ 2e C04-4-4 C04-4-5 In the case of atoms with more than one occupied subshell, such as in tin (C04-4-4), the first two electrons are removed from the subshell with the highest n and ℓ (5p), and only the next two come out of the 5s subshell (C04-4-5). Note that in this case the electrons in the completely filled 4d subshell are not considered valence electrons, so the oxidation of Sn, stops at +4, which is not a noble gas configuration (although it has no open subshells). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 67/250 9/2/2019 Chem 110 04-5 Periodic trends Ionization energies are the dominant factor influencing the metallic or nonmetallic properties of elements We are now well versed in the properties of individual atoms and their ions in the gas phase and can understand the trends governing these properties. Yet, with the exception of noble gases, none of the elements exist in the form of separated, individual gaseous atoms. We need to develop a way to translate the properties of individual atoms and ions into the properties of bulk elements. We need to figure out how atoms combine together into larger assemblies such as molecules or extended networks, and how the individual molecules interact with each other to determine the properties of bulk materials. And we will eventually need to understand how atoms of different elements come together to form the variety of substances that we find in the surrounding world or make in our laboratories and factories. We started our journey already (03-4) when we drew a map with a dividing line between different regions to explore. We reproduce that "map" below (F04-5-1). At the time our "divide-and-conquer" strategy might have seemed arbitrary, but now we are ready to support it with some objective data. Figure F04-5-1. The periodic table with metals, nonmetals, and metalloids marked. Alkali metals (group 1) are all highly reactive and readily become +1 ions, while alkaline earth metals (group 2) are less reactive and form +2 ions. Transition metals form many different ions, but share characteristics that set them apart from other elements. They are similar because of their incompletely filled d-subshells. In the same way, lanthanides and actinides resemble each other due to their partially filled f-subshells. Among the nonmetals we have the chemically inert noble gases (group 18), the halogens (group 17), the oxygen family (chalcogens, group 16), and the nitrogen family (pnictogens, group 15). Let's revisit the basic atomic property that tells us how strongly electrons are attracted to the nucleus, IE1 (F04-5-2). We now draw another dividing line in the plot at IE1 slightly below 1000 kJ/mol. Essentially all elements below this line are identified as metals in the periodic table above, all elements above the line are nonmetals, and the few elements in close proximity to the line are metalloids. The cleanness of the break (although there are a few minor outliers) is dazzling in its simplicity, yet it underscores how electronic configuration, an abstract atomic property, governs the tangible properties of elements in bulk. The metals have low IEs, easily give up their relatively weakly bound electrons and form cations. The nonmetals have high IEs, do not give up their electrons readily, and a select few (with highly favorable electron affinities) form stable anions. The metalloids are somewhere in between, but as their name indicates, they are more like metals than nonmetals on average https://genchem.science.psu.edu/sites/default/files/filefnlBYE 68/250 9/2/2019 Chem 110 Figure F04-5-2. The first ionization energies as a function of atomic number (Z). The dividing line drawn at IE1 just below 1000 kJ/mol, neatly divides the elements into metals (orange circles) that fall largely below the line, nonmetals (green squares) which appear mainly above the line, and metalloids (brown triangles), in close proximity to the line. Metals are lustrous, malleable and ductile (easily shaped), and they conduct heat and electricity very well. Most are solids; Hg is the one exception, and is a liquid at room temperature. All of these properties are related to the availability of high-energy electrons that can roam freely in the solid structures of bulk samples. The group 1 alkali metals form +1 cations most easily (they have the lowest IEs), with the largest atoms being the most reactive. The group 2 alkaline earth metals are somewhat less active in formation of +2 cations, and they are followed in reactivity by the other elements that form multiple cations with various charges (F04-4-3). Nonmetals are usually brittle solids, liquids or gases at room temperature. Some nonmetals are monatomic (noble gases), while others are diatomic (O2, N2, F2, Cl2, I2, Br2, H2), tetratomic (P4), or even octatomic (S8) at room temperature and pressure. Generally, they are poor or non-conductors of heat or electricity. Their properties are related to their unwillingness to let their valence electrons go (they have high IEs). Instead, some of them tend to accept extra electrons and form anions (−1 for group 17, −2 for group 16, and −3 for group 15). The noble gases are an extreme example of stability and are very unreactive. With their closed shell electron configurations, they do not readily give up their electrons, nor do they accept any; they have the highest IEs in each row. They do not form stable ions, and the two smallest (He and Ne) never participate in any bonding, forever destined to be unattached. You may explore all the elements, including their properties, appearance, and history, in our interactive periodic table. The table can be launched by clicking on the button "Periodic table" on the right upper corner of any web page. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 69/250 9/2/2019 Chem 110 05 Molecular Composition In the previous Lessons, we learned a lot about the properties of individual atoms. The substances we encounter in the world around us, however, are very rarely in atomic form. Your experience with atomic species is most likely limited to the helium in party balloons, or to the trace amounts of other noble gases in our atmosphere. The substances we encounter most often are not atomic species, but assemblies of atoms, joined by strong bonding forces. The assemblies are quite diverse, from pure elements in various allotropic forms, to compounds built of atoms of different elements formed into molecules or extended networks. They differ in composition and structure. In our quest to understand how atoms join together, we will first analyze the composition of chemical compounds. After we learn what atoms are present, and in what ratios, we will be ready to probe their bonding arrangements and structure in future Lessons. 05-1 Assemblies of atoms Pure elements may exist in atomic form (noble gases only), as homonuclear diatomic molecules (hydrogen, oxygen, nitrogen, and halogens), as homonuclear polyatomic molecules (phosphorus and sulfur), or as extended networks (such as metallic solids or carbon and silicon). Compounds that are assemblies of at least two types of atoms can exist as molecules or extended networks. The latter includes ionic solids, wherein atoms exist in the form of ions. The participating atoms and their ratios are described by their empirical or molecular formulas which list the atoms with subscripts indicating their relative ratios. 05-2 Formulas The empirical formula is the simplest formula that gives the correct relative number of atoms of each kind. It is usually obtained experimentally from elemental analysis. It defines the smallest repeating unit of the composition (but not necessary the smallest repeating structural unit). The molecular formula is the formula that specifies the number of each atom type in one molecule. The molecular formula can be defined only for substances that consist of well-defined molecular structures. The molecular formula is always a multiple of the empirical formula, with "1" being a possible and even common multiplier. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 70/250 9/2/2019 Chem 110 05-1 Assemblies of atoms Atoms combine into compounds composed of molecules, ions, or extended networks In previous Lessons we learned about individual, isolated atoms and their properties, and how properties are determined by an atom’s electron configuration. Yet, with the exception of noble gases, atoms are encountered in assemblies, where the individual participants are strongly bonded together within molecules or extended networks. In our quest to understand how and why atoms bond together, we start with the simple question of composition: how many atoms and what type of atoms come together to form the assembly? In general, we will encounter assemblies of atoms of just one element or two or more elements. Various structural forms in which pure elements can exist are called allotropes. Allotropes have the same composition, but different structures, i.e., different atom connectivity. In such cases there is really no issue of composition, except perhaps for relative isotopic abundances, as all atoms present are of the same type. Assemblies of atoms of two or more elements are called compounds. The majority of substances around us are pure compounds or are mixtures of compounds. The simplest assemblies are composed of just two atoms. If the atoms are of the same element, they are called homonuclear diatomic molecules. If they are composed of two different atoms they are called heteronuclear diatomic molecules. To express their compositions, we just list the atoms present. For example, H2 is the smallest molecule built of the two simplest atoms, F2, Cl2, Br2, or I2 are the halogen molecules, and N2 and O2 are the most abundant gases in our atmosphere. Examples of heteronuclear diatomic molecules include HF (hydrogen fluoride), HCl (hydrogen chloride), HBr (hydrogen bromide), CO (carbon monoxide), and NO (nitrogen oxide). Figure F05-1-1. Examples of homonuclear (Cl2, O2) and heteronuclear (HCl, CO) diatomic molecules. At this stage we are interested only in the composition of atomic assemblies. We will analyze these structural details in later Lessons. The vast majority of atomic assemblies contain more than two atoms. These may include collections of identical atoms bonded into polyatomic molecules such as O3 (ozone), P4 (white phosphorus), or S8 (cyclooctasulfur), or extended networks containing huge numbers of bound atoms such as diamond (an allotrope of C) or a metal (such as Fe or Au). For illustration purposes, a 1 carat diamond (F05-1-3) contains 0.017 mole or 1022 atoms of carbon, while a cubic centimeter of gold (F05-1-3) has about 0.1 mole or 6 × 1022 atoms of gold. Figure F05-1-2. Examples of the simple elemental molecules: ozone (O3), white phosphorus (P4), and cyclooctasulfur (S8). For now, we are focusing only on the composition of these molecules. You may explore them in 3D by clicking on the picture, although the bonding details will be discussed in later Lessons. , Figure F05-1-3. Examples of the extended atomic networks of carbon (diamond) and gold. Click on structural pictures to interact with 3D models. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 71/250 9/2/2019 Chem 110 The most often encountered assemblies, called compounds, are composed of atoms of different types. Some form polyatomic molecules consisting of just a few atoms, such as CH4 (methane), H2O (water), NH3 (ammonia), HNO3 (nitric acid), or H2SO4 (sulfuric acid). However, they may also be built of hundreds of millions of atoms, as in the DNA molecule of a single gene, or anything in between in size. Figure F05-1-4. Examples of polyatomic compounds methane (CH4), water (H2O), ammonia (NH3) and nitric acid (HNO3). You may click on the molecules to explore them in 3D. We will explore the details of these structures in later Lessons. Atoms may also participate in compounds in the form of ions, forming extended ionic solids. These solids can be composed of only atomic ions, such as NaCl (sodium chloride), MgBr2 (magnesium bromide), or CaO (calcium oxide). Ionic solids can also be composed of both atomic and molecular ions, as in NaNO3 (sodium nitrate), KOH (potassium hydroxide), or NH4Cl (ammonium chloride). Additionally they can be composed completely of molecular ions, such as in (NH4)2SO4 (ammonium sulfate). Such ionic solids may contain a huge number of ions, depending on their crystal size. A 1 mm3 crystal of NaCl from a salt shaker contains about 2 × 1019 ions of each type. Ionic solids may also contain water molecules incorporated in a definite ratio in the crystal structure. Such water molecules usually surround metallic ions and often can be removed from the crystals with heat. A notation "•nH2O" is used to indicate the number (n) of water molecules per empirical formula, for example CuSO4•5H2O shows that there are 5 water molecules per each Cu2+ ion. Such water-containing salts are called hydrates CaO ScN NaNO3 KOH Figure F05-1-5. Examples of ionic solids from left to right: CaO, ScN, NaNO3, and KOH. Compounds are characterized by their composition and structure As you may have noticed reading the formulas above, we express the atomic composition by listing all the atoms participating in the assembly and their relative amounts (as subscripts). Both of these pieces of information are critical in describing the composition of the atomic assembly, but are not sufficient to fully describe its structure. Just listing of atoms does not tell us anything about the structure, for example, dioxygen (O2) and ozone (O3) are both made of only oxygen atoms but they have different molecular structures. Carbon (C) may exist as C60 molecules, or as extended networks of diamond or graphite, each with its unique structure. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 72/250 9/2/2019 Chem 110 Similarly in assemblies that contain multiple types of atoms, without specifying the atom ratio, we could not distinguish between CO (carbon monoxide) and CO2 (carbon dioxide), both of which are composed of carbon and oxygen, but in different ratios and connectivity. Even with the atoms and their ratio specified, we may still not be able to uniquely identify the assembly, For instance, for a formula such as CH2, even though we know that the compound is made of carbon and hydrogen atoms in a 1 : 2 ratio, we still need to know how many of these CH2 units are present in the entire assembly. For example, there are two CH2 units in ethylene (C2H4) five in cyclopentane (C5H10) and six in cyclohexane, (C6H12) and each of these compounds has a different structure. Even when the molecular formula is defined, numerous structural variations are possible. For example, there are 12 different stable structures (called isomers) possible for a compound with a molecular formula of C5H10 (Figure F05-1-6). Figure F05-1-6. Some molecular structures with an empirical formula of CH2. Click on the structures to explore their 3D shapes. Click on the cyclopentane link to see the slide show of all 12 stable isomers with the formula of C5H10. The details of these structures and their nomenclature will be explored in future Lessons. In the atomic assemblies listed above, atom ratios are expressed with small integers (whole numbers). This observation is in total agreement with atomic theory, which postulates that atoms are the smallest building blocks of matter from the chemical point of view and that they do not change their identity in chemical reactions. Indeed, the basis for the atomic theory first proposed in the early 19th century at the beginnings of modern chemistry was the observation that the proportion of elements in a given compound are the same regardless of its source, and that they are expressed by small integers. We will tackle the issue of structure (how the atoms are bonded and why) in later Lessons, but for now we will concentrate on various ways to express and understand composition. We will define and apply the concepts of empirical and molecular formulas. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 73/250 9/2/2019 Chem 110 05-2 Formulas Empirical formulas give the smallest relative number of each kind of atom whereas molecular formulas specify the number of each type of atom in one molecule According to our observations, each atomic assembly or compound may be described by a formula that specifies the relative number of atoms of each element present in that compound. The empirical formula is the simplest formula that gives the correct relative number of each kind of atom. In other words, the empirical formula defines the smallest repeating unit of the composition (but not necessarily the smallest repeating structural unit). The molecular formula is the formula that specifies the number of each atom type in one molecule. The molecular formula can be defined only for substances that consist of well-defined molecular structures. All gases (except for noble gases) consist of molecules, and so do most liquids and a number of solids. The molecular formula is always a multiple of the empirical formula (with "1" being a possible and even common multiplier). When the molecular formula is known, it is clearly a preferable way to describe the composition of the compound, as it precisely defines the molecular unit. However, it is impossible to provide the molecular formula for many substances that are not composed of molecules; in those cases the empirical formula is the only option. Let's look at some examples. The empirical formula of carbon dioxide is CO2. Since the carbon dioxide molecule is built of one carbon and two oxygen atoms, the molecular formula is also CO2 (the multiplier is one). The empirical formula of glucose is CH2O, but its molecular formula is C6H12O6 (the multiplier is six). The empirical formula only tells us about the ratio of atoms, while the molecular formula identifies that one molecule of glucose is built of 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. Figure F05-2-1. Molecular structure of glucose, C6H12O6. Click on the image for a 3D model. In contrast, sodium chloride (table salt) has the empirical formula NaCl, indicating that the ratio of sodium to chlorine is 1:1 (the structure actually contains ions of Na+ and Cl−). As we have previously illustrated, NaCl forms an extended ionic solid with a 3 dimensional structure of alternating ions. In this case, no individual "NaCl" molecules can be identified; all of the ions are interacting equally with their oppositely charged neighbors. We can only use the empirical formula in such cases. The empirical or molecular formula specifies the ratio of all atoms present in the compound, so now it is possible to specify the formula mass (or molecular mass) by adding the masses of all the atoms in the formula. For example, in carbon dioxide there are two oxygen atoms per each carbon, and the molecular mass is 44.01 amu (12.01 amu + 2 x 16.00 amu). We can also specify the mass of one mole of molecules. This quantity, called molecular mass, molecular weight, MW, or formula weight, FW, (especially if it is based on the empirical formula) can be calculated by adding the atomic weights of all atoms present, and using units of g/mol. One mole of CO2 molecules contains one mole of carbon atoms and two moles of oxygen atoms, and thus FW(CO2) = 44.01 g/mol. Note that we measure mass by weighing it, and in Earth's gravitational field weight and mass are synonymous; in general, the same mass would have different weights in different gravitational fields. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 74/250 9/2/2019 Chem 110 Figure F05-2-2. The relationships between number of particles, number of moles, and masses of samples. Empirical formulas are determined experimentally using percent composition data We can convert the molecular composition into mass percentage of its constituent elements. The calculation can be performed in amu or in g/mol, and it is equally applicable to the empirical formula and the molecular formula, with both giving the same results since they represent the same ratio of elements. In this formula n is the number of atoms of an element, and AW is its atomic weight, while FW is the molecular weight (both must be in the same units, whether amu or g/mol). % of element = n × AW E05-2-1 × 100% FW For CO2, the %C in carbon dioxide is 27.3% and the %O is 72.7%. Since carbon and oxygen are the only elements present in CO2, the mass percentages of the two must add up to 100%. It is always advisable to carry out that internal check, especially for more complex formulas with multiple elements. So, given a formula, one can determine the mass percent of each element in the molecule. Mass percent calculations can also be inverted; one can determine the formula given the mass percent of each element in the molecule. Imagine, for example, that we know that the substance named butyric acid has an experimentally-determined composition by mass of %C = 54.2%, %H = 9.15%, and %O = 36.6%. What would be the formula? A simple way to accomplish this task is to assume that we have a 100 g sample; since we are dealing with %, that simplifies the calculations. Our sample would then contain 54.2 g of carbon, 9.15 g of hydrogen, and 36.6 g of oxygen atoms. We can calculate the number of moles of each element: moles of C = 54.2 g = 4.52 mole => 9.15 g moles of H = = 9.08 mole => = 1.97 per mole of O 9.08 = 3.97 per mole of O 2.29 1.01 g/mol 36.6 g moles of O = 4.52 2.29 12.0 g/mol = 2.29 mole => 16.0 g/mol 2.29 = 1.00 per mole of O 2.29 Knowing the number of moles of each atom, we can calculate the ratio of atoms in the formula. We divide all the numbers of moles of each atom by the smallest number of moles (which is oxygen in this example). Thus, we have determined the ratio of carbon to oxygen and hydrogen to oxygen. Since the % composition values were obtained experimentally, we do not expect to get perfect integer ratios for all atoms. The deviations are very minor, however, and are easily rounded to yield a formula for butyric acid of C2H4O. This calculated formula is an empirical formula; it gives the smallest integer ratio for the atoms present. This is also why such a formula is called "empirical"; it comes from the experimental measurement of the mass percentages of the elements present. Such measurements are called elemental analysis, and are routinely carried out to establish the atomic composition of compounds. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 75/250 9/2/2019 Chem 110 Empirical formulas augmented by molecular mass information give molecular formulas Returning to our results for butyric acid, we still need to decide if the empirical formula is actually the molecular formula of the compound. What is the multiplier? To answer that question we need additional information; we need to know how many "formula units" are contained within the structure of butyric acid. The simplest way to do that is to establish the molecular weight of the compound by another independent method. We have learned before that mass spectrometry can provide precise molecular weights. This technique is based on forming ions from atoms or molecules and sorting them by mass with the help of a magnetic field. Using mass spectrometry, we can determine that butyric acid has a molecular mass of 88.10 g/mol. The empirical formula of C2H4O that we calculated has a formula weight that is too small; FW(C2H4O) = 44.05 g/mol. Clearly our empirical formula has to be multiplied by 2. Therefore the molecular formula of butyric acid is C4H8O2.. Figure F05-2-3. Molecular structure of butyric acid, C4H8O2. The structure is based on independent determination. There are hundreds of isomeric structures possible with this molecular formula. Click on the image for a 3D model. Even though we have determined the empirical formula and the molecular formula of butyric acid, we still really don’t know anything about the structure of the compound. Many different structures that contain these component atoms are possible. Our next goal is to figure out how the atoms are connected to each other and by what type of bonds. This description will be called a structural formula (as in F05-2-3), and will account for all the valence electrons of all atoms involved in bond formation https://genchem.science.psu.edu/sites/default/files/filefnlBYE 76/250 9/2/2019 Chem 110 06 Bonding The vast majority of substances around us are composed of assemblies of atoms held together by strong electrostatic forces called bonds. To form such bonds, atoms redistribute their valence electrons to achieve a noble gas configuration. The bonding that results lowers the energy of the system. 06-1 The octet rule Filled-shell noble gas configurations, with their perfectly spherical electron densities, are especially stable. Other atoms may achieve this configuration only by gaining, losing, or sharing electrons. With the exception of the hydrogen atom, which only needs to be surrounded by two electrons to achieve the same configuration as [He], all atoms need eight electrons in their valence shell to have a full shell, or noble gas configuration. This is called the octet rule; fulfillment of the octet rule is the driving force for bond formation. Atoms achieve this octet by forming ionic or covalent bonds. In ionic bonding, ions with noble gas configurations and opposite charges are electrostatically attracted to each other and come together to form extended ionic solids. In covalent bonds, atoms share electron pairs that are attracted to two nuclei at once. For nonmetals, the number of covalent bonds that an atom prefers (called valence) is 8 − N, where N is the number of valence electrons on that atom. Metals and metalloids often do not follow the octet rule when bonding to nonmetals. Metal atoms do not have enough electrons to satisfy the octet rule and they bond with each other through metallic bonding wherein all valence electrons are shared equally by an extended network of metallic cations and are free to move throughout the metal. 06-2 Ionic bonding Metal atoms can lose electrons, and nonmetal atoms can gain electrons; both form ions with noble gas configurations. The formation of such ions in the gas phase is endothermic, but the electrostatic attraction between ions in close proximity in the solid state compensates for the energy required to form gaseous ions. As a consequence, ionic compounds form extended networks or lattices, which are organized to maximize the electrostatic attractions between ions of opposite charge and minimize repulsions between ions of like charge. 06-3 Lattice energy The strength of ionic bonding is gauged by the lattice energy, i.e., the energy necessary to convert one mole of an ionic solid into individual ions in the gas phase. Lattice energy is not directly measurable, but can be calculated based on thermodynamic cycles. If the electrostatic interaction between the ions is stronger, the lattice energy is higher. The energy of these electrostatic interactions is proportional to the product of the charges on the ions, and inversely proportional to the separation between them (taken as the sum of their ionic radii). Lattice energy accounts for all attractions and repulsions in an ionic solid, and is therefore affected by the packing of ions in the crystal. Ionic solids generally have high melting points, a property which correlates with the magnitude of their lattice energy. 06-4 Covalent bonding Covalent bonds form between nonmetal atoms when electron pairs are shared between adjacent atoms. The shared electrons are attracted to both nuclei. These energy-lowering electrostatic interactions are most effective if the electron density increases along the internuclear axis between the bonded atoms. A shared pair of electrons constitutes a covalent bond; if only one pair is shared between two atoms, that bond is referred to as a single bond. To account for electron sharing schemes, we use Lewis structures, which are diagrams of lines and dots surrounding atomic symbols. Shared pairs are drawn as lines (representing the connectivity of atoms within the molecule), and the nonbonding lone pairs are represented by dots. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 77/250 9/2/2019 Chem 110 06-5 Multiple bonds In some molecules the atoms share two or three electron pairs, forming double or triple bonds, respectively. The number of electron pairs shared is called the bond order. Bond orders of 2 or 3 are normally found between nonmetal atoms of the second row of the periodic table. Multiple bonds are shorter and stronger than corresponding single bonds, although the second or third bonds are typically weaker than the first. Bond lengths between a specific pair of atoms usually change very little from compound to compound and average values provide an approximate measure of interatomic distances. For single bonds, bond lengths are interpreted as the sums of the atomic bonding radii, and the trends that govern atomic size may be used to predict trends in bond lengths. In general, smaller atoms form shorter and stronger bonds than bigger atoms. Bond strength is measured by the bond dissociation energy (BDE), i.e., the energy needed to break that specific bond (while leaving the other bonds in the molecule intact). In general, BDEs follow the same trends as bond lengths and do not vary drastically from molecule to molecule. Average bond energies provide a good measure of the stabilizing effects obtained when electron pairs are shared. 06-6 Polyatomic ions So far we have discussed ions formed by atoms accepting or giving up their valence electrons. Covalent molecules may also form ions, for example, by losing or gaining protons (H+). The polyatomic ions so created have internal covalent bonding, but form ionic solids with other atomic and polyatomic ions of opposite charge. Usually, such salts exhibit ordered crystalline structures, but with weaker electrostatic attractions between ions than those found in atomic ions. The polyatomic ions are typically more separated in the solid, or even insulated from each other by the covalent moieties. The typical polyatomic ions, called oxyanions, are species with a large number of oxygen atoms bonded to the central atom that could be a metal or nonmetal. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 78/250 9/2/2019 Chem 110 06-1 The octet rule Formation of a stable octet electron configuration can be achieved by ionic or covalent bonding, but metals participate in metallic bonding due to an insufficient number of valence electrons Through our exploration of the electron configuration of atoms, their ionization energies, and their electron affinities we have learned that filled-shell noble gas configurations are especially stable, with their perfectly spherical electron densities. It should not be at all surprising that achieving such a configuration is the driving force in formation of atomic assemblies. A system composed of atoms may lower its energy if the atoms can achieve the electronic configuration of a noble gas by reapportioning their electrons when they come together. With the exception of helium (which has two valence electrons), a noble gas configuration means that there are eight electrons in the valence shell of the atom. An atom will have to lose, gain, or share electrons to achieve this number. Any such adjustments may only involve the valence shell electrons; they are energetically the easiest to remove or share, and additional electrons can only be added to the outermost valence shell. We call this phenomenon the octet rule: whenever possible, the electrons in a compound (or other bonded assembly) are distributed in such a way that eight electrons surround each atom of the main group element. Hydrogen atoms are surrounded by only two electrons in their structures to match the helium configuration. The American chemist G. N. Lewis introduced a useful model to account for the valence electrons of atoms and their apportionment among atoms participating in bonding. In this model, called a Lewis dot structure, the electrons are drawn as dots surrounding atomic symbols (T06-1-1). The first four dots are placed separately around the four sides of the atomic symbol, and any additional dots are then paired with those already present. Figure F06-1-1. Lewis dot structures for the main group elements. All elements in a family (column) of the periodic table have identical number of valence electrons. The octet configuration can formally be achieved in two different ways, giving us two distinct forms of bonding: ionic, and covalent. Metals that do not have sufficient number of valence electrons to form octets participate in the third type of bonding (metallic bonding). All types of bonding are based on electrostatic attractions between positively charged nuclei and negatively charged electrons; these interactions decrease the overall energy when atoms join together and result in a more stable system. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 79/250 9/2/2019 Chem 110 Ionic bonding is formed by ions of opposite charges. The lowering of the energy is a result of the electrostatic attraction between anions and cations. Covalent bonding is based on the sharing of electron pairs among directly bonded atoms. The shared electrons are electrostatically attracted to the bonded nuclei, lowering the energy of the system. In metallic bonding, because there are too few electrons to satisfy the octet rule, electron sharing is carried out to an extreme. Valence electrons are shared among all metal atoms. In a way, metal cations are "bathed" in a sea of electrons that move freely through the metallic solid. Ionic bonds form when metals transfer electrons to nonmetals, forming ions that attract each other electrostatically Ionic bonding is found between atoms from opposite ends of the periodic table. As you may remember, metals have low ionization energies (particularly group 1 alkali metals), and can easily lose electrons to form cations with noble gas configurations. On the other hand, nonmetals, particularly halogens (group 17), have favorable negative electron affinities, and easily gain electrons to form anions with noble gas configurations. These complementary characteristics of metals and nonmetals are perfect for electron transfer between the bonding partners. For example, a sodium atom may give up its valence electron to become a sodium cation (with a noble gas configuration), while a chlorine atom can accept that electron, and be converted into a chloride ion, also with the noble gas configuration (F06-1-1). The resulting ions are strongly attracted to each other by an electrostatic force, and form an extended crystalline solid NaCl (sodium chloride). Figure F06-1-2. Ionic bonding in sodium chloride. An electron transfer from the sodium to the chlorine atom generates ions of opposite charges that are attracted to each other by an electrostatic force. The Lewis structures of the atoms and the ions formed by the electron transfer are also shown. Note that the ionic charges are shown as a superscript. Both Na+ and Cl−have noble gas configurations. Covalent bonds form when nonmetals share electrons Covalent bonds form mainly between nonmetal atoms. As you may recall, electrons in nonmetals are held quite tightly, as is illustrated by their relatively high ionization energies. An octet configuration can be obtained by sharing electrons rather than by giving them up (which would be energetically costly). For example, two hydrogen atoms may come together to form an H2 molecule. In the H2 molecule the two electrons are attracted to both nuclei, formally giving both atoms the [He] configuration. Similarly, by sharing two electrons, two fluorine atoms form an F2 molecule with an octet of electrons around each. In the hydrogen fluoride molecule, a hydrogen atom and a fluorine atom combine, wherein the hydrogen has the [He] configuration while the fluorine has an octet of electrons. The shared electron pairs are replaced by a line connecting the atoms in the Lewis structure of covalently bonded atoms; in the standard chemical notation, this line represents the bond. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 80/250 9/2/2019 Chem 110 Figure F06-1-3. Covalent bonds in Lewis notation. The bond is a shared pair of electrons attracted to both nuclei (and possibly screened by core electrons). For nonmetals, simple arithmetic tells us how many covalent bonds the atom needs to form in order to satisfy the octet rule. For example, referring back to Table 06-1-1, it is immediately obvious that carbon needs to form four bonds, nitrogen requires three, and both fluorine and hydrogen require one. The number of desired covalent bonds must match the number of unpaired electrons in the Lewis dot structure of the atom. You may recall that we already introduced the concept of the valence of an atom as the number of covalent bonds an atom prefers to form; now we know that the octet rule is behind that concept. The number of bonds needed by a neutral atom is 8 − N, where N is the number of valence electrons. The nuclei and core electrons in metallic bonding are immersed in an electron sea composed of all valence electrons Figure F06-1-4. Electron sea model of metals. The metal cations (the nuclei and core electrons) are immersed in a "sea" of their valence electrons which freely roam around the cations. Metals, in general, do not have enough valence electrons to satisfy the octet rule by forming specific bonds between atoms one electron pair at a time. To overcome this deficiency, the valence electrons are collectively shared by all metal ions in the solid. A simple model that accounts for bonding in metals is called the electron-sea model. In this model, the metal is an extended, tightly packed 3-dimensional network of metal cations (which consist of the nucleus plus core electrons) immersed in a "sea" of mobile electrons. The electrons are confined to the solid by their electrostatic attraction to the nuclei, but can easily "flow" via their thermal motions or if a voltage is applied; this explains why metals are good conductors of heat and electricity. The fact that metal cations in the network may have up to 12 close neighbors also accounts for metal malleability and ductility (ease of shape deformations), as ions can change their positions in space relative to their partners easily, and electrons can adjust to this new spatial positioning of the nuclei without difficulty. A full explanation of metallic properties requires refinement to the simple model described here. We will postpone such in-depth discussion of metallic bonding until the second semester of general chemistry. In this lesson, we will concentrate on probing ionic and covalent bonding. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 81/250 9/2/2019 Chem 110 06-2 Ionic bonding The formation of ions of opposite charges from neutral atoms is energetically unfavorable in the gas phase Let's return to our example of ionic bonding in sodium chloride. Since we know how much energy it takes to ionize sodium in the gas phase (IE1 = 496 kJ/mol) and how much energy is released when chlorine accepts an electron (EA = −349 kJ/mol), we can very easily evaluate the overall energetics of the formation of one mole of separated ions of each kind in the gas phase. + Na(g) + Cl(g) ⟶ Na (g) + Cl − (g) Δ Hr xn = (496 − 349) kJ/mol = 147 kJ/mol C06-2-1 This process is clearly endothermic, meaning that it will not occur spontaneously in the gas phase. Chlorine has the most favorable electron affinity of all elements, but even if we match it with the easiest element to oxidize, (cesium, with an IE1(Cs) = 376 kJ/mol) ion formation in the gas phase would still be unfavorable; the overall enthalpy change would be ΔHrxn = 27 kJ/mol. In addition, we have not even taken into account the energy needed to produce gaseous sodium and chlorine atoms from their most stable forms (solid Na, and gaseous Cl2). These energy expenditures are called atomization energies and in this case are 108 kJ/mol to vaporize sodium metal, and 122 kJ/mole to break the Cl−Cl bonds in Cl2(g). We can contrast this endothermic process of making ions in the gas phase with the highly exothermic—indeed, violent —reaction of sodium metal and chlorine gas, forming solid sodium chloride: Na(s) + 1 2 Cl (g) ⟶ NaCl(s) 2 Δ Hr xn = −411 kJ/mol C06-2-2 We know that solid NaCl is a stable and ubiquitous substance just from casual observation, so its formation must be energetically favorable. Clearly, the cause of this stability is the powerful, energy-lowering electrostatic interaction between the oppositely charged ions that is in effect as soon as they get within close distance in the crystalline solid. The electrostatic energy can be evaluated with the help of the Coulomb equation (see E01-4-2): Eel = kQ1 Q2 E06-2-1 d Here, k = 8.99 × 109 J·m/C2, and Q1 = −Q2 = −1.602 × 10−19C (one atomic unit of charge), while d is the sum of the ionic radii for Na+ (116 pm) and Cl− (167 pm); this is the closest the ions can come to each other. The electrostatic stabilization energy comes to a substantial −491 kJ per mole of ions—this is clearly enough to overcome the endothermic ion formation in the gas phase (147 kJ/mol, see above). This is true even if atomization energies of 108 kJ/mol and 122 kJ/mol are included, giving a total of 377 kJ/mol of energy expenditure to make ions. But this is still not sufficient to explain the highly exothermic formation of solid NaCl. Apparently, there is more to the electrostatic stabilization than what we have accounted for so far. Ionic solids form because of large stabilizing electrostatic interactions between ions Let's examine the structure of crystalline NaCl a bit more closely (F06-2-1), concentrating on the sodium cation in the middle. That sodium cation is interacting with six chloride ions (labeled A) in its direct vicinity, including the four that are visible in the picture, and one more in each layer directly in front and behind the one shown. We have accounted for only one interaction in our basic electrostatic calculation above (E06-2-1). But simply multiplying our number by six would not be correct either, since we would neglect mutual electrostatic repulsion energies among the six Cl− ions surrounding our selected Na+, as well as its own repulsions with 12 other Na+ ions (B) displaced "diagonally" in all three dimensions from our ion of interest. Although the electrostatic interactions drop off as the distance separating the charges increases, more refined calculations should include additional "spheres" of electrostatic influence (both attractive and repulsive) from the further-removed ions. In general, if the crystal structures are known, such detailed electrostatic calculations are possible, and indeed are often carried out to gain better understanding of ionic solids. These calculations are, however, outside of the scope of our presentation. We will use a different approach to quantitate the strength of ionic bonding (see 06-3), nevertheless, the electrostatic arguments presented here explain the stability of extended networks in ionic solids satisfactorily. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 82/250 9/2/2019 Chem 110 Figure F06-2-1. A model of a small fragment of crystalline NaCl. The grey Na+ cation in the center interacts with 6 Cl− ions with which it is in direct contact; four are visible (labeled A), and additional two are in the crystal layers directly behind and in front of the center grey cation. The center Na+ also has repulsive interactions with other Na+ ions (labeled B). Weaker electrostatic interactions with further removed ions are also present (both attractions and repulsions). You may take a tour of the surroundings of one of the sodium cations The thermodynamic data presented here for NaCl also illustrate the limitations imposed by ionic bonding. Ionic solids will be formed only between cations and anions. Usually this means metal cations (especially those on the left side of the periodic table with relatively small ionization potentials) and nonmetal anions (especially those on the right side of the periodic table with favorable electron affinities). For main group elements, ionic solids are limited to ions with a noble gas configuration. Generating other ions by removing core electrons (as in Na2+, for example) or adding electrons beyond the valence shell (as in, Cl2− for example), is energetically so costly that even the increased electrostatic stabilization does not result in an overall favorable process. In general, electrostatic stabilization in solids cannot compensate for the cost of the increasing ionization energies for each successive electron removed and the positive unfavorable electron affinities of sequentially added electrons beyond the +3 or −3 charge. This ±3 charge is a practical upper limit for ions in ionic solids. Similarly, transition metals (which may have more than three electrons beyond the noble gas core) will generally form ions that do not have a noble gas configuration, demonstrating the limits of the octet rule. As a reminder, when forming ions transition metals will first lose electrons from their valence ns2 subshell before losing any electrons from their (n−1)d subshell. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 83/250 9/2/2019 Chem 110 06-3 Lattice energy Lattice energies that measure the strength of ionic bonding are calculated using a thermodynamic cycle As we have just discovered, the principal reason behind the stability of ionic compounds is the electrostatic attraction between ions of opposite charge. The ions are drawn together, releasing energy while forming highly ordered 3dimensional crystalline lattices. The strength of such ionic bonding can be defined as the energy required to break up the solid into individual ions in the gas phase. This energy is called the lattice energy. For example, it takes 788 kJ for one mole of solid sodium chloride to completely separate into ions: + NaCl(s) ⟶ Na (s) + Cl − (g) C06-3-1 Δ Hlattice = +788 kJ/mol Notice that the reverse process (the forming of an ionic solid from gaseous ions) is highly exothermic, signifying the stability of the solid. In general, the higher the lattice energy, the more the ions are attracted to each other in the solid, and the stronger the ionic bonding. Lattice energies cannot be measured directly. An indirect approach is employed to obtain their values, based on a thermodynamic cycle called the Born-Haber cycle. The thermodynamic principle behind this method is the fact that enthalpy is a state function; the change in energy (ΔH) does not depend on the paths used in the preparation of the compound, only on its structure and state. In fact, we employed similar thermodynamic principles in the previous section (06-2) to learn about interactions between ions in NaCl. The calculated difference in energy between the ionic solid and the gaseous ions gives us the lattice energy that we were after. That energy difference is the measure of the net electrostatic attractions between ions in the solid; this is the best gauge of the ionic bond strength. The lattice energy of several ionic solids obtained from analogous thermodynamic cycles are collected in Table T06-3-1. T06-3-1. Lattice energy of selected ionic solids Compound Lattice energy [± 1] (kJ/mol) Compound Lattice energy [± 2] (kJ/mol) Compound Lattice energy [± 3] (kJ/mol) LiF 1047 BeF2 3526 AlF3 6252 LiCl 860 MgF2 2978 CrCl3 5529 LiBr 820 MgCl2 2522 VF3 5890 LiI 761 MgBr2 2451 ScF3 5540 NaF 928 MgI2 2340 CrCl3 5529 Sc2O3 13708 NaCl 786 CaF2 2651 NaBr 751 CaCl2 2271 NaI 703 CaI2 2087 V2O3 14520 KF 826 SrF2 2513 Cr2O3 14957 KCl 717 BaF2 2373 Al2O3 15920 KBr 689 BaCl2 2069 Ti2O3 14149 KI 650 RbF 795 BeO 4443 ScN 7506 RbCl 695 MgO 3845 VN 8233 RbBr 668 CaO 3454 NbN 8022 RbI 632 SrO 3276 CsF 759 BaO 3054 CsCl 667 NiO 4010 CsBr 647 VO 3863 CsI 601 ZnO 3971 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 84/250 9/2/2019 Chem 110 The major factor controlling the magnitudes of lattice energies are the charges on ions, with ion sizes being a secondary contributor The major trends in lattice energy are accounted for by factors that control the electrostatic interactions, including the magnitude of the charge on the ions, the ion sizes, and the specific crystal arrangements of the ions. Of these factors, the magnitude of the ionic charge is by far the most dominant, as the electrostatic attraction is directly proportional to the product of charges in Coulomb’s law. The doubling or tripling of that contribution upon going from a +1 ion to a +2 or +3 ion is clearly discernible in the data in Table T06-3-1. The ion sizes vary much less from ion to ion, and so do their sums (values of d in E06-2-1). In general, the differences in ion sizes contribute less to the observed magnitudes of lattice energy, but differing sizes explain the trends among salts with the same ionic charges very well. Ions with a given set of charges often have identical or similar lattice symmetries, and thus specific arrangements of atoms do not strongly influence the general trends, although they do affect the magnitudes of specific lattice energies. Figure F06-3-1. Examples of trends in lattice energies and melting points for simple ionic solids with common ions. The values of d (the sum of the ionic radii, or the distance between the two ions) are shown below the ions in pm (100 pm = 1 Å). The lattice energies (and melting points) dramatically increase as ion charges increase and decrease as one of the ions in the molecule increases in size (with the other one kept the same). The data in Table T06-3-1 show that increasing ion size correlates with decreasing lattice energy. Direct comparison of ionic solids where one of the ions is kept constant while the other ion increases in size illustrates this trend the best (F06-3-1). The lattice energy steadily decreases with increase of d, as predicted by the inversely proportional relationship between the electrostatic energy and the separation of charges (E06-2-1). The comparison of the lattice energies of two ionic solids where the sum of the ionic radii (d) is almost the same highlights both of the two most important trends. For example, SrO (d = 258 pm) has a lattice energy that is almost 4 times larger than LiCl (d = 257 pm); as expected given the +2/−2 charges in the former (compared to +1/−1 charges in the later). On the other hand, when the charges are the same, as in KCl (d = 319 pm) and NaI (d = 322 pm), the lattice energies differ very little, even if the solids involve different ions of different sizes. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 85/250 9/2/2019 Chem 110 Given the ionic bonding principles that we have just explored, we can understand the physical properties of ionic solids. As we have seen, such solids are organized to maximize the electrostatic attractions between ions. This organization is the basis of their crystalline, highly ordered periodic structure. Since there are no direct bonds between ions (only electrostatic attractions) such crystals can easily be mechanically broken into smaller pieces by splitting along crystallographic planes while preserving their crystalline order. We call such solids brittle. The large attractions between ions as gauged by the high lattice energies indicate that individual ions are extremely hard to separate into the gas phase from such solids, and even relatively minor dislocations of ions from their optimal positions within the lattice are energetically costly. Therefore, ionic solids built of atomic ions have high melting points, since melting destroys the highly ordered state (even if the close distance between the ions is retained). Indeed, as seen in Figure F06-3-1, higher melting points correlate with higher lattice energies. You may, for example, predict with confidence that MgO will have a significantly higher melting point than NaCl, or order the sodium halides according to their melting points even if you do not know anything about their specific values. The ability to predict trends in physical or chemical properties of materials based only on the understanding of their structures and some basic chemical principles demonstrates the power of the scientific method. We will continue to draw connections between the atomic structure and macroscopic properties of matter throughout our Lessons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 86/250 9/2/2019 Chem 110 06-4 Covalent bonding Covalent bonds are made by sharing of electron density between atoms The electrostatic forces at work in covalent bonding may be illustrated by analyzing H2, which is the simplest molecule and is built of two protons and two electrons. When the two protons in the nuclei of the hydrogen atoms are brought close together, there is electrostatic repulsion between them and the energy of the system increases. The shared electrons are attracted to both nuclei, but their effectiveness in providing electrostatic attraction to counter the nuclear repulsions depends on their position. An electron in positions close to the internuclear axis can attract both nuclei to itself and also diminish their mutual repulsion by screening their charges. This stabilizing influence diminishes if the electron moves away from the midpoint, and becomes destabilizing when it is in a position behind one of the nuclei; in such positions the electron attracts the nearer nucleus more strongly than the one further away, and pulls the nuclei apart. The region of space where electron-nuclei attractions provide stabilization may be "mapped out" by doing electrostatic calculations for multiple points surrounding the nuclei (F06-4-1). The resulting bonding region shown in the figure leads us to the conclusion that covalent bonding calls for increased electron density on and around the inter-nuclear axis. Figure F06-4-1. From left to right: (a) Electrostatic interactions in H2 or in any electron pair that is shared between two nuclei. The orange vectors illustrate repulsive forces between like charges, and the blue vectors show attractive forces between opposite charges. The particles are not drawn to scale. (b) The green area represents the bonding region (the parabolic shape is darwn by considering electrostatic interactions of electrons). Higher of electron density in the marked area contributes to bonding. Sharing two electrons doubles the attractions, but also introduces electron-electron repulsion that destabilizes the system somewhat (F06-4-1). The bond between the atoms maximizes electrostatic attractions by having the shared electrons occupy the inter-nuclear bonding region (F06-4-1a), but also minimizes repulsions by having these electrons avoid each other. Although the full elucidation of quantum effects is beyond the scope of our presentation, we should add that the kinetic energy of electrons is lower in the inter-nuclear region, decreasing the overall energy of the system. In a simplistic way you may visualize it as electrons being "trapped" in the bonding region and slowed down. The bottom line is that the bonded molecule is more stable than two separate hydrogen atoms. As you may remember, in quantum chemistry we deal with electron densities (which represent probabilities) rather than specific electron location, and we use wavefunctions and orbitals to describe this probability. We will return to these concepts to describe the details of how covalent bonds are formed in a later Lesson (Lesson 9-1). For now, we can conclude that the attractive force between the positively charged nuclei and the negatively charged electron-pair cloud between them holds atoms together. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 87/250 9/2/2019 Chem 110 Lewis structures illustrate the apportionment of bonding and nonbonding electron pairs to atoms in molecules One pair of shared electrons (bonding electrons) is all that is available in the hydrogen molecule, and that is all that is necessary to attain the noble gas configuration of [He]. More than one electron pair may need to be shared to reach the octet configuration of a noble gas for atoms in other molecules. The number of shared electron pairs (bonds) is specified by the valence of the atom. Let's consider some simple examples of molecules with bonds to hydrogen (F06-4-2): Figure F06-4-2. The Lewis structures of hydrogen fluoride, water, ammonia, and methane. For nonmetals, the number of bonds an atom forms with hydrogen to attain an octet follows the valence rule (8 − N), where N is the number of valence electrons on that atom. In our standard notation for a Lewis structure (F06-1-2), we show shared electrons as lines connecting the nuclei, and unshared electron pairs (also known as lone pairs or nonbonding pairs) as pairs of dots. In all of these structures the hydrogen atoms are surrounded by two bonding electrons ([He] configuration), and the other atoms are surrounded by a full octet. The fluorine atom in the hydrogen fluoride molecule forms one bond to a hydrogen and has 3 nonbonding pairs. The oxygen atom In a water molecule forms two bonds to hydrogen atoms and has two lone pairs. The nitrogen atom in ammonia has three bonds to hydrogen atoms and one unshared electron pair. The carbon atom in methane forms four bonds to hydrogen atoms and has no lone pairs. Each shared electron pair constitutes one covalent bond. If the two atoms are joined by just one bond, that bond is referred to as a single bond. The Lewis structures of F06-4-2 account for the apportionment of all valence electrons for all of the atoms participating in bonding. They clearly show the number of bonds and lone electron pairs, and most importantly they show the connectivity of the molecule, specifying which atoms are bonded to which atoms. However, these structures are deficient in their lack of information about the three-dimensional positioning of the atoms in relation to each other. As we will soon learn (Chapter 8), there are ways to use the Lewis structures to deduce information about the three-dimensional positioning, but until then we will draw them in a way that keeps the bonding and lone pairs as far from each other as possible in the plane of the drawing; we anticipate that electron pairs repel each other, and we need to maximize their separation. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 88/250 9/2/2019 Chem 110 06-5 Multiple bonds Multiple bonds result when more than one electron pair is shared between the same two atoms in molecules Atoms in some molecules may share multiple electron pairs in order to achieve an octet configuration. If two electron pairs are shared the bond is called a double bond, and if three electron pairs are shared we have a triple bond. Some transition metals may form quadruple bonds, sharing four electron pairs, but these are outside of the scope of our Lesson. The number of electron pairs shared is called the bond order. Examples of common simple molecules with single and multiple bonds are shown in Table T06-5-1. Table T06-5-1. Examples of single, double, and triple bonds and their bond lengths Bond order of 1 hydrogen peroxide Bond order of 2 Bond order of 3 dioxygen 146 pm hydrazine 121 pm diazene 145 pm ethane dinitrogen 125 pm ethene 154 pm ethanol ethyne 134 pm 142 pm 120 pm carbon monoxide methanal methylamine 110 pm 121 pm hydrogen cyanide methyleneimine 147 pm 113 pm 127 pm 116 pm Bond lengths depend on atomic bonding radii and bond order Multiple bonds may form between atoms of the same element or between different elements, but they are usually limited to nonmetals of the second row of the periodic table (we will address that limitation later in Lesson 9). Single bond lengths can be predicted reasonably well by adding the values of the atomic bonding radii. For example, we know that atomic radii shrink from left to right in a given row of the periodic table and would expect to see declining bond lengths in the C−C, C−N, C−O series. This trend is indeed confirmed by the data in Table T06-5-1. The multiple bonds are shorter than the single bonds between the same pair of atoms, and the bond lengths in general correlate with bond order; the higher the bond order the shorter the bond. The bond lengths (single or multiple) between a given pair of atoms usually vary little from compound to compound, and the average bond lengths (Table T06-5-2) describe the bonding distances with adequate precision for most applications. Deviations, when observed, are readily explainable based on the details of the electronic structure of the specific cases (we will discuss such cases later on, in Lesson 9). