Fundamentals of Power Electronics 1. Power Semiconductor Devices (Switches) There are several power semiconductor devices currently involved in several industrial applications. This lecture will concentrate mainly on four power devices only, namely; Diodes, SCRs (Thyristors), MOSEFTs, and IGBTs. Diodes: These are two terminal switches, as shown in Fig. 1-a, formed of a pn junction. It is not controllable and its operating states are determined by the circuit operating point. A forward positive voltage (vD is positive) will turn it on and a reverse negative current (from Cathode to Anode, iD is negative) will turn it off. Practically, the diode characteristic consists of two regions, as shown in Fig. 1-b; a forward bias region (ON state) where both vD and iD are positive and the current in this region increases exponentially with the increase in the voltage, and a reversed bias region (OFF state) where both vD and iD are negative and very small leakage current flow through the diode until the applied reverse voltage reaches the diode’s breakdown voltage limit VBR. Ideally, the diode is represented by a short circuit when forward biased and as an open circuit when reversed biased with the ideal characteristic shown in Fig. 1-c. Fig. 1 Diode: a) symbol, b) characteristic, and c) ideal characteristic [1] Silicon Controlled Rectifiers “SCRs” (Thyristors): These are three terminal switches as shown in Fig. 2-a, formed of three pn junctions (pnpn). This is a controllable switch that usually required to be latched to conduct. This latching (triggering) process is carried out by 1 injecting current to the gate terminal (ig) at the required latching instant provided that the device is forward biased (vAK is positive). Practically, the thyristor characteristic has three main regions as shown in Fig. 2-b; the Conduction Region where the thyristor is operating in its ON state, the Forward Blocking Region where the thyristor is forward biased but not yet triggered or the voltage didn’t reach the forward breakover voltage, and a Reverse Region that consists of the reverse blocking region and the reverse avalanche region similar to the diode characteristic. Among the important points along the SCR characteristic: Fig. 2 Thyristor: a) symbol, b) characteristic, and c) ideal characteristic [1] Fig. 3 Thyristor gate circuit [1] 2 o Latching Current: This is the minimum required current to turn on the SCR device and convert it from the Forward Blocking State to the ON State. o Holding Current: This is the minimum forward current flowing through the thyristor in the absence of the gate triggering pulse. o Forward Breakover Voltage: This is the forward voltage required to be applied across the thyristor to turn it ON without the gate signal application. o Max Reverse Voltage: This is the maximum reverse voltage to be applied across the thyristor before the reverse avalanche occurs. Ideally, SCRs are represented by a short circuit when operating within the conduction region and as an open circuit when operating within the blocking region. The ideal characteristic is shown in Fig. 2-c. It is also worth mentioning that once the SCR is triggered and turned ON the gate signal can be removed without turning it OFF. SCRs are turned OFF when reversing the terminal voltage and current. Metal Oxide Semiconductor Field Effect Transistors “MOSFETs”: These are three terminal switches as shown in Fig. 4-a. This is considered the fastest power switching device. It is a controllable switch that requires a gate-source voltage (vGS) higher than a threshold value (vTh) for the device to conduct. Practically, MOSFET’s characteristic consists of three regions, as shown in Fig. 4-b; a cut OFF region (OFF state) when vGS < vTh, a linear region when vDS < vGS – vTh, and an active region when vDS > vGS – vTh. Ideally, MOSFETs are represented by a short circuit when operating within the ON State and as an open circuit when operating within the OFF State. Insulated Gate Bipolar Transistors “IGBTs” (Thyristors): These are also three terminal switches as shown in Fig. 5. Their operation modes and characteristics are almost similar to those for MOSFETs, shown in Fig. 4-b, except for the operating ranges. Other Semiconductor Devices: These include; Bipolar Junction Transistors (BJTs), Gate Turn Off Thyristors (GTO Thyristors), Triode ac switches (Triacs), Static Induction Transistors (SITs), Static Induction Thyristors (SITHs), and MOS-Controlled Thyristors 3 (MCTs). Comparisons between different types of semiconductor devices from the point of view of ratings and power and frequency ranges are given in Table 1 and Fig. 6, respectively. Fig. 4 MOSFET: a) symbol and b) characteristic [1] Fig. 5 IGBT symbol [1] Table 1 Power semiconductor devices ratings comparison [1] 4 Fig. 6 Frequency and power ranges for different power semiconductor devices [1] 2. Important Parameters for Periodic Waveforms For any periodic waveform as shown in Fig. 7, the following parameters can be determined: Peak Value: This represent the maximum value of the periodic waveform. Peak – to – Peak Value: This represents the difference between the maximum and the minimum values of the waveform. Fig. 7 Periodic waveform and its parameters 5 Average Value: This represent the DC component content of the waveform and can be calculated from the following expression; f avr 1 T T f t dt f avr or 0 1 f t d t 0 where favr is the average value of the periodic function f(t) { f( t)} over a period T {}. Root Mean Square (RMS) Value: this represent the effective value of the periodic function and can be expressed by; (sometimes it is referred to by Effective Value) f rms 1 T T f 2 t dt f rms or 0 f 1 2 t d t 0 where frms is the rms value of the periodic function f(t) { f( t)} over a period T {}. Peak Reverse Voltage (PRV): This represents the maximum reverse voltage applied to a semiconductor device during its operation in the off state. Sometimes referred to as the Peak Inverse Voltage (PIV). Conduction Period (Angle): The period of time (angle) during which a semiconductor switch is conducting (operating in its ON state). Extinction Angle: This is the angle ( t) at which the semiconductor switch stops conducting (switched to the OFF state). Firing Angle: This is the angle ( t) at which controlled semiconductor switch starts conducting (switched to the ON state). Sometimes referred to as the Delay Angle. 3. Power Electronic Converters In general, power electronics converters can be classified into four main categories namely; Rectifiers, DC – to – DC Converters, AC – to – AC Converters, and Inverters. 3.1 Rectifiers These converters are used to convert fixed AC power to fixed or variable DC power. They are classified into two main categories; Uncontrolled Rectifiers and Controlled Rectifiers. 6 3.1.1 Uncontrolled Rectifiers In this type, the generated DC power is fixed with the converter used and the input AC power. They usually use diodes as their power switches. The following subsections deal with the basic operation of some examples of uncontrolled rectifiers. Single-phase half-wave rectifier loaded with resistive load: Fig. 8-a presents the basic circuit for a single-phase, half-wave, rectifier loaded with a resistive load. The circuit is supplied by a single phase transformer whose secondary represents the rectifier’s circuit AC source (vs) that is represented by a sinusoidal wave given by, vs = Vm sin ( t) where vs is the supply voltage, Vm is the peak value of the supply voltage, is the angular frequency, and t and is the time. For this configuration, the diode will conducts (becomes forward biased) whenever the supply voltage (vs) is positive to force the current in the diode from the anode to the cathode. Fig. 8 Single-phase half-wave rectifier: a) circuit and b) waveforms [2] For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 8-b where two operating states occur as presented in Table 2. 