12 electromagetic induction answers

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Name: ______________________________

Date: ______________________________

Topic 12 Review Answers

Electromagnetic Induction

1.

A

7.

C

8.

C

9.

C

2.

D

3.

A

4.

D

5.

D

6.

C

[1]

[1]

[1]

[1]

[1]

[1]

[1]

[1]

[1]

1

16.

D

17.

A

18.

C

19.

B

10.

D

11.

C

12. (a) (i) M shown at peak or trough;

(ii) Z shown on t -axis;

(b) by Lenz’s law, emf (or current) must change direction as flux cutting changes direction; as magnet oscillates, flux is cut in opposite directions;

13.

B

14.

A

15.

D

[1]

[1]

1

1

2

[4]

[1]

[1]

2

[1]

[1]

[1]

[1]

[1]

20.

B

21.

A

22.

C

23.

B

24.

A

25.

(i) (induced) e.m.f. proportional to rate of change of magnetic flux (linkage);

(do not allow induced current) as current increases, magnetic field in coil increases; thus change in flux linkage and e.m.f. induced;

(ii) direction of (induced) e.m.f. such as to tend to oppose; the change producing it; induced e.m.f. must oppose e.m.f. of battery / growth of current in circuit;

(iii) energy is supplied by the battery; in making charge move against the induced e.m.f.;

26.

Electromagnetic induction

(a) the induced emf is induced in such a direction that its effect is to oppose the change to which it is due / OWTTE ;

(b) description : on opening the switch, the reading on the voltmeter will deflect to the left and then drop to zero; explanation: when the switch is opened the field drops to zero − so again a time changing flux; which will induce an emf in the opposite direction as the emf will now be such as to oppose the field falling to zero / Lenz’s law; when the current reaches zero, there will no longer be a flux change;

3

3

2

1

4

[1]

[1]

[1]

[1]

[1]

[8]

[5]

3

27.

(a) (i) emf (induced) proportional to; rate of change / cutting of (magnetic) flux (linkage);

(ii) magnetic field / flux through coil will change as the current changes;

(b) (i) sinusoidal and in phase with current;

(ii) sinusoidal and same frequency; with 90° phase difference to candidate’s graph for ϕ ;

(iii) emf is reduced; because B is smaller;

Award [0] for “emf is reduced” if argument fallacious.

(c) advantage: no direct contact with cable required; disadvantage: distance to wire must be fixed;

28.

(a) e.m.f. induced proportional to/equal to; rate of change of flux (linkage) / rate of flux cutting;

(b) (i) for e.m.f./current to be induced in secondary, flux must be changing in the core; changing flux is caused by varying current in primary;

(ii) induced currents in core are kept small; ( do not allow reduced/ prevented ) to reduce heating/energy losses;

( do not allow mere “eddy current losses” )

(iii) use of

N

S

N

P

=

V

V

S

P

; to give N

P

= 8600 turns; and I

P

=

42

230

= 180 mA;

29.

Electrical conduction and induced currents

(a) the force on the electrons produced by the electric field causes them to accelerate along the direction of the rod; however, they will (soon) collide with a lattice ion but after collision will again be accelerated (along the rod) before making another collision /

OWTTE ; hence the electrons gain a drift / net velocity in the direction of the wire / in the (opposite) direction to the field even though they still have random velocities / OWTTE ;

2

2

2

2

2

2

3

3

2

1

1

[10]

[9]

4

(b) (i)

1

(ii) Lenz’s law says that the direction of the induced current is such as to oppose change; therefore, to produce a (magnetic) force that opposes F the current must be in direction shown / reference to left / right hand rule / OWTTE ; 2

(iii) the force on the electrons is given by Bev ; as v increases so does this force and therefore, so does the induced current; therefore, net force on rod decreases / OWTTE ;

(c) (i) the induced emf is equal / proportional to the rate of change / cutting of

(magnetic) flux;

3

1

(ii) if the rod moves a distance ∆ x in time ∆ t then area swept out by rod = l ∆ x ; flux = Bl ∆ x; rate of change of flux =

Bl ∆ x

= Blv =

ε

;

∆ t

(iii) induced current:

F

I = ;

Bl substitute to give I = 3.1A; speed v :

ε = IR = 0.47;

ε = Bvl substitute to give v = 4.5 (4.4) ms

− 1

;

3

4

1

1

30.

