Prof. S. Ben-Yaakov , DC-DC Converters [3- 1] Magnetics Design 3.1 Important magnetic equations 3.2 Magnetic losses 3.3 Transformer 3.3.1 Ideal transformer (voltages and currents) 3.3.2 Equivalent circuit of transformer (coupling, magnetization current) 3.3.3 Design of transformer 3.4 Inductor design Prof. S. Ben-Yaakov , DC-DC Converters [3- 2] Faraday’s law BDC B H Ae Φ HDC ∆B dΦ dB = nA e ; µ= ∆H dt dt Φ - magnetic flux Weber [ Wb ] V - voltage [ V ] Wb B - flux density 2 = Tesla [ T ] m Also : Gauss [ G ] 1T = 10,000 G V =n 1 Prof. S. Ben-Yaakov , DC-DC Converters [3- 3] Ampere’s law le I n H - magnetic field [ A/m ] ∫ Hdl = n ⋅ I n ⋅I = H ⋅ le H= n ⋅I [ A/m ] le Prof. S. Ben-Yaakov , DC-DC Converters [3- 4] Magnetic losses BDC mW P cm3 B H HDC ∆B Magnetic losses ~∆B “Good number” = 100mW/cm3 =100KW/m3 2 Prof. S. Ben-Yaakov , DC-DC Converters [3- 5] Magnetic Losses z “Good number”=100mW/cm3=100 kW/m3 Prof. S. Ben-Yaakov , DC-DC Converters [3- 6] Magnetic losses BDC mW P cm3 B H HDC ∆B Magnetic losses ~∆B “Good number” = 100mW/cm3 =100KW/m3 3 Prof. S. Ben-Yaakov , DC-DC Converters [3- 7] Magnetic Losses Prof. S. Ben-Yaakov , DC-DC Converters [3- 8] Magnetic Losses z z z 4 Curves for constant loss: 500mW/cm3 Figure of merit B*f Each material has optimum operating temperature (minimum loss) Prof. S. Ben-Yaakov , DC-DC Converters [3- 9] Transformer currents I2 I1 I1 n2 n1 I2 n1 For ideal transformer n2 I1 n2 = I2 n1 n1I1 = n2I2 At any given moment n1I1 = n2I2 I1,I2 opposite direction. No magnetic energy stored due to useful currents I1, I2 (they cancel each other) Prof. S. Ben-Yaakov , DC-DC Converters [3- 10] Transformer voltages V1 φ V1 = n1 dφ1 dt n1 n2 V2 = n2 dφ 2 dt Assu min g φ1 = φ2 dφ1 dφ2 = dt dt V1 n1 = V2 n2 5 V2 Prof. S. Ben-Yaakov , DC-DC Converters [3- 11] Voltages Since each winding also represents an inductance, therefore for any winding Vn = 0 Permissible voltages: AC only on any winding V A S1 S1 t S2 S2 V S1 B S1 S2 t S2 V C S1 S2 S1 t S2 Prof. S. Ben-Yaakov , DC-DC Converters [3- 12] Equivalent circuit (preliminary) Ideal Ideal Llkg1 Llkg1 Lm2 Lm1 1:n Ideal Llkg2 Lm1 Lm2 = Lm1n2 Ideal transformer L → ∞ 1:n 6 1:n Prof. S. Ben-Yaakov , DC-DC Converters [3- 13] Leakage z Leakage inductance I1 V1 z Leakage inductance is the uncoupled magnetic flux Lkg1 I2 n1 n2 V2 1:n Lkg2 Lm1 ideal z Relationship between Llkg, M and k (coupling coefficient). M = k L1 ⋅L 2 L lkg1 ≅ L m1(1 − k ) L lkg2 ≅ L lkg1 ⋅ n2 Prof. S. Ben-Yaakov , DC-DC Converters [3- 14] Leakage Llkg1 1:n Llkg2 Vo Lm1 ideal Llkg1 Lm1 7 Vo′ = L'lkg2 V'o Vo n2 L′lkg2 = L lkg2 n2 Prof. S. Ben-Yaakov , DC-DC Converters [3- 15] Magnetization Current