7 Table 2 Operation states Period Diode Representation Diode State Output Voltage (vo) Load / Supply Current (io / is ) Diode Voltage (vD) vs vs / R Zero Zero Zero vs ON (Forward SC* Biased) OFF (Reverse OC* t < 2 Biased) * SC = Short Circuit, and OC = Open Circuit 0t< The average value of the load voltage Vdc can be calculated as follows, Vdc 1 2 V dc v s t dt 0 Vm 1 Vm sin t dt 2 0 0.318 V m Since the load is resistive load, therefore the load voltage and current are in phase and they are related by is = vs / R. Consequently, the average value of the load current Idc is I dc V dc V m 0.318 V m R R R The rms value of the load voltage Vrms can be calculated as follows, 1 2 V rms V rms 2 v s t dt 1 2 0 V m sin t 2 dt 0 Vm 0 .5 V m 2 Therefore the rms value of the load current Irms is I rms V rms V m 0.5 V m 2R R R The output power is given by Pac I rms V rms 8 Vrms 2 R 0.5 Vm 2 R The PRV of the diode in this configuration is Vm. Single-phase half-wave rectifier loaded with resistive load and a battery: Fig. 9-a presents the basic circuit for a single-phase, half-wave, rectifier loaded with a resistive load and a battery. For this configuration, the diode will conducts (becomes forward biased) whenever the supply voltage (vs) is positive and greater than the battery voltage “E” to force the current in the diode from the anode (point 2) to the cathode (point 4). Vm PRV = Vm + E E Fig. 9 Single -phase half-wave rectifier: a) circuit and b) waveforms [3] For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 9-b where two operating states occur as presented in Table 3. Table 3 Operation states Period Diode State Diode Representation OFF (Reverse OC* Biased) ON (Forward SC* t1 t < t2 Biased) OFF (Reverse OC* t2 t < t4 Biased) * SC = Short Circuit, and OC = Open Circuit 0 t < t1 Output Voltage (vo) Load / Supply Current (io / is ) Diode Voltage (vD) E Zero vs - E vs (vs - E)/ R Zero E Zero vs - E In the analysis of this circuit, point 1 is considered the grounded reference for all node voltages and consequently the following voltages can be defined: v1 (Voltage at point 1) = zero 9 vs (Supply Voltage) = v2 – v1 = v2 vD (Diode Voltage) = v2 – v4 vR (Resistive Load Voltage) = v4 – v3 = v4 – E vo (Output Load Voltage) = v4 – v1 = v3 + vR = E + vR Moreover, the load (supply) {since the load, the battery, and the supply are connected in series}) current may be defined as io (Load Current) = is (Supply Current) = vR / R The angle at which the diode starts conducting is the same angle at which the supply voltage is equal to the battery voltage. Therefore, at t we have, v s t E V m sin E sin 1 Vm Since the wave form during the first half cycle is symmetric around t 2 . Therefore, the angle at which the diode stops conducting is be given by, The average value of the load voltage Vdc can be calculated as follows, V dc 2 2 1 1 v s t dt E d t V m sin t d t E dt 2 2 V dc 1 2 Vm cos 2 E 2 The average value of the load current Idc is I dc 1 2 Vm cos 2 E E 2 Vm cos 2 E V E 2 dc R R 2 R 10 The PRV of the diode in this configuration is (Vm + E) which represent the maximum value of vD = v2 – v4 when there is no current flowing in the load as shown in Fig. 9-b. Single-phase full-wave rectifier loaded with resistive load: Fig. 10-a presents the circuit connection for a single-phase, full-wave, rectifier loaded with a resistive load. It is sometimes referred to as the full-wave bridge rectifier. For this configuration, two diodes always conducting during the same interval to provide a closed loop for the current. D1 and D2 conduct whenever the supply voltage (vs) is positive while D3 and D4 conduct whenever the supply voltage (vs) is negative as illustrated by Fig. 10-b. Fig. 10 Single -phase full-wave rectifier loaded with resistive load [2] For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 10-b where two operating states occur as presented in Table 4. Table 4 Operation states Period Conducting Diodes Output Voltage (vo) Load Current (io ) Supply Current (is ) 0t< D1 & D2 vs vs / R vs / R t < 2 D3 & D4 - vs - vs / R vs / R 11 Diode Voltage (vD) - vs for D3 & D4 vs for D1 & D2 Since the load is a resistive load. Then, the load current will have the same waveform as the load voltage but with current scale according the load current-voltage characteristic, io (Load Current) = vo / R Table 4 reveals that, during the negative half cycle of the supply voltage, the load current is positive (io = - vs / R) (vs itself is negative) whereas the supply current is negative (is = vs / R). The average value of the load voltage Vdc can be calculated as follows, V dc V dc v t d t V 1 1 s 0 m sin t d t d t 0 2 Vm 0.6366 V m The average value of the load current Idc is I dc V dc 2 V m 0.6366 V m R R R The rms value of the load voltage Vrms can be calculated as follows, 1 V rms V rms v t 2 s 1 d t 0 Vm 2 V m sin t 2 dt 0 0.707 V m Therefore the rms value of the load current Irms is I rms 0.707 