# recommend trator

```1.
Recommend the KW-rating of a standard 4-wheel tractor that when attached to the proper
implement could perform any of the operation shown below under the given conditions:
OPERATION
IMPLEMENT
Plowing
4-30 cm disk plow at
15 cm plowing depth
3-m width spike tooth
Harrowing
harrow
Cultivation
4-row cultivator
Furrowing
3-row furrower
DRAFT REQ'T
10 N/sq. cm.
SPEED
5 kph
1.75 KN/m
1.70 KN/cultivator
1.60 KN/furrower
bottom
8 kph
7.5 kph
8 kph
Assume that the tractor would operate at 75% of its rated Drawbar Power
Sol’n:
Plowing:
π·π΅π = πππ΄ →
1000
(5ππβ &times; (3600)) (10π/π π. ππ)(4 &times; 30ππ &times; 15ππ)
1000
= 25πΎπ
Harrowing:
π·π΅π = πππ΄ → [8ππβ &times; (
1000
)] (3π)(1.75πΎπ/π) = 11.67πΎπ
3600
Cultivation:
π·π΅π = πππ΄ → [7.5ππβ &times; (
1000
)] (4 − πππ€ ππ’ππ‘)(1.70πΎπ/ππ’ππ‘) = 14.17πΎπ
3600
Furrowing:
π·π΅π = πππ΄ → [8ππβ &times; (
1000
)] (3 − πππ€ ππ’π)(1.60πΎπ/ππ’π) = 10.67πΎπ
3600
Since Plowing is the highest calculated DBP, choose it because it satisfies the power
requirement of other farm operation.
For the tractor to operate 75% only of its rated DBP,
πππππ‘ππ π·π΅π =
25πΎπ
= 33.33πΎπ
0.75
Hence, you may recommend 35KW Tractor.
```