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 89/250 9/2/2019 Chem 110 Table T06-5-2. Average bond lengths (in pm): Single Bonds I Br Cl S P Si F O N C H H 161 142 127 132 138 145 92 94 98 110 74 C 210 191 176 181 187 194 141 143 147 154 N 203 184 169 174 180 187 134 136 140 O 199 180 165 170 176 183 130 146 F 197 178 163 168 174 181 128 Si 250 231 216 221 227 234 P 243 224 209 214 220 S 237 218 203 208 Cl 232 213 200 Br 247 228 I 266 Multiple Bonds Bond Length Bond Length N=N 124 C=C 134 N≡N 110 C≡C 116 C=N 127 C=O 123 C≡N 116 C≡O 113 N=O 122 O=O 121 Bonds are stronger if they are shorter or have higher bond order As we have just learned, the strength of bonding in ionic solids is measured by the lattice energy, which expresses the strength of the electrostatic interactions between collections of ions. In contrast, the strength of a covalent bond is specific to the pair of atoms sharing the electrons, and is generally only weakly influenced by other atoms or bonds in the molecule. The strength of a covalent bond is defined by the energy needed to break that exact bond while leaving other parts of the molecule intact. This energy is called the bond dissociation energy (BDE), and the stronger the bond, the higher its BDE. We will define the process involved in breaking the bonds later (Lesson 16). The bond strength of a given covalent bond does not vary much from molecule to molecule, and average values are quite useful for qualitative applications (Table T06-5-3). Deviations from the average values are found in some molecules, and the reasons for these deviations are linked directly to the details of their structure. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 90/250 9/2/2019 Chem 110 Table T06-5-3. BDEs, average single bond dissociation energies (in kJ/mol) I Br Cl S P Si F O N C H H 299 366 431 368 322 323 568 463 391 413 436 C 220 276 328 259 264 301 453 358 276 348 N 159 243 200 200 335 272 176 193 O 234 234 203 364 340 368 190 146 F 277 237 193 327 490 582 157 Si 234 310 464 226 P 184 264 319 218 253 242 S Cl 208 218 Br 175 193 I 151 226 209 266 Multiple Bonds Bond BDE Bond BDE N=N 418 C=C 620 N≡N 941 C≡C 815 C=N 615 C=O 745 C≡N 891 C≡O 1072 N=O 607 O=O 499 Even a casual scan of trends in bond lengths in Table T06-5-2 and bond strengths in Table T06-5-3 yields a general and very useful correlation: the shorter the bond and the higher its bond order, the stronger it is. This trend holds for bonds with different bond orders between the same pairs of atoms as well as for different bonds of the same order. We may also notice that for most multiple bonds, the second and third bonds are not as strong as the first bond (the exceptions include bonds between atoms with lone pairs such as oxygen and nitrogen). We will come to fully appreciate this difference when we learn how these bonds are constructed (in Lesson 9). Bond C≡C C=C C−C Length 113 pm 134 pm 154 pm BDE 839 kJ/mol 614 kJ/mol 348 kJ/mol Bond C−F C−Cl C−Br Length 134 pm 176 pm 193 pm BDE 486 kJ/mol 327 kJ/mol 285 kJ/mol Under standard conditions, compounds with covalent bonds are usually gases, liquids, or relatively soft solids with low melting points. The molecules in such substances are held together by weak electrostatic attractions called intermolecular forces. The molecules may move past each other or even separate with relative ease. In some covalent compounds, however, if the atoms bond into extensive covalent networks, like in diamond for example, the solids may be very hard and have extremely high melting points. In general. the bonds holding the atoms together within the molecules (called intramolecular forces) are strong while the intermolecular forces are much weaker. We will learn much more about these interactions and how they govern the properties of covalent compounds in future Lessons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 91/250 9/2/2019 Chem 110 06-6 Polyatomic ions Atoms in polyatomic ions are held together by covalent bonds So far we have studied compounds that were either ionic or covalent. We have learned how to identify ionic compounds from the elements they contain, typically a metal and a nonmetal, and typically from opposite sides of the periodic table. Metals have low ionization energies and form cations easily, and nonmetals have negative electron affinities and form anions readily. The ions are held together by electrostatic interactions between positive and negative charges. The ionic solids formed by the ions, called salts, can be recognized by their characteristic physical properties. They are brittle solids at room temperature, and have high melting points. Identification of covalent molecular compounds is also facilitated by identification of the type of elements in the molecular formula. Covalent substances are composed of nonmetals or metalloids, which are the elements in the upper right hand side of the periodic table. Atoms in molecular compounds are held together by strong covalent bonds, but the individual molecules are held together by weak electrostatic attraction (intermolecular forces). Such compounds are often gases or liquids at room temperature and pressure. In the solid state, molecular compounds are often soft and melt easily. In general, they have low melting and boiling points. However, there are also chemical species that are more complex. They have ionic character, but the ions involved have internal covalent bonding. We have seen examples of such compounds when we discussed formulas and composition. The simplest examples of such salts result from replacing one of the atomic ions with a polyatomic ion. For example, in sodium hydroxide, NaOH, the hydroxide ion has a covalent O−H bond, and in ammonium chloride (NH4Cl) all four hydrogens form covalent bonds to the nitrogen in the center of the ammonium cation. The structural complexity of the polyatomic ions can progress quickly. You may be familiar with some of the common polyatomic ions, such as carbonate (CO32−), nitrate (NO3−), peroxide (O22−), sulfate (SO42−) or phosphate (PO43−). You might be surprised by permanganate, MnO4−, or dichromate, Cr2O72−, which still have internal covalent bonding even though they are composed of metal/nonmetal combinations. You may have recognized some of the oxyanions listed above since they are derived from familiar oxoacids including nitric acid, sulfuric acid, and phosphoric acid. What all of these species have in common are multiple oxygen atoms covalently bonded to a central atom that could be a metal or nonmetal. We will discuss bonding and structure of such species in forthcoming Lessons. Table T06-6-1 Common polyatomic ions Even though the polyatomic anions have only internal covalent bonding, they combine with cations (atomic or polyatomic) to form ionic solids. Usually such salts form precisely ordered crystals, but typically with much lower melting points than purely ionic salts. The electrostatic attractions between such ions are not as strong as in the atomic ions; the covalently bonded fragments separate the charges by a larger distance and even insulate the charges from each other. Consider ammonium dichromate, (NH4)2Cr2O7, and its melting point of 180 °C. Both the low melting point and a casual look at the composition may lead one to identify this compound as covalent. There is no metallic cation to start the formula, and the metal is hidden in the part of the formula reserved for nonmetals. Yet, in the signature process for salts, ammonium dichromate dissolves in water and dissociates into the ammonium cations and the dichromate anions. The compound is ionic, but its ions are constructed using covalent bonds. For now, we list the most common polyatomic ions that we will encounter in our future Lessons (Table T06-6-1). We will discuss their structures, and some aspects of their bonding later in the course. https://genchem.science.psu.edu/sites/default/files/filefnlBYE Formula Name Formula Name NH 4+ H 3O+ ammonium hydronium SO 32− SO 42− sulfite sulfate HO − O 22− hydroxide peroxide NO 2− NO 3− nitrite nitrate CH 3COO− acetate H 2PO4− C 2O42− oxalate HPO 42− CN − SCN − cyanide PO 43− thiocyanate N 3− azide HCO 3− CO 32− ClO − ClO 2− ClO 3− ClO 4− dihydrogen phosphate hydrogen phosphate phosphate hydrogen carbonate carbonate hypochlorite chlorite MnO 4− permanganate chlorate CrO 42− chromate perchlorate Cr 2O72− dichromate 92/250 9/2/2019 Chem 110 07 Molecular Structure Once we have grasped the basic concepts of ionic and covalent bonding, we are ready to dive deeper and discover that the two types of bonding are just extremes on a continuum of electron sharing schemes. The extent of bias in electron density allocations to the bonding atoms and the resulting charge polarization are predetermined by the differences in electronegativity between the atoms. The unequal sharing of electrons results in bond dipoles, and ultimately in the polarity of an entire molecule, which in turn constitutes the critical component of intermolecular interactions, as we will see later in the course. Lewis structures are an important tool to account for atomic connectivity and for the distribution of all valence electrons among bonded atoms. They allow us to begin to envision the 3-dimensional shapes of molecules and are basis for the development of bonding theories. Mastering the skill to efficiently create Lewis structures and to interpret the electron apportionments they represent is just the first step in our exploration of the electronic structure of molecules. 07-1 Electronegativity Electronegativity is the tendency of an atom in a compound to attract electron density toward itself. It is usually expressed on Pauling's scale, which is unit-less. Highly electronegative atoms behave as electron acceptors, while atoms with low electronegativity act as electron donors. Electronegativity increases from the left to right and from the bottom to top in the periodic table, with some deviations among the transition metals. 07-2 Bond dipoles Bond dipoles for diatomic molecules provide a direct measure of the charge separation and the polarity of a species. The analysis of bond dipoles through the prism of electronegativity differences between bonded atoms establishes boundaries for ionic and covalent bonding, and allows us to evaluate the relative contributions of the two in the "gray" area of polar covalent bonds. Exploring bond dipoles is the first step to understanding molecular polarity, and eventually the intermolecular interactions that govern phase transitions. 07-3 Lewis structures Lewis structures are symbolic representations of atom connectivity in a molecule or ion and account for the apportionment of all valence electrons into bonding electrons and lone pairs. A systematic protocol for drawing Lewis structures facilitates their generation; our procedure is guided by the octet rule. Determining the formal charges on each atom helps us to evaluate the relative importance of alternative structures. 07-4 Resonance Some molecules cannot be accurately represented by just one Lewis structure. The culprits are delocalized electron pairs. In contrast to localized pairs, which are only shared between a pair of bonded atoms, three or more atoms share delocalized electron pairs. Such increased sharing lowers the energy of the system. In order to adequately account for delocalized pairs, superposition of multiple structures with alternative electron apportionments is needed; these are called resonance structures. The relative importance of each resonance structure and their individual contributions are evaluated based on partial charge criteria. 07-5 Octet rule exceptions There are three categories of compounds whose atoms do not always obey the octet rule. They include compounds with an odd number of electrons (radicals), compounds with insufficient valence electrons to construct an octet, and hypervalent compounds which have atoms with more than eight electrons. Hypervalent compounds can only occur when central atoms from the 3rd row (or below) of the periodic table bond to small electronegative atoms. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 93/250 9/2/2019 Chem 110 07-1 Electronegativity Electrons in covalent bonds are not always shared equally We recently learned about ionic bonds between ions, which are formed when electrons are transferred from metal atoms to nonmetal atoms. We used NaCl as a prime example of ionic interactions wherein one atom (from the left side of the periodic table) completely gives up its electron, while the other atom (from the right side of the periodic table) accepts it. As we learned, the electrostatic attraction between the ions lowers the energy of the system. We also explored covalent bonding, wherein the electrostatic attraction of one or more shared electron pairs to both bonded nuclei lowers the system’s energy. The molecules H2 and Cl2 illustrate bonding where the electron sharing is perfectly equal. However, with H−Cl (hydrogen chloride) we arrive at an interesting junction. Hydrogen chloride is a gas under standard conditions, implying the presence of a covalent bond, even though hydrogen is from the same group as sodium (group 1). So, why don't we get an ionic HCl with H+ and Cl− ions in this case? You may recognize that hydrogen and chlorine are both nonmetals, whereas ionic solid formation requires the combination of a metal and a nonmetal. If we take our analysis to the next level, we realize that hydrogen is a nonmetal (despite being in group 1) because of its high ionization energy; IE1 for H is 1312 kJ/mol, while that of Na is only 496 kJ/mol. Thus, although chlorine is "willing" to accept the electron, hydrogen is "reluctant" to give it away. Does this mean that the bonding electron pair is shared equally in H−Cl? As we will learn shortly (Lesson 07-2), one can answer this question experimentally by measuring dipole moments. For now, let's just jump to the results, which tell us that hydrogen has a slight positive charge (+0.18 au) in an H−Cl molecule, while chlorine has a negative charge of equal magnitude (−0.18 au). This polarization indicates that chlorine is pulling a larger share of the bonding electron pair toward itself. This tendency of an atom to attract electron density in the bond toward itself is called electronegativity (χ). Electronegativity is a measure of the tendency of an atom in a molecule to attract shared electron density toward itself American chemist Linus Pauling observed that the H−Cl bond (BDEH−Cl = 429 kJ/mol) was notably stronger than the mean of the BDEs of H−H and Cl−Cl bonds (BDEH−H = 433 kJ/mole and BDECl−Cl = 240 kJ/mol). One would expect the mean value to be closer to the observed value if electron sharing was equal in HCl. Pauling deduced that the difference is due to the partially ionic nature of the bond (18%, based on the partial charges reported above), which adds stability. He proposed to use the extra bond stability as a measure of the differences in electronegativity (Δχ) between bonded atoms (H and Cl in this case). Using the available BDE values for various bonds (and an arbitrarily set value of electronegativity for hydrogen) the Pauling electronegativity scale was developed. The accepted values shown in Figure F07-1-1 are based on the most current BDEs (and use geometric means of BDEs as a reference). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 94/250 9/2/2019 Chem 110 Figure F07-1-1. Pauling electronegativity scale. The least electronegative atoms are metals in the lower left corner of the periodic table (light yellow) and the most electronegative atoms are in the upper right corner (dark orange). Electronegativity increases going from the bottom-left to the upper-right of the periodic table, with some deviations observed among transition metals. Click on the image to see a 3D view. Pauling electronegativity is a unit-less number on an arbitrary scale, ranging from 0.79 for cesium to 3.98 for fluorine. With the exception of some of the transition metals, electronegativity increases across the periodic table from left to right and in a less pronounced fashion within the groups from the bottom to the top. The increase of electronegativity in each row follows the trend in Zeff. Indeed, the increasing effective nuclear charge is responsible for increases in IE1 and |EA|, and both of them contribute to electronegativity (see Mulliken electronegativity). Electronegativity is the best expression of the tendency of an atom to donate or accept electron density within chemical bonds. Highly electronegative atoms readily accept electron density and form negative ions. Atoms with low electronegativity, sometimes called electropositive, readily donate electron density and form positive ions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 95/250 9/2/2019 Chem 110 07-2 Bond dipoles Dipole moments are the experimental measure of the polarization of electron density in molecules When two electric point charges of opposite sign and equal magnitude Q are separated by a distance r, an electric dipole forms. It is quantified by its dipole moment, μ: E07-2-1 μ = Qr The SI unit of the dipole moment is coulomb-meter (C·m), but it is typically expressed in debyes (D), a unit that equals 3.34 × 10−30 C·m. For molecules, we usually use electron charge (1 au = 1.60 × 10−19 C) and separation distances in picometers (pm) or angstroms (1 Å = 100 pm), matching units of bond lengths. For reference, the dipole moment of (+1) and (−1) charges separated by 100 pm is: μ = Qr = (1.60 × 10 −19 10 −12 m C) (100 pm) ( 1 D )( 1 pm 3.34 × 10 −30 ) = 4.79 D E07-2-2 C⋅ m The dipole moment provides us with a measure of charge separation, or the system polarity. By convention it is a vector pointing from the center of positive charge to the center of negative charge, with the length representing the magnitude of μ. It turns out that the dipole moments of molecules can be experimentally measured by various methods. Such measurements, when done on diatomic molecules in the gas phase (where the molecules are electrostatically unperturbed by any neighbors), provide us with valuable information on the sharing of bonding electrons and the polarity of molecules. We collect some pertinent data in Table T07-2-1. Table T07-2-1. Experimental and calculated (fully ionic) dipoles of diatomic molecules μ μ calculated Molecules (observed) (100% ionic) Bond length %ionic D D pm % H−I 0.45 7.76 162 6 0.46 H−Br 0.83 6.85 143 12 0.76 H−Cl 1.11 6.13 128 18 0.96 H−F 1.83 4.45 93 41 1.78 Cs−F 7.88 11.25 235 70 3.19 K−Br 10.63 13.51 282 79 2.14 Na−Cl 9.00 11.30 236 80 2.23 K−Cl 10.27 12.79 267 80 2.34 Na−F 8.16 9.24 193 88 3.05 Δχ (electronegativity difference) Let us first demonstrate how the dipole moments are calculated assuming a fully ionic bond. In the H−Cl molecule the bond length is 128 pm. We can take advantage of the calculation in E07-2-2 where the separation distance was 100 pm, and just use the ratio of distances here. If the charges were fully separated (+1 on H and −1 on Cl), the dipole moment would be (128/100) × 4.79 D = 6.13 D. Yet the measured dipole moment is only 1.11 D, or 0.18 (1.11/6.13) of that expected for the ionic molecule. We conclude that H−Cl bond is 82% covalent and 18% ionic. We use the same strategy to calculate the ionic dipole moments for other molecules in T07-2-1, using their bond lengths. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 96/250 9/2/2019 Chem 110 If we return to our examples from the previous section (Lesson 07-1), we now understand the partial charge separation that we used for the H−Cl molecule (δ = 0.18 of the full electron charge). Molecules of H2 and Cl2 have no dipole moment (μ = 0), but molecules of H−Cl and Na−Cl do (Figure F07-2-1). Note that we are looking here at individual Na−Cl molecules in the gas phase and not the ionic solid. Gaseous molecules of NaCl and other ionic substances shown in the bottom half of Table T07-2-1 can be prepared by heating the ionic solid to a high temperature under vacuum. We use them here for illustration purposes; they are not stable under standard conditions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 97/250 9/2/2019 Chem 110 Charge polarization is visualized by listing partial charges on atoms, drawing dipole vectors, or displaying maps of electrostatic potential energy μ=0D μ=0D μ = 1.11 D μ = 9.00 D Figure F07-2-1. Molecules of H2, Cl2, HCl and NaCl. The dipole moment, partial charge, and full charge are illustrated on the Lewis structures. The partial charge of an HCl molecules is δ = 0.18. The dipole moment vector for NaCl is not shown, but would be 8 times longer than the one shown for HCl, if presented on the same scale. On the electrostatic potential maps (MEP, drawn here to reflect relative molecular sizes and on a common ±200 kJ potential energy scale), reds represent areas of high electron density, blues represent low electron density, and greens are "neutral'. Molecules of H2 and Cl2 have nonpolar covalent bonds; there is no charge separation (μ = 0). An H−Cl molecule has a polar covalent bond. It has a dipole moment, μ = 1.11 D, with partial charge separation; chlorine has δ−= −0.18 au, and hydrogen has δ+ = 0.18 au, as we calculated above. The dipole moment vector (F07-2-1) shows the direction of the electron density shift. An Na−Cl molecule is 80% ionic. The partial covalent bond is shown in F07-2-1 as a broken line, and charges are shown as full charges (which is an approximation). It has a large dipole moment, μ = 9.00 D; the dipole moment vector would have to be about 8 times longer than one for H−Cl if drawn to scale. The colored surfaces shown in Figure F07-2-1 are maps of electrostatic potential energy (MEP); essentially, they show the electron density in a molecule as mapped on its surface. First, a boundary surface for the molecule is drawn that contains 95% of electron density (as we did when we studied atomic orbitals). For all practical purposes, this surface is the same as the van der Waals surface that we discussed previously, and corresponds to the sum of the non-bonding radii. It is also what we call the space-filling model of a molecule, as it shows the volume of its electron cloud. Next, we use a positive +1 point charge as a probe and move it on the surface, measuring its electrostatic energy. We finish by painting the surface with colors representing that energy. Areas in red represent high electron density, while those in blue represent low electron density (greens are in the middle-range). Such MEPs can only be generated by computers, but are visually very informative. It’s like having a pair of "superman glasses" and being able to see and distinguish molecular regions of varying electron densities. The electronegativity differences between bonded atoms determine if the bonds are covalent, polar covalent, or ionic The general trends observable in Table T07-2-1 clearly indicate that there really is a continuum of the degree of polarization of electron density involved in bonding. At one end is equal sharing (where there is no difference in electronegativity between bonded atoms), in the center are polar covalent bonds (with a moderate contribution from ionic bonding), and at the other end are highly polarized, essentially ionic bonds between atoms (where electronegativity differences are large). In other words, purely ionic bonds and nonpolar covalent bonds merely represent the extremes of bonding possibilities. The electronegativity scale (F07-1-1) provides us with a way to rapidly predict the kind of bonding present and assess the polarity of the bond by looking at the difference in electronegativity. The difference in electronegativity, Δχ, is detailed in the last column of table T07-2-1. Although it is impossible to draw clear dividing lines, it is common to assume that for atoms with Δχ ≥ 1.8 there is full or almost full electron transfer, resulting in the formation of ionic solids (F07-2-2) On the other hand, bonds between atoms with Δχ ≤ 0.4 are deemed nonpolar covalent bonds. In the midway range bonds are polar covalent, with their polarity increasing as Δχ increases (Figure F07-2-2). The suggested cutoff values are only given here to build up your chemical intuition. There are many complicating factors that make these arbitrary dividing lines very fuzzy, indeed. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 98/250 9/2/2019 Chem 110 Figure F07-2-2. The difference in electronegativity, Δχ, can be used to predict the bond polarity. Bonds with Δχ ≤ 0.4 are deemed to be nonpolar covalent, bonds with Δχ between 0.4 and 1.8 are polar covalent, and bonds with Δχ > 1.8 are ionic. All MEPs are at the common ±200 kJ scale. The concept of polarity is not limited to just diatomic molecules. Any molecule in which the centers of positive and negative charges do not coincide is a polar molecule. We will learn later (Lesson 08-4) how to determine polarity of molecules by analyzing bond dipoles, but even now it is important to appreciate that polarity determines interactions between molecules, called intermolecular forces (Lesson 11-2) which are responsible for the properties of gases, liquids, and solids, as well as the transitions between these phases. Polar molecules interact with each other and other polar molecules and ions through electrostatic forces. Dipole "ends" of a particular sign (+ or −) are attracted to ions or dipole ends with the opposite sign, and are repelled by ions and dipole ends of the same sign. Although dipole-ion and dipoledipole interactions are much weaker than the ion-ion interactions of ionic bonding, they are comparable to the kinetic energy of thermal motions around room temperature (25 °C). The relative magnitude of these energy terms influences the phase behavior of substances around us. To illustrate, the polarity of water molecules is the reason that water remains a liquid at temperatures at which most other small molecules exist as gases. Since liquid water is necessary to support life as we know it, these intermolecular interactions are clearly worth extensive examination (Chapter 11). To build our understanding of the interactions responsible for holding atoms together, we initially treated ionic and covalent bonding as two separate concepts. We recognize that when covalent bonding is dominant, the compounds exist as molecules in the form of gases, liquids, or soft solids (characterized by relatively low melting and boiling points), with the exception of extended covalent networks such as those in diamond or silicon. We learned that both the polarity of covalent bonds and the overall polarity of molecules are very important in determining the properties of covalent substances. On the other hand, when ionic bonding is dominant the compounds are brittle, high-melting solids, with extended lattice structures that dissociate into aqueous ions if soluble in water. This new understanding of electronegativity gives us the ability to quickly recognize the predominant bonding interactions in a substance and understand its properties, even if we were initially unsettled by the continuity of the bonding models from covalent nonpolar, through covalent polar, to ionic. We can now add more sophistication to our approach and move beyond simple metal-nonmetal (or ionic) and nonmetal-nonmetal (or covalent) paradigms. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 99/250 9/2/2019 Chem 110 07-3 Lewis structures Lewis structures show atom connectivity and apportionment of all bonding and nonbonding electrons to individual atoms in molecules As we mentioned before, Lewis structures are in essence an accounting scheme for apportioning valence electrons among atoms in molecules. They show connectivity between atoms, and they show the number of bonding and lone electron pairs on each atom. The octet rule and the valence rules derived from it govern the possible arrangements of electron pairs in most compounds. Lewis structures are also the starting point to understand the 3-dimensional shapes of molecules, and to eventually understand theories of bonding. They constitute the symbolic language of chemistry. Fluency in both reading and writing this language is a critical skill every student of chemistry must master. With practice, reading Lewis structures should become equivalent to reading a novel; one does not see individual letters or words, but assimilates the meaning of whole sentences. Similarly, a practiced chemist does not see the lines or electron dots, but grasps the molecular shape, with its intricate bonding arrangements and regions of high and low electron density, as well as their effects on molecular properties or reactivity. Let us begin with the basic steps: 1. Sum the valence electrons for all atoms. Based on the molecular formula, add together the number of valence electrons, using the periodic table as a guide. If the species is an ion, adjust the result by adding one electron for each negative charge, and subtract one for each positive charge. 2. Establish the connectivity of the atoms. Draw a single line to represent a bond between all directly bonded atoms. Connectivity information may be provided by the name of the compound; a specific name always corresponds to a defined atom connectivity. Connectivity may also be suggested by the way the formula is written (atoms are often listed in the order they are connected). Frequently, the central atom is listed first, followed by the other atoms attached to it. If no information is provided, decide which atom is the central atom; this usually should be the least electronegative element. Distribute the atoms and bonds evenly in the plane of the drawing in order to provide clarity to the drawing. The number of single bonds drawn to an atom must not exceed one for H, four for any atom of the second row, and six for any other atom. 3. Distribute the remaining electrons. Take the total number of valence electrons and subtract the number of electrons used to form single bonds (2 electrons per bond). Place the remaining electrons pairwise as lone pairs on nonhydrogen atoms, starting with the most electronegative atoms, completing an octet on each. If there are too few electrons to complete octets, go on to step 4. If there are too many electrons after octets have been completed, go on to step 5. 4. Make multiple bonds if needed. If the central atom ends up with less than octet, use lone pairs on atoms bonded to it to form double or triple bonds. 5. Place any leftover electrons on the central atom. If there are any valence electrons not assigned to specific atoms affix them to the central atom even if it results in exceeding the octet on that atom We can illustrate this process by drawing the Lewis structure of formaldehyde (methanal), CH2O. 1. Valence electrons NV (C) = 4 NV (O) = 6 NV (H) = 2 × 1 Total = 12 2. Connectivity https://genchem.science.psu.edu/sites/default/files/filefnlBYE The valence electrons of all atoms are added together. There are 12 valence electrons to be apportioned to carbon and oxygen. Hydrogens form one bond each and do not accept any additional electrons. The name unambiguously defines the species. If it was not given, the atom order suggests that carbon is the central atom, which is consistent with it being the least electronegative atom (hydrogens cannot serve as central atoms, they may only form one bond). 100/250 9/2/2019 Chem 110 3. Distribute electrons Six electrons were used to make three single bonds. The remaining 6 are allocated, pairwise, to the oxygen atom. Carbon does not have an octet. 4. Multiple bonds Since all valence electrons have been apportioned, one of the oxygen's lone pairs has to be reassigned to be shared with carbon, forming a double bond. Both carbon and oxygen have octet, and both hydrogens have two valence electrons. The Lewis structure satisfactorily accounts for bonding in formaldehyde. 5. Extra electrons This step is not needed since we were able to draw a Lewis structure with complete octets using all of the valence electrons. The Lewis structures that best describe electron distribution in molecules have the smallest formal charges possible Often, some additional insight can be gained about the structure by assigning formal charges. Formal charges are essential when identifying the charge-bearing atoms in molecules or in polyatomic ions (see below). Also, if multiple Lewis structures can be drawn with the same atom connectivity but different electron apportionment to individual atoms, the structure that best fits the actual molecule can be selected by choosing the structure with the smallest formal charges. Formal charges (FC) are assigned following a simple "electron-bookkeeping" procedure. The number of electrons on a given atom in the Lewis structure, NLS, is the sum of all unshared electrons on that atom plus half of the electrons shared with bonding partners. The formal charge on each atom is then calculated by subtracting NLS from the number of valence electrons that atom has based on its electronic configuration (NV). E07-3-1 F C = NV − NLS Let's practice the whole procedure on thiocyanate ion, NCS−. 1. Valence electrons NV (N) = 5 NV (C) = 4 NV (S) = 6 −1 charge = 1 Total = 16 The valence electrons of all atoms are added together. The negative charge on the anion indicates the presence of one extra electron, which is added to the total. 2. Connectivity The name unambiguously defines the species. If it was not given, the atom order suggests that carbon is the central atom, which is consistent with it being the least electronegative atom. If no information were given, other options to consider would be C−N−S, C−S−N, or a cyclic structure. 3. Distribute electrons Four electrons were used to make two single bonds, represented by lines. The remaining 12 electrons are distributed pairwise, first by giving three pairs to nitrogen, then by giving three pairs to sulfur. Electrons should be distributed to the most electronegative atoms first. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 101/250 9/2/2019 Chem 110 4. Multiple bonds Since all electrons have been apportioned, and the central atom does not yet have an octet, multiple bonds need to be formed. There are three options to form these bonds: using both lone pairs on nitrogen, using both lone pairs on sulfur, or using one lone pair from each. In each structure all atoms have a complete octet. We indicate that the species is an ion by enclosing the structure in brackets and specifying its charge as a superscript outside of the bracket. 5. Formal charges Since we have more than one possible structure, we must calculate the formal charge on each atom to decide which is the "best". For each structure NLS is subtracted from NV, to yield the formal charge on each atom. The individual formal charges must always add up to the total charge on the species (−1 in this case), and are written above the corresponding atom. The formal charges are often shown as part of the Lewis structure; zero formal charges may be omitted, as can "1"s following the "+" or "−" signs. If formal charges are assigned to atoms, it is not necessary to draw the bracket with the overall charge. All three Lewis structures drawn in our exercise describe the thiocyanate anion. In all structures N, C, and S have octets; they differ only in the way electrons are apportioned to the atoms. We say that the structures contribute to a description of the true electron distribution in this ion. Using formal charges, we can decide which of the structures contributes the most, i.e., which is the dominant ("best") structure. The following guidelines are used in selecting the dominant structure: the dominant structure has the smallest charge separation, preferably with zero formal charges or the smallest possible formal charges the positioning of the formal charges in the dominant structure is consistent with the relative electronegativities of atoms; the dominant structure should have negative formal charges on the most electronegative atoms, and positive charges on the least electronegative atoms Applying these guidelines, we can easily determine that the middle structure in the example above is going to contribute less than the other two, as it has the largest charge separation (−2 and +1). The remaining structures have the smallest charges (−1) possible for the anion. We can select the dominant structure as being the one with −1 formal charge on nitrogen (above, on the right), as nitrogen is more electronegative than sulfur. We have arrived at a peculiar junction: we have gone from only being able to draw Lewis structures for the simplest molecules, to being forced to select the dominant structure from an abundance of possibilities. Why do we have multiple Lewis structures? Are there different thiocyanate ions? We will address these questions in the next section. It is important to realize that formal charges are only an accounting tool: they do not represent true charges (see 072), but they give us some guidance on how charges are distributed among atoms in molecules or polyatomic ions. We have just explored (see above) how to use formal charges to determine the relative contributions of various Lewis structures to the actual structure, but even if only one Lewis structure can be drawn, we often show formal charges on specific atoms. For example, we can use square brackets to show the overall charge on the hydroxide (HO−) or hydronium ions (H3O+), or we can specifically assign the formal charges to the oxygen atoms in the two ions. In the overall neutral form of the simple amino acid glycine (below right), there appears to be no need for formal charges, yet when calculated, they give us some insight into the structure of the molecule, showing its zwitterionic nature. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 102/250 9/2/2019 Chem 110 We may also note that atoms with full octets, but with non-zero formal charges, do not follow our simple valence rules; they form fewer bonds than their valence number if negatively charged, or more bonds if positively charged. These changes reflect converting bonding pairs into lone pairs, or vice versa. We will later return to these issues to refine our arguments and improve our understanding of Lewis structures, but it is important that you practice drawing and reading Lewis structures until it becomes second nature. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 103/250 9/2/2019 Chem 110 07-4 Resonance Molecules with delocalized electrons require more than one Lewis structure to describe them adequately We previously mentioned that ozone, O3, is a less stable allotrope of oxygen than O2. If we draw its Lewis structure by following the procedure outlined in the previous section, we arrive at structure I in step 3, as shown in Figure F07-4-1. This structure has serious shortcomings: it does not have an octet on the central oxygen, and it has large formal charge separation. In step 4 of our procedure we add double bonds to rectify these shortcomings. We can form a double bond with the blue oxygen on the left (II), or with the green oxygen on the right (III). Both II and III are satisfactory Lewis structures. They are equivalent, i.e., they present the same bonding pattern, but they are not the same as the terminal oxygens are distinct atoms (in structure II, blue oxygen is doubly-bonded, but it is singly-bonded in structure III). Figure F07-4-1. Resonance structures for ozone. Structure I does not have an octet on the central oxygen and does not contribute significantly to the description of the molecule. II and III are equivalent and contribute equally to the molecule. That is, the real structure of ozone is a superposition (blending) of structures II and III. Formal charges are shown in orange. However, there is a big problem with either of these structures: in an ozone molecule both O−O bonds have been measured to be identical in length, specifically 128 pm (1.28 Å). These bonds are shorter than a typical single O−O bond (146 pm), but longer than a typical double bond (121 pm). The experimental data tells us that our structures are wrong! Interestingly, even if both are incorrect, the average, or superposition, of II and III gives a correct description of ozone. Just as two defective pictures of the same object, each with missing pixels, generate a sharp image when combined, superposition of two (or more) Lewis structures gives us a more realistic picture of the molecule. Such a superposition is called resonance, and I, II and III are resonance structures or resonance forms of each other, as marked by the two-headed arrows. Structure I does not contribute significantly because it has high formal charges and its central oxygen does not have an octet, but II and III contribute equally. The term resonance might be misleading, implying oscillations between structures. In reality, there is no oscillation of any kind. The individual resonance structures do not exist as molecules, and the molecule that exists cannot be adequately described by any one Lewis structure. To fix the notation problem (the "broken" picture) we have to use multiple Lewis structures (multiple defective pictures). To trace the origins of this difficulty in notation, let's look at structure I and deconstruct how II and III are made from it. We observe that of the lone pairs on terminal oxygen atoms, two pairs on each atom stay put, while the third is shared (forming the second bond to the central oxygen). Thus we have a pair of electrons on each terminal oxygen atom that either forms the second bond or plays the role of the lone pair depending on the resonance structure. In the real molecule, all three oxygen atoms share these electron pairs. So far we have dealt only with localized electron pairs, which are shared between two directly bonded atoms. Resonance describes pairs of delocalized electrons that are shared by more than two atoms. In Lewis structures we do not have a way to designate electrons shared by three (or more) atoms, so we are left with resonance notation. In an effort to show such sharing, one may draw broken-line multiple bonds (IV), which are meant to show that the O−O bond orders are 1.5 for both bonds (midway between a bond order of 1 and 2). Such structures are not easily readable, and are not used frequently. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 104/250 9/2/2019 Chem 110 Figure F07-4-2. Resonance structures for ozone.Structures II and III are combined to give IV, in which the electron sharing between three atoms is shown with a broken line. Structures such as IV are difficult to read (as they have fractional bonds, see below) and are not used frequently. Since more sharing strengthens the bonding, the ability to draw more resonance structures indicates that the molecule has higher stability. The term "resonance-stabilized,” is commonly used to highlight the presence of delocalized bonds, despite the fact that resonance is merely a notation issue and not a physical phenomenon. For molecules represented by equivalent resonance structures the bond orders and formal charges are averages of the values found in these structures For an additional example of resonance, let’s consider the nitrate ion NO3−, shown below with one oxygen in green and one in orange (F07-4-3). In this case we can draw three resonance structures with all atoms satisfying the octet rule. The structures are equivalent, as a rotation around N by 120° converts one into another, reproducing bonding arrangements, but they are not actually the same; after the rotation the atom colors do not match. The green oxygen atom cannot be turned into an orange oxygen atom; they are atoms with distinct identities. This distinction is important, because the result is three equivalent structures that contribute to the description of the real anion. If they were the same, we would not have resonance! Figure F07-4-3. Three equivalent resonance structures for a nitrate ion. The average of the three structures (right) yields N−O bond order of 1⅓ and formal charges of −2/3 on each oxygen. Let's concentrate on the green oxygen. It forms a single bond (bond order of 1) to nitrogen in each of the first two structures and a double bond (bond order of 2) in the third structure. Since the real ion is the superposition of equal parts of all resonance structures, we can expect that O−N bond order to be an average of 1⅓ (which is equal to (1+1+2)/3). We also expect the bond length to be shorter than a single bond, but longer than a double bond. The same is true for the other two N−O bonds to the orange and black oxygen atoms. This expectation is borne out: the N−O bonds are all equal in length at 126 pm, which is in-between the lengths of a single bond (average N−O is 136 pm) and a double bond (average N=O is 122 pm). Similarly, the formal charge on the green oxygen is −1 in the first two structures, and 0 on the third, for an average of −2/3. All of the oxygens repeat the pattern. The outcome of this analysis is that the real nitrate ion is perfectly symmetrical, with three identical bonds and the formal charge distributed equally among the three oxygens. None of the individual resonance structures are able to show it, but the superposition of all three does the job, as shown by a unique structure with fractional bond orders (1⅓) and fractional formal charges (−2/3); this is shown on the right in F07-4-3. For molecules represented by non-equivalent resonance structures the dominant contributor is the structure with the lowest formal charges In many instances, the resonance structures are not equivalent, as we saw in the case of the thiocyanate ion. We can select the dominant contributor (left) and the second best contributor (middle) in F07-4-4 by using the formal charge criteria presented previously (F07-4-4) Such estimates of the relative contributions of various structures are qualitative. We are not able to assign specific weights to individual structures, or to calculated bond orders or partial charges. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 105/250 9/2/2019 Chem 110 Figure F07-4-4. Resonance structures of a thiocyanate anion.The structure on the left contributes the most to the description of the ion because it has the smallest formal charge (−1) on the most electronegative atom. The structure on the right contributes the least because its formal charges deviates the most from 0. The relative contributions of each structure cannot be quantified. Cyclic delocalization of bonding electrons may lead to increased stability Resonance is very important in describing many organic molecules with delocalized bonding. We will demonstrate just one case here, and present a few more later on in the course. The well-known molecule benzene is a cyclic hydrocarbon with apparent alternating single and double bonds. It is often drawn as a skeletal structure where each vertex (corner) represents a carbon atom and the hydrogen atoms are not shown explicitly; each carbon is assumed to be bonded to a sufficient number of hydrogen atoms to make a total of four bonds. The two equivalent resonance structures shown in F07-4-5 signal that all C−C bonds should be equal in length and strength. They are indeed equal, as the bond length of 140 pm is intermediate between a C−C single bond of 154 pm and a C=C double bond of 134 pm. This is consistent with a bond order of 1.5. This cyclic resonance is often shown in a shorthand notation with a circle in the middle of a hexagon. This replaces two resonance structures with one, and also stresses that the cyclic delocalization of bonding electrons is providing special stability, even beyond that of normal non-cyclic resonance. Indeed, benzene rings are found in many compounds in nature and in commercial products because of this dramatically increased stability. Figure F07-4-5. Resonance in benzene. For organic molecules, skeletal Lewis structures are used, in which each vertex represents a carbon atom. The hydrogens are assumed to be bonded to the carbons according to octet rule and are not drawn. All C−C bonds in benzene are equal (with a bond order of 1.5), and all carbon atoms share 6 of the bonding electrons equally. The resulting delocalized electrons are represented by the circle, as shown in the structure on the right. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 106/250 9/2/2019 Chem 110 07-5 Octet rule exceptions So far we have relied on the octet rule so much in our discussion that it feels unseemly to consider cases where its simplicity and usefulness are violated. Yet there are many instances where we need to extend our horizons beyond counting to eight. Broadly speaking, there are three categories of exceptions: 1. molecules or polyatomic ions with an odd number of electrons 2. molecules or polyatomic ions with atoms that have fewer than an octet of valence electrons 3. molecules or polyatomic ions in which atoms have more than an octet of valence electrons Radicals, molecules with unpaired electrons are generally very reactive The first group is the least numerous. The members are often called free radicals, or just radicals. By their nature they cannot have all their electrons paired, and cannot reach an octet. The presence of an unpaired electron makes them very reactive. As we will see later, the pairing of electrons is part of the driving force leading to bond formation. Radicals often exist only as short-lived intermediates in chemical reactions, or in the gas phase under very low pressure, as long as they are separated from other radicals or molecules with which they would otherwise react. Stable species with an odd number of electrons are quite rare. Molecules with atoms that have an insufficient number of valence electrons tend to combine with other molecules to increase the number of shared electrons The second group of exceptions occurs if there are fewer than eight electrons around an atom in the molecule. Such exceptions are also rare. For some molecules there are simply not enough valence electrons to formulate an octet. For example, beryllium hydride (BeH2) has only 4 valence electrons, and borane (BH3) has only 6. These molecules may exist in the gas phase under low pressure, where they cannot combine with other molecules to supplement their contingent of valence electrons. Such electron deficient molecules or ions are also encountered as fleeting reaction intermediates on their way to rapidly quench their thirst for electrons by sharing electrons with other molecules. One interesting example is boron trifluoride, BF3, a chemical cousin of BH3. Boron can borrow electrons from fluorine in the Lewis structure of BF3, forming a double bond (F07-5-1). Following step 5 of our Lewis structure procedure, we end up with three resonance structures. How do we decide which resonance structure is the most important and contributes the most? On the one hand, we have a resonance structure with only three single bonds and no octet on boron, but with zero formal charges. On the other hand, we have three equivalent resonance structures that contain a double bond; each has an octet on boron, a formal positive charge on fluorine, the most electronegative atom, and a formal negative charge on boron, an atom with low electronegativity. Here, experimental results come to the rescue, and we find that the B−F bond length in BF3 is 131 pm, which is shorter than a standard B–F single bond (137 pm). This suggests that resonance structures with double bonds must contribute significantly. However, BF3 reacts with compounds that have lone pairs (such as ammonia) to form stable complexes, indicating that boron's electron deficiency is not sufficiently quenched by sharing electrons with fluorine, and implying that the non-octet structure is also important. We are not able to declare a winner in the best structure competition, but at least we know that the octet formation is going to be dominant in all other cases. Even the most electronegative atom in the periodic table can give up some electron density to help a non-octet atom. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 107/250 9/2/2019 Chem 110 Figure F07-5-1. Resonance structures in BF3. In the first structure (left), boron has no octet, but the formal charges on all atoms are zero. In the three equivalent structure (right), boron has a full octet, but the formal charges on fluorine and boron are against the electronegativity trends. BF3 reacts with ammonia, forming a stable complex with full octets on all non-hydrogen atoms. Atoms of the 3rd period and below can expand their valence to more than eight electrons by bonding to small electronegative atoms The third group of exceptions to the octet rule is by far the largest. There are numerous molecules and polyatomic ions that have atoms with more than eight electrons around them. Such species are called hypervalent, as they exceed the valence rules that we explored before. The central atoms of hypervalent molecules or ions must satisfy several conditions. They have to be from the 3rd period of the periodic table or below, and be large. In most cases, they have to form bonds with small, electronegative atoms (such as F, Cl, or O). Second row atoms do not form hypervalent compounds or ions. Some examples of hypervalent species are shown in Figure F07-5-2. Figure F07-5-2. Examples of hypervalent molecules and ions: phosphorus pentachloride, PCl5, sulfur hexafluoride SF6, hexafluoroantimonate anion, SbF6−, thionyl tetrafluoride, SOF4, and xenon tetrafluoride, XeF4. In each case, the central atom exceeds octet. The main reasons for the restrictions listed above are the relative sizes of the atoms involved. Second row atoms are just too small to accommodate more than four bonded neighbors. Bigger atoms (from the 3rd row or below) have room for up to six neighbors around them, especially if the neighbors are relatively small. For example, nitrogen is too small to form bonds to five fluorines, but phosphorus can bond to five fluorines in PF5 or even five chlorines in PCl5. Bromine and iodine are too large to fit comfortably around a central phosphorus atom; PBr5 is very unstable, and PI5 does not exist. Hypervalent resonance forms with minimized formal charges contribute to a more precise presentation of electronic structure For atoms in the 3rd row (or below) we may encounter difficulties when selecting the most important Lewis structure, which is the one that contributes the most to the description of the actual molecule or ion. Since the octet of electrons is no longer a formal limit, we may have some controversial decisions to make, a bit similar to the BF3 case presented above. Specifically, our decision may be between a structure that has an octet on the central atom, but also has many formal charges, and a structure with a hypervalent central atom, but diminished formal charges. Consider the phosphate trianion (F07-5-3), for which we can write a Lewis structure with an octet on the phosphorus atom with the overall charge of the species shown outside of the bracket, or with formal charges assigned to individual atoms (+1 on P and −1 on each oxygen). Since the phosphorus atom can form hypervalent compounds (F07-5-3), we can also write four equivalent resonance structures with −1 charges appearing on three oxygen atoms, i.e., the minimum possible for a trianion. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 108/250 9/2/2019 Chem 110 Figure F07-5-3. Resonance structures for a hypervalent atom. For the phosphate ion, PO43−, one can write a resonance structure with an octet on phosphorus and multiple formal charges (left), or four equivalent resonance structures (right) in which phosphorus is hypervalent (5 bonds = 10 electrons), but with fewer formal charges. Experimental measurements show that the negative charge is distributed equally in the species; all oxygen atoms are equivalent. Also, all P-O bonds are of equal length. Both structural notations, the octet structure (on the left in F07-54), and the hypervalent resonance structures (on the right in F07-5-3) match these experimental observations. However, the P-O bond length in phosphate trianion (153 pm) is notably shorter than an average single P-O bond (165 pm), suggesting that resonance structures with the double bond contribute significantly to the electronic description of the ion. The double-bonds that are formally drawn for hypervalent atoms are distinct from the double bonds formed by octetsatisfying atoms. Their constructions would require participation of d orbitals, but as mentioned above, these orbitals do not participate in bonding to any significant extent in the compounds under consideration. To account for the increased bonding (shorter, stronger bonds) a different theoretical model is applied (molecular orbital theory), which we will cover in the second semester of general chemistry. For now, for simplicity, we can rationalize it as a strong electrostatic attraction between the central atom (with a positive formal charge) and the negatively-charged atoms bonded to it. In our course, if a Lewis structure can be drawn where there are complete octets on all non-hydrogen atoms, it is not necessary to draw additional resonance structures, even if structures with lower formal charges result. The Lewis structure with complete octets can be used to determine the three-dimensional shape of the molecule and most of its properties of interest, such as polarity and applicable intermolecular forces, topics which we will discuss in future lessons (see Chapter 8 and Chapter 11). However, chemists routinely draw double bonds from hypervalent atoms, including those in resonance structures. Such structures should remind us about increased bond strengths (and shorter lengths), and in the case of resonance structure, about increased stability of the whole molecule. In Figure F07-5-4, we show some examples of such notation for a couple of hypervalent ions. and 4 additional (equivalent) resonance structures and 1 additional (equivalent) resonance structure Figure F07-5-4. Examples of Lewis structures for hypervalent atoms with and without double bonds. The sulfate ion (SO42−) is drawn with an octet on sulfur (top left) and in hypervalent representation (top right) with two double bonds and a zero formal charge on sulfur. The S-O bond in sulfate is 149 pm in length (an average S-O single bond is 170 pm, while an average S=O double bond is 143 pm). The chlorate ion (ClO3−) is shown with an octet on chlorine (bottom left) and with a hypervalent chlorine atom (bottom right) that has double bonds, but a zero formal charge. The Cl-O bond in chlorate is 149 pm (an average Cl-O single bond is 171 pm). In summary, if multiple Lewis structures can be drawn with the same atom connectivity, but different electron apportionment to individual atoms, our rules for evaluating the relative contribution of these resonance forms to the description of the actual electronic structure of the molecule are as follows: https://genchem.science.psu.edu/sites/default/files/filefnlBYE 109/250 9/2/2019 Chem 110 For 2nd period atoms, structures where all non-hydrogen atoms have an octet contribute more than structures where atoms have incomplete octets. Hypervalent structures with more than eight electrons around period 2 atoms are not possible. If all atoms have octets, then the structure with lowest formal charges is most dominant. Among structures with the same formal charges, the one with formal charges that match the electronegativity trends is a more important contributor. For 3rd period atoms (and below), hypervalent structures with more than eight valence electrons per atom are possible. We will consider non-hypervalent structures to be sufficient to describe most properties of a species, even if a hypervalent structure with smaller formal charges can be drawn. However, such hypervalent constructs add to our understanding of the structures, bond lengths, and properties of these species. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 110/250 9/2/2019 Chem 110 08 Molecules in 3D Lewis structures display the connectivity of atoms and apportionment of all valence electrons into bonding and lone pairs. However, they do not explicitly depict one of the most important aspects of molecules: the 3-dimensional disposition of their bonded atoms. Information about the shapes and sizes of molecules, or about the overall polarity resulting from uneven distributions of electron density, is central to understanding the properties of the molecules and substances around us. Though this information is not explicitly displayed in Lewis structures, we can extract it from them, using what we know about geometrical and electrostatic patterns in molecules. 