V m V rms V m R R 2R The PRV for any diode in this configuration is (Vm) as shown in Fig. 10-b. Single-phase full-wave rectifier loaded with highly inductive load: Fig. 11-a presents the circuit connection for a single-phase, full-wave, rectifier loaded with a highly inductive load. Highly inductive loads are basically R-L loads where L >>> R. 12 Therefore, the load time constant L is very high and can be considered infinity. R Consequently, the load current is assumed constant. For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 11-b where two operating states occur as presented in Table 5. Fig. 11 Single -phase full-wave rectifier loaded with highly inductive load Table 5 Operation states Period Conducting Diodes Output Voltage (vo) Load Current (io ) Supply Current (is ) 0t< D1 & D2 vs Ia Ia t < 2 D3 & D4 - vs Ia - Ia Diode Voltage (vD) - vs for D3 & D4 vs for D1 & D2 Table 5 reveals that, during the negative half cycle of the supply voltage, the load current is positive (io = Ia) whereas the supply current is negative (is = - Ia). 13 The average value of the load voltage Vdc can be calculated as follows, Vdc 1 1 V dc vs t d t 0 2 Vm Vm sin t d t 0 0.6366 V m Since the load is a highly inductive load. Then, the load current is considered constant (ripple free current) and equal to the average value of the load current Idc as follows, I dc I a V dc 2 V m 0.6366 V m R R R In case the load contains a DC battery “E” (or a back emf) in addition to the highly inductive load, the load current will be I dc 2 Vm V E I a dc R E R 2 Vm E R (provided that E < Vdc) The rms value of the load voltage Vrms can be calculated as follows, V rms v t 1 2 s d t 0 V rms Vm 2 V 1 m sin t 2 dt 0 0.707 V m Since the load current is constant over the studied period, therefore the rms value of the load current Irms is I rms I dc I a The PRV for any diode in this configuration is (Vm) as shown in Fig. 11-b. 3.1.2 Controlled Rectifiers In this type, the generated DC power is controllable and variable. They usually use SCRs as their power switches. For fast switching operation, MOSFETs and IGBTs are used. The following subsections deal with the basic operation of some examples of controlled rectifiers. 14 Single-phase half-wave controlled rectifier loaded with resistive load: Fig. 12-a presents the basic circuit for a single-phase, half-wave, controlled rectifier loaded with a resistive load. For this configuration, the thyristor will conducts (becomes forward biased) when triggered using gate pulses provided that the supply voltage (vs) is positive to force the current in the thyristor from the anode to the cathode. The instant at which the gate pulse occurs is known as the firing angle and represented by (). The gate pulses are repeated every 2 (one complete cycle). The firing angle can occur at any instant ranging from 0 to as the thyristor has to be forward biased when triggered, otherwise it won’t conduct. For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 12-c where three operating states occur as presented in Table 6. Fig. 12 Single-phase half-wave controlled rectifier [2] The average value of the load voltage Vdc can be calculated as follows, V dc 1 2 v s t dt 1 2 V m 15 sin t dt V dc Vm 1 cos 2 The average value of the load current Idc is I dc V dc V m 1 cos R 2 R Table 6 Operation states Period Thyristor Representation Thyristor State Output Voltage (vo) Load / Supply Current (io / is ) Thyristor Voltage (vT1) Zero Zero vs vs vs / R Zero Zero Zero vs OFF (Forward OC* Blocking) ON (Forward SC* t< Biased) OFF (Reverse OC* t < 2 Biased) * SC = Short Circuit, and OC = Open Circuit 0t< Therefore, the average output voltage can vary from 0 to vary from 0 to Vm and the average load current will Vm when varying from to 0, respectively. Moreover, since the load R voltage and current for this configuration are always positive, therefore, this converter operates in the first quadrant only as revealed by Fig. 12-b. The rms value of the load voltage Vrms can be calculated as follows, V rms 1 2 V rms Vm 2 v t 2 s dt 1 2 V m sin 2 1 2 Therefore the rms value of the load current Irms is I rms V rms V m R 2R sin 2 1 2 The PRV of the thyristor for this configuration is Vm. 16 sin t 2 dt Single-phase full-wave controlled rectifier loaded with highly