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develop-electricfield

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Developed group
Electric potential
Student’s name :noora ahmed khalid
∆v= Ed
10^ − 6
∆v= f/q d
class : 12g4
37x10^-637 ×
=3.7x10^-5
=0.25
=0.065
3.7x10^-5 x 0.25
=440v
∆v= w/q
w=120j q=2.4
=120/2.4
=50v
Answer 50V
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