I1 Ideal Im Vin Vo Lm1 Vin Llkg2 I2 R t Vo t I2 1:n t Im t I1 t Prof. S. Ben-Yaakov , DC-DC Converters [3- 16] Transformer I1 V1 n1 n2 B sat+ B I2 B max+ V2 ∆Β B sat- H Bmax- 1. Bmax ( could be symmetrical or asymmetrical ) 2. Bmax < Bsat 3. In most case ( high frequency ) Bmax limit by magnetic losses. V1 = n1 8 dΦ dB = n1A e dt dt Prof. S. Ben-Yaakov , DC-DC Converters [3- 17] Symmetrical operation V1 B= Vm 1 ∫ Vdt n1A e Bmax + = Bmax − t on Ts B ∆B = 2Bmax = B max+ n1 = Bmax- n1A e ~ t on t on → TS 2 ~ Vm t on n1A e {Vm ,ton } 2Bmax A e 1 fs Prof. S. Ben-Yaakov , DC-DC Converters [3- 18] Skin effect High Frequency DC δ R AC >1 RDC δ − skin depth 72 δ (mm ) = f f in Hz 9 Prof. S. Ben-Yaakov , DC-DC Converters [3- 19] Skin Effect Solutions Litz wire Tape Prof. S. Ben-Yaakov , DC-DC Converters Proximity effect I I Current crowding due to magnetic fields 10 [3- 20] Prof. S. Ben-Yaakov , DC-DC Converters [3- 21] Aw Aw = [w A1 ⋅ n1 + w A 2 ⋅ n2 ] k k - filling factor k<1 w A1 = Aw wA I1 rms J J - current density A/m2 J ≅ 4.5 A/mm2 Aw - winding area I2 = Prof. S. Ben-Yaakov , DC-DC Converters n1 I1 n2 [3- 22] Ap n1I1rms ⋅2 Jk {V1, t on } n1 = 2Bmax A e Aw = n1 = JkA w 2 ⋅ I1rms Ap = A w Ae = Ap = Ap = 11 {V1, t on } JkA w = I1rms ⋅ 2 2Bmax A e {V1, t on }2 ⋅ I1rms {2Bmax }Jk {V1, t on }2 ⋅ I1 rms ∆B ⋅ Jk {V1,Don }2 ⋅ I1 rms fs ⋅ ∆B ⋅ Jk Prof. S. Ben-Yaakov , DC-DC Converters [3- 23] Transformer design stages Ap = 1. Calculate Ap {V1,Don }2 ⋅ I1 rms fs ⋅ ∆B ⋅ Jk In symmetrical operation In asymmetrical operation ∆B = Bmax+ - Bmax- ∆B = Bmax - 0 2. Look for core 3. Calculate n1 by: 4. Calculate n2 n1 = {Vm ,ton } 2Bmax A e Prof. S. Ben-Yaakov , DC-DC Converters [3- 24] Inductor design Need to store energy ( in transformer n1·I1= n2·I2 ) I L B µ 12 H µ = µ oµr µo - air (vacuum) permeability µr - relative permeability Prof. S. Ben-Yaakov , DC-DC Converters [3- 25] Permeability Henry m µo = 1.26·10-6 µr of ferrites ∼ 2000 - 4000 B = µH Bo B µ r1 µr 2 H Ho If µ is high B will reach quickly Bsat Need to slower µ µ r 2 < µ r1 Prof. S. Ben-Yaakov , DC-DC Converters [3- 26] Gaps Discrete air gap µo µr Φ Distributed air gap Same Φ magnetic lines in ferromagnetic material and in air. l g << l e lg + le ≅ le 13 le lg Prof. S. Ben-Yaakov , DC-DC Converters [3- 27] Current Crowding Current crowding due to magnetic fields RAC high around gap Prof. S. Ben-Yaakov , DC-DC Converters [3- 28] Inductance with Gap l g << l e le lg lg + le ≅ le Φ = constant Hg = B µo Hm = B µm nI = l eH = Hml e + Hgl g 14 B ≅ constant Hl e = Bl e Bl g + µm µo Prof. S. Ben-Yaakov , DC-DC Converters [3- 29] Inductance with Gap Hl e = zDividing H= Bl e Bl g + µm µo