inductive load: Fig. 13-a presents the circuit connection for a single-phase, full-wave, controlled rectifier loaded with a highly inductive load. For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 13-c where two operating states occur as presented in Table 7. Table 7 Operation states Period Conducting Thyristors Output Voltage (vo) Load Current (io ) Supply Current (is ) t < + T1 & T 2 vs Ia Ia + t < 2 + T3 & T 4 - vs Ia - Ia Thyristor Voltage (vT) - vs for T3 & T4 vs for T1 & T2 Fig. 13 Single -phase full-wave rectifier loaded with highly inductive load [2] The average value of the load voltage Vdc can be calculated as follows, V dc 1 V dc v s t d t 2 Vm 1 V m cos 17 sin t d t d t Since the load is a highly inductive load. Then, the load current is considered constant (ripple free current) and equal to the average value of the load current Idc as follows, I dc V E I a dc R 2 Vm cos E (provided that E < Vdc and Vdc > 0) R In case the load doesn’t contain a DC battery “E” (or a back emf) in addition to the highly inductive load, the load current will be I dc I a Vdc 2 Vm cos R R (provided that Vdc > 0) Therefore, the average output voltage can vary from 2 Vm to 2 Vm when varying from to 0, respectively. Moreover, since the load voltage for this configuration can be positive or negative while the load current is always positive because the thyristors prevents a reverse current flow. Therefore, this converter operates in the first and the fourth quadrants as revealed by Fig. 13-b. The rms value of the load voltage Vrms can be calculated as follows, V rms V rms 1 v t 2 s Vm 2 d t 1 V m sin t 2 dt 0.707 V m Since the load current is constant over the studied period, therefore the rms value of the load current Irms is I rms I dc I a The PRV for any thyristor in this configuration is (Vm). Single-phase semiconverter loaded with highly inductive load: Fig. 14-a presents the circuit connection for a single-phase semiconverter loaded with a highly inductive load. This configuration consists of a combination of thyristors and diodes and is 18 used to eliminate any negative voltage occurrence at the load terminals. This is because the diode Dm is always activated (forward biased) whenever the load voltage tends to be negative. For one total period of operation of this circuit, the corresponding waveforms are shown in Fig. 14-b where four operating states occur as presented in Table 8. The average value of the load voltage Vdc can be calculated as follows, Vdc vs t dt Vm sin t dt 1 Vdc Vm 1 1 cos Fig. 14 Single -phase semiconverter loaded with highly inductive load [2] 19 Table 8 Operation states Period Conducting Switches Output Voltage (vo) Load Current (io ) Supply Current (is ) Diode Dm Current (iDm ) Switch Voltage 0t< Dm 0 Ia 0 Ia 0.5 vs for T1 & D2 - 0.5 vs for T2 & D1 t< T1 & D 2 vs Ia Ia 0 - vs for T2 & D1 & Dm t < + Dm 0 Ia 0 Ia - 0.5 vs for T1 & D2 0.5 vs for T2 & D1 + t < 2 T2 & D 1 - vs Ia - Ia 0 vs for T1 & D2 & Dm The average value of the load current Idc is Vm I dc V E dc R 1 cos E (provided that E < Vdc) R Therefore, the average output voltage can vary from 0 to Vm when varying from to 0, respectively. Moreover, since the load voltage and current for this configuration are always positive, therefore, this converter operates in the first quadrant only as revealed by Fig. 14-b. The rms value of the load voltage Vrms can be calculated as follows, Vrms vs t 2 dt 1 Vrms Vm Vm sin t 2 dt 1 1 sin 2 2 The PRV for any switch in this configuration is (Vm). 3.2 DC – to – DC Converters These converters are used to convert fixed DC power to controllable, variable DC power. The following subsections deal with the basic types of these converters. They are sometimes referred to as DC Choppers. DC Choppers can be classified according to their operation range (load voltage and current) into five main categories as shown in Fig. 15. 