The circuit shown has labeled time domain circuit variables. Convert them to phasors. Solve
the circuit analysis problem and find the phasor currents I(R), I(L), and I(C). Compute the
maximum current for I(L) and compare it to the maximum of I(S).
From the given current source the value of  is,
  10, 000 rad/sec
Find X L :
X L  j L
 j 10, 000   20 10 3 
 200 j
 20090
Find X C :
XC   j

1
C
j
10, 000   0.5 106 
 200 j
 200  90
Find equivalent impedance.
1000  20090 
Z1 
1000   20090 
 196.178.7
Current flows through the capacitor.
iC 
0.01cos 104 t  196.178.7 
196.178.7  200  90
iC  590 cos 104 t  A
Z2 
1000  200  90 
1000   200  90 
 38.46  192.3
Current flows through the inductor.
0.01cos 104 t   38.46  192.3 
iL 
38.46  192.3  20090
iL  0.1867.5 cos 10 4 t  A
Z3 
 20090  200  90 
 20090    200  90 
0
Current flows through the resistor.
iR  0 .
The maximum absolute value of iL is,
iL  0.0692  0.1662 cos 104 t  A
=0.18cos 104 t  A
...... (1)
The maximum absolute value of iS is,
is =0.01cos 104 t  A
...... (2)
Compare (1) and (2),
From this statement, we conclude the value of iL is maximum than iS without considering
the reactive component.