out le and defining µe = B H Ba B Bm = + l µ e µm µo e lg Prof. S. Ben-Yaakov , DC-DC Converters [3- 30] Gap Calculation 1 1 = + µ e µm 1 1 = + µreµo µrmµo 1 l µo e lg 1 1 1 = + µre µrm l e lg 15 le + µrm 1 l g = µre l µrm e l g 1 l µo e lg µre If l µrm e l g = le + µrm lg le < µrm lg l µre ≈ e lg Prof. S. Ben-Yaakov , DC-DC Converters [3- 31] Inductance V =L L dI dt V =n dΦ dt dI dΦ =n dt dt L-? n dΦ dB dH n dI = nA e = nA eµ = nA eµ dt dt dt l e dt L dI n2 A eµ dI = dt l e dt L= n2 A eµ le Prof. S. Ben-Yaakov , DC-DC Converters [3- 32] Two windings on same core L1 n1 = L 2 n2 2 Inductor design B Bmax H 16 Prof. S. Ben-Yaakov , DC-DC Converters [3- 33] Saturation Limits L dI dΦ =n dt dt Ipk dI Bmax dB L ∫ dt = nA e ∫ dt 0 0 dt dt L Ipk = nAeBmax n= LIpk quick design and check A eBmax Ae = LIpk n= nBmax JkA w Irms Prof. S. Ben-Yaakov , DC-DC Converters Ap = A eA w = LIpkIrms [3- 34] Ap Bmax Jk LIpkIrms ≈ LI2 Energy stored = LI2 2 Air gapped core Design 1. Calculate Ap 2. Choose a core 3. Iterate 4. Calculate l g ( or increase gap until L is as required ) 17 Prof. S. Ben-Yaakov , DC-DC Converters [3- 35] Cores z Transformer core z Inductor core air gap Prof. S. Ben-Yaakov , DC-DC Converters [3- 36] Cores 1. E - core 2. TOROID 3. ARENCO 18 4. POT Prof. S. Ben-Yaakov , DC-DC Converters [3- 37] Commercial cores Prof. S. Ben-Yaakov , DC-DC Converters [3- 38] Distributed gap core zThe AL = Hy turn concept of AL ( sometime Hy 1000 turns ) L for n turns: L = n2 ⋅ A L Distributed air gap 19 Prof. S. Ben-Yaakov , DC-DC Converters [3- 39] AL Prof. S. Ben-Yaakov , DC-DC Converters Toroid Data 20 [3- 40] Prof. S. Ben-Yaakov , DC-DC Converters [3- 41] Permeability change 1 Amp/m =79.5 Oe L decreases with DC current ! Prof. S. Ben-Yaakov , DC-DC Converters [3- 42] Losses Misleading notations ! ∆B NOT B “Good number”=100mW/cm3 These curves are measured by feeding ac signals. If the current is composed of DC + ripple, core loss is due only to ripple component ! DC bias tend to increase loss 21 Prof. S. Ben-Yaakov , DC-DC Converters [3- 43] Temp. Rize z “Hot Spot” - Critical parameter Prof. S. Ben-Yaakov , DC-DC Converters [3- 44] Hanna Curve n= LI pk Ae Bmax Hn = Hn = 22 H LI pk Ae Bmax nI LI le Ae Bmax H= LI2 Ve HBmax = 1 Bmax LI2 Ve Bmax = µ = µ rµ o H Prof. S. Ben-Yaakov , DC-DC Converters [3- 45] Hanna Curve Prof. S. Ben-Yaakov , DC-DC Converters Core Size Selection 23 [3- 46] Prof. S. Ben-Yaakov , DC-DC Converters [3- 47] Basic Design of Distributed Gap Core 1. Calculate LI2 2. Look up manufacturer data 3. Select Core 4. Calculate n = 1000 5. Check Lmin L AL(1000) 6. Calculate losses. Temp rise and and µ = f ( 7. Iterate 24 nI ) le