20 Fig. 15 DC Choppers’ classification 3.2.1 First Quadrant DC Chopper In this type, the load voltage and load currents are always positive. Fig. 16 presents the circuit of this type. For one total period of operation of this circuit (T), the corresponding equivalent circuits and waveforms are shown in Fig. 17 where two operating modes occur as presented in Table 9. Fig. 16 First quadrant DC Chopper 21 Fig. 17 Modes of operation equivalent circuit and output Waveforms The equations that governs the operation of this type can be summarized as follows, the average value of the load voltage Vdc can be calculated as follows, V dc 1 T kT V s d t k Vs 0 where Vs is the DC supply voltage, T is the total period of operation, and k is the duty cycle given by k t on , where ton is the period at which the chopper is ON. T Table 9 Operation modes Period Mode Chopper State 1 ON (SC*) 0 t < kT OFF (OC*) 2 kT t < T * SC = Short Circuit, and OC = Open Circuit 22 Diode State Output Voltage (vo) OFF (OC*) ON (SC*) Vs 0 Currents (i ) i1 i2 (is ) i1 0 (iDm ) 0 i2 For (L / R) >> T, the load current is continuous and can be expressed by, V E t R / L 1 e t R / L s i1 t I1 e R i t E (t kT ) R / L 1 e (t kT ) R / L i2 t I 2 e R where I 1 Vs R 0t kT k T t T ek z 1 E Vs e k z 1 E TR I , , and z . 2 z ez 1 R R e 1 R L For discontinuous mode of operation (I1 = 0), the load current can be expressed by, V E i1 t s 1 e t R / L R i t E (t kT ) R / L 1 e (t kT ) R / L i2 t I 2 e R 0t kT k T t T For the load current to be continuous, I1 should be greater than or equal to zero. Therefore, V e kz 1 E 0 I 1 s z R e 1 R e kz 1 E z e 1 V s 0 E e kz 1 z Vs e 1 3.2.2 Second Quadrant DC Chopper In this type, the load voltage is always positive while the load current is always negative. Fig. 18-a presents the circuit connection of this type. For one total period of operation of this circuit (T), the corresponding equivalent circuits and waveforms are shown in Figs. 18-b and 18-c where two operating modes occur as presented in Table 10. 23 Fig. 18 Second quadrant DC Chopper The equations that governs the operation of this type can be summarized as follows, the average value of the load voltage Vdc can be calculated as follows, V dc 1 T T V s d t 1 k V s kT where Vs is the DC supply voltage, T is the total period of operation, and k is the duty cycle given by k ton , where ton the period at which the chopper is ON. T Table 10 Operation modes Period Chopper State Diode State Load Voltage (vo) ON (SC*) OFF (OC*) 0 t < kT OFF (OC*) ON (SC*) kT t < T * SC = Short Circuit, and OC = Open Circuit 0 Vs Currents (iL ) i1 i2 (is ) 0 i2 For continuous load current operation, the load current is can be expressed by, E I1 e t R / L 1 e t R / L R iL t E Vs ( t kT ) R / L 1 e (t kT ) R / L i2 t I 2 e R where I 1 E V s 1 e 1 k z R R 1 e z V , I 2 E s R R 24 e k z e z 1 e z 0t kT k T t T , and z T R . L (ich ) i1 0 3.2.3 First and Second Quadrants DC Chopper In this type, the load voltage is always positive while the load current can be either positive or negative. It is also know as the two quadrant chopper. Fig. 19 presents the circuit connection of this type. This is considered a combined converter consisting of both the first-quadrant and the second quadrant DC choppers. It can operate in the first quadrant by controlling S1 and D4 in the same manner explained in Section 3.2.1. Moreover, it can operate in the second quadrant by controlling S4 and D1 in the same manner explained in Section 3.2.2. S1 and S4 must not be switched ON at the same time; otherwise, the source will be short circuited. Table 11 shows the different operation mode of this converter. Fig. 19 First and second quadrants DC Chopper Table 11 Operation modes Mode Conducting switch Load Current (iL) Load Voltage (vL) 1 2 3 4 S1 S4 D1 D4 + ve - ve - ve + ve Vs 0 Vs 0 Note that the diode D1 is activated once S4 is switched off while the diode D4 is activated once S1 is switched off. This operation is carried out because of the presence of the inductance in the load that requires a continuous flow of current at the instant of turning OFF the chopper switches. 