Generated by Foxit PDF Creator © Foxit Software http://www.foxitsoftware.com For evaluation only. Example for Electricity Section "Phys 106" 1. Two balls each having a charge of 3 µC are separated by 20 mm. What is the force of repulsion between them? Solution (9 x 109 N ⋅ m 2 /C 2 )(3 x 10-6 C)(3 x 10-6C) F= ; F = 202 N (20 x 10-3m) 2 2. Two point charges of -3 and +4 µC are 12 mm apart in a vacuum. What is the electrostatic force between them? Solution (9 x 109 N ⋅ m 2 /C 2 )(−3 x 10-6C)(4 x 10-6C) F= ; F = 750 N, attraction (12 x 10-3m) 2 3. What is the separation of two -4 µC charges if the force of repulsion between them is 200 N? Solution r= kqq ' (9 x 109 N ⋅ m 2 /C 2 )(−4 x 10-6C)2 = ; F 200 N r = 26.8 mm 4. Two identical charges separated by 30 mm experience a repulsive force of 980 N. What is the magnitude of each charge? Solution kq 2 Fr 2 (980 N)(0.030 m)2 F = 2 ; q= = ; q = 9.90 µC r k 9 x 109 N ⋅ m 2 /C 2 5. A +8-nC charge is placed at a point P, 40 mm from a +12-µC charge. What is the potential energy per unit charge at point P in joules per coulomb? Will this change if the 8-nC charge is removed? Solution kQq (9 x 109 N ⋅ m 2 /C2 )(+12 x 10-6C)(8 x 10−9C) P .E. = = r 0.040 m P.E. = 0.0216 J; V= P .E. 0.0270 J = ; q 8 x 10-9 C V = 2.70 x 106 J/C; No The P.E./q is a property of space. If another charge were placed there or if no charge were there, the P.E./q is the same. 6. A charge of +6 µC is 30 mm away from another charge of 16 µC. What is the potential energy of the system? Solution Generated by Foxit PDF Creator © Foxit Software http://www.foxitsoftware.com For evaluation only. kQq (9 x 109 N ⋅ m 2 /C2 )(+6 x 10-6C)(16 x 10−6C) P . E. = = ; r 0.030 m P.E. = 28.8 J 7. A 28-µF parallel-plate capacitor is connected to a 120-V source of potential difference. How much charge will be stored on this capacitor? Solution Q = CV = (28 µF)(120 V); Q = 3.36 mC 8. A potential difference of 110 V is applied across the plates of a parallel-plate capacitor. If the total charge on each plate is 1200 µC, what is the capacitance? Solution Q 1200 µ C C= = ; C = 10.9 µF V 110 V 9. What is the potential energy stored in the electric field of a 200-µF capacitor when it is charged to a voltage of 2400 V? Solution P .E. = ½CV 2 = ½(200 x 10-6 F)(2400 V) 2 ; P.E. = 576 J 10. 10. A parallel plate capacitor has a plate area of 4 cm2 and a separation of 2 mm. A dielectric of constant K = 4.3 is placed between the plates, and the capacitor is connected to a 100-V battery. How much energy is stored in the capacitor? Solution A (4.3)(8.85 x 10-12 C2 /N ⋅ m 2 )(4 x 10-4 m 2 ) C = Kε 0 = ; C = 7.61 pF d 0.002 m P.E. = ½CV2 = ½(7.61 x 10-12 F)(100 V)2; P.E. = 3.81 x 10-8 J 11. What is the potential drop across a 4-Ω resistor with a current of 8 A passing through it? Solution V = IR = (8 A)(4 Ω); V = 32.0 V 12. Find the resistance of a rheostat if the drop in potential is 48 V and the current is 4 A. Solution V 48 V R= = ; R = 12.0 Ω I 4A Generated by Foxit PDF Creator © Foxit Software http://www.foxitsoftware.com For evaluation only. 13. An electric lamp has an 80-Ω filament connected to a 110-V direct-current line. What is the current through the filament? What is the power loss in watts? Solution V 110 V ; I= = I = 1.38 A R 80 Ω P= V 2 (110 V)2 = ; R 80 Ω P = 151 W Generated by Foxit PDF Creator © Foxit Software http://www.foxitsoftware.com For evaluation only.