Marion Dairies
• 1. Calculate the probability that the mean score of Blugert given
by the simple random sample of Marion
•
• Dairies customers will be 75 or less.
• 1) The mean n = 50
• 2) Sample size μ = 80
• 3) Standard deviation σ = 25.
• Z = -1.41
•
•
• 2. If the Marketing Department increases the sample size to 150,
what is the probability that the mean score of Blugert given by
the simple random sample of Marion Dairies customers will be
75 or less?
•
• 1) Mean n = 150
• 2) Sample Size μ = 80
• 3) Standard deviation σ = 25
• Formula:
• z= -2.45.
• P (z≤-2.4494) = 0.73%.