3.2.4 Third and Fourth Quadrants DC Chopper In this type, the load voltage is always negative while the load current can be either positive or negative. Fig. 20 presents the circuit connection of this type. It can operate in the third quadrant by controlling S3 and D2 while it can operate in the fourth quadrant by controlling S2 and D4. S2 25 and S2 must not be switched ON at the same time; otherwise, the source will be short circuited. Table 12 shows the different operation mode of this converter. Fig. 20 Third and Fourth quadrants DC Chopper Table 12 Operation modes Mode Conducting switch Load Current (iL) Load Voltage (vL) 1 2 3 4 S2 S3 D2 D3 + ve - ve - ve + ve 0 - Vs 0 - Vs The diode D2 is activated once S3 is switched off while the diode D3 is activated once S2 is switched off. 3.2.5 Four-Quadrants DC Chopper In this type, both the load voltage and the load current can be either positive or negative. Fig. 21 presents the circuit connection of this type. It can operate in the third quadrant by controlling S3 and D2 while it can operate in the fourth quadrant by controlling S2 and D4. S2 and S2 must not be switched ON at the same time; otherwise, the source will be short circuited. Table 13 shows the different operation mode of this converter. Fig. 21 Four-quadrants DC Chopper 26 Table 13 Operation modes Mode Conducting switch Load Current (iL) Load Voltage (vL) 1 2 3 4 S2 S3 D2 D3 - ve + ve - ve + ve 0 - Vs 0 - Vs The diode D2 is activated once S3 is switched off while the diode D3 is activated once S2 is switched off. 3.3 Other Power Converters In addition to the previously discussed converters, there are also the AC - to - AC Converters, that convert fixed AC power to controllable, variable AC power, and the DC - to – AC Converters (Inverters), that convert fixed AC power to controllable, variable DC power. These converters are not covered within the scope of this course. 4. Fast Switching Modulation Techniques There are several techniques to control (modulate) fast power semiconductor switches. This section will introduce the basic principle and the main types of Pulse Width Modulation (PWM) techniques. This technique is basically based on comparing a reference signal vr with a carrier signal vcr to generate the control (switch’s gate) signal as shown in Fig. 22. This generated control signal is send to the control terminal of the power electronic switches to activate them whenever vr < vcr provided that the switch is forward biased. By varying the carrier signal magnitude the ON period (ton) and the duty cycle of switching changes. Moreover, the switching frequency (switching period) is varied by varying the reference signal frequency. Fig. 22 Basics of PWM 27 4.1 PWM for DC Output These techniques are used for the converters generating DC outputs. They are classified into two main categories: Uniform (Equal width) PWM: The generated pulses have equal width as shown in Fig. 23. They are generated by comparing a triangular wave with a DC signal. Fig. 23 Uniform PWM for DC outputs [4] Sinusoidal PWM: The generated pulses have different widths as shown in Fig. 24. Fig. 24 Sinusoidal PWM for DC outputs [1] 28 They are generated by comparing a triangular wave with a variable DC signal to generate a sinusoidal variable duty cycle tracking the following function, d t D dc D max sin o t where d t is the required duty cycle signal to be generated, D dc is the normal duty cycle with no sinusoidal modulation, D max is the maximum modulation constant, and o is the modulation frequency. The generated DC output voltage in this case can be represented by v o d t V dc D dc D max sin o t V dc D dc V dc D max V dc sin o t where Vdc is the DC source voltage. 4.2 PWM for AC Output They techniques are used for the converters generating AC outputs. They are classified into three main categories: Uniform (Equal width) PWM: The generated pulses have equal width as shown in Fig. 25. They are generated by comparing two inverse triangular waves with two opposite DC signal levels. Fig. 25 Uniform PWM for AC outputs [4] 29 Bipolar Sinusoidal PWM: The generated pulses have different widths as shown in Fig. 26. They are generated by comparing a triangular wave with a sinusoidal wave. Whenever, the reference signal is greater than the triangular signal a pulse is generated by turning ON switch S1. On the other hand, whenever, the reference signal is lower than the triangular signal a pulse is generated by turning ON switch S2 as shown in Fig. 27. Fig. 26 Biopolar Sinusoidal PWM for AC outputs [1] Fig. 27 Simplified circuit for generating biopolar Sinusoidal PWM for AC outputs [1] Unipolar Sinusoidal PWM: The generated pulses have different widths as shown in Fig. 28. They are used when a positive and negative sinusoidal control signal are available. These signals are compared with sawtooth signals to generate to output Vo1 and Vo2 . The difference generates the total output control signal Vo = Vo1 - Vo2. For example, positive pulses can be used to trigger S1 while negative pulses can be used to trigger S2, shown in Fig. 27, to generate the output voltage waveform shown in Fig. 28. 