(a) (i) correct labelling of A and V;

(ii) P on resistor at “bottom”;

(b) (i) I = 0.40 A;

R =

V

I

=

10

0 .

40

= 25 Ω ;

(ii) the rate of increase of I decreases with increasing V / OWTTE; because: the conductor is (probably) heating up as the current increases / OWTTE ; and resistance (of a conductor) increases with increasing temperature;

(c) (i) from graph, current in Y = 0.30A; current in X = 0.20A to give total current = 0.50A;

(ii) potential across Z = 7.0V;

2

3

2

[17]

5

therefore, R =

7 .

0

0 .

50

= 14 Ω ;

(iii) resistance of parallel combination

14

7

× 5 or

5 .

0

0 .

50

;

= 10 Ω ; or resistance of Y =

5 .

0

0 .

30

= 17 Ω and resistance of X is 25 Ω ; so combination =

25 × 17

= 10 Ω ;

42

(d) (i) upwards the direction of the compass needle is the resultant of two fields

/ OWTTE ; the field must be into the plane of the (exam) paper to produce a resultant field in the direction shown / OWTTE ;

Award [1] for “upwards because of the right hand rule” / OWTTE.

(ii)

2

2

2 vector addition with correct values of two angles shown 30 ° , 60 ° or 90 ° ; from diagrams B

E

= B

W

× tan 60 or B

E

=

B

W tan 30

;

(e) (i) the emf induced in a circuit / coil / loop is equal to / proportional to; the rate of change of flux linking the circuit / coil / loop;

Do not allow “induced current”.

(ii) the induced emf / current is in such a direction that its effect is to oppose the change to which it is due / OWTTE ;

(f) (i) description: on closing the switch, the reading of the voltmeter will increase to a maximum value; then drop back to zero; explanation: on closing the switch, a magnetic field is established in the solenoid so a flux links the loops; the field is changing with time / the current is changing with time so an emf is induced in the loops; when the current reaches a maximum there is no longer a time changing flux so there is no induced emf;

(ii) description: on opening the switch, the reading on the voltmeter will increase to a maximum value but in the opposite direction; and then drop to zero; explanation:

2

2

1

4

6

when the switch is opened the field drops to zero − so again a time changing flux which will induce an emf in the opposite direction as the emf will now be such as to oppose the field falling to zero

/ Lenz’s law; when the current reaches zero, there will no longer be a flux change;

31.

Electromagnetic induction

(a) (i) 3.3 × 10

− 2

T;

(ii) flux linkage = 3.3 × 10

− 2

× 1.7 × 10

− 4

× 250;

= 1.4 × 10

− 3

Wb (turns);

Award [0] if answer given as flux in (a)(ii) but allow full credit in (b)(i).

(b) (i) new flux linkage = 7.23 × 10

− 4

Wb turns or ∆ B = 1.6 × 10

− 2

T; change = (1.4 − 0.7) × 10

− 3 or change = 1.6 × 10

− 2

× 1.7 × 10

− 4

× 250; change = 7 × 10

− 4

Wb turns (no mark for answer)

(ii) e.m.f.

is proportion al/equal to rate of

(linkage); change of flux 

(do not al low

"induced c urrent" ) emf =

(

7 × 10

− 4

)

=

0 .

35

2 × 10

− 3

V ;

(c) (i) emf / induced current acts in such a direction to (produce effects to) oppose the change causing it;

(ii) induced current produces a magnetic field in the coil / induced current is in field of magnet; this produces a force; (award only if the first marking point is correct) the force acts to oppose the motion of the coil;

4

1

2

2

2

1

3

[28]

[11]

7

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