08-1 VSEPR Both bonding and nonbonding electron pairs on an atom repel each other electrostatically. The energy of a molecule is lowered if such repulsions are minimized for all atoms in the molecule. This can be achieved by placing any atom’s electron pairs as far as possible from each other in three dimensions. The geometrical model we use to understand this placement is called Valence Shell Electron Pair Repulsion or VSEPR. All electron pairs around a given central atom are divided into bonding and nonbonding electron domains. The number of bonding domains is equal to the number of atoms bonded to the central atom. If bonding involves a double or a triple bond, all shared electrons in that bond count as one domain. Nonbonding pairs (lone pair electrons), if any exist, constitute additional electron domains. The total number of domains is called the steric number of an atom. The steric number determines the canonical shape of the molecule, which is called the electron-domain geometry. Possible electron-domain geometries include linear (for a steric number of 2), trigonal planar (for 3), tetrahedral (for 4), trigonal bipyramidal (for 5), and octahedral (for 6). 08-2 Canonical geometries Molecular geometry is defined by the distances between nuclei (bond lengths) and the angles between their inter-nuclear axes. Lone pairs, though critical to determining geometry, do not have well-defined axes, and therefore, angles to them cannot be explicitly specified. Therefore, molecular geometry only describes the positions of atoms and bonds, not those of the lone pairs. For each of the canonical molecular shapes determined by electron-domain geometry there are a number of molecular geometries available, each pre-determined by the number of nonbonding domains present and each described by its own AXE formula. In AXE notation the number of bonded partners, X, and nonbonding domains, E, are listed as subscripts. 08-3 Molecular shapes We can further refine our understanding of molecular geometry by acknowledging that the mutual repulsions of the domains are not equal. Lone pair domains repel most strongly, multiple-bond domains are next, and single-bond domains repel the least.This gradation in repulsive interactions allows us to make qualitative predictions about how bond angles deviate from their canonical values. 08-4 Molecular polarity Maps of electrostatic potential. The 3-dimensional structure of molecules can be used to predict molecular polarity. The presence of polar bonds can be deduced from electronegativity differences between the bonded atoms. Utilizing the structuredependent spatial orientation of bonds, the bond dipole vectors can then be added together to decide whether or not the molecule has a net dipole moment, i.e. whether it is polar, and to qualitatively predict its magnitude and direction. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 111/250 9/2/2019 Chem 110 08-1 VSEPR Electron domains are distributed around central atoms to minimize electron-pair repulsion The underlying principle governing the formation of covalent bonds is the sharing of valence electron pairs. While an atom may form bonds to several bonding partners, some electrons may remain unshared (which we call lone pairs), or even, on rare occasions, unpaired (which happens in radicals). As we have learned, Lewis structures provide a convenient accounting technique to keep track of how valence electrons are apportioned to bonding partners, telling us how many partners each atom has, how many electron pairs it shares with each of them to form single, double, or triple bonds, and how many lone pairs (or single electrons) it has. However, with the exception of trivial cases such as diatomic molecules, Lewis structures do not provide any direct information on molecular shapes. We can easily determine the number of bonding partners and lone pairs on any atom of interest in a molecule, but the 3-dimensional disposition of these bonding or lone electron pairs around the atom requires further analysis. So far, we have drawn Lewis structures with all the atoms in one plane, with angles between bonds and disposition of nonbonding pairs around atoms arbitrarily chosen for clarity of presentation. To fully describe molecular shape, we need realistic bond lengths and true bond angles. We already know about bond lengths, and how to estimate them from atomic sizes, or to approximate them with average values. It turns out we can also get surprisingly good values for the bond angles from simple electrostatic and geometric arguments. Since electrons repel each other electrostatically, electron pairs on a given atom will arrange themselves in space to be as far from each other as possible. This mutual evasion minimizes the energy of the molecule by minimizing the electron repulsion. This model is appropriately called Valence Shell Electron Pair Repulsion (VSEPR). Let's start with the simplest set of cases: a central atom (A) with no lone electron pairs, singly bonded to an increasing number of identical other atoms (X). With just one bonding partner (A−X), the situation is trivial: we do not have any bond angles to analyze, and therefore, we can omit it from our examination. If there are only two bonding partners, X−A−X, the two bonds arrange themselves pointing in opposite directions, with a 180° angle between them. The molecule adopts a linear shape (Table T08-1-1). When three bonding partners are present, the three bonds in AX3 can minimize their repulsion if they point to the vertices (corners) of an equilateral triangle that has the central atom in its center, resulting in trigonal planar geometry, with 120° angles between bonds. Likewise, the optimal arrangement of the four bonds in AX4 is tetrahedral, with the central atom in the middle of the tetrahedron and the four bonding partners at the vertices. All bond angles are 109.5° (it requires some trigonometry to calculate this). With five bonding partners, the five bonds in AX5 minimize their repulsion by pointing to the corners of a trigonal bipyramid that has the central atom in the middle of the polyhedron. Here, the bond angles are 120° between equatorial bonds (those laying in the trigonal base common to both pyramids) and 90° between any pair of equatorial and axial bonds (axial bonds are those pointing toward the apexes of the pyramids). The axial bonds are 180° apart. Similarly, the six bonds in AX6 form an octahedron with the central atom in the middle and bond angles of 90° or 180°. There are only a few special cases where a very large central atom can bond to more than 6 other small atoms (AX7, AX8, or AX9). They are outside the scope of our Lesson, but even these cases mostly follow the logic of electron-pair repulsion outlined here. Canonical structures represent the optimal possible spatial arrangement of atoms bonded to the central atom The regular polyhedra we have described serve as canonical structures, and set standards to which all further modifications will refer. They represent arrangements of atoms bonded to a central atom that maximizes both distances between these atoms and the separation between the bonding electron pairs. Such ideal structures can only exist when all atoms bonded to the central atom are identical, as shown by examples in T08-1-1. Any perturbations, such as the presence of lone pairs, multiple bonds, or even atoms of varying electronegativity, will cause small deviations from the canonical shapes. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 112/250 9/2/2019 Chem 110 Table T08-1-1. The canonical molecular shapes Lewis structure Geometry Polyhedron Name Example AX 2 linear BeH 2 AX 3 trigonal planar BH 3 AX 4 tetrahedral CH 4 AX 5 trigonal bipyramidal PF 5 AX 6 octahedral SF 6 We already know that single bonds are actually clouds of shared electrons that occupy internuclear space. Lone electron pairs similarly occupy certain volumes of space that point in a particular direction (even if there is no bonded atom at the "end of the cloud"). We call either of these directional electron density volumes electron domains. All electrons shared by the central atom and any given bonding partner must belong to the same electron domain as they are all found along the same internuclear axis. Therefore a multiple bond in a molecule constitutes just one domain, as do all single bonds and lone electron pairs, or any unpaired electrons if present. The number of electron domains around any central atom is called its steric number. linear trigonal planar tetrahedral trigonal bipyramidal octahedral Figure F08-1-1. The arrangements adopted by two, three, four, five, and six connected balloons (from left to right). Electron domains are similar to these balloons and avoid each other in space by minimizing electron pair repulsions. The electron domains protruding from the central atom behave like balloons tied together, trying to share the available space, and pushing each other away (Figure F08-1-1). This analogy describes the electron pair repulsions that we used to arrive at our canonical shapes (shown in Table T08-1-1) quite well. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 113/250 9/2/2019 Chem 110 08-2 Canonical geometries Electron-domain geometries result in specific molecular geometries when the presence of lone electron pairs is considered We can extend the balloon analogy to construct shapes for molecules with lone pairs and multiple bonds. A central atom’s number of electron domains (its steric number) is read directly from the Lewis structure. The "AXE” notation is commonly used to systematize this approach. As we already learned in the previous section, the “A” in AXE notation designates the central atom, while “X” represents the bonding domains and “E” represents the nonbonding pairs (or single electrons if present). Table T08-2-1 lists the possibilities. Table T08-2-1. Molecular geometries classified in the AXE notations Steric number Zero lone pairs One lone pair Two lone pairs Three lone pairs 2 AX2E0 linear 3 AX3E0 trigonal planar AX2E1 bent AX4E0 tetrahedral AX3E1 trigonal pyramidal AX2E2 bent AX5E0 trigonal bipyramidal AX4E1 seesaw AX3E2 T-shape AX6E0 octahedral AX5E1 square pyramidal AX4E2 square planar 4 5 AX2E3 linear 6 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 114/250 9/2/2019 Chem 110 To determine the molecular structure of a molecule or ion we follow a series of well-defined steps: 1. We start by drawing the Lewis structure for the molecule or ion. We count the number of bonding domains (including single and multiple bonds), and the number of nonbonding domains (lone pairs) on the central atom. The number of bonding domains equals the number of atoms bonded to the central atom. In rare cases a single (unpaired) electron will constitute its own nonbonding domain when we deal with radicals. 2. Next, we write the AXE formula for the central atom, with subscripts indicating the number of domains of each type. The total number of domains equals the steric number of the atom. If the structure has multiple central atoms, we analyze each one in turn. 3. The steric number tells us the electron-domain geometry (ED geometry). We have only five options in this category: linear, trigonal planar, tetrahedral, trigonal bipyramidal, or octahedral; these are shown in Table T08-1-1, and repeated in the first column of Table T08-2-1. 4. Depending on the number of nonbonding pairs, we then arrive at the molecular geometry. The molecular geometry only describes the relative position of atoms (i.e., their nuclei) neglecting lone pairs. As you may remember from our quantum introduction, electrons behave as density clouds that reflect the probability of finding electrons in a given region of space. Therefore we cannot pinpoint their exact locations (or any bond angles involving them). On the other hand, the positions of the nuclei are well-defined, and the separation between inter-nuclear axes unambiguously defines the bond angles between atoms. 5. Finally, we adjust the ideal bond angles from the canonical structures to correct for unequal repulsions between the various types of electron domains. We will learn how to carry out this final refinement in the next Lesson. Molecules with a steric number of 3 can have trigonal planar or bent molecular geometries, whereas a steric number of 4 yields tetrahedral, trigonal pyramidal, or bent molecular geometries For now, let's examine these geometries in more detail. A molecule with a steric number of 3 has trigonal planar ED geometry, giving us two possible molecular geometries: trigonal planar (with no lone pairs), or bent (with one electron pair) as shown in the second row of T08-2-1. With a steric number of 4, the ED geometry is tetrahedral. We now have three options, with zero, one, and two electron pairs. The resulting molecular geometries are tetrahedral, trigonal pyramidal, and bent, respectively. In Figure F08-2-1, we maintain the tetrahedron outline for AX3E1 and AX2E2 to show how the geometries are related. ⇒ AX4E0 tetrahedral ⇒ AX3E1 trigonal pyramidal AX2E2 bent Figure F08-2-1. The geometries of molecules with a steric number of 4. The lone pairs point in the direction of the vacant vertices. Molecules with a steric number of 5 can have trigonal bipyramidal, seesaw, T-shaped, or linear molecular geometries With a steric number of 5, the electron-domain geometry is trigonal bipyramidal. Depending on the number of lone pairs, we have four possible molecular shapes in this case: trigonal bipyramidal (no lone pairs), seesaw also called a sawhorse (one lone pair), T-shaped (two lone pairs), and linear (three lone pairs). The relationship between these shapes is shown in F08-2-2. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 115/250 9/2/2019 Chem 110 ⇒ ⇒ AX5E0 trigonal bipyramidal AX4E1 seesaw ⇒ AX3E2 T-shaped AX2E3 linear Figure F08-2-2. The geometries of molecules with a steric number of 5. The lone pairs point in the direction of the vacant vertices. For AX4E1 we have an interesting choice to make: should the lone pair be in the equatorial position, as shown in Table T08-2-1, or in the axial position (F08-2-3). As we will see in the next section, the nonbonding domains are more repulsive than bonding domains. The lone pair in the equatorial position has two repulsive interactions with axial bonding pairs 90° apart, while the lone pair in the axial position has three such interactions with the equatorial bonding pairs. Since repulsions are much greater when the domains are situated 90° apart rather than when they are 120°, the equatorial lone pair results in lower energy. By the same logic, both lone pairs in AX3E2 are equatorial (see F08-2-3), which keeps them 120° apart from each other. Figure F08-2-3. Two possible placements of the lone pair in AX4E1. The lone pair experiences less repulsion in the equatorial position. Molecules with a steric number of 6 can have octahedral, square pyramidal or square planar molecular geometries With a steric number of 6, the electron-domain geometry becomes octahedral (F08-2-4). The possible molecular geometries include octahedral (no lone pairs), square pyramidal (one lone pair), and square planar (two lone pairs). Since all positions in the octahedron are equivalent, the positioning of the first lone pair is immaterial, but the second one is best placed 180° to the first, to minimize the repulsions between them. ⇒ AX6E0 octahedral ⇒ AX5E1 square pyramidal AX4E2 square planar Figure F08-2-4. The geometries of molecules with a steric number of 6. The lone pairs point in the direction of the vacant vertices. We have just taken the first step in learning how to translate collections of lines (bonds) and dots (electron pairs) into reasonably good approximations of molecular shapes. It takes some practice to be able to look at Lewis structures and visualize how the atoms are positioned in 3 dimensions. So far we have explored how to interpret such structures for ideal, abstract molecules. Next, we will analyze some real examples, adding more sophistication to our model. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 116/250 9/2/2019 Chem 110 08-3 Molecular shapes The repulsion caused by lone pair electron domains is greater than the repulsion caused by multiple-bond domains, which in turn is greater than that caused by single-bond domains As we have already alluded, the canonical shapes and bond angles in Table T08-1-1 result only when all of the X atoms bonded to the central atom are the same. Even minor perturbations in the size or electronegativity of X causes small deviations from the perfect polyhedra; the bond lengths are no longer all equal and the bond angles depend on the relative strengths of repulsions between different electrons domains. In general, bonding electron domains are less repulsive than non-bonding electron domains. The bonding electrons are attracted to the nuclei of both bonding partners, so they are farther away from the central atom on average than lone-pair electrons, which gain stabilization only through attraction to the central atom’s nucleus. You can imagine this phenomenon as if the nonbonding electrons pushing their way closer to the nucleus electrostatically shoved the other domains closer to each other. Therefore, the repulsion caused by the lone pairs (lp) is greater than the repulsion caused by the bonding pairs (bp). As a result, all else being equal, lp-lp repulsion is stronger than lp-bp repulsion, and in turn, lp-bp repulsion is stronger than bp-bp repulsion. Similarly, bonding domains comprised of multiple bonds (which have higher electron density) are somewhat more repulsive than single-bond domains, although less so than lone pairs. This gradation in the energetic penalties resulting from repulsive interactions among the various electron domains has qualitative predictive value with regard to bond angles. We illustrate these repulsive interactions and their influence on the fine details of molecular shapes for different AXE categories below. Molecules with a steric number of 3 have bond angles close to the canonical angle of 120° The trigonal planar canonical structure has 120° bond angles, as found in BF3 (Figure F08-3-1). Even if we cannot decide which resonance structure is dominant or what the bond order is, the three B−F bonds are equivalent and they repel each other equally, preserving the symmetry of the structure. In carbonyl dichloride (phosgene), the double bond domain repels the single bond domains more strongly than they repel each other. The O−C−Cl angles open up from the canonical 120° to 124°, while the Cl−C−Cl bond angle gets smaller. A similar situation is found in ethene (ethylene) regarding its double bond. In ozone, the lone-pair domain repels both bonding domains more forcefully than they repel each other. This is true even though the bond order is 1.5 because of resonance, and the bonds have higher electron density than would single bond domains. Similarly, the repulsion between the double-bond and the single-bond domains in trans-diazene is weaker than the repulsion that they are both getting from the lone pair domains. As a result, the H−N−N bond angle decreases significantly from the canonical 120°. This is one of the largest departures from standard bond angles that we will encounter. Typically, the deviations are just a few degrees, only occasionally exceeding 10°. trigonal planar trigonal planar trigonal planar bent bent AX3E0 AX3E0 AX3E0 AX2E1 AX2E1 boron trifluoride carbonyl dichloride ethene ozone trans-diazene Figure F08-3-1. Examples of bond angles in structures with trigonal planar electron-domain geometry. The central atoms used for analysis are shown in red. For clarity, only lone pairs on the central atoms are shown. The imaginary axes for lone pairs are added to help relate the structures to their canonical equivalents. In trans-diazene, the trans- prefix indicates that the hydrogens are on the opposite sides of the double bond (we will discuss such geometrical isomers later in the course). Notice that for planar geometries the angles around the central atom must add up to 360° (within rounding error). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 117/250 9/2/2019 Chem 110 Molecules with a steric number of 4 have bond angles close to the canonical angle of 109.5° Perfect tetrahedral bond angles of 109.5° are observed only when the four domains are identical, as illustrated by methane in Figure F08-3-2. If one of the domains is a lone-pair domain, the angles between the bonding domains shrink noticeably, as seen in ammonia. This angle contraction is not halted even if the bonding domains have higher electron density because of their increased bond order (due to resonance, as happens in the sulfite ion (SO32−). When there are two lone-pair domains, as in water molecules, the effect is even more pronounced, as the lone-pair domains strongly repel not only the bonding domains, but each other as well. Deviations from the canonical structures are even caused by what might be considered minor perturbations. In methyl chloride (four bonding domains), the electrons in the C−Cl bond are polarized away from carbon and toward chlorine due to the electronegativity difference. This shift diminishes the repulsion between the C−Cl and the C−H bonding electrons, which are much closer to the central carbon because of the reversed electronegativity difference and the short length of the C−H bonds. As the result, Cl−C−H bond angles close up a bit, while the H−C−H bond angles open up. tetrahedral trigonal pyramidal bent trigonal pyramidal tetrahedral AX4E0 AX3E1 AX2E2 AX3E1 AX4E0 methane ammonia water sulfite ion methyl chloride Figure F08-3-2. Examples of bond angles in structures with tetrahedral electron-domain geometry. The central atoms used for analysis are shown in red. For clarity, only lone pairs on the central atoms are shown. The imaginary axes for lone pairs are added to help relate the structures to their canonical equivalents. Molecules with a steric number of 5 have bond angles close to the canonical angles of 90° and 120° With a steric number of 5, the canonical electron-domain geometry is trigonal bipyramidal. Phosphorus pentafluoride (F083-3) is one example of such a structure. In this geometry we have two groups of angles to analyze: the angles between the equatorial domains, and the angles between the equatorial and axial domains. As we discussed previously, the placement of the lone pair in the equatorial position leads to less repulsion and a lower energy of the system. Sulfur tetrafluoride illustrates such a situation. The equatorial lone pair repels the other equatorial domains (S−F bonds) more strongly than they repel each other, squeezing them together to form a 102° F−S−F angle. Similarly, the axial S−F bonds are pushed back away from the lone pair (the standard inter-axial bond angle would have been 180°). When a second lone pair is present the lowest energy structure is also obtained when it is in the equatorial position, as in chlorine trifluoride. Again, the axial Cl−F bonds are pushed back away from the lone pairs. When a third lone pair is present, as in xenon difluoride, it is positioned in the equatorial plane and returns the structure to the higher symmetry. The repulsions of all equatorial domains are now balanced, resulting in a perfectly linear structure. Thionyl tetrafluoride shows the effect of a double bond domain, and has a structure very similar to sulfur tetrafluoride; the domain with the strongest repulsion is that of the equatorial S=O double-bond instead of the lone pair. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 118/250 9/2/2019 Chem 110 trigonal bipyramidal seesaw T-shaped linear AX4E1 AX3E2 AX2E3 AX5E0 sulfur tetrafluoride chlorine trifluoride xenon difluoride thionyl tetrafluoride AX5E0 phosphorus pentafluoride trigonal bipyramidal Figure F08-3-3. Examples of bond angles in structures with trigonal bipyramidal electron-domain geometry. The central atoms used for analysis are shown in red. For clarity, only lone pairs on the central atoms are shown. The imaginary axes for lone pairs are added to help relate the structures to their canonical equivalents. Notice that angles between the equatorial domains must add up to 360° as these domains lie in one plane. Molecules with a steric number of 6 have bond angles near the canonical angle of 90° In the canonical octahedral electron-domain geometry all positions are equivalent. Even if we label two separate angles in SF6 (F08-3-4), there are no equatorial and axial positions that can be distinguished, as any four of the identical atoms (fluorines in this case) can formally constitute the base of what could be called a "square bipyramid". Replacing one of the bonding domains with a lone pair breaks that symmetry. As shown in iodine pentafluoride, the lone pair repels the bonding domains away from itself, squeezing the remaining bond angles to below 90°. A second lone pair should then be placed 180° from the first, to minimize their mutual repulsions. Xenon tetrafluoride illustrates such a situation where the repulsive action of both lone pairs on the remaining bonding domains balances out. octahedral square pyramidal AX6E0 AX5E1 square AX4E2 sulfur hexafluoride iodine pentafluoride xenon tetrafluoride Figure F08-3-4. Examples of bond angles in structures with octahedral electron-domain geometry. The central atoms used for analysis are shown in red. For clarity, only lone pairs on the central atoms are shown. The imaginary axes for lone pairs are added to help relate the structures to their canonical equivalents. As we were focusing on the geometry of our examples, and not their makeup, you may not have noticed that we named two xenon compounds among them. Yes, the noble gas xenon can form compounds! It turns out that the largest noble gases may form stable hypervalent compounds. Examples are limited to combination with the most electronegative element, fluorine; XeF2, XeF4, and XeF6 form reasonably stable crystalline substances. There are also a few unstable xenon oxyfluorides and oxides, and a few very transient compounds of krypton (KrF2) and even argon (HArF). No compounds of helium or neon have ever been prepared, and radon is not studied due to its radioactivity. If a molecule has multiple central atoms, they all have to be analyzed in turn. For example, glycine, the simplest amino acid, has 4 atoms that are bonded to at least two other atoms. The electron-domain and molecular geometries of these atoms are listed in Table T08-3-1. The predicted values for several bond angles are also included (experimental values confirm our expectations). However, one issue remains unaddressed: the relative orientation of all "fragments" around the central atoms. We can identify the geometry around each central atom, but how are these geometries stitched together in the molecule of glycine? To answer this question we must use even more sophisticated models of electron repulsion in a process called conformational analysis. Although that topic is beyond the scope of general chemistry, we will address some of its simplest concepts in later Lessons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 119/250 9/2/2019 Chem 110 Table T08-3-1. Structural data for glycine Glycine Central Steric atom number O 4 AX2E2 C 3 AX3E0 trigonal planar C 4 AX4E0 N 4 AX3E1 AXE https://genchem.science.psu.edu/sites/default/files/filefnlBYE ED geometry Molecular geometry Bond angles predicted / observed bent α <109.5° 106° trigonal planar β <120° 117° tetrahedral tetrahedral γ 109.5° 109.5° tetrahedral trigonal pyramidal δ <109.5° 107° tetrahedral 120/250 9/2/2019 Chem 110 08-4 Molecular polarity Molecules are polar if they have polar bonds and a geometry such that their bond dipoles do not cancel each other out We previously explored the concept of molecular polarity, starting with diatomic molecules where bond dipole moments gave us information about uneven electron density distributions among bonding partners. Larger molecules can also be polar overall, if the centers of the positive and the negative charges do not coincide. Two conditions have to be satisfied for a molecule to show a net dipole moment: 1. The molecule has to have polar bonds, i.e. bonds between atoms of differing electronegativity. The larger the electronegativity difference, the bigger the magnitude of the resulting bond dipoles. 2. The bond dipoles must not cancel. The bond dipole moments are vectors that have magnitude and direction. The magnitude of the vectors is dictated by the electronegativity differences between the bonded atoms. The relative spatial positions of the vectors and their orientation (the direction they point in) is determined by the 3-dimensional shape of the molecule. We need to perform vector addition of all bond dipoles to qualitatively establish whether a given molecule has a dipole moment (and to determine the magnitude and direction of that dipole). Let's look at a couple of examples to familiarize ourselves with the procedures involved. In a water molecule, we have two polar O−H bonds (χ(O) = 3.44, χ(H) = 2.20). Even if we do not know the specific magnitudes of the bond dipoles, we know they must be substantial because of the relatively large electronegativity difference between O and H (Δχ = 1.24). The water molecule is bent, with an H−O−H bond angle of 104°. In the Figure F08-4-1 we draw the bond dipoles along the O−H bonds on an arbitrary scale, with arrows pointing toward the more electronegative atom. The two bond-dipole vectors have the same magnitude, but point in different directions. To add the vectors graphically, we use the "head-to-tail" method; we translate one vector (green) to the end of the other vector (blue) without changing its direction or magnitude. The vector sum shown in orange is obtained by connecting the tail of the first vector with the head of the other. The vector sum indicates that there is a net dipole moment for the whole molecule, showing an overall shift of electron density toward the oxygen. That polarization may be alternatively illustrated by the MEP of water. The experimentally determined dipole moment of water is 1.85 D. Figure F08-4-1. The bond dipoles of water molecule are added graphically by the "head-to-tail" method, where the line starts with a cross at the atom with positive partial charge and ends with an arrow at the atom with a negative partial charge. In a water molecule, H (white) has positive charge and O (red) has negative charge. Negative charge on oxygen means that electron density shifts toward it and electrons spend more time near oxygen. The polarization of electron cloud is apparent in the MEP image (full scale of potential energy). Figure F08-4-2. The bond dipoles of carbon dioxide cancel out. The molecule has no dipole moment, even though it has polar bonds. The MEP illustrates the symmetrical charge polarization in this molecule. On the other hand, a carbon dioxide molecule also has polar bonds (χ(O) = 3.44, χ(C) = 2.55), but the bond dipole moments cancel out because the molecule has linear geometry. The bond dipole vectors are equal in magnitude, but point in opposite directions, and the vector sum is zero. The CO2 molecule is non-polar (μ = 0). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 121/250 9/2/2019 Chem 110 Symmetrical molecules with identical atoms bonded to the central atom have no net dipole moments, even if they have polar bonds Keeping the results for the CO2 molecule in mind, we can intuitively conclude that certain symmetrical molecules where all atoms bonded to the central atom are identical will have no dipole moments, even if they have polar bonds. This is obvious for linear and octahedral molecules (AX2E0 and AX6E0) as for each bond dipole there is another of the same magnitude but pointing in the opposite direction (Figure F08-4-3). The same is true for the linear AX2E3 and square planar AX4E2. It is less obvious for the trigonal planar or the tetrahedral molecules, but vector addition (F08-4-3) demonstrates that the bond dipoles cancel out in these cases as well. The trigonal bipyramid is just a sum of the linear (axial bonds) and trigonal planar geometries (equatorial bonds) which both have cancelling bond-dipole vectors. Figure F08-4-3. Symmetrical molecules where the bond dipoles cancel and the net dipole of the molecules is zero. In the first four structures from the left, the canceling of dipole vectors is directly visible. In AX3E0 the vector sum of the two "upper" bond dipoles is equal but opposite to the dipole moment of the "lower" bond. In AX4E0 the vector sums of the two bond dipoles on one side of tetrahedron cancel out with those on the other side. AX5E0 is a combination of AX2E0 (axial bonds) and AX3E0 (equatorial bonds). Click on the image to see the dipole vectors. Strictly speaking, we should also consider the contributions of lone pair dipoles, which have dipole moment vectors pointing away from the nucleus along the lone pair axis. However, the nonbonding electrons are non-directional (spacially quite diffuse) and held closely to the nuclei, so these contributions are usually small and may be neglected in our qualitative reasoning. For symmetrical molecules (see above) the lone pair dipoles cancel if the bond dipoles do. Molecular dipole moments are vector sums of bond dipole Let's consider some instructive examples (F08-4-4). In methyl chloride the C−Cl bond dipole is enhanced by the sum of three C−H bond dipoles, as carbon is less electronegative than chlorine but more electronegative than hydrogen. The molecule is polar and the measured dipole is 1.87 D. In ammonia, the N−H bond dipoles (Δχ = 0.84) are augmented a bit by the lone pair dipole, while in nitrogen trifluoride the bond dipoles are in the opposite direction (Δχ = 0.94), and are partially canceled by the lone pair dipole. As a result the molecular dipole of ammonia is larger and in opposite direction than that of NF3. As we noted above, CO2 has no dipole moment, but SO2 does due to its bent geometry. Similarly, CF4, being perfectly tetrahedral, does not have a dipole moment, but SF4 does due to the presence of the lone pair that "breaks" molecular symmetry. These pairs of contrasting cases stress the need for careful evaluation of individual molecular structure; do not be fooled by the seemingly fortuitous similarity of some formulas. The number of lone pairs and the 3-dimensional structure should be carefully considered before assessing overall polarity. μ = 2.1 D μ = 1.7 D μ = 0.3 D μ = 2.0 D μ = 1.7 D Figure F08-4-4. The bond dipoles and molecular dipoles (μ) of several molecules. The numbers listed are electronegativity values. Click on an image to explore bond dipoles (orange), molecular dipoles (red) and MEPs (on 100 kJ scale) of the molecules. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 122/250 9/2/2019 Chem 110 The logic of predicting a dipole (qualitatively) from the electronegativity difference and molecular structures may occasionally be reversed. Sometimes structures may be distinguished from each other based on the experimental polarity criterion. For example, three isomeric dichloroethylenes are shown in Figure F08-4-5. Their dipole moments have been experimentally measured as 0 D, 1.47 D, and 1.96 D. Which isomer has no dipole moment? Which is the most polar? A simple examination of bond dipoles clearly shows that I has no dipole, as its bond dipoles cancel exactly. The other two require some simple head-to-tail vector addition before we can conclude that III is the most polar. The bond angles and the bond-dipole vector angles decide the outcome, since all contributing bond dipoles (C−Cl and C−H, respectively) are the same. Figure F08-4-5. The bond dipoles for C−H and C−Cl bonds in isomeric dichloroethylenes. The C−H (smaller arrows) and C−Cl bond (larger arrows) dipole vectors are added "head-to tail" in each molecule. In I, the bond dipoles cancel out and in II and III, the sum of the vectors results in a green vector (II) and an orange vector (III). The side-by-side comparison of green and orange vectors clearly shows that III has the largest vector sum. Now we can see the true nature of Lewis structures. They are not just a bunch of lines and dots, they are highly sophisticated ideograms. They can communicate extensive information on molecular shape and polarity if supplemented with electronegativity data. Even when drawn with awkward geometries and bond angles, experienced viewers can visualize the 3-dimensional molecular structures in exquisite detail. We will need all of this information when we start exploring molecular interactions in future Lessons. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 123/250 9/2/2019 Chem 110 09 Valence Bond Theory At the beginning of our course we studied quantum wavefunctions and the resulting atomic orbitals as representations of electron density around individual atoms. When atoms combine to form molecules these orbitals interact to form new receptacles for the redistributed valence electrons. Valence bond theory is one of the bonding models that describe the bond formation process in terms of interpenetrating atomic orbitals. Even if there are other theories of bonding, such as molecular orbital theory, our approach is to use the simplest model that accounts for the phenomenon of interest. 09-1 Orbital overlap When two atoms approach each other their orbitals overlap. The wavefunctions of two electrons, one on each atom, interpenetrate and add together. This results in a wavefunction with increased amplitude and higher electron density (which is the square of the wavefunction). The increased electron density along the internuclear axis is called a σ bond. The length of the bond corresponds to the distance at which the electrostatic energy is minimized. The electrons constituting the bonding pair must have opposite spins in order to obey the Pauli exclusion principle. The making of bonds by spin-pairing electrons in overlapping orbitals is the essence of valence bond theory. 09-2 Hybridization Atoms can be considered to pre-mix their valence orbitals to form hybrid orbitals before bonding. Depending on the number of orbitals participating in mixing, there are three hybridization types; sp3 forms four hybrids, sp2 forms three hybrids and leaves one p orbital unhybridized, and sp forms two hybrids and leaves two unchanged p orbitals. Either the atomic or the hybrid orbitals can overlap head-on producing a σ bond. For atoms following the octet rule, the number of electron domains on the atom determines the hybridization type. 09-3 π bonds The p orbitals left out of hybridization may overlap sideways forming π bonds. The π bonds have electron density above and below the internuclear axis, but not along the axis. They are weaker than σ bonds, because of diminished overlap in the sideways approach. If an atom participates in formation of a double or triple bond, only one of the bonds is the σ bond; the remaining bonds are π bonds. The molecules that require resonance structures for adequate representation have a delocalized π system built of more than two overlapping p orbitals on adjacent atoms. Such a π system holds delocalized π electrons that are shared by more than two atoms. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 124/250 9/2/2019 Chem 110 09-1 Orbital overlap The energy of two interacting hydrogen atoms has a minimum when the atoms are 74 pm apart, which is the H-H bond length in an H2 molecule Over the last few Lessons we have learned a lot about molecules. We know how to write Lewis structures showing the connectivity between atoms and any nonbonding pairs. We can translate these structures into molecular shapes and reasonably estimate bond lengths and angles. We can analyze bond dipoles and molecular polarity. However, we have not yet explained how the bonds are made. To address that fundamental question we need to return to the quantum chemistry concepts that describe electron density distribution in atoms, which we introduced at the beginning of our course. After all, atoms are our building blocks and we need to figure out how they join together to form bonds. We begin with construction of the simplest molecule, H2, from two hydrogen atoms. As you recall, each hydrogen atom has one electron in a 1s orbital in its ground state. Two hydrogen atoms at a large distance from each other do not interact at all. The electrostatic energy of the system is zero as the electrostatic forces are infinitesimal (Figure F09-1-1). At closer distances the 2 electrons are attracted by both hydrogen nuclei and the energy of the system drops. The decrease is small at first, when the two atoms are at the van der Waals distance, and then greater when they are within bonding distance. At even closer separation, the nuclear-nuclear repulsion becomes dominant, and the energy rapidly increases as the nuclei get very close to each other. Figure F09-1-1. The energy of two hydrogen atoms as the function of internuclear separation. At large distances the atoms do not interact electrostatically and there is no stabilization energy. At closer distances (for example at the van der Waals distance) the energy gets lower, and it reaches a minimum at the bonding distance of 74 pm. At shorter distances, the nuclear-nuclear repulsions increase the energy of the system. The energy of the H2 molecule reaches a minimum at a separation distance of 74 pm; that distance is what we call the bond length. It corresponds to the lowest energy compromise between the attractive and repulsive interactions, and the energy lowering at this point equals the negative of the bond dissociation energy (BDE). The σ bond in a H2 molecule is formed by the overlap of the two 1s orbitals of the hydrogen atoms As the two hydrogen atoms get closer their 1s orbitals overlap and interpenetrate, creating a space for the shared electrons. The overlap of orbitals is equivalent to constructive interference of the two 1s wavefunctions. When two water-wave crests interfere a bigger wave is created. Similarly, when two wavefunctions with the same algebraic sign overlap they add together, creating a new wave with a larger amplitude in the internuclear space (F09-1-2). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 125/250 9/2/2019 Chem 110 Figure F09-1-2. Constructive interference (addition —) of two 1s wavefunctions (----). The amplitude of the wave increases in the space between the nuclei. The new volume with increased electron density is called the σ bond. It is shown as a 90% boundary surface. Since the electron density is the square of the wavefunction, the probability of finding the electron in the space along the internuclear axis also increases. As you may remember, that space between nuclei was identified as the "bonding region" in our electrostatic analysis done previously. Thus, the overlap of two atomic orbitals generates a new space where the electron density is shared effectively. That new electron "cloud" (the new orbital) is called the σ bond. As we have done previously for atomic orbitals, we represent it with a boundary surface encompassing 90% of bonding electron density. A characteristic of a σ bond is that it is cylindrically symmetric about the internuclear axis. Note that it encloses both bonded nuclei. The σ bond, like any orbital, can hold up to two electrons, but the two electrons must have opposite spins due to the Pauli exclusion principle. The spin-pairing requirement is responsible for the fact that all bonding and nonbonding electrons that we have considered in Lewis structures are always present as pairs. The radicals are a rare exception, and as we have alluded previously, the driving force to pair the odd electrons is responsible for the high reactivity of such species. In Valence Bond theory σ bonds form by the head-on overlapping of orbitals The overlap of atomic orbitals is not limited to 1s orbitals. We can easily extend that paradigm to the overlap of any valence orbitals, for example a 1s orbital on hydrogen overlaps with a 2p atomic orbital on fluorine in the formation of a σ bond in an H−F molecule (Figure F09-1-3). In a Cl2 molecule two 3p orbitals overlap to form a Cl−Cl σ bond. In each case, the single valence electron from each atom participating in bonding is spin-paired in the bond. Notice that the overlap of orbital lobes of the same algebraic sign (in-phase) is needed for constructive interference of wavefunctions. Figure F09-1-3. Overlap of 1s and 2p orbitals in an HF molecule, and two 3p orbitals in Cl2. The overlapping orbitals have matching phases (algebraic signs of their wavefunctions). The bonding theory we have just described is called Valence Bond theory (VB). Within its framework, bonds form by sharing spin-paired electrons between bonding partners. That sharing manifests itself in increased electron density along the internuclear axis in the space generated by the overlap of atomic orbitals, and is called a σ bond. The shared electrons are localized between the bonded atoms. We have previously described single bonds with electron domains in the VSEPR model, or lines connecting atoms in a Lewis structure; both are representations of the σ bond of VB theory. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 126/250 9/2/2019 Chem 110 Atomic orbital overlap does not adequately explain bonding in molecules Unfortunately, we quickly encounter difficulties when analyzing other simple molecules. Consider methane, CH4, with its tetrahedral shape and bond angles of 109.5°. Carbon has one 2s and three 2p valence orbitals in its ground state configuration; 2 paired electrons reside in the 2s orbital, and two unpaired electrons reside in the 2p orbitals. (Figure F09-1-4). Following our VB recipe, one would predict that carbon should form a CH2 molecule by overlap of the two unpaired electrons in 2p orbitals with two 1s orbitals on the hydrogens. The resulting two C−H bonds would be at 90° to each other, as that is the angle between any two p orbitals. In such a compound carbon would not have an octet. We know from experimental measurements that methane consists of a tetrahedral carbon atom σ-bonded to four hydrogen atoms. To match the true methane structure we need to prepare carbon for bonding by first making four equivalent orbitals from the four available valence orbitals (one 2s and three 2p). That process is called hybridization. Figure F09-1-4. The valence electrons of the ground state configuration of carbon and the formation of σ bonds by overlap of singly occupied 2p orbitals (two loops) with 1s hydrogen orbitals (green circles). The filled 2s orbital is omitted for clarity. The CH2 molecule is unstable because carbon atom does not have an octet. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 127/250 9/2/2019 Chem 110 09-2 Hybridization Hybrid orbitals better suited for bonding are created by the mixing of atomic orbitals To prepare four orbitals for bonding with four hydrogen atoms, the carbon atom needs four unpaired electrons. That requires promotion of one of the 2s electrons to an empty p orbital. The excited state that is produced has high energy (402 kJ/mole above the ground state); it still has three degenerate p orbitals at 90° to each other, along with the lower energy 2s orbital. These orbitals would not form four equivalent bonds at 109.5°. To make the orbitals equal we need to mix them all together (combine their wavefunctions mathematically) and form 4 new orbitals. Each new orbital is constructed from 1/4 of 2s orbital (it has 25% s character) and the rest of it (75%) is mixture of all three 2p orbitals. This process is called hybridization and the mixed orbitals are called hybrid orbitals. In a way the process is equivalent to making mixed drinks. Imagine that we have 3 glasses of pineapple juice (the 2p orbitals) and one glass of coconut cream (the 2s orbital), and we have to make four identical mixed drinks ("Coco Coladas"). First we split the glass of coconut cream among 4 new glasses, 1/4 per glass, and then we mix all the pineapple juice in a pitcher and fill the remaining room in each of the four new glasses to the rim. Notice that the number of glasses of mixed drinks (and orbitals as well) must equal the number of glasses of original components before mixing. Additionally, we report the "strength" of the mixture as the ratio of the two components, 1:3 in our case, or sp3 in the case of orbitals; this indicates that the hybrid orbital contains 25% of the s orbital (one part in four). The mixing of one s and three p orbitals creates four sp3 hybrid orbitals that are 109.5° apart, with large front lobes ready to form bonds or hold lone pairs Returning to the orbitals, the mixing does not require any additional investment of energy; the resulting sp3 hybrids have lower energy than the 2p orbitals, but higher energy than the 2s orbital. On average the energy is the same. Each of the four hybrids then overlaps with a 1s orbital on a hydrogen atom, forming the four equivalent σ bonds of methane. The energy released by bond formation more than compensates for the initial investment that was needed to form the excited state (this energy is equivalent to the BDE of the C−H bonds in methane, or 410 kJ/mol for each bond). Figure F09-2-1. Hybridization scheme for the generation of sp3 hybrids. The promotion of one of the 2s electrons to the 2p orbital generates an excited state with four unpaired electrons, followed by the mixing of orbitals to make four equivalent hybrid orbitals. The hybridization affects the energy of the orbitals, and also their shape and orientation. Generally, the mixing of s and p orbitals can be understood in the context of the interference of their wavefunctions. On the side of the p orbital where its sign matches the sign of the s orbital, the waves add, giving a "swollen" large lobe, while on the side where the wave signs are mismatched, the waves subtract, giving a shrunken lobe (F09-2-2). The hybrids will be able to use their large front lobe (large "nose") to better overlap with orbitals on the bonding partners. The small back lobe (small "tail") will point away from the bonding region, and will often be omitted from the pictures for clarity. The hybrids with larger s percentages have bigger noses (they are more spherical) and smaller tails. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 128/250 9/2/2019 Chem 110 Figure F09-2-2. Mixing of s and p orbitals. The lobes of the same sign add, while those of opposite sign subtract, yielding hybrid orbitals of uneven lobes; the shape depends on the amount of s orbital contribution. The relative sizes of lobes can be explored in 3D by selecting the %-s character or by clicking on specific hybrids. The angles between orbitals also change upon mixing. Although it requires some significant trigonometry (which we will skip), it can be shown that the sp3 hybrids are 109.5° apart. The new hybrids can now make σ bonds with hydrogen atoms and form methane with the correct shape. → = Figure F09-2-3. The four atomic orbitals (s and three p) mix to form four hybrid orbitals on carbon (top). The four sp3 hybrids point to the corners of a tetrahedron, with angles between them of 109.5o. When superimposed, the tail lobes are often omitted for clarity (middle right). The hybrids' large lobes overlap with s orbitals of four hydrogen atoms to form four σ bonds (bottom), each holding two electrons (bottom). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 129/250 9/2/2019 Chem 110 The procedure laid out above does not describe the actual reaction that makes methane, but only serves as a model on how the structure of methane can be explained in terms of the valence atomic orbitals that are available on carbon and hydrogen atoms. The geometry of methane is an observable fact; the hybridization procedure is a conceptual model accounting for that geometry. The sp3 hybridization scheme applies to all atoms with 4 electron domains that obey the octet rule. Any such atom with AX4E0, AX3E1, or AX2E2 molecular geometry is indeed sp3 hybridized, even if it does not form 4 bonds. For example, in ammonia the nitrogen atom is sp3 hybridized and its lone pair resides in a sp3 hybrid orbital. In water, oxygen is sp3 hybridized, and both of its lone pairs are held in sp3 hybrid orbitals. (Figure F09-2-4) Figure F09-2-4. Hybridization of nitrogen in ammonia (left) and oxygen in water (right). All lone pairs reside in sp3 hybrid orbitals. The mixing of one s and two p orbitals creates three sp2 hybrid orbitals that are 120° apart, leaving one p orbital unhybridized The BH3 molecule has 3 bonds, 3 electron domains, and its hybridization scheme has to be adjusted accordingly. Since boron's ground state electronic configuration has only one of its three electrons unpaired (Figure F09-2-5), we again have to first promote one electron from the 2s orbital to a 2p orbital to produce an excited state with three unpaired electrons. In this case we need to produce three equivalent hybrids. This can be achieved by mixing the 2s orbital with the two occupied 2p orbitals, leaving one empty 2p orbital behind. This hybridization produces different hybrids than before, with 1:2 ratio of s to p. These are sp2 hybrids, each containing 33% s orbital character. As expected for orbitals with a larger s fraction, they will have bigger front lobes and lower energy than the sp3 hybrids. The overlap of three hybrids with three 1s orbitals on hydrogen atoms generates the three σ bonds of a BH3 molecule. Figure F09-2-5. Hybridization scheme for the generation of sp2 hybrids. The promotion of one of the 2s electrons to the 2p orbital generates an excited state with three unpaired electrons, followed by the mixing of orbitals to make three equivalent hybrids. As before, the hybridization also changes the angle between orbitals. For sp2 hybrids that angle is 120°, matching the bond angles in the trigonal planar molecular geometry of BH3. The new feature in this hybridization type is the presence of the unhybridized atomic p orbital that is perpendicular to the plane containing the three sp2 hybrids. In the BH3 molecule, that p orbital is empty. As we have discussed before, this molecule is unstable, boron has an incomplete octet, and it will react with other molecules that can provide electrons to fill the vacancy. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 130/250 9/2/2019 Chem 110 Figure F09-2-6. The three sp2 hybrids of BH3, and the unhybridized atomic p orbital that is perpendicular to the plane containing the hybrids. The mixing of one p and one s orbital creates two sp hybrid orbitals that are 180° apart, leaving two perpendicular p orbitals unhybridized In a BeH2 molecule, the hybridization is different again, and involves only two orbitals. The ground state Be has two paired 2s electrons (F09-2-6). In the excited state one of them occupies the 2p orbital, and the mixing of 2s and 2p singly occupied orbitals then leads to two sp hybrids. Two empty 2p orbitals do not participate in the hybridization. The s to p ratio in the hybrids is 1:1, resulting in even larger front lobes and lower energy hybrid orbitals (the energy is the average of the energy of the original 2s and 2p orbitals). This is as expected for an orbital with a large s contribution (50%). Figure F09-2-7. Hybridization scheme for the generation of sp hybrids. The promotion of one of the 2s electrons to the 2p orbital generates an excited state with two unpaired electrons, followed by mixing of these orbitals to make two equivalent hybrids. Two unhybridized p orbitals remain empty. The two sp hybrids are 180° apart, and when they form bonds by overlapping with the two 1s hydrogen orbitals the resulting molecular geometry is linear. The two unhybridized p orbitals are perpendicular to the axis of the two hybrids, and to each other (F09-2-8). Figure F09-2-8. The two sp hybrids and the two empty unhybridized atomic p orbitals, perpendicular to the axis containing the sp hybrids. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 131/250 9/2/2019 Chem 110 The number of hybrid orbitals for the three hybridization types matches the number of electron domains for atoms with steric numbers 2, 3, and 4 The three hybridization types (sp, sp2, and sp3) match the linear, trigonal planar, and tetrahedral electron-domain geometries of atoms following the octet rule. This immediately tells us how to decide the hybridization type of an atom in a molecule. It is sufficient to count electron domains around that atom in the Lewis structure and match that number to the number of hybrid orbitals. The steric number determines the number of hybrids needed to form the σ bonds and hold lone pairs; sp hybridization provides two hybrids, sp2 provides three hybrids, and sp3 provides four hybrids. As we have learned, there are also hypervalent atoms with trigonal bipyramidal or octahedral electron pair geometry. The trigonal bipyramidal ED geometry requires 5 hybrid orbitals, and the octahedral geometry calls for 6 hybrid orbitals. We know that only atoms from the third row or below form hypervalent compounds. It would be tempting to include d orbitals to produce the correct number of hybrids, sp3d and sp3d2, respectively. It turns out, however, that d orbitals do not mix well with the s and p orbitals of the same shell (n = 3 or higher) because they have significantly higher energy; that is why there are no 3rd row elements with d electrons in the periodic table. The explanation of bonding in such hypervalent atoms requires a more sophisticated valence bond theory (which is beyond the scope of our presentation), or a model called molecular orbital theory (MO theory); this is briefly covered in the second semester of general chemistry. However, this limitation of VB theory illustrates clearly that models in science are not reality, but only approximations. We use the simplest model that correctly accounts for the structures and properties of interest, but we must be aware that a more sophisticated theory may need to be used, or even invented, when the theory does not explain an experimental observation. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 132/250 9/2/2019 Chem 110 09-3 π bonds π bonds form by sideways overlap of p orbitals on adjacent atoms We have just learned how to identify the hybridization of an atom based on the Lewis structure. Consider for example, ethene (ethylene) in Figure F09-3-1. Both carbons have three electron domains, including two single bond domains and one double bond domain. The steric number of 3 requires an sp2 hybridization type for both carbons. The only difference between carbon and the boron atom that we have discussed previously (F09-2-5) is that carbon has four valence electrons instead of three. That one extra electron resides in the unhybridized p orbital. Figure F09-3-1. Hybridization of carbons in ethene (ethylene) The two carbon atoms have three electron domains each, implying sp2 hybridization. Both sp2 hybridized carbons form two σ bonds to hydrogens by overlapping their sp2 hybrids with a 1s orbital on a hydrogen atom. The third σ bond is the C−C bond, and it is formed by overlapping two sp2 hybrids from the two carbons. (Figure F09-3-2). The two unhybridized p orbitals on the carbon atoms are singly occupied, and can overlap sideways to share their unpaired electrons. This type of overlap generates another type of bond called a π bond. Figure F09-3-2. Formation of σ and π bonds in ethylene. The p orbitals perpendicular to the σ network overlap sideways, forming a π bond. In contrast to σ bonds, the π bond has increased electron density above and below the internuclear axis, but not along the axis itself. The sideways overlap is not as efficient as head-on overlap, and π bonds are generally weaker than σ bonds and in fact do not exist alone (without a σ bond) In a molecule of ethyne (acetylene) each carbon has two electron domains, and therefore both carbons are sp hybridized (Figure F09-3-3). As in BeH2, the sp hybrids on each carbon form σ bonds to hydrogens, and the other two sp hybrids form the C−C σ bond. The two unhybridized p orbitals on each carbon hold one electron each (they were empty in BeH2). As in ethene, the p orbitals can overlap sideways forming π bonds. Since the two sets of p orbitals are 90° to each other (and to the internuclear axis), the two π bonds that are formed lie in two perpendicular planes. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 133/250 9/2/2019 Chem 110 Figure F09-3-3. Hybridization of carbons in ethyne (acetylene). The two carbon-hydrogen bonds and the C−C bond are made using sp hybrids on carbons. The two π bonds are perpendicular to each other and to the C−C axis. σ bonds formed by head-on overlap of atomic or hybrid orbitals exhibit free rotation, whereas π bonds formed by sideways overlap of p orbitals cannot rotate around the internuclear axis We can now generalize our observations about σ and π bonds. Only one of the multiple bonds formed by an atom that follows the octet rule can be σ; the other bonds formed in a double or triple bond must be π bonds. Although all bonds look equivalent in a Lewis structure, we now know that that the multiple lines represent different types of bonds. The σ bonds are made by head-on overlap of various combinations of atomic or hybrid orbitals (F09-3-4), producing increased electron density along the internuclear axis. The electron density in σ bonds has cylindrical symmetry (any perpendicular cross-section is a circle), and rotation around σ bonds does not change the overlap. In general, such rotations are facile, requiring only very small amounts of energy. This so called free-rotation is responsible for the relative orientation of individual central atoms with all their electron domains, and therefore, for the overall shape of multi-central atom molecules. The different shapes are called conformations, and their relative energies depend on repulsions between bonding and nonbonding electron domains on adjacent atoms. The analysis of such interactions is called conformational analysis and it is outside of the scope of our course. Figure F09-3-4. Various orbitals overlapping head-on to make σ bonds. Only the sideways overlap of p orbitals can make π bonds. By contrast, rotation around double bonds does not occur freely at all; it requires breaking of the π bond, which is energetically costly. As we have mentioned, a π bond by itself is weaker than a σ bond, but it still takes a lot of energy to break (above 250 kJ/mol for an average π bond). Double bonds occur frequently with C, N, and O, but not so with larger atoms; σ bonds to larger atoms are longer, making sideways overlap ineffective. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 134/250 9/2/2019 Chem 110 Delocalized electrons in molecules with resonance reside in networks of overlapping π orbitals As an additional exercise, let's see if we can deduce the hybridization of all atoms in the nitrate ion. As you may remember, we can draw three equivalent resonance structures for this anion. (F09-3-5). The green oxygen has four electron domains in the first two structures (I and II), but only three in the third (III), which would require that the green oxygen is sp3 hybridized in I and II, but sp2 hybridized in III. That accounting is against the resonance rules, however. The resonance forms may differ in electron apportionment to different atoms, but since they represent one real molecule, any atom (an oxygen in our case) must have the same electron-domain geometry in all resonance structures. Otherwise, we would have oscillating structures, which is not experimentally observed. Since all oxygens are equivalent, the only way to satisfy the resonance requirement is to have all oxygen atoms be sp2 hybridized. You see that requirement manifest itself in our "average" Lewis structure on the right. A general lesson for us is that hybridization of an atom that holds electrons participating in resonance has to be read from the resonance form wherein that atom has the smallest steric number (smallest number of electron domains). Figure F09-3-5. Resonance structures for the nitrate ion. The average structure with delocalized bonds is marked on the right. If all oxygens and the nitrogen atom in the middle of the nitrate ion are sp2 hybridized, then there is an unhybridized p orbital on each atom of this anion. The p orbitals overlap sideways with each other, resulting in an extended π network through which π electrons can freely move. That π network explains what delocalized electrons are and how are they shared between more than two atoms. Any time a molecule needs resonance structures to adequately represent its electron distribution (i.e. it has delocalized electrons), it has to have delocalized π bonding (a π system built of more than two p orbitals). Any atom contributing a p orbital to that network must be sp2 or sp hybridized. Figure F09-3-6. Each atom in the nitrate ion contributes one p orbital to the π system, which accounts for delocalized electrons. Click on the images for 3D displays. Similar delocalization takes place through the π system of benzene. All carbons are sp2 hybridized, and each provides one p orbital and one π electron to the cyclic π system. That cyclic electron delocalization provides extra stability to the benzene molecule called aromaticity. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 135/250 9/2/2019 Chem 110 Figure F09-3-7. Delocalized π electrons in benzene. Each carbon atom in benzene is sp2 hybridized and contributes one p orbital to the cyclic π system. The cyclic delocalization of π electrons is responsible for the extra stability found in benzene and related molecules. Click on the images for 3D displays. Delocalized electrons in delocalized π systems are modeled better with molecular orbital theory, which is covered in the second semester of general chemistry. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 136/250 9/2/2019 Chem 110 10 Organic Molecules Compounds of carbon constitute the largest group of molecular structures; millions of such compounds are known, some appear in nature, while others are synthesized in industry or in laboratories. The vast array of carbon compounds of various sizes exists due to carbon’s ability to easily form bonds not only to other carbons, but also to any element in the periodic table. Carbon even forms π bonds to nonmetals in the 2nd and 3rd rows of the periodic table. The versatility of carbon manifests itself in the fact that living organisms are made up of carbon compounds, and function by performing chemistry on such compounds. Life itself is organic chemistry. 10-1 Alkanes Alkanes have a general formula of CnH2n+2. They constitute one class of hydrocarbons, compounds built only from hydrogen and carbon. All carbon atoms in alkanes are sp3 hybridized and all bonds are single bonds. Because of the free rotation around the σ bonds, alkanes are flexible and can easily change shape (conformation) in order to minimize repulsions between bonds on adjacent atoms. Alkanes with more than 3 carbons can exist as multiple variants of the same formula with different atom connectivity, called constitutional isomers. As the number of carbons in the formula grows, the number of possible isomers increases rapidly. 10-2 Other hydrocarbons Unsaturated hydrocarbons have on average fewer hydrogen atoms per carbon atom. They are divided into four groups: alkenes, alkynes, aromatics, and cycloalkanes. Alkenes have one or more double bonds and sp2 hybridized carbons. When alkenes contain more than 3 carbons, they can exist as constitutional and stereochemical isomers. The stereochemical isomers, called in this case geometrical isomers, have the same connectivity but different disposition of atoms around the double bond marked as trans and cis. Alkynes have one or more triple bonds and sp hybridized carbons; they have four fewer hydrogens per each triple bond than their saturated analogues. Aromatic hydrocarbons have cyclic π systems built from the p orbitals of sp2 hybridized carbons. The cycloalkanes are examples of unsaturation due to ring formation, which requires the formal removal of two hydrogens. With the exception of cyclopropane (C3H6), all cycloalkane rings are puckered. 10-3 Functional groups Functional groups are individual atoms or groups of atoms of a preset structure that are responsible for the characteristic properties and chemical reactions of a molecule. Members of the same functional group will undergo the same types of reactions with little influence from the hydrocarbon residue to which they are bonded. The common functional groups include alcohols, amines, aldehydes, ketones, and acids and their derivatives (esters and amides). The ability to recognize functional groups allows one to predict the chemical behavior of the compound containing them. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 137/250 9/2/2019 Chem 110 10-1 Alkanes Carbon is special because its atoms can bond to each other and to atoms of other elements to a practically unlimited degree Compounds of carbon have a special place in chemistry. Carbon has 4 valence electrons and forms four bonds in the vast majority of its compounds. Because it is small, it forms short strong bonds both to other carbons and to most other elements, nonmetal and metal alike. It forms double and triple bonds with other carbons and with nonmetals of the second and the third row of the periodic table. There is no other element with such a rich repertoire of bonding arrangements; it is not surprising that nature recruited carbon as the element of life. The main constituents of living matter are carbon compounds of varying complexity, ranging from relatively simple compounds with just a few atoms, such as glycine or glucose (which we discussed earlier), to large and exquisitely intricate compounds containing millions of atoms, such as molecules of DNA (deoxyribonucleic acid), RNA (ribonucleic acid), or proteins. Table T10-1-1. The first eight normal (linear) alkanes. Formula Name CnH2n+2 CH 4 Lewis structure (condensed structure) methane 3D structure (skeletal structures) No. of isomers 1 CH 4 C 2H6 ethane 1 CH 3CH3 C 3H8 propane 1 CH 3CH2CH3 C 4H10 butane 2 CH 3CH2CH2CH3 C 5H12 pentane 3 CH 3CH2CH2CH2CH3 C 6H14 hexane 5 CH 3CH2CH2CH2CH2CH3 C 7H16 heptane 9 CH 3CH2CH2CH2CH2CH2CH3 C 8H18 octane 18 CH 3CH2CH2CH2CH2CH2CH2CH3 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 138/250 9/2/2019 Chem 110 The chemistry of compounds of carbon, called organic chemistry, is a vast sub-discipline of chemistry encompassing petroleum products, polymers (plastics and fibers), pharmaceuticals, pesticides, paints, and a multitude of advanced materials. There are millions of organic compounds known, either found in nature or prepared in industry or the laboratory. In alkanes, the simplest hydrocarbons, carbon and hydrogen atoms are bonded only through single bonds Our introduction to organic chemistry starts with hydrocarbons, which are compounds containing only carbon and hydrogen. They are the simplest, in terms of composition, yet even with just these two elements, there is a rich variety of possible classes and structures. Hydrocarbons are divided into four subgroups including alkanes (compounds containing only single bonds with names ending in "ane"), alkenes (compounds with one or more double bonds with names ending with "ene"), alkynes (compounds with one or more triple bonds with names ending in "yne"), and aromatics (compounds with cyclic π systems). Alkanes have a general formula of CnH2n+2, which can be appreciated by looking at the Lewis structures of compounds with straight chains (normal alkanes) forged from –CH2– units with only the terminal carbons requiring a third hydrogen to close the octet. Table T10-1-1 lists such linear alkanes containing between 1 and 8 carbons. In addition to straight chain alkanes, branched structures are also possible (see below) for compounds with more than 3 carbon atoms. It is often convenient to represent organic molecules in a simplified structure called a skeletal formula (T10-1-1), representing carbon backbone of a compound. The tetravalent nature of carbon allows us to simplify the Lewis structure notation by omitting the redundant hydrogen atoms. In such skeletal formulas each vertex represents a carbon atom, and the number of implied hydrogens on each carbon is such as to assure that it has four bonds. Skeletal formulas are strongly preferred for their clarity. Differently branched alkanes of the same composition are constitutional isomers Branched structures can arise when an alkane has 4 or more carbons in the formula. For C4H10 (butane) it is possible to a have either a straight chain of four carbon atoms, or a chain of 3 carbon atoms with a fourth carbon bonded to the central carbon atom (Table 10-1-2). Such structures are referred to as branched hydrocarbons, since new chains of carbons branch off of the main chain. In both versions of the butane molecule we still need 10 hydrogen atoms to complete the octets on the carbon atoms, so both will have the same molecular formula but different connectivity between atoms. Compounds with the same formula but different structures are called isomers. Specifically, isomers with different atom connectivity are called constitutional isomers. Five-carbon alkanes can exist in 3 isomeric forms, and for C6H14 the number of possible isomers is 5. The number of possible isomers rapidly increases with the number of carbons in the formula (Table 10-1-1); for an alkane with 20 carbons the number of possible isomers is over 366,000! Different isomers have their own systematic names, but some have common names that have been in use for a long time and are deeply entrenched. For systematic names, the longest carbon chain is counted and this number is used as the parent root of the name. Substituents (which are shorter hydrocarbon chains that are called alkyl groups) are indicated by their chain length and position on the main chain, with the counting starting at the end of the chain closest to the branching point. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 139/250 9/2/2019 Chem 110 Table T10-1-2. Isomers of butane, pentane, and hexane (common names are in parentheses) Straight chain (normal) C4H10 butane Branched chains 2-methylpropane (isobutane) C5H12 pentane 2-methylbutane (isopentane) 2,2dimethylpropane (neopentane) C6H14 hexane 2-methylpentane (isohexane) 3-methylpentane 2,3dimethylbutane 2,2dimethylbutane (neohexane) All carbon atoms in alkanes have four electron domains (four bonds) and are tetrahedral, with bond angles very close to the ideal tetrahedral angle of 109.5°. All carbons are sp3 hybridized and all C–C bonds are formed by overlap of sp3 hybrids on adjacent carbons, while all C–H bonds are formed by overlapping sp3 hybrids on carbon with the 1s orbital on hydrogen. The C–C bond lengths are about 154 pm, and the C–H bond lengths are about 110 pm. When drawing skeletal structures, it is customary to show bonds to any carbon linked to four other carbons as solid and broken wedges, accurately illustrating their disposition above and below the plane of the drawing (Table T10-1-2). Free rotation around C‒C bonds affects the overall shape of alkane molecules Since the σ bonds have cylindrical symmetry, there is "free rotation" around all C–C and C–H bonds. While the latter is inconsequential (hydrogens have spherical symmetry), the former affects the overall shape of the molecule, reorienting the individual tetrahedral carbon domains relative to each other in space. Because the energy costs of such rotation are minimal, the different shapes, called conformations, constantly and rapidly interconvert. In general, multiple conformations may be present at room temperature. For example, 77% of hexane molecules exist in one of the conformations shown below (F10-1-1). This point illustrates the flexibility of molecular shapes, as well as the fact that the skeletal structures can be drawn in multiple ways; some of these drawings may not represent the actual shape of the molecule, but may instead favor clarity, if the structures are branched. Figure F10-1-1. Different skeletal drawings of hexane, all representing the same molecule. Usually no conformational information is implied in such drawings (unless the hydrogens are explicitly drawn with solid and broken wedges). Conformations that may approximate the drawings can be viewed in 3D by clicking on the skeletal structures. All these conformations (and all others not pictured) interconvert rapidly at room temperature. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 140/250 9/2/2019 Chem 110 10-2 Other hydrocarbons Hydrocarbons other than alkanes have varying degrees of unsaturation All alkanes have the maximum possible number of hydrogens that a hydrocarbon can have, which is two per each carbon, plus two extra to cap the ends of the chain. Alkanes are called completely saturated. Other classes of hydrocarbons can have fewer hydrogens per carbon, and are formally unsaturated. For example, if two "missing" hydrogens are replaced with a double bond we obtain a hydrocarbon known as an alkene. Alkenes are a class of hydrocarbons containing one or more C–C double bonds. Alkenes have at least one C‒C double bond and may have geometrical isomers in addition to constitutional isomers due to restricted rotation around double bonds Alkenes containing one double bond have a formula of CnH2n, indicating one degree of unsaturation; i.e., two hydrogens less than the corresponding alkane. Some simple examples of alkenes are collected in Figure F10-2-1. In ethylene (C2H4) both carbons have three electron domains and are sp2 hybridized. The un-hybridized p orbitals form a π bond. The bonds are slightly distorted from the canonical values as predicted by VSEPR model. The C–C double bond length of 134 pm is shorter than a C–C single bond (154 pm), which is in agreement with the bond order of 2. Similar geometry is found around all C–C double bonds. Figure F10-2-1.Simple examples of alkenes. The drawing of ethylene (C2H4) illustrates typical bond angles and bond lengths. For butene (C4H8), there are 3 constitutional isomers possible, one of which exists as a pair of geometrical isomers called cis and trans. In the cis isomer the methyl groups marked by the blue arrows are on the same side of the double bond. In the trans isomer the marked methyl substituents are on opposite sides of the double bond. When an alkene contains four carbons, constitutional isomers are possible (F10-2-1). The double bond can be at position 1, as in 1-butene (a terminal alkene) or at position 2 as in two isomeric 2-butenes (internal alkenes). There is also an isomer with a branched chain, 2-methylpropene. The two isomers of 2-butene are of a different type than the constitutional isomers. They have the same atom connectivity, but differ in the spatial (3-dimensional) orientation of the atoms. Such isomers are stereoisomers—specifically, isomers with a differing disposition of substituents on the double bond are called geometrical isomers. In the trans isomer the two methyl substituents on the "ends" of the double bond are on the opposite side, while in the cis isomer they are on the same side (F10-2-1). With a larger number of carbons, or multiple double bonds, the number of possible constitutional and stereochemical isomers both increase rapidly. Alkynes have at least one C‒C triple bond Alkynes are the class of hydrocarbons that have one or more C–C triple bonds. Alkynes containing one triple bond have the formula of CnH2n-2 and are formally referred to as having two degrees of unsaturation (four hydrogens are missing). Some simple examples of alkynes are shown in Figure F10-2-2. In ethyne (C2H2), both carbons are sp hybridized, and as expected with two electron domains, the molecule is linear (180° bond angles). The two unhybridized sets of p orbitals form two π bonds in mutually perpendicular planes. The triple bond so formed (one σ bond and two π) is very short (120 pm). The C–H bonds are also a bit shorter than those in alkanes or alkenes due to improved overlap between the sp hybrids on carbon and the s orbitals on hydrogens. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 141/250 9/2/2019 Chem 110 Figure F10-2-2. Simple examples of alkynes. The drawing of ethyne illustrates typical bond angles and bond lengths. There are two constitutional isomers possible for butyne (C4H6): one has a terminal triple bond (1-butyne) and the other has an internal triple bond (2-butyne). For C4H6 there are two constitutional isomers possible (F10-2-2). With a larger number of carbons, or more than one triple bond, the number of possible constitutional isomers increases. Aromatic compounds contain benzene rings Aromatic compounds constitute another group of unsaturated hydrocarbons; benzene is one that we have already mentioned on several occasions. Its formula of C6H6 indicates that it has four degrees of unsaturation. It would take 8 extra hydrogens to reach the saturated formula of an alkane with the same number of carbons (C6H14). We can easily conclude that the three double bonds account for the three degrees of unsaturation. The ring itself explains the fourth degree of unsaturation; in formally joining the ends of hydrocarbon to form a ring, we lose two hydrogen atoms. Some examples of benzene derivatives are displayed in Figure F10-2-3. In benzene all carbons are sp2 hybridized with trigonal planar geometry. The 6 unhybridized p orbitals (one per carbon) form a delocalized π network, granting extra stability. All C–C bonds are of equal length (140 pm), which is shorter than a single bond (154 pm), but longer than the double bonds (134 pm) in other hydrocarbons. Figure F10-2-3. Aromatic hydrocarbons: benzene and its derivatives. Benzene illustrates the typical C–C and C–H bond lengths and angles found in aromatic hydrocarbons. Cycloalkanes have only single bonds, but are unsaturated because their carbon atoms form rings Having realized that cyclic hydrocarbons are also formally unsaturated, we can take a brief look at a few other possibilities (F10-2-4). Cyclopropane (C3H6), the smallest cyclic hydrocarbon, has apparent C–C bond angles of 60°. The sp3 hybridization of the carbons (containing four single bonds) seems to be inconsistent with such bond angles. A closer analysis (which is beyond the scope of our course) indicates that in this molecule the C–C σ bonds are "bent", i.e. the bonding electron density does not lie along the internuclear axis. The bonding is clearly not conventional in this strained molecule. On the other hand, cyclopentane (C5H10) and cyclohexane (C6H12) have conventional tetrahedral bond angles about carbon. The carbon rings are not flat (with all carbons in one plane) as skeletal structures would indicate, but have puckered conformations, called envelope for cyclopentane and chair for cyclohexane. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 142/250 9/2/2019 Chem 110 Figure F10-2-4. Examples of simple cycloalkanes. Cyclopropane has unusual bent σ bonds between carbons, which explains the apparent 60° angles. Cyclopentane and cyclohexane have puckered shapes. Click on the pictures for 3D models. A summary of hydrocarbons is presented in Table T10-2-1. Click on the name of the example molecule to see and manipulate a 3-D structure. The examples are limited to six-carbon representatives from each group. Table T10-2-1. Hydrocarbon categories and six-carbon examples Hydrocarbon Bonding Example Formula Alkanes hexane single bonds Degree of unsaturation C nH2n+2 0 Cycloalkanes ring cyclohexane C nH2n 1 Alkenes double bond hexene C nH2n 1 Alkynes triple bond hexyne C nH2n−2 2 Aromatic conjugated double bonds in a ring benzene C 6H6 4 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 143/250 9/2/2019 Chem 110 10-3 Functional groups Functional groups have similar chemical properties that are only weakly influenced by other parts of the molecule The hydrogen atoms in hydrocarbons can be substituted with other atoms or groups of atoms called functional groups. A functional group is composed of a discrete atom or a group of atoms with a set structure, and gives an organic molecule its distinctive chemical properties. A given functional group chemically behaves the same way in every molecule, and is only slightly affected by the rest of the molecule (its carbon backbone). Table T10-3-1. Common functional groups Functional group General formula Example Halides ethyl bromide Alcohols ethanol Ethers diethyl ether Amines diethylamine Aldehydes acetaldehyde Ketones acetone Carboxylic acids acetic acid Esters ethyl acetate Amides acetamide https://genchem.science.psu.edu/sites/default/files/filefnlBYE Structure 144/250 9/2/2019 Chem 110 This consistency in chemical properties allows chemists to organize a massive amount of information into manageable patterns. Rather than having to deal with millions of individual and potentially different compounds, we need only to understand and characterize a couple dozens of different functional groups. We will limit our presentation to the listing of the most basic functional groups and some of their characteristics (Table T10-3-1). In our general formulas, R stands for the different hydrocarbon "residues" to which the functional group may be attached. Notice that in skeletal structures hydrogen atoms are always explicitly shown when bonded to non-carbon atoms (so-called heteroatoms) Functional groups typically contain heteroatoms such as halogen, oxygen or nitrogen atoms The groups of molecules in Table T10-3-1 are obtained by bonding a functional group to a hydrocarbon residue R. In halides, a hydrogen atom on the residue is replaced by one of the halogens (F, Cl, Br, or I). Halides are widely commercially used as solvents, flame retardants and refrigerants, in polymer production, and as pharmaceuticals. Alcohols are related to water, where a hydrocarbon residue replaces one of the hydrogens. They can serve as solvents, fuels, or preservatives. Ethanol is "the component" of alcoholic beverages. In an ether, two hydrocarbon residues are bonded to the same oxygen atom. Ethers are commonly used as solvents, and diethyl ether was one of the first anesthetics ever used during surgery. Amines consist of derivatives of ammonia, in which one, two, or three hydrogens are substituted with hydrocarbon residues. They have wide applications in the dye and the pharmaceutical industries and often have unpleasant smells. Amines are weak bases, a property that will become important when we talk about reactions (see C10-3-1). In acid-base reactions, the nitrogen lone pair of an amine can accept a proton, to form an organic ammonium cation. C10-3-1 The remaining functional groups in Table T10-3-1 contain an important subunit called the carbonyl group, which is a carbon atom doubly bonded to an oxygen atom (C=O). In an aldehyde the carbonyl group is bonded to a hydrogen on one side, and an R group on the other. In a ketone, the carbonyl group is bonded to two hydrocarbon residues R which can be the same or different. The last three groups on our list are carboxylic acids (with a carbonyl group bonded to an O–H group on one side and an R group on the other), esters (with a carbonyl bonded to an O–R group on one side and an R group on the other) and amides (with the carbonyl bonded to an NH group on one side and an R group on the other). Formally speaking, the last two are derivatives of carboxylic acids and alcohols or amines, respectively. Carbonyl- containing compounds have interesting characteristics. Formaldehyde (which is the smallest aldehyde) is used in the production of resins; other aldehydes are used in the production of perfumes and flavors. Ketones are very common solvents, and are precursors for pharmaceuticals. Carboxylic acids are important ingredients in the production of polymers and pharmaceuticals and other common substances. In fact, a dilute solution of the carboxylic acid acetic acid (CH3COOH) is commonly known as vinegar. Carboxylic acids are weak acids that partially dissociate in water (C10-4-2). We will learn more about this reaction in future Lessons. C10-3-2 Esters are commonly used as solvents, odorants and fragrances in perfumery and in food. The amide functional group plays an especially important role in biological and polymer chemistry. This functional group is formed when a carboxylic acid and an amine react, linking the residues connected to them. It is utilized in many polymers; nylon and kevlar are among the most well known. In biology this functional group is found in proteins and is referred to as a peptide bond. The specific chemical properties and reactions of the functional groups are a wide-ranging subject covered in separate chemistry courses. Our goal here is much more limited: we want to familiarize you with the concept of functional groups and enable you to recognize the most common ones listed above. To that effect, we provide below three examples of ubiquitous pharmaceuticals and call your attention to the functional groups present in them (F10-3-1). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 145/250 9/2/2019 Chem 110 Figure F10-3-1. Familiar over-the-counter medications with their functional groups identified. The hydrocarbon residues (alkyl or aromatic) are not marked for clarity. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 146/250 9/2/2019 Chem 110 11 Intermolecular Forces In earlier Lessons we learned about atoms as the building blocks of chemistry. It was quickly evident that there are very few substances composed of individual atoms. Most of the time atoms combine to form molecules held together by chemical bonds. In subsequent Lessons we learned about the rules of molecular bonding and structure. Now that we understand the 3-dimensional shapes of individual molecules and can describe their polarity, it is time to broaden the scope of our investigations once more. Except for gases, molecules typically do not exist alone at ambient conditions (300 K and 1 atm), but aggregate to form liquids and solids. The interactions that bring them together are much weaker than the intramolecular bonds responsible for their structural integrity. Still, these forces play a crucial role in determining the properties of bulk materials, which are the properties that we observe in our macroscopic world. In this Lesson we will explore the connection between the molecular structure of a material and the properties it displays for the first time. 11-1 States of matter The vast majority of substances around us exist in one of the three basic states, gas, liquid, or solid. Molecules may transition between these states or phases without any changes to their structure. Liquid and solid phases are called condensed phases, where molecules are held together by various electrostatic intermolecular forces (IMFs). Their mutual attraction is countered by the kinetic energy of their thermal motions, which is proportional to temperature. As the temperature increases, the molecules move more rapidly, and may overcome their mutual attractions and transition from solid to liquid once a certain temperature–called the melting point–is reached. With further increases in temperature all remaining intermolecular forces can be overcome and the molecules transition from the liquid into the gas phase. When that transition happens throughout the liquid the boiling point has been reached. The values of the melting and boiling points serve as indicators of the strength of the intermolecular interactions in solids and liquids, respectively. 11-2 Electrostatic interactions All substances have some type of intermolecular forces (IMFs) acting between neighboring particles. These IMFs are electrostatic by nature, and can occur between particles that have permanent charges, have permanent dipole moments, or have temporary dipole moments induced in them by other particles. The net electrostatic attraction between the particles is the sum of all these forces. The strength of the net electrostatic attraction is determined by the magnitude of interacting charges (full, partial, or induced), and is inversely proportional to the distance between the charges. The magnitude of the attractive interaction is determined by the specific type of IMF, and ranges from 1/d to 1/d6 where d is the distance between the particles. 11-3 Ions and dipoles The strongest interactions involve permanently charged particles, such as the ion-dipole interactions commonly encountered when ions dissolve in polar liquids such as water. Dipole-dipole interactions are another type of intermolecular force, and are common between polar molecules in liquids and solids. 11-4 Dispersion forces Nonpolar substances also have electrostatic intermolecular forces acting between neighboring particles. In this case the source of the interactions are temporary dipoles, which may be induced in nonpolar molecules through interaction with an ion, a dipole, or even another nonpolar molecule in close proximity. These induced dipoles interact with other particles in a manner similar to permanent dipoles. The generation of an instantaneous dipole depends on the susceptibility of a molecule to have its electron cloud distorted; this property is called polarizability. Polarizability increases with the total number of electrons present in the molecule, and also correlates with its size. The intermolecular forces created by such instantaneous dipoles are called London dispersion forces (LDF), and, together with dipole-dipole interactions, are referred to as van der Waals forces. The total sum of all intermolecular forces present dictates the properties of substances in an additive manner. For molecules of similar shapes and sizes, dipole interactions are primarily responsible for any difference in the melting or boiling points. For molecules of varying sizes, dispersion forces usually dominate over the dipole-dipole interactions in determining the properties of a substance. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 147/250 9/2/2019 Chem 110 11-5 Hydrogen bonding Hydrogen bonds are a special type of dipole-dipole interaction; they are stronger than London dispersion forces or other dipole-dipole interactions. Hydrogen bonds form if there are N–H, O–H, or F–H bonds present in the molecules. These three types of bonds are highly polar, with a significant partial positive charge on the almost bare hydrogen nucleus. Because of its small size this hydrogen may approach the lone pairs on atoms of other molecules closely, and interact quite strongly to form a hydrogen bond. Hydrogen bonds are directional, like covalent bonds (although much weaker). They are responsible for the many unique properties of water and are very important in biology and biochemistry. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 148/250 9/2/2019 Chem 110 11-1 States of matter The balance of intermolecular electrostatic attraction and the thermal energy of molecular motions determines the state of matter In previous Lessons we learned a lot about atoms, their electronic structures, and how they bond together to form molecules. These bonds within molecules, called intramolecular forces, hold the molecule together. We have also explored molecular shapes and the polarity of individual structures. Now, we are ready to translate our knowledge of atoms and molecules into an understanding of the directly observable, macroscopic behavior of substances that surround us. We are entering the second stage of our chemical education: finding connections between microscopic (nanoscopic) structures and the physical and chemical properties of "bulk" matter. All particles – ions, molecules and atoms – are susceptible to electrostatic forces. The particles may have permanent charges, dipole moments, or they may acquire instantaneous dipole moments. When they are in close vicinity, opposite charges attract each other. These electrostatic interactions between neighboring molecules or atoms are called intermolecular forces (IMFs); they lower the energy of the system, keeping particles in close contact and aggregating them into bulk materials. Even though the particles in bulk materials are in close contact, the particles are in constant motion. They vibrate or move and collide with each other and with the walls that contain them. In these collisions they transfer and redistribute their kinetic energy. This incessant movement constitutes the thermal energy of the sample. The average kinetic energy of all particles in the sample is directly proportional to its absolute temperature. Only at the absolute zero (expressed in Kelvin, 0 K or –273.15 °C) does all motion and thermal energy vanish. We will develop these ideas more fully in the next Chapter, when we discuss the kinetic molecular theory of gases. Intermolecular attractions and the kinetic energy of thermal motions are "antagonistic," in the sense that the first is keeping the particles in close contact, while the second makes them fly apart. The relative magnitudes of these energies influence the state (or phase) of the sample. In gases thermal motions dominate, and in solids the intermolecular forces prevail, whereas in liquids the thermal motions and intermolecular forces are comparable We are all familiar with the three basic states of matter, gas, liquid, and solid, illustrated in Figure F11-1-1. Figure F11-1-1. The three basic states of matter: gas, liquid and solid. The phase transitions are associated with changes in the thermal energy of the particles. Each of the phases of matter has its own characteristics. In gases, kinetic energy overpowers the energy of the intermolecular interactions. The atoms or molecules have barely any contact with each other (except for very brief collisions). Freed from interactions, the particles move in all directions, going past each other and through any available small openings. Gases flow readily and rapidly and fully fill any container they occupy. They have no shape or volume of their own. The gas particles are widely separated. Since the volume occupied by the molecules is small compared to the total volume of the sample, gases are readily compressible through the application of external pressure. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 149/250 9/2/2019 Chem 110 In liquids, the kinetic energy of thermal motions is comparable in magnitude to the energy of the intermolecular interactions. The molecules constantly interact and electrostatically attract each other; they are closely packed in space. Consequently, liquids are much denser than gases, as the empty space between particles has been largely eliminated. Application of pressure to a liquid sample does not significantly change the volume, (liquids are incompressible). Yet even with the restriction of motion caused by the dense packing, the molecules can move past each other (albeit covering much smaller distances between collisions than gas molecules). As a result, liquids can flow and will assume the shape of their container, but only the portion that they occupy – they do not expand in volume to fill the container. In solids, the intermolecular interactions overpower the kinetic energy of the particles. The particles are "glued" together and held tightly in place by the IMFs. They vibrate in their positions, but move past each other only very slowly and with great difficulty. Solids have their own shapes and volumes and are essentially incompressible. Often, the particles in solids are well organized, forming crystalline patterns or lattices to maximize their intermolecular interactions. Liquids and solids are called condensed phases, as the molecules are tightly packed, with various opportunities for interaction with multiple neighboring molecules. Atoms or molecules transition between phases in response to temperature and pressure changes It is an amazing fact that molecules can transition, unchanged, between the three states. There is no change in the chemical formula of a molecule or the types and numbers of chemical bonds as it undergoes a phase transition. Many substances can exist as any of the three phases within relatively narrow ranges of pressure and temperature. For example, at atmospheric pressure (1 atm), water exists as a solid up to 273 K, as a liquid at higher temperatures (273 373 K) and as a gas above 373 K. Additionally, all three phases can coexist in equilibrium at the so-called triple point (near 273 K and 0.006 atm). Although intermolecular attractions are much weaker than the bonds between atoms that hold molecules intact, they are strong enough to compete with thermal motions and hold molecules together as liquids or solids. Figure F11-1-2. The three states of water. In the solid, the molecules are organized in a repetitive pattern, in the liquid they are in close contact and can move past each other freely, and in the gas they are separated from each other, with very little molecular interactions between them. To illustrate the competition between intermolecular forces and thermal energy, let us describe the changes that would take place on a microscopic level in the heating of a solid. The solid is built of molecules initially at room temperature (around 300 K). If we increase the thermal energy by increasing the temperature, the molecules, on average, will vibrate faster and with larger amplitudes. Eventually, the molecules will gain sufficient energy to break some of the intermolecular attractions to their neighbors, and will break out of the organized pattern of the solid; they will start moving past each other and the solid will turn into a liquid. The temperature at which this happens is called the melting point. Qualitatively, the numerical value of the melting point is a measure of the strength of the molecular interactions in the solid; the stronger the interactions (IMFs), the higher the melting point. Providing more energy to the molecules (now in the liquid phase) increases their kinetic energy further. Some molecules may have enough speed to break free of the remaining intermolecular interactions and escape the liquid to enter the gas or vapor phase. At a certain temperature, called the boiling point, bubbles of the vapor form in the liquid, and all molecules may enter the gas phase (provided there is sufficient thermal energy). The boiling point is the measure of the strength of intermolecular interactions in a liquid: the stronger the interactions, the higher the boiling point. In the gas phase, the molecules are so separated that their intermolecular interactions are no longer significant relative to their kinetic energy. Increasing the temperature further only causes the molecules to move faster and experience more energetic collisions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 150/250 9/2/2019 Chem 110 Let us imagine reversing the order of phase transitions by starting with a substance that is a gas at room temperature. In addition to lowering the temperature, we can also increase the external pressure to bring molecules closer together and increase their intermolecular interactions. If we lower the temperature sufficiently (i.e. remove kinetic energy from the sample) we can liquefy the gas. However, all gases have a so-called critical point (temperature/pressure point), above which the gas cannot be liquefied. In other words, bringing molecules closer by increasing pressure above the critical point temperature is ineffective in making them to aggregate. With further cooling, we can solidify the liquid. This example illustrates that pressure also affects the distance between molecules, and thus affects the strength of their interactions (the closer they are the stronger the IMF). Phase diagrams illustrate phases and phase transitions as a function of temperature and pressure Chemists often use phase diagrams to illustrate how the temperature and pressure affect the state of a sample. A typical phase diagram is shown in Figure F11-1-3. The phase diagrams of different substances have a similar overall "shape,” differing only in some details and in the pressure/temperature ranges of the phases, which is dependent on the strength of the IMFs. Figure F11-1-3. A typical phase diagram. The boundaries between phases correspond to different sets of temperature and pressure at which the two phases are in equilibrium. Every point along these boundaries is a phase transition point, where either melting, boiling, or sublimation take place. At the triple point all three phases are in equilibrium. Above the critical point, the substance is a supercritical fluid. In the plots, solids occupy the region where temperature is low (low kinetic energy) and pressure is high (forcing the molecules closer to each other, which strengthens their interactions), while gases dominate where temperature is high (and they have a lot of kinetic energy) and pressure is low. At low pressures, solids may directly convert into gases (a process called sublimation). Notice that the melting points and boiling points (and sublimation points as well) lie along the boundary lines between phases, and change with pressure. We usually refer to melting and boiling points at 1 atm of pressure as normal. We will discuss the phase diagrams in more detail later in the course. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 151/250 9/2/2019 Chem 110 11-2 Electrostatic interactions Intermolecular interactions are caused by electrostatic forces between ions, dipoles, and induced dipoles All intramolecular and intermolecular forces arise because matter is composed of charged subatomic particles. These interactions are electrostatic in nature, but we must differentiate between the two types of attractions because they differ in magnitude and properties. The bonds between atoms are the intramolecular forces responsible for maintaining the integrity of discrete molecules or extended networks. They are strong, directional (i.e. point from an atom to its bonding partners) and act at short range (the nuclei are short distances from each other). On the other hand, intermolecular forces occur between neighboring molecules; they are generally weaker than chemical bonds, are less directional, and operate at longer range (the nuclei of the interacting particles do not get very close). In fact, we have already learned about the extreme examples of such interactions: ionic bonds. Ion-ion forces are long-ranged and are not directional; ions interact equally strongly with all neighboring ions, as we discovered previously when we examined lattice energies. However, ionic bonds have strengths in the several hundred to several thousand kJ/mol range, and are comparable in strength to covalent or metallic bonds which also have bond strengths on the order of several hundred to a thousand kJ/mol. Ionic bonds are strong because ions with full charges (or even multiple charges) attract each other with energy that is proportional to the charge (Q) and inversely proportional to the distance between them (1/d). Electrostatic interactions also involve non-ionic particles that do not carry full charges. Polar particles have only partial charges associated with their molecular dipole moments (μ). The nonpolar particles depend on induced dipoles for their intermolecular interaction. An induced dipole is an instantaneous temporary dipole moment that results when the electron cloud of a particle is distorted. The ease with which the electron density cloud is distorted is called the polarizability (α). Attractive forces produced by these temporary dipole moments are known as dispersion forces (also called London dispersion forces, or LDFs). The energy of the electrostatic interactions of polar and nonpolar molecules will be much smaller than ion-ion interactions, as the charges involved are of a much smaller magnitude. Even more importantly, this interaction energy is more sensitive to the distance between the interacting partial charges; it is inversely related to the distance raised to a higher power (between 1/d2 and 1/d6, depending on the type of interaction). Typically, the energies of such interactions are, at most, a few dozen kJ/mol, and are often no more than 15% of the strength of intramolecular bonding interactions. The electrostatic intermolecular interactions are summarized in Table T11-2-1. Interactions between electricallyneutral molecules (non-ionic particles) include dispersion forces and dipole-dipole attractions (collectively called van der Waals forces or vdWF), as well as hydrogen bonds, which are a special case of directional dipole-dipole interactions. We will discuss all these forces in detail below. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 152/250 9/2/2019 Chem 110 Table T11-2-1. Types of intermolecular interactions Interactions Energy ion-dipole ∝ Qμ d dipole-dipole μμ ∝ d ion-induced dipole ∝ dipole-induced dipole ∝ dispersion ∝ 3 Qα d 4 μα d 6 αα d hydrogen bonding 2 6 μμ ∝ d 3 Situations Examples Typical strength (kJ/mol) ions in polar liquids Na+/H2O 50 - 200 polar liquids or solids CH3CN(ℓ) or (s) 5 - 25 ions in nonpolar liquids Na+/Ar 3 - 15 nonpolar molecules in polar solvents I2/CH2Cl2 2 - 10 nonpolar liquids or solids N2(ℓ), I2(s) 1 - 40 H bonded to N, O, F H2O(ℓ) 10 - 40 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 153/250 9/2/2019 Chem 110 11-3 Ions and dipoles Ions in solution are stabilized by strong interactions with the dipoles of polar solvent molecules The strongest intermolecular interactions occur when ions interact with polar molecules. The most typical examples of such ion-dipole forces are found in solutions of salts in water. As we will learn in more detail later, ionic solids such as NaCl dissociate into individual ions when they dissolve in water. The positive ions attract the negative ends of the water molecule dipoles, and repel the positive ends. Thus, a sphere of water molecules encloses the cation, with oxygen atoms interacting with the cation (Figure F11-3-1). The negative chloride ions, conversely, attract the positive ends of the water dipoles. The anion is surrounded by H–O bonds of water molecules, forming hydrogen bonds (see Lesson 11-5). Figure F11-3-1. Ion-dipole interactions for Na+ and Cl– ions in water. The cation (left) attracts the negative end of the water dipole (oxygen atom), while the anion (right) is hydrogen-bonded (see below) to H–OH groups. Click on the images to view 3D models. The strength of dipole-dipole interactions depends on the orientation of interacting molecules, and diminishes strongly with increasing intermolecular distances Dipole-dipole interactions are important between polar molecules in both liquids and in solids. These forces depend not only on the magnitude of the molecular dipoles μ, but also on the relative orientations of the dipoles. Figure F11-3-2 illustrates two possible orientations for the dipole-dipole interaction between polar molecules of HCl. The total dipole interaction is averaged over many orientations that result from the constant motion of the particles. The average strength of dipole interactions is on the order of 0.2 kJ/mol, which is very weak when compared to the much larger H–Cl bond dissociation energy of 431 kJ/mol. Since the energy of the dipole-dipole interactions falls off with 1/d3, it is very distancesensitive. For ion-ion interactions, if the distance between ions increases by the factor of two, the interaction energy also decreases by a factor of two. For dipole-dipole interactions, the same change in distance between dipoles leads to an 8fold decrease in the interaction energy. Figure F11-3-2. Dipole-dipole interactions in HCl. Only two of the many possible relative orientations of the dipoles are presented. The bond strength in HCl is 431 kJ/mol. All dipole-dipole interactions, including those shown, are about 0.2 kJ/mol. All dipole-dipole interactions account for only 10% of the total IMFs in liquid HCl. The other 90% are dispersion forces (see the next Lesson). MEP are shown at the full range of electrostatic energy. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 154/250 9/2/2019 Chem 110 This drop-off in energy with distance has even more significance when comparing interactions between polar molecules in the solid and liquid phases. For example, consider how molecules of acetonitrile (CH3CN) fit together in a crystalline solid and in a liquid sample (Figure F11-3-3). In the solid phase the molecules are neatly arranged, with the positively-charged ends of their dipoles (the –CH3 end) close to the negatively-charged ends of the dipoles on nitrogen atoms. This arrangement minimizes positive-positive and negative-negative repulsive interactions. In the liquid phase, the molecules move constantly, rearranging their positions and orientations. There are, on average, more attractive than repulsive interactions, but the molecules are much more disordered and separated (the density of the solid is higher than the density of the liquid). Both of these factors are responsible for weaker intermolecular interactions in the liquid phase. Figure F11-3-3. Acetonitrile (H3C-C≡N:) in the solid and liquid phases. In the solid (left), the molecular dipoles are organized to maximize the attractions between the positive dipole ends (light-blue –CH3) and the negative ends (red N). In solution (right), the thermal motion randomizes the orientations, and although the attractive forces dominate (since they lower the energy), there are also repulsive interactions present. MEP are shown at the full range of electrostatic energy. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 155/250 9/2/2019 Chem 110 11-4 Dispersion forces Nonpolar molecules develop temporary dipoles when approached by ions, dipoles, or even other nonpolar molecules Intermolecular interactions are not limited to charged or polar molecules. Molecules or atoms without a permanent dipole moment can have a temporary dipole moment induced. Intermolecular forces that depend on these induced dipole moments are called London dispersion forces (LDFs) or simply dispersion forces. An induced dipole moment is caused by a temporary shift in the electron cloud density. Even though the electrons are distributed symmetrically in non polar molecules or atoms, the electron cloud symmetry can be perturbed by the presence of an electrical charge in its proximity, such as an approaching ion or a molecule with a permanent dipole. Figure F11-4-1. Induced dipole in a nonpolar species. The approaching Na+ ion polarizes the electron cloud of argon, which induces a temporary dipole in the argon that is attracted to the sodium ion and other cations in the vicinity. When an ion approaches and interacts with a nonpolar species the interaction is due to ion-induced dipole forces. For example, an argon atom has a perfectly spherical electron cloud. If a sodium cation approaches closely, the electrons on argon will be attracted toward it, causing deformation of the electron density (Figure F11-4-1). There will be a slight excess of electron density on the side of the approaching Na+, and a small deficiency on the opposite side of the argon nucleus. A temporary dipole will form on the argon atom, and there will be a net attraction between the two species. The magnitude of this induced dipole will be proportional to the polarizability (α). These attractions will be similar to those previously described between a sodium cation and water, but weaker, because of the smaller magnitudes of such induced dipoles and the inverse dependence of their interaction energy on a higher power of separation distance (1/d4). Both positive and negative charges on ions, as well as dipoles of polar molecules, can polarize nonpolar atoms or molecules generating a temporary dipole. In general, the induced dipoles will track the motion of the polarizing (dipoleinducing) particle, and will disappear when the interacting molecules separate. The individual interactions are weak, and effective only at short range, but are very general and prevalent. Furthermore, no polarizing charge or dipole is necessary to induce an instantaneous dipole moment. Let's consider two helium atoms in close proximity (Figure F11-4-2). On average, they have perfectly spherical electron density, but electrons are in constant motion which can result in both electrons being on the same side of the He nucleus at any one moment in time, yielding an instantaneous, if temporary, asymmetry of the electron distribution. This instantaneous dipole moment can induce a temporary dipole moment in a second He atom, which happens to be in close proximity, and other neighboring atoms will be similarly affected. These transient, fluctuating dipoles attract one another in the same way that permanent dipoles do (see above). The interactions are weaker because the dipoles are smaller, (proportional to the polarizability of the molecule) and the energy dependence on distance is 1/d6. Nevertheless, this type of interaction is sufficient to liquefy helium (which is not very polarizable) if thermal energy is withdrawn by cooling the gas to a low temperature of 4 K. Figure F11-4-2. Dispersion forces in helium. The momentary asymmetry of electrons around neutral helium (green) creates a dipole that polarizes helium atoms in close proximity (rainbow color). The induced dipoles attract each other and polarize more helium atoms. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 156/250 9/2/2019 Chem 110 The attraction forces due to such "self-polarization" are called London dispersion forces (LDF), or just dispersion forces. Their strength depends on the polarizability of atoms or molecules, which can be thought of as the squashiness of the electron cloud; the more polarizable the electron density, the stronger the interactions. In general, the polarizability increases with the number of electrons; heavier and bigger atoms or molecules have stronger dispersion forces than do lighter particles. They have more electrons, and their outermost electrons are farther from the nucleus, and thus are held less tightly. Boiling points are a good measure of the strength of London dispersion forces for nonpolar molecules As we mentioned before, boiling points are a measure of the strength of the intermolecular interactions in liquids. When we compare boiling points of non-polar noble gases and diatomic halogen molecules (Figure F11-4-3), we can easily observe the LDF trends presented above. The boiling points for noble gases increase steadily from helium (4 K) to Xe (166 K), in agreement with the increasing number of electrons (and size), and thus, the increased polarizability. A similar trend is observed among the halogens. The smallest halogen (F2) has the lowest boiling point (85 K) and the largest (I2) has the highest boiling point (458 K). It may be tempting to invoke the high electronegativity of fluorine and expect some "polar" contributions (and an increase in its boiling point), but such logic does not hold; the F2 molecule has no permanent dipole moment (nor does any other dihalogen), and dispersion forces are the only intermolecular interactions present. Figure F11-4-3. As the sizes of noble gas and halogen atoms increase the dispersion forces among the atoms increase, causing the boiling points to increase as well. Cross-group comparison of boiling points provides some additional insight. For example, F2 (18 electrons, MW = 38 g/mol) and Ar (18 electrons, AW = 40 g/mol) have the same number of electrons and very similar masses. Their boiling points are also very similar (85 K vs 87 K). However, Cl2 (34 electrons, MW = 71 g/mol) and Kr (36 electrons, AW = 83 g/mol) have very different boiling points (239 K vs. 121 K). The source of the stronger LDFs in Cl2 is the cylindrical shape of the molecule, which has a greater contact surface than a spherical Kr atom. The chlorine molecules can interact with each other ("touch") over a larger area than Kr atoms can (for comparison, the ratio of the long molecular axis to the atomic sphere diameter is 1.1 for F2/Ar and 1.4 for Cl2/Kr). The same phenomenon is observed for more complex molecules. The boiling points of three isomeric pentanes are 309 K, 301 K, and 283 K for pentane, isopentane, and neopentane, respectively (F11-4-4). The straightchain alkanes are cylindrical in shape and have more potential contact area with their neighbors than the more spherical neopentane; the linear alkanes have stronger LDFs and higher boiling points. The irregularly-shaped isopentane occupies the middle ground. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 157/250 9/2/2019 Chem 110 pentane bp = 309 K isopentane bp = 301 K neopentane bp = 282 K Figure F11-4-4. Dispersion forces in pentanes. The boiling points for nonpolar molecules of the same mass depend on the total area of interaction over which the dipoles may be induced. Cylindrical alkanes such as pentane have a large contact areas, while more compact isomers have limited contact area which reduces to just a "point contact" for nearly spherical neopentane. The same dispersion forces account for the steady increase in the boiling points and melting points of unbranched alkanes (Figure F11-4-5). Hydrocarbons are considered nonpolar, so no significant dipole-dipole interactions are present. However, each added CH2 group adds more electrons than can be polarized and more contact points along the chain that may develop instantaneous dipole moments. Figure F11-4-5. Dispersion forces in linear (unbranched) alkanes. Increasing chain length of the alkanes causes both melting and boiling points to increase. It is important to note that dispersion forces are always attractive, and are found in all substances, charged or uncharged, polar or nonpolar. LDF’s depend on a very shallow penetration of molecular electron clouds. Since molecules have stable and filled valence shells (due to the octet rule), any further interpenetration leads to repulsive forces. These weak attractions are in contrast to bonding interactions (in which octets are completed), which require very substantial overlap and deep interpenetration of atomic or hybrid orbitals. The intermolecular repulsions set the size limits on nonbonding radii that were introduced earlier. The nonbonding distances are known as the van der Waals radii, and represent the distances at which the dispersion and dipole-dipole interactions stop being attractive; this is also the minimum possible distance between molecules in the condensed phase. The space-filling models we have used throughout our lessons represent such molecular sizes. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 158/250 9/2/2019 Chem 110 Dispersion forces always contribute to the intermolecular interactions of uncharged molecules When several kinds of intermolecular forces are present in a substance the effect is additive, and it can be difficult to untangle the relative importance of each one, especially when polar molecules are involved. If the substances to be compared have similar molecular weights and shapes, then the dispersion forces will contribute about equally, and any differences in their total IMFs would be driven by differences in polarity and would manifest themselves by variations in melting points or boiling points. For example, in a series of molecules of very similar shape and almost the same molecular weight, the magnitudes of the dipole moments will dictate the trend of the overall strengths of IMF in action; the more polar molecules will have higher boiling points (F11-4-6). carbon dioxide MW = 44 amu μ=0D bp* = 216 K propane MW = 44 amu μ = 0.1 D bp = 231 K dimethyl ether MW = 46 amu μ = 1.30 D bp = 248 K oxirane MW = 44 amu μ = 1.9 D bp = 284 K acetaldehyde MW = 44 amu μ = 2.7 D bp = 294 K acetonitrile MW = 41 amu μ = 3.9 D bp = 355 K Figure F11-4-6. Comparison of intermolecular forces (IMFs) for molecules with similar dispersion forces but different polarities. All molecules have essentially the same molecular weights and very similar shapes, causing their dispersion forces to be similar. The polarity differences set the trend in their boiling points, with liquids comprised of more polar molecules boiling at higher temperatures (All MEPs are on a common ±200 kJ scale). When molecules differ substantially in size (i.e. molecular weights), then LDF usually dominate the interactions, and the larger molecules will have higher melting or boiling points, even if they are less polar. For example, in the hydrogen halides series shown in Figure F11-4-7, polarity and molecular mass follow opposite trends: the mass increases from H–F to H–I, while the dipole moments drop in the same order, as dictated by differences in electronegativity. Dispersion forces (dependent on size) take precedence, as evidenced by the boiling point ordering except for HF, which has a boiling point that is far too high to simply dismiss as a rare outlier. The reasons for the exceptionally strong IMFs in HF will be discussed in depth in Lesson 11-5. H−F MW = 20 amu μ = 1.83 D bp = 292 K H−Cl MW = 36.5 amu μ = 1.11 D bp = 188 K H−Br MW = 81 amu μ = 0.83 D bp = 207 K H−I MW = 128 amu μ = 0.45 D bp = 239 K Figure F11-4-7. Comparison of the intermolecular forces (IMFs) for molecules with differing polarities and molecular weights. With the exception of HF (see Lesson 11-5), the London dispersion forces dominate the intermolecular interactions. For HCl, HBr, and HI, dispersion forces increase with molecular weight, which goes against the dipole moment trends. (All MEPs are on a common ±100 kJ scale). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 159/250 9/2/2019 Chem 110 11-5 Hydrogen bonding Hydrogen bonds are directional dipole-dipole interactions We have just observed that H–F molecules have intermolecular interactions larger than we would expect given the dispersion forces and dipole-dipole interactions of similar molecules. We can identify more "exceptions" quite readily just by looking at other simple compounds of nonmetals with hydrogen (F11-5-1). The 14th group (4A), hydrides, (compounds of the carbon family with hydrogen) follow the expected trend: their boiling points increase with size, i.e., with increasing dispersion forces. Due to the symmetry of the molecules, polarity does not play any role. The hydrides for groups 15, 16 and 17 (5A, 6A and 7A) with the exception of the first member of each series, also follow this trend. But, water (H2O), ammonia (NH3), and hydrogen fluoride (HF) all show strong deviations; they all have substantially higher boiling points than expected. Figure F11-5-1. Comparison of intermolecular forces (IMFs) in molecules with differing polarities and molecular weights. The boiling points of the hydrides of groups 14, 15, 16, and 17, (4A, 5A, 6A and 7A) increase along with their molecular weights, indicating that London dispersion forces dominate. The exceptional behavior of NH3, H2O and HF is due to hydrogen bonding. The extraordinary deviations from the boiling-point trends observed for NH3, H2O and HF are due to hydrogen bonding, which is a special case of directional dipole-dipole interactions. Hydrogen bonding occurs when a hydrogen atom is bonded directly to one of the highly electronegative atoms N, O, and F. Due to their small size and high electronegativity, their bonds to hydrogen are quite polar. Since hydrogen has no core electrons, there is a significant partial positive charge on the exposed hydrogen nucleus. This positive charge is attracted to the areas with higher electron density, such as lone pairs, on the electronegative atoms in other molecules. Since hydrogen is so small, it can approach the lone pair of the electronegative atom on another molecule quite closely, which increases the strength of the interaction, especially if the approach is along the axis of the lone-pair. Hydrogen bonds are formed when hydrogen atoms bonded to F, O, and N interact with electron pairs on electronegative elements, especially F, O, and N Only electron pairs on the most electronegative neutral atoms (F, O, N) participate in hydrogen bonding, accepting the positively-polarized hydrogen. The capability to form stronger hydrogen bonds increases with the increased electron density on the atom accepting the hydrogen. Thus, the negatively-charged F, O, or N ions form even stronger hydrogen bonds, and anions of other less-electronegative elements (such as halides or sulfides) are also able to accept the hydrogen bonds. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 160/250 9/2/2019 Chem 110 The name of the hydrogen bond denotes both the increased strength of the interactions and its directionality, similar to covalent bonds. Hydrogen bonds are stronger than other dipole-dipole and dispersion forces, (but are weaker than covalent bonds). Typically, their strength is on the order of 5-25 kJ/mol, but in special cases may reach 100 kJ/mol. In the strongest hydrogen bonds, the angle between hydrogen and the two atoms it interacts with is 180°; i.e., the atom holding the hydrogen (the donor), the hydrogen itself, and the atom with the lone pair to which the hydrogen bond is made (the acceptor) are collinear. Figure F11-5-2. Hydrogen bonds and their relative strengths. Hydrogen bonds may form between molecules of one substance (NH3, HF or H2O, top), or between different substances (bottom). The relative strengths depend on the bond dipole (H–N < H–O < H–F), which depends on the electronegativity difference between the atom providing the lone pair (hydrogen-bond acceptor) and the atom accepting the electrons (electron acceptor, in this case hydrogen). More electronegative atoms are more reluctant to share their electrons and produce a larger dipole. Hydrogen bonding dominates the intermolecular interactions of neutral molecules and plays an important role in biological structures and processes Hydrogen bonds are generally stronger than dipole-dipole forces or London dispersion forces, and if present in the substance, they usually provide the largest contribution to intermolecular interaction, resulting in higher melting and boiling points relative to similar compounds lacking hydrogen bonds. Like other intermolecular forces, they are additive; molecules capable of forming multiple hydrogen bonds have dramatically increased intermolecular interactions. Indeed, many of the unique properties of water are directly related to the ability of water molecules to form multiple hydrogen bonds. We previously noted the unusually high melting and boiling points for a substance comprised of molecules of such small size; Solid water (ice) is less dense than the liquid phase, thanks to the highly organized network of hydrogen bonds (four per water molecule) that support a structure with large voids (Figure F11-5-3), which collapse on melting. As a consequence, water expands when it freezes, and ice floats on top of water. Without this property aquatic life would not be able to survive in frozen lakes in the winter. We will return to other unique properties of water when we explore liquids in more depth. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 161/250 9/2/2019 Chem 110 Figure F11-5-3. The structure of ice (two perspectives). With its intricate network of hydrogen bonds (marked in yellow), these ice structures maintain large voids within the solid which results in ice having lower density than liquid water. Click on the image on the right to explore this 96-molecule model in 3D. Because of their relative strength and directionality, hydrogen bonds are extremely important in biology and biochemistry. Proteins, (the key structural elements of living organisms), enzymes (responsible for anabolism and metabolism), receptors (crucial to cell signaling) and DNA (the repository of the genetic code of living organism) all maintain their structures and function because of hydrogen bonding. Life as we know it depends upon hydrogen bonding. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 162/250 9/2/2019 Chem 110 12 Gases In this Lesson we explore the properties of gases. In the gas phase molecules move freely from collision to collision, and the thermal motion (kinetic energy) overpowers the intermolecular interactions. The kinetic molecular theory model (KMT) describes the movement of molecules, and provides the theoretical underpinning for our understanding of the macroscopic properties of gas. 12-1 Kinetic molecular theory The simple kinetic molecular theory model (KMT) assumes that perfectly elastic collisions occur between non-interacting spherical atoms or molecules. It explains that pressure is the result of the force with which the moving particles collide with the walls of the container. Temperature is a measure of the average kinetic energy of the particles. Particles with the average kinetic energy move with a root-mean square speed (urms). The distribution of speeds of the moving particles is determined by the temperature and mass of the particles. For particles of the same mass, molecules move faster and have a larger range of speeds at higher temperatures. At lower temperatures the molecules move slower on average and have a narrower distribution of speeds. At any given temperature, more massive particles move slower and have a narrower range of speeds while smaller particles move faster and have a wider distribution of speeds. 12-2 Effusion and diffusion Effusion (gas escaping through a small hole) and diffusion (the spreading out of gas through space) are measurable properties that are explained well by kinetic molecular theory. The rates of both processes are proportional to the root-mean square speed of the molecules involved, and therefore are inversely proportional to the square root of molecular mass. Effusion or diffusion rates can be used to determine the molecular mass of a gas sample by experimental comparison with a gas of known molecular mass. 12-3 PVT relationships A sample of gas is described by four state variables, pressure (P), volume (V), temperature (T) and the amount of gas particles, usually expressed in moles (n). These variables completely define the state of a gas and dictate its physical experimentally measurable properties. We can explore the relationship between these variables by keeping two variables constant while manipulating the others. Under constant pressure and temperature, the volume of gas is directly proportional to the number of moles (Avogadro's law). At constant temperature and an unchanging number of moles of gas, the pressure is inversely proportional to the volume (Boyle's law). With the pressure and number of moles kept constant, the volume of gas is directly proportional to temperature (Charles's law). All of these PVT relationships can be derived directly from KMT. 12-4 The ideal gas law When we combine the individual PVT relationships, the result is the ideal gas law: PV = nRT, where R represents the gas constant. The ideal gas law can be used to calculate any of the variables of state, given the other values. In this way we can calculate that the volume occupied by one mole of gas at standard temperature and pressure of 1 atm and 0 °C, (STP) is 22.41 L. The ideal gas law may be rearranged to show the relationship between gas density and its molecular mass which can be used to determine the molecular masses of gas molecules. Dalton's law of partial pressures, which states that the individual components of a mixture of gases behave as if they were alone in the container, is another example of the ideal gas law in action. 12-5 Real gases Real gases deviate in behavior from the ideal gas law. These deviations are due to intermolecular forces, which cause a decrease the pressure of the gas, and the actual volume of molecules themselves, which results in a larger value for the total volume of the gas compared to what the ideal gas law predicts. The van der Waals equation is an equation of state that corrects for these deviations using experimentally determined molecular parameters a and b, which are measures of intermolecular interactions and molecular volume, respectively. The smallest deviations from the ideal gas law are observed for small gas molecules (with small molecular volume and weak intermolecular interactions) and at high temperatures (where the thermal motions dominate the intermolecular interactions). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 163/250 9/2/2019 Chem 110 12-6 Atmosphere The Earth’s atmosphere is a mixture of gases, the composition of which is expressed in molar fractions or ppm (parts per million). The density and pressure of the gases diminish exponentially with increasing altitude. The trends in temperature changes also depend on the altitude, but are strongly affected by energy delivered by Sun, and the processes and reactions initiated by arriving photons. The temperature decreases in the troposphere, increases in the stratosphere, decreases in the mesosphere, and increases again in the thermosphere. 12-7 Atmospheric temperature As Sun's energy travels through the atmosphere it gets partially absorbed by gas molecules. In the thermosphere the highest-energy photons are absorbed, leading to formation of ions (photoionization) and high-energy excited states. Eventually, the absorbed energy is converted to kinetic energy so that the temperature increases with increasing altitude in this layer. The ozone cycle is responsible for the increase in temperature with increasing altitude in the stratosphere. In the troposphere, the greenhouse effect traps part of the energy irradiated by Earth's surface, increasing Earth's equilibrium temperature. The atmosphere acts as a filter, protecting life on Earth’s surface from harmful high-energy photons generated by the sun. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 164/250 9/2/2019 Chem 110 12-1 Kinetic molecular theory Gas particles move in straight lines with constant speed between collisions, during which they redistribute and preserve their total kinetic energy As we described in the Chapter 11, all gas particles (atoms or molecules) are in constant motion. They collide with each other and with the walls that contain them; kinetic energy is transferred and redistributed through these collisions. These motions constitute the thermal energy of the sample. Thermal motions play an important part in phase transitions, heat transfer processes, and in the energetics of chemical reactions. To better understand these processes we need a quantitative model that can illuminate how a system of particles behaves and how it responds to changes in temperature and pressure. The kinetic molecular theory (or KMT) of gases provides us with such a model. The assumptions of the kinetic theory are quite simple: 1. Gases consist of a large number of very small particles (molecules or atoms) in constant, random motion. The molecules are separated by distances that are far greater than their sizes. In other words, the total volume of all molecules is negligible compared to the volume of the gas sample. 2. The molecules exert no forces on each other (i.e. there are no intermolecular interactions), and between collisions they move in straight lines with constant velocities. 3. All collisions with other molecules and with the walls of the container are elastic, i.e., no kinetic energy is lost during the collisions. Figure F12-1-1. The gas is a collection of a large number of particles colliding with each other and with the walls. This 2-dimensional model depicts the motion of a collection of helium atoms at 2000 atm and 25 °C. The speed of the particles shown here is 1012 times slower that the actual speed. To lower the pressure to 1 atm, the volume of this box would have to be increased by 2000. We can develop these assumptions mathematically and show that there is a connection between the behavior of gas particles and the experimentally measurable quantities: P, V and T. Based on these simple assumptions a profound understanding of the behavior of all gases is obtained. In the picture that emerges, the gas is a collection of a large number of randomly moving particles (atoms or molecules) constantly colliding with each other and with the walls of the container in elastic collisions. The collisions between particles result in changes to the direction of their movement and their speed, but the average kinetic energy is preserved. Pressure results from collisions of gas particles with the walls of the container In the collisions with the walls the particles rebound and transfer their momentum to the area of the wall (A) with which they collided. The momentum transferred per unit time is equivalent to a force F acting at that area, and the force acting on a given area is defined as pressure (P = F/A). That pressure is directly proportional to the number of particles (N) in the container (the more particles, the more collisions with the walls), inversely proportional to the volume (V) of the container (the smaller the container the more often the particles collide with the walls), directly proportional to the mass (m) of the particles (more massive particles transfer more momentum upon collision), and directly proportional to the square of their average speed (u) (the faster the particle moves, the greater the momentum it transfers to the walls). That average speed is the mean-square average (average of squares) and it is the speed of a particle that has the average kinetic energy. We can write this relationship as shown in equation E12-1-1, where the factor of 1/3 comes from the fact that the speed components along the 3 axis directions (x, y, and z) are equivalent: https://genchem.science.psu.edu/sites/default/files/filefnlBYE 165/250 9/2/2019 Chem 110 1 PV = 3 2 N mur ms E12-1-1 This important first results of KMT means that the pressure of the gas is the result of the collisions of its molecules with the walls of the container. Indeed, there is a simple relationship between the macroscopic variables (P, V) and the unique molecular parameters (the mass of the gas molecules and their mean-square speed). Notice that both sides of the equation above have dimensions of energy. You may recall the PV work term from our early considerations, and observe that the right side is (within a multiplication factor) related to the kinetic energy of the particles (ε = ½mu2). We can combine these ideas. Temperature is a measure of the average kinetic energy of particles Although we have not yet introduced it formally, you may recall the ideal gas law from your previous chemistry studies: PV = nRT. In the ideal gas law n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. We also take into account two other relationships. Avogadro's number NA can be expressed as n/N = 1/NA. The Boltzmann constant kB, which is the per-molecule equivalent of R, can be expressed as kB = R/NA. Substituting these expressions in E12-1-1, we obtain: ϵav = 3 RT = 2 NA 3 2 kB T E12-1-2 This is another major result, as it tells us that temperature is a measure of the average kinetic energy of gas particles. Thus, temperature, that nebulous yet commonly used term, now has a very concrete meaning related to the thermal motions of molecules. Finally, since we are chemists, and we think about masses of molecules in terms of their molecular mass, ℳ (in kg/mol for SI unit consistency), we take into account that Nm/n = ℳ, and find that: 1 RT = 3 2 Mur ms E12-1-3 or − − − − − 3RT ur ms = √ E12-1-4 M Speeds of gas molecules are described by the Maxwell-Boltzmann distribution with the most probable speed being lower than the root-mean-square speed As described above, the root-square-mean speed, urms, is the speed of a particle with the average kinetic energy of the entire sample. This result highlights another important relationship: all particles move faster at higher temperatures, and lighter particles move faster than heavier particles at the same temperature. Though we obtained expressions for the average kinetic energy and average speed (urms) of collections of gas particles (molecules or atoms), individual particles move with different speeds. Individual particles can also change their speeds during collisions, even though momentum is preserved. It is informative to examine the entire distribution of speeds of a sample of N2 molecules at three different temperatures as shown in Figure F12-1-2. This function describing allocations of molecular speeds is called a Maxwell-Boltzmann distribution. Note that the curve is not symmetrical, and trails off at higher molecular speeds. The consequence of this is that the most probable speed ump (the peak maximum) is not equal to the average speed uav (which is shifted to the right). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 166/250 9/2/2019 Chem 110 Figure F12-1-2. The Maxwell-Boltzmann distribution of molecular speed for N2 molecules (ℳ = 0.028 kg/mol) at 100 K, 300 K and 1000 K. The most probable speed, ump, at each temperature corresponds to the peak values (green circles). The average speed uav (light pink circles) is slightly offset to the right, and the root mean square speed urms (black circles) is furthest to the right. Click on "Averages" button to display the average speeds. You may modify the temperature and mass of the gas particles in any plot, or add more gases to the collection. The distributions of speed are a bit like the exam-score distributions we obtain by plotting the number of students receiving each possible exam score. As happens often with exam scores, the distribution of speeds is not symmetrical, and the most probable speed (ump) does not equal the average speed (uav), or the root-mean square speed (urms), but the differences between them are small. The number of particles that are moving at a given range of speeds is proportional to the area under the distribution curve. Therefore, we can see that at a fixed temperature, a small number of particles move very quickly, and a small number of particles move very slowly. Most move at the most probable speed (the peak ump). The speed at the peak maximum increases with temperature. At any temperature the distribution is biased toward the higher speeds (uav > ump), and it grows broader at higher temperatures; this indicates that the range of speed increases with the temperature. Such distributions stress the random nature of thermal motions, which we must treat using statistical methods, with different kinds of averages and means. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 167/250 9/2/2019 Chem 110 12-2 Effusion and diffusion Gas particles with lower masses move faster on average than particles with higher masses Now that we have learned how the speed distribution changes for one gas at different temperatures, (F12-1-2), let’s examine different gases at the same temperature (Figure F12-2-1). Since all gases must have the same average kinetic energy at any given temperature, the bigger molecules (with larger molecular mass ℳ) must have a smaller urms, and vice versa. This same logic applies to the whole speed distribution. The lightest molecules have the highest speeds and the broadest distributions, while the heaviest molecules have the lowest speeds and the narrowest speed distributions. Figure F12-2-1. The Maxwell-Boltzmann distribution of molecular speed for different gas particles (O2, H2O, He, H2) at the same temperature of 300 K. The lightest molecules move the fastest and have the broadest distribution of speeds, while the heaviest are the slowest and have a narrow speed distribution. The most probable speed, ump, for each gas corresponds to the peak value (green circles). The average speed uav (light pink circles) is slightly offset to the right, and the root mean square speed urms (black circles) is furthest to the right. Click on "Averages" button to display the average speeds. You may adjust the molecular mass and temperate or add another gas to your collections of plots. Lighter gas molecules effuse and diffuse faster than the heavier gas molecules The difference in speed distributions for gases with different masses affects how gases behave in two common situations. In effusion, gases escape through a tiny hole; in diffusion, they spread through space or through another substance (a gas, for example). Since both processes depend on the speed of the gas particles, we can predict with confidence that at a set temperature, lighter molecules will effuse or diffuse faster than heavier molecules. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 168/250 9/2/2019 Chem 110 Figure F12-2-2. The effusion of a gas through a pinhole redistributes the gas molecules evenly throughout the volume of the containers (left). Time-lapse photographs of He- and Ar-filled balloons over a 36 h period show how gas effuses out of the balloons. Helium atoms escape the balloon about 3 times faster than Ar atoms. Thomas Graham studied rates of effusion even before the kinetic molecular theory was fully developed. He observed that the ratio of the rates of effusion for two different gases (r1 and r2) is inversely proportional to the square roots of the ratio of their molar masses (ℳ 1 and ℳ 2). Graham’s Law is given in E12-2-1: r1 r2 − − − − M2 = √ M1 E12--2-1 In effusion, the hole is so small that only an individual particle can flow through it without collisions with other molecules. The only way for a particle to get to the other side is to strike the hole exactly, and the probability of this event increases with higher speed. Faster movement means more collisions per second with the wall, and therefore a better chance to hit the target. The rate of effusion should then also be dependent on speed; it is proportional to the root-meansquare speeds, urms (E12-1-6). For two different gases we can write: r1 r2 = ur ms (1) ur ms (2) = − − − − − 3RT √ M1 − − − − − 3RT √ M2 − − − − M2 = √ E12-2-2 M1 The kinetic molecular theory gives the empirical Graham's law a nice mechanistic underpinning; we can understand the inverse relationship of the effusion rate ratios by thinking about how effusion is dependent on speed. Effusion experiments can be used to determine the ratio of the molecular masses of two gases, and if ℳ for one of them is known, the other can be easily calculated. Figure F12-2-3. The diffusion of gases, shown as the mixing of two different gases. With time, the molecules of both gases equally distribute between the two chambers after a hole is opened. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 169/250 9/2/2019 Chem 110 Although Graham's law can also approximate the ratio of the diffusion rates of two gases under identical conditions, diffusion is a bit more complicated than effusion. As gases mix and diffuse into one another there are frequent collisions that affect the paths of traveling particles. A distinguishing feature of diffusion is that it results in mixing or mass transport, without requiring bulk motion. Particles mix through their random thermal motion. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 170/250 9/2/2019 Chem 110 12-3 PVT relationships Gases exert pressure on any surface with which they are in contact A sample of gas is described by four variables: pressure (P), volume (V), temperature (T) and the amount of gas particles, usually expressed in moles (n). These variables completely define the state of a gas and its physical conditions. In the previous section, we explored the kinetic molecular theory of gases. Now we will use this theory to explain the macroscopic behaviors of gases, i.e., the functional dependencies among these four variables. As we have already observed, pressure is defined as the force (F) acting on a given area (A): F P = E12-3-1 A Gases exert pressure on any surface with which they are in contact. That pressure is due to the constant barrage of gas molecules colliding with the surface. Anything that affects the number of collisions per unit time (such as temperature, volume, and number of particles) affects the pressure. The SI unit of pressure is the pascal (1 Pa = 1 N/m2 where N is newtons and m is meters). Pressure can also be described using units of the bar (1 bar = 105 Pa). On Earth’s surface, we are in a very unique position: we live surrounded by a mixture of gases (air) that we call the atmosphere. The atmosphere protects us from damaging energy and high-energy matter particles arriving from our solar neighborhood, is the medium for our weather, and provides the oxygen necessary for us to live. We will explore the atmosphere in greater detail later, but for now we will concentrate on describing atmospheric pressure. Let’s imagine a column of air with a 1 m × 1 m cross-section, stretching from Earth's surface to the outer reaches of our atmosphere (Figure F12-3-1). This column of air has a mass of about 104 kg, and because of the gravitational pull of Earth, it applies a force of F = 104 kg × 9.8 m/s2 to the 1 m2 area, translating into 1 × 105 Pa of pressure. This example attaches a value to atmospheric pressure, but we need to remember that the weight of the air column actually makes the air denser closer to the Earth’s surface, which in turn leads to more collisions per second, which are responsible for the observed pressure. Atmospheric pressure depends on both altitude and the weather, as both of these factors affect air density. Standard atmospheric pressure is taken as a typical pressure at sea level and is defined as 1 atmosphere (1 atm = 1.01325 × 105 Pa = 1.01325 bar). Because the first pressure measurements were made using mercury, pressure is often expressed in mmHg, also called torr (1 atm = 760 mmHg = 760 torr). Figure F12-3-1. Atmospheric pressure. The gravitational pull on gas molecules causes the air density to increase at lower altitude Higher gas density means more collisions per unit time per area and thus higher pressure. Boyle’s law quantifies the relation between volume and pressure of a sample of gas at constant temperature Pressure within a confined container of gas is a bit easier to study than atmospheric pressure. It has long been known that the pressure of a gas is related to its volume. Consequently, many early experiments on gases were directed at probing how the volume of a gas depends on other variables, as volume is relatively easy to measure. Typically, two variables are kept constant while the relationship between the other two is explored; this results in three gas laws: Boyle’s law, Avogadro’s law, and Charles’s law. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 171/250 9/2/2019 Chem 110 Boyle's law describes the relationship between the volume and pressure for a constant number of moles of gas at a constant temperature. The experimental setup used to demonstrate this is shown below in Figure F12-3-2; the volume of the gas is adjusted with a piston, and the pressure is read on a pressure gauge. The results show that there is an inverse relationship between pressure and volume: as the volume of a fixed amount of gas at constant temperature decreases its pressure increases. Figure F12-3-2. Boyle's law experiment measuring the inverse relationship between the volume of a gas and its pressure. The volume is adjusted by pushing the piston down. The temperature and the number of gas particles (n in units of moles) remain constant. The experimental results of Boyle’s law can be connected easily to the predicted behavior of gases using the kinetic molecular theory. At constant temperature the root mean square speed (urms) does not change. Therefore, when the volume is decreased the molecules travel a shorter distance between collisions, and there are more collisions per unit time: the pressure increases with the number of collisions. The data obtained from Boyle’s experiment are usually plotted in one of the two ways shown in Figure F12-3-3: with V as a function of P, or with P as a function of 1/V. Because P and V are inversely proportional, when comparing the same sample of gas at two sets of volume and pressure, or two gases at constant temperature and number of moles of particles, the relationship in Boyle’s law can be written as follows: P1 V1 = P2 V2 E12-3-2 Figure F12-3-3. Boyle's law plots at several temperature values (the temperature is constant for each separate experiment). The volume of the gas is plotted as a function of pressure (left), and as a function of the reciprocal volume (1/V) (right). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 172/250 9/2/2019 Chem 110 Avogadro’s law relates the number of moles of gas to the volume it occupies at constant pressure and temperature Avogadro's law states that under constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of gas (Figure F12-3-4). This law explains how equal volumes of all gases contain the same number of molecules when T and P are held constant, and why the ratios of volumes of reacting gases and their products can be expressed with a simple whole number. It eventually led to the concept of the mole, and the number that we now know as Avogadro's number (NA = 6.02214 × 1023). This relationship between volume and moles can also easily be predicted using kinetic molecular theory (E12-1-1): the mean-square speed is constant at constant T, and if P is also constant, V is directly proportional to N (N is the number of particles, which is proportional to the number of moles, n). If the number of moles of particles in the container increases, the volume must also increase in order to maintain a constant pressure. Figure F12-3-4. Avogadro's law. The same volume of gas at constant temperature and pressure contains the same number of molecules. Since the volume and the number of moles are directly proportional, a plot of V versus n for a gas at constant T and P will be linear with a positive slope, as shown in in Figure F12-3-5. And when comparing two gases 1 and 2 at constant temperature and pressure, the relationship described by Avogadro’s law can be written as follows: n1 V1 = n2 V2 E12-3-3 Figure F12-3-5. Avogadro's law plotted for several values of P with T constant at 273.15 K (0 °C). The volume of gas is directly proportional to the number of moles. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 173/250 9/2/2019 Chem 110 Charles’s law prescribes that a volume of a sample of gas is proportional to the absolute temperature if kept at constant pressure Charles's law states that the volume of a fixed amount of gas, maintained at constant pressure, is directly proportional to the absolute temperature. Kinetic molecular theory accounts for this observed relationship very well, as shown in Figure F12-3-5. As the temperature drops, so does the kinetic energy of the particles (and their average speed). There are fewer collisions per unit time and the collisions are less energetic. Since the number of moles of gas and the pressure must remain constant, the only solution is to shrink the volume occupied by the gas. Figure F12-3-6. Charles's law: the volume of a fixed amount of gas at constant pressure is directly proportional to temperature. Since the volume is directly proportional to temperature, a plot of V versus T (in °C) for a gas at constant P and n will be linear with a positive slope, as shown in in Figure F12-3-7. And when comparing the same sample of gas at two different sets of temperature and volume, or two gases at constant pressure and number of moles of particles, the relationship described by Charles’s law can be written as follows: V1 T1 = V2 E12-3-4 T2 If we examine the Charles’s law plots for a few different constant pressures, we find an interesting phenomenon. As the temperature is lowered, all the lines converge and can be extrapolated to a volume of zero. We cannot actually carry the cooling that far since gases liquefy, but the result still has a profound significance; it means that there is a lowest possible temperature of absolute zero (0 K or −273.15 °C). Figure F12-3-7. Charles's law: the volume of a fixed amount of gas at constant pressure is proportional to temperature. The extrapolated lines converge to zero volume at −273.15 °C, which is absolute zero (0 K). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 174/250 9/2/2019 Chem 110 At absolute zero, the thermal energy of motion vanishes, in agreement with the definition of temperature derived from kinetic molecular theory (E12-1-4). In a way, this gives us an anchor point for the temperature scale. Units of measure, however, are another issue. After all, we do not talk about temperature in terms of average kinetic energy. Instead, temperature is measured indirectly, by measuring a physical property that is linked to changes in the thermal energy, such as liquid thermal expansion (conventional liquid-filled thermometers) or electric conductivity (thermocouple thermometers). Historically, the temperature scales were arbitrarily set by selecting two well-defined thermal states. For example, the Celsius scale is based on the freezing and boiling points of water at 1 atm; the difference in thermometer readings was then divided into 100 degrees. The absolute scale in kelvin uses degrees of the same size as the Celsius scale (T(K) = T(°C) + 273.15). The true power of kinetic molecular theory is its ability to predict the macroscopic properties of gases and their dependence on the variables of state, without even needing to test any specific examples. For instance, how does the pressure of a gas relate to temperature when volume and the number of moles are held constant. An increase in temperature means an increase in the average kinetic energy and urms. Since there is no change in volume, there are more collisions with the walls per unit time, and the collisions are more forceful, increasing the gas pressure. This is one of the reasons that closed gas containers should not be heated, as they may explode. The relationship between the gas pressure and temperature is know as Gay-Lussac's law. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 175/250 9/2/2019 Chem 110 12-4 The ideal gas law The ideal gas law combines all the variables of state into one equation The laws we just examined showed that volume is inversely proportional to pressure (when n and T are held constant), proportional to temperature (when n and p are constant), and proportional to the number of moles (when P and T are invariant). We can combine these relationships into a general law, called the ideal gas law, where R is the gas constant, or proportionality constant. E12-4-1 P V = nRT An ideal gas is defined as any gas that obeys the kinetic molecular theory postulates. Specifically, the volume of molecules must be significantly smaller than the volume occupied by the gas, and the molecules of gas cannot have any intermolecular interactions. Many real gases satisfy these requirements closely enough that the observed parameters differ only slightly (a few percent) from those calculated by the ideal gas law. Table T12-4-1. Values of the gas constant, R The proportionality constant R in E12-4-1 is one of the fundamental physical constants. The value of R depends on the units used for the variables of state, and the most common values and units are collected in Table T12-4-1. The equivalent of the gas constant "per-molecule" is the Boltzmann constant (kB = R/NA). Units Value L·atm/(mol·K) J/(mol·K) cal/(mol·K) m 3·Pa/(mol·K) L·torr/(mol·K) 0.08206 8.314 1.987 8.314 62.36 The molar volume of an ideal gas at standard temperature and pressure is 22.41 liters The ideal gas law is useful in solving for any variable of state when the rest are known. For example, we can find the volume of one mole of gas at 0 °C (273.15 K) under 1 atm of pressure: nRT V = P L ⋅ atm = 1 mol × 0.08206 mol ⋅ K 273.15 K × 1.0 atm = 22.41 L E12-4-2 The conditions of 1 atm and 0 °C are called the standard temperature and pressure (STP), and the volume occupied by one mole of gas under STP conditions is called the molar volume of an ideal gas (VSTP). Many common gases have a VSTP within less than 2% of the ideal gas value (F12-4-1). Figure F12-4-1. STP volumes of some common gases. In many cases the STP molar volumes are very close the ideal gas value, but some gases show substantial deviations (click on the image to see more examples). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 176/250 9/2/2019 Chem 110 Measurements of gas density allow for determination of its molecular mass The ideal gas law can also be related to the density of a gas (d = mass per unit volume) by dividing both sides of E12-4-1 by V and RT and multiplying by ℳ (the molar mass): nM d= PM = V E12-4-3 RT The number of moles multiplied by the molar mass (in g/mol) gives the number of grams of gas, and when divided by the volume of gas it results in the density of the gas. Therefore, the density of a gas is proportional to pressure and molar mass, and inversely proportional to temperature. This relationship can be stated as: M = dRT E12-4-4 P Using this relationship, the molecular mass of an unknown gas can be determined by measuring its density at constant temperature and pressure. To illustrate the method, let’s calculate the molecular mass of air. A flask of a known volume is weighed evacuated (with a vacuum pump), and then refilled with air and weighed again. With the temperature and pressure recorded, the density, and therefore, the molar mass can be calculated (Figure F12-4-2). Figure F12-4-2. At 295 K, a 1 L flask evacuated with a vacuum pump (left) is opened to the air (at 761 mmHg) and weighed again (right). The air inside has a mass of 1.18 g; thus, the gas density is 1.18 g/L. The molar mass of air is then calculated (E12-4-4) to be 28.5 g/mol. Dalton’s Law states that the pressure of a mixture of gases equals the sum of the partial pressures of the components Gases mix without limit, forming homogeneous gas solutions. For ideal gases, there are no intermolecular interactions, and the gases in the mixture should behave independently. We can define the partial pressure of each gas as the pressure that it would exert if it were alone in the container. The partial pressure of each gas in the mixture is related to the total pressure by Dalton's law of partial pressures; the total pressure Pt of a mixture of gases equals the sum of the partial pressures of all component gases. Rearranging the ideal gas law provides the following relationship where nt is the total number of moles of gas in the mixture: RT Pt = P1 + P2 + P3 + ⋯ = nt E12-4-5 V To calculate the total pressure using Dalton’s law, we can consider each gas in the mixture to be an ideal gas. If we have a mixture of three gases we can then write the following: RT P1 = n1 ( RT ) and V P2 = n2 ( RT ) and V P3 = n3 ( ) V In the mixture, all gases are at the same temperature and occupy the same common volume. The total pressure (Pt) is therefore determined by the total number of moles (nt) of all gases present: RT Pt = P1 + P2 + P3 = nt V RT = (n1 + n2 + n3 ) https://genchem.science.psu.edu/sites/default/files/filefnlBYE E12-4-6 V 177/250 9/2/2019 Chem 110 Each gas's contribution to the total pressure depends on its mole fraction in the mixture. In general, mole fractions (X) are defined as the number of moles of a selected component, divided by the total number of moles (X1 = n1/nt). For the first gas we can write: RT P1 Pt n1 V = RT nt = n1 E12-4-7 nt V Rearranging this equation lets us solve for the pressure contributed by the first gas: P1 = ( n1 nt E12-4-8 ) Pt = X1 Pt For example, the mole fraction of N2 in air is XN2 = 0.78 and the mole fraction of O2 is XO2 = 0.21 (the remaining 1% are other gases, which we will neglect). We can say that nitrogen contributes 78% of the atmospheric pressure in the air. Thus. the estimated average molar mass of air (ℳ t) is calculated as follows, which is very close to our experimental determination (F12-4-2): g Mt = X1 M1 + X2 M2 = (0.78 × 28 mol g ) + (0.21 × 32 https://genchem.science.psu.edu/sites/default/files/filefnlBYE mol ) = 28.56 E12-4-9 178/250 9/2/2019 Chem 110 12-5 Real gases Plots of compressibility factors illustrate deviations from ideal gas behavior at high pressures and low temperatures The ideal gas law has its limitations. One way to test the limits of its applicability is to plot PV/RT (called compressibility factor) for one mole of gas over a wide range of pressures. The ideal gas law predicts that PV/RT should equal 1.0 (for 1 mole of gas) for all values of pressure. Real gases deviate from this prediction as shown in Figure (F12-5-1). Figure F12-5-1. Deviations from the ideal gas law for several gases at 300 K (left), and for nitrogen gas at different temperatures (right). For most gases the deviations are quite small at low pressures, but become quite apparent at higher pressures. The magnitude of the deviations also depends on temperature, with smaller deviations observed at higher temperatures. These deviations can be explained by two main factors: real gas molecules have finite sizes, and real gas molecules do interact through intermolecular forces. The volume of the molecules may become a significant part of the total volume, especially at high pressures where the amount of empty space diminishes as the gas particles are forced together. Under high pressures, the value of PV/RT is greater than the expected value of 1 (for example, see H2 or N2 in F12-5-1). At constant temperature and with an unchanging number of moles, this means that the apparent volume of a gas sample is greater than would be predicted by the ideal gas law. The intermolecular attractions affect the pressure. If a molecule about to strike a wall experiences an attraction from a nearby molecule, it will slow down a bit and hit the wall with a smaller impact and less momentum. The intermolecular attractions make the apparent pressure smaller than that predicted by the ideal gas law. The van der Waals equation takes into account molecular volume and intermolecular forces in order to quantify deviations from ideal gas behavior The Dutch physicist Johannes Van der Waals recognized in the late 1800’s that the ideal gas law could be corrected to account for molecular volume and intermolecular attractions. The resultant van der Waals equation is given below: 2 (P + an V 2 ) × (V − nb) = nRT E12-5-1 Van der Waals introduced two parameters specific to each gas: a and b. The pressure term P is adjusted upward by adding a term (containing a) that takes into account the strength of the intermolecular attractions, and encompasses the polarity and polarizability of gas molecules. The attractive IMFs increase proportionally to n2/V2 (the molar density squared) as the probability of collisions between pairs of molecules increases; collisions increase as the molar density of each of the colliding molecules increases. The volume is adjusted downward by subtracting the volume occupied by the molecules, with b describing the molar volume (i.e. the volume occupied by the molecules themselves). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 179/250 9/2/2019 Chem 110 Table T12-5-1. Van der Waals constants for some common gas molecules Gas b a (L2(L/mol) atm/mol2) Ne He H2 H 2O O2 Ar N2 Kr CO 2 CH 4 Xe Cl 2 CCl 4 0.0171 0.0237 0.0266 0.0305 0.0318 0.0322 0.0391 0.0398 0.0427 0.0428 0.0510 0.0562 0.1383 0.211 0.0341 0.244 5.46 1.36 1.34 1.39 2.32 3.59 2.25 4.19 6.49 20.4 The van der Waals constants for various gases are collected in Table T12-5-1. We can consider the values of a in terms of the molecular attractions that we explored previously. London dispersion forces are the only intermolecular forces that are present for atomic noble gases. These gases have small values of a, with He being the least polarizable and having the weakest attractions. The interactions are stronger for polar molecules (H2O) and large molecules (CCl4), which are highly polarizable due to the size of their electron clouds. In fact, carbon tetrachloride is a liquid at STP (it has a boiling point of 77 °C) which is consistent with its large value of a. You may recall that dipole-dipole and dispersion forces are collectively referred to as van der Waals forces. The volume correction (nb) depends not only on the size of the molecules, but also how close they can get together. For atoms (or for molecules approximated as spheres), their van der Waals radii define the closeness of their approach; this is the closest they can come to each other before the repulsive forces start increasing. The discussion above explains how the van der Waals forces and radii made it into our presentation. The constants (a and b) are obtained by measuring the macroscopic prosperities (P, V and T) of real (i.e. non-ideal) gases, yet they provide the insight into the nanoscopic world—into the sizes and interactions of individual molecules. Inversely, kinetic molecular theory allows us to understand the macroscopic trends. For example, we can now readily predict that the smallest deviations from ideal behavior will be found for small molecules with weak intermolecular interactions (He, for example), and the largest deviations will be found for large, polar, or polarizable molecules (like CCl4). The deviations will be smaller at high temperatures (where the thermal motions dominate the attractions), and at low gas densities (where the volume correction is small and there are fewer molecules per volume). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 180/250 9/2/2019 Chem 110 12-6 Atmosphere Earth's atmosphere is a mixture of many gases, with nitrogen and oxygen being the main components The atmosphere is a layer of gases that surrounds a body (a planet, for example) that has sufficient gravitational pull to hold the mass of gases. Earth's atmosphere is a mixture of gases composed mainly of nitrogen (78%) and oxygen (21%) with much smaller fractions of CO2 and noble gases, and traces of other components. The composition of air at sea level is summarized in Table T12-6-1. Water vapor (humidity) is highly variable, depending on weather, and is not included in the summary. T12-6-1. Composition of dry air at sea level Gas Nitrogen (N 2) Oxygen (O 2) Argon (Ar) Carbon dioxide (CO 2) Neon (Ne) Helium (He) Methane (CH 4) Krypton (Kr) Hydrogen (H 2) Nitrous Oxide (N 2O) Xenon (Xe) Content Molar Mass (mole fraction) (g/mol) 0.78084 0.20946 0.00934 0.00039445 0.00001818 0.00000524 0.00000179 0.00000114 0.00000055 0.000000325 0.00000009 28.013 31.998 39.948 44.0099 20.183 4.003 16.043 83.80 2.0159 44.0128 131.3 As you can see in the table, mole fractions are used to describe the composition of air. The mole fraction is the ratio of the moles of the component of interest to the total number of moles. Since most components are present at very small mole fractions, parts per million (ppm) are a convenient way to list these values. If a number was listed as a percent, this would describe how many parts per hundred; a percent is obtained by multiplying the fraction by 102. Similarly, ppm values are obtained by multiplying the molar fraction by 106. For example, Ne is present at 18.18 ppm. This translates to 18.18 × 10−6 for the mole fraction. Indeed, the mole fractions are the measure of the concentration of gases in the gaseous solution (a solution is a mixture that is homogenous on the atomic or molecular level). In gases, when fractions are expressed in ppm, they refer to ratios of volume (for gases under constant T and P, the volume is proportional to the number of moles). In liquid solutions, the units of ppm would refer to ratios of masses. The atmospheric pressure and density decline exponentially with altitude but the temperature decreases or increases in adjacent layers The atmosphere changes with altitude. The density of the gases and the number of collisions per second drop exponentially as altitude increases, and as a consequence, so does the pressure. The temperature also changes as a result of various chemical and physical processes occurring at different altitudes. Reversals in the direction of temperature change serve as the boundaries between different layers (Figure F12-6-1). The troposphere extends up to about 12 km above the surface. In this layer of the atmosphere, temperature drops as altitude increases. Airplanes fly around 10 km above the surface, which would be close to the boundary between the troposphere and the stratosphere. The tallest mountain on Earth (which is Mount Everest at 8.85 km) almost reaches the maximum altitude at which humans can still function (barely) without supplementary oxygen. Note that at the summit the pressure is about 30% of the standard atmospheric pressure, as is the partial pressure of O2. The troposphere contains about 75% of the mass of our atmosphere. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 181/250 9/2/2019 Chem 110 Table T12-6-2. Changes in air properties with increasing altitude. Altitude Density Pressure Collision frequency Temperature (km) 0 5 10 50 100 200 (kg/m 3) 1.28 0.74 0.41 10 −3 10 −7 10 −10 (atm) 1 0.5 0.25 10 −3 10 −6 10 −10 (sec −1) 10 10 5 •10 9 2 •10 9 5 •10 6 10 3 1 (K) 298 256 224 270 200 850 Figure F12-6-1. Regions of the atmosphere showing pressure and density drop at higher altitudes. The inversions of temperature trends creates natural boundaries for different regions(spheres). Above the troposphere is the stratosphere, where the temperature increases with increasing altitude. Above the stratosphere are the mesosphere (where temperature again decreases with increasing altitude) and the thermosphere (where temperature again increases with increasing altitude). Due to density and temperature differences, the gases mix slowly between layers. The change in temperature patterns in the different layers is due to radiation energy and chemical reactions initiated by radiation arriving from our Sun. These reactions are called photochemical reactions, as they are initiated by photons. We will discuss these processes in more detail in the next Lesson. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 182/250 9/2/2019 Chem 110 12-7 Atmospheric temperature Some light energy is absorbed as it travels through the atmosphere towards Earth's surface As we have just learned the temperature of the atmosphere changes with increasing altitude in a non-monotonous way; it decreases in the troposphere, increases in the stratosphere, decreases in the mesosphere, and increases again in the thermosphere (Figure F12-7-1). Indeed, the inversions of temperature trends serve to define the boundaries between the atmospheric layers. This pattern of alternating temperature trends is due to various photochemical reactions and processes initiated by photons arriving from our Sun. Figure F12-7-1. The temperature profile of the atmosphere is given by the purple curve. The names of the regions of the atmosphere are given on the right-hand side of the figure. The boundaries between regions are determined by reversals in the direction of the temperature change with altitude. The black wavy lines indicate the depth of penetration of solar radiation into the atmosphere before it is absorbed. These Sun-energy driven processes are an integral part of Earth's energy balance that controls our climate. We have introduced some of the pertinent basic ideas in the context of our study of electromagnetic radiation and spectroscopy. Now that we have learned about the structure of gas molecules, the properties of gases, and Earth's atmosphere, we can explore the energy conversion processes in more detail. The wavelength distribution of Sun light as it enters the atmosphere is shown in yellow in Figure F12-7-2. About 10% of the energy is delivered in the form of ultraviolet (UV) radiation, 40% enters as visible light, and about 50% is infrared (IR) radiation. Very high energy (X-ray or gamma) and very low energy (radio) photons are a very small fraction (< 1%) of the energy flux. The red curve shows the analogous spectral distribution at sea level. The differences between these distributions is the energy absorbed by the atmosphere which amounts to 19% of the total energy arriving from our Sun. At Earth's surface UV, visible, and IR constitute 3%, 44%, and 53% of the energy delivered, respectively. Thus, our atmosphere acts as a filter, protecting life on Earth’s surface from harmful high-energy photons generated by the sun. While the light travels towards Earth's surface, it interacts with molecules of atmospheric gases; it gets absorbed, and converted to other forms of energy, ultimately ending up as thermal energy (kinetic energy of gas particles). The atmospheric temperature changes depend on how far the energy delivered by Sun is able to penetrate the atmosphere before it is absorbed and what are the available processes leading to the energy conversions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 183/250 9/2/2019 Chem 110 F12-7-2. Distribution of light wavelengths reaching Earth. This plot compares the distribution of solar radiation (i.e. intensity and wavelength) outside the atmosphere (in yellow) to the distribution at sea level (in red). The dips in the red curve marked in blue are the result of the absorption of infrared radiation by water in the atmosphere, the dip marked in green is due to radiation absorbed by atmospheric CO2. Ionization reactions in the thermosphere are the main pathway for converting high-energy radiation into kinetic energy High energy wavelengths (photons with λ < 100 nm) are absorbed at high altitudes (above 80 km) in the thermosphere. At these altitudes the gas density is extremely low and molecular collisions are relatively infrequent (Table T12-6-2). The energetically-dominant processes are direct collisions between photons and gas molecules. If the colliding photons have sufficient energy, photoionization may take place, with the photon ejecting an electron from the molecule to form an ion, as shown in the example of N2 molecules: N 2 + + hν ⟶ N 2 − + e C12-7-1 The energy of the photon (calculated as E = hν = hc/λ) must be equal to or greater than the ionization energy in order for this to happen. This process is analogous to the ionization of atoms. For example, the ionization energy of N2 is 1495 kJ/mol, and we can calculate the maximum wavelength required for this reaction as follows: E = λ= NA hc E12--7-1 λ NA hc = 80 nm 1495 kJ/mol E12-7-2 This calculation indicates that the wavelength of the absorbed radiation has to be below 80 nm in order to initiate photoionization in nitrogen gas. Recall that shorter wavelengths correspond to higher energy photons. Table T12-7-1 collects some photoionization processes that occur in the thermosphere, as well as the maximum wavelength needed for each. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 184/250 9/2/2019 Chem 110 Table T12-7-1. Ionization energies (IE) for processes occurring in the thermosphere Thermosphere process N 2 + hν → N2+ + e− O 2 + hν → O2+ + e− O + hν →O+ + e− NO + hν → NO + + e− IE (kJ/mol) λ max (nm) 1495 1205 1313 890 80.1 99.3 91.2 134.5 λmax is the longest wavelength of photons having sufficient energy to ionize atoms or molecules Molecules may also absorb energy in the same way atoms do: when a photon (with energy equal hν) is absorbed by a molecule, an electron is promoted to a higher-energy molecular orbital, resulting in an excited state (marked with an asterisk). For example, in the case of nitrogen gas in the thermosphere: ∗ N 2 + hν ⟶ N2 C12-7-2 The ions formed in the photoionization processes and the excited state molecules have excess potential energy that is eventually converted to kinetic energy (i.e. heat) upon collisions. Even if these unstable species have a significant atmospheric lifetime because the concentration of gases at this altitude is low (and thus collision frequency is also low), they ultimately collide with other particles; ions recombine with electrons and excited states relax to the ground state. The energy is converted to kinetic energy of translation, vibrations, and rotations, or it is used in chemical reactions. For example, if a nitrogen molecule in an excited state collides with an oxygen molecule in the upper atmosphere, the following reaction can take place: ∗ N2 + O 2 ⟶ N O + O 2 C12-7-3 All these process described above convert the energy of the absorbed photons into thermal energy, increasing the temperature of the gases in the thermosphere. The effect diminishes with diminishing altitude as more and more highenergy photons are absorbed when light travels toward Earth and the density of the atmosphere increases providing more opportunities for absorption. At about 80 km, essentially all high-energy photons (λ < 100 nm) are absorbed: the upper atmosphere's mission to protect life on Earth from being bombarded by dangerous radiation is accomplished! The region below the thermosphere is called the mesosphere. The temperature in the mesosphere decreases with altitude since little or no absorption of solar radiation occurs in this region of the atmosphere. The concentration of gases in the mesosphere is low and chemical reactions requiring collisions between two species are still relatively slow. In addition, high-energy radiation has already been absorbed in the thermosphere. Absorption of UV light is responsible for the warming of the stratosphere The region below the mesosphere is called the stratosphere. The temperature in the stratosphere increases with increasing altitude. This increase in temperature is attributed to the ozone cycle, a process by which ultraviolet (UV) radiation is absorbed as ozone decomposes and reforms in the atmosphere. The concentration of ozone in the atmosphere varies with altitude (like all atmospheric gases) but its concentration peaks in the stratosphere at ~ 10 ppm. Ozone is formed in the stratosphere in a two-step process that begins with the photo decomposition of O2 (see C12-7-4). Photodissociation is the process wherein photon energy is used to break chemical bonds. A molecule of O2 can be broken apart into two oxygen atoms if the energy of the incoming photon is greater than or equal to the bond dissociation energy (495 kJ/mol for O2), absorbing short wavelength UV radiation (λ ≤ 242 nm). O 2 + hν ⟶ O + O C12-7-4 In the second step, an oxygen atom combines with an oxygen molecule to form ozone, O3, which is an allotrope of oxygen; a different physical form (molecular structure) in which an element can exist. Ozone is less stable than O2 by about 142 kJ/mol, and can undergo photodissociation when it absorbs light with λ ≤ 320 nm. O + O 2 ⟶ O 3 https://genchem.science.psu.edu/sites/default/files/filefnlBYE C12-75 185/250 9/2/2019 Chem 110 O 3 + hν ⟶ O 2 + O C12-7-6 By combining the processes in this cycle, we see that two UV photons are absorbed, while all of O2 that decomposes is reformed and all of O3 that forms decomposes. The result of this cycle is conversion of solar UV radiation into heat without changing the concentrations of O2 or O3. This process is responsible for the warming of the stratosphere while absorbing UV light (up to 320 nm). Such wavelengths cause sunburns and skin cancers. The ozone layer filters out a significant amount of the harmful UV light arriving from outer space, diminishing its intensity at the Earth’s surface. The temperature in the troposphere decreases linearly with increasing altitude The troposphere is the region closest to Earth's surface. Most of the light from our Sun, mainly visible light but also some UV light and a large portion of IR radiation passes through the atmosphere and is absorbed by the ground and oceans; it adds up to 51% of the energy arriving from Sun to the edge of the atmosphere. The Earth's surface radiates this heat back out in the form of IR radiation (Figure F12-7-3). However, significant part of this IR radiation is absorbed by so called greenhouse gases that include H2O, CO2, CH4 and O3 in the lower atmosphere. These molecules absorb the radiation energy and send it out in all direction, both downward toward Earth's surface and upward where more molecules absorb it, and repeat the process. The net effect is the "trapping" of energy close to the surface, the so called greenhouse effect. The temperature of the troposphere is greatest at sea level because the Earth's surface is the body emitting IR radiation, and the concentration of the greenhouse gases which absorb it is greatest near sea level. Figure F12-7-3. The distribution of radiation emitted from earth as observed from outside the atmosphere is shown in red. The curve depicts the expected distribution of light that would be emitted by Earth' surface to maintain a stable planetary temperature. The area in yellow corresponds to the light absorbed by atmospheric gases, mainly water, CO2 and methane. The bands above the curve indicate the regions of the spectrum in which each of these molecules absorb significant amounts of energy. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 186/250 9/2/2019 Chem 110 13 Liquids Liquids are an example of a condensed phase, wherein molecules are tightly packed and in constant contact with each other. The strengths of intermolecular interactions between molecules in liquids are comparable to the energy of their thermal motions. Heat exchange with the surroundings, leading to changes in the average kinetic energy, may lead to phase changes. Removal of heat converts liquids into solids, while addition of heat frees the molecules from their mutual interactions as they transition into the gas phase. 13-1 Phase changes The transition from the solid to the liquid phase is called fusion (or melting). It is an endothermic process. The reverse exothermic process is called freezing. The transition from liquid to gas phase is called vaporization; it is an endothermic process. Condensation, the reverse of vaporization, is exothermic. Additionally, solids may directly transition into the gas phase in an endothermic process called sublimation. The reverse exothermic process is called deposition. Each of the transitions is an isothermal process. The heat exchanged with the surroundings during the process is called the enthalpy of the transition. The enthalpy of sublimation (ΔHsub) is the sum of the enthalpies of fusion and vaporization (ΔHfus and ΔHvap). The magnitude of the enthalpy of phase transitions is the same in both directions, but of opposite sign. 13-2 Heating curves The addition of heat to a sample increases its temperature (and its average kinetic energy) until the temperature of a phase transition is reached. The amount of heat required to increase the temperature of a substance by one degree (1 oC or 1 K) is defined as the heat capacity, and can be expressed per mole (as molar heat capacity) or per gram (as specific heat). Each phase of the substance has its own characteristic heat capacity. At the transition point all heat absorbed is used to disrupt intermolecular forces, and the temperature stays constant until all molecules have transitioned to the new phase. Plotting the temperature as a function of heat absorbed yields a heating curve, which illustrates the changes taking place as a sample transitions from phase to phase. The transitions can be run in reverse by cooling the sample. Most often, the heat of vaporization (or conversely the heat given off during condensation) represents the greatest heat exchange with the surroundings, because it is during this process that the majority of intermolecular forces are completely disrupted (or reinstated, in the case of condensation). 13-3 Vapor pressure Some molecules in the liquid phase have sufficient energy to escape into the gas phase even at temperatures below the boiling point. In a closed container at constant temperature, a dynamic equilibrium is reached when the rate of escape into the gas phase equals the rate of return to the liquid phase. At equilibrium, the gas phase exerts a pressure defined as the vapor pressure at that temperature. The equilibrium vapor pressure depends on the strength of the intermolecular interactions present; liquids with weak interactions between molecules have a high vapor pressure and are volatile (they evaporate easily). As temperature increases, the vapor pressure increases. The temperature at which the vapor pressure equals the pressure outside the container is called the boiling point. 13-4 Phase diagrams A plot of the phases and their coexistence curves as a function of temperature and pressure constitutes a phase diagram. The coexistence curves represent conditions at which two phases exist in equilibrium. The intersection point of the three coexistence curves is called the triple point, where all three phases are in equilibrium simultaneously. The liquid-gas coexistence curve ends abruptly at the critical point, above which the liquid and gas phases are indistinguishable and the substance exists as a supercritical fluid. A gas cannot be liquefied at temperatures above its critical point temperature. In the area between the curves only one stable phase may exist. The solid phase occupies the low temperature-high pressure region of the phase diagram, while the gas phase occupies the high temperature-low pressure section; the liquid phase lies in between. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 187/250 9/2/2019 Chem 110 13-5 Properties of liquids The intermolecular interactions between molecules of a substance determine not only the phase at given temperatures and pressures, but also other physical properties. The interactions of molecules within pure substances are called cohesive forces. The interactions of molecules with surfaces with which they come into contact are called adhesive forces. One manifestation of cohesive forces is viscosity, or a resistance to flow, which is related to the ease with which molecules can break some of their intermolecular forces and move past each other. Another manifestation of cohesive forces is surface tension. Molecules on the surface of the liquid have fewer attractions to other molecules and are therefore less stabilized. The liquid tries to minimize its surface area pulling the surface molecules closer together. The balance between cohesive and adhesive forces is what causes mercury to form a convex meniscus in glass containers (stronger cohesion), while water forms a concave meniscus (stronger adhesion). Because of the strong glass-water attraction, molecules of water "climb" the walls of a test tube; the only force holding the liquid in is the force of gravity. This strong adhesion is what causes capillary action in small diameter tubes. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 188/250 9/2/2019 Chem 110 13-1 Phase changes Fusion, vaporization, and sublimation are endothermic processes, whereas freezing, condensation, and deposition are exothermic We have just learned how substances transition from one phase of matter to another, if the average kinetic energy of their molecules changes sufficiently. This change affects the balance between the energy of the intermolecular attractions and the energy of the thermal motions. Thus, if a substance changes its phase, it has to exchange heat with the surroundings. Under conditions of constant pressure, the energy change equals a change in enthalpy (ΔH). The phase transition from solid to liquid, called fusion (or melting) is endothermic as shown in Figure F13-1-1. It requires an increase in the thermal energy of the particles to disrupt the intermolecular forces between them. The amount of energy required to melt a substance is called the enthalpy of fusion (ΔHfus), or sometimes the heat of fusion. We will use the terms "enthalpy" and "heat" interchangeably, as we are going to deal with processes taking place under constant pressure (usually an atmospheric pressure of 1 atm). The amount of heat exchanged in the phase transition is an extensive property of the substance, and it is usually given on a per-mole basis. The transition in the reverse direction, from liquid to solid, is called freezing. It is an exothermic process; the intermolecular attractions gained by organizing the particles into the close-packed arrangement of the solid phase lower the energy of the system. The enthalpy of the process is still called the heat of fusion, except it has a negative algebraic sign in accordance with conventions for exothermic heat transfer. Figure F13-1-1. Enthalpy changes during phase transitions. Melting, vaporization, and sublimation are endothermic (orange). Energy in the form of heat is needed to break the intermolecular attractions between the particles of the system. Freezing, condensation, and deposition are exothermic (green). The increased intermolecular attractions (which are the result of bringing the particles back into increased contact in the condensed phases) lower the energy of the system. The enthalpy of the system increases as we move to the top of the chart, and decreases moving to the bottom The liquid to gas (vapor) transition is called vaporization. It is an endothermic process. The heat required, called the enthalpy of vaporization (ΔHvap), is used to completely break all intermolecular attractions in the substance. The particles are freed from each other, and begin to move as separate entities in the gas phase. The gas phase is the highest-energy phase for any substance. The reverse process is called condensation; particles return to the condensed liquid phase in an exothermic process and intermolecular attractions are restored, lowering the energy of the system. The solid phase can change directly into the gas phase through a process called sublimation. Sublimation is endothermic, as all intermolecular interactions between particles are broken in the transition. The heat exchanged in the process is called the enthalpy of sublimation (ΔHsub). The reverse process is called deposition; since the restored intermolecular interactions lower the energy of the substance, deposition is exothermic. As can be readily appreciated from the graph in Figure F13-1-1, the enthalpy of sublimation is equal to the sum of the enthalpies of fusion and vaporization (ΔHsub = ΔHfus + ΔHvap). As you may recall, enthalpy is a state function and is path-independent. It does not matter whether the solid is converted directly into the gas, or it is first converted into the liquid phase then into the gas; the overall change in the enthalpy of the system must be the same. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 189/250 9/2/2019 Chem 110 The magnitude of the phase change enthalpy (ΔHsub, ΔHfus, or ΔHvap) is an excellent measure of the strength of the intermolecular forces in a substance. Large values indicate strong intermolecular interactions, as shown in Figure F13-1-2. For example, water has strong hydrogen bonds in addition to dipole-dipole and dispersion forces, and so has a larger heat of vaporization than that of butane (with only dispersion forces). Mercury represents a case of metallic bonding, and has a greater heat of fusion and vaporization than any of the non-metallic liquids shown. Examination of the chart also shows that heats of vaporization are bigger than heats of fusion for individual substances. This general trend is due to the fact that fusion is a transition between the solid and liquid condensed phases: the molecules remain in close contact, and only some intermolecular interactions are broken. In the vaporization transition from liquid to gas (or sublimation directly from solid to gas), the molecules have to move from a condensed phase to the gas phase, breaking all intermolecular interactions in the process. These phase changes therefore require more energy to accomplish. Figure F13-1-2. Phase-transition enthalpies for several substances. For each substance, the heat of sublimation is equal to the sum of the heats of fusion and vaporization. Heats of vaporization are larger than heats of fusion. This is because all intermolecular interactions in liquid are broken upon vaporization, but many of the interactions in solids remain after melting since molecules are still in close contact. Heating a sample leads to an increase in temperature until a transition temperature is reached, at which point the heat is used to disrupt intermolecular interactions at constant temperature Let us examine phase changes at the molecular level. When heat is added to a solid, the thermal motions of the particles (atoms, ions, or molecules) increase. Since the particles are densely packed and cannot move far, they instead vibrate faster and with larger amplitudes. This increased average kinetic energy is registered as an increase in the temperature of the solid. At a certain temperature some of the particles have sufficient kinetic energy to break loose from these interactions and start moving past each other. The solid starts to melt. Further addition of heat does not lead to an increase in temperature; instead, the supplied energy is used to break intermolecular attractions throughout the solid. This process of fusion is isothermal, meaning the temperature remains constant until the entire solid has melted; the temperature at which this happens is called the melting point. The melting point is a characteristic property of the pure substance, and it is a measure of the strength of the intermolecular interactions in the solid. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 190/250 9/2/2019 Chem 110 If more heat is added after all of the solid has melted, the temperature of the resulting liquid starts increasing, indicating the growing kinetic energy of the particles. At this point some of the particles close to the surface of the liquid will have enough kinetic energy to escape into the vapor phase. At higher temperatures, even more particles escape and the pressure of the gas above the liquid, called vapor pressure, goes up. In a closed container kept under constant pressure (atmospheric pressure of 1 atm, for example), no particles can leave the system. Some of the particles of the vapor may hit the surface of the liquid and reenter the liquid phase. When the rate of escape is equal to the rate of reentry into the liquid phase, equilibrium is established between the liquid and vapor phases. With increasing temperature, more and more particles move to the vapor phase, and when the vapor pressure in the container reaches the outside pressure, the substance begins to boil. This temperature is called the boiling point, and its value is indicative of the strength of the intermolecular interactions in the liquid. At the boiling point even the particles below the surface have sufficient energy to break their intermolecular attractions and form the vapor. When a liquid changes into a gas there is an immense change in volume (more than 1000-fold for water, for example); bubbles of vapor form throughout the whole liquid and rise to the surface. The temperature of the boiling liquid remains constant until all liquid is transformed into vapor. The energy provided during this phase transition is used to break all of the remaining intermolecular interactions. Finally, when all particles are in the gas phase, providing more heat increases the kinetic energy of the particles, leading to an increase in the temperature of the vapor. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 191/250 9/2/2019 Chem 110 13-2 Heating curves Heat capacity is the amount of heat needed to increase the temperature of a sample by one kelvin Let's explore the phase changes described in the previous section in a quantitative fashion, using water as an example. We will start with 1 mol (18 g) of solid water (ice) at −50 °C, and we want to convert all ice to water vapor (steam) at 150 °C. First, we have to provide enough energy to warm the solid to the temperature at which fusion takes place, which is 0 °C. The amount of heat required to raise the temperature of the ice by 1 K or 1 °C is defined as the heat capacity (given the symbol C) of ice. In fact, for pure substances (like ice) the heat capacity is either called the molar heat capacity (Cm) if given per mole, or the specific heat capacity (Cs), (sometimes just called specific heat) if given for 1 gram of the substance. The amount of heat (q) needed to raise the temperature of n moles or m grams of a substance by a certain number of degrees of temperature is calculated using Equation E13-2-1: q = nCm ΔT = mCs ΔT E13-2-1 In general, each phase of a substance has its own unique Cm, and Cs can be calculated by dividing Cm by the molecular weight. For ice these values are Cm(ice) = 37.6 J/(mol·K) and Cs(ice) = 2.09 J/(g·K). Since we wish to bring our ice sample from −50 °C to 0 °C, the change in temperature is ΔT = 50 °C = 50 K. Using E13-2-1 and the value of Cm(ice) we can calculate that we need 1.88 kJ of heat for this change in temperature. We can observe the temperature change as a function of the heat delivered to our sample in a plot called the heating curve (Figure F13-2-1a). The first line segment (A-B in F13-2-1a) corresponds to heating the sample of ice from −50 °C to 0 °C. An alternative presentation, with temperature as the x variable (Figure F13-2-1b), shows the increasing enthalpy of the sample. The slope of the same A-B segment in F13-2-1b corresponds to Cm, since we are heating exactly one mole of ice in our example. Figure F13-2-1. The heating curve for one mole of water being converted from −50 °C ice to 150 °C steam. Plot on the left (a) presents the changes in the temperature of the sample as a function of added heat, while the plot on the right (b) shows the increasing enthalpy of the sample as a function of the increasing temperature as heat is added. The heat delivered from the surroundings is the heat gained by the sample. The heat of transition is the amount of heat required to change the phase of the sample at the temperature of transition Having heated our sample of ice to 0 °C (point B), fusion begins and the temperature remains constant until the whole sample has melted (B to C in Figure 13-2-1). The heat required to accomplish this process is the heat of fusion, which for water is ΔHfus = 6.02 kJ/mol. In general, the heat q exchanged with the surroundings during a phase transition is calculated using the enthalpy for that specific phase transition (ΔHtrans) in Equation E13-2-2: q = nΔHf us https://genchem.science.psu.edu/sites/default/files/filefnlBYE E13-2-2 192/250 9/2/2019 Chem 110 Since we are melting one mole of ice we can use the heat of fusion for water to calculate that the total heat required from B to C is 6.02 kJ. After all of the solid ice melts, further heating of the liquid water is required to bring it to the boiling point at 100 °C, at which point the next phase transition begins. The heat required to reach the boiling point is now expressed by the heat capacity of liquid water, where Cm(water) = 75.3 J/(mol·K) or Cs(water) = 4.18 J/(g·K), and ΔT = 100 °C = 100 K. Using Equation E13-2-1, the amount of heat required is 7.53 kJ. The heating of water corresponds to segment C-D, and the slope of that segment in F13-2-1b corresponds to the molar heat capacity of water. At 100 °C water boils and the phase transition to vapor takes place. The temperature does not change during the phase transition. We must use the heat of transition, ΔHvap = 40.67 kJ/mol, to calculate the heat required (E13-2-2); 40.67 kJ of heat is needed to evaporate the whole 18 g sample. The vaporization corresponds to segment D-E in Figure F13-21. Finally, the water vapor produced in the last step is heated up to 150 °C, which is our final temperature. The heat capacity of steam is Cm(steam) = 33.1 J/(mol·K) or Cs(steam) = 1.84 J/(g·K), and ΔT = 50 °C = 50 K which allows us to calculate that we need 1.66 kJ of heat to accomplish the final step (E13-2-1). The heat of vaporization is generally the largest energy expenditure when converting a sample in the solid state to one in the gas phase To summarize, we have transferred 1.88 kJ of heat from the surroundings to our sample to warm the ice, 6.02 kJ to melt it, 7.53 kJ to heat the resulting water to the boiling point, 40.67 kJ to vaporize it, and 1.66 kJ to heat the resulting steam to the final temperature. Our total heat expenditures were 57.76 kJ; a large fraction of this energy (70%) was spent on converting the liquid into a gas (this energy corresponds to ΔHvap). The fact that the majority of our applied heat went towards vaporization attests to the very strong intermolecular attractions between water molecules that have to be broken before the molecules can enter the gas phase. Overall, the heat added from the surroundings has converted H2O(s) into H2O(g), increasing the enthalpy of the sample (Figure F13-2-1b). The vapor has higher energy than ice. The heating process can be reversed by cooling the sample. The path followed starts with steam at the right side of Figure F13-2-1, and proceeds along the same path toward ice on the left side. We encounter the heat transfer associated with phase transitions in everyday situations. We cool our drinks by adding ice; the heat needed to melt the ice is taken from the drink, lowering its temperature. In hot weather we sweat, and the evaporating water withdraws heat (needed for evaporation) from our skin, providing a mechanism to regulate our body temperature. Refrigerators cool by withdrawing heat from the food compartment and using it to evaporate liquids with low boiling points (usually under reduced pressure). The resultant gas is then compressed back into a liquid and recycled. There is one final point to consider. If you look back at our phase change diagram (Figure F13-1-1) and compare it to the heating curve (Figure F13-2-1), you may notice that they appear to be inconsistent. The phase change diagram in F13-1-1 is schematic, showing all possible phase transitions, but neither the temperature nor pressure is specified. Thus, the diagram does not take into account the heating or cooling processes required to reach the respective temperatures of phase transitions. In contrast, the heating curve depicts experimental results at a fixed pressure (typically 1 atm). Once we fix the pressure of an experiment, the number and type of possible phase transitions and temperatures at which they occur are also fixed. For diagrams illustrating one substance such as in F13-1-1 or comparisons between substances such as in F13-1-2, the heats of phase transitions (ΔHfus, ΔHvap, and ΔHsub) at standard temperature (298.15 K) are used. These standard heats are obtained by extrapolations from the values measured at the actual temperatures of the transitions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 193/250 9/2/2019 Chem 110 13-3 Vapor pressure Vapor pressure represents a dynamic equilibrium between molecules in the liquid phase and molecules in the gas phase of a substance As we described the molecular view of phase transitions in the previous section, we noted that some molecules close to the liquid’s surface had sufficient kinetic energy to escape into the vapor phase long before the liquid reached the boiling point temperature. The pressure of the vapor phase above the liquid is called the vapor pressure. To describe vapor pressure, let’s consider an example in which we place a sample of liquid in an evacuated empty flask that is held at a constant temperature below the boiling point. At first the inter-phase movement of a small fraction of molecules is mainly from the liquid to the vapor phase. With time, as the number of molecules in the gas phase increases, the return of molecules back to the liquid becomes more probable. Since more energetic molecules have a greater chance to escape into the gas phase, some self-sorting of molecules with various kinetic energies occurs. On average, the gas phase molecules would be expected to have higher kinetic energy than the liquid-phase molecules. As a result of evaporation, the liquid would normally cool down a bit. However, since our experiment is run at constant temperature by providing heat from the surroundings to maintain the temperature, the average kinetic energies of both phases remain the same. Eventually, a dynamic equilibrium is established. Equilibrium is defined as the point in a physical or a chemical process where the forward rate is equal to the reverse rate. In our example, at equilibrium the rate of escape from the liquid phase and the rate of return to the liquid phase are equal. Even if molecules constantly travel between the two phases, at equilibrium the ratio of molecules in the two phases remains constant. Equilibrium vapor pressure has been established within the flask as shown in Figure F13-3-1. Figure F13-3-1. Liquid added to an evacuated flask reaches a dynamic equilibrium with its vapor. The pressure of the vapor pushes up the column of mercury in the side arm allowing for vapor pressure measurement. If the liquid is left in an open container, some of the molecules do not return back to the liquid phase; instead, they diffuse away and equilibrium is never reached. In this case the liquid evaporates, and eventually all of the molecules leave, resulting in an empty container. Liquids that evaporate readily under ambient conditions are called volatile. Volatile substances have higher vapor pressures than non-volatile compounds. Vapor pressure (at a given temperature) and volatility depend on the strength of the intermolecular interactions between liquid-phase molecules. The stronger the interactions, the lower the vapor pressure, and the less volatile the substance. Vapor pressure increases exponentially with temperature Changes in temperature affect the vapor pressure; if we increase the temperature, a larger fraction of molecules gains sufficient speed to escape the surface of the liquid. You should recall that a collection of gas molecules at a given temperature has a characteristic speed distribution. Molecules in liquids have a very similar distribution of speed and kinetic energy; at higher temperatures there are more molecules with a kinetic energy above the threshold value needed to escape the liquid, as shown in Figure F13-3-2. Thus, we expect that the vapor pressure of a liquid will increase with increasing temperature, which is consistent with kinetic molecular theory. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 194/250 9/2/2019 Chem 110 Figure F13-3-2. Distribution of the kinetic energy of liquidphase molecules at two different temperatures. At the higher temperature there are more molecules with sufficient energy to escape the liquid phase. Figure F13-3-3 illustrates several examples where the vapor pressure of each liquid increases with increasing temperature, forming curves with distinct exponential shapes. When the vapor pressure reaches the external pressure the liquid boils, and vapor bubbles form throughout the volume of the liquid. The temperature at which this happens when the external pressure is 1 atm is called the normal boiling point, but a liquid can boil at different temperatures if the external pressure is different from standard atmospheric pressure. For example, water boils at 70 oC at the high altitudes of Mount Everest, or at 120 oC in the average pressure cooker. It takes significantly longer to cook food on Mount Everest since the boiling water has less kinetic energy. On the other hand, the pressure cooker significantly shortens the cooking time. The normal boiling point of each compound in Figure F13-3-3 occurs at the point where its vapor pressure curve crosses the 1-atm line; they increase from left to right. As you may recall, boiling points increase with the strength of intermolecular attractions in liquids. The compounds in F13-3-3 illustrate this relationship very well. The vapor pressure increases with temperature, slowly at first at low temperatures, and then rapidly as the temperature approaches the boiling point of a liquid. The exponential shape of the vapor-pressure curve has its basis in the molecular kinetic theory, wherein the fraction of molecules that have sufficient speed to escape the liquid phase is an exponential function of the temperature. Figure F13-3-3. Vapor pressure as a function of temperature for several substances. Compounds with increasing boiling points follow the trend of increasing intermolecular interactions among the molecules in the liquid. These interactions increase with the sizes of the molecules (increasing the dispersion forces), with their polarity, and with their ability to form hydrogen bonds. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 195/250 9/2/2019 Chem 110 13-4 Phase diagrams Phase diagrams represent pure phases and the boundary lines between them, which meet at the triple point where all three phases coexist at equilibrium We have just explored the equilibrium between the liquid and the gas phase. Similar dynamic equilibria exist between the solid and the liquid phase, and between the solid and the gas phase under some range of temperature and pressure. As we already mentioned, the phases and the equilibria between them are often presented in the form of phase diagrams. A general phase diagram is shown in Figure F13-4-1, with the three major phases and the boundary curves between them as functions of pressure and temperature. This graph is not really a standard 2D plot; it should not be interpreted that pressure is simply a function of temperature, but rather we must imagine it as a "flattened" 3D plot, where the state of the substance is described by the two variables T and P. Figure F13-4-1. A general phase diagram. The colored lines are the coexistence curves. The orange curve between the liquid and gas phase, starting from the triple point and ending at the critical point, represents the P-T relationship predicted by the Clausius-Clapeyron equation. A gas cannot be liquefied at temperatures above its critical point since gas and liquid are no longer distinguishable at these conditions and the supercritical fluid that is formed has properties of both phases. The yellow solid-liquid coexistence curve is typically nearly vertical, and most commonly slants to the right, reflecting higher stability of the solid phase under high pressure. The two coexistence curves cross the third one (the blue solid-gas coexistence curve), at the triple point, where all three phases coexist in equilibrium. In the areas between the curves, only one phase can exist. Crossing the coexistence curves corresponds to a phase transition. The line at 1 atm is drawn because the normal melting and boiling point are located where it crosses the corresponding coexistence curves. We can now recognize that one curve of the diagram (the orange liquid-gas coexistence curve) represents the Clausius-Clapeyron function, and describes the liquid-vapor equilibrium. Crossing this curve corresponds to a phase transition (vaporization or condensation). A similar boundary curve (blue) separates the solid and gas phases. Transitions across this curve correspond to sublimation and deposition. The solid-liquid coexistence curve (yellow) is nearly vertical, and in most cases leans slightly to the right. In general, the denser phase (usually the solid) is more stable at high pressure. Passage across this curve corresponds to melting (fusion) or freezing. The three curves meet at the triple point, where the three phases coexist in equilibrium. Only two phases are in equilibrium along the curves themselves, and only one phase is present in the areas between the curves. The solid phase occupies the upper left corner of the plot (corresponding to high pressure and low temperature). The gas phase occupies the lower right region of the diagram (corresponding to low pressure and high temperature). The liquid phase occupies the center. The crossing point of the 1-atm line with the solid-liquid boundary curve corresponds to the normal melting point. When this curve (yellow line) is nearly vertical it means that melting points are not strongly influenced by pressure. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 196/250 9/2/2019 Chem 110 The intersection of the 1-atm line and the liquid-gas boundary curve represents the normal boiling point. The heavy slant of this boundary indicates that boiling points are strongly dependent on pressure. The liquid-vapor curve ends abruptly at the critical point. At this point, and at pressures and temperatures above this point, the liquid and gas phases are no longer distinguishable, and we are left with a supercritical fluid that has properties of both phases (fluid is a name encompassing both gases and liquids). The highest temperature at which condensation can occur is called the critical temperature. Above this temperature the gas cannot be liquefied, regardless of the pressure applied. The kinetic energy of molecules above this temperature is always greater than any intermolecular attractions; the greater the attractions, the higher the critical temperature. The pressure needed to liquefy a gas at the critical temperature is called the critical pressure. These two values establish the placement of the critical point https://genchem.science.psu.edu/sites/default/files/filefnlBYE 197/250 9/2/2019 Chem 110 The phase diagram for water is atypical, because the solid-liquid coexistence line bends to the left since ice is less dense than water The phase diagram of water differs significantly from most phase diagrams, and is shown in Figure F13-4-2. We use the logarithmic scale for pressure and the linear scale for temperature to better illustrate the ranges of the phase changes. The water phase diagram is anomalous due to its solid-liquid coexistence curve, which slants to the left. This slant indicates that at higher pressures, liquid water is favored as the more stable phase. We know that the denser phase of a substance is more stable under high pressure, and liquid water is indeed denser than ice. The extensive hydrogenbonding network creates voids within ice crystals, and is responsible for its lower density. There are very few substances that show a similar trend in density; most solids are denser than the corresponding liquid. Figure F13-4-2. Phase diagram for water. We use a logarithmic scale for pressure in order to see all phases to the full extent. The normal melting (mp) and boiling point (bp) are found at the intersection of the 1-atm line and the coexistence curves. Water has a triple point at a temperature very close to 0 °C, but at a low pressure (0.006 atm). At pressures below that of the triple point, there is an equilibrium established between the solid and gas phases. This property of water is often used to freeze-dry various materials. The water is removed by sublimation at low pressure. The advantage of this method is that the materials do not have to be heated to remove the water, thus protecting the integrity of any heatsensitive components (for example nutrients or medicines present in the substance). The 1-atm line crosses the solidliquid boundary at 0 °C and the liquid-gas coexistence curve at 100 °C; these are the familiar normal melting and boiling points of water, respectively. No liquid phase is observed in the phase diagram for carbon dioxide at ambient pressure, because the triple point lies above atmospheric pressure For most substances, including water, the 1-atm line lies between the pressures of the triple and the critical points. For such substances, all three phases can be observed at normal pressure by changing the temperature. There are some substances for which the triple point is above the 1-atm line, including carbon dioxide (CO2). The phase diagram of CO2 is shown in Figure F13-4-3. In such substances, only the solid and the gas phase are observed under atmospheric pressure. Solid CO2 is called dry ice, and sublimes at −78 °C at 1 atm; it transitions directly into the gas phase without an intermediate liquid, thereby justifying its name. Figure F13-4-3. Phase diagram for CO2. We use a logarithmic scale for pressure in order to see all phases to the full extent. The 1-atm line shows that CO2 can only exist as a solid or a gas at this pressure, and the sublimation point (sp) is −78 °C (195 K). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 198/250 9/2/2019 Chem 110 Carbon dioxide has an additional interesting property; its critical point occurs at an accessible temperature and pressure, under conditions that do not result in too much expense. Therefore supercritical CO2 can be produced at a reasonable cost, and used as a convenient nontoxic solvent. One common use is to extract the caffeine from coffee beans. After dissolving the caffeine in the supercritical liquid, the solvent is removed by simply lowering the pressure and converting the CO2 back to the gas phase. The gas can then be compressed and reused, leaving the extracted caffeine behind. Many substances have multiple versions of the solid phase under different pressures. For example, there are at least 9 different forms of ice. In addition, some liquid phases may exist in more than one form; liquid crystals exhibit a different ordering of molecules in the liquid phase. Some of these interesting variations will be explored in the secondsemester of general chemistry. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 199/250 9/2/2019 Chem 110 13-5 Properties of liquids Viscosity is a reflection of the strength of the cohesive forces that provide resistance to flow The intermolecular attraction forces that make molecules of one substance stick together are called cohesive forces. They are an intrinsic property of a substance that find their source in the electronic structure and shapes of the molecules. We have explored many liquid properties that depend on the strength of such cohesive forces, such as vapor pressure, boiling points, or ΔHvap. Intermolecular forces in liquids are not only apparent in phase transitions; another commonly encountered manifestation of cohesive forces is viscosity. Viscosity is a measure of resistance to flow, and is usually measured in kg/m·s. Some liquids such as water or gasoline flow easily, while others, such as glycerin (F13-5-1) or molasses, flow very slowly. Indeed, the viscosity of molasses is so high that it is often used to describe sluggishness (“as slow as molasses”). Viscosity is related to the ease with which molecules can move past each other. Molecules with elongated shapes and multiple contact areas for interactions become entangled and slip past each other slowly. In general, viscosity decreases with increasing temperature for a given substance; the increased kinetic energy facilitates the breaking of intermolecular interactions. Figure F13-5-1. Relative viscosity of glycerin (left cylinder) and water (right cylinder). The glycerin molecules have strong intermolecular interactions (multiple hydrogen bonds), making it difficult for one molecule to slip past another. The falling marble is slowed down by the slow motions of molecules getting out of the way. Surface tension results from minimization of the surface area of a liquid, since the strongest cohesive forces exist in the bulk Another manifestation of cohesive forces is surface tension which is a measure of the energy needed to create the surface area of a liquid. Molecules on the surface of a liquid have fewer partners to interact with than molecules below the surface. The surface molecules are exposed to air (or other gases), with which they have no interactions of any significance. Compared to the molecules in the bulk sample, the surface molecules have higher energy since they are not stabilized by as many intermolecular interactions and are attracted inwards the liquid. To minimize this excess energy, the system will respond by minimizing the surface area, resulting in a lower number of molecules with less than optimal interactions. The end result is the formation of a sort of "flexible skin" on the surface of the liquid. You may have seen a water strider or another insect walking on water (F13-5-2) and utilizing surface tension. The same phenomenon is responsible for the formation of nearly perfect spherical droplets by many liquids with strong intermolecular interactions; this includes water (which has strong hydrogen bonding) and mercury (which has metallic bonding). Of all shapes, the sphere has the smallest surface to volume ratio, so spherical droplet formation minimizes the number of molecules on the surface. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 200/250 9/2/2019 Chem 110 Figure F13-5-2. Surface tension. The molecules at the surface of the liquid are attracted inwards and experience fewer intermolecular attractions when they are exposed to gas-phase molecules instead of liquid-phase molecules. These surface molecules are less stable, so the system tries to minimize the number of such molecules by adopting the shape that has the smallest surface area. This creates a flexible "skin" on which a water strider can move efficiently, without getting wet. The capillary effect and menisci depend on the balance of cohesive forces within the liquid and adhesive forces between the liquid and the surrounding solid surfaces Often, the properties of a substance depend on the balance between the cohesive forces and the adhesive forces. Adhesive forces are interactions of molecules with surfaces with which they come into contact. Consider the menisci of water and mercury in a glass test tube, as shown in Figure F13-5-3. Water forms a concave meniscus, and its surface curves downward. The intermolecular interactions between water molecules are weaker than the interactions between water molecules and the glass surface of the tube, so the adhesive forces are stronger than the cohesive forces. The system tries to maximize the stronger interactions by increasing its contact surface. Molecules of water cling to the walls of the test tube as far up as possible; the only force holding the liquid in is gravity. In contrast, mercury forms a convex meniscus, with an upward-curved surface. The cohesive forces within mercury are metallic bonds, which are stronger than the adhesive forces between mercury and glass. This system tries to minimize the contact surface, and the molecules avoid interacting with the walls of the test tube as much as possible. Similarly, water spreads out on a piece of glass, wetting the whole surface and maximizing the adhesive forces, while mercury on glass stays beaded in the form of spherical droplets flattened by gravity. Figure F13-5-3. Menisci of mercury and water (click on a picture for alternative view). In mercury the cohesive forces (weak metallic bonds) are stronger than the adhesive forces to glass causing mercury to minimize contact with the glass while maximizing intermolecular interactions within the liquid. As a result a convex meniscus forms. Water’s adhesive forces with glass are stronger than its cohesive forces. Water maximizes its area of contact with glass, climbing the walls and forming a concave meniscus. In narrow tubes, these adhesive forces give rise to capillary action, wherein a column of water can climb the tube until the attraction is overpowered by gravitational forces. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 201/250 9/2/2019 Chem 110 The balance between adhesive and cohesive forces determines the behavior of two substances when they come into contact. The adhesive forces between water and glass are strong enough that in glass tubes of small diameter (called capillary tubes) the water can climb to substantial heights, until gravity balances the increased attraction (F13-5-3). Such capillary action is partially responsible for delivering water and nutrients to the upper parts of plants and trees. The narrow tube walls in plants (xylem) have surfaces containing organic compounds with large numbers of −OH groups and oxygen atoms that form hydrogen bonds with water molecules, increasing the adhesive forces. The counterbalance of cohesive and adhesive forces determines surface interactions between immiscible liquids or liquids and solids Adhesive and cohesive forces also affect whether spherical droplets are formed, or a substance spreads out into a thin layer when coming into contact with another substance. When water droplets are introduced onto the surface of oil, they remain droplets (F13-5-4); the cohesive forces within water are stronger than the adhesive forces of water with the hydrocarbon molecules of the oil. Another example of this balance of forces is the beading of rain droplets on a freshly waxed car (wax often contains long hydrocarbon chains). In contrast, oil droplets placed on the surface of water spread evenly over the whole surface. In this case the cohesive forces within oil are weaker than water-oil adhesive forces.The relative strengths of adhesive and cohesive forces are of paramount importance when making glue (strong adhesion required), or non-stick surfaces (weak adhesion needed). Figure F13-5-4. From left to right: (a) Beading of water droplets in oil. The water's cohesive forces are stronger than any water-oil adhesive forces. Water droplets minimize their contact area with oil by remaining spherical. Only when the droplets touch the glass at the bottom of the dish do they start to spread out (water-glass adhesive forces are stronger than water-water cohesive forces). (b) Spreading of oil on water. The oil-oil cohesive forces are weaker than the oil-water adhesive forces. The spreading oil pushes away the small speck of camphor (or pepper powder ) floating on the water's surface. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 202/250 9/2/2019 Chem 110 14 Solutions As we’ve just explored pure substances, let’s now turn our attention to mixtures. Homogenous mixtures composed of only one phase are called solutions. The major component of the mixture is called the solvent, while the minor components are called solutes. Solutions may be solids, liquids or gases. Liquid solutions, and especially aqueous solutions, are most prevalent. Solutions have physical properties distinct from both the solvent and the solutes alone. The properties of a solution are uniform throughout the sample, as the components are mixed at the molecular level. 14-1 Dissolution process Gases mix completely and spontaneously, since mixtures are statistically favored over pure components. In general, the statistical factors at play are related to the entropy, or randomness of the system. Spontaneous processes are favored by an increase in entropy. The formation of a solution in condensed phases is also favored by increased entropy, but the solute-solute and solvent-solvent attractions must be broken and replaced with solvent-solute interactions. If the enthalpy change associated with these alterations in intermolecular attractions is favorable (corresponding to an exothermic process), the dissolution is spontaneous. If the enthalpy change is weakly endothermic, the entropy-driven process is still spontaneous, but if enthalpy is strongly endothermic, no solubility is observed. 14-2 Electrolytes Electrolytes are substances that dissociate into ions when dissolved in water. Strong electrolytes (including ionic salts, strong acids and strong bases) dissociate completely in water. Weak electrolytes (including weak acids and weak bases) dissociate only partially in water (only a small fraction of the total sample of molecules dissociate). Non-electrolytes (including most covalent compounds) do not dissociate into ions at all when dissolved in water, preserving their molecular integrity. 14-3 Concentration The concentration of a solute is expressed as a ratio of the amount of solute compared to the amount of solvent and it may be quantitatively expressed in various ways. The amount of solute can be given as either mass or number of moles, and the amount of solvent can be given as the mass, number of moles, or volume. The most commonly used measures of concentration are mass fraction, mass percent, molar fraction, molarity, and molality. 14-4 Solubility Solubility is defined as the amount of solute that will dissolve in a solvent, and is determined by the nature of the intermolecular interactions, temperature, and (for gases) pressure. Ionic and polar substances are more likely to be soluble in polar solvents, while nonpolar solvents will most likely dissolve non-polar solutes. This generalization of solvent-solute interactions can be summarized as "like dissolves like". Gas solubility is proportional to the partial pressure of the gas above the solution, and for gases the solubility diminishes with increasing temperature. In contrast, the solubility of ionic or covalent substances usually increases with increasing temperature, although exceptions are common. A solution in equilibrium with a solute in a different phase is referred to as saturated. Solutions with solute concentrations approaching saturated are called concentrated, while those on the low end of the concentration range are called dilute. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 203/250 9/2/2019 Chem 110 14-1 Dissolution process Dissolution depends on entropic effects, which are always favorable, and enthalpic effects, which may be favorable or unfavorable So far in our exploration of the physical properties of gases and liquids we have concentrated on pure substances. However, the forms of matter around us are most often heterogeneous or homogenous mixtures. In heterogeneous mixtures, the ingredients are not dispersed uniformly, and properties change from one region of the sample to another. In homogenous mixtures the components are uniformly mixed at the atomic or molecular level, and we observe consistent properties and composition throughout the whole sample. We call such mixtures solutions. The major component in a solution is called the solvent and the minor components are called solutes. We usually think of a solution as a liquid that contains a dissolved substance, which could be a solid, another liquid, or a gas. In fact, there are also solid solutions, including brass (zinc in copper), steel (carbon in iron), or sterling silver (copper in silver), as well as gaseous solutions (such as air). Indeed, we already encountered gaseous solutions when we discussed diffusion, partial pressures, and the atmosphere. Liquid solutions are the most common, and we will focus on them in this Lesson. We will be particularly concerned with aqueous solutions, in which water serves as the solvent. Gaseous solutions are simple to make and are always homogeneous; gases mix spontaneously without any energy supplied by the surroundings. Imagine that we have a gas in one container connected to another identical but empty container. If we open a stopcock between the containers, after a while the gas molecules will be distributed equally between the containers. This is the most statistically probable distribution. Any aggregation of an excess of molecules in one of the containers is highly unlikely. Similarly, if the two containers are occupied by different gases, each container will hold an identical mixture of gases after a period of time with the stopcock open. Both components will be distributed equally between the containers. This statistical tendency of gases to interdisperse is related to a thermodynamic quantity called entropy. Entropy can be simplistically described as the amount of randomness in a system. Spontaneous processes, in general, are associated with a balance between two different thermodynamic parameters; entropy and enthalpy of the system. Increasing entropy favors spontaneity (increasing randomness), and decreasing enthalpy favors spontaneity (decreasing energy and increasing stabilization). While entropy always increases upon mixing (the system becomes more dispersed), the enthalpy change can either be favorable (exothermic) or unfavorable (endothermic). Although the entropy increase upon mixing always favors the formation of a solution in the gas phase, the situation is more complex in liquid solutions. The entropy of the system still increases upon mixing, but the enthalpy change is influenced by the strong intermolecular attractions in condensed phases that may restrain molecules from mixing. Solute-solute and solvent-solvent interactions are broken during dissolution, while solute-solvent interactions are formed Figure F14-1-1 shows that the energetic balance of breaking those forces and establishing new intermolecular solventsolute attractions constitutes the enthalpic component of solution formation: Solute-solute interactions between the molecules of the solute must be broken so individual molecules can be distributed among the solvent molecules (ΔH1). This process is always endothermic and requires energy. Solvent-solvent interactions between molecules of the solvent must be overcome to make space for the molecules of the solute (ΔH2). This process is always endothermic and requires energy. Solute-solvent interactions form as the molecules mix, lowering the energy of the solution (ΔH3). This process is always exothermic and releases energy. The first two processes are endothermic since they break attractive interactions. The third is exothermic since new attractions are formed. The extent to which a given substance is able to dissolve in another is determined by the relative magnitudes of the enthalpies involved (F14-1-1). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 204/250 9/2/2019 Chem 110 Figure F14-1-1. Enthalpies of solution formation with exothermic process on the left and endothermic process on the right. ΔHsol = ΔH1 + ΔH2 + ΔH3. The process of separating the solvent and solute particles (ΔH1, ΔH2) is an endothermic process and causes enthalpy of the system to increase. The mixing of the solvent and solute (ΔH3) is either endothermic (because of repulsion between the solvent and solute) or exothermic (because of favorable interactions being formed). If the newly created interactions between the solvent and the solute molecules dominate (ΔHsol = ΔH1 + ΔH2 + ΔH3 < 0), the overall enthalpy change is favorable. Since the entropy of mixing is always favorable, the dissolution will be spontaneous (F14-1-1a). If the newly established interactions are not able to compensate for the broken interactions between the solvent and solute (ΔHsol = ΔH1 + ΔH2 + ΔH3 > 0, F14-1-1b), the dissolution may still occur if the increase in entropy is large enough to make the process favorable. In such a case the dissolution process is endothermic, but still spontaneous; we call such dissolutions entropy-driven. When the latent interactions between the solute and solvent molecules are weaker than the existing intermolecular interactions in the pure solvent and the pure solute that would need to be broken to produce the solution (ΔHsol = ΔH1 + ΔH2 + ΔH3 >> 0), the dissolution will not take place. We then say that the substance is insoluble in the given solvent. Solubility can be understood by considering the specific intermolecular interactions made and broken during the dissolution Consider a solution of cyclohexane (C6H12) in heptane (C7H16). Both hydrocarbons are liquids at 25 °C and are completely miscible (they have no limit of solubility). London dispersion forces are the dominant intermolecular forces in both liquids. The forces are stronger in heptane, as shown by its higher boiling point (98 °C for heptane vs. 80 °C for cyclohexane). One would expect the addition of cyclohexane to heptane to be slightly endothermic, as the rod-like heptane molecules have more contact areas that facilitate polarization, while cyclohexane molecules are more spherical in shape, with limited contact area (Figure F14-1-2). The net effect is the lowering of the number of attractive interactions if cyclohexane is added to heptane. Indeed, a 20% molar solution of cyclohexane has ΔHsol = +0.6 kJ/mol, and the endothermic dissolution is entropy-driven. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 205/250 9/2/2019 Chem 110 heptane ethanol cyclohexane water Figure F14-1-2. Structures of heptane, cyclohexane. ethanol and water (MEPs are on ±200 kJ scale). The immiscible layers of water (bottom) and cyclohexane (top) in a test tube. The menisci of both liquids (pointed out by arrows) are clearly visible. The dissolution of cyclohexane in ethanol (CH3CH2OH) is more endothermic (ΔHsol = +2.8 kJ/mol for the 20% solution), as the cost of breaking the hydrogen bonds in ethanol to accommodate molecules of cyclohexane goes up. This enthalpy cost is still easily balanced by the entropy of mixing; cyclohexane and ethanol are miscible. In contrast, cyclohexane is essentially insoluble in water (F14-1-2). The intermolecular interactions in water are dominated by dipole-dipole interactions, specifically by hydrogen bonding, while dispersion forces are essentially the only attractions between the molecules in cyclohexane. The two intermolecular forces are quite dissimilar in their nature; the costs of breaking the interactions within the solvent (water) and the solute (cyclohexane) cannot be compensated by any strong solvent-solute interactions. As a result, the two liquids are immiscible, and no solubility is observed. Water is not inhospitable to all solutes. Solutes that have similar intermolecular forces to water are quite soluble. Ethanol is completely soluble in water, as the dominant dipole-dipole and hydrogen bonding intermolecular interactions in both are the same. Indeed, the mixing of ethanol and water is favorable and exothermic (ΔHsol = −10.0 kJ/mol). Water has a special ability to dissolve ionic substances because it is polar. You should recall that ions are attracted to each other by the strong electrostatic forces in ionic solids. When the substance is dissolved, water must be able to provide sufficient ion-dipole attractive interactions to the dissolved solute to both compensate for the energy needed to separate the ions, and also to break apart the hydrogen-bonded structure of water (at least locally, in the immediate vicinity of the ions). We previously analyzed these ion-dipole attractions for Na+ and Cl−; the ions in solution are surrounded by a solvation sphere of water molecules (F14-1-3). We often refer to the stabilizing interactions between the solute(s) and the solvent as solvation, and solvation in water is called hydration, especially if the formation of structured assemblies is involved. Figure F14-1-3. Ion-dipole interactions for Na+(aq) and Cl−(aq) ions in water. The cation attracts the negative end of the water dipole (oxygen), while the anion is hydrogen-bonded to H–OH groups. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 206/250 9/2/2019 Chem 110 In the case of sodium chloride, dissolution in water is weakly endothermic (ΔHsol = +3.9 kJ/mol). Other ionic solids may dissolve in water through even more endothermic entropy-driven processes, such as the dissolution of ammonium nitrate (ΔHsol(NH4NO3) = +26.4 kJ/mol). Some ionic solids dissolve in exothermic processes, such as magnesium sulfate (MgSO4) (ΔHsol(CuSO4) = −66.5 kJ/mol). Not all ionic solids are soluble in water; in some cases the ion-ion attractions are so strong that the molecules of water cannot dislodge and solvate individual ions when they are part of the solid lattice. Figure F14-1-4. Exothermic dissolution of CuSO4 (left) and endothermic dissolution of NH4NO3 (right). In the exothermic process the heat released by the system (by the dissolving copper sulfate) is transferred to the water, increasing the temperature of the solution. In the endothermic process, the heat needed to dissolve the ammonium nitrate (which is entropically driven) is withdrawn from the water, lowering the temperature of the solution. It is also not surprising that ionic solids are much less soluble in solvents that have significant organic residues (such as hydrocarbon chains) that interact mainly through dispersion forces. For this reason, many ionic solids are not very soluble in ethanol (CH3CH2OH), even though it is polar and has the ability to hydrogen bond. For example, 36 g of NaCl will dissolve in 100 mL of water at 25 oC, but only 1.4 g will dissolve in 100 mL of methanol, and only 0.06 g will dissolve in 100 mL of ethanol at the same temperature. Ionic solids are totally insoluble in pure hydrocarbon solvents, such as heptane or cyclohexane; the intermolecular forces are too dissimilar in the solute and the solvent. Dissolution can be reversed through solvent removal without changes in solute identity A final word must be said about the difference between dissolution and chemical reactions. In the dissolution process the original solute can be recovered, chemically unchanged, after the solvent is removed. Even though the dissolution of ionic solids leads to solvated individual ions (such as the solvated sodium and chloride ions formed in the dissolution of NaCl), the original ionic solid is reformed after the solvent is evaporated. The same is true of liquid solutions; a liquid solvent can be separated from a liquid solute by fractional distillation, where the mixture is held at the boiling point of one of the components so that it is selectively evaporated leaving the other pure component behind. In contrast, when iron metal is dissolved in hydrochloric acid, a chemical reaction takes place, giving us a solution that contains Fe3+ and Cl− ions and producing hydrogen gas (C14-1-1). This is not a simple dissolution, it is a chemical reaction: 2 Fe(s) + 6 HCl(aq) ⟶ 2 FeCl (aq) + 3 H (g) 3 2 E14-1-1 If we evaporate the water from the resultant solution, we obtain the ionic solid iron(III) chloride hexahydrate, FeCl3 • 6H2O, which may be further dehydrated into anhydrous FeCl3. These solids are chemically different from the original iron. The chemical reaction that took place changed the chemical identity of the species involved. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 207/250 9/2/2019 Chem 110 14-2 Electrolytes Electrolytes are substances that dissociate into ions in solution, which enables the solution to conduct electricity When sodium chloride dissolves in water, we get a solution containing solvated Na+(aq) and Cl−(aq) ions, which move freely within the liquid. Since flow of electricity simply requires the movement of charged particles, such a solution can conduct electricity if two metal electrodes are immersed in it and a potential is applied. Ions carry the charge between the electrodes and allow current to flow; an indicator light will light up if included in the circuit. deionized water tap water acetic acid (aq) ammonia (aq) HCl (aq) methanol (aq) Figure F14-2-1. Electrical circuit set up to test conductivity of aqueous solutions. The relative magnitude of the flowing electric current is shown by the position of yellow light on the 1-10 scale at the bottom of the digital measuring device. Pure water ("deionized") does not have a significant number of ions present and does not conduct electricity. A solution with a relatively small number of ions allows a limited current to flow. A solution with a large number of ions is fully conductive. In general, substances that dissolve in water and dissociate into ions are called electrolytes. A strong electrolyte is one that dissociates completely in water to form ions. Substances that dissociate partially in water are called weak electrolytes. In these substances, only a small fraction of the molecules dissociate into ions when dissolved in water; most of the molecules of a weak electrolyte retain their molecular integrity. Substances that do not dissociate into ions at all are called nonelectrolytes. Conductivity tests like the one above (F14-2-1) can determine to which class a substance belongs. Ionic solids, strong acids, and strong bases are all strong electrolytes that dissociate completely in solution All ionic solids that are soluble in water are strong electrolytes. Upon dissolution, ionic solids dissociate completely into ions, producing solutions with high conductivity. Ionic solids often consist of metal/non-metal combinations of elements and are called salts. Sodium chloride (table salt) is one example of a soluble ionic solid that dissociates according to the following equation, where the presence of water is implied by the aqueous phase designation (aq) in the products: + NaCl(s) ⟶ Na (aq) + Cl − (aq) C14-2-1 In ammonium salts, a protonated amine plays the role of the cation, combining with an appropriate anion. Such salts are formed if the lone pair in ammonia or an organic amine bonds a proton. Ammonium salts dissociate into ions in aqueous solution and are strong electrolytes. The simplest example of such a salt is ammonium chloride, NH4Cl. Another class of ionic solids are the strong bases; these are defined as the hydroxides of the groups 1 (1A) and 2 (2A) elements, with the exception of Be(OH)2 and Mg(OH)2 (which are not strong bases or strong electrolytes). The strong bases are all strong electrolytes, and dissociate completely in aqueous solution to produce hydroxide ions and the appropriate metal cation. The group 2 hydroxides illustrate that a substance does not have to be very soluble to be a strong electrolyte. For example, the solubility of calcium hydroxide, Ca(OH)2, is only about 0.17 g per 100 mL of water, but the amount that is dissolved completely dissociates into ions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 208/250 9/2/2019 Chem 110 Some covalent compounds also dissociate in water. Acids, which are a class of compounds defined as proton donors, dissociate in water, producing solvated protons in the form of H3O+(aq), called hydronium ions. The hydronium ion is frequently represented just as H+(aq). Hydrogen chloride is a covalent substance, but when dissolved in water it becomes hydrochloric acid that dissociates completely according to the following equation: + HCl(aq) + H O(l) ⟶ H O 2 3 (aq) + Cl − C14-2-2 (aq) Acids that dissociate completely are called strong acids, and they are strong electrolytes. There are only seven strong acids: hydrochloric acid (HCl), hydrobromic acid (HBr), hydroiodic acid (HI), perchloric acid (HClO4), chloric acid (HClO3), nitric acid (HNO3) and sulfuric acid (H2SO4). Weak electrolytes are molecules that dissociate partially when they dissolve Any other substances that dissociate producing protons can do it only partially, i.e. only a small fraction of the molecules are dissociated in solution. Such substances are called weak acids. Since the number of ions formed constitutes only a small fraction of the dissolved substance, weak acids are also weak electrolytes. Examples of weak acids include hydrofluoric acid (HF), phosphoric acid (H3PO4), hydrocyanic acid (HCN), formic acid (HCOOH), acetic acid (CH3COOH) and other organic carboxylic acids. The weak acid acetic acid is commonly known as vinegar; it is only about 1% dissociated, as shown in the following equation: − + ⇀ CH COOH(aq) + H O(l) − ↽ − CH COO (aq) + H O (aq) 3 2 3 3 C14-2-3 Notice that we use a different arrow notation for the dissociation of HCl (a strong acid) and the dissociation of acetic acid (a weak acid). In the case of HCl the arrow points to the right, indicating that, for all practical purposes, all molecules of HCl have dissociated into ions. There are no undissociated HCl molecules floating around—the process is complete. In the case of acetic acid, we have two arrows, one pointing to the right as before, and another one pointing to the left. This double-arrow symbol designates an equilibrium, where both the forward and the reverse process are taking place at the same time. In such solutions there are both individual ions and undissociated molecules present, and they readily interconvert. Some molecules of acid dissociate, and some ions of opposite charge come together to reform the neutral molecule. This is an example of dynamic equilibrium, a phenomenon we have already encountered in our discussion of vapor pressure, and which we will explore in more detail in Chapter 18. Amines are another class of compounds that produces ions in equilibrium with undissociated molecules. Amines are considered weak bases and weak electrolytes. The lone pairs of amine nitrogens are able to accept protons from water in aqueous solution, forming the protonated amine (i.e. the ammonium cation) and a solvated hydroxide ion. Protonated amines are weak acids. Ammonia offers the simplest example of such reaction: + − ⇀ NH (aq) + H O(l) − ↽ − NH (aq) + HO (aq) 3 2 C14-2-4 4 This reaction is written as an equilibrium, similarly to the deprotonation reaction of weak acids; both the forward and reverse processes are taking place simultaneously. Ammonia is only partially protonated in water (about 1%); it is a weak electrolyte. Other weak bases include organic amines such as methylamine (CH3NH2), triethylamine ((CH3CH2)3N), aniline (C6H5NH2), and pyridine (C5H5N); all are weak electrolytes. Nonelectrolytes retain their molecular structure in solution Substances that maintain their molecular integrity when they dissolve and do not dissociate into ions are called nonelectrolytes. Most covalent compounds, with the exception of acids and weak bases, do not dissociate into ions when dissolved in water. Such covalent nonelectrolytes include many groups of organic molecules, such as alcohols (for example methanol and ethanol), simple ketones (acetone, for instance), aldehydes (for example formaldehyde), and carbohydrates such as table sugar or glucose (C6H12O6). C H 6 12 ⇀ O (s) + H O(l) − ↽ − C H 6 2 6 12 O (aq) + H O(l) 6 2 C14-2-5 What happens when a substance dissolves in a solvent affects the properties of the resulting solution. Some of these properties (for example conductivity) depend on the identity and the number of species in the solution, but in many cases just the number of solute particles (molecules or ions) that exists in the solution determines the solution's characteristics. In either case, the ratio of solute particles to solvent molecules is expressed by various measures of concentration, some of which we will explore in the next Lesson. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 209/250 9/2/2019 Chem 110 14-3 Concentration Mass fractions, mole fractions, and molarity are the most common ways to express concentration of solutes in solvents The concentration of a solution describes the amount of solute in relation to the amount of solvent or solution. It may be quantitatively expressed in various ways. Mass fraction is the ratio of the mass of solute per total mass of the solution (Equation E14-3-1). Usually, the mass fraction is multiplied by 100 to give mass percent or weight percent of the solute. If the fraction is very small, it is more convenient to use parts per million (ppm) or parts per billion (ppb) instead of percent (parts per hundred). You may recall that we introduced these fractions when we talked about mixtures of atmospheric gases. In the case of gas solutions, they refer to ratios of volumes (or moles) rather than to ratios of masses (which are used for liquid and solid solutions). mass f raction = mass of the component × 100 = mass% = weight% E14-3-1a total mass mass f raction = mass of the component × 10 6 = ppm E14-3-1b = ppb E14-3-1c total mass mass f raction = mass of the component × 10 9 total mass Mole fraction was also previously introduced, as a measure of the concentration of gases. Molar fractions are usually used for gas solutions, but also have limited applications in condensed phase solutions. "Xi" is the symbol used for the mole fraction of the component of interest as compared to the total moles in the solution (E14-3-2): Xi = molef raction = moles of the component E14-3-2 total moles Molarity is the most commonly used concentration measure for liquid solutions; molarity is, defined as the number of moles of solute per 1 L of solution and is given units of upper case M, which represents mol/L (E14-3-3). A 1 M solution is called a “1 molar solution.” M = molarity = moles of solute E14-3-3 volume (L) of solution Depending on convenience or tradition, chemists may routinely use many different expressions of concentration. For example, in the previous section we specified the solubility of some substances in g per 100 mL of solvent—yet another way to convey concentration. The ability to convert between various concentration measures is an important skill, requiring some practice. The scheme in Figure F14-3-1 outlines the connections between the quantities involved. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 210/250 9/2/2019 Chem 110 Concentration conversions and dilution calculations are routinely based on molar quantities Figure F14-3-1. Scheme illustrating connections between the various quantities involved in calculating concentrations. Let's illustrate various ways to convert concentrations. We will use a concentrated solution of hydrochloric acid as our example, which is 36.0% HCl by weight and has a density of 1.18 g/mL. The figure of 36.0% corresponds to the mass percent measure of concentration (E14-3-1). A 100-g sample of this solution contains 36.0 g of HCl and 64.0 g of water, which corresponds to 0.987 moles of HCl (36.0 g divided by 36.46 g/mol) and 3.55 moles of H2O (64.0 g divided by 18.01 g/mol). Thus, the molar fraction (E14-3-2) of HCl in the solution is XHCl = (0.987/(0.987+3.55)) = 0.218. A 1 L (1000 mL) sample of this solution weighs 1.18 kg. Since 36.0% of that mass is HCl, the 1 L volume contains 425 g or 11.6 moles of HCl. Thus, the molarity of the solution is 11.6 mol/L (E14-3-3). Often, chemists need to prepare dilute solutions from a more concentrated solution (often called the "stock" solution). Let's say we want to prepare 1.00 L of 1.00 molar (1 M) HCl solution using the HCl solution from our example above. Calculations of such dilutions are based on the idea that the number of moles of the solute must remain constant when the sample is diluted with solvent (water). The number of moles of solute is calculated by multiplying the molarity of the solution by the volume (n = MV). In dilutions, the number of moles must be the same before and after dilution (E14-34). E14-3-4 n = Minit Vinit = Mf inal Vf inal In our hydrochloric acid example, Minit = 11.6 mol/L, Mfinal = 1.00 mol/L, Vfinal = 1.00 L, and simple arithmetic gives us Vinit = 0.0862 L. We need to dilute 86.2 mL of our stock solution with water to reach a total volume of 1.00 L in order to obtain a 1.00 M solution of HCl. Note that in the manipulation of chemical solutions two different processes can take place: transfer, or dilution. The transfer of a solution involves moving a given volume of solution from container number 1 to container number 2. The volume and the number of moles of solute may change, but the concentration does not change (V1 ≠ V 2, n1 ≠ n2, M1 = M2). The unchanging value of molarity allows the calculation of either the volume or number of moles in the second container. In contrast, the dilution of a solution involves the addition of water (or solvent) to one container of the solution, which does not affect the number of moles of solute present. The volume and the concentration of the solution changes, but the number of moles of solute does not change before and after the dilution (V1 ≠ V2, M1 ≠ M2, n1 = n2). The unchanging number of moles of solute is the source of equation E14-3-4 above. In the case of strong electrolytes, we know that these compounds dissociate completely into ions in solution, and the concentration of each ion in the final solution can be calculated by using the stoichiometry of the dissociation process. In order to calculate the concentration of chloride ions in 1 L of 2.0 M solution of calcium chloride, we must first write the dissolution process: CaCl (s) ⟶ Ca 2 2 + (aq) + 2 Cl − (aq) C14-3-1 From the balanced reaction we can see that there are two mole of chloride ions formed for every one mole of calcium chloride dissolved. In 1 L of a 2.0 M solution of CaCl2 there are 2 moles of CaCl2. Therefore, there are four moles of dissociated chloride ions in the 1 L volume, and the concentration is 4 mol/1 L = 4.0 M chloride ions. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 211/250 9/2/2019 Chem 110 14-4 Solubility Saturated solutions contain the maximum amount of solute that will dissolve, dilute solutions contain less, and supersaturated solutions contain more than this amount All gases and some liquids are completely miscible (soluble in each other without limits). The atmosphere supplies an illustration of the first case, and we presented a couple of examples of miscible liquids in the previous section. What these cases have in common is that they do not involve dissimilar intermolecular interactions; the IMFs are practically non-existent in gases, and they are very similar in both the solvent and the solute for miscible liquids. However, in many cases, especially for solid-state solutes, the strength and type of the intermolecular interactions impose limits on solubility. Returning to our classical example of an ionic solid dissolving in water, we notice that at room temperature (25 °C) only 36 g of NaCl dissolves in 100 mL of water. When we add solid NaCl to water (F14-4-1), initially the water molecules extract individual ions from the crystalline solid, solvating each one in turn as previously described. As the number of solvated ions increases, so does the probability of some of them colliding with the surface of undissolved crystals and being recaptured. Figure F14-4-1. Dissolution of NaCl in water. The individual ions are carried off the surface of the crystal and solvated, leading to the dissolution of the solid. A dynamic equilibrium is reached when enough solid is added so that the dissolution and crystallization rates are the same. At this point the solution is saturated and adding more solid will cause it to precipitate. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 212/250 9/2/2019 Chem 110 The rebuilding of the crystal is called crystallization. At a certain point a dynamic equilibrium is achieved, with the rates of dissolution and crystallization being equal (C14-4-1). At this point we have a saturated solution; no more solute will dissolve in the available amount of solvent at that temperature. That maximum amount of solute that will dissolve in a given solvent and temperature is called its solubility, i.e. solubility values are equilibrium values for saturated solutions in contact with some undissolved solid. Under certain conditions it is possible to obtain a supersaturated solution, which contains more of the solute than its solubility limit at the given temperature. Since crystallization requires precise orientation of molecules in a 3D arrangement, the formation of the first crystals (sometimes called seed crystals) may be slow. Such solutions are unstable, and any perturbation (such as the addition of an external seed, a speck of dust or another solid impurity) may spark rapid crystallization of the excess dissolved solute (F14-4-2). Figure F14-4-2. Rapid crystallization (real speed) of a supersaturated solution of sodium acetate. The saturated solution is made at 100 °C. It contains 170 g of solute per 100 mL of water. It is slowly cooled to 25 °C where the solubility is only 46 g per 100 mL. Thus, there is 124 g (per 100 mL) of excess sodium acetate above its solubility limit at 25 °C. The sodium acetate rapidly crystallizes when a seed crystal is added. We can now reexamine some of the descriptive adjectives we used to qualitatively describe concentrations of solutions. The solubility of a substance is equivalent to the concentration of the saturated solution at the given conditions of temperature and pressure. A concentrated solution is close in concentration to the saturated solution, while a dilute solution is on the other end of the concentration range. Both of those terms are strictly relative, and can be meaningfully applied to a specific substance, or used to compare substances of similar solubility. For example, at 25 °C, a saturated solution of NaCl has a solubility of 5.4 mol/L, while a saturated solution of cesium sulfate has a solubility of only 0.06 mol/L, a concentration that would be considered "dilute" for sodium chloride. “Like dissolves like” is the empirical pattern that polar solutes typically dissolve in polar solvents and nonpolar solutes typically dissolve in nonpolar solvents Solubility is strongly influenced by the type and strength of the intermolecular interactions, especially between the solute and solvent molecules: the stronger the interactions, the greater the solubility. We previously noted these trends when we discussed the enthalpy of the dissolution process. We noted, for example, that simple alcohols like ethanol are miscible with water. A closer examination shows that the solubility of an alcohol drops off as the hydrocarbon chain grows longer (T14-4-1). The London dispersion interactions become more and more dominant over the hydrogen-bonding forces with increasing chain length, and the alcohol becomes less similar to water and less soluble. Table T14-4-1. Solubility of alcohols in water and cyclohexane. Alcohol CH 3OH CH 3CH2OH CH 3CH2CH2OH CH 3CH2CH2CH2OH CH 3CH2CH2CH2CH2OH CH 3CH2CH2CH2CH2CH2OH CH 3CH2CH2CH2CH2CH2CH2OH https://genchem.science.psu.edu/sites/default/files/filefnlBYE Solubility in water Solubility in cyclohexane in g per 100 mL in g per 100 mL ∞ ∞ ∞ 8.06 2.82 0.62 0.17 3.84 ∞ ∞ ∞ ∞ ∞ ∞ 213/250 9/2/2019 Chem 110 Dissolution of alcohols in hydrocarbon solvents follows the opposite trend (Table 14-4-1). Long chain alcohols are miscible with cyclohexane, as dispersion forces are dominant in both the solvent and the solute. However, the solubility diminishes for methanol with only one CH3 group attached to the OH group. You may recall that cyclohexane is insoluble in water, and that methanol is the alcohol most similar to water. One can imagine what kind of structural changes we would need to make to cyclohexane to make the modified molecule soluble in water. Indeed, such modified molecules already exist; glucose is essentially a hydrocarbon that has -OH groups covering the whole molecular surface (F14-4-3). The intermolecular forces within glucose and water are thus very similar. It is not surprising that glucose is very soluble in water (91 g per 100 mL at 25 oC). water glucose acetone acetic acid DMSO Figure F14-4-3. Structures of water, glucose, acetone, acetic acid, and dimethylsulfoxide, showing the similarities in the polarities of their functional groups. Glucose is very soluble in water, and acetone, acetic acid, and DMSO (dimethylsulfoxide) are miscible with water. All MEPs are at ±200 kJ scale. In general, molecules that have similar polarity to water are expected to be soluble in water. For example, acetone, acetic acid, and dimethylsulfoxide (all liquids at 25 °C) are completely miscible with water (F14-4-3). Their ability to form hydrogen bonds also heavily influences solubility in water. The examination of multiple examples of solvent-solute interactions gives us the helpful rule, "like dissolves like". Thus, ionic and polar substances are more likely to be soluble in polar solvents, while nonpolar solvents will most likely dissolve nonpolar solutes. If the intermolecular interactions broken and formed upon mixing are approximately the same, dissolution is probable. Figure F14-4-4. Illustration of "like dissolves like." Iodine, I2, a nonpolar solid, dissolves in (d) a nonpolar solvent (heptane), but is insoluble in (b) a polar solvent (water). Copper sulfate pentahydrate (CuSO4 · 5H2O), an ionic solid, dissolves in (a) water (a polar solvent), but is insoluble in (c) heptane (a nonpolar solvent) The solubility of a gas diminishes with rising temperature and is proportional to the gas’s partial pressure above the solution The solubility of a substance is different under different conditions. The solubility of gases is affected by pressure, and the solubility of all substances depends on temperature. In general, the solubility of a gas in a solvent depends on the partial pressure (Pg) of that gas above the solution; increases in Pg lead to increases in solubility. At equilibrium, at a given pressure, the rates of gas molecules entering and leaving the solution are the same. Increasing the partial pressure of the gas above the solution increases the rate at which gas molecules strike the liquid surface. On average more molecules enter the solution than escape it, and so a new equilibrium is established with a higher concentration of gas molecules dissolved in the solution. This relationship is described by Henry's law: Cg = kPg https://genchem.science.psu.edu/sites/default/files/filefnlBYE E14-4-2 214/250 9/2/2019 Chem 110 Figure F14-4-5. Henry's law for the solubility of several gases in water at 25 °C. The slopes of the lines correspond to the values of the Henry's law constants (k). k increases with increasing intermolecular forces, which, for molecules shown here, are limited to dispersion forces. An exception is CO, which has a small dipole moment and exhibits somewhat stronger interactions than N2. The increasing solubility of gases under higher pressure is used to prepare carbonated beverages. High-pressure CO2 is used to fill the bottles with extra gas, which rapidly escapes when the bottle is opened. Henry’s law states that the concentration of a gas in solution, Cg (usually expressed as molarity), is directly proportional to the partial pressure of the gas above the solution (Pg). The value of the proportionality constant k, known as the Henry's law constant, depends on the solute, solvent and temperature (see below). The Henry's law plots for several gases are shown in Figure F14-4-5. As a general trend, the solubility of gases decreases with increasing temperature (F14-4-6). This phenomenon is commonly observed when carbonated beverages go flat when left open at room temperature. The solubility of the carbon dioxide gas is lower at room temperature, so the CO2 escapes the liquid. Similarly, the solubility of O2 in water diminishes with temperature, making the oxygenation levels needed for living organisms difficult to maintain in the warm waters of lakes or streams. Figure F14-4-6. Solubility of gases in water as a function of temperature. For all gases, the solubility diminishes with increasing temperature. Solubility correlates with molecular sizes (dispersion forces) and is enhanced somewhat for weakly polar molecules (CO, NO). https://genchem.science.psu.edu/sites/default/files/filefnlBYE 215/250 9/2/2019 Chem 110 The solubility of ionic compounds frequently increases with temperature but some counterexamples exist Figure F14-4-7. Solubility of ionic compounds as a function of temperature. For most substances the solubility increases with the temperature, but there are multiple exceptions to the general trend. The solubility of liquid and solid solutes generally increases with temperature (F14-4-7), in some cases quite dramatically (see for example KNO3). However, there are many exceptions to that trend (see, for example, CdSeO4. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 216/250 9/2/2019 Chem 110 15 Chemical Reactions As we have learned over the last few lessons, intermolecular interactions affect phase transitions and other properties of condensed phases, but do not change the participating molecules. Now we are ready to explore processes in which molecules change their identities. It turns out that even stable molecules may engage in even stronger types of interactions in which electrons are transferred, bonds are broken and remade, and energy is exchanged with the surroundings. In such processes, called chemical reactions, reactants (the initial participants) are transformed into products (new chemical species). The only constant in such reactions are atoms, whose number and type remain unchanged even as their bonding arrangements are reconfigured. 15-1 Reaction types Reactions are divided into categories depending on their outcome. The categories we introduce include combination, decomposition, combustion, single displacement and double displacement. Chemical reactions are described by chemical equations, listing reactants on the left and products to the right of the reaction arrow. The stoichiometric coefficients are the numbers in front of reactants and products that express the molar ratios in which they participate in the reaction. In order to obey the law of conservation of mass, the stoichiometric coefficients must be such that the number of each type of atom is the same on both sides of the equation. Equations with coefficients that satisfy this condition are called balanced equations, and they constitute the basis of all stoichiometric calculations. 15-2 Driving force For a reaction to proceed as indicated by its equation, there must be some driving force. This driving force might be a lowering of the system’s enthalpy (this happens when products are more stable than reactants), or an increase of entropy (when products are statistically more likely than reactants). The driving force of double exchange reactions is most commonly manifested in the formation of a precipitate, the formation of a weak electrolyte or nonelectrolyte, or the formation of a gas. 15-3 Redox reactions Redox reactions are chemical processes in which electrons are transferred between reactants, resulting in reduction of one and oxidation of the other. The reactant that loses electrons is oxidized, and the reactant that gains electrons is reduced. The transferred electrons are accounted for by assigning oxidation states (or oxidation numbers) to each element in reactants and products. In single exchange redox reactions the driving force is the transfer of electrons from metals of higher activity to metals of lower activity, as ordered in the metal activity series. 15-4 Stoichiometry Stoichiometry deals with relative quantities of reactants and products in chemical reactions. It is based on the stoichiometric coefficients of balanced chemical equations and the proportionality between molecules and moles. It is used to determine the amounts of reactants and products of a given reaction in mass, moles, or volumes. The stoichiometric calculations are used to identify the limiting reactant, which is the reactant that determines the maximum theoretical yield of products. The amount of product actually formed is commonly expressed as percent yield, which is calculated by dividing the actual yield by the theoretical yield. 15-5 Example calculations Stoichiometric calculations are applicable to all types of reactions, including combustion, elemental analysis, redox reactions, solution reactions, titrations, and reactions of gases utilizing the ideal gas law. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 217/250 9/2/2019 Chem 110 15-1 Reaction types Combination, decomposition, combustion, and single and double displacement are the common types of chemical reactions A chemical reaction is a process that transforms one set of molecules, called reactants, into a different set of molecules, called products. Chemical reactions encompass changes in the apportionment of bonding and lone-pair electrons between atoms, and the resulting energy changes. The nuclei remain unchanged, preserving the atoms' identities. Elements can only undergo transmutation into a new element in nuclear reactions, which will not be explored until the second semester of general chemistry. There are a wide variety of chemical reactions, from the relatively simple, such as the production of carbon dioxide bubbles when an Alka-Seltzer tablet dissolves in water , to the complex reactions that take place in our eyes and brain as we read this sentence. Some go almost unnoticed, like the constant oxidation reactions in our bodies, providing energy that allows us to function. Others may be spectacular, like the 4th of July fireworks, which release energy in the form of light, heat, and acoustic waves for our entertainment. All reactions can be represented by chemical equations, which are a form of symbolic notation that captures the essence of the changes taking place. We will only explore a very small subset of reactions to illustrate some basic concepts of chemical reactivity. Even with a limited scope, it helps to categorize reactions into several groups that describe the net change. These categories are listed below with illustrative examples. Combination: elements react to form compounds, or small compounds combine to make larger ones 2 Mg(s) + O (g) ⟶ 2 MgO(s) C15-1-1 CaO(aq) + CO (g) ⟶ CaCO (s) C15-1-2 2 2 3 Decomposition: a compound breaks apart into two or more smaller compounds Δ C15-1-3 PbCO (s) − → PbO(s) + CO (g) 3 2 Combustion: a compound (usually organic) reacts (usually violently) with oxygen, O2(g); complete combustion means that the highest-oxidation state oxides are produced (CO2 for carbon, H2O for hydrogen). C15-1-4 2 CH OH(g) + 3 O (g) ⟶ 2 CO (g) + 4 H O(g) 3 2 2 2 Single displacement: one element replaces another in a compound C15-1-5 CuSO (aq) + Zn(s) ⟶ ZnSO (aq) + Cu(s) 4 4 Double displacement (metathesis): exchange of ions or atoms between two compounds CaCl (aq) + 2 AgNO (aq) ⟶ 2 AgCl(s)↓ + Ca(NO ) (aq) C15-1-5 HNO (aq) + KOH(aq) ⟶ KNO (aq) + H O(l) C15-1-7 Na S(aq) + 2 HCl(aq) ⟶ H S(g)↑ + 2 NaCl(aq) C15-1-8 2 3 3 3 2 3 2 2 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 2 218/250 9/2/2019 Chem 110 Chemical equations follow certain conventions to standardize their meaning. The reactants are always listed on the left. The arrow translates to "react" and points to the products. You may recall from our previous encounter with such symbols, that an arrow pointing to the right signifies a reaction that essentially goes in one direction; products are formed from the reactants, and there is no significant reaction in the opposite direction. The chemical formulas of the reactants and products are often supplemented by designation of their physical state in parentheses (g meaning gas, ℓ meaning liquid, s meaning solid, and aq indicating an aqueous solution). For ionic, metallic, or extended solids the elemental symbols or empirical formulas are used, sometimes specifying the allotropic form in parentheses (for example, K, NaCl, C(graphite), etc). Occasionally, some additional symbols may be included such as "Δ" above the reaction arrow to indicate heat has been added, an upward pointing arrow after the formula (↑) to indicate gas formation, or a downward pointing arrow (↓) after the formula to indicate precipitation of a solid. Balanced chemical equations document that no atoms are created or destroyed in chemical reactions Although listing the reactants and products on opposite sides of the arrow identifies the reaction unambiguously, the complete equation must still be balanced. A balanced equation allows us to carry out the stoichiometric calculations that describe the relative amounts of reactants and products, and to determine the percent yield of the products. A balanced equation is a reflection of the law of conservation of mass; the number of atoms of each element must be equal on both sides of the equation—no atoms can be created or destroyed in regular chemical reactions (nuclear reactions notwithstanding). Balancing an equation can be achieved only by changing the stoichiometric coefficients (the numbers in front of each chemical formula). Altering subscripted numbers within a formula changes the identity of the molecule, and therefore changes the entire reaction rather than balancing it. To balance a chemical equation we follow a systematic approach, balancing one element at a time and adjusting as necessary. For example, the combustion of ethane (C15-1-9) produces carbon dioxide and water. It is unbalanced when written with coefficients of 1 in front of each formula. For instance, there are 2 carbon atoms in the reactants but only 1 carbon atom in the products. C15-1-9 CH CH (g) + O (g) ⟶ CO (g) + H O(g) 3 3 2 2 2 Indeed, we can start the balancing with carbon: we have 2 carbon atoms among the reactants on the left, so we must also have 2 carbon atoms in the products. We need to place a "2" in front of CO2, the only carbon-containing product. We can then move on to the hydrogen atoms; we have 6 of them on the left, and all must be included in water, which is the only hydrogen-containing product. We need to put a “3” in front of H2O on the right to account for those 6 hydrogen atoms. The last element to balance is oxygen; we have total of 7 oxygen atoms on right side of the equation (2 x 2 in carbon dioxide and 3 in water). We need the same number on the left, but the oxygen atoms come in sets of two since dioxygen is the reactant; we must have a coefficient of 7/2 in front of O2 (C15-1-10). CH CH (g) + 3 3 7 2 O (g) ⟶ 2 CO (g) + 3 H O(g) 2 2 2 C15-1-10 Although C15-1-10 is balanced, chemists often prefer to use the smallest possible whole number coefficients instead of fractions. Whole number coefficients can be obtained by multiplying all coefficients on both sides of the equation by two (C15-1-11). The ability to multiply a balanced equation in this way illustrates the meaning of stoichiometry: it gives the relative ratio of atoms or molecules involved in a reaction, with a focus on proportions and not on specific absolute amounts. We will return to this concept later in the lesson. 2 CH CH (g) + 7 O (g) ⟶ 4 CO (g) + 6 H O(g) 3 3 2 2 2 https://genchem.science.psu.edu/sites/default/files/filefnlBYE C15-1-11 219/250 9/2/2019 Chem 110 Figure F15-1-1. Stoichiometry of the combustion reaction of ethane. The balanced equation uses the smallest whole number stoichiometric coefficients to reflect the whole numbers of molecules participating in the reaction. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 220/250 9/2/2019 Chem 110 15-2 Driving force Reactions of electrolytes are presented as net ionic equations with spectator ions omitted Consider a double-exchange reaction between lead nitrate and potassium iodide carried out in water. The two compounds are about to exchange their cations, creating lead iodide and potassium nitrate. The molecular equation, a balanced equation showing the complete chemical formulas without indicating the ionic nature of the reactants and products, is shown below. Pb(NO ) 3 2 + 2 KI ⟶ PbI 2 C15-2-1 + 2 KNO 3 However, both reactants are ionic solids and strong electrolytes and are completely dissociated into hydrated ions, as should be indicated thusly (C15-2-2): 2 + Pb − (aq) + 2 NO 3 + (aq) + 2 K − (aq) + 2 I C15-2-2 (aq) ⟶ At the starting point, we formally have four different kinds of ions floating in solution. Dissolving NaCl in water yields two kinds of ions (Na+ and Cl−), which will reconstitute as NaCl(s) if the water is evaporated. Following this logic, if there is no reaction, after the evaporation of water, we would get a mixture of all four ionic solids: two reactants, and two products; that would be quite a messy exchange. However, when we actually pour a solution of potassium iodide into the solution of lead nitrate, a yellow precipitate of lead iodide, PbI2, forms (F15-2-1). Figure F15-2-1. Precipitation of lead iodide (PbI2) that is created in a double exchange reaction upon the addition of drops of potassium iodide to a solution of lead nitrate It turns out that lead iodide is essentially insoluble in water. Taking the precipitation of one of the products into account, we can now complete equation C15-2-2 as follows: 2 + Pb − (aq) + 2 NO 3 + (aq) + 2 K − (aq) + 2 I (aq) ⟶ + PbI (s)↓ + 2 K 2 − (aq) + 2 NO 3 C15-2-3 (aq) The equation above is a complete ionic equation showing all reactant and product ions and the insoluble solid of PbI2 that separated from the solution. A closer examination of the equation indicates that we have some of the same ions on both sides of the equation (K+ and NO3−). These ions actually do not participate directly in the reaction; they are spectator ions. We can remove them from both sides (like in an algebraic equation), giving us the net ionic equation: 2 + Pb − (aq) + 2 I (aq) ⟶ PbI (s)↓ 2 C15-2-4 Notice that the net ionic equation is still balanced. Charges on ions are balanced as well; the sum of the ionic charges must be the same on both sides of the equations. The net ionic equation is especially important: it shows only those species that actually take part in the reaction and the chemical change that takes place. For example, from the net ionic equation above, we can tell that to make solid PbI2, we need a source of Pb2+(aq) and I−(aq) ions. We will obtain the same result by using HI(aq) and lead acetate, for example. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 221/250 9/2/2019 Chem 110 The driving forces for exchange reactions include formation of a precipitate, gas, weak or nonelectrolyte, and redox activity This example demonstrates that for double exchange to work, it needs some kind of driving force that will assure that products (as written in the chemical equation) actually form. Normally, the most obvious driving force is an exothermicity of the process (ΔH < 0), i.e., the product stability exceeding that of the reactants. For example, the products of combustion reactions of hydrocarbons, carbon dioxide and water, are much more stable than the reactants, hydrocarbons and oxygen. Another driving force in reactions can be a favorable entropy change, analogous to the dissolution process. We will explore these thermodynamic aspects of reactions in the next Chapter and in the second semester of general chemistry. The driving forces at work in exchange reactions that we consider here are: formation of a precipitate formation of a gas formation of a weak electrolyte or nonelectrolyte redox (activity series) You may observe that in the first three categories a product is removed from the reaction phase. Insoluble solids separate from the aqueous phase, gases escape the solution, and the formation of nonelectrolytes (often water) involves converting ionic species into covalent compounds. In all of these cases at least one of the products is removed from the reaction mixture, driving the reaction to completion. In the reduction-oxidation (redox) processes, electrons are transferred from a higher energy state in a more active metal to a lower energy state in less active metals. To be able to predict the outcome of a double exchange reaction, we need to recognize which type of the driving force is present. For example, for precipitation reactions, we need to know whether any of the ions involved in the reaction form an insoluble salt. It turns out that the solubility of many salts follows similar patterns, which may be generalized into a set of widely applicable guidelines (Table T15-2-1). Table T15-2-1 Solubility guidelines for ionic solids in water soluble Guidelines Exceptions ammonium (NH 4+) alkali metals (Li +, Na+, K+, Rb+, Cs+) nitrates (NO 3−) acetates (CH 3COO−) perchlorates (ClO 4−) halides (Cl −, Br−, I−) sulfates (SO 42−) Ag +, Hg22+. Pb2+ Ca 2+, Sr2+, Ba2+, Ag+, Hg22+, Pb2+ sulfides (S 2−) and hydroxides (HO−) insoluble carbonates (CO 32−) and phosphates (PO43−) NH 4+, Li+, Na+, K+, Rb+, Cs+ Ca 2+, Sr2+, Ba2+ NH 4+, Li+, Na+, K+, Rb+, Cs+ A second driving force for exchange reactions is the formation of a weak electrolyte or a nonelectrolyte. This driving force is most often encountered in acid-base neutralization reactions, wherein an acid reacts with a base to produce a salt and water. For example, the molecular equation for a reaction between hydrochloric acid and sodium hydroxide is shown in C15-2-5: C15-2-5 HCl(aq) + NaOH(aq) ⟶ H O(ℓ) + NaCl(aq) 2 When the molecular equation is rewritten as a complete ionic equation, we can see that chloride ion and sodium ion are spectator ions: + H (aq) + Cl − + (aq) + Na − (aq) + OH + (aq) ⟶ H O(ℓ) + Na 2 (aq) + Cl − (aq) C15-2-6 The net ionic equation makes the key transformation more obvious; the net change is the formation of water by a reaction between H+ and HO−: https://genchem.science.psu.edu/sites/default/files/filefnlBYE 222/250 9/2/2019 Chem 110 + H − (aq) + OH C15-2-7 (aq) ⟶ H O(ℓ) 2 Equation C15-2-7 represents the main feature of a neutralization reaction between any strong acid and any strong base. The formation of a covalent nonelectrolyte molecule (water) from ions (H+ and HO−) provides the driving force for this type of reaction by removing a pair of ions from the solution. Formation of a gas is another driving force. In these types of reactions a gas is produced that escapes the solution due to its limited solubility in water. For example, hydrogen sulfide gas forms when hydrochloric acid reacts with sodium sulfide, as shown in the molecular equation C15-2-8. 2 HCl(aq) + Na S(aq) ⟶ H S(g)↑ + 2 NaCl(aq) 2 2 C15-2-8 The net ionic reaction (C15-2-9) resembles the neutralization reaction of equation C15-2-7, although sulfide ion is a weak base. The product is a weak electrolyte, like water. It also happens to be a gas; it escapes the solution, driving the reaction to completion. + 2H 2 − (aq) + S C15-2-9 (aq) ⟶ H S(g)↑ 2 Other gases often produced in exchange reactions include CO2, NO2, or SO2. Sometimes a weak acid is produced first, with decomposition into gas in a subsequent step. For example, the reaction of hydrochloric acid with sodium hydrogen carbonate (baking soda) produces carbonic acid (C15-2-10). This weak acid is a weak electrolyte, which decomposes to produce carbon dioxide gas and water (C15-2-11). HCl(aq) + NaHCO (aq) ⟶ H CO (aq) + NaCl(aq) C15-2-10 H CO (aq) ⟶ CO (g) + H O(ℓ) C15-2-11 3 2 3 2 2 3 2 The net ionic equation is obtained by combining these two steps, and removing the spectator ions and carbonic acid (which is only an unstable intermediate): + H − (aq) + HCO 3 (aq) ⟶ CO (g)↑ + H O(ℓ) 2 2 C15-2-12 The exchange reactions presented above are all very similar; they can be thought of as acid-base neutralization reactions. Their products are all weak electrolytes or nonelectrolytes, and are all covalent molecules that exist as gases or liquids. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 223/250 9/2/2019 Chem 110 15-3 Redox reactions In a redox reaction one reactant gets oxidized, losing electrons, while another reactant gets reduced, gaining electrons A redox reaction is a type of reaction where oxidation and reduction of the reactants take place. When an atom, an ion, or a molecule has lost one or more electrons, we say it has been oxidized. Figure F15-3-1. Transfer of electrons in a redox reaction The name oxidation is used because the first reactions of this type studied involved oxygen, yielding oxygen-containing products. Oxygen is an excellent oxidizing agent, as we can see by the formation of rust on iron bridges parts, or the formation of green copper oxide on copper roof tiles after long exposure to oxygen in the air. However, the oxidation is only part of the process; when one chemical entity loses electrons, another must gain electrons. Such electron transfer from one species to another occurs in every redox reaction. The species that gains electrons is said to be reduced. Since reduction cannot occur without oxidation and vice versa, we can say that each species is acting as an agent of the change that the other species undergoes. An oxidizing agent (or oxidant) oxidizes something else, but in the process is itself reduced (it gains electrons from the other reactant). A reducing agent reduces something else, but in the process is itself oxidized (it loses electrons to the other reactant). The oxidation of magnesium is a fantastic example of a redox process. Shiny, silver-colored magnesium metal can be ignited in air, creating a bright flame, as it is converted into a dull, gray magnesium oxide powder (C15-3-1). 2 Mg(s) + O (g) ⟶ 2 MgO(s) 2 C15-3-1 In this reaction each magnesium atom loses two electrons, and each oxygen atom gains two electrons. Thus, oxygen is reduced and magnesium is oxidized; oxygen is the oxidizing agent, and magnesium is the reducing agent. Oxidation numbers are used to account for electrons gained and lost by atoms participating in redox reactions To keep track of the gained and lost electrons we assign oxidation numbers (or oxidation states) to each atom in the reaction. Oxidation numbers are assigned based on the difference between the number of valence electrons the neutral atom would have, and the number of electrons assigned to it in a Lewis structure. The number of electrons assigned to the atom includes all lone-pair electrons, plus half of the electrons shared with atoms of equal electronegativity, plus all electrons shared with atoms of lesser electronegativity. In this model, for the purpose of determining the oxidation numbers, the bonds between different atoms are treated as ionic; the atom with greater electronegativity is awarded all electrons in a bond. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 224/250 9/2/2019 Chem 110 Based on this rule, species in elemental form always have oxidation numbers equal to zero. Any monatomic ion has an oxidation number equal to its charge. In compounds, nonmetals (as being more electronegative) usually have negative oxidation numbers, but exceptions are known. Oxygen is usually −2 (with the exception of peroxides, where it is −1). Hydrogen is usually +1 when bonded to nonmetals, and −1 when bonded to metals (when it is called a hydride). The oxidation number of fluorine (the most electronegative element) is always −1 unless it is in elemental form. Other halogens are commonly −1 as well, but in compounds with more electronegative elements they have positive oxidation numbers. The sum of the oxidation numbers of all atoms must always add up to the overall charge of the species. Using the guidelines above, we can rewrite our redox reaction from equation C15-3-1 while explicitly showing oxidation numbers: C15-3-2 The metallic magnesium and molecular oxygen both have an oxidation number of 0. In the MgO product the magnesium ion (Mg2+) has a +2 oxidation number, while the oxide ion (O2−) has a −2 oxidation number. The overall reaction can be divided into two half-reactions that separately describe the oxidation and reduction processes: 2 + Mg(s) ⟶ Mg − O (g) + 4 e 2 C15-3-3 − + 2e C15-3-4 2 − ⟶ 2O The overall redox reaction (C15-3-2) is the sum of the two half reactions. However, in order for the overall redox reaction to be balanced, the overall number of electrons lost and gained in the half-reactions must be the same. We cannot lose only 2 electrons from magnesium and gain 4 electrons on oxygen. We must multiply all coefficients in the oxidation half-reaction (C15-3-3) by 2 before we add the half reactions to get the overall redox reaction. The activity series organizes metals in order of their reactivity with water or their ability to lose electrons In redox processes, the driving force for the reaction is based on the products being of lower energy than the reactants. In single exchange reactions, this means that electrons are transferred from a higher energy state in a more active metal to a lower energy state in less active metals. For example, in the reaction between zinc metal and copper sulfate, zinc ions replace copper ions in solution: Zn(s) + CuSO (aq) ⟶ ZnSO (aq) + Cu(s) 4 4 C15-3-5 In this reaction the zinc atom transfers two electrons to the copper ion, and zinc is oxidized. Its oxidation number changes from 0 to +2, while copper accepts two electrons and is reduced; its oxidation number changes from +2 to 0. The redox nature of this reaction is clearly apparent from the net ionic reaction: Zn(s) + Cu 2 + 2 + (aq) ⟶ Zn (aq) + Cu(s) C15-3-6 Zinc is a more active metal than copper; the valence electrons have higher energy in zinc metal than in copper metal. This difference in stability provides the driving force for this reaction. Similarly, the difference in the activity of different metals provides the driving force for other reactions of metals. Indeed, metals can be arranged according to their decreasing activity, forming the activity series. The most active metals lose electrons most easily, and are listed at the top. The inert metals that give up their electrons with great difficulty are listed at the bottom. The activity series is presented in Table T15-3-1. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 225/250 9/2/2019 Chem 110 Table T15-3-1. Activity series for metals Element Lithium Potassium Barium Active Calcium Sodium Magnesium Aluminum Manganese Zinc Chromium Iron Cadmium Cobalt Nickel Tin Lead Hydrogen Copper Silver Inert Mercury Platinum Gold Oxidation half reactions Li → Li + + e− K → K + + e− Ba → Ba 2+ + 2e− Ca → Ca 2+ + 2e− Na → Na + + e− Mg → Mg 2+ + 2e− Al → Al 3+ + 3e− Mn → Mn 2+ + 2e− Zn → Zn 2+ + 2e− Cr → Cr 3+ + 3e− Fe → Fe 2+ + 2e− Cd → Cd 2+ + 2e− Co → Co 2+ + 2e− Ni → Ni 2+ + 2e− Sn → Sn 2+ + 2e− Pb → Pb 2+ + 2e− H 2 → 2 H+ + 2e− Cu → Cu 2+ + 2e− Ag → Ag + + e− Hg → Hg 2+ + 2e− Pt → Pt 2+ + 2e− Au → Au 3+ + 3e− You may notice that the alkali and alkaline earth metals (group 1 and 2) appear at the top of the table (they are easily oxidized), which is consistent with their low ionization energy. Yet the activity series matches ionization energy trends only very crudely. For example, lithium is more active than potassium, even though it has a higher first ionization energy. Ionization energies measure the ease of removal of an electron from an isolated atom in the gas phase. However, the activity series represents the ease with which an electron may be removed from a solid-state metal and transferred to an ion in aqueous solution. From the point of view of the driving force of a single-exchange redox reaction, we can conclude that a metal higher in the activity series will reduce any metallic element below it and displace it from its compounds. Zn(s) will reduce Cu2+ (C15-3-5), and Cu(s) will reduce Ag+ , but no reaction will take place between Zn2+ and Cu(s), or between Cu2+ and Ag(s). The activity series includes hydrogen. All metals above hydrogen in the activity series react with water or aqueous acids to reduce H+(aq) to H2(g). The most active metals (K, Na, and Li, for example) react violently with water, reducing H+ within the water molecules. Less active metals like magnesium and zinc react sluggishly with water; Zn, for example, reacts imperceptibly slowly at room temperature. Increasing the temperature or adding acid can accelerate these reactions. In general, higher temperatures accelerate chemical reactions by increasing the energy of the reactants. The addition of an acid increases the concentration of H+ (which is actually in the form of H3O+) and facilitates the reaction. Examples of these reactions are provided below: 0 +1 2 K(s) + 2 H 0 +1 2 0 +1 Mg(s) + 2 H 0 +1 +1 2 0 O(ℓ) ⟶ 2 NaOH(aq) + H (g) C15-3-8 2 +2 2 C15-3-7 2 +1 2 Na(s) + 2 H 0 O(ℓ) ⟶ 2 K OH(aq) + H (g) 0 O(ℓ) ⟶ Mg(OH) (aq) + H (g) +2 0 Zn(s) + 2 H Br(aq) ⟶ ZnBr (aq) + H (g) 2 E15-3-10 2 2 C15-3-10 2 https://genchem.science.psu.edu/sites/default/files/filefnlBYE 226/250 9/2/2019 Chem 110 However, not all metals react with water. Metals that are below hydrogen in the activity series do not produce H2 in water , even at higher temperature or in the presence of acids. Such metals are commonly called noble metals because of their resistance to oxidation; they are often used in the production of jewelry because they do not tarnish in air. It is possible to oxidize noble metals if the acid used is a strong oxidant. For example, the noble metal copper reacts with nitric acid: copper is oxidized and the nitrogen of the nitrate ion is reduced, forming nitrogen dioxide. The oxidation states of Cu and N are included below the reaction in C15-3-11. 0 +2 +5 +4 C15-3-11 Cu(s) + 4 H N O (aq) ⟶ Cu(NO ) (aq) + 2 H O(ℓ) + 2 N O (g) 3 3 2 2 2 Gold is also a noble metal, and the least active of all metals. However, it can be oxidized by a 1:3 mixture of concentrated nitric and hydrochloric acid called aqua regia as shown in C15-3-12. The oxidation states of Au, N and H are included below the reaction. Notice that even though H+ is a reactant, its oxidation number does not change (it is not part of the redox process). In this case the nitrogen of the nitrate gets reduced, yielding nitrogen oxide. 