30 Fig. 28 Unipolar Sinusoidal PWM for AC outputs [1] 5. Numerical Examples Example 1: For the half-wave uncontrolled rectifier circuit shown in Fig. 29. The supply is a 110 V, 60 Hz. The resistive load is 25 . Calculate: 1. The average value of the output voltage and current, 2. The rms value of the output voltage and current, 31 3. The average value of the power delivered to the load, 4. The average value of the power delivered to the load if the source has a resistance of 60 . Given: V = 110 V, f = 60 Hz, R = 25 , and Rs = 60 . Solution: For half-wave uncontrolled rectifier circuit shown in Fig. 29. Fig. 29 Single-phase half-wave rectifier [2] 1. The average value of the load voltage Vdc can be calculated as follows, Vdc 1 2 Vdc Vm 0 1 v s t dt Vm sin t dt 2 0 2 x 110 49.517 V The average value of the load current Idc is I dc V dc V m R R 2 x 110 1.981 25 A 2. The rms value of the load voltage Vrms can be calculated as follows, 32 1 2 V rms V rms 2 v s t dt 0 Vm 2 1 2 V m sin t 2 dt 0 2 x 110 77.782 V 2 Therefore the rms value of the load current Irms is I rms V rms 77.782 3.111 A R 25 3. The average power delivered to the load is Pavr 1 2 Pavr 0 1 v o t io t d t 2 77.7822 25 v s t 2 d t Vrms 2 R 0 R 242.002 W 4. If the source has a resistance of 60 , the load voltage will be related to the total voltage using the voltage divider equation as follows, v o t v s t R R R s Therefore the value of the average power delivered to the load is Pavr 1 2 v o t i o t d t 0 Pavr 77.782 2 25 25 602 1 2 v t 2 s 0 R R R s 2 d t V rms 2 R R R s 2 20.934 W Example 2: For the single-phase, full-wave uncontrolled rectifier circuit shown in Fig. 30. The supply is a 110 V, 60 Hz. The resistive load is 25 . Calculate: 1. The average value of the output voltage and current, 2. The rms value of the output voltage and current, 3. The average value of the power delivered to the load, Given: V = 110 V, f = 60 Hz, and R = 25 . 33 Solution: For full-wave uncontrolled rectifier circuit shown in Fig. 30. Fig. 30 Single-phase, full-wave rectifier [2] 1. The average value of the load voltage Vdc can be calculated as follows, V dc 1 V dc v s t d t 0 2 Vm 1 2 2 x 110 V m sin t d t d t 0 99.035 V The average value of the load current Idc is I dc V dc 99.035 3.961 A R 25 2. The rms value of the load voltage Vrms can be calculated as follows, V rms V rms 1 2 v s t d t 0 Vm 2 2 x 110 1 V m sin t 2 dt 0 110 V 2 Therefore the rms value of the load current Irms is 34 I rms V rms 110 4 .4 R 25 A 3. The average power delivered to the load is Pavr Vrms 2 1 vs t 2 vo t io t d t R d t R 0 0 1 Pavr 110 2 25 484 W Example 3: For the first quadrant DC chopper shown in Fig. 31. The supply is a DC source of 220 V. The load parameters are as follows: E = 0 V, L = 7.5 mH, and R = 5 . The chopper is switched at 1 kHz with a duty cycle of 50 %. Calculate: 1. The average value of the load voltage, 2. The maximum and the minimum values for the instantaneous load current, 3. The peak-to-peak load current ripple. 4. The approximated average value of the load current, Given: Solution: Vs = 220 V, E = 0 V, f = 1 kHz, L = 7.5 mH, R = 5 , and k = 0.5. For the first quadrant DC chopper shown in Fig. 31. Fig. 31 First quadrant DC chopper [2] 1. The average value of the load voltage Vdc can be calculated as follows, Vdc 1 T kT V s d t k V s 0.5 x 220 110 V 0 35 2. Since the back emf (battery voltage) is zero. Then, the load current will satisfy the continuity equation E e kz 1 z . Therefore, the load current is continuous and the Vs e 1 crrosponding waveforms are shown in Fig. 32. Fig. 32 First quadrant DC chopper waveforms [2] Therefore the maximum and the minimum values for the instantaneous load current can be determined using the following equations I1 Vs R ek z 1 E ez 1 R , I2 Vs R e k z 1 E e z 1 R , z and TR L using the circuit parameters and substitute in the above equation yield to, z TR 5 R 0.667 , L f L 1000 x 7.5 x 10 3 I1 220 e 0.5 x 0.667 1 1.396 1 0 44 x 18.38 0 . 667 5 e 1 1.948 1 36 A, and