1. A [1] 2. C [1] 3. C [1] 4. D [1] 5. A [1] 6. D [1] 7. B [1] 8. D [1] 9. A [1] 10. A [1] 1 11. B [1] 12. C [1] 13. D [1] 14. A [1] 15. (a) (b) (i) M shown at peak or trough; 1 (ii) Z shown on t-axis; 1 by Lenz’s law, emf (or current) must change direction as flux cutting changes direction; as magnet oscillates, flux is cut in opposite directions; 2 [4] 16. Electromagnetic induction (a) (b) the induced emf is induced in such a direction that its effect is to oppose the change to which it is due / OWTTE; 1 description: on opening the switch, the reading on the voltmeter will deflect to the left and then drop to zero; explanation: when the switch is opened the field drops to zero − so again a time changing flux; which will induce an emf in the opposite direction as the emf will now be such as to oppose the field falling to zero / Lenz’s law; when the current reaches zero, there will no longer be a flux change; 4 [5] 2 17. (i) (induced) e.m.f. proportional to rate of change of magnetic flux (linkage); (do not allow induced current) (ii) (iii) as current increases, magnetic field in coil increases; thus change in flux linkage and e.m.f. induced; 3 direction of (induced) e.m.f. such as to tend to oppose; the change producing it; induced e.m.f. must oppose e.m.f. of battery / growth of current in circuit; 3 energy is supplied by the battery; in making charge move against the induced e.m.f.; 2 [8] 18. (a) (b) (i) emf (induced) proportional to; rate of change / cutting of (magnetic) flux (linkage); 2 (ii) magnetic field / flux through coil will change as the current changes; 1 (i) sinusoidal and in phase with current; 1 (ii) sinusoidal and same frequency; with 90° phase difference to candidate’s graph for ϕ; 2 emf is reduced; because B is smaller; 2 (iii) Award [0] for “emf is reduced” if argument fallacious. (c) advantage: no direct contact with cable required; disadvantage: distance to wire must be fixed; 2 [10] 19. Electromagnetic induction (a) (i) 3.3 × 10−2 T; (ii) flux linkage = 3.3 × 10−2 × 1.7 × 10−4 × 250; = 1.4 × 10−3Wb (turns); 1 2 Award [0] if answer given as flux in (a)(ii) but allow full credit in (b)(i). 3 (b) (i) new flux linkage = 7.23 × 10−4 Wb turns or ∆B = 1.6 × 10−2 T; change = (1.4 − 0.7) × 10−3 or change = 1.6 × 10−2 × 1.7 × 10−4 × 250; 2 change = 7 × 10−4Wb turns (no mark for answer) (ii) e.m.f. is proportion al/equal to rate of change of flux (do not allow (linkage); "induced current" ) (7 ×10 ) = 2 ×10 −4 emf = (c) (i) (ii) 0.35 −3 2 V; emf / induced current acts in such a direction to (produce effects to) oppose the change causing it; 1 induced current produces a magnetic field in the coil / induced current is in field of magnet; this produces a force; (award only if the first marking point is correct) the force acts to oppose the motion of the coil; 3 [11] 20. (a) (b) force exerted per unit mass; on a small / point mass; from the law of gravitation, the field strength 2 F M =G 2 ; m R = g0 to give GM = g0R2; NB To achieve full marks, candidates need to state that 2 F = m g0. (c) downwards; (accept 90° to B field or down the wire) 1 (d) F = Bevcosθ; 1 4 (e) work done in moving an electron the length of the wire is W = FL = BevLcosθ; emf = work done per unit charge; therefore, E = BLvcosθ; or F electric field = = Bvcosθ; e emf E = electric field × L; to give E = BLvcosθ; 3 Award [2 max] if flux linkage argument is used. (f) F=G Mm mv 2 = ; r r2 such that v2 = (g) GM g 0 R 2 ; = r r v2 = 10 × (6.4) 2 × 1012 to give v = 7.8 × 103 m s–1; 6 6.7 × 10 L= E ; Bv cos θ = 10 3 =2.2 × 104 m; 6.3 × 10 −6 × 7.8 × 10 3 × 0.93 3 2 [14] 21. Electrical conduction and induced currents (a) the force on the electrons produced by the electric field causes them to accelerate along the direction of the rod; however, they will (soon) collide with a lattice ion but after collision will again be accelerated (along the rod) before making another collision / OWTTE; hence the electrons gain a drift / net velocity in the direction of the wire / in the (opposite) direction to the field even though they still have random velocities / OWTTE; 3 5 (b) (i) 1 (ii) (iii) (c) (i) (ii) Lenz’s law says that the direction of the induced current is such as to oppose change; therefore, to produce a (magnetic) force that opposes F the current must be in direction shown / reference to left / right hand rule / OWTTE; 2 the force on the electrons is given by Bev; as v increases so does this force and therefore, so does the induced current; therefore, net force on rod decreases / OWTTE; 3 the induced emf is equal / proportional to the rate of change / cutting of (magnetic) flux; 1 if the rod moves a distance ∆x in time ∆t then area swept out by rod = l∆x; flux = Bl∆x; rate of change of flux = (iii) Bl∆x = Blv = ε ; ∆t 3 induced current: I= F ; Bl substitute to give I = 3.1A; speed v: ε = IR = 0.47; ε = Bvl substitute to give v = 4.5 (4.4) ms−1; 4 [17] 6