0 +5 +1 − Au(s) + N O 3 + (aq) + 4 H +3 + 4 Cl − ⟶ AuCl https://genchem.science.psu.edu/sites/default/files/filefnlBYE − 4 +1 +2 (aq) + 2 H 2 O(ℓ) + N O(g) C15-3-12 227/250 9/2/2019 Chem 110 15-4 Stoichiometry Molar ratios of reactants and products expressed in balanced equations are the basis of all stoichiometric calculations Stoichiometry is the application of proportions to chemical reactions. It allows us to calculate and measure out the amounts of reactants needed to carry out a reaction, and to predict the amounts of products formed. It all starts with a balanced equation that describes the transformation taking place. For example, the coefficients in the equation for the combustion of hydrogen to yield water tell us that 2 molecules of hydrogen combine with one molecule of oxygen to form two molecules of water (C15-4-1). C15-4-1 2 H (g) + O (g) ⟶ 2 H O(l) 2 2 2 Table T15-4-1 Stoichiometry of combustion of H2 Equation 2 H 2(g) structures molecules mass (amu) amount (mol) mass (g) + O 2(g) + 2 molecules of H 2 4.0 amu of H 2 2 mol of H 2 4.0 g of H 2 + + + + → 2 H 2O(ℓ) → 1 molecule of O 2 32.0 amu of O 2 1 mol of O 2 32.0 g of O 2 → → → → 2 molecules of H 2O 36.0 amu of H 2O 2 mol of H 2O 36.0 g of H 2O We can express this information as the masses of elements participating in the reaction. Using atomic masses we calculate that two molecules of hydrogen have a mass of 4.0 amu, while a molecule of oxygen has a mass of 32.0 amu. When the reaction is over, we should have 36.0 amu of water. Of course, it is impractical to measure or manipulate such small quantities. Even if we wanted to carry out the reaction on a molecular scale, dealing with just a couple of molecules is extremely hard, if not impossible. We need to convert the proportions expressed in the chemical equation to practicable scale. The mole is the perfect "conversion" tool. On a macroscopic scale, the proportions are the same as on the microscopic scale; we have two moles of hydrogen (H2) reacting with one mole of oxygen (O2) to produce 2 moles of water (H2O). Instead of dealing with individual molecules, we deal with Avogadro's numbers of them. We can measure out the 4.0 g of H2 and 32.0 g of O2 needed to produce 36.0 g of H2O. We are also not limited to whole number molar quantities; we can double or quarter the scale of our reaction, or we can multiply the amounts by any whole or fractional multiplier. The mass ratio of the two reactants will always remain 1:8. The power of proportion will always deliver just the right relative amounts of reactants, and allows us to predict the amount of products that will be formed from any given amount of reactants. Basic stoichiometric calculations always rely on the proportion of moles of reactants and products, as derived from the stoichiometric coefficients of a balanced chemical equation (F15-4-1). The number of moles is commonly obtained from direct measurements of the masses of the substances involved. For gases, the number of moles can be obtained from the ideal gas law, given the pressure, volume and the temperature. For a given volume of solution, the number of moles may be obtained directly, if the molar concentration is known, or indirectly if the weight percent and mass of the solution or its density are known. Whatever information is available, finding the solution is a matter of converting the given values into moles using unit conversions and stoichiometry. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 228/250 9/2/2019 Chem 110 Figure F15-4-1. Basic stoichiometric calculations always rely on the proportions of reactants and products. These are derived from the stoichiometric coefficients of the balanced reaction equation. We convert experimentally measured quantities (mass, concentration, P,V,T of a gas) to moles using appropriate connections. A well-designed problem-solving strategy utilizing ICF tables facilitates all stoichiometric calculations Next we need to know how to use the information provided to solve stoichiometry problems. The real challenge in doing this is mapping out a problem-solving strategy without being distracted by side-tasks. The "moles of reactants" to "moles of products" ratio will always be at the center of our strategy (F15-4-1), while other calculations and conversions will play a "supporting" role. To be successful we must organize the given information and find connections between this information and the quantities we need to determine. The balanced chemical reaction, which provides the stoichiometric coefficients, is the most important part of this strategy. Starting with the balanced reaction, we can develop a basic template that will allow us to organize the given information and chart the steps we must execute to reach the solution. Basic Template: 1. Write the balanced chemical equation for the reaction. 2. Make an ICF table (Initial, Change, Final) below the equation and enter the given information. Make note of what you want to determine as well. Start by including a row to record experimental information given or to be determined and a row for additional information needed to make the connections to numbers of moles. In this second row, note connections between measured quantities and moles. I. When given mass, use formula weight (FW) to get numbers of moles. II. For solutions, use molarity (M) and volume (V) to get numbers of moles. III. For gases, use P, V, and T within the ideal gas equation to get numbers of moles. Below this initial information, add more rows for the initial number of moles, (I), calculated from the experimental quantities, the change in number of moles (C) as the reaction proceeds to completion, the change in experimental quantity, and the final number of moles (F) after the reaction is done. You may supplement the table with additional rows converting the number of moles into the masses of reactants and products. We will call this table the ICF table to indicate that it tracks the number of moles from their initial quantities to the final values. 3. Solve the problem. Fill in the table until you are able to solve the problem. I. Use the connections to convert given measured quantities into moles, and the final number of moles back to experimentally determinable quantities. II. Use the stoichiometry of the balanced reaction (the mole ratios) to relate the number of moles of reactants to the number of moles of products. III. Use conservation of mass (total mass of reactants = total mass of products) when it is appropriate. 4. Make sure your answer is reasonable. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 229/250 9/2/2019 Chem 110 As you peruse the examples provided to illustrate this problem-solving strategy, note that not all steps or connections are used for every problem, just as in some problems not all of the information provided will be needed to answer the questions asked. The ability to determine which information is relevant to the posed question is an important skill that is best developed through abundant practice. Consider this example of a combustion reaction: Example 1. If a clean-burning engine burns exactly 1 gallon of gasoline, how many grams of CO2 will it produce? Assume that the gasoline consists of only octane and that its density is d = 0.6929 g/mL. The essence of the reaction that the example addresses is the conversion of octane (and oxygen) to carbon dioxide (and water) as expressed in the balanced equation (C15-4-2): 2C H 8 18 (l) + 25 O (g) ⟶ 16 CO (g) + 18 H O(g) 2 2 2 C15-4-2 Our strategy for solving the problem will center around finding out how many moles of octane (C8H18) will burn, as it —being the sole carbon-containing reactant—will determine the number of moles of CO2 produced, taking into account the 2:16 molar ratio of the reactant (octane) to the product (CO2). The supporting calculations will include calculating the number of moles of octane available, and the conversion of moles of CO2 produced into grams of CO2. The complete calculations using our strategy outlined above are presented on a separate page, but the example brings into focus two additional concepts that we need to consider. In our example, we assumed that we had an excess of oxygen, and that the entire amount of octane was converted completely into the product. This may not always be the case. The theoretical and actual yields of products are determined by the amount of the limiting reactant The reactant that is used up first in a reaction is called the limiting reactant (or limiting reagent); its amount limits the amount of the product that can form in the reaction. Excess reagents are those present in quantities greater than necessary to completely react with the limiting reagent. In our example, octane was the limiting reactant, and oxygen was the excess reactant. The limiting reactant sets the upper limit on the amount of product that the reaction can produce. This amount is called the theoretical yield. The theoretical yield is the amount that will be produced if the reaction works perfectly, as predicted by the reaction’s stoichiometry. A calculation based on the balanced equation and the amount of limiting reactant available predicts a theoretical yield of products. In our example, we assumed that the octane was completely converted to CO2 as the only carbon-containing product; we calculated the theoretical yield of carbon dioxide. In practice, the actual yield, the amount actually obtained from the reaction, is less than the theoretical yield. This outcome may be due to an incomplete reaction, side reactions (formation of other products), or mechanical losses during the separation of the product from the reaction mixture. During hydrocarbon combustion, other carbon containing products may form, such as carbon monoxide or soot (carbon particles); these are formed in side reactions that decrease the actual yield of the expected product. We neglected such complications in our example by assuming there would be clean, complete combustion. In general, chemists calculate percent yield using equation E15-4-1. The percent yield is usually less than 100%, and cannot ever be more than 100%. Efficient reactions have high yields (>90%). actual yield % yield = × 100% E15-4-1 theoretical yield Many commercially important products, such as pharmaceuticals, are produced in multistep reactions. If the synthesis (preparation from simpler components) involves just 7 steps and each has 90% yield, the desired product is obtained in only 48% yield (0.97), meaning that over 50% of the materials are lost in the entire process. This simple calculation illustrates the importance of finding reaction conditions that maximize the percent yield. For example, we might change the temperature or add a catalyst. To understand how to use the limiting reagent, let's consider another example: https://genchem.science.psu.edu/sites/default/files/filefnlBYE 230/250 9/2/2019 Chem 110 Example 2. Lithium oxide is used on the space station to remove water from the air via the following reaction. If we need to remove 100.0 kg of water and 82.00 kg of Li2O is available, which is the limiting reactant? How much product is formed? Li O(s) + H O(g) ⟶ 2 LiOH(s) 2 2 C15-4-3 In this example, the mole ratio of the two reactants is 1:1. In cases like this we can determine the limiting reagent by comparing the number of moles of each reactant. The limiting reagent will be the one with the smaller number of moles. The complete calculations for this example are presented on a separate page. When the mole ratio of reactants is not 1:1, or if more than two reactants are involved, it is a bit harder to determine which is the limiting reagent. There are two approaches to determining the limiting reactant. The first approach is to choose one of the reactants (usually the first one in the balanced reaction) and determine the number of moles of the second reactant needed to react completely with the first by using the stoichiometric mole ratio. If the number of moles of the second reactant is equal to or greater than the number of moles needed to react completely, then the first reactant is the limiting reagent (it will be used up completely). However, if there is not enough of the second reactant to react completely, then the second reactant is the limiting reagent. The second approach is to assume in turn that each reactant is the limiting reagent and calculate the number of moles (or mass) of one of the products. The limiting reagent is the one that produces the smaller amount of product. We will illustrate both of these methods in Example 3: Example 3. Silicon carbide (SiC) is widely used in the production of car brakes (because of its abrasiveness and high thermal endurance) and in the production of high-temperature semiconductor electronics. It is made from sand (SiO2) and carbon at high temperatures. CO is also formed as shown in C15-4-4. If 100.0 kg of sand reacts with 100.0 kg of C, and 55.0 kg of SiC are formed, what is the percent yield? SiO (s) + 3 C(s) ⟶ SiC(s) + 2 CO(g) 2 C15-4-4 Since we base the percent yield calculation on the amount of the limiting reagent available, we need to start by determining which reagent is present in a limiting amount. Reaction stoichometry indicates that in this case, we need three times as many moles of carbon as SiO2; our calculations (see this separate page), therefore, must account for this ratio. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 231/250 9/2/2019 Chem 110 15-5 Example calculations Stoichiometric calculations are central to quantitative analysis of chemical reactions Stoichiometry calculations form the basis of quantitative examination of chemical reactions with regard to mass balance, but their use is not limited to calculating the masses of products and their yields. We can apply these concepts to any chemical reaction, including combustion, elemental analysis, redox reactions, solution reactions, acid-base reactions, titrations, or reactions of gases (utilizing the ideal gas law). To be able to apply our problem-solving template to such situations we have to understand the nature of the experiment so we can extract and interpret the numerical data correctly. Elemental analysis applies stoichiometry to determine compositions of compounds For example, you may recall that when we discussed molecular composition we used elemental analysis based on the combustion of a known amount of the sample. Now that we understand reactions better, let’s consider another example of calculations directed toward finding the empirical formula from the experimental data. Example 4. An alcohol is composed only of C, H, and O. A 4.00 g sample of the alcohol is completely combusted with an excess of oxygen, producing 7.65 g of CO2 and 4.70 g of H2O. What is the empirical formula of the alcohol? To get the empirical formula we need to determine the molar ratio of the elements present, x:y:z in CxHyOz. In this case we cannot start with the balanced equation for combustion as we do not know the formula of the alcohol, which is precisely what we need to find out. We know that the complete combustion will convert all carbon atoms present in the alcohol into carbon dioxide and all hydrogen atoms into water. We will not be able to directly learn about the oxygen content because oxygen atoms are present in both reactants (the alcohol and O2) and both products (CO2 and H2O). However, we have information on the identity (CO2 and H2O) and the mass of the products formed in the combustion. Thus, we can calculate both the molar ratio of carbon to hydrogen and the mass of carbon and hydrogen in the products. Applying the mass conservation law, we can then calculate the mass of oxygen in the sample as we know the mass of the sample that was analyzed. The calculations in this case proceed in the "reverse" order; we start with masses of products to learn about the composition of the reactants, but the use of stoichiometric proportions (F15-4-1) and the overall scheme of "connecting" masses with moles remain the same. Titrations illustrate concentration-based stoichiometry calculations for reactions in solution The example above illustrates how molar ratios are the true underpinning of stoichiometric calculations. If molar information can be obtained by other means, such calculations do not need to involve masses of reactants or products. For example, consider a titration experiment where a known volume of solution with an unknown concentration is allowed to react with a solution of known concentration called the titrant. The volume of the titrant needed to react completely with the unknown can be measured, and the concentration of the unknown solution can then be determined using the stoichiometry of the balanced reaction. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 232/250 9/2/2019 Chem 110 Figure F15-5-1. Titration of an acid with a base. A sample of H2SO4 (aq) of unknown concentration (the analyte) is analyzed. A base solution of known concentration (the titrant) is added dropwise from a burette (a long, calibrated tube with a stopcock at the bottom end). Phenolphthalein is added to the H2SO4 solution and acts as an indicator by turning the solution pink when a small excess of base is added beyond the equivalence point. In the example shown, the volume of titrant used is 12.3 mL. In an acid-base neutralization reaction experiment (F15-5-1), a strong base of known concentration is added dropwise to a solution of a strong acid of unknown concentration (or vice versa) and the volume needed to reach the equivalence point (or endpoint) is measured. The titration equivalence point is the point when the amount of H+ and HO− ions in the solution is equal, usually indicated by a change in the color of an indicator added to the solution. Example 5. If 12.3 mL of 0.200 M NaOH solution is needed to neutralize 10.0 mL of H2SO4 solution, what is the concentration of H2SO4? Since we want to find the concentration of sulfuric acid, we want to use the balanced molecular equation rather than the net ionic equation. Taking into account that sulfuric acid is a diprotic acid (it can give up two H+ ions), we need two moles of NaOH for each mole of the acid to neutralize it completely. The numbers of moles present in solution are easily obtained if the molar concentrations are known (n = V × M). In this case, the stoichiometric calculations follow the basic template. The full solution is presented on a separate page. Stoichiometric calculations involving gases utilize the ideal gas law to quantify moles of gaseous reactants and products Gas reactions are also amenable to stoichiometric calculations, and may involve volume or pressure rather than mass quantities. In general, the ideal gas law provides sufficient accuracy for reactions near room temperature and under relatively low pressures. In many cases, even further simplifications are possible. To illustrate, let’s consider another example: Example 6. A reaction between ozone (O3) and water was carried out at 40 °C and 780 mmHg as shown in C15-5-1 below. How many liters of ozone are needed to produce 3 L of O2? O (g) + H O(l) ⟶ H (g) + 2 O (g) 3 2 2 2 C15-5-1 Given the balanced equation and a specified temperature and pressure, one might be tempted to use the ideal gas law to calculate the number of moles. However, that is unnecessary, as all measurements are of gases at constant P and T. Under these conditions, the number of moles is directly proportional to the gas volume as stated in Avogadro's law (n = V(P/RT)const). From the reaction stoichiometry we can set up a simple proportion: one mole of ozone produces 2 moles of oxygen, and thus 1 L of ozone produces 2 L of O2. Therefore, we need 1.5 L (1 × 3/2 L) of ozone to produce 3 L of O2. In other reactions involving gases the use of the ideal gas law may be needed. Such is the case in heterogeneous reactions combining masses of solid species or concentrations of solutions with gas calculations. We always convert the given information to moles, and use the stoichiometry of a balanced reaction. Let’s consider the following example: https://genchem.science.psu.edu/sites/default/files/filefnlBYE 233/250 9/2/2019 Chem 110 Example 7. Sodium azide, NaN3, is used in automobile airbags to produce a large volume of N2 gas within milliseconds of a collision as shown in C15-5-2 below. How many liters of N2 gas at 735 mmHg and 26 °C are produced from 126 g of NaN3? 2 NaN (s) ⟶ 2 Na(s) + 3 N (g) 3 2 C15-5-2 This calculation follows the established pattern. Since we are already given the balanced reaction, we follow our standard template and first calculate the number of moles of sodium azide available and then, using reaction stoichiometry, calculate the number of moles of N2 produced. Only in the final stages of our calculations we use the ideal gas law to calculate the volume of gas formed under the specified conditions. As the result of our calculations illustrate, a relatively small sample of solid NaN3 can very rapidly provide a large quantity of gas that fills the airbag, cushioning the car occupants and minimizing the effects of a collision. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 234/250 9/2/2019 Chem 110 16 Thermochemistry Many of the reactions and physical processes that we have studied over the course of several lessons are associated with the flow of heat between a system and its surroundings. Heat flow can be measured using calorimetry, and the enthalpies of known reactions can be used to calculate or estimate the enthalpies of other processes with the help of Hess's law. 16-1 Reaction enthalpies If the products are more stable than the reactants, heat is released to the surroundings in an exothermic reaction. Conversely, when a reaction is endothermic, heat flows from the surroundings into the system. Numerical information about the heat exchanged with the surroundings may be included in balanced chemical equations describing the process, called thermochemical equations. The enthalpy of a reaction is an extensive property, and depends on the state of reactants and products. For the reverse reaction, the enthalpy has the same magnitude but opposite sign. 16-2 Calorimetry The heat exchanged by reactions with the surroundings can be measured using calorimetry. If the heat capacity of the immediate surroundings is known, the amount of heat transferred can be calculated from the change in the temperature of the surroundings. Such measurements can be carried out under constant pressure in an insulated calorimeter open to the atmosphere, or at constant volume in a bomb calorimeter. 16-3 Hess's law Hess's law states that the sum of the enthalpies for a series of steps is the same as ΔH for the overall process. This conclusion is based on enthalpy being a function of state. The change in enthalpy does not depend on the specific steps or the number of steps, only on the initial and final state. Based on Hess's law, thermodynamic cycles can be constructed that allow us to determine enthalpies for reactions that cannot be measured directly. These reactions can be incorporated into thermodynamic cycles in which the enthalpies of other steps are known. Hess's law gives us the conceptual underpinning for using enthalpies of formation (ΔH°f) and bond dissociation energies (BDEs) to evaluate the enthalpy for a large number of reactions based on a limited amount of data. 16-4 Enthalpies of formation The enthalpy of formation (ΔH°f) represents the amount of heat released or absorbed when 1 mole of a compound is made from pure elements in their most stable form under the standard conditions of 298 K and 1 atm. Elements in their most stable form at standard conditions are assigned enthalpies of formation equal to zero, and serve as a reference point on the energy scale. A large number of standard enthalpies have been measured for inorganic and organic compounds. With the help of Hess's law, these values can be used to calculate and predict the enthalpy of reaction without the necessity of carrying out the actual measurements. In general, compounds or systems of the same composition that have a lower (more negative) enthalpy of formation are more stable than those with a higher enthalpy of formation. 16-5 Bond energies The amount of energy required to break a bond in such a way that the bonding electrons are equally divided between the resulting fragments is called the bond dissociation energy (BDE). BDEs also represent values at standard conditions; in most cases the average values for a given bond type are used. Reaction enthalpies may be estimated by comparing BDEs of bonds broken and bonds formed. If the sum of the BDEs of bonds formed is larger than that for bonds broken, the reaction is exothermic. The BDEs provide a link between the structural aspects responsible for bond strengths and reaction thermochemistry, which often dictates reactivity. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 235/250 9/2/2019 Chem 110 16-1 Reaction enthalpies Spontaneous reactions typically have favorable enthalpy or entropy In Chapter 15 we have learned about many physical processes and chemical reactions associated with energy changes. In the vast majority of these processes, the energy transfer between the system of interest and the surroundings takes place under constant pressure. Under such conditions, enthalpy is the preferred way to account for the heat flow and PVwork (if any). In many reactions volume changes are very small, and the change in enthalpy corresponds to the change in the internal energy of the system. We cannot directly measure the total enthalpy, but we are only interested in changes of enthalpy. Specifically, for a chemical reaction, its enthalpy is the difference in enthalpy between the product and the reactants, ΔHrxn = H(products) − H(reactants). If the products are more stable (have lower enthalpy) then ΔHrxn < 0, the energy is transferred to the surroundings, and the reaction is called exothermic. If the reverse is true and the reactants are more stable (have lower enthalpy) than the products, then ΔHrxn > 0, the energy is provided by the surroundings, and the reaction is deemed endothermic. For example, a reaction between hydrogen and oxygen resulting in the formation of water is exothermic (F16-1-1). Water is more stable (i.e. has lower enthalpy) than H2 and O2. The reaction is accompanied by a release of energy to the surroundings. Figure F16-1-1. Energy diagram of the exothermic reaction between H2 and O2. The enthalpy of the product (H2O) is lower than the combined enthalpy of the reactants. In this reaction, the energy is released in the form of heat, light (as a flame), and acoustic waves (result of high kinetic energy and velocity of gas molecules). The air temperature around the exploding balloon is measured by a thermocouple (a wire thermometer) and the acoustic wave is registered by a smartphone app for illustrative purposes. The actual measurement of enthalpy change for this reaction can be done in a bomb calorimeter. Other reactions may be endothermic, giving products that are less stable than the reactants. Such reactions are much less likely to take place unless they have some other driving force, such as an increase in the entropy of the system. For example, the spontaneous reaction between barium hydroxide octahydrate and ammonium thiocyanate results in the formation of barium thiocyanate, ammonia and water. The large number of small molecules produced increases the disorder of the system, making the entropy change highly favorable. (F16-1-2). This increase in entropy is similar to the dissolution process, where the transformation from an ordered crystalline solid to a large number of hydrated ions in solution resulted in a favorable entropy change. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 236/250 9/2/2019 Chem 110 Figure F16-1-2. Energy diagram of the endothermic reaction between barium hydroxide octahydrate and ammonium thiocyanate that produces barium thiocyanate, ammonia, and water. The reaction is entropy-driven and the heat needed for the reaction is provided by the surroundings. The temperature of the air around the solution drops due to the heat being absorbed from the surroundings, which is sufficient to freeze a small amount of water under the beaker, fusing it to the wooden base. Thermochemical equations include enthalpies of reactions We can now supplement our balanced chemical equation with the value of enthalpy associated with the specific reaction defined by the equation. Since enthalpy is an extensive property (it depends on the amount of matter in the system), in such thermochemical equations the value of enthalpy given corresponds to the numbers of moles specified by the stoichiometric coefficients. For example, in the complete combustion of one mole of methane 802.3 kJ of energy is released to the surroundings (C16-1-1). CH (g) + 2 O (g) ⟶ CO (g) + 2 H O(g) 4 2 2 2 Δ Hr xn = −802.3 kJ C16-1-1 Notice the negative sign of the reaction enthalpy; this is as expected for an exothermic process. In contrast, the enthalpy of the reverse reaction has the same magnitude, but opposite sign (C16-1-2). Such a strongly endothermic process is highly unlikely to be spontaneous. There is no entropic driving force as both sides have the same number of molecules. CO (g) + 2 H O(g) ⟶ CH (g) + 2 O (g) 2 2 4 2 Δ Hr xn = 802.3 kJ C16-1-2 The enthalpy of the reaction depends on the states of the reactant and products. You may recall that phase transitions change the energy of the system, and therefore the phase transition enthalpies must be taken into consideration. For example, if liquid water is the product of methane combustion, the thermochemical equation is: CH (g) + 2 O (g) ⟶ CO (g) + 2 H O(l) 4 2 2 2 Δ Hr xn = −890.3 kJ C16-1-3 The additional 81.3 kJ (as compared to C16-1-1) of energy is released from the condensation of two moles of water. If we start with a different amount of reactants, for example two moles of methane instead of one, we double the amount of heat released. For the combustion of two moles of methane producing gaseous water we can write: 2 CH (g) + 4 O (g) ⟶ 2 CO (g) + 4 H O(g) 4 2 2 2 Δ Hr xn = −1604.6 kJ C16-1-4 The relationships described by the thermochemical equations are often shown graphically in relative energy diagrams. The diagrams relate information about the changes between different energy states of reactants and products, but do not address the energy contents of any species listed. We will later learn how to establish a reference point for our energy diagrams. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 237/250 9/2/2019 Chem 110 Figure F16-1-3. Graphical representation of energy changes for the combustion reaction of one mole of methane. Exothermic processes are shown with an arrow pointing downwards, from a higher energy state to a lower energy state. Before we continue, let's summarize what we have learned about enthalpy of reactions: 1. Enthalpy is an extensive property. 2. When we reverse a reaction (or process) the magnitude of the enthalpy is the same but the sign is reversed. 3. The enthalpy of a reaction (or process) depends on the state of the reactants and products. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 238/250 9/2/2019 Chem 110 16-2 Calorimetry The amount of heat exchanged between the reaction participants and the surroundings is measured using a calorimeter The measurement of the energy released or absorbed by a system during a reaction or any physical process is called calorimetry (i.e., the measuring of calories). A calorie (cal) is an energy unit based on the heat capacity of water. By definition, 1 cal will increase the temperature of 1.000 g of water by 1 °C (from 14.5 °C to 15.5 °C). One calorie is equal to 4.184 J. We did, in fact, already encounter heat capacities when we discussed heating curves in the context of phase transitions. The idea behind calorimetry is that with known heat capacities we can measure heat flow by measuring temperature changes. The basic equation that we use to calculate the heat transferred when heating a single phase is as follows: E16-2-1 q = m × C × ΔT The heat released by a system must equal the heat absorbed by the surroundings, and conversely, the heat absorbed by a system must equal the heat lost by the surroundings. In most cases, we define the system as the molecules of reactants and products. Everything else in the direct vicinity of the system is defined as the surroundings, including the solvent (for example, water) in which the reaction takes place, the thermometer, and the container. Measurement of the temperature increase in a coffee-cup calorimeter is needed to determine the heat of a neutralization reaction Although an actual calorimeter that is used to obtain precise measurements is much more sophisticated, we can illustrate its operating principles through the example of a simple coffee cup calorimeter (Figure 16-2-1). We usually use nested coffee cups for better thermal insulation. We want to make sure that all heat produced (or absorbed) by our system of interest stays trapped in our measuring device, rather than being lost to the surrounding air. The calorimeter is not sealed, but is open to the atmosphere so that the reaction is run under constant pressure. Let's say we want to measure the heat of the neutralization reaction between aqueous solutions of HCl and NaOH. We have 50 mL of a 1.0 M solution of each reagent at 19 °C. First we pour the NaOH solution into our cup calorimeter, which is equipped with a stirring rod, a thermometer and a stopper. The HCl solution is added, and then we close the stopper, stir the solution, and observe that the temperature rises to 26 °C. Figure F16-2-1. Coffee cup calorimeter. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 239/250 9/2/2019 Chem 110 The calculation of the heat transferred takes into account that we have a total of about 100 mL of an aqueous solution with a density close to 1 g/mL. The specific heat of water (Cm) is 4.18 J/g-K. The temperature change was ΔT = Tfinal − Tinitial = 26 °C − 19 °C = 7 °C = 7 K. Thus, the heat absorbed by our calorimeter (which is part of the surroundings) is calculated using E16-2-1: J q = m × C × ΔT = 100 g × 4.18 g ⋅ K × 7 K = 2.9 kJ E16-2-2 The amount of heat released by our neutralization reaction (which is the system) is the same amount as that absorbed by the calorimeter (the surroundings). Since our reaction mixture contained 0.05 mole of H+ and 0.05 mole of HO− (n = 50 mL × 1.0 M), we must divide our total heat transferred by the number of moles to find the amount of heat transferred per mole. Therefore, the heat of the neutralization reaction is ΔHrxn = −2.9 kJ/0.05 mole = −58 kJ/mol (C16-21). + H − (aq) + HO (aq) ⟶ H O(l) 2 Δ Hr xn = −58 kJ/mol C16-2-1 Of course, we can expect that our value for the enthalpy of the neutralization is approximate. We neglected any temperature changes to the cup calorimeter itself, and we made a number of simplifying assumptions about the density, the mass of the solution, and the specific heat of the solution (we assumed it to be pure water). Surprisingly, our value is very close to the values obtained with much more sophisticated calorimeters. Indeed, depending on circumstance, the heat of neutralization of many acid-base reactions is around −57 to −59 kJ/mol. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 240/250 9/2/2019 Chem 110 16-3 Hess's law Hess’s law is used to determine enthalpies of reactions that cannot be measured directly Enthalpy is a state function. It does not depend on the path or the number of steps needed to convert the reactants into products. The energetic outcome is determined simply by the enthalpy difference between the final and the initial states. This conclusion is known as Hess's law: the sum of the enthalpies for a series of steps is the same as ΔH for the overall process (F16-3-1). A → B ΔH1 B → C ΔH2 -----------------------A + B → B + C ΔH1 + ΔH2 = ΔHrxn A → C ΔH1 + ΔH2 = ΔHrxn Figure F16-3-1. Hess's Law energy diagram. The enthalpy change between A and C is the same regardless of whether the transformation happens in one step from A → C, or through a series of steps as in A → B → C. Thermochemical equations can be treated as algebraic equations; they can be added to or subtracted from each other and equivalent terms present on both sides of the equations can be canceled. Graphical representations of Hess's law (F16-3-1) are called thermodynamic cycles, and as the name illustrates, the initial and final states are connected by two different paths forming a loop along which reactants can travel to get to the product. Hess's law allows us to calculate the enthalpy of processes that cannot be measured directly. You may recall its application to calculate lattice energies. In general, this means that a relatively small number of experimentally measured enthalpies can be used to calculate ΔH for a vast number of reactions by using different combinations of enthalpy values. The enthalpy of a reaction that cannot be measured directly is determined algebraically or graphically using an appropriate thermodynamic cycle Let's return to our example of the combustion of methane (C16-3-1). We know that the combustion of one mole of methane releases 890.3 kJ of heat. In an independent experiment we can measure the combustion of one mole of carbon monoxide to carbon dioxide: we find that it produces 283.0 kJ of heat (C16-3-2). How much heat is produced when one mole of methane is combusted to form carbon monoxide (C16-3-3)? This measurement is experimentally impossible to carry out, since controlling the degree of oxidation of carbon to form only CO (instead of CO2 or a mixture) in a combustion reaction cannot be done. CH (g) + 2 O (g) ⟶ CO (g) + 2 H O(l) 4 CO(g) + 2 1 2 2 O (g) ⟶ CO (g) CH (g) + 1 4 2 2 1 2 2 O (g) ⟶ CO(g) + 2 H O(l) 2 2 Δ H1 = −890.3 kJ C16-3-1 Δ H2 = −283.0 kJ C16-3-2 Δ H3 = ? C16-3-3 From an "algebraic" point of view we observe that in C16-3-3 we have one molecule (or mole) of methane on the left side of the equation and one molecule (or mole) of carbon monoxide on the right side of the equation. Since we need to have CO as a product, we need to subtract equation C16-3-2 from equation C16-3-1. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 241/250 9/2/2019 Chem 110 CH (g) + 2 O (g)−CO(g)− 4 2 1 2 O (g) ⟶ CO(g) + 2 H O(l)−CO (g) 2 2 2 C16-3-4 In C16-3-4 the CO2 molecules on the product side cancel out, and subtracting half a mole of dioxygen from the 2 moles on the reactant side gives us 3/2 of a mole of dioxygen (2 O2 − ½ O2 = 1½ O2). Since CO is subtracted from the reactant side, we can move the CO molecules to the product side (with a change of sign to the stoichiometric coefficient). We then obtain the exact equation of interest laid out in C16-3-3. Since we subtracted the chemical equations to get the overall reaction, we must also subtract the enthalpies to get the overall enthalpy. Thus, ΔH3 = ΔH1 − ΔH2 = −890.3 kJ − (−283.0 kJ) = −607.3 kJ. The same information can be presented graphically (F16-3-2) in the form of a thermodynamic cycle. All reactions involved are exothermic, with arrows pointing downward toward systems with lower energy. Figure F16-3-2. Hess's law applied to the combustion of methane. The enthalpy of combustion of methane to carbon dioxide (ΔH1) and the enthalpy of combustion of carbon monoxide to CO2 (ΔH2) can be measured experimentally. The enthalpy of combustion of methane to CO cannot be measured, but it can be calculated from the thermodynamic cycle presented here. Note that the composition is the same on each energy level of the diagram (1 C + 4 H + 4 O). Energy and stability comparisons can only be made for systems of exactly the same composition. This example illustrates that enthalpies of reactions establish a relative stability scale for systems of the same composition. It is directly apparent from the plot that carbon dioxide and water are more stable (have lower energy) than methane and oxygen, with partial oxidation products (carbon monoxide) occupying the middle ground. If we could anchor our relative scale to a preset reference point for energy, we would have an absolute energy scale. In the next section, we will describe how this is done. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 242/250 9/2/2019 Chem 110 16-4 Enthalpies of formation The standard enthalpies of formation of compounds use pure elements as a zero-enthalpy reference point To compare the energy (and enthalpy) changes on a common scale, it is a chemical convention to use elements in their most stable form as a reference. Since enthalpy depends on the conditions (P and T) and the state (gas, liquid, or solid) of a system, a set of standard conditions has been designated to be 298 K (25 °C) and 1 atm of pressure. Notice that these standard thermodynamic conditions are different than the STP for gases (T = 273.16 K or 0 °C, and 1 atm). Under these standard conditions (designated by a superscript "°"), the standard enthalpy of formation for a compound (ΔH°f) may be defined as the amount of heat absorbed or released when one mole of the compound is formed from elements in their most stable form. Under standard conditions, the enthalpy of formation of a pure element in its most stable form is assigned a value of zero. The standard enthalpy of the formation of liquid water ΔH°f (H2O) is obtained by measuring the heat of combustion of hydrogen: H (g) + 2 1 2 ∘ O (g) ⟶ H O(ℓ) 2 2 Δ Hr xn = −285.8 kJ/mol = Δ H f (H O) 2 C16-4-1 This process can be visualized with our standard energy graph (F16-4-1). The reaction is exothermic (with a downward arrow), but our starting point is now defined as the zero-enthalpy level (the top level, where the elements are in their most stable form). Thus the standard enthalpy of water is also defined. Similarly, the enthalpy of combustion of 1 mole of carbon (graphite) under standard conditions provides the standard enthalpy of formation of carbon dioxide (C16-42). ∘ C(s) + O (g) ⟶ CO (g) 2 Δ Hr xn = −393.5 kJ/mol = Δ H 2 f (CO ) 2 C16-4-2 Figure F16-4-1. Standard heats of formation of water and carbon dioxide. The standard heats of formation of elements or elemental compounds are zero (by definition). The enthalpies of formation correspond to the heat of the combustion reactions shown. The method is not limited to reactions involving elements as reactants. Here we can again use our example of the combustion of methane under standard conditions: ∘ CH (g) + 2 O (g) ⟶ CO (g) + 2 H O(l) 4 2 2 2 Δ Hr xn = −890.3 kJ C16-4-3 Let's start by drawing an energy diagram for this reaction (F16-4-2). Methane is composed of one carbon atom and four hydrogen atoms. We can analyze their combustions individually. We first combust one mole of graphite to get one mole of carbon dioxide, which produces 393.5 kJ/mol of heat (see above). This is followed by the combustion of 2 moles of hydrogen to produce water and 571.5 kJ of heat (2 moles × −285.8 kJ/mol), for a total heat transfer of –965.1 kJ. In total, we have formed 1 mole of CO2 and 2 moles of H2O, which is exactly the same amount of the same products as formed by the combustion of 1 mole of methane. Since the combustion of methane only gives −890.3 kJ/mol, we can place its energy 890.3 kJ/mol above the energy of products of its combustion (CO2 and 2 H2O), or 74.8 kJ/mol below the reference point (which is the pure elements). Using Hess's law, we have thus established the enthalpy of formation of methane: ΔH°f (CH4) = −74.8 kJ/mol. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 243/250 9/2/2019 Chem 110 Figure F16-4-2. Hess's thermodynamic cycle for the combustion of methane under standard conditions. The enthalpy of combustion of methane is compared with the sum of the enthalpies of combustion of one mole of C(graphite) and two moles of H2. The comparison shows that formation of methane from elements is exothermic by −74.8 kJ/mol. Therefore, ΔH°f (CH4) = −74.8 kJ/mol. Click on the picture for a stepwise analysis of the thermodynamic cycle. The standard enthalpies of formation are available for a large number of compounds in thermodynamic tables Table T16-4-1. Selected standard enthalpies of formation, ΔH°f (298 K, 1 atm) Substance Formula acetic acid acetylene ammonia aluminum oxide benzene bromine calcium carbonate calcium oxide carbon dioxide carbon monoxide carbon tetrachloride diamond ethane ethanol ethanol ethyl bromide ethylene formaldehyde glucose C 2H4O2(ℓ) C 2H2(g) NH 3(g) Al 2O3(s) C 6H6(ℓ) Br 2(g) CaCO 3(s) CaO(s) CO 2(g) CO(g) CCl 4(ℓ) C(s) C 2H6(g) C 2H5OH(g) C 2H5OH(ℓ) C 2H3Br(g) C 2H4(g) CH 2O(g) C 6H12O6(s) ΔH° f (kJ/mol) −487.0 226.8 −46.2 −1675.7 49.0 30.907 −1207.1 −635.5 −393.5 −110.5 −193.3 1.9 −84.7 −235.1 −277.7 −97.6 52.3 −108.6 −1273.0 https://genchem.science.psu.edu/sites/default/files/filefnlBYE Substance Formula hydrogen bromide hydrogen chloride hydrogen fluoride hydrogen iodide hydrogen peroxide iron(III) oxide methane methanol ozone propane silver chloride sodium bicarbonate sodium carbonate sodium chloride sodium hydroxide sucrose sulfur trioxide water water vapor HBr(g) HCl(g) HF(g) HI(g) H 2O2(ℓ) Fe 2O3(s) CH 4(g) CH 3OH(ℓ) O 3(g) C 3H8(g) AgCl(s) NaHCO 3(s) Na 2CO3(s) NaCl(s) NaOH(s) C 12H22O11(s) SO 3(g) H 2O(ℓ) H 2O(g) ΔH° f (kJ/mol) −36.2 −92.3 −268.6 25.9 −187.8 −824.2 −74.8 −238.6 142.3 −103.8 −127.0 −947.7 −1130.9 −410.9 −425.6 −2221.0 −395.2 −285.8 −241.8 244/250 9/2/2019 Chem 110 Analogous procedures have been carried out for a variety of compounds, and the standard enthalpies of formation have been determined. Some values are listed in Table T16-4-1. A much more extensive list is available in our data tables (the button on the top of the web page). There are some important general observations that can be made by analyzing even this small subset of the data. Although most enthalpies of formation are negative (indicating that the compounds are more stable than the elements from which they are made) this is not universally true. There are multiple examples of stable compounds (for example acetylene or benzene) that have positive enthalpies of formation. Such compounds do not decompose spontaneously into their elements because there is no low-energy mechanistic path available, even though the elemental products are more stable; the path to get to these products often requires a high-energy intermediate step. You might also notice that less-stable forms of elements have positive enthalpies of formation (for example, diamond is a less stable form of carbon than graphite). Different states of the same substance also differ in their heats of formation. For example, liquid water has a lower enthalpy of formation than water vapor, and the difference is equal to the amount of heat released upon the condensation of one mole of water vapor. Enthalpies of reactions are calculated by subtracting the sum of the enthalpies of formation of the reactants from those of the products With the help of Hess's law, the heats of formation become a powerful tool for evaluating the thermochemistry of a reaction. Let's once more return to the combustion reaction of methane, this time listing the heats of formation under each species: ∘ CH (g) + 2 O (g) ⟶ CO (g) + 2 H O(ℓ) 4 2 2 Δ Hr xn 2 C16-4-4 ∘ ΔH − 74.8 f 0 − 393.5 2(−285.8) − 890.3 (kJ/mol) We have, in fact, already analyzed the thermochemistry of this reaction in our energy chart (F16-4-2). We were able to find the enthalpy of formation of methane based on its heat of combustion and the heats of formation of carbon dioxide and water. Using the same cycle we can rewrite our calculation in general terms as: ∘ ΔH f ∘ (CH ) + 2 × Δ H 4 f ∘ ∘ (O ) + Δ Hr xn = Δ H 2 f ∘ (CO ) + 2 × Δ H 2 f E16-4-1 (H O) 2 We are essentially restating that the two paths must have the same enthalpy according to Hess's law. The first path goes from elements to carbon dioxide and water through the combustion of methane, and the second path starts with direct combustion of elements. We can rearrange our equation to express the standard enthalpy of combustion as a function of enthalpies of formation of reactants and products. ∘ ∘ Δ Hr xn = [Δ H f ∘ (CO ) + 2 × Δ H 2 f ∘ (H O)] − [Δ H 2 f ∘ (CH ) + 2 × Δ H 4 f (O )] 2 E16-4-2 The result indicates that the enthalpy of the reaction is equal to the difference between the enthalpies of formation of products and enthalpies of formation of reactants multiplied by the appropriate stoichiometric coefficients (2 for water and 2 for oxygen). This result is, of course, general, as expressed in E16-4-3 where n and m stand for the appropriate stoichiometric coefficients of all products and reactants, respectively: ∘ ∘ Δ Hr xn = ∑ nΔ H f ∘ (products) − ∑ mΔ H f E16-4-3 (reactants) We can use this relationship to evaluate the enthalpy of one spectacularly exothermic reaction, the so-called thermite reaction between aluminum powder and iron oxide (C16-4-5). 2 Al(s) + Fe O (s) ⟶ Al O (s) + 2 Fe(s) 2 3 2 3 C16-4-5 Δ Hr xn = ? You may recall that aluminum is higher in the metal activity series than iron and it oxidizes at the expense of iron oxide (which is reduced). Thus, our reaction is expected to be exothermic. ∘ Δ Hr xn = [Δ H ∘ f ∘ (Al O ) + 2 × Δ H 2 3 f ∘ (Fe)] − [2 × Δ H https://genchem.science.psu.edu/sites/default/files/filefnlBYE f ∘ (Al) + Δ H f (Fe O )] 2 3 E16-4-4 245/250 9/2/2019 Chem 110 The standard heat of formation of aluminum oxide is highly exothermic, ΔHof(Al2O3) = −1675.7 kJ/mol, but the heat of formation for iron oxide is less so ΔH°f(Fe2O3) = −824.2 kJ/mol. The standard heats of formation of elemental metals are zero by definition. Thus, the enthalpy of the reaction is ΔH°rxn = −1675.7 kJ/mol − (−824.2 kJ/mol) = −851.5 kJ/mol. The heat produced during the reaction (F16-4-2) is sufficient to melt the iron formed in the reaction (mp = 1,535 °C). Figure F16-4-3. The thermite reaction between aluminum and iron oxide is highly exothermic. Once initiated by a flame, it produces sufficient heat to melt the iron formed in the reaction, which glows yelloworange as it drips into the sand trap below the reaction vessel. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 246/250 9/2/2019 Chem 110 16-5 Bond energies Bond dissociation energy is the enthalpy required to break a bond in a homolytic fashion, producing two radicals In an earlier lesson on bonding we introduced the concept of bond dissociation energy (BDE), which is the energy needed to break a given bond under standard conditions. BDE values correspond to a homolytic bond cleavage process wherein the electrons in the broken bond are split equally between the fragments. Let's consider a couple of examples: ∙ Cl (g) ⟶ 2 Cl (g) BDE = 242 kJ/mol 2 ∙ H (g) ⟶ 2 H (g) BDE = 436 kJ/mol 2 ∙ ∙ HCl(g) ⟶ H (g) + Cl (g) BDE = 431 kJ/mol C16-5-1 C16-5-2 C16-5-3 Enthalpies of reactions are calculated by subtracting BDEs of the bonds broken from those of the bonds formed The BDE values quoted above are the precise values for the specific bonds broken in the gas phase. With the help of Hess’s law, we can use them to calculate the standard enthalpy of reaction between hydrogen and chlorine to form hydrogen chloride. H (g) + Cl (g) ⟶ 2 HCl(g) 2 2 C16-5-4 We must first provide enough energy to break H–H and Cl–Cl bonds (242 kJ/mol + 436 kJ/mol = 678 kJ/mol), producing pairs of H• and Cl• radicals, which then combine to make the H–Cl bonds in two HCl molecules. Since we know the H–Cl bond dissociation energy (C16-5-3), making two H–Cl bonds (the opposite process) releases 862 kJ/mol of energy. We have successfully made stronger bonds on average (2 × 431 kJ/mol), at the expense of weaker bonds (242 kJ/mol + 436 kJ/mol). Since we released more energy in making bonds than we absorbed in breaking bonds, the overall process is exothermic. The enthalpy of the reaction is obtained by subtracting the energy of the bonds formed from the energy of bonds broken (242 kJ + 436 kJ − 2 x 431 kJ = −184 kJ). Notice that all BDEs are positive by definition, and we need to place a negative sign in front of the BDEs of the bonds formed to properly account for the fact that bond making is always exothermic. We can generalize this analysis: Δ Hr xn = ∑ BDE(bonds broken) − ∑ BDE(bonds formed) E16-5-1 We have calculated that reaction C16-5-4 is exothermic by −184 kJ. Since our reactants are elements in their most stable form at standard state and we have produced two moles of HCl(g), the standard enthalpy ΔH°f(HCl) = −92 kJ/mol, which is in perfect agreement with the value in Table T16-3-1. Unfortunately, the exact values of BDEs are known only for a limited number of bonds. Instead, chemists use average BDE values. Although not 100% accurate, these average values provide a convenient way to rapidly estimate the enthalpies of reactions. Equation E16-5-1 has to be modified accordingly to take into account the approximations involved: Δ Hr xn ≈ ∑ BD Eav (bonds broken) − ∑ BD Eav (bonds formed) E16-5-2 Exact and average bond dissociation energies are available in thermodynamic tables Even if the average BDEs are only approximate, the conclusions reached from their use may be strengthened by chemical intuition. It is simpler to discuss the driving force in a reaction in terms of stronger bonds being formed at the expense of weaker bonds, than in terms of the heats of formation of reactants and products. Bond breaking and formation have a much more intimate connection to the structures of the molecules involved. Bond orders can be read from Lewis structures and bond lengths can be approximated from atomic radii. In general, a bond’s strength (and its BDE) correlates with its bond order and its length, providing us with a direct (if approximate) connection between molecular structure and thermochemistry, which, in turn, often controls reactivity. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 247/250 9/2/2019 Chem 110 Here we present again a collection of BDEs for single and multiple bonds (T16-5-1). We have marked the precise BDEs for diatomic molecules in green, but most of the other BDEs are average values. Table T16-5-1. BDEs, average single bond dissociation energies (in kJ/mol) I Br Cl S P Si F O N C H H 299 366 431 368 322 323 568 463 391 413 436 C 220 276 328 259 264 301 453 358 276 348 N 159 243 200 200 335 272 176 193 O 234 234 203 364 340 368 190 146 F 277 237 193 327 490 582 157 Si 234 310 464 226 P 184 264 319 218 253 242 S Cl 208 218 Br 175 193 I 151 226 209 266 Multiple Bonds (BDE in kJ/mol) Bond BDE Bond BDE N=N 418 C=C 620 N≡N 941 C≡C 815 C=N 615 C=O 745 C≡N 891 C≡O 1072 N=O 607 O=O 499 Enthalpies of reactions estimated from BDEs help in selecting more feasible reactions and to better understand reactions on a molecular level We will now demonstrate the use of average BDEs to estimate the enthalpy of two possible reactions between ethane and chlorine, one forming ethyl chloride and HCl (C16-5-5) and the other producing methyl chloride (C16-5-6). ∘ C H (g) + Cl (g) ⟶ C H Cl(g) + HCl(g) 2 6 2 2 5 Δ Hr xn (A) = ? C16-5-5 We need to identify the bonds broken and the bonds made in both reactions. The best way to do so is to draw the Lewis structures of all species involved in the reaction. In the first reaction (C16-5-5), we see that the C–C bond remains intact, but a C–H bond is broken in our organic substrate. The average BDE(C–H) is 413 kJ/mol (T16-5-1). The BDE of the second bond broken, Cl–Cl, is 242 kJ/mol. The two formed bonds are C–Cl and H–Cl. The average BDE(C–Cl) is 328 kJ/mol, and BDE(H–Cl) = 431 kJ/mol. This estimate gives us ΔHorxn (A) = 413 kJ + 242 kJ − (328 kJ + 431 kJ) = −104 kJ. ∘ C H (g) + Cl (g) ⟶ 2 CH Cl(g) 2 6 2 3 Δ Hr xn (B) = ? C16-5-6 By contrast, even if the condensed formula of ethane is given in the second reaction (C16-5-6), we recognize that the C–C bond must have been broken in this case, since we have two single-carbon molecules as products. The average BDE(C–C) is 348 kJ/mol (T16-5-1). The BDE of the Cl–Cl bond is 242 kJ/mol. The average BDE(C–Cl) is 328 kJ/mol, and two such bonds are formed in the products. This estimate gives us ΔHorxn (B) = 348 kJ + 242 kJ − 2 x 328 kJ = −66 kJ. The thermodynamic cycles corresponding to these calculations are shown graphically in Figure F16-5-1. Note that we first formally break the bonds in endothermic processes, then make new bonds in exothermic processes (indicated by downward arrows), which must be given negative signs, as is required for any exothermic process. The results indicate that the first reaction (C16-5-5) is favored thermodynamically (more exothermic). Indeed, ethyl chloride and HCl are the main products observed when ethane reacts with chlorine. This example shows how Hess's law can be used to predict the thermodynamically favored reaction, which often (but not always) will be the one observed experimentally. https://genchem.science.psu.edu/sites/default/files/filefnlBYE 248/250 9/2/2019 Chem 110 Figure F16-5-1. The thermodynamic cycles for the reaction between ethane and chlorine. The cycles are based on BDEs. ΔH1 = BDE(C−H) + BDE(Cl−Cl), ΔH2 = −(BDE(C−Cl) + BDE(H−Cl)), ΔH3 = BDE(C−C) + BDE(Cl−Cl), ΔH4 = −2×BDE(C−Cl). Consider another visually appealing reaction (F16-5-2): we can use "magic beans" and a few drops of water to start a fire on a piece of cotton. The magic beans are pellets of potassium peroxide, K2O2(s), which decomposes in the presence of water: ∘ K O (s) + 2 H O(l) ⟶ 2 KOH(aq) + H O (aq) 2 2 2 2 C16-5-7 Δ Hr xn = ? 2 Subsequently, the hydrogen peroxide formed in the first step decomposes to form water and oxygen. ∘ 2 H O (aq) ⟶ 2 H O(l) + O (g) 2 2 2 2 C16-5-8 Δ Hr xn = ? Figure F16-5-2. The reaction of potassium peroxide with water on cotton. The reaction is initiated by the addition of a few drops of water. The processes involved are exothermic and produce oxygen; this is a sure way to set fire to any combustible material (such as cotton) in the vicinity. We can calculate the enthalpy of the first reaction (C16-5-7) using enthalpies of formation. Subtracting the enthalpies of formation of the reactants from the enthalpies of formation of the products shows that the first step is mildly exothermic. The necessary heats of formation can be found in our thermodynamic data table. ∘ K O (s) + 2 H O(l) ⟶ 2 KOH(aq) + H O (aq) 2 2 2 2 2 Δ Hr xn C16-5-9 ∘ ΔH f − 495.8 2(−285.8) 2(−482.4) − 187.8 − 85.2 (kJ/mol) The enthalpy of the second reaction (C16-5-7) may be calculated using BDEs or heats of formation. We will carry out both calculations to see how they compare. Based on the enthalpies of formation, the second reaction is much more exothermic than the first, and produces the O2 that supports the combustion of cotton. ∘ 2 H O (aq) ⟶ 2 H O(l) + O (g) 2 2 2 2 Δ Hr xn C16-5-10 ∘ ΔH f 2(−187.8) 2(−285.8) 0 https://genchem.science.psu.edu/sites/default/files/filefnlBYE − 196.00 (kJ/mol) 249/250 9/2/2019 Chem 110 When using the BDEs to analyze the thermodynamics of the second step (C16-5-10), it helps to draw the Lewis structure of hydrogen peroxide, H–O–O–H. This will help you realize that the simplest way to convert two molecules of hydrogen peroxide into the products is to break all of the bonds. We must break four sets of O–H bonds, and two sets of O–O bonds. Then we can reform four sets of O–H bonds (to make two molecules of water) and make one O=O double bond to form the O2 molecule. Since we are using average bond energies, the O–H bonds in hydrogen peroxide and in water are given the same value and cancel out. Thus, we are left with two broken O–O bonds (BDE = 146 kJ/mol) and one newly made O=O bond (BDE = 499 kJ/mol) for a net difference of −207 kJ. The difference between the more accurate calculation (the −196 kJ value based on enthalpies of formation) and the estimate based on BDEs (−207 kJ) is quite small (less than 6%). This confirms that the use of average BDE values is an acceptable approximation when calculating the heat of reaction. We have learned a lot of chemistry, but there is so much more to explore! We mentioned entropy, but never analyzed it. We talked about the rates of reactions or physical processes, but we never even mentioned the word kinetics. We introduced acids and bases, but we have not defined pH. We mentioned that mass can be converted into energy, but we never discussed nuclear reactions. We learned very little about metals, and almost nothing about solid-state structures (except for some ionic solids). We did not have time to talk about the amazing new materials chemists cook up in their labs. But we hope we got you interested in chemistry and instilled in you some basic concepts on which you can build. We hope you stay with us on our journey through the chemical world in the second semester of general chemistry! https://genchem.science.psu.edu/sites/default/files/filefnlBYE 250/250