PHYSICS http://manishkumarphysics.in/ [SINGLE CORRECT CHOICE TYPE] Q.1 In the figure hown the equivalent capacitance between ' A ' and ' B ' is : (A) 3.75 F (B) 2 F 1F (C) 21 F (D) 16 F 3F 6F B 5F A Q.2 2F The equivalent capacitance between x & y is (A) (C) Q.3 4F 5 F 6 (B) 7 F 6 1F 1F 1F x y 2F C ( + 2) 2 2 1 (D) 1 F In the figure initial tatu of capacitance and their connection is shown. Which of the following is incorrect about this circuit : + 10V – + 15V – A B 2F C A B D C D 3F (A) Final charge on each capacitor will be zero. (B) Final total electrical energy of the capacitors will be zero. (C) Total charge flown from A to D is 30C. (D) Total charge flown A to D is – 30C. Q.4 A capacitor (without dielectric) is discharging through a reistor. At some instant a dielectric is inserted between the plates, then (A) Just after the insertion of the dielectric, current will increase. (B) Just after the insertion of the dielectric, charge on capacitor will increase. (C) Just after the insertion of the dielectric, energy stored in the capacitor will increase. (D) after the insertion of the dielectric, time constant will increase Q.5 In the circuit shown, switch S2 is closed first and i kept closed for a long time. Now S1 is closed. Just after that instant the curent through S1 is Q.6 mk (A) R towards right 1 (B) R towards left 1 (C) zero 2 (D) R 1 The key K (figure) connected in turn to each of the contacts over short identical time intervals so that the change in the charge on the capacitor over each connection is small. The final charge qr on the capacitor is (A) ( E1R 2 E 2 R1 ) C R1 R 2 ( E1E 2 ) C (B) E E 1 2 (C) ( E1R1 E 2 R 2 ) C R1 R 2 (D) none of these CAPACITOR PAGE # 1 PHYSICS http://manishkumarphysics.in/ Q.7 initially switch S is connected to position 1for a long time. The net amount of heat generated in the circuit after it shifted to position 2 is (A) C ( + 2) 2 2 1 (B) C (1 + 2) 2 (C) C ( + )2 2 1 2 (D) none of these Q.8 A capacitor of capacitance 0.1F is connected to a batteryh of emf 8V as shown in the fig. Under steady steady state condition. (A) Charge on the capacitor is 0.4 C. (B) Charge on the capacitor is 0.2 C. (C) Current in the resistor (R) between points A & B is 0.1A. (D) Current in the resistor (R) between points A & B is 0.4A. Q.9 For the circuit shown in the figure, determine the charge of the capacitor in steady state. (A) 4C (B) 6 C (C) 1C (D) Zero [PARAGRAPH TYPE] Paragraph for Question no. 10 to12 The switch s has been closed for long time and the electric circuit shown caries a steady current. Let C1 = 3.0 F, C2 = 6.0 F, R1 = 4.0k,and R1 =7.0k. the power disssipated in R2 is 2.8W. Q.10 The power dissipated to the resistor R1 is (A) 2.8 W (B) 1.6 W (C) 4.9 W (D) 0 Q.11 The charge on capacitors C1 and C2 are respectively. (A) 940 mC, 940 C (B) 44 C, 440 C (C) 240 C, 840 C (D) 840 C,240 C Q.12 Long time after switch is opened, jthe charge on C1 is : (A) Zero (B) 420 C (C) 240 C mk CAPACITOR (D) 660 C PAGE # 2 PHYSICS http://manishkumarphysics.in/ [MULTIPLE CORRECT CHOICE TYPE] Q.13 A parallel plate capacitor of capacitance 'C' has charges on its plates initially as shown in thefigure. Now at t = 0, the switch 'S' is closed. Select the correct alternative(s) for this circuit diagram. (A) (B) (C) (D) The plates of a parallel plate capacitor with no dielectric are connected to a voltage sourch. Now a dielectric of dielectric constant K is insrted to fill the whole space between the plates with voltage sourch remaining connected to the capacitor. (A) the energy store in the capacitor will become K-time (B) the electric field inide the capacitor will decrease K-times (C) the force of attraction between the platess will become K2-times (D) the charge on the capacitor will become K-times. [MATRIX TYPE] The circuit involves two ideal cells connected to a 1 F capacitor via a key K. Initially the key K is in position 1 and the capacitor is charged fully by 2V cell. The key is pushed to position 2. Column I gives physical quantities involving thecircuit after the keyk is pushed from position 1. kColumn II given corresponding results. Match the statements in Column I whith the corresponding values in Column II. Column I (A) The net charge crossing the 4volt cell in C is (B) The magnitude of work done by 4Volt cell in J is (C) The gain in potential energy of capacitor in J is (D) The net heat produced in circuit in J is ANSWER KEY Q.4 D Q.5 Q.11 C Q.12 CAPACITOR Column II (P) 2 (Q) 6 (R) 8 (S) 16 D B B D Q.6 Q.13 A Q.7 ACD Q.14 C ACD mk 5 2C . 2 B Q.2 C Q.3 A Q.9 B Q.10 (A) P ; (B) R ; (C) Q ;(D) P Q.15 The work done by the time steadyi state is reached is Q.1 Q.8 Q.15 Q.14 In steady state the charges on the outer surfaces of plates 'A' and 'B' will be same in magnitude and sign. In steady state the charges on the outer surfaces of plates 'A' and 'B' will be same in magnitude and opposite in sign. In stady state the charges on the inner surfaces of plates 'A' and 'B' will be same in magnitude and opposite in sign. PAGE # 3