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Force between the charges.
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F  1.6  104 N attractive.
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Given:
Negative charge, q1  2  104 C
Positive charge, q2  8  104 C
Distance between the charges, d  0.3 m
Formula Used:
From Coulomb’s law,
F
Kq1 q2
d2
Where,
F is electrostatic force
K is coulomb’s constant
q1 and q2 are charges and
d is distance between the charges.
Calculation:
As, K  9  109 N.m2 / C2
On putting the values,
F
9  109   2  104   8  104 
0.32
 1.6  104 N
As, F  1.6  104 N
Negative means the force is attractive in nature.
Conclusion:
Therefore, the electrostatic force between the charges is F  1.6  104 N and